imagine two like charges in close contact. if one of the charges becomes oppositely charged, what happens to the electrostatic force?

Given:

The mass of the pendulum, m=1.29 kg

The length of the simple pendulum, L=0.830 m

The period of the pendulum, T=1.809 s

To find:

(b) The spring constant of the spring so that the period of the oscillation of the spring will be T.

Explanation:

The period of oscillation of a spring-mass system is given by the equation,

On rearranging the above equation,

On substituting the known values,

Final answer:

The spring constant of spring is 15.56 N/m

Carbon monoxide produces the largest number  of photons.

A molecular cloud, sometimes called a stellar nursery (if star formation is occurring within), is a type of interstellar cloud.

The density and size of which permit absorption nebulae, the formation of molecules (most commonly molecular hydrogen),helium and traces of carbon, oxygen and nitrogen.

This is in contrast to other areas of the interstellar medium that contain predominantly ionized gas.

In molecular cloud due to suitable conditions formation of CO takes place .

Carbon monoxide is very good at radiating infrared radiation releasing a lot of photons , and plays the role of a thermostat, dispelling any heat that manages to build up. Thus, the cloud manages to stay cool.

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Answer:

C. Fe: 24 electrons

Explanation:

From the analogy given, the atom with a charge of +2 is Fe having 24 electrons.

To calculate the charges on an atom;

     Number of charges = Number of protons - Number of electrons.

   O: 10 electrons: 8 protons = 8 - 10 = -2

   N: 10 electrons; 7 protons = 7 - 10 = -3

   Cl: 18 electrons; 17 protons = 17 - 18 = -1

So;

    Fe: 24 electrons and 26 protons = 26 -24  = +2

Therefore, the solution is Fe

The equation given as:

\(\(\[ \gamma_{d}\)

=\(\frac{G_{s} \gamma_{w}}{1+e} \]\)\)

needs to be rewritten in terms of 6. We know that e = 2.71 approximately,  the equation in terms of 6 is:

\(\(\[\gamma_d = \frac{6G_s\gamma_w}{22.26}\]\)\)

This new equation gives the value of γd in terms of 6.

so we will substitute this value in the equation to get:

\(\[\gamma_d = \frac{G_s\gamma_w}{1+2.71}\]\)

Simplifying the expression by adding the denominator terms and getting a common denominator, we get:

\(\(\[\gamma_d = \frac{G_s\gamma_w}{3.71}\]\)\)

Now, we can divide both sides of the equation by 3.71 to isolate γd on one side and write the equation in terms of 6, as follows:

\(\[\gamma_d\)

\(= \frac{G_s\gamma_w}{3.71} \times \frac{6}{6}\] \[\gamma_d \(\)

\(= \frac{6G_s\gamma_w}{22.26}\]\)\)

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The work done on the barbell is 700 Joule. The result is obtained by multiplying the distance by the force.

The work done on an object can be counted by the equation:

W = F × d

Where

A weightlifter lifts a barbell with a mass of 350 N. It reach the distance of 2 meters from the ground.

Find the work done on the barbell!

We have

The work done on the barbell will be

W = F × d

W = 350 × 2

W = 700 Joule

Hence, on the barbell is done the work of 700 Joule.

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To determine the empirical formula, we need to find the mole ratio of the elements in the compound. We can assume a 100 g sample of the compound, which means:

Mass of carbon = 62.1 g

Mass of hydrogen = 5.21 g

Mass of nitrogen = 12.1 g

Mass of oxygen = (100 - 62.1 - 5.21 - 12.1) = 20.59 g

Next, we need to convert the masses to moles:

Moles of carbon = 62.1 g / 12.011 g/mol = 5.17 mol

Moles of hydrogen = 5.21 g / 1.008 g/mol = 5.17 mol

Moles of nitrogen = 12.1 g / 14.007 g/mol = 0.864 mol

Moles of oxygen = 20.59 g / 15.999 g/mol = 1.287 mol

The smallest mole value is that of nitrogen, which is approximately 0.864 mol. We can use this value as a reference to find the mole ratio of the other elements:

Carbon: 5.17 mol / 0.864 mol ≈ 5.99 ≈ 6

Hydrogen: 5.17 mol / 0.864 mol ≈ 5.99 ≈ 6

Nitrogen: 0.864 mol / 0.864 mol = 1

Oxygen: 1.287 mol / 0.864 mol ≈ 1.49 ≈ 1.5

The mole ratio of the elements in the compound is approximately C6H6N1.5O1 or simplified, C12H12N3O2. This is the empirical formula of the compound.

