Answer:
C
Explanation:
We have two laws that cannot be violated. The conservation of mass and the conservation of energy. The answer is C.
At Six Flags Great Adventure Amusement Park in New Jersey, a popular ride known as "Free
Fall" carries passengers up to a height of 33.5 m and drops them to the ground inside a small
cage. How fast are the passengers going at the bottom of the exhilarating journey?
At the bottom of the journey, the passengers will be travelling at a speed of approximately 39.2 m/s.
What is acceleration?Acceleration is the rate of change of an object's velocity over time. It is a vector quantity, meaning it has both magnitude and direction. Acceleration is usually denoted by the letter a in equations. It is the second derivative of position with respect to time, or the rate of change of velocity. Acceleration describes how quickly an object's speed changes with time. Acceleration can involve either an increase or decrease in speed, and it can involve either a change in direction or no change in direction.
This is because the velocity of a free falling object is equal to the square root of two times the acceleration of gravity times the height from which the object is dropped.
In this case, the height is 33.5 m, and the acceleration of gravity is 9.8 m/s2.
Therefore, the velocity at the bottom of the journey is equal to the square root of two times 9.8 m/s2 times 33.5 m, which is equal to 39.2 m/s.
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How does head to tail rule helps us to find the resultant of forces ?? Explain with the help of a diagram.
Head to tail rule helps us to find the resultant of forces because in this rule we join many vectors with each other forming resultant vector.
What is head to tail rule?
The joining of tail of the first vector with the head of the second vector represents the resultant vector whereas the direction of the resultant vector is from the tail of the first vector towards the head of the second.
So we can conclude that Head to tail rule helps us to find the resultant of forces because in this rule we join many vectors with each other forming resultant vector.
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Un clavadista salta del trampolín de 2.8 m con una velocidad inicial de 3.2 m/s.
a. Determina la altura máxima:
b. El tiempo para llegar a la altura máxima:
c. El tiempo para tocar el agua:
d. La velocidad al tocar el agua.
The maximum height achieved by the body is 2.645 meters.
What is the maximum height achieved by the body when thrown upwards with velocity {v}?The maximum height achieved by the body when thrown upwards with velocity {v} is -
h{max} = v²/2g
Given is to find the maximum height achieved by the body.
The maximum height achieved by the body is -
h{max} = v²/2g
h{max} = (2.3)²/20
h{max} = (2.3)²/20
h{max} = 2.645 meters
Therefore, the maximum height achieved by the body is 2.645 meters.
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{A diver jumps off the 2.8 m springboard with an initial velocity of 3.2 m/s.
to. Determine the maximum height.}
from problem 2,suppose another boy, boy C pulls the heavy cabinet with 5N of force in the same direction with boy A
1. what will be the net foece on the cabinet?
2. will the cabinet move?
3. in what direction will the cabinet move?
Answer:
Searching in Google I found that in problem 2 were two boys pulling the heavy cabinet, a Boy A pulling in the left direction with 10 N of force, and a boy B pulling in the right direction with 5 N.
1. F = 10 N
2. Yes, it will move.
3. It will move to the left direction of the cabinet (same direction as the boys A and C).
Explanation:
Searching in Google I found that in problem 2 were two boys pulling the heavy cabinet, a Boy A pulling in the left direction with 10 N of force, and a boy B pulling in the right direction with 5 N.
1. Hence, if another boy (C) pull in the same direction as the boy A with 5 N of force, we have:
\( \Sigma F = F_{A} + F_{C} - F_{B} \)
\( \Sigma F = 10 N + 5 N - 5 N = 10 N \)
The net force on the cabinet is 10 N.
2. Yes, the cabinet will move. From point 1 we can deduce that the cabinet will move since the net force on the cabinet is different from zero (10 N).
3. The direction of the motion is the same as the Boys A and C, that is to say, to the left of the cabinet.
I hope it helps you!
