if you walk 3 kilometers in 30 minutes , what is the average speed in kilometers per hour?

The angle of incidence in the glass is approximately 31.8°.

To find the angle of incidence in the glass, we can use Snell's law, which states that the ratio of the sines of the angles of incidence and refraction is equal to the ratio of the indices of refraction:

n1 * sin(angle of incidence) = n2 * sin(angle of refraction)

In this case, n1 is the index of refraction for flint glass (1.61), n2 is the index of refraction for ethanol (1.36), and the angle of refraction in ethanol is 27.2°.

Plugging in these values into Snell's law, we get:

1.61 * sin(angle of incidence) = 1.36 * sin(27.2°)

To find the angle of incidence, we can rearrange the equation:

sin(angle of incidence) = (1.36 * sin(27.2°)) / 1.61

Now, we can solve for the angle of incidence by taking the inverse sine (or arcsine) of both sides:

angle of incidence = arcsin((1.36 * sin(27.2°)) / 1.61)

Calculating this value, the angle of incidence in the glass is approximately 31.8°.

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Answer:

I cant read it sorry.

Explanation:

Answer:

Bile helps in the digestion of fats

b. Momentum is conserved.

c. Objects always stick together after an inelastic collision.

d. One object may be stationary before an inelastic collision.

In an inelastic collision, there are certain conditions that apply to the collision itself and the behavior of the objects involved. Let's examine each option in detail:

a. Energy is conserved: In an inelastic collision, energy is not conserved. Some energy is typically lost in the form of heat, sound, or deformation of the objects involved. This loss of energy is due to the internal forces and interactions within the objects during the collision.

b. Momentum is conserved: Conservation of momentum is a key characteristic of an inelastic collision. In an inelastic collision, the total momentum of the system before the collision is equal to the total momentum after the collision. This means that the sum of the individual momenta of the objects involved remains constant.

c. Kinetic energy is conserved: Kinetic energy is not conserved in an inelastic collision. As mentioned earlier, some of the initial kinetic energy is transformed into other forms of energy, such as heat or deformation. The total kinetic energy after the collision is generally less than the total kinetic energy before the collision.

d. Objects always stick together after an inelastic collision: In an inelastic collision, the objects involved may stick together or deform upon impact. However, it is not a universal rule that objects always stick together after an inelastic collision. The degree of stickiness or deformation depends on the specific properties of the objects and the nature of the collision.

Therefore, the correct conditions for an inelastic collision in a closed system are:

- Momentum is conserved.

- Objects may stick together or deform after the collision.

- One object may be stationary before the collision.

It's important to note that these conditions may vary depending on the specific scenario and the nature of the objects involved in the collision.

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Answer:

Energy is conserved.

Momentum is conserved

One object may be stationary before an inelastic collision.

Explanation:

Answer:

350.72 m/s

Explanation:

Formula for velocity of wave is;

v = fλ

Where;

v is speed

f is frequency

λ is wavelength

We are given;

f = 512 Hz

λ = 0.685 m

Thus;

v = 512 × 0.685

v = 350.72 m/s

your on here to lol we must be hella failing g

Answer:

PLS PLS PLS mark brainliest

Explanation:

The following are the environmental problems caused by the invasive algae which is known as Lyngbya.

A. It blocks the sunlight from reaching the water, thereby depriving the plants in the water from accessing it. So they won't be able to manufacture their foods and eventually die off.

B. The algae produce offensive odour like rotten egg , which drive people and other organisms away.

C. The algae prevent oxygen from entering the water, and prevent the resident organisms from making use of it, which leads to their death.

D. The algae also give off heat into the chilly spring waters.

In conclusion, the goals of the Crystal River project is to save the living organisms in the river from extinction and to make it a livable environment for them.

Answer:

Explanation:

For every action (or force), there is an equal and opposite action (or force).

The value of the resistor depends on the value of the resistivity of the wires used. For example, if the resistivity of the wires is 2.00×10⁻⁸ ohm-meters, then the resistance of the parallel wire would be:R = 2.00×10⁻⁸ ohm-meters × 1270.88 = 0.0255 ohms. Therefore, the value of the resistor for the given parallel wires would be 0.0255 ohms.

