Imagine you work as a consultant, and your daily job involves listening to the constructive criticism of others. As part of your job, you must listen to opposing viewpoints to make important decisions. In this activity, you are a consulting dam engineer. You must make a decision about four different dams; should they be repaired, taken down, or left alone? You will listen to contrasting opinions about what should be done with the dams before you make the final decision. As the consulting dam engineer, what do you decide to do with this dam? Explain your reasoning. By making your decision, did you support the opinions of the mayor and/or the dam safety official? Why or why not? (Site 1)

Tension is a force along the length of a medium, especially a force carried by a flexible medium, such as a rope or cable.

The tension in the cord is approximately 10624 N.

To solve this problem, we can use the principles of Newton's laws and apply them to each of the objects involved. We will also use the fact that the tension in the cord is the same on both sides of the pulley (neglecting any friction or mass in the pulley).

First, we can consider the forces acting on the block (m1). The only forces acting on the block are its weight (mg) and the tension in the cord (T), which is directed upward. We can resolve these forces into components parallel and perpendicular to the inclined plane:

The weight of the block has a component parallel to the inclined plane given by \(mg*sin(θ)\).

The tension in the cord has a component parallel to the inclined plane given by \(T*sin(θ)\).

Using Newton's second law, we can write:

\(m1 * a = T * sin(θ) - m1 * g * sin(θ)\)

where a is the acceleration of the block down the inclined plane.

Next, we can consider the forces acting on the sphere (\(m2\)). Since the sphere is hanging from the cord, the only force acting on it is its weight (\(mg\)), which is directed downward. Using Newton's second law, we can write:

\(m2 * a = m2 * g - T\)

where a is the acceleration of the sphere downward.

Since the cord is assumed to be massless and the pulley is assumed to be frictionless, the tension in the cord is the same on both sides of the pulley. Therefore, we can set the two expressions for T equal to each other:

\(T * sin(θ) - m1 * g * sin(θ) = m2 * g - T\)

Solving for T, we get:

T = \((m2 + m1) * g / (sin(θ) + 1)\)

Substituting the given values, we get:

T = \((540 kg + 2.00 kg) * 9.81 m/s^2 / (sin(49.0°) + 1)\)

T = 10624 N (to three significant figures)

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Answer: 0

Explanation: Work is force times displacement so although you're exerting a force on the chair since your not moving there is no displacement and anything times a value of zero is zero

Answer:

2.8s

Explanation:

=>a = v-u/t

=> t = v - u / t

= 28-0 / 10

= 2.8 s

Answer:

the magnitude F of the total friction force is 2456.7 lb

Explanation:

Given the data in the question;

maximum speed = 35 mi/hr = ( 35×5280 / 60×60) = 51.3333 ft/s

diameter = 200ft

radius = 200/2 = 100 ft

First we calculate the normal component of the acceleration;

\(a_{n}\) = v² / p

where v is the velocity of the car( 51.3333 ft/s)

p is the radius of the curvature( 100 ft)

so we substitute

\(a_{n}\) = (51.3333 ft/s)² / 100ft

\(a_{n}\) = (2635.1076 ft²/s²) / 100ft

\(a_{n}\) = 26.35 ft/s²

we convert Feet Per Second Squared (ft/s²) to Standard Gravity (g)

1 ft/s² = 0.0310809502 g

\(a_{n}\) = 26.35 ft/s² × 0.0310809502 g

\(a_{n}\) =  0.8189g

Now consider the dynamic equilibrium of forces in the Normal Direction;

∑\(F_{n}\) = m\(a_{n}\)

F = m\(a_{n}\)

we know that mass of the car is 3000-lb =  3000lb(\(\frac{1}{g}slug\)/1 lb)

so

we substitute

F =  3000lb(\(\frac{1}{g}slug\)/1 lb)  × 0.8189g

F = 2456.7 lb

Therefore; the magnitude F of the total friction force is 2456.7 lb

Explanation:

To determine the force F of interaction between the half ring and the point charge, we can use the principle of superposition, which states that the total force on a point charge due to a collection of other charges is the vector sum of the individual forces that each of those charges would exert on the point charge if it were the only charge present.

First, we need to find the electric field at the center of curvature due to the charged half ring. The electric field at a point on the axis of a uniformly charged ring is given by:

E = kqz / (z^2 + R^2)^(3/2)

where k is Coulomb's constant, q is the linear charge density, z is the distance from the center of the ring to the point on the axis, and R is the radius of the ring.

At the center of curvature of the half ring, z = R, so the electric field is:

E = kq / (2R)

Next, we can use the electric field to find the force on the point charge q:

F = qE

Substituting the given values, we get:

F = (20 x 10^-9 C) x (9 x 10^9 N·m^2/C^2) x (1/20 cm)

F = 9 x 10^-3 N

Therefore, the force of interaction between the half ring and the point charge is 9 x 10^-3 N.

