Imagine you have a barrel that contains thousands o candies with several different colors. We know that the manufacturer produces 35% yellow candles Five students each take a random sample of 20 candies, one at a time, and record the percentage of yellow candies in their sample. Which sequence below is the most plausible for the percent of yellow candies obtained in these five samples? 30%, 35%, 15%, 40%, 50%. 35%, 35%, 35%, 35%, 35%. 5%, 60%, 10%, 50%, 95%. Any of the above.

Answer:

24

Step-by-step explanation:

12 tablespoons= 1/4 cup

So 24= 1/2 cup

(a) A nonzero vector orthogonal to the plane through the points P, Q, and R is (9, -17, 35). (b) The area of triangle PQR is \(\sqrt\)(811) / 2.

(a) To determine a nonzero vector orthogonal to the plane through the points P, Q, and R, we can first find two vectors in the plane and then take their cross product. Taking vectors PQ and PR, we have:

PQ = Q - P = (5, 1, -2) - (-4, 0, 0) = (9, 1, -2)

PR = R - P = (6, 4, 1) - (-4, 0, 0) = (10, 4, 1)

Taking the cross product of PQ and PR, we have:

n = PQ x PR = (9, 1, -2) x (10, 4, 1)

Evaluating the cross product gives n = (9, -17, 35). Therefore, (9, -17, 35) is a nonzero vector orthogonal to the plane through points P, Q, and R.

(b) To determine the area of triangle PQR, we can use the magnitude of the cross product of vectors PQ and PR divided by 2. The magnitude of the cross product is given by:

|n| = \(\sqrt\)((9)^2 + (-17)^2 + (35)^2)

Evaluating the magnitude gives |n| = \(\sqrt\)(811).

The area of triangle PQR is then:

Area = |n| / 2 = \(\sqrt\)(811) / 2.

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The expected return and standard deviation for the following portfolios using the portfolios are given below:

a) Expected Return in Security z is 15% and in security Y is 35%.

standard deviation is 20% and 40% respectively

Expected Return = (WA*RA) + (WB*RB) + (Wn*Rn)

Portfolio Standard Deviation

σP = (wA²σA² + wB² σB² + 2wAwB x σAσB x ρAB)\(^\frac{1}{2}\)

Case I: All in Z (Single Asset portfolio)

Wz = 100%; Wy=0%

Expected Return = 15%

σ = 20%

Case II: 0.75 in Z and 0.25 in Y

E(r) = (0.15*0.75)+(0.35*0.25)

= 20%

σ = [(0.75)²*(0.20)²+ (0.25)²*(0.40)² +2*0.75*0.25*0.20*0.40*0.25]\(^\frac{1}{2}\)

= √0.04

= 0.2 or 20%

Case III: 0.5 in Z and 0.5 in Y

Expected Return = 0.25 or 25%

σ = \(\sqrt{0.01+0.04+0.01}\)

= 0.2449 or ~25%

Case IV: 0.25 in Z and 0.75 in Y

Expected Return = 0.3 or 30%

σ = \(\sqrt{0.0025+0.09+0.0075}\)

= 0.3162 or 31.62%

Case V: All in Y (Single Asset portfolio)

Wz = 0%; Wy=100%

Expected Return = 35%

σ = 40%

b) The mean-standard deviation frontier

Portfolio               Wz Wy     σP E(R)

1                       100%  0%     20% 15%

2                        75% 25%     20% 20%

3                        50% 50%     25% 25%

4                        25% 75%    31.62% 30%

5                         0% 100%   40% 35%

c) Portfolios om the left side of the efficient frontier may not be preferred by the someone interested in high expected return and low risk portfolios.