The question involves a problem about parallel wires separated by a distance of 5.0 mm. To find the resistor for a given length of parallel wires, we need to know the value of the resistivity of the wires. We can use the formula to find the value of the resistor. Resistivity (ρ) is a property of materials that tells us how well a material can conduct electricity. It is measured in ohm-meters (Ω.m).The formula for the resistance (R) of a wire with resistivity (ρ), length (L), and cross-sectional area (A) is given by:R = ρ(L/A)where R is the resistance in ohms, ρ is the resistivity in ohm-meters, L is the length of the wire in meters, and A is the cross-sectional area in square meters.Now, we have to determine the resistance of a parallel wire by using the given values. The length of the wire (L) is 10 cm = 0.1 m. The distance between the wires (d) is 5.0 mm = 0.005 m. The cross-sectional area (A) of the wire can be calculated by using the diameter of the wire (d) as follows:A = π(d/2)² = π(0.001/2)² = 7.854×10⁻⁷ m². Now, we can substitute these values into the formula for the resistance of the parallel wire:R = ρ(L/A) = ρ(0.1/7.854×10⁻⁷) = ρ(1270.88)The value of the resistor depends on the value of the resistivity of the wires used. For example, if the resistivity of the wires is 2.00×10⁻⁸ ohm-meters, then the resistance of the parallel wire would be:R = 2.00×10⁻⁸ ohm-meters × 1270.88 = 0.0255 ohms. Therefore, the value of the resistor for the given parallel wires would be 0.0255 ohms.

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The initial temperature of the water was approximately 81.67°C.

To solve this problem, we can apply the principle of energy conservation. The heat lost by the copper block is equal to the heat gained by the water.

The heat lost by the copper block can be calculated using the formula: Q1 = m1 * c1 * ΔT1,

where m1 is the mass of the copper block (40 g), c1 is the specific heat capacity of copper (0.39 J/g°C), and ΔT1 is the change in temperature (final temperature - initial temperature of the copper block).

The heat gained by the water can be calculated using the formula: Q2 = m2 * c2 * ΔT2, where m2 is the mass of the water (105 g), c2 is the specific heat capacity of water (4.18 J/g°C), and ΔT2 is the change in temperature (final temperature - initial temperature of the water).

Since the copper block and the water reach equilibrium, Q1 = Q2. Therefore, we can equate the two equations:

m1 * c1 * ΔT1 = m2 * c2 * ΔT2

Substituting the given values:

(40 g) * (0.39 J/g°C) * (95°C - initial temperature) = (105 g) * (4.18 J/g°C) * (24°C - initial temperature)

Simplifying the equation and solving for the initial temperature of the water gives us approximately 81.67°C.

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We know that the vertical clearance of the crossbar by the ball is x=1.57m.

From a point 36.0 m from the goal, a place kicker must kick a football. The ball must clear the 3.05 m-high crossbar as a consequence of the kick. The ball kicks off the ground with a speed of 20.0 m/s at an angle of 53° from the horizontal.

v=18cos48 m/s

Time is therefore defined as distance multiplied by speed, which equals 28/18cos48 divided by 48, or 2.324

Use s = ut + (0.5)a(t2) when resolving vertically.

Where is the unidentified distance, s? (the height above the GROUND)

initials are u (vertical) 18 divided by 48 gives a speed of -9.8 meters per second (negative since we take upwards as positive)

t = 2.3247... (what we found previously) (what we found previously)

Adding the figures to the formula gives 4.616

Subtracting the goalpost's height (3.05) results in 1.57m above the crossbar, or 1.56.

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The correct option is B. The spectrum of a signal is the range of frequencies in the signal.

A spectrum (plural spectra or spectrums) is a condition that isn't restricted to a specific set of values but can vary, without gaps, across a continuum. The word became first used scientifically in optics to explain the rainbow of colors in visible light after passing via a prism. As clinical information of mild superior, it got here to apply to the whole electromagnetic spectrum. It thereby has become a mapping of a variety of magnitudes (wavelengths) to a range of traits, which are the perceived "shades of the rainbow" and different houses which correspond to wavelengths that lie outdoors of the visible light spectrum.