The net force acting on an object, is the vector sum of all the forces acting on it
The correct values for the forces acting on the cabinet are;
1. The net force on the cabinet is 10 N
2. Yes, the cabinet will move
3. The cabinet will move in the direction of boy A and boy C
The reason the above values are correct are as follows:
Question: The possible missing part of the question is; In problem 2 boy A is pulling a heavy cabinet with \(F_A\) = 10 N force, and boy B is pulling the same cabinet at the same time and in opposite direction with a force of \(F_B\) = 5 N
The known parameter:
The force with which boy C pulls the heavy cabinet = 5 N
The direction in which boy C pulls the cabinet = The same direction as boy A
Question 1. The net force on the cabinet, \(F_{NET}\) is given as follows;
Taking the direction of the force of boy A as the positive direction, we have;
\(\overset \longrightarrow {F_A}\) = 10 N
\(\overset \longrightarrow {F_B}\) = - 5 N
\(\overset \longrightarrow {F_C}\) = 5 N
\(\overset \longrightarrow {F_{NET}}\) = \(\overset \longrightarrow {F_A}\) + \(\overset \longrightarrow {F_B}\) + \(\overset \longrightarrow {F_C}\)
\(\overset \longrightarrow {F_{NET}}\) = 10 N + (-5 N) + 5 N = 10 N
The net force on the cabinet, \(\overset \longrightarrow {F_{NET}}\) = 10 N
Question 2. Yes: Given that there is a net force acting on the cabinet, according to Newton's first law of motion, in the absence of friction force, the cabinet will move in the direction of the net force of 10 Newton
Question 3. The cabinet will move in the direction of the net fore
The direction of the net force is the direction boy A and boy C are pulling the cabinet
Therefore, the cabinet will move in the direction boy A and boy C are pulling the heavy cabinet
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Describe how the ASC PPS conversion factor is different from the OPPS conversion factor?
What is the definition of palliative care?
use your own words
The ASC PPS conversion factor is different from the OPPS conversion factor because of the following reason:
ASC PPS Conversion factor: The Ambulatory Surgical Center Payment System (ASC PPS) is a Medicare payment system for ASC services, and it is determined by multiplying the ASC national conversion factor by the relative weight of the APC. ASC PPS conversion factors are adjusted for changes in inflation and other factors.OPPS Conversion factor: The Outpatient Prospective Payment System (OPPS) conversion factor is used to calculate Medicare payments for outpatient hospital services, and it is adjusted annually based on changes in inflation and other factors.The OPPS conversion factor is applied to each APC to determine payment rates for outpatient services. Furthermore, Palliative care is specialized medical care that aims to improve the quality of life for individuals with serious illnesses. It is focused on relieving symptoms and stress associated with serious illnesses. The goal of palliative care is to help patients feel more comfortable and enhance their quality of life. Palliative care is not the same as hospice care because it is given to patients at any stage of an illness, and it may be provided alongside curative treatments.
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Which of the following is NOT true of all the inner planets?
A
They are made of solid rock.
B
They are called gas giants.
C
They do not have rings.
D
They have impact craters.
Hi there! :)
\(\large\boxed{\text{B. They are called gas giants.}}\)
In the solar system, we can categorize the planets as such:
Inner planets: Mercury, Venus, Earth, Mars
Outer planets: Jupiter, Saturn, Uranus, Neptune
The Inner planets are the only planets that consist of solid rock. They also do not have rings and have impact craters due to their early formation.
In comparison, all of the outer planets are primarily made up of gaseous material and contain rings.
Therefore, the correct choice is B.
PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP
I NEED TO GIVE THIS IN TODAY!!!
Answer:
a) greater
smaller
Explanation:
Which option below best explains why the second law of thermodynamics is
not violated when heat flows from a cold freezer and into the much warmer
room?
OA. The flow of internal energy out of the freezer is balanced by the
flow of energy into the room.
B. The freezer and room are not an isolated system, since electrical
energy flows in.
OC. The spontaneous flow of heat from a cool area and into a warmer
area is allowed.