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The direction of the squirrel's velocity at t = 5.93s is 71.3 degrees counterclockwise from the positive x-axis.

To determine the direction of the squirrel's velocity at a given time t, we need to find the velocity vector and then calculate its direction angle relative to the positive x-axis.

The velocity vector is the time derivative of the position vector r(t):

v(t) = dr(t)/dt = [(0.280m/s) + (0.0720m/s2)t]i^ + (0.0570m/s2)t2j^

At t = 5.93s, we can substitute this value into the velocity equation to obtain the velocity vector:

v(5.93s) = [(0.280m/s) + (0.0720m/s2)(5.93s)]i^ + (0.0570m/s2)(5.93s)2j^

v(5.93s) = (0.701m/s)i^ + (1.98m/s)j^

Next, we can calculate the direction angle of the velocity vector relative to the positive x-axis using trigonometry:

theta = tan^-1(vy/vx)

where vx and vy are the x- and y-components of the velocity vector, respectively.

Substituting the given values, we get:

theta = tan^-1[(1.98m/s) / (0.701m/s)] = 71.3 degrees

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The average rate of production of the aerogel is 50,000 grams per minute.

Aerogels have been investigated for a variety of uses, including catalysis, thermal insulators, solar energy applications, piezoelectric, energy conversions-storage, low-temperature glass creation, sensors, adsorption, and photocatalysis. They are porous and have low density structures.

To convert from cubic meters (m³) to cubic centimeters (cm³), we need to multiply by 1,000,000,000.

0.360 m³ = 0.360 × 1,000,000,000 = 360,000,000 cm³

So the company can produce 360,000,000 cm³ of aerogel in 24 hours.

Let's assume it's 0.2 g/cm³ (this is a typical value for silica aerogel).

Mass = density x volume

Mass = 0.2 g/cm³ x 360,000,000 cm³

Mass = 72,000,000 grams

The company can produce 72,000,000 grams of aerogel in 24 hours.

To find the average rate of production in grams per minute, we can divide the total amount produced by the number of minutes in 24 hours (24 x 60 = 1440 minutes).

Average rate of production = 72,000,000 grams / 1440 minutes

Average rate of production = 50,000 grams/minute (to the nearest thousand)

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the force between the two wires if they are separated by 2.50 cm is 0.525 N.

Given that force F between two parallel wires carrying electric currents is inversely proportional to the distance d between the wires and that a force of 0.750 N exists between wires that are 1.75 cm apart and that we are supposed to find the force between them if they are separated by 2.50 cm.

Let the initial force be F₁ and the initial distance be d₁.

Therefore, we can write the relationship between force and distance as;

F₁d₁ = F₂d₂

Where

;F₁ = 0.750 N (initial force)

d₁ = 1.75 cm (initial distance)

F₂ = ? (force at new distance)

d₂ = 2.50 cm (new distance)

Let us find F₂;F₁d₁ = F₂d₂F₂ = F₁d₁/d₂

Now substitute the values we know;

F₂ = (0.750 N x 1.75 cm) / 2.50 cmF₂ = 0.525 N

Therefore, the force between the two wires if they are separated by 2.50 cm is 0.525 N.

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Given

mj = 65 kg

mc = 78 kg

voj = 5.75 m/s

after collision

vfj = vfc = 0 m/s

Procedure

The law of momentum conservation can be stated as follows. For a collision occurring between object 1 and object 2 in an isolated system, the total momentum of the two objects before the collision is equal to the total momentum of the two objects after the collision.