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Answer:

V(t) = 14,000(0.89)^t

Step-by-step explanation:

Present value of the Dodge Challenger = $14,000

Present percentage value = 100%

Depreciation value = 11%

Number of years = t

Future value = V(t)

V(t) = Present value of the Dodge Challenger(Present percentage value - Depreciation value)^t

= 14,000(100% - 11%)^t

= 14,000(89%)^t

= 14,000(0.89)^t

V(t) = 14,000(0.89)^t

Since it is a right triangle, we can apply the trigonometric function:

Sin a = opposite side / hypotenuse

Where:

a= angle = x

Opposite side = 5

Hypotenuse= 13

Replacing:

Sin x = 5/13

Solve for x

x = arc sin (5/13)

x= 22.6 = 23 ° (rounded)

Answer : A. 23°

After simplification, 7h+(-9.1d)-13+6d-3.5h is 3.5h-3.1d-13.

According to the question,

We have the following expression:

7h+(-9.1d)-13+6d-3.5h

Now, we will simplify it by adding or subtracting the numbers or the numbers with the same variable together. For example, 3.5h can only be subtracted from 7h because both of them h as a variable. And 6d can be subtracted from 9.1d.

(More to know: when a positive and a negative number is multiplied then the result is always negative. In this case, we will multiply +1 into -9.1d.)

Now, let's simplify the given expression:

7h-3.5h-9.1d+6d-13

3.5h-3.1d-13

Hence, the expression obtained after solving the given expression is 3.5h-3.1d-13.

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The ratio of the weight of a semi-truck trailer tire compared to the weight of a mobile home will be 51: 52.

The utilization of two or more additional numbers that compares is known as the ratio.

The weight of the semi-truck trailer tire is 102 pounds.

The weight of the mobile home is 104 pounds.

The ratio of the weight of a semi-truck trailer tire to a mobile home is given as.

Ratio = 102 / 104

Ratio = 51 / 52

Ratio = 51: 52

The ratio of the weight of a semi-truck trailer tire to a mobile home will be 51: 52.

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Answer:

135

Step-by-step explanation:

135+45=180, and supplementary angles always equal 180

Answer:

The answer is 135

Step-by-step explanation:

Definition of supplementary angles: either of two angles whose sum is 180°, so 180 - 45 = 135!

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To find the equation of the tangent to the curve at the point (0, 0), we need to find the derivative of the curve with respect to t and evaluate it at t = 0. Let's differentiate x and y with respect to t:

dx/dt = 9cos(t)

dy/dt = 2t + 1

Evaluating dx/dt and dy/dt at t = 0 gives:

dx/dt = 9cos(0) = 9

dy/dt = 2(0) + 1 = 1

Therefore, the slope of the tangent line at (0, 0) is dy/dx = (dy/dt)/(dx/dt) = 1/9. Using the point-slope form of a linear equation, we can write the equation of the tangent line as y - y1 = m(x - x1), where (x1, y1) is the point of tangency. Plugging in the values (0, 0) and m = 1/9, we get:

y - 0 = (1/9)(x - 0)

y = (1/9)x

Graphically, the curve x = 9sin(t), y = t^2 + t represents a spiral-like shape, while the tangent line at (0, 0) is a straight line with a slope of 1/9. The tangent line intersects the curve at the origin and appears to "touch" the curve at that point.

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Step-by-step explanation:

Let's solve your equation step-by-step.

4(x−3)−x−1=3x−12

Step 1: Simplify both sides of the equation.

4(x−3)−x−1=3x−12

(4)(x)+(4)(−3)+−x+−1=3x+−12(Distribute)

4x+−12+−x+−1=3x+−12

(4x+−x)+(−12+−1)=3x−12(Combine Like Terms)

3x+−13=3x−12

3x−13=3x−12

Step 2: Subtract 3x from both sides.

3x−13−3x=3x−12−3x

−13=−12

Step 3: Add 13 to both sides.

−13+13=−12+13

0=1

Answer:

(-5/2, 4)

Second quadrant

Step-by-step explanation:

Mathematically, we can calculate the midpoint using the formula;

(x,y) = (x1 + x2)/2, (y1 + y2/2

We have;

(x,y) = (-4-1)/2, (3+5)/2

(x,y) = (-5/2, 4)

to get the quadrant, as we can see, this is negative x and positive y and that makes it the 2nd quadrant

a) The line integral over C is:

∫C F dr = ∫r1 F dr + ∫r2 F dr = 2/5 + 1 = 7/5.

b) The potential function at (-1,1) and (1,1) yields:

∫C F dr = f(1,1) - f(-1,1) = 2.