O D. The electric motor on the freezer does work to remove the heat
from inside the freezer.
''The freezer and room are not an isolated system, since electrical energy flows in.'' is the correct statement.
What is Second Law of Thermodynamics?
The Second Law of Thermodynamics says that "in all energy exchanges, if no energy enters or leaves the system, the potential energy of the state will always be less than the energy of the initial state."
So we can conclude that ''The freezer and room are not an isolated system, since electrical energy flows in.'' is the correct statement.
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Tell me how the temperatures in the tropics, temperate zones, and polar zones are similar and how they are different.
- giving brainlist + extra points :P
Answer:
Hewo My Lovelys!!
Answers are down below!!
Explanation:
The climate region near the equator with warm air masses is known as tropical. In tropical and polar climates, the weather is consistent throughout the year. In temperate zones, the weather is affected by both warm and cold air masses at different times during the year, so the weather changes with the seasons.
Hope this helps!! =3
Have a great day, evening, or night!! <3
A sample of hydrogen (H2) gas was collected over water at 60°C. If the total volume of gas collected was 55.6 mL and the atmospheric pressure was 1.1 bar, what mass (in g) of hydrogen gas was collected above the water? The vapour pressure of water at 60°C is 150 torr.
First, calculate the partial pressure of H2 by considering the total pressure:
\(P_{\text{tot}}=P_{H2}+P_{H20}\)where,
Ptot = 1.1bar
PH20 = 150Torr
Convert the previous values to atm:
Ptot = 1.1 bar = 1.085 atm
PH20 = 150 Torr = 0.197 atm
Then, for PH2 you obtain:
\(P_{H2}=P_{\text{tot}}-P_{H20}=1.085\text{atm-}0.197\text{atm}=0.888atm\)Next, use the following equation for ideal gases:
\(PV=\text{nRT}\)where,
V: volume = 55.65mL = 0.05565 L
R: gas constant = 0.082 atm*L/mol*K
T: temperature = 60 + 273 = 333K
P: partial pressure of H2 = 0.888atm
Solve the equation for n and replace the values of the other parameters:
\(n=\frac{PV}{RT}=\frac{(0.888atm)(0.05565L)}{(0.082atm\cdot\frac{L}{\text{mol}\cdot K})(333K)}=0.00181mol\)Next, use the atomic weight to determine the mass of H2:
\(M=(\frac{2.0141g}{\text{mol}})(0.00181mol)=0.0036g\)Hence, there are 0.0036 g of H2 collected above the water
A ball of mass 0.40 kg travels horizontally and strikes a vertical wall with a speed of 5.0 m s. It rebounds horizontally with a speed of 3.0 m s. The ball is in contact with the wall for a time of 0.20 s. Calculate the magnitude of average force exerted on the wall.
Answer:
To find the magnitude of the average force exerted on the wall by the ball, we can use the impulse-momentum theorem, which relates the impulse exerted on an object to the change in momentum of that object:
Impulse = Change in momentum
We can express the impulse as the product of the average force and the time for which it acts:
Impulse = Average force × Time
Since the ball rebounds horizontally, its initial and final momenta have the same magnitude but opposite directions, so the change in momentum is:
Change in momentum = 2 × (final momentum) = 2 × (0.40 kg × 3.0 m/s) = 2.4 kg m/s
Using the formula for impulse, we can then solve for the average force:
Average force = Impulse / Time = (2.4 kg m/s) / 0.20 s = 12 N
Therefore, the magnitude of the average force exerted on the wall by the ball is 12 N.
A classroom measures 3 m X 4m x 6 m.
Calculate the volume of air in the room. Give your answer in
a
cubic metres (mº).
A runner covers the last straight stretch of a race in 8s.During that time he speeds up from 7 m/s to 9m/s. What is the acceleration
Given
Time taken is t=8 s.
The initial speed is u=7 m/s
The final speed is v=9 m/s.
