ILL GIVE BRAINIEST TO WHOEVER IS CORRECT!! PLEASE HELP ASAP!!

Write an equation of a line in a standard form that passes through points A(-3,4) and B(1,-2) with work

Whenever a set X is a subset of set Y, we say the Y is a superset of X and we write, Y ⊇ AX.

Symbol ⊇ is used to denote ‘is a super set of’

Answer:

circle=6, triangle=2, star=8, square=4

Step-by-step explanation:

6+2=8

6-2=4

8+4=12

8-4=4

4+4=8

Answer: No It's not proportional as the constant of proportionality for both of them.are different.

Step-by-step explanation:

For the first part of the question, a 150-pound teenager eats 5.5 pounds of food per day, we've to calculate the constant of proportionality. This will be:

y = kx

150 = 5.5k

k = 27.27

For the second part of the question, a 250-pound panda eats 40 pounds of bamboo a day. we've to calculate the constant of proportionality. This will be:

y = kx

250 = 40k

k = 250/40

k = 6.25

This shows that the 150-pound teenager eats 5.5 pounds of food per day, is not proportional to a 250-pound panda eating 40 pounds of bamboo a day because th e value of k are different.

The frequency of A allele after a single generation of mutation can be found as follows: Frequency of A allele after a single generationp(A) = p(A) x (1 - m) + q(a) x m

where,
m = mutation rate = 10^-6p(A) = frequency of A allele in initial generation = 0.75q(a) = frequency of a allele in initial generation = 0.25Thus,p(A) = 0.75 x (1 - 10^-6) + 0.25 x 10^-6 = 0.74999925

And the frequency of a allele will beq(a) = 1 - p(A) = 1 - 0.74999925 = 0.25000075

Therefore, the frequency of the A and a alleles in the next generation will beA: 0.74999925 and a: 0.25000075.

This is option D.

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The unit tangent vector t(1) at t = 1 is:

t(1) = (4 i + 6 j + 3 k) /\(\sqrt{(61)}\)

To find the unit tangent vector,

we need to calculate the derivative of the position vector r(t) with respect to the parameter t, and then normalize the resulting vector.

Given the position vector r(t) = 4t i + 3t^2 j + 3t k,

we can find the derivative:

r'(t) = d(r(t))/dt

     = 4 i + 6t j + 3 k

Now, we can evaluate r'(t) at t = 1:

r'(1) = 4 i + 6(1) j + 3 k

      = 4 i + 6 j + 3 k

To obtain the unit tangent vector,

we need to normalize r'(1):

t(1) = r'(1) / ||r'(1)||

where ||r'(1)|| represents the magnitude or length of r'(1).

The magnitude of r'(1) is given by:

||r'(1)|| = \(\sqrt{((4^2) + (6^2) + (3^2))}\)

       = \(\sqrt{61}\))

This is the normalized vector representing the direction of the tangent to the curve at the point where t = 1.

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Sandra have 40 coins in total out of 120 coins.

Let the coins with Sandra be x

Then Joel has 1/2 as many coins as Sandra coins so x/2 coins and

mark has 3 times as many as Joel so 3x/2 coins in total.

There amount is 120 coins in total

therefore ,

3x/2 + x/2 + x = 120

4x/2 + x = 120

2x + x = 120

3x = 120

x = 40

So Sandra has total of 40 coins out of 120 coins.

An equation is said to be linear if the maximum power of the variable is consistently 1. Another name for it is a one-degree equation. A linear equation with one variable has the conventional form Ax + B = 0. In this case, the variables x and A are variables, while B is a constant. A linear equation with two variables has the conventional form Ax + By = C.

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Answer:

one months bill would be $32+$0.75X=$47   X= minutes use over given time.

X= 20

Step-by-step explanation:

The amount of the money after 7 years with a rate of 13% with an initial amount of $400 will be $ 941.04.

Compound interest is the interest on a loan or deposit calculated based on the initial principal and the accumulated interest from the previous period.

Tanvi opened a savings account and deposited $400.00 as principal.

The account earns 13% interest, compounded annually.

Then the balance after 7 years will be

We know the compound interest formula.