Parametrize the first segment of C from (-1,1) to (0,0) as r1(t) = (-1+t, 1-t) for 0 ≤ t ≤ 1.

Then the line integral over this segment is:

\(\int r1 F dr = \int_0^1 F(r1(t)) \times r1'(t) dt\)

=\(\int_0^1 (3(-1+t)^2(1-t)^2, -2(-1+t)^3(1-t)) \times (1,-1)\) dt

=\(\int_0^1 [6(t-1)^2(t^2-t+1)]\)dt

= 2/5

Similarly, parametrize the second segment of C from (0,0) to (1,1) as r2(t) = (t,t) for 0 ≤ t ≤ 1.

Then the line integral over this segment is:

∫r2 F dr = \(\int_0^1 F(r2(t)) \times r2'(t)\) dt

= \(\int_0^1(3t^4, 2t^3) \times (1,1) dt\)

= \(\int_0^1 [5t^4] dt\)

= 1

The line integral over C is:

∫C F dr = ∫r1 F dr + ∫r2 F dr = 2/5 + 1 = 7/5.

Let f(x,y) = \(x^3 y^2\).

Then the gradient of f is:

∇f = ⟨∂f/∂x, ∂f/∂y⟩ = \((3x^2 y^2, 2x^3 y)\).

∇f = F, so F is a conservative vector field and the line integral over any path from (-1,1) to (1,1) is simply the difference in the potential function values at the endpoints.

Evaluating the potential function at (-1,1) and (1,1) yields:

f(1,1) - f(-1,1)

= \((1)^3 (1)^2 - (-1)^3 (1)^2\) = 2

∫C F dr = f(1,1) - f(-1,1) = 2.

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Answer:

x=-2

Step-by-step explanation:

2x+6-17=4x-7

-2x=4

x=4/-2

Hi!

This has one solution.

2(x+3)-17= 3x -7 +x

Distibute on left side and add like terms on right.

2x + 6 - 17 = 4x - 7

Simplify left side.

2x - 11 = 4x - 7

Subtract both sides by 2x and add 7 to both sides.

-4 = 2x

Divide both sides by 2.

-2 = x

Answer:

y = 3x - 1

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 3x + 2 ← is in slope- intercept form

with slope m = 3

Parallel lines have equal slopes , then

y = 3x + c ← is the partial equation

To find c substitute (3, 8 ) into the partial equation

8 = 9 + c ⇒ c = 8 - 9 = - 1

y = 3x - 1 ← equation of parallel line

The function f(t) is defined as e raised to the power 5t plus 4t plus the natural logarithm of the quantity t squared plus 3 times the constant c, raised to the power of 7, plus t times e raised to the power of -1 plus 5 times e raised to the power of 6.

Given a function:

f(t)=e5t+4t+7ln(t2+3c)+te-1+5e6

where c is a constant.

The solution to the question is shown below.

Step 1: We have given a function:

f(t)=e5t+4t+7ln(t2+3c)+te-1+5e6

We have to find the number of words we have to write to express this function in words.

Step 2: Solution

f(t) = et5+4t + ln(t²+3c)⁷ +te-1+5e⁶

Where,

et5+4t = exponential function

ln(t²+3c)⁷ = natural logarithmic function

te-1 = linear function

e⁶ = exponential function

Therefore, f(t) can be expressed in words as:

The function f(t) is defined as e raised to the power 5t plus 4t plus the natural logarithm of the quantity t squared plus 3 times the constant c, raised to the power of 7, plus t times e raised to the power of -1 plus 5 times e raised to the power of 6.

Step 3: Conclusion

Hence, the function f(t) can be expressed in words with:The function f(t) is defined as e raised to the power 5t plus 4t plus the natural logarithm of the quantity t squared plus 3 times the constant c, raised to the power of 7, plus t times e raised to the power of -1 plus 5 times e raised to the power of 6.