To find
The acceleration
Explanation
We know the acceleration is the ratio of the difference in the speed to the time taken.
Thus,
\(\begin{gathered} a=\frac{v-u}{t} \\ \Rightarrow a=\frac{9-7}{8} \\ \Rightarrow a=\frac{2}{8}=\frac{1}{4}=0.25\text{ m/s}^2 \end{gathered}\)Conclusion
The acceleration is
\(0.25\text{ m/s}^2\)NASA's Langley Research Center has been experimenting with the use of air bags to soften the landings of crew exploration vehicles (CEV) on land. What stopping time will be required in order to safely stop a 7250 kg CEV moving at 7.65 m/s with an average force of 426000 N (an average force of 6 G's)
The stopping time will be 0.13 second required in order to safely stop a CEV .
What is speed?Speed is distance travelled by the object per unit time. Due to having no direction and only having magnitude, speed is a scalar quantity With SI unit meter/second.
The average force acting on CEV is = 426000 N.
Mass of the CEV is = 7250 kg.
Initial speed of the CEV is = 7.65 m/s
Hence, deceleration of the CEV is = ( 426000 N ÷ 7250 kg) = 58.75 m/s²
Hence, required stopping time = 7.65 m/s ÷ 58.75 m/s² = 0.13 second.
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Amy crashed her bike into the fence. She was thrown over it onto the lawn. Which Newton law applies
Answer:
Newton's First Law of Motion applies here.
Explanation:
Before crashing into the fence, Amy was moving at a certain speed on her bike. As, she crashed her bike into the fence, the collision stopped the bike suddenly. But, Amy had the same speed due to inertia of her body. Due tot his speed Amy did not stop and she was thrown over the fence onto the lawn. So, the force of inertia of Amy's body caused her to be overthrown in this case. We study about inertia in Newton's First Law of Motion, which is also known as Law of Inertia.
Newton's First Law of Motion applies here.
what is the meaning of physics
Answer:
the branch of science concerned with the nature and properties of matter and energy. The subject matter of physics, distinguished from that of chemistry and biology, includes mechanics, heat, light and other radiation, sound, electricity, magnetism, and the structure of atoms.
Explanation:
The distance (in m) that light will travel in 4 minutes is?A. 7.2 E10B. 3E8C. 1.2E9D. 6.8E11
ANSWER
\(A)7.2E10\)EXPLANATION
To find the distance that light travels in 4 minutes, apply the relationship between distance and time:
\(d=v\cdot t\)where v = velocity; t = time
The velocity of light is:
\(3\cdot10^8m\/s\)Also, converting the given time to seconds:
\(\begin{gathered} 1\min =60s \\ 4\min =60\cdot4=240s \end{gathered}\)Therefore, the distance traveled is:
\(\begin{gathered} d=3\cdot10^8\cdot240 \\ d=720\cdot10^8 \\ d=7.2\cdot10^{10}m\Rightarrow7.2E10 \end{gathered}\)What is the approximate number of wavelengths of light that can travel in 1 direction within a retroreflecting bead that has a diameter of 5 × 10-5 m? (Note: The speed of light = 3 × 108 m/s, and its frequency is approximately 1015Hz.)
0.6
1.7 × 10^2
1.5 × 10^4
3.3 × 10^6
The approximate number of wavelengths of light that can travel in one direction within a retroreflecting bead that has a diameter of 5 ×\(10^-^5\) m is 167.
Number of wavelengths of light in a retroreflecting bead with 5 × 10^-5 m diameter?
This calculation is based on the formula n = L/λ, where n is the number of wavelengths, L is the length of the object, and λ is the wavelength of light. To calculate the wavelength of light, we use the formula c = λf, where c is the speed of light and f is the frequency of light.
In this problem, we are given the diameter of the retroreflecting bead, which is assumed to be spherical. Therefore, its length is equal to its diameter, which is 5 × \(10^-^5\)m. We are also given the speed of light, which is 3 × \(10^8\) m/s, and an approximation of the frequency of light, which is \(10^1^5\) Hz.
