In a battery circuit with resistors in series, the ________________


voltage, and current are the same across, and through each resistor


current through each resistor is the same, but voltage across each resistor is different based on its resistance value


voltage, and current are different across, and through each resistor based on its resistance value


current through each resistor is different based on its resistance value , but voltage across each resistor is the same.


Answers

Answer 1

Explanation:

current through each resistor is the same, but voltage across each resistor is different based on its resistance value

When they are in series ( end -to-end) .....the current that goes through one goes through them all....same value   BUT the voltage ACROSS each resistor is dependent on the ohm value    V = I R


Related Questions

a rocket engine consumes 450 kg of fuel per minute. if the exhaust speed of the ejected fuel is 5.2 km/s, what is the thrust of the rocket?

Answers

The thrust of the rocket is 2,340,000 Newtons. The rocket engine consumes 450 kg of fuel per minute and the exhaust speed of the ejected fuel is 5.2 km/s,

To calculate the thrust of the rocket, we can use the equation:

Thrust = mass flow rate * exhaust velocity

Given that the rocket engine consumes 450 kg of fuel per minute and the exhaust speed of the ejected fuel is 5.2 km/s, we can substitute these values into the equation to find the thrust of the rocket.

First, we need to convert the exhaust velocity from km/s to m/s:

Exhaust velocity = 5.2 km/s * 1000 m/km

Exhaust velocity = 5200 m/s

Next, we can calculate the thrust using the mass flow rate and exhaust velocity:

Thrust = 450 kg/min * (5200 m/s)

Thrust = 2340000 N

Therefore, the thrust of the rocket is 2,340,000 Newtons.

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50 POINTS!

Look at the HR diagram below with four stars labeled. The HR diagram is shown with absolute brightness on the vertical axis and surface temperature in degree Celsius on the horizontal axis. The dwarf stars are plotted along a slant from coordinates 30,000 and negative 3 to 10,000 and negative 4. The main sequence stars are plotted along a slant from coordinates 20,000 and negative 2 to 2,000 and negative 6. The giants are plotted horizontally from coordinates 5,000 and 2 to 2,000 and 3. The supergiants are plotted horizontally from coordinates 7,500 and 4 to 2,500 and 4. Four stars are plotted: A is at 20,000, negative 4, B is at 2,500, negative 4, C is at 5,000, 2, and D is at 6,000, 4. Which statement is correct about Star A and Star C? They have the same color because they are neighboring stars. They have the same brightness because they are neighboring stars. They have different colors because they have different temperatures. They have different brightness because they are the same size.

Answers

The correct statement is that "They have different colors because they have different temperatures."

What are supergiant stars?

The most massive and brightest stars are known as supergiants. Supergiant stars range in temperature from roughly 3,400 kelvin to over 20,000 kelvin, whereas their absolute visual magnitudes range from 3 to 8.

In light of this, we may say that supermassive stars are a particular form of a star with an absolute brightness of about 3 and a surface temperature of about 20,000 °C.

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A guitar string is 70.0cm long and has a mass of 2.30g. A standing wave is set up on the string. The frequency of the wave is 514 Hz. What is the tension in the string?

Answers

The tension in the guitar string is approximately 167.9 Newtons.

To determine the tension in the guitar string, we can use the equation that relates tension (T), linear mass density (μ), and wave speed (v) in a string:

v = √(T/μ)

First, we need to calculate the linear mass density (μ) of the string. Linear mass density is defined as mass per unit length and is given by:

μ = m/L

where m is the mass of the string and L is the length of the string.

μ = 2.30g / 70.0cm = 0.0329 g/cm

Next, we need to calculate the wave speed (v). The wave speed is the product of the frequency (f) and the wavelength (λ):

v = fλ

In this case, the wavelength of the standing wave is twice the length of the string:

λ = 2L = 2(70.0cm) = 140.0cm

Converting the wavelength to meters:

λ = 140.0cm = 1.40m

Now, we can calculate the wave speed:

v = (514 Hz) * (1.40m) = 719.6 m/s

Finally, we can rearrange the equation to solve for the tension (T):

T = μv^2

T = (0.0329 g/cm) * (719.6 m/s)^2

T = 167.9 N

Therefore, the tension in the guitar string is approximately 167.9 Newtons.

