imagine you would interview a news Anchor about how they use graphs in presentation of Science in the news think of at least four questions you would ask then imagine how they would answer your question

Answer:

the emission of energy as electromagnetic waves or as moving subatomic particles, especially high-energy particles which cause ionization.

is called radiation

Answer:

Explanation:

I hope it's help u

The question addresses the stability of the atmosphere and the factors that determine convective stability or instability. It also explains the difference between the adiabatic lapse rate of dry air and wet saturated air.

a) The stability of the atmosphere is determined by the temperature profile and relative densities of the air cell and atmosphere. If the temperature of the surrounding atmosphere decreases with altitude at a rate greater than the adiabatic lapse rate of the air cell, the atmosphere is considered convectively stable.

In this case, the air cell will return to its original position. Conversely, if the temperature of the surrounding atmosphere decreases slower than the adiabatic lapse rate of the air cell, the atmosphere is convectively unstable. The air cell will continue moving in the same direction.

b) The adiabatic lapse rate refers to the rate at which temperature decreases with altitude for a parcel of air lifted or descending adiabatically (without exchanging heat with its surroundings). The adiabatic lapse rate of dry air is higher (around \(9.8^0C\) per kilometer) compared to the adiabatic lapse rate of wet saturated air (around 5°C per kilometer).

This difference arises because when water vapor condenses during the ascent of saturated air, latent heat is released, reducing the rate of temperature decrease. A diagram can illustrate the difference between the two lapse rates, showcasing their respective slopes.

c) When wet unsaturated air rises from the ocean surface, its temperature decreases at a rate equal to the dry adiabatic lapse rate. However, if the ambient lapse rate (temperature decrease with altitude) is higher than the adiabatic lapse rate for dry air, a temperature inversion layer forms at higher altitudes.

In this inversion layer, the temperature increases with altitude instead of decreasing. A schematic diagram can depict the temperature changes of the wet air in comparison to the ambient temperature, showing the inversion layer.

Cumulus clouds form at the altitude where the rising moist air reaches the level of the temperature inversion layer. These clouds are formed due to the condensation of water vapor as the air parcel cools to its dew point temperature.

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planets

Explanation:

Answer:

The key benefits to this is the athlete thinks and reflects for themselves which is a vital part of the Learning Styles Model. This technique is most useful for more experienced athletes who like to have involvement and their own opinions about their performance.

Explanation:

Answer: The balloons repel each other but attract the rabbit fur.

Brainliest pwease if I could do you any help!

Here, both the balloons gains a negative charge through rubbing and they attracts to the neutral rabbit fur. But the balloons themselves repel each other. Hence, option B is correct.

When a  material rub on a surface its electrons gets aligned and acquire a negative charge. This negative charge when comes in contact with a neutral material, the second one get partially polarized and gets attracted to the negative charge.

This flow of electrons through induced polarization is called static electricity. When the balloon are rubbed with the neutral rabbit fur and gets negatively charged by friction.

This negatively charged balloons repel each other but they induce a polarity to the neutral rabbit fur and its positive charges gets aligned with the negative charges results in electrostatic attraction.

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Considering the definition of speed, the average speed of the plane is 681.6 m/s.

speed ​​is a quantity that expresses the relationship between the space traveled by an object.

In other words, speed can be defined as the amount of space traveled per unit of time with which a body moves and can be calculated using the expression:

speed= distance traveled÷ time

In this case, you know:

So, in both cases you know the distance traveled and the speed. Therefore, you must calculate the time in which each part of the trip is made, in order to later know the total time. For this, the definition of speed is used:

So, you know:

Replacing in the definition of speed:

speed= 1,090,000 m÷ 1599,1784 s

speed= 681.6 m/s

In summary, the average speed of the plane is 681.6 m/s.

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Answer:

Explanation:

Given:

Mass of bicyclist = 50 kg

Mass of bicycle = 10 kg

Initial velocity (u) = 5 m/s

Final velocity (v) = 10 m/s

Find:

(a) What was the total kinetic energy before accelerating = ?

(b) What was the total kinetic energy after accelerating = ?

(c) How much work was done to increase the kinetic energy of the bicyclist = ?