Using the formula c = λf, we can solve for the wavelength of light:
λ = c/f = (3 ×\(10^8\) m/s)/\((10^1^5\)Hz) = 3 ×\(10^-^7\)m
Finally, we can use the formula n = L/λ to calculate the approximate number of wavelengths of light that can travel in one direction within the retroreflecting bead:
n = L/λ = (5 ×\(10^-^5\) m)/(3 ×\(10^-^7\) m) = 166.67 ≈ 167
Therefore, the approximate number of wavelengths of light that can travel in one direction within a retroreflecting bead that has a diameter of 5 ×\(10^-^5\) m is 167.
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If the pressure head in the aquifer is 100 ft., calculate the effective stress (N/m") in the aquifer.
If the aquifer is pumped and the hydraulic head at some point is reduce by 12 ft., what will be the resulting changes in the pressure head (m), the effective stress (N/m*), the fluid pressure (N/m*), and the total stress (N/m? ?
The resulting changes will be:
1. Pressure head: 88 ft (or 26.82 m)
2. Effective stress: No change, assuming no other factors affect it
3. Fluid pressure: No change
4. Total stress: Decreased by the same amount as the effective stress
To calculate the effective stress in the aquifer, we need to subtract the fluid pressure from the total stress.
Given:
Pressure head in the aquifer = 100 ft (or 30.48 m)
The pressure head in the aquifer is directly proportional to the fluid pressure, which can be calculated using the formula:
Fluid pressure (P) = ρ * g * h
Where:
ρ = density of the fluid (water) = approximately 1000 kg/m³
g = acceleration due to gravity = 9.8 m/s²
h = pressure head
Fluid pressure = 1000 kg/m³ * 9.8 m/s² * 30.48 m ≈ 298,440 N/m² (or Pa)
The total stress in the aquifer is the sum of the fluid pressure and the effective stress. Therefore, the effective stress can be calculated by subtracting the fluid pressure from the total stress.
Now, let's consider the changes in the hydraulic head due to pumping:
Change in hydraulic head = -12 ft (or -3.66 m)
The resulting changes in each parameter will be as follows:
1. Pressure head:
The pressure head will be reduced by 12 ft, so the new pressure head will be 100 ft - 12 ft = 88 ft (or 26.82 m).
2. Fluid pressure:
The fluid pressure does not change, as it depends on the density of the fluid and the acceleration due to gravity, which remain constant.
3. Effective stress:
The effective stress can be calculated as the total stress minus the fluid pressure. Since the fluid pressure remains constant, the effective stress will also remain constant unless there are other factors affecting it.
4. Total stress:
The total stress is the sum of the fluid pressure and the effective stress. As mentioned earlier, the fluid pressure remains constant, so the total stress will decrease by the same amount as the effective stress, assuming no other factors affect the total stress.
Therefore, the resulting changes will be:
1. Pressure head: 88 ft (or 26.82 m)
2. Effective stress: No change, assuming no other factors affect it
3. Fluid pressure: No change
4. Total stress: Decreased by the same amount as the effective stress
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Consider a cool gas placed in front of a hot light bulb. The observed spectrum of the light bulb will contain dark lines where some light has been absorbed by the gas. Those dark lines reveal the: ________
The dark lines observed in the __spectrum__ of a hot light bulb when a cool gas is placed in front of it reveal valuable information about the properties of the gas and its interaction with light.
These dark lines are known as absorption lines or Fraunhofer lines, named after the German physicist Joseph von Fraunhofer who first observed them in the early 19th century.
The absorption lines occur because the atoms or molecules of the cool gas can absorb specific wavelengths of light. Each chemical element or compound has a unique set of energy levels that its atoms or molecules can occupy.
When light passes through the cool gas, the atoms or molecules in the gas can absorb photons of specific energies that match the energy differences between these levels.
As a result, the absorbed photons are removed from the incident light, leading to dark lines at those specific wavelengths in the observed spectrum.