A = P (1 + r)ⁿ

We have

P = $ 400

r = 13%

n = 7 years

Then we have

A = 400 x (1 + 0.13)⁷

A = 400 x 1.13⁷

A = 400 x 2.3526

A = $ 941.04

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Answer:

X = 25

Step-by-step explanation:

here DGF is a right angled triangle so we can use Pythagoras theorem in it so

let us consider DF = x as hypotenuse (h)

GF =24 as base (b)

DG=7 as perpendicular (p)

Now applying Pythagoras theorem we get

h² = p² + b²

x² = 7²+24²

x = √625

x = 25

hope it helps. :)

The equation for the function is f(x) = 3 * cos (16x + \(\frac{16\pi }{3}\) ) + 5.

What is an equation?

A assertion that two expressions with variables and/or numbers are equal is referred to as an equation. The fundamental driving forces behind the evolution of mathematics have been attempts to logically solve equations, which are really questions.

We know that f(x) = a cos (bx + c) + d.

We are given

a = 3 which is the amplitude

Period = 8π

b = 16

Phase shift = \(\frac{c}{b}\)

⇒\(\frac{\pi }{3}\) = \(\frac{c}{16}\)

⇒ c = \(\frac{16\pi }{3}\)

d = 5 as there is upward translation

So, from this we get the equation as

⇒f(x) = 3 * cos (16x + \(\frac{16\pi }{3}\) ) + 5

Hence, the equation for the function is f(x) = 3 * cos (16x + \(\frac{16\pi }{3}\) ) + 5.

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Question: Write an equation for a function with the given characteristics. A cosine curve with a period of 8π, an amplitude of 3, a right phase shift of π/3, and a vertical translation up 5 units.

f(x) = ______________

Data categorization is a process of organizing and grouping data into meaningful classes or categories.

This process is often used to simplify data and make it easier to understand and analyze. Data categorization involves breaking down a large set of data into smaller, more manageable groups. For example, a company may group customers into categories based on their age, income, or location. Each group can then be analyzed separately to better understand customer behavior. Categorizing data can also help identify trends or patterns that may not be visible when looking at the data as a whole. Categorization can also be used to identify outliers or anomalies in the data. By breaking down the data into smaller groups, it becomes easier to see which elements don’t fit the pattern or are not part of the normal range. Categorizing data can be done using a variety of methods. For example, data can be divided into numerical ranges or grouped into categories such as low, medium, and high. Data can also be grouped using descriptive terms, such as customer type or product type. Once the data is categorized, calculations such as averages, medians, and modes can be used to analyze the data. This can help to identify patterns or trends that can be used to make decisions or draw conclusions.

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Answer:

First what does x represent. For example x could equal 5 so (5)2 +2 simplified is 10 +2 which is 12 :)

Step-by-step explanation:

You need to find a number that, when multiplied by a given number modulo a certain value, produces a remainder of 1. This can be done using the extended Euclidean algorithm, and the resulting inverse is the residue of the coefficient modulo the modulus.

Finding the inverse of a modulo involves finding a number that, when multiplied by a given number modulo a certain value, produces a remainder of 1. This process is important in modular arithmetic, where calculations are performed with remainders of a fixed integer modulus.

To find the inverse of a modulo, you can use the extended Euclidean algorithm, which is a method for finding the greatest common divisor of two integers.

The steps for finding the inverse of a modulo are as follows:

1. Identify the number you want to find the inverse of (let's call it "a") and the modulus (let's call it "m").

2. Use the extended Euclidean algorithm to find the greatest common divisor of "a" and "m", and the coefficients x and y such that ax + my = gcd(a,m).

3. If gcd(a,m) = 1, then "a" has an inverse modulo "m" and the inverse is given by x mod m.

4. If gcd(a,m) is not equal to 1, then "a" does not have an inverse modulo "m".

In step 3, x mod m represents the residue of x modulo m, which is the unique non-negative integer less than m that is congruent to x modulo m. In other words, it is the remainder when x is divided by m.

For example, to find the inverse of 5 modulo 7, we can use the extended Euclidean algorithm to find that 2(5) + (-1)(7) = 1. Therefore, the inverse of 5 modulo 7 is 2.