Computation:

Total mass (M) = 50 kg + 10 kg = 60 kg

1. The total kinetic energy before accelerating = 1/2[Mu²]

The total kinetic energy before accelerating = 0.5[(60)(5)²]

The total kinetic energy before accelerating = 750 J

2. The total kinetic energy after accelerating = 1/2[Mv²]

The total kinetic energy after accelerating = 0.5[(60)(10)²]

The total kinetic energy after accelerating = 3,000 J

3. Total work done = Δ K.E

Total work done = 3,000 J - 750 J

Total work done = 2,250 J

Answer:

c. Y

Explanation:

Newton's third law of motion states that action and reaction are equal and opposite. Hence for every action, there is an equal and opposite reaction.

Considering the system of forces shown in the image, W and Y are  opposite forces. When the driver slams on the brakes, he will be pushed forward towards the windscreen. The force Y exerted by the seat belt keeps him on the drivers seat by moving him backwards towards the seat.

Answer:

First, we need to remember the second Newton's law:

This says that:

F = m*a

Force equals mass times acceleration.

This means that if we apply a force to an object, the object will accelerate.

This also means that if an object is not moving, or moving with a constant velocity, it will keep doing that until a force is applied.

Now let's answer the 3 cases:

a. The baseball is in space and stationary. What will the ball do? Nothing, it will keep being stationary Why? There is no force applied, or the net force is equal to zero.

b. The ball is in space and someone hits it with a bat. What will the ball do? Will move with constant speed Why? A hit with a bat can be thought as a great force applied for a really short period of time, this means that the speed of the ball will increase a lot, but because the force only last for a really short time, after that the ball will keep moving with constant speed.

c. The ball has a small jet pack attached that is continuously firing. What will the ball do? The ball's speed will keep increasing more and more. Why? Now we have a constant force, this means that we will have a constant acceleration, and as we know, the acceleration is the rate of change of the speed, this will mean that the speed of the ball will keep increasing until the jet pack stops firing, and after that, the ball will keep moving with constant speed.

The charge enclosed by a Gaussian sphere of radius r, where 0 < r < r, is q. This is because the charge enclosed by a Gaussian surface only depends on the total charge inside the surface, and not on the shape or size of the surface.

In this case, the conducting sphere of radius r is the same as the Gaussian sphere of radius r, so all of the charge q is enclosed by the Gaussian sphere. As the radius of the Gaussian sphere decreases to zero, the charge enclosed by the sphere also decreases to zero, since there is no charge inside the sphere

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Answer:

v = v +at = 22 + (1.6 6.8 s  ms) = 33 ms

Explanation:

Answer:

do human activity for the

The approximate period of the simple pendulum on the Moon is approximately 15.4 seconds. so option d is correct answer.

The period of a simple pendulum is given by the equation T = 2π√(L/g), where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity. In this case, since the acceleration due to gravity on the Moon is roughly 1/6 that of Earth, we can assume that g on the Moon is approximately g/6.

Let's consider the ratio of the periods on Earth and the Moon:

\(Tmoon / Tearth = 2\pi \sqrt{(L/gmoon)} / 2\pi \sqrt{(L/gearth)}\)

Since the length of the pendulum is the same on both Earth frequency and the Moon, it cancels out in the ratio. Substituting g_moon = g_earth/6, we get:

T_moon / T_earth = √(g_earth / g_earth/6)

Simplifying the equation, we find:

T_moon / T_earth = √(6)

T_moon = √(6) * T_earth

Substituting T_earth = 6.0 s, we get:

Approximating the value of sqrt(6) as 2.45, we can calculate the approximate period on the Moon:

T_moon ≈ 2π * 2.45 ≈ 15.4 s

Therefore, the approximate period of the simple pendulum on the Moon is approximately 15.4 seconds. so We take 15seconds Option d is correct

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The Complete question is

A simple pendulum on Earth has a period of 6.0 s. What is the approximate period of this pendulum on the Moon, where the acceleration due to gravity is roughly 1/6 that of Earth?

a. 1.0s b. 2.4 s c. 36 s d. 15 s

B. A wave travels through medium. Hope this helped!

Answer:

200

Explanation:

P = M x V

P = 8 x 25

P = 200

Answer:

Approximately \(1.3\times 10^{8}\; \rm m\cdot s^{-1}\).