The velocity before the collision would be 4.8m/s

Answer:

See below

Explanation:

Force X distance = work

 200 N * 240 m = 48 000 N-m = 48 000 j

F = ma

200 = 800 a

a = 1/4 m/s^2

d = v t  + 1/2 a t^2

12 m/s t  + 1/2  1/4 m/s^2  t^2 = 240

                shows t = 17 sec  (via Quadratic Formula)

final velocity = 12 + at = 12 + 1/4(17) = 16.26 m/s

Performing a blind finger sweep is not recommended as it may push the object further into the airway or cause injury.

Performing a blind finger sweep involves blindly inserting a finger into a person's mouth or throat to remove an obstructing object. While this approach may seem instinctive, it can be dangerous and ineffective.

When an object is lodged in the airway, the natural reaction is to clear it by sweeping a finger to dislodge or extract the obstruction. However, this technique can inadvertently push the object deeper into the airway, making the situation worse.

When an object obstructs the airway, the primary goal is to remove it without causing harm. The blind finger sweep technique lacks precision and may lead to unintended consequences.

The object can become lodged in the throat or cause further blockage, potentially obstructing the person's breathing entirely. In addition, blindly reaching into the mouth can cause injury to the person's throat or oral cavity, further exacerbating the situation.

Instead of performing a blind finger sweep, it is advisable to follow proper first aid protocols for airway obstruction. For conscious individuals who can cough or speak, encourage them to continue coughing forcefully, as coughing is a natural reflex that helps dislodge foreign objects.

If the person is unable to cough or speak, perform abdominal thrusts (Heimlich maneuver) or back blows (for infants), as appropriate, to aid in dislodging the obstruction. It is crucial to seek medical assistance promptly to ensure proper treatment and evaluation.

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At the equilibrium position in SHM, the acceleration of the mass is zero, the speed is at a maximum, and the potential energy is zero. Option C is correct choice.

In simple harmonic motion (SHM), a mass attached to a spring oscillates back and forth around its equilibrium position. At the equilibrium position, the displacement of the mass from its equilibrium position is zero, and the restoring force of the spring is also zero. This means that the mass does not experience any net force at this point, and thus its acceleration is zero.

At the equilibrium position, the mass has maximum speed because it has been accelerated towards the equilibrium position by the restoring force of the spring, and then decelerated by the same force as it passes through the equilibrium position. At this point, all of the potential energy stored in the spring has been converted into kinetic energy. Therefore, the kinetic energy of the mass is a maximum, and the potential energy is zero. Option c is  correct choice.

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Answer:

Given,

Object distance, u=25cm

Focal length, f=20cm

From mirror formula

f

1

​

=

v

1

​

+

u

1

​

−20

1

​

=

v

1

​

−

25

1

​

⇒

v

1

​

=−

20

1

​

+

25

1

​

v=100cm

The image will be real, inverted magnified

Explanation:

Given,

Object distance, u=25cm

Focal length, f=20cm

From mirror formula

f

1

​

=

v

1

​

+

u

1

​

−20

1

​

=

v

1

​

−

25

1

​

⇒

v

1

​

=−

20

1

​

+

25

1

​

v=100cm

The image will be real, inverted magnified

A spinning top (also called easily a top) is a specific toy that does not utilize the gyroscope effect during its movement.

The gyroscope effect refers to the characteristic that allows an object to maintain a constant direction of axis rotation when it is rotating.

This effect (gyroscope effect) mainly depends on the velocity of the object and its direction.

The gyroscope effect is exploited by many applications such as in missiles or satellites when they are in orbit.

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Answer:

465000 meters

Explanation:

kilometer to meter = ×1000

465 × 1000 = 465000

Answer:

465000 M

Explanation:

1Km = 1000m

465Km= (465)(1000)

465000

The battery is 3 volts and the resistor is 100 ohms. The ammeter has a fuse that blows when you try to put too much current through it, like more than 10 amps. The current through the ammeter is 0.03 amps.

In order to determine the current through the ammeter, we can use Ohm's law, which states that current (I) is equal to voltage V divided by resistance (R), Or I= V/R.In this case, the voltage of the battery is 3 volts and the resistance of the resistor is 100 ohms. therefore the current through the circuit is :I = V/R I = 3/100 I = 0.03 amps.

Since the ammeter has a fuse that blows when the current exceeds 10 amps and the current in this circuit is only 0.03 amps, there is no risk of blowing the fuse. The ammeter will simply measure the current flowing through the circuit, which is 0.03 amps.