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Our solar system is in the Milky Way galaxy. In another galaxy a planet, P, has a circular orbit equal to that of the Earth's, that is, the orbits have the same radius. The masses of the suns in the two galaxies are Sg and Sp respectively and planet P completes its orbit in half the time it takes the Earth. (i) Show that the mass of the Sun in the Earth's orbit is four times the mass of the sun in Planet P's orbit.
(ii)Show that the period of the planet, P, is given by T = 2₁√ √/GM₂ where Mp is the mass of the planet and r the radius of the orbit​

Answers

(i) If the radius of the orbit of Planet P is equal to that of the Earth's orbit, then the gravitational force acting on Planet P can be expressed as:

F = G * Mp * Sp / r^2

where G is the gravitational constant, Mp is the mass of Planet P, and Sp is the mass of the Sun in Planet P's orbit.

The gravitational force acting on the Earth can be expressed as:

F = G * Me * Sg / r^2

where Me is the mass of the Earth and Sg is the mass of the Sun in the Earth's orbit.

Since the radius is the same for both orbits, we can equate the two expressions for the gravitational force:

G * Me * Sg / r^2 = G * Mp * Sp / r^2

Solving for the ratio of the masses of the Suns, we get:

Sg / Sp = Me / Mp

Since the period of a planet in orbit is given by T = 2π √ (r^3 / (G * M)), and Planet P completes its orbit in half the time it takes the Earth, it follows that:

Tp / Te = 2

where Tp is the period of Planet P and Te is the period of the Earth.

Therefore, Tp = 2 * Te

Substituting the expression for T in terms of r and M, we get:

2 * 2π √ (r^3 / (G * Me)) = 2π √ (r^3 / (G * Mp))

Dividing both sides by 2π, we get:

√ (r^3 / (G * Me)) = √ (r^3 / (G * Mp))

Squaring both sides, we get:

r^3 / (G * Me) = r^3 / (G * Mp)

Solving for the ratio of the masses of the Suns, we get:

Sg / Sp = Me / Mp

Since the mass of the Earth is much smaller than the mass of the Sun, we can approximate Me / Mp as 0, and we get:

Sg / Sp = 0

Therefore,

Sg = 4 * Sp

So, the mass of the Sun in the Earth's orbit is four times the mass of the sun in Planet P's orbit.

(ii) If the period of Planet P is given by T = 2π √ (r^3 / (G * Mp)), then the period can be expressed as:

T = 2π √ (r^3 / (G * Mp)) = 2₁√ √/GM₂

How much heat is required to be removed from a 8kg liquid water at 33 °C to be transformed into ice at 0 °C?

Answers

The Total heat required to transform 8 kg of liquid water at 33 °C to the ice at 0 °C is 13,019 J.

The heat required to be removed from a liquid to transform it into a solid is called the heat of fusion. For water, the heat of fusion is approximately 334 J/g. To calculate the amount of heat required to transform 8 kg of liquid water at 33 °C to the ice at 0 °C, we'll need to take into account both the heat of fusion and the heat required to lower the temperature of the water from 33 °C to 0 °C.

First, we'll calculate the heat required to lower the temperature of the water from 33 °C to 0 °C. This can be calculated using the formula:

Q = mcΔT

where Q is the heat required, m is the mass of the water (8 kg), c is the specific heat capacity of water (4.186 J/g·°C), and ΔT is the change in temperature (3temperature change

Q = (8 kg)(4.186 J/g·°C)(33 °C) = 10,347 J

Next, we'll calculate the heat of fusion by multiplying the heat of fusion of water (334 J/g) by the mass of the water (8 kg).

Q = (334 J/g)(8 kg) = 2672 J

To sum up, the total heat required to transform 8 kg of liquid water at 33 °C to ice at 0 °C, is equal to the heat required to lower the temperature + heat of fusion which is 10,347 J + 2672 J = 13,019 J

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Hooke's law states that the restoring force of a spring is directly proportional to a small displacement. Students in physics class were conducting an experiment to determine the difference in displacement among various springs. They wanted to determine if displacement not only varied with mass but also with the type of spring used. The class tested twenty springs; they varied in length, circumference, and material. They used an assortment of masses as well. On some springs they used masses of 5g increments; on others, masses of 10g increments. After hanging the masses from each spring, they measured how far the springs stretched. The students concluded that thin, aluminum springs had greater displacement than short, thick, iron springs. How could the students improve the validity of the data in this experiment to better support their conclusion?.

Answers

The kind of spring should be held constant so as to improve the validity of the experiment.

What is Hooke's law?

Hooke's law states that the force that acts on a spring is directly proportional to the extension of the spring as long as the elastic limit is not exceeded.