Explanation:

Look up the speed of light in vacuum: \(c \approx 3.00\times 10^{8}\; \rm m\cdot s^{-1}\). Denote the speed as \(c\).

If the speed of light in a medium is \(v\), the refractive index of that medium would be:

\(\displaystyle n = \frac{c}{v}\).

Note, that the refractive index of a medium is inversely proportional to the speed of light in this medium. A medium with a larger refractive index would thus correspond to a slower speed of light.

Rearrange this equation to find the speed of light \(v\) in this medium:

\(\begin{aligned}v &= \frac{c}{n} \\ &= \frac{3.00\times 10^{8}\; \rm m\cdot s^{-1}}{2.4} \\ &\approx 1.25 \times 10^{8}\; \rm m\cdot s^{-1}\end{aligned}\).

Answer:

t = 143.16 seconds

Explanation:

Given that,

The average speed of race horse, v = 16.764 m/s

Distance covered, d = 2400 m

We need to find how long did it take the horse to complete the race. We know that, the average speed is equal to total distance covered per unit time. So,

\(v=\dfrac{d}{t}\\\\\text{Where t is time taken}\\\\t=\dfrac{d}{v}\\\\t=\dfrac{2400\ m}{16.764\ m/s}\\\\t=143.16\ s\)

It will take 143.16 seconds to complete the race.

The five states of matter are solid, liquid, gas, plasma, and Bose-Einstein condensate.

Define states of matter.

One of the various states in which matter can exist is a state of matter. In daily life, we can observe five different states of matter: solid, liquid, gas, ,plasma and Bose-Einstein condensates . Liquid crystal is one of many known intermediate states, and certain states, like  neutron-degenerate matter (in extremely high densities), and quark-gluon plasma (in extremely high energies), only occur in extremely extreme circumstances.

Plasma lacks a defined shape or volume, much like a gas. Plasmas respond strongly to electromagnetic forces, form magnetic fields, and are electrically conductive in contrast to gases.

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Answer: A method of classifying stars by their temperatures and compositions.

Explanation:

The Morgan-Keenan Spectral Classification system is a method of classifying stars by their temperatures and compositions.

The primary factor used to categories stars is their temperature.

The Morgan-Keenan luminosity class (MK or MKK) was developed as a result of the Harvard spectral classification classification scheme does not completely describe the star as it cannot distinguish between stars with the same temperature but different luminosities.

Since then, class I stars have been separated into Ia-O, Ia, and Ib, and classes VI (sub-dwarf), and D (white dwarf) have been added, replacing the original roman numerals between I (supergiant star) and V (main sequence).

The original Harvard classification of the star is supplemented by the MK luminosity class in order to fully define it. For instance, the entire classification of the Sun, which is a main sequence G2 star, is G2V.

The MK luminosity class is added to the Harvard classification of the star in order to fully define it.

A method of classifying stars by their temperatures and compositions is applied in Morgan-Keenan Spectral Classification system.

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The impulse-momentum theorem can be utilized: Change in momentum is an impulse. The impulse is known to be 0.05 Ns (1008+10011). Therefore, the force exerted by each player is equal to 1008+10011 N divided by 0.05.

According to the impulse-momentum theorem, the change in an object's momentum will be proportional to the impulse applied to it. Now that we understand the impulse-momentum theorem, we can see that the same velocity change can be caused by applying a small net force for a long time and a large net force for a short time.

p equals F net t. The impulse-momentum theorem is derived from the equation F net t, which is also referred to as impulse.

The use of airbags in automobiles is one example. Because they can reduce the force exerted on an object involved in a collision, airbags are used in automobiles. By extending the amount of time required to stop the driver and passenger's momentum, airbags accomplish this.

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Answer:

P = 1 / f = 1 / 16.7 = .06 sec      period of 1 revolution

Period of 1/3 revolution = .06 s / 3 = .02 sec

If the light flashes every .02 sec the fan will appear motionless

The time cat will take to run 5.5km is 55.89 minutes.

according to given details,

distance = 13.1m

time = 8 s

speed = ?

distance (b) = 5.5km = 5500m

time = ?

speed = ?