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Answer: 12.5 pounds

Step-by-step explanation:

How many times greater, 75=6x

divide by 6

Answer:

0,7 or 70 cent

Step-by-step explanation:

4.9 ÷ 7

=0,7

All of the given options are generally correct regarding the considerations for Maximum Time Frame calculations.

Let's break down each option:

a. If you take an Incomplete or Withdrawal, this will not be included: In most cases, if you receive an Incomplete or withdraw from a course, the units for that particular course will not be included in the calculation for Maximum Time Frame.

b. F grades won't count toward your Max Time Frame: Usually, failing grades (F) are not counted towards the Maximum Time Frame calculation since they do not contribute to earned credits.

c. When you withdraw from a class, it's taken out of the calculation for Max Time Frame: Generally, when you withdraw from a class, the units for that class are not considered in the calculation for Maximum Time Frame.

d. If you drop a class before the drop/add deadline, it will not show up as an attempted class: Typically, if you drop a class before the drop/add deadline, it will not be considered as an attempted class and therefore will not be included in the Maximum Time Frame calculation.

However, it's important to note that policies regarding Maximum Time Frame calculations may vary among educational institutions. It's always advisable to consult your institution's specific policies or contact the appropriate academic advisors for accurate information regarding Maximum Time Frame calculations at your institution.

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Answer:

138

Step-by-step explanation:

$ 11.50 x 12 = 138

Therefore, the correct option is 39.364.

When conducting a test at the 5% significance level, the critical value of\( χ2df is 39.364\).

The χ2 distribution is a continuous probability distribution that is commonly used in statistics to determine the variance of a population or the goodness of fit of a sample to an anticipated distribution. In the given question, we have to calculate the critical value of χ2df when conducting the test at the 5% significance level.The formula for calculating χ2 is:χ2=(n−1)s2σ2

Where, n is the sample size, s2 is the sample variance, and σ2 is the population variance .The null hypothesis H0 of this test is:H0:σ2=50The alternative hypothesis Ha of this test is:Ha:σ2≠50So, the degrees of freedom are:\(df=n−1=25−1=24\)The χ2 critical value with 24 degrees of freedom at the 5% significance level is:χ2df=39.364

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To find the height of the cylinder, we can use the formula for the volume of a cylinder, which is V = πr²h, where V is the volume, r is the radius, and h is the height.

We are given the volume and the radius, so we can substitute these values into the formula and solve for h.

First, we need to convert the volume from milliliters to cubic centimeters, since the units of the formula are in cubic centimeters. We know that 1 milliliter is equal to 1 cubic centimeter, so we can simply use 1,494.54 cm³ as the volume.

V = πr²h

1,494.54 = π(5.7)²h

1,494.54 = 102.06πh

h = 1,494.54 / 102.06π

h ≈ 4.56 cm

Therefore, the height of the cylinder is approximately 4.56 cm.

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Answer:

-18

Step-by-step explanation:

because you take 40 + -58 and you can make the positive and negative sign a negative so now it would be 40-58

if you reverse it to make it 58-40 you would get 18 and then reverse it back to negative because you reversed it once so now its -18

Answer:This is -8/10 which can be reduced to -4/5

Answer:

c =√a2 + b2=√152 + 122=√369=19.20937

∠α =arcsin(a)c= arcsin(15)19.209372712299=arcsin(0.78086880944303) = 51.34° = 51

answer is C

Answer:

Tan x = opp/ adj

Tan x = 15 / 12

Tan x = 1.25

Angle = 51.34

C. 51 degrees

HOPE ITS HELPS..!!

The expected value per ticket from the standpoint of the charity is $0.27.

The expected value represents the average amount that the charity earns by selling one ticket. In this case, the charity plans to sell 1100 tickets at a cost of $1.00 each, resulting in a total revenue of $1100.00. Since there is only one prize worth $400.00, the charity's net earnings will be $700.00 ($1100.00 - $400.00) if all the tickets are sold.

To calculate the expected value per ticket, we divide the net earnings by the number of tickets sold, which is $0.64 ($700.00 / 1100). Rounded to the nearest cent, the expected value per ticket is $0.27.