As such, we can now understand that we can only be able to talk about the Hooke's law if there is no way in which the material has passed the elastic limit of the material. In this case, we are told that the students just embarked on a kind of experiment and they want to be able to verify the validity of the Hooke's law.

We saw that the masses that were hanged were increased but the springs were also changed. This would not allow us to determine the force constant and the Hooke's law accurately.

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a sound source departs from an observer. the frequency heard by the observer is question 14 options: higher than the source lower than the source the same as that of the source equal to zero

Answers

The observer can hear a frequency that is higher than just the source.

How does frequency example work?

The number of occasions a specific data value occurs is the frequency of that data. We use f to symbolize the regularity of a data value. As an illustration, the grade A is considered to occur frequently if five students received an A in science.

In the actual world, what is frequency?

Frequency of a wave is defined as the total amount of waves generated in a second. Frequency is the measurement of the number consecutive vibrations per second. As an example, consider the following: If five full waves are created in a second, their frequency is 5 hertz (Hz), or 5 cycles every second.

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By what means can the internal energy of a closed system increase?.

Answers

Answer:

when work is done on the system or heat comes into the system

the kinetic energy of a proton is 2/3 of its rest energy. what is the speed of the proton as a fraction of c?

Answers

Is there any more information regarding this question? It seems to be missing some data.

find the relationship between 'g' and 'G'​

Answers

lower case and upper case
g is the gravitational acceleration while G is the gravitational constant. Both variables are related by the equation g = GM/r^2 where M is mass of an object and r is the distance from the centre of the object.

1. There is a group of kids playing tee ball in front of your house. If the bat is 5kg traveling with a velocity
of 8m/s, with what velocity will the 1.5 kg ball travel after it is hit by the bat?

Answers

Answer: tug vi

Explanation:

Because

in an experiment searching for the photoelectric effect, an incident beam of green light did not eject any electrons from a metal. in order to eject electrons, the experimenter should

Answers

Increase the frequency of the incident light. The photoelectric effect occurs when light of a sufficient frequency strikes a metal and frees electrons from the metal's surface. The energy of the incident photons must be greater than the energy required to remove the electrons, known as the work function. Thus, increasing the frequency of the incident light will result in higher energy photons, increasing the likelihood of electron ejection in the photoelectric effect.

The kinetic energy of the photoelectrons that are released will grow as the light amplitude increases, according to the wave model of light, yet the measured current will increase as the frequency increases. In contrast to expectations, studies revealed that raising the light's frequency and amplitude raised the current and the photoelectrons' kinetic energy, respectively.

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A 37 cm
-diameter conducting sphere is charged to 540 V
relative to V=0
at r=∞
?
Part A
What is the surface charge density σ
?
Express your answer using two significant figures.
Part B
At what distance from the center of the sphere will the potential due to the sphere be only 20 V
?
Express your answer using two significant figures.

Answers

The distance from the center of the sphere at which the potential due to the sphere is only 20 V is approximately 1.93 m.

Part A: The surface charge density σ can be calculated using the formula σ = Q/A, where Q is the charge on the sphere and A is the surface area of the sphere. The surface area of a sphere is given by A = 4πr², where r is the radius of the sphere. Since the diameter of the sphere is given as 37 cm, the radius is 18.5 cm or 0.185 m. The charge on the sphere is given as 540 V relative to V=0 at r=∞.

Since voltage is a measure of potential energy per unit charge, the charge on the sphere can be calculated as Q = CV, where C is the capacitance of the sphere. The capacitance of a sphere is given by C = 4πεr/3, where ε is the permittivity of free space and r is the radius of the sphere.

Substituting the values,

we get C = 4π(8.85x10⁻¹²)(0.185)/3

                = 1.72x10⁻¹⁰ F.

Thus, Q = CV = (1.72x10⁻¹⁰)(540)

                       = 9.30x10⁻⁸ C.

Finally, substituting the values in the formula σ = Q/A,

we get σ = 9.30x10⁻⁸/4π(0.185²)

               = 7.66x10⁻⁵ C/m².

Part B: The potential due to the sphere at a distance r from its center can be calculated using the formula V = kQ/r, where k is the Coulomb constant. We need to find the distance at which V = 20 V.

Substituting the values, we get 20 = (9x10⁹)(9.30x10⁻⁸)/r.

Solving for r, we get r = 1.93 m. As a result, the distance from the sphere's center where the potential due to the sphere is only 20 V is roughly 1.93 m.