The positions and patterns of these dark lines provide a characteristic fingerprint of the gas present. By comparing these lines to known spectral patterns, scientists can identify the elements or compounds in the gas.
Moreover, the intensity or depth of the absorption lines can reveal information about the density or concentration of the gas.
The greater the concentration of absorbing particles in the gas, the deeper and more pronounced the absorption lines will be.
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the north end of a strong magnet and the south end of a weak magnet are near each other. which experiences the larger force? how do you know?
The north end of a strong magnet experiences the larger force.
How do we know which experiences the larger force?The fundamental principle underlying most magnetic interactions is polarity- where opposite poles attract and like ones oppose each other.
When we bring together two magnets with varying strengths - say a stronger and weaker one- their behavior becomes predictable: The north pole of the powerful magnet should get drawn towards south pole of weaker magnetic field, while its own southern extremity should experience some pushback.
And according to physics principles governing magnetic forces- in particular how attraction and repulsion work-, we know such attractions would typically have more potency than opposing forces; hence why we can conclude that stronger magnets exert relatively larger forces at their respective northern ends.
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Demonstrate that the wavefunctions for the particle-on-a-ring probiem show no preferred position on the ring, in other words that the probability of finding the particle at any particular angle. ψ∗ψ d ϕ, is independent of the angular variable ϕ. Question 12 An O2 molecule confined in a nanoparticle to move along a one-dimensional path can be modeled as a particle in a box. If the path is 10 fim long, and our sample consists of a very large number of such systems, calculate the ratio of molecules that can be found in n=50. relative to the number found in n=1, given that the ambient temperature is 77 K.
The wavefunctions for the particle-on-a-ring problem exhibit no preferred position on the ring, meaning that the probability of finding the particle at any specific angle is independent of the angular variable.
In the particle-on-a-ring problem, we consider a particle confined to move along a circular ring. The wavefunction of the particle, denoted by ψ, describes its probability distribution. To demonstrate that the wavefunctions show no preferred position on the ring, we need to show that the probability density, given by ψ∗ψ, is independent of the angular variable ϕ.
The wavefunction for the particle-on-a-ring is given by ψ(ϕ) = (1/√2π)e^(imϕ), where m is an integer representing the angular momentum of the particle. The probability density is given by ψ∗ψ = |ψ(ϕ)|^2 = (1/2π), which is a constant value independent of ϕ. This means that the probability of finding the particle at any particular angle on the ring is the same for all angles.
This result can be understood intuitively by considering the symmetry of the problem. Since the particle is confined to a circular ring, there is no preferred position or direction on the ring. The wavefunction must therefore exhibit this symmetry and be constant throughout the ring.
In summary, the wavefunctions for the particle-on-a-ring problem show no preferred position on the ring because the probability density is constant and independent of the angular variable ϕ.
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Which is an example of physical weathering?
a- limestone in rock dissolving when acid rain flows across it
b- bits of rock rusting when exposed to oxygen and water
c- wind blowing off bits of a rock over time
d- oxidation of certain metals in rock
An example of physical weathering is the wind that is blowing off bits of a rock over time. This results into breaking down of large rocks. Thus, the correct option is C.
What is Physical weathering?Physical weathering is also called as mechanical weathering. It is a process which causes the disintegration of large rocks, minerals, and large soil particles without any chemical change. The primary process in physical weathering is the abrasion, it is the process by which clasts and other particles are reduced in size and mix up with soil.
Physical weathering occurs when large rocks are broken down through mechanical processes such as wind blowing, water, gravitational force, freeze-thaw cycles, or the growth of roots into the rocks.
Therefore, the correct option is C.
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During take off, a plane leaves the ground and
travels in a straight line until it reaches a
height of 10 km. The distance the plane flies
during take off should be in the range 57 km
to 62 km.
What is the smallest possible angle that the
path of the plane could make with the ground?
Give your answer in degrees to 1 d.p.