This force can also be interpreted as the force required to hold the point charge at the center of curvature against the electric field due to the charged half ring. It is an attractive force because the point charge is opposite in sign to the charged half ring.

Answer:

5.65N.

Explanation:

Solution Given:

radius of R = 10 cm=10/100=0.1 m

linear density λ = 1 Mikrokulon/m= 10^-6 Coulomb/m

force F=?

q1 = 20nC=20*10^-9 C

we have

Coulomb's law, which states that the force between two charges is proportional to the product of the charges and inversely proportional to the square of the distance between them. Mathematically, this can be expressed as:

F = k*(q1*q2)/r^2

since q1 is located at the center of curvature of the half ring , so the half ring is uniformly charged with a linear density of λ= 1 μC/m.

again

equation becomes.

F=k*(q1*λL)/r^2

Since the half ring is a semicircle,

we have L=πr

F=k*(q1*λ*πr)/r^2

substituting value

F=9 x 10^9 N*m^2/C^2 *(20*10^-9 C* 10^-6 m^3*π*0.1 m)/(0.1m^2)

F=5.65 N

Therefore, the force of interaction between the half ring and the point charge is 5.65N.

Answer:

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

mass = Density × volume

From the question we have

mass = 74 × 7

We have the final answer as

Hope this helps you

The ranking is based on the tilt of the Earth's axis and its orbit around the Sun. The figure at 40°N in June receives the most daylight because it is located at a high latitude during the summer solstice in the Northern Hemisphere. The Earth's axis tilts towards the Sun, resulting in longer days and shorter nights. The figure at 40°S in December receives a moderate amount of daylight as it is located at a lower latitude during the summer solstice in the Southern Hemisphere.

The figure at 40°N in December experiences less daylight because it is located at a high latitude during the winter solstice in the Northern Hemisphere, with shorter days and longer nights. Lastly, the figure at 40°S in June receives the least amount of daylight as it is located at a lower latitude during the winter solstice in the Southern Hemisphere, where the days are shortest and the nights are longest. Based on the information given, the ranking of figures based on the amount of daylight they experience in a 24-hour period, from most to least.

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Answer:

The gravitational force of an object that has half the mass is C) 9G.

Explanation:

Newton's Law of Gravitation:

We can see that the gravitational force, \(F_g\), and mass (let's combine M * m into just "m"), \(m\), are directly proportional to each other.

This means that if \(F_g\) increases, \(m\) also increases.

Therefore, if the mass is halved, that means that the gravitational force is also going to be halved.

The answer is 18G / 2 = 9G, which corresponds to answer C) 9G.

The quantity of heat energy that must be transferred to 2.25 kg of brass to raise its temperature from 20 °C to 240 °C is 195030 J

First, we shall list out the given parameters from the question. This is shown below:

The quantity of heat energy that must be transferred can be obtained as follow:

Q = MCΔT

= 2.25 × 394 × 220

= 195030 J

Thus, we can conclude quantity of heat energy that must be transferred is 195030 J

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A car travels 200 km in the first 2.5 hour then stop for half hour then travels the final speed of 200 km in 2 hours. The average speed of the car is 80 km/hour.

To find the average speed of the car, we need to calculate the total distance traveled and the total time taken.

In the first 2.5 hours, the car travels 200 km.

Then, it stops for half an hour.

After that, the car travels another 200 km in 2 hours.

So the total distance traveled is 200 km + 200 km = 400 km.

The total time taken is 2.5 hours + 0.5 hours + 2 hours = 5 hours.

Therefore, the average speed of the car is:

Average speed = total distance / total time

= 400 km / 5 hours

= 80 km/hour.

So the average speed of the car is 80 km/hour.

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Answer:

Let R be the total distance

R²=10.4²+(8.7+2.1)²

R²=10.4²+10.8²

R²=224.8

You square root both sides

R=14.99km

If an airplane takes off, it travels 10.4 km west, 8.7 km north, and 2.1 km up, then using the Pythagorean theorem it is 14.99km from its take-off point.

Pythagoras' theorem is a fundamental theorem in mathematics that relates to the sides of a right-angled triangle. It states that in a right-angled triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides.

In equation form, the theorem can be written as:

c² = a² + b²

Where

c =the length of the hypotenuse,

a and b = the lengths of the other two sides.

The theorem is named after the ancient Greek mathematician Pythagoras, who is credited with his discovery and proof. Pythagoras' theorem is widely used in mathematics and has many practical applications in fields such as architecture, engineering, and physics.