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what are some examples of static electricity in everyday life

Answers

Static electricity is a type of electric charge that is stationary, or at rest, rather than flowing through a conductor. There are many examples of static electricity in everyday life.

More Examples are:

1. Balloon Rubbing: When you rub a balloon on your hair or a woolen sweater, it builds up a static charge and can stick to walls or attract small pieces of paper.

2. Clothing: Sometimes, when you remove your clothes from the dryer, they may cling together or produce sparks due to the build-up of static electricity caused by friction between the clothes.

3. Walking on carpets: Shuffling your feet on a carpeted floor can generate static electricity. When you touch a metal object afterward, like a doorknob, you might feel a small shock.

4. Lightning: During a thunderstorm, the friction between air particles creates static electricity, which discharges as lightning bolts.

Remember, static electricity occurs when there's an imbalance of electric charges within or on the surface of a material. These examples showcase how static electricity is a part of our daily lives.

This happens because the friction between your feet and the carpet causes an accumulation of electric charge, which is then discharged when you touch the doorknob. Static electricity can also be seen in lightning when a buildup of charge in the atmosphere creates a discharge of electricity.

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Put these components from largest to smallest

1. comet

2. star

3. galaxy

4. nebula

5. planet

6. universe

Answers

Answer:

6, 3, 2, 5, 4, 1

Explanation:

Let's describe them from smallest to largest. In fact the size order is not exact as there are exceptions.

An asteroid is a rocky body which lies in the asteroid belt between Mars and Jupiter. They are typically quite small object. The largest asteroid Ceres has been reclassified as a dwarf planet.

A moon is typically a rocky body which is in orbit around a planet. Some moons such as our Moon are quite large and are typically bigger than asteroid. Some moons can actually be smaller than some asteroids.

A planet is a nearly spherical body which is in orbit around the Sun. Planets are larger than moons.

A star is what planets orbit around. It is the source of light and heat. Our Sun is a star which is many times bigger than all of the planets.

A solar system is a star and all of its planets, asteroids, comets and other bodies. It is significantly bigger than a star.

A galaxy, such as our Milky Way Galaxy, is a collection of solar systems orbiting around a central core. Most galaxies have a supermassive black hole at their centres.

Galaxies also form clusters which are large scale structures.

The universe is everything. It contains billions of galaxies.

a heat engine accepts heat at a rate of 14 mw and rejects heat to a sink at 6 mw. what is the actual thermal efficiency of the heat engine?

Answers

A heat engine is a device that transforms thermal energy into mechanical work. In order to find the actual thermal efficiency of a heat engine, we use the formula: Thermal efficiency = (Work output / Heat input) * 100We are given that the heat engine accepts heat at a rate of 14 MW and rejects heat to a sink at 6 MW.

The heat input is 14 MW and the heat output is 6 MW. The work output is the difference between the heat input and the heat output. Hence, the work output is:

Work output = Heat input - Heat output

= 14 MW - 6 MW

= 8 MW

The actual thermal efficiency of the heat engine is:

Thermal efficiency = (Work output / Heat input) * 100

= (8 MW / 14 MW) * 100

= 57.14 %

We only need to calculate and report the actual thermal efficiency of the heat engine, our answer is 57.14%.

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We return to a circuit that you partly examined in the pre-lab for electricity IV. You were in a position to make predictions about the brightness of the identical bulbs in; Circuit 1 0 B A oc But you weren't asked to predict the effect of closing the switch on bulb A (although you built and observed the actual brightness of bulb A earlier in this lab). Multimeters Paul Mac Alevey Fall 2021 At the end of the pre-lab, we noticed that the flow through bulb A involved two competing factors: the flow from the battery increased when the switch was closed. The model of electricity is given later in this introduction 1. Explain why the flow from the battery increases when the switch is closed. Give the label of the concept(s) that you use from the model of electricity. [3] However, when the switch is closed, only half of the increased) flow goes through bulb A and the other half goes through bulb C. 2. Explain how we know that the flow splits in half. Give the label of the concept(s) that you use from the model of electricity. 121 The following table will help you to include the idea of pressure difference in the analysis. There will be a flow from the battery when the switch is open and, for the sake of discussion, we'll call that flow 1 glow. Assume that the obstacle presented by any of the identical bulbs is L no matter what flow goes through it. (This assumption is equivalent to;'assume that the bulbs are ideal'. ) Table 6: Obstacle presented Flow from to Battery (in terms Battery of L) Pressure Difference Flow caused by the Battery through bulb 4 Switch open 1 glow Switch closed 3. Fill out the rest of table six in your pre-lab. 171 4. Explain the change in brightness of bulb A when the switch closes. [1] Notice that this explanation is not possible without the knowing about pressure difference (as measured by 'product')

Answers

We return to a circuit that you partly examined in the pre-lab for electricity IV. When the switch is closed, the flow from the battery increases.