The expected value is a useful concept for assessing the potential outcomes of an event. In this context, it helps the charity estimate the average amount they can expect to earn per ticket sold. It is important to note that the expected value is not necessarily the actual amount that will be earned from each ticket, as individual outcomes can vary. However, it provides a baseline estimate based on probabilities and can help the charity make informed decisions about their fundraising efforts.

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Answer:

Actually, I am not sure about the Ans of 6 no.

please mark me brilliant

To determine the final value of the time function f(t) corresponding to the one-sided Laplace transform F(s) = 40 / ((s + 10)(s^2 + 4)), we need to find the value of f(t) as t approaches infinity.

The final value theorem states that if the limit as s approaches 0 of sF(s) exists, then the final value of f(t) is equal to that limit. In this case, we can calculate the limit by evaluating the numerator of F(s) at s = 0.

By substituting s = 0 into the denominator of F(s), we find that both (s + 10) and (s^2 + 4) evaluate to 10 and 4, respectively. Thus, the denominator becomes 10 * 4 = 40.

Now, substituting s = 0 into the numerator, we obtain 40. Therefore, the final value of the time function f(t) is 40.

In summary, the final value of the time function f(t) corresponding to the given one-sided Laplace transform is 40.

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After 1 hour, the alcohol percentage of the beer in the tank will be approximately 5.62%. Initially, the tank contains 100 gallons of beer with 5% alcohol, resulting in 5 gallons of alcohol. The alcohol percentage is approximately 3.2/40 * 100 = 8%.

For every minute, 1 gallon of beer with 7% alcohol is pumped in, contributing 0.07 gallons of alcohol. At the same time, 2 gallons of beer are drained from the tank, resulting in a loss of 0.1 gallons of alcohol. After 60 minutes, a total of 60 gallons of 7% alcohol beer is pumped in, adding 4.2 gallons of alcohol. Meanwhile, 120 gallons of beer are drained out, removing 6 gallons of alcohol. Combining the initial alcohol content with the inflow and outflow, we find that the tank contains 100 + 60 - 120 = 40 gallons of beer after 1 hour, with 5 + 4.2 - 6 = 3.2 gallons of alcohol. Thus, the alcohol percentage is approximately 3.2/40 * 100 = 8%.

In conclusion, after 1 hour, the beer in the tank will have an alcohol percentage of approximately 5.62%. The calculation takes into account the initial alcohol content, the inflow rate of beer with higher alcohol percentage, and the outflow rate of the mixed beer. By considering the amounts of alcohol gained and lost during the hour, we determine that the tank will contain 40 gallons of beer with 3.2 gallons of alcohol. Dividing the alcohol content by the total volume of beer and multiplying by 100 yields the final alcohol percentage.

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The probability that the mean weight of 20 randomly picked fruit will be between 752 grams and 766 grams can be calculated using the Central Limit Theorem. According to the Central Limit Theorem, if the sample size is large enough, the sampling distribution of the mean will be approximately normally distributed regardless of the shape of the population distribution.

In this case, the mean weight of the fruit is normally distributed with a mean of 744 grams and a standard deviation of 37 grams.

To find the probability, we need to standardize the values of 752 grams and 766 grams using the formula z = (x - μ) / (σ / √n), where z is the standard score, x is the value, μ is the mean, σ is the standard deviation, and n is the sample size.

For 752 grams:
z1 = (752 - 744) / (37 / √20) = 0.589

For 766 grams:
z2 = (766 - 744) / (37 / √20) = 1.573

Now, we can use a standard normal distribution table or a calculator to find the probability between these two z-scores.

Using the standard normal distribution table, the probability between z1 = 0.589 and z2 = 1.573 is approximately 0.1398 or 13.98%.

Therefore, the probability that the mean weight of 20 randomly picked fruit will be between 752 grams and 766 grams is approximately 0.1398 or 13.98%.

Please note that the calculation assumes the weights of the fruit are independent and identically distributed.

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Answer:

B

Step-by-step explanation:

Answer choice B would equal -3/4