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Answer:

A system of equations consists of two or more equations with two or more variables, where any solution must satisfy all of the equations in the system at the same time.

Answer:

The answer is -3g=(-6)

The function can be factored as

We see now that the function vanishes to zero when x = 9 or x = -7 which are the zeros of the function.

The set of all vectors in r4 satisfying the equation is,

( x, R , y ) = ( 1 , R , 1/2 ) ( 2 , R , 1 ) ( 3 , R , 3/2 ) ( 4 , R , 2 ) ( 5 , R , 5/2 ) ( 6 , R , 3 ) ( 7 , R , 7/2 ) ( 8 , R , 4 )

A basis for R4 always consists of 4 vectors. (TRUE: Vectors in a basis must be linearly independent AND span.) 4. The union of two subspaces is a subspace.

If S is a subspace of R4, then the zero vector 0=[0000] in R4 must lie in S. 2x+4y+3z+7w+1=0. So 0∉S, and we conclude that S is not subspace of R4.

The space R4 is four-dimensional, and so is the space M of 2 by 2 matrices. Vectors in those spaces are determined by four numbers. The solution space Y is two-dimensional, because second order differential equations have two independent solutions.

The interval of x is known and the relation of x , y is known.

So,

x = 2y  ;   x = { 1 , 2 , 3 , 4 , 5 , 6 , 7 , 8 }

Then,

1 = 2y , 2 = 2y , 3 = 2y , 4 = 2y , 5 = 2y , 6 = 2y , 7 = 2y , 8 = 2y ,

We can write,

y = { 1/2 , 1 , 3/2 , 2 , 5/2 , 3 , 7/2 , 4 }

Therefore,

The set of all vectors in r4 satisfying the equation is,

( x, R , y ) = ( 1 , R , 1/2 ) ( 2 , R , 1 ) ( 3 , R , 3/2 ) ( 4 , R , 2 ) ( 5 , R , 5/2 ) ( 6 , R , 3 ) ( 7 , R , 7/2 ) ( 8 , R , 4 )

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Answer:

Step-by-step explanation:

Answer:

The rotation is 270 degrees counterclockwise

Step-by-step explanation:

Given

See attachment

Required

Degrees of rotation

From the question, the rotation is counterclockwise

Using point B and B' as points of reference.

\(B =(2,5)\)

\(B' =(5,-2)\)

The rule that supports the above is: rotation by 270 degrees counterclockwise.

Because the rule is:

\((x,y) ==>(y,-x)\)

a) Graph representing the pricing structure of Swiss cheese is shown below:

b) A customer will have to pay $5.50 for the purchase of 12 ounces of Swiss cheese.

We can obtain this by calculating the first ounce at a cost of $1.50, then the next six ounces (for a total of seven ounces) at a cost of $0.50 per ounce, and the remaining five ounces at a cost of $1.00 per ounce.

The cost of the Swiss cheese for 1 ounce is $1.50, for the next 6 ounces, the cost would be (6 * $0.50) $3.00, and the last 5 ounces will cost (5 * $1.00) $5.00.

Adding all three costs yields:

$1.50 + $3.00 + $5.00 = $9.50

Therefore, a customer will have to pay $9.50 for 11 ounces of Swiss cheese.

But he/she is purchasing 12 ounces of Swiss cheese.

So, adding $1.00 to $9.50 yields:

$9.50 + $1.00 = $10.50

Therefore, a customer will have to pay $5.50 for the purchase of 12 ounces of Swiss cheese.c) $10.50 can buy 7 ounces of Swiss cheese.

For the first ounce, $1.50 will be charged, and the remaining $9.00 will purchase 18 more ounces.

But, each ounce costs $0.50 after the first ounce.

Thus, dividing $9.00 by $0.50 gives 18 ounces.

Adding the first ounce gives:

1 + 18 = 19

Therefore, $10.50 can purchase 19 ounces of Swiss cheese.

But we are asked to determine how many ounces of Swiss cheese can be purchased for $10.50.