So by using formula,

speed = distance / time

speed = 13.1m/8s

speed = 1.64 m/s

As now we have speed using same formula

s = d / t

t = d / s

t = 5500m / 1.64 m/s

t = 3,353.65 sec

t = 55.89 minutes

Speed is calculated as distance times speed. You need to be aware of the units for distance and time in order to calculate the units for speed. The units in this example will be metres per second (m/s), since the distance is measured in metres (m) and the time is measured in seconds (s).

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Answer:

Explanation:

The picture is cut off so the wrecking ball and its path are not shown. It would be better if the whole picture is available.

Based on the written info, at the bottom of the path, the wrecking ball is moving at 10m/s.

The centripetal acceleration = velocity^2 / radius

= 10^2 / 25

= 100 / 25

= 4m/s^2

The centripetal force = mass * centripetal acceleration

= 600*4

= 2400N

As the ball is moving horizontally at the bottom, net vertical force is zero.

So Tension force in cable = Wrecking ball weight + Centripetal force

= 600*g + 2400

= 6000 + 2400; assuming g is 10m/s^2

= 8400N

Answer:

Hey there!

It does not need a medium to transfer heat.

Let me know if this helps :)

Answer:medium

Explanation:

Got it right on USA test prep

Answer:

The value is  \(w = 7.54 \ m\)        

Explanation:

From the question we are told that

     The length of the crack is  \(a = 0.3 \ m\)

     The  frequency is  \(f = 30.0 \ kHz = 30 *10^{3} \ Hz\)

      The distance outside the cave that is being consider is  \(D = 100 \ m\)

      The speed of sound is \(v_s = 340 \ m/s\)

Generally the wavelength of the wave is mathematically represented as

        \(\lambda = \frac{v}f}\)

=>     \(\lambda = \frac{340 }{30*10^{3}}\)

=>     \(\lambda = 0.0113 \ m/s\)

Generally for a  single slit the path difference between the interference patterns of the sound wave and the center  is mathematically represented as  

          \(y = \frac{ n * \lambda * D}{a}\)

=>     \(y = \frac{ 1 * 0.0113 * 100}{0.3}\)

=>     \(y = 3.77 \ m\)

Generally the width of the sound beam is mathematically represented as

         \(w = 2 * y\)

=>      \(w = 2 * 3.77\)

=>      \(w = 7.54 \ m\)        

Answer: Some places like Florida and California are both very hot and dry places, the sun damages your skin more in sunny places then in colder more breezy places.

Explanation:

Let v be the maximum speed that the motorcycle can have while moving over the crest without losing contact with the road.

Since the hill's crest is a circular arc with a radius of 59.7 m,

its weight W can be resolved into two components: a radial force W cos θ that is perpendicular to the road and a tangential force W sin θ that is parallel to the road.Let's now take a look at the forces acting on the motorcycle. The forces that act on the motorcycle are the gravitational force W, the centripetal force F, and the force of friction f.

As a result, the following equation can be used to find the maximum speed that the motorcycle can have while moving over the crest without losing contact with the road:

`Ff = mv²/r`where `m` is the mass of the motorcycle and `r` is the radius of the circular arc of the hill.

We can calculate the radial component of the weight as

`W cos θ = mg cos θ`, where `m` is the mass of the motorcycle and `g` is the acceleration due to gravity, which is approximately 9.8 m/s².

Substituting `W cos θ` and `W sin θ` into the equation for `Ff`, we have:

`f = µW cos θ` and `F = W sin θ`

Substituting these equations into the equation for `Ff`, we have:

`µmg cos θ = mv²/r - mg sin θ`

Simplifying this expression yields:

`v² = rg(µ cos θ - sin θ)`

Substituting the given values, we have:

`v² = (59.7 m)(9.8 m/s²)(0.9) = 522.7 m²/s²`

Therefore, the maximum speed that the cycle can have while moving over the crest without losing contact with the road is:

`v = sqrt(522.7 m²/s²) = 22.85 m/s`

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