Here in the question

We can use the Pythagorean theorem to find the distance from the takeoff point:

Distance = √(West)² + (North+Up)²

Plugging in the given values, we get:

Distance = √(10.4)² +( 8.7 + 2.1)²

Distance ≈ 14.99km

Therefore, the airplane is approximately 14.99km away from the takeoff point.

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The moment of inertia of the uniform cylindrical grinding wheel is 2,150 kgm².

What is the moment of inertia?

This refers to the angular mass or rotational inertia can be defined with respect to the rotation axis, as a property that shows the amount of torque needed for a desired angular acceleration or a property of a body due to which it resists angular acceleration. The unit is kgm².

From the question:

Mass,M =4.2kg

Radius, R=32Cm

The formula for calculating the moment of inertia for uniform cylindrical grinding wheel:

moment of inertia, I =1/2MR²

I =\(\frac{1}{2}\) * 4.2 * 32²

  =2,150.4 kgm²

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Answer:

c. Work is - on the way up and + on the way down

Explanation:

Work done is given as the product of the applied force and the displacement of the object.

Work done = F x d

Work done = mg x d

where;

g is acceleration due to gravity = 9.8 m/s²

When the ball goes up, it moves against the force of gravity which tends to pull every object downwards. Since the ball moves against gravity, the work done is negative.

Also, when the ball goes down, it moves in the direction of gravity which acts downwards. Since the ball moves in the same direction as gravity, the work done is positive.

The correct option is "C. Work is negative (-) on the way up and positive (+) on the way down"

Answer:

i cant see

Explanation:

but im smart

Answer:

Contact forces are those types of forces that result when the two interacting objects are perceived to be physically contacting each other. Examples of contact forces include frictional forces, tensional forces, normal forces, air resistance forces, and applied forces.

Explanation:

The kinetic energy of the flywheel after 1 minute of rotation, given that it has a mass of 50 and radius of 40 cm is 32.4 KJ (Option D)

We'll begin by obtaining the velocity of the flywheel. This is shown below:

v = at

v = 0.6 × 60

v = 36 m/s

Finally, we shall determine the kinetic energy of the flywheel. Details below:

KE = ½mv²

KE = ½ × 50 × 36²

KE = 25 × 1296

KE = 32400 J

Divide by 1000 to express in KJ

KE = 32400 / 1000

KE = 32.4 KJ

Thus, the kinetic energy is 32.4 KJ (Option D)

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Answer:

Explanation:

Step 1: Subtract 15 from 125

\(125-15=110\)

She traveled 110 miles in 2.75. We need to find her avg. speed.

Step 2: Divide 110 by 2.75

\(110/2.75=40\)

The answer is: Her average speed is 40 miles per hour.

Hope this helped!

Answer: if the predator sees the light bugs easier than the dark bugs then the bright bug will most likely go extinct

Explanation:

A cesium-133 atom's radiation goes through 1.5 million cycles in around 0.1633 microseconds (or 163.3 nanoseconds).

9,192,631,770 hertz (cycles per second) is the frequency of the microwave spectral line that the isotope cesium-133 emits. The basic unit of time is provided by this. Cesium clocks have an accuracy and stability of 1 second in 1.4 million years.

The radiation emitted by cesium-133 has a frequency of 9,192,631,770 cycles per second, or 9.192631770 109 Hz.

The following formula may be used to determine how long 1.5 million radiation cycles take to complete:

Time is equal to the frequency of cycles.

Plugging in the numbers, we get:

time = 1.5 million / 9.192631770 × 10^9 Hz

time = 1.632995101 × 10^-7 seconds

So it takes approximately 0.1633 microseconds (or 163.3 nanoseconds) for radiation from a cesium-133 atom to complete 1.5 million cycles.

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Answer: 1.14 kg*m/s

Explanation:

The first person explained everything right, they just forgot to convert the angular acceleration to rads/sec^2 from revs/sec^2. Once that is converted, your answer should come out right.

Another small thing, the answer there has an extra unnecessary step. It tells you to find the square root of w^2 to find w but that is unnecessary since the final equation asked for w^2. Hope this helps! :)

The moment of inertia I of the flywheel about its rotation axis is

Given

Angular displacement,

\(\theta = 30rev \\\\\theta = (30) * 2\pi rad \\\\\theta = 188.495rad\)

Therefore, Final angular velocity (w) will be:

\(w^2 = 2\alpha\theta\\\\w^2 = 2 * (0.200 * 2\pi) * (188.49)\\\\w^2 = 473.73\\\\w = 21.76 rad/s\)

Therefore,

moment of inertia

\(I = 2 * K / w^2\)

\(I = 2 * 330 / 473.73\)