Not drawn accurately
Explanation:
please mark as brainliest answer
The smallest possible angle that the path of the plane could make with the ground is 18.9 degrees.
We are given that the plane travels a distance of 57 km to 62 km during take off, and that it reaches a height of 10 km. We want to find the smallest possible angle that the path of the plane could make with the ground.
The smallest possible angle will occur when the plane travels the maximum distance of 62 km..
To calculate the angle, we can use the following formula:
sin(theta) = opposite / hypotenuse
sin(theta) = 10 / 62
theta = sin⁻¹(10/62) = 18.9 degrees
As a result, the least conceivable angle that the plane's path might create with the ground is 18.9 degrees.
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When were Spaces waves (gravitational waves) first detected?
Gravitational waves, also known as space waves, were first detected on September 14, 2015, by the Laser Interferometer Gravitational-Wave Observatory (LIGO) in the United States. The detection of these waves was a monumental achievement for the field of astrophysics as it provided direct evidence of the existence of these waves, which were predicted by Albert Einstein's theory of general relativity over a century ago.
The detection of these waves was made possible by LIGO's advanced detectors, which are able to pick up incredibly tiny vibrations in space-time caused by the collision of massive objects such as black holes or neutron stars. These vibrations, which are caused by the ripples in space-time created by the collision, are incredibly weak and difficult to detect, which is why it took so long for scientists to confirm their existence.
The detection of these waves not only confirms Einstein's theory of general relativity but also opens up new avenues for studying the universe. By detecting gravitational waves, scientists can now study the most violent and energetic events in the universe, such as the collision of black holes or the birth of a neutron star, providing new insights into the nature of our universe.
Gravitational waves, which are ripples in the fabric of spacetime caused by the acceleration of massive objects, were first detected on September 14, 2015. The discovery was made by the Laser Interferometer Gravitational-Wave Observatory (LIGO), a large-scale physics experiment designed specifically for this purpose. LIGO consists of two observatories located in the United States, one in Washington and the other in Louisiana.
The detection was a groundbreaking achievement, as it confirmed a major prediction of Albert Einstein's general theory of relativity and opened up a new way of observing the universe. The gravitational waves detected by LIGO were generated by the merger of two black holes, which occurred approximately 1.3 billion years ago. As these black holes spiraled towards each other and eventually collided, they released a tremendous amount of energy in the form of gravitational waves.
These waves traveled through spacetime, eventually reaching Earth and causing minuscule vibrations in the LIGO detectors. The data collected from the detectors was carefully analyzed to confirm the presence of gravitational waves and eliminate any false signals.
Since the first detection, LIGO and other observatories, such as the Virgo detector in Italy, have continued to detect gravitational waves from various cosmic events, providing valuable insights into the behavior of massive objects and the nature of spacetime itself. This new field of research, known as gravitational-wave astronomy, is expected to contribute significantly to our understanding of the universe.
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Which of the following factors affect the momentum of the moving object?a. mass and volumeb. mass and densityc. mass and shaped. mass and velocityThe momentum of a 255 g softball moving at 35 m/s isa. 7.9 kg m/sb. 3.5 kg m/sc. 5.0 kg m/sd. 2.1 kg m/s
The momentum of an object is given by the formula below:
\(p=mv\)Where p is the momentum, m is the mass and v is the velocity.
Therefore the correct option of the first part is d.
Then, calculating the momentum with a mass of 0.255 kg and a velocity is 35 m/s, we have:
\(\begin{gathered} p=0.255\cdot35\\ \\ p=8.925\text{ kg m/s} \end{gathered}\)A plane passes over Point A with a velocity of 8000 m/s north. Forty seconds later it passes over Point B at a velocity of 10,000 m/s north. What is the planes’ acceleration from A to B?