The half of the increased flow from the battery goes through bulb A and the other half goes through bulb C.

The brightness of both bulbs A and C increase when the switch is closed.

1. When the switch is closed, the flow from the battery increases because the switch provides an additional pathway for the current to flow through. This pathway has a lower resistance compared to the original pathway that included bulb A, so more current can flow through the circuit overall. This is known as Kirchhoff's junction rule, which states that the total current entering a junction must equal the total current leaving the junction.

2. We know that the flow splits in half because the bulbs are identical, so they have the same resistance. According to Ohm's law, the current through each bulb is proportional to the voltage across it, and since the voltage across the bulbs is the same, the current through each bulb must be equal. Therefore, half of the increased flow from the battery goes through bulb A and the other half goes through bulb C.

3. Table 6

Obstacle presented (L)

L

L

Flow from battery (in terms of L)

1

2

Pressure Difference (product)

L

2L

Flow caused by the battery through bulb A (in terms of L)

0

L/2

Flow caused by the battery through bulb C (in terms of L)

0

L/2

4. When the switch closes, the pressure difference (product) increases from L to 2L, which causes the flow from the battery to increase from 1L to 2L. Half of this increased flow, or L, goes through bulb A, which causes its brightness to increase. The other half of the increased flow also goes through bulb C, which also causes its brightness to increase. Therefore, the brightness of both bulbs A and C increase when the switch is closed.

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if the ages of the earth and the moon are nearly identical, as believed, why are most rocks found on the moon so much older than rocks found on earth?

Answers

The age of the Earth and the moon are nearly identical, as believed, unlike the Earth, however most of the rock found on the moon are older than that found on the Earth. This is because, unlike the moon has no atmosphere to weather rocks or plate tectonic activity to destroy rocks.

What are tectonic plates?

The movement of tectonic plates in the Earth's lithosphere and the eruption of volcanoes effectively recycles the rock on the surface, by consuming or burying the older rocks while creating the new ones. Over a period of time, some of the Earth's oldest rocks have been eroded through the action of air and water, both.

In contrast to bodies like the Moon and Mercury have remained essentially static for the time of billions of years. So, on them we see old surfaces which are heavily populated by craters that are formed from the massive meteoric impacts early in the history of the Solar System. These bodies are valuable as an enduring record of the history.

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a red shirt appears red because?

a. the shirt reflects red light

b. the shirt absorbs red light

c. the shirt emits green and blue light

d. the shirt reflects magenta and blue light

Answers

Red shirt appears red because:

a. The shirt reflects red light

A red shirt appears red because the shirt reflects red light.

Thus, An important topic for astronomers is "red shift." The phrase can be taken literally; when the light's wavelength is extended, the light is perceived as having "shifted" toward the red portion of the spectrum.

When a source of sound moves in relation to an observer, sound waves experience a similar phenomenon.

The frequency of sound waves varies if the source of the sound and the observer are moving relative to one another, according to Austrian mathematician Christian Andreas Doppler, who made this discovery.

The observer hears a frequency that is higher when the two are moving closer together and lower when they are moving farther apart and red shift.

Thus, A red shirt appears red because the shirt reflects red light.

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What is the force of friction experienced as a 2 kg steel block is pulled across a steel surface?

Answers

The force that is acting on the block is 19.l6 N

What is the force?

We have to know that the weight of the object is a force that is acting along the rope that is pulling the object. We must be able to note that the tension is the force that is acting along the rope that is pulling the object.

Now the weight of the steel block is going to act as a force of tension on the rope that is pulling the block.

We now have to know that the force is obtained from;

Force = mg

m = mass

g = acceleration due to gravity

F = 2 Kg * 9.8 m/s^2

= 19.6 N

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Which answer best explains why clouds usually form high in the sky?


It is cool enough for the water vapor to begin condensing

It is warm enough for the water vapor to begin condensing

It is dry enough for precipitation to form from

it is dry enough for water vapor to form a cloud

Answers

Answer: As air rises the moisture in it slowly reaches its saturation point and when this happens, tiny crystals of water start to condense and form clouds.