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A 25.5 kg video cart is rolled down a hallway. It is accelerated at 0.12 m/s2. If a force of 30 N is applied to move the cart . The wheels have 26.4 N  force of friction against the floor

Force of friction is that force  that resists the sliding or rolling of one solid object over another

F(applied) - friction = F net

30 - fr = mass * acceleration

30 - fr  = 25.5  *  0.12  

fr = 30 - 3.06

  = 26.4 N

The wheels have 26.4 N  force of friction against the floor

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Explanation:

Are the compounds formed by the ionic bonding or electronic bonding. They are formed by transferring the electron form one element's valance shell to other element's shell.

i hope it helps...

Answer:

im not sure, but i think...

Explanation:

the harpy eagle???

Answer:

1 * .04 + 2 * .00302 + 3 * .0011 = .04934

He is still within .05

Answer:

A gas is a state of matter in, which atoms remains in a constant motion, they do not stick together. They are free and can move in all directions. The gas molecules expands to fill the available space.

Explanation:

hope this helps! (please give me brainliest, but you do not have to tho)

Answer:

A gas is a state of matter in, which atoms remains in fast  motion,  the gas molecules expands to fill the available space.so the answer would be The atoms in a gas move at high speed. i hope this helped :)  also remember Gas is a state of matter that has no fixed shape and no fixed volume.

Explanation:

Answer:

warm rises cold sinks

Explanation:

Answer:

Explanation:

This problem bothers on the simple harmonic motion of a loaded spring

Given data

mass attached, m= 0-.675 kg

spring constant, k= 72.4 N/m

the period of oscillation can be solved for using the formula bellow

\(T= 2\pi \sqrt{\frac{m}{k} }\)

Substituting the given data into the expression above we have

\(T= 2*3.142\sqrt{\frac{0.675}{72.4} }\\T= 6.284*\sqrt{0.0093 }\\T= 0.6\)

T= 0.6 sec

Answer:

0.607

Explanation:

Trust me

None of the statements are true except for "Decreasing acceleration is also called deceleration."

Acceleration is the rate of change of velocity, so it involves a change in velocity over time.
A change in speed will result in a change in acceleration, but not necessarily in the same direction.
A decrease in speed will result in a change in acceleration, but the acceleration will be in the opposite direction of the initial velocity.
Constant acceleration means that the acceleration is not changing, so it is not constantly changing.

I hope this helps :)

A change in speed is acceleration ... it can be constant or changing.

Decreasing acceleration is also called deceleration. No.

A decrease in speed is acceleration ... it an be constant or changing.

Constant acceleration is constantly changing. No.

The initial velocity and the height of this building are 29 m/s and 780 meters respectively.

In order to calculate the initial velocity, we would apply the second equation of motion:

S = ut - ½at²

200 = u10 - ½(9.8 × 10²)

200 = u10 - 490

u10 = 490 - 200

u10 = 290

u = 290/10

Initial velocity, u = 29 m/s.

Next, we would determine the height of the building:

H = ut + ½at²

H = 29(10) + ½(9.8 × 10²)

H = 290 + 490

Height, H = 780 meters.

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Signals generated by transducers are normally of the order of microvolts to millivolts.

What are transducers?

Transducers are electrical components that transform energy from one form into another. They are electrical sensors that generate an electrical signal based on the quantity being assessed.

A transducer is a device that transforms a physical quantity such as force, pressure, or temperature into an electrical signal. This electrical signal can then be amplified, filtered, or measured in other ways.

Some common examples of transducers include microphones, strain gauges, accelerometers, and thermocouples.

What are the signals generated by transducers?

The signals generated by transducers are normally of the order of microvolts to millivolts. The magnitude of the signal generated depends on the quantity being assessed, as well as the type and sensitivity of the transducer.

In order to use the signal generated by a transducer, it is usually necessary to amplify and filter the signal to remove noise and unwanted frequencies. This can be done using an amplifier or other signal processing equipment.

Overall, the signals generated by transducers are a crucial part of many electronic systems and are used in a wide variety of applications.

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