Spectrum has due to the fact that been implemented via analogy to topics outside optics. therefore, one would possibly communicate approximately the "spectrum of political opinion", the "spectrum of interest" of a drug, or the "autism spectrum". In these uses, values within a spectrum may not be associated with precisely quantifiable numbers or definitions. Such makes use of implying a wide variety of situations or behaviors grouped together and studied under an unmarried identity for ease of discussion. Nonscientific makes use of the time period spectrum is once in a while deceptive.

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Complete Question:

The spectrum of a signal is:

A. the lowest frequency value subtracted from the highest

B. the range of frequencies in the signal

C. all of the frequencies from 0 to the highest frequency used

D. the average of the highest frequency and the lowest

To find the x and y coordinates of the center of mass for the system of these three objects, we need to calculate the weighted average of the x and y coordinates of each individual object.

First, let's label the objects:
- Pipe wrench: mass = 2.3 kg
- Hatchet: mass = 1.5 kg
- Hammer: mass = 1.0 kg

Next, let's denote the x and y coordinates of each object's center of mass on the graph:
- Pipe wrench: (x1, y1)
- Hatchet: (x2, y2)
- Hammer: (x3, y3)

To calculate the x coordinate of the center of mass (x_cm), we use the formula:
x_cm = (m1*x1 + m2*x2 + m3*x3) / (m1 + m2 + m3)

Substituting the given values, we get:
x_cm = (2.3*x1 + 1.5*x2 + 1.0*x3) / (2.3 + 1.5 + 1.0)

Similarly, to calculate the y coordinate of the center of mass (y_cm), we use the formula:
y_cm = (m1*y1 + m2*y2 + m3*y3) / (m1 + m2 + m3)

Substituting the given values, we get:
y_cm = (2.3*y1 + 1.5*y2 + 1.0*y3) / (2.3 + 1.5 + 1.0)

By plugging in the specific x and y coordinates for each object, you can calculate the x_cm and y_cm values for the system of these three objects.

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Answer:

Resistance = 15 Ohms

Explanation:

Given the following data;

Emf voltage = 18 V

Internal resistance = 3 Ohms

Potential difference = 15V

To find the resistance of the wire;

First of all, we would determine the current flowing through the wire.

Mathematically, the terminal potential difference is given by the formula;

V = E - IR

Where;

V is the terminal potential difference.

E is the electromotive force (emf).

I is the current.

R is the internal resistance.

15 = 18 - I*3

15 = 18 - 3I

3I = 18 - 15

3I = 3

I = 1 Amperes

Next, we find the resistance of the wire;

Voltage = current * resistance

Substituting into the formula, we have;

15 = 1 * resistance

Resistance = 15/1

Resistance = 15 Ohms

Hooke's Law states that the force that the spring exerts on the mass in a mass-spring system is opposite of and proportional to the displacement of the mass from equilibrium. The statement is True.

The force is an action of push or pull on any object to change the state of motion or rest.

The Hookes's law is related to the spring force. The force F is applied on the mass connected to spring to compress or extend it about the equilibrium position at distance x. When force is removed, the mass attached to the spring moves in opposite direction of force.

The larger the force, longer is the distance from equilibrium position. This concludes that the Hooke's law is correct.

Thus, the statement is True.

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the maximum height reached by ball is 0.45m.

Given :-

spring constant ( k ) = 400N/m

mass of ball = 1kg

spring compressed ( x )= 0.150m

we calculate height by using mechanical energy conservation According to the principle of conservation of mechanical energy, The total mechanical energy of a system is conserved .

Mechanical energy is the sum of the potential and kinetic energies in a system :-

K₀ + U₀ = K + U    (eq 1)                    

where,

           K₀ = initial kinetic energy = 0

           U₀ = initial potential energy = \(\frac{1}{2} kx^{2}\)

           K = final kinetic energy when it reaches at its max height =0

           U = final potential energy when it reaches at its max height =mgh

The elastic potential energy is = \(\frac{1}{2} kx^{2}\)

                                                     =  0.5 × 400 × 0.15 × 0.15

                                                     = 4.5 J.  

putting value in eq 1 :-

                                    0 + 4.5 = 0 + mgh

                                     4.5 = 10h

                                      h=0.45m

Thus from the above conclusion we can say that the maximum height reached by the ball is 0.45m.