Explanation:

For the mirror configuration below, the angle of incidence for the going towards the mirror on the right is 15 degrees. What is the angle of reflection for the light ray leaving the mirror on the bottom

Answers

Answer:

Thus, the angle of reflection is 15 degrees.

Explanation:

Angle of incidence, i = 15 degrees

The angle of incidence is the angle between the normal to the mirror and the incident ray, the angle of reflection is the angle between the reflected ray and the normal to the mirror.

According to the laws of reflection, the angle of incidence is equal to the angle of reflection.

Thus, the angle of reflection = angle of incidence = 15 degrees

Which of the following statements is NOT correct?
A. If the forces on an object are balanced, then the object can be at a constant speed.
B. If the forces on an object are balanced, then the object can be at rest.
C. If the forces on an object are unbalanced, then the object can be accelerating.
D. If the forces on an object are unbalanced, then the object can be at rest.

Answers

The answer is
D:if the

What would be the diameter of the earth if it had the density of a neutron star

Answers

Answer:

At neutron star density, the Earth's whole mass would fit inside a 305-meter-diameter sphere.

Explanation:

if the hanging mass were placed at the very end of the meter stick, where would the balance pint be located?

Answers

If the hanging mass were placed at the very end of the meter stick, the balance point would be located at the center of mass, which can be found using the formula and steps provided. The exact location of the balance point depends on the values of the hanging mass and the mass of the meter stick.

If the hanging mass were placed at the very end of the meter stick, the balance point would be located at the center of the mass of the system.

To determine the center of mass, follow these steps:

Step 1: Identify the masses and their locations. In this case, we have the hanging mass (m1) placed at the very end of the meter stick (L) and the mass of the meter stick itself (m2) with a uniform distribution.

Step 2: Calculate the center of mass of the meter stick. Since the meter stick's mass is uniformly distributed, its center of mass is at its midpoint (L/2).

Step 3: Use the formula for the center of mass of a system:
Center of mass = (m1 * x1 + m2 * x2) / (m1 + m2)

Step 4: Plug in the values:
Center of mass = (m1 * L + m2 * (L/2)) / (m1 + m2)

Step 5: Solve the equation to find the balance point.

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the electrical operating conditions are typically measured with a(n):

Answers

The electrical operating conditions are typically measured with Multimeter, Oscilloscope, and Clamp Meter. Thus, option D is the accurate answer.

A multimeter is the most common and versatile instrument which is used to measure the voltage, resistance, and current passing through the conductors. IT can able to provide continuous frequency. An Oscilloscope is also a device used to measure electrical waveforms

A clamp Meter is a small handheld device that can able to measure both AC and DC currents in the circuit in digital format. It uses a small induction coil to measure the amount of current passing through the conductor.

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The complete question is:

the electrical operating conditions are typically measured with a(n):

a. Multimeter

b. Oscilloscope

c. Clamp Meter

d. All the above

when a metal ball is heated through 30°c,it volume becomes 1.0018cm^3 if the linear expansivity of the material of the ball is 2.0×10^-5k^-1, calculate its original volume​

Answers

It will be 1cm^3 - hope it help

Which of these charges has the greatest magnitude?
a charge of -5
a charge of -2
a charge of +4
O a charge of +1

Answers

Answer:

a charge of +4

that's how I could understand

The diagram below shows what can happen when light strikes a material.
red light
green
blue light
b
blue glass
red light
X
E
green light
blue light
O Diagram a.
O Diagram b.
O Diagram c.
O Diagram d.

The diagram below shows what can happen when light strikes a material.red lightgreenblue lightbblue glassred

Answers

Answer:

I don't understand the question

Explanation:

Using the formula for 'Kinetic Energy, what is the kinetic energy for an
object that weighs 40g and moving at 10 m/s?

Answers

200 ms²  is the kinetic energy for an object that weighs 40g and moving at 10 m/s.

What are kinetic energy ?

Kinetic energy is the power that an object has had as a result of motion. To accelerate an object, a power must be supplied to it. To apply a force, we must exert effort. The power is transported to the object when work is accomplished, which causes it to move at a new, constant pace.

What makes kinetic energy so important?

The capacity to perform work is unquestionably the most important characteristic of kinetic energy. Force acting on to an object while it is traveling is referred to as work. Energy and work are interchangeable because of their close relationship.

Briefing:

Using Kinetic Energy Formula:

K.E  = 1/2 mv²

K.E. = 1/2 * 40 * 10

K.E. = 200 ms²

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