Therefore, we must now subtract one ounce since it costs

$1.50.19 - 1 = 18

Therefore, $10.50 can buy 18 ounces of Swiss cheese.

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A customer can purchase 19 ounces of Swiss cheese for $10.50.

a) The graph that represents the pricing structure of Swiss cheese is shown below:

b) A customer needs to pay $8.00 for a purchase of 12 ounces of Swiss cheese.

c) The number of ounces of Swiss cheese that can be purchased for $10.50 can be calculated as follows:

Let's say a customer purchases x ounces of cheese.

Then the equation that represents the price is given by;

price = $1.50 + $.50(x - 1)

For $10.50, the equation becomes:

$10.50 = $1.50 + $.50(x - 1)

Simplifying the above equation,

$9 = $.50(x - 1)18 = x - 1x = 19

Therefore, a customer can purchase 19 ounces of Swiss cheese for $10.50.

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To find the parallel line of y =3z+6 passing through the slope intercept points (-2,5).

For a line to be parallel to another line, by definition it must have the same slope.

Because the equation is in the slope-intercept form we can use the slope of the line.

The slope- intercept form of a linear equation is :

y=mx+b

Where m is the slope and b is the y− intercept value.

Therefore, for the given equation, the slope is 3.

Now we can use the point slope formula to determine the equation for the parallel line.

The point - slope formula states: (y−y1)=m(x−x1)

Where m is the slope and (x1,y1) is a point the line passes through.

Substituting the slope from the given line and the given point gives:

y−5=3(x+2)

Transforming this to the slope-intercept form by solving for y gives:

y−5=3x+6

y−5+5=3x+6+5

y=3x+11

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A postfix expression does not require parentheses to specify evaluation order is true.

Postfix expressions are expressions in which operators appear after their operands. This makes the expressions very simple to evaluate and operate upon as the order of evaluation is very natural and straightforward.

A postfix expression can be evaluated easily without using parentheses to specify the order of evaluation. The order of evaluation in postfix expressions is determined by the position of the operands and operators in the expression.

In postfix expressions, the operands are evaluated first, and then the operator is applied to the operands.

In infix expressions, parentheses are used to specify the order of evaluation.Without parentheses, the order of evaluation can be difficult to determine, leading to ambiguity and confusion.

However, in postfix expressions, parentheses are not necessary as the order of evaluation is clear from the position of the operands and operators in the expression.

In conclusion, the statement "A postfix expression does not require parentheses to specify evaluation order" is true.

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Answer:

The combination of a reflection in a line and a translation in a perpendicular direction is a reflection in a parallel line. However, a glide reflection cannot be reduced like that. Thus the effect of a reflection combined with any translation is a glide reflection, with as special case just a reflection.

Step-by-step explanation:

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ok thx

Step-by-step explanation:

Answer:

The combination of a reflection in a line and a translation in a perpendicular direction is a reflection in a parallel line.

Step-by-step explanation:

Hope this helps!

The area of sector in question 9 is 141.87 ft² and the area of sector in question 10 is 107.70 m².

A circle is a collection of points that are all equally distance from the circle's centre. The radius is the usual distance a circle travels from its centre to its point. The circle's centre (o) and radius (r) serve as its definition (r).

A sector is referred to as a component of a circle made up of the circle's arc and its two radii. It is a section of the circle made up of the arc's circumference and the radii of the circle at its ends.

Given in question 9, r = HK = 25 ft

angle of sector = 26°

so the area of sector A₉ = (26°/360°)π*r²

⇒ A₉ = (26°/360°)* 22/7 * (25)²

⇒ A₉ = (26°/360°)* (22 * 625)/7

⇒ A₉ = 357,500/2520

⇒ A₉ = 141.87 ft²

Given in question 10, SR = 26 m

⇒ r = ST = SR/2

⇒ r = 26/2 = 13 m

angle of sector = 73°

so the area of sector A₁₀ = (73°/360°)π*r²

⇒ A₁₀ = (73°/360°)* 22/7 * (13)²

⇒ A₁₀ = (73°/360°)* (22 * 169)/7

⇒ A₁₀ = 271,414/2520

⇒ A₁₀ = 107.70 m²

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