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Answer: Velocity = v = 35 m/s

Explanation:

Kinetic energy of an object is defined as the energy possess by an object due to its motion. Kinetic energy K.E of an object is equal to the half of the mass of that object multiplied by square of the object's velocity.

Mathematically,

v = 35 m/s

If the direction of the current is changed, the measurement of the system being measured could potentially change.

The direction of the current can affect the flow of electricity through the system, which can in turn affect any measurements being taken.

For example, if you were measuring the voltage of a circuit, changing the direction of the current could change the voltage being measured. It's important to carefully consider the direction of the current when taking measurements to ensure accuracy and consistency in your results.

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Answer:

v = 17.30 m / s

Explanation:

For this exercise we will use Newton's second law

at the bottom of the loop and stopped

           ∑ F = 0

           N-W = 0

           N = W

            W = 770 N

the mass of the body is

            W = mg

             m = W / g

            m = 770 / 9.8

            m = 78.6 kg

on top of the loop and moving

           ∑ F = m a

           N + W = m a

note that the three vectors go in the same vertical direction down

the centripetal acceleration is

           a = v² / r

we substitute

           N + W = m v² / r

           v = \(\sqrt{(N+W) \frac{r}{m} }\)

let's calculate

          v = \(\sqrt{ (350+770) \frac{21}{78.6} }\)

          v = 17.30 m / s

Yes, the statement is correct. GTPase activity is an important feature of G proteins, a family of signaling proteins that play a crucial role in signal transduction pathways.

When a G protein is activated by a signaling molecule (ligand), it exchanges its bound GDP molecule for GTP, which activates it. The activated G protein then interacts with its downstream effector proteins to initiate a cellular response.

However, G proteins are active only when GDP is bound to them. After activation, the G protein's intrinsic GTPase activity hydrolyzes the bound GTP to GDP and inorganic phosphate (Pi), thus turning off the signal.

The inorganic phosphate released in this process can also serve as a secondary messenger, triggering downstream signaling events, such as the activation of kinases that phosphorylate target enzymes.

The hydrolysis of GTP to GDP and inorganic phosphate also provides energy for signal transduction. This energy is used to drive conformational changes in the G protein and to perform work in downstream signaling events.

Thus, the GTPase activity of G proteins is crucial for the proper functioning of signaling pathways and for the termination of signaling events

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An airplane is flying with a velocity of 42 m/s at a standard altitude of 3 km. At a point on the wing, the airflow velocity is 88 m/s. The  pressure at the point on the wing is  \(P = 6.96 * 10^4 N/m^2\).

To calculate the pressure at a point on the wing, we can use Bernoulli's equation, which relates the pressure, velocity, and density of a fluid in steady, incompressible flow.

The equation is as follows:

P + 1/2 * ρ * \(V^2\) = constant

where P is the pressure, ρ is the density of the fluid, and V is the velocity of the fluid.

Given:

\(P_1 = 7.01 * 10^4 N/m^2\) (pressure at standard altitude)

ρ = \(0.909 kg/m^3\) (density of the fluid)

\(V_1 = 42 m/s\) (velocity of the airplane)

\(V_2 = 88 m/s\) (velocity at the point on the wing)

To find the pressure at the point on the wing, we can use Bernoulli's equation for the standard altitude and the point on the wing, and then solve for P:

\(P_1 + 1/2\) * ρ * \(V_1^2\) = \(P + 1/2\)  * ρ * \(V_2^2\)

Substituting the given values:

\(7.01 * 10^4 + 1/2 * 0.909 * 42^2 = P + 1/2 * 0.909 * 88^2\)

Simplifying the equation:

\(7.01 × 10^4 + 1/2 * 0.909 * 1764 = P + 1/2 * 0.909 * 7744\)

7.01 × 10^4 + 804.906 = P + 3526.242

\(P + 4329.148 = 7.01 *10^4\)

\(P = 7.01 * 10^4 - 4329.148\)

\(P = 6.96 * 10^4 N/m^2\)

Therefore, the pressure at the point on the wing is \(P = 6.96 * 10^4 N/m^2\)

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(1) The image of an object placed further from the lens than the focal point will be upside down and smaller than the object.

(2) When light rays reflect, they bounce back.

(3)  Images formed by a concave lens will look magnified.

(4) When light rays enter a different medium, they bend.