\(I = 1.39kgm^2\)

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Explanation:

The mechanical energy can be expressed as kinetic and potential energy, given by the equation;

ME=KE+PE

but since the car isn't elevated off the ground nor is it subjected to the restoring force of a spring, we can then say PE=0

ME=KE

The equation of KE=0.5mv²

ME=0.5mv²

32 000=0.5(1600)v²

\(v {}^{2} = \frac{32 \: 000}{1600 \times 0.5} \)

\(v {}^{2} = \frac{32 \: 000}{800} \)

\( {v}^{2} = 40\)

\(v = \sqrt{40} = 6.324\)

v=6.324 m/s :)

Answer:

The difference between them is that the velocity-time graph reveals the speed of an object (and whether it is slowing down or speeding up), while the position-time graph describes the motion of an object over a period of time.

Explanation:

The electrical force between the two charges can be calculated as +1.8×10⁻² N and its repulsive.

To find the electrical force, distance = 2 meters

charge q1 = 2×10⁻⁶ C

charge q2 = 4×10⁻⁶ C

         The force of attraction or repulsion acting along a straight line between two electric charges is directly proportional to the product of the charges and inversely to the square of the distance between them.

Formula can be written as,

          F = K ( q1q2 / r² )

F - electric force

k - Coulomb constant

q1, q2 - charges

r - distance of separation

Substituting the values in the formula,

         F = 9 × 10⁹ Nm²/C² ( (2×10⁻⁶ C ×  4×10⁻⁶ C) / (2²))

            = 0.0179751

         F = 1.8 × 10 ⁻² N.

As both the charges q1 and q2 are positive, the charges gets repulsive.

SO, the correct answer is Option A.

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Okay, here are the step-by-step workings:

The initial temperature was 20 °C

The temperature increase was 10 °C

To convert from °C to °F, use the formula:

°F = (°C × 1.8) + 32

For 20 °C:

°F = (20 × 1.8) + 32 = 68 °F

For the 10 °C increase:

°F Increase= (10 × 1.8) + 32 = 18 °F

So the temperature increase in °F was 18 °F.

The full answer is:

The temperature increase in °F was 18 °F.              Thanks!      

Answer: 30 Years Old

Explanation: The constitution has around three qualifications for service in the U.S. Senate, Your age must be at least 30 years.

Answer:

The accuracy and precision of a result depend on several factors, including:

1. Quality of the measurement tools - Using high-quality measurement instruments can lead to more accurate and precise results.

2. Calibration of instruments - Instruments should be calibrated regularly to ensure accurate and precise readings.

3. Skill of the person performing the measurement - The person performing the measurements must have proper training and knowledge of the tool they're using.

4. Sample size - Increasing the sample size can lead to more accurate results.

5. Sampling bias - If the sample used for the measurement is biased, it can lead to inaccurate or imprecise results.

6. Experimental design - Proper experimental design can help reduce measurement errors and increase accuracy.

Answer:

No, it cannot. The car needs the friction of the surface to drive because the car pushes the surface backwards, and the surfaces makes a reaction force pushing the car forward, and that works because of the friction. In a frictionless surface the tires would rotate in the same place

Answer:

The gravitational field strength (acceleration due to gravity) on the moon is 1.63 m/s²

Explanation:

From the question, the moon has a gravitational field strength (acceleration due to gravity) that is about 1/6 that of  Earth's.

To determine the gravitational field strength (acceleration due to gravity) on the moon, we will multiply the Earth's gravitational field strength (acceleration due to gravity) by 1/6.

Earth's gravitational field strength = 9.8 m/s²

∴ Moon's gravitational field strength = 1/6 × 9.8 m/s²

Moon's gravitational field strength  = 1.63 m/s²

Hence, the gravitational field strength (acceleration due to gravity) on the moon is 1.63 m/s².

Answer:

If the wavelength is doubled, the width of the central bright spot on the screen will increase by a factor of 2 (that is, it will also double).

Explanation:

For a single-slit diffraction, diffraction patterns are found at angles θ for which

w sinθ = mλ

where w is the width

λ is wavelength

m is an integer, m = 1,2,3, ....

From the equation, w sinθ = mλ

For the first case, where nothing was changed

w₁ = mλ₁ / sinθ

Now, If the wavelength is doubled, that is, λ₂ = 2λ₁

The equation becomes

w₂ = mλ₂ / sinθ

Then, w₂ = m(2λ₁) / sinθ

w₂ = 2(mλ₁) / sinθ

Recall that, w₁ = mλ₁ / sinθ

Therefore, w₂ = 2w₁

Hence, If the wavelength is doubled, the width of the central bright spot on the screen will increase by a factor of 2 (that is, it will also double).