The image of an object placed further from the lens than the focal point will be diminished and inverted.

Thus, the correct answer will be "upside down and smaller than the object".

The ability of light to bounce back when it strike a hard surface is known as refection.

A concave lens is diverging lens is usually virtual, erect and magnified.

The change in speed of light when it travels from medium to another medium is known as refraction. Refraction is also, the ability of light to bend around obstacles.

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Answer:

It is upside down and larger than the object

They bounce back

Magnified

They bend

Explanation:

During a certain time interval, the net work done on an object is zero joules. We can be certain that the object's final speed is same as its initial speed.

When the net work done on an object is zero, this indicates that the kinetic energy of the body has not changed which means that the object's final speed is same as its initial speed.

Since, we know from the Work energy Theorem that the Change in Kinetic energy is equal to the work done.

So, Zero work indicates that the kinetic energy has not varied which directly signifies that the speed has not change in the course of the interval.

Work is done by the force acting on the body which gets transferred in the kinetic energy of the body.

Kinetic energy is the energy produced due to the motion of the body in the system.

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From the given information provided, if we make width larger, ground state energy will decrease. "It will decrease", is the correct answer.

The ground state energy is the lowest possible energy that a quantum mechanical system can have.

If we make the width of the infinite potential well larger, the ground state energy of the system will decrease. This is because the ground state energy of the infinite potential well is inversely proportional to the square of the width of the well. As the width of the well increases, the energy levels become more closely spaced and the ground state energy decreases.

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Answer:

Option D. 1000 J.

Explanation:

From the question given above, the following data were obtained:

Force (F) applied = 200 N

Distance (s) = 5 m

Time (t) = 10 s

Workdone (Wd) =?

Workdone (Wd) is simply defined as the product of force (F) and distance (s) moved in the direction of the force. Mathematically, it is expressed as:

Wd = F × s

With the above formula, we can calculate the Workdone as illustrated below:

Force (F) applied = 200 N

Distance (s) = 5 m

Workdone (Wd) =?

Wd = F × s

Wd = 200 × 5

Wd = 1000 J

Thus, the Workdone is 1000 J

Mount Rainier National Park is located in the Cascade Range of Washington state, and two important geologic forces at work in this area are volcanic activity and glaciers.

Volcanic activity has played a major role in shaping the landscape of Mount Rainier National Park. The mountain is a stratovolcano, which means that it is composed of layers of volcanic ash, rock, and lava flows. Over time, eruptions have built up the mountain and created the characteristic cone shape that we see today. Mount Rainier is still an active volcano, with the last eruption occurring in the mid-1800s. Volcanic activity in the area can cause earthquakes, landslides, and other hazards.

Glaciers have also had a significant impact on the landscape of Mount Rainier National Park. The park is home to the largest glacier system in the contiguous United States, with over 25 named glaciers covering the mountain. These glaciers are formed by snowfall that accumulates over time and compacts into ice. As the ice moves down the mountain, it can carve out valleys and create features such as moraines, cirques, and U-shaped valleys. Glaciers also play an important role in shaping the hydrology of the region, as they melt and feed into streams and rivers.

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Answer:

Explanation:

As a pendulum swings, its potential energy converts to kinetic and back to potential. ... During the course of a swing from left to right, potential energy is converted into kinetic energy and back.

Answer:

Once the weighted end of the pendulum is released, it will become active as gravity pulls it downwards. Potential Energy Is Converted To Kinetic Energy. which is the energy exerted by a moving object. An active pendulum has the most kinetic energy at the lowest point of it's swing when the weight is movin.

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The safety valve is set to automatically reduce pressure at a predetermined threshold to prevent overpressure and ensure the safety of the system or equipment.

Safety valves are essential components in various systems where pressure regulation is critical, such as steam boilers, pressure vessels, or pipelines. They are designed to open when the pressure exceeds a specific setpoint, allowing excess fluid or gas to escape and thus reducing the pressure inside the system. The predetermined threshold at which the safety valve opens is determined during the design and installation process based on the system's specifications, operating conditions, and safety requirements. This setpoint is typically determined with careful consideration of the maximum allowable pressure for the system and the safety margins needed to prevent failures or hazardous conditions.

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the safety valve is set to automatically reduce pressure at____.