Answer:
The planes’ acceleration from A to B is 500m/s^2
Explanation:
Given that the initial velocity u is 8000m/s
and also given the final velocity v=10,000 m/s
the time taken to move from A to B = 40 second
The acceleration is defined as the rate of change of velocity with time
we know that the expression for acceleration is given as
a=(v-u)/t
substituting our given data into the expression for a we have
a=(10000-8000)/40
a=2000/40
a=500m/s^2
The planes’ acceleration from A to B is 500m/s^2
using the domain theory explain the stroking method of magnetization
The stroking method of magnetization is a technique used to magnetize ferromagnetic materials. It is based on the principles of domain theory, which helps us understand the behavior of magnetic materials at the atomic and microscopic level.
In domain theory, a ferromagnetic material is composed of many tiny regions called magnetic domains. Each domain consists of a large number of aligned atomic magnetic moments, creating a net magnetic field within the domain.
However, the magnetic moments in different domains can be randomly oriented, resulting in a lack of overall magnetization in the material.
The stroking method takes advantage of the fact that magnetic domains can be influenced and aligned by an external magnetic field. When a ferromagnetic material is subjected to an external magnetic field, the field causes the magnetic moments in the domains to align in the direction of the applied field. As a result, the domains merge and grow in size, leading to an overall magnetization of the material.
To apply the stroking method, a non-magnetized ferromagnetic material, such as a piece of iron, is taken and a strong permanent magnet is brought close to it.
The magnet is then repeatedly stroked along the length of the material in the same direction. The stroking motion ensures that the external magnetic field from the permanent magnet is consistently applied to the material.
As the magnet is stroked, the aligned magnetic domains within the material start to merge and grow. This process continues with each stroke, gradually increasing the overall magnetization of the material. Eventually, after several strokes, the material becomes fully magnetized, with the majority of the magnetic domains aligned in the direction of the stroking.
The stroking method is effective because the repeated application of the external magnetic field helps overcome the resistance of domain boundaries within the material.
These boundaries are regions where magnetic moments change orientation between adjacent domains, and they can hinder the alignment process.
By stroking the material, the external field continuously acts on the domains, encouraging them to overcome these barriers and align more uniformly.
It's important to note that the stroking method is a relatively simple and basic technique for magnetizing materials. In practical applications, more sophisticated methods, such as using electromagnets or specialized machinery, are often employed to achieve precise and controlled magnetization. However, the underlying principle of domain alignment remains a fundamental concept in magnetism.
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A string under a tension of 170 N has a frequency of 300 Hz.What will its frequency become if the tension is increased to 340 N?
The speed of the wave on a string is given by Taylor's formula:
\(v=\sqrt[]{\frac{F}{\mu}}\)where
F = tension force
μ = linear density = mass per unit length
But also we can say the speed of any wave is given by:
\(v=\lambda\times f\)where:
λ = wave length
f = frequency
Plug the second equation in the first one. We get:
\(\lambda\times f=\sqrt[]{\frac{F}{\mu}}\)Now solve for f:
\(f=\frac{1}{\lambda}\times\sqrt[]{\frac{F}{\mu}}\)Lets say wave length is the same on the second case. Since it's the same string μ will also be the same.
See that 340 N = 2 x 170, so we can write:
\(\begin{gathered} f_{new}=\sqrt[]{2}\times\frac{1}{\lambda}\sqrt[]{\frac{F}{\mu}} \\ f_{new}=\sqrt[]{2}\times f_{old} \\ f_{new}=\sqrt[]{2}\times300 \\ f_{new}\approx424Hz \end{gathered}\)If there is no dropped ceiling, or if the drop is not as much as the height of the recessed luminaires, you will find that the center-to-center spacing of recessed luminaires will have to be in increments of ____________________ ft.
Answer:
The answer is "4".
Explanation:
The luminaire would be recessed inside a wall, so that, dependent on the surface mountings, its top-level is flush with the ceiling. It is the hanging under the primary structural, in which the drop was an area of the above falling ceiling, that referred to its full space, because it will be generally used for the HVAC air return and the total space is also used to obfuscate piping, cabling, and ducts, that's why the middle-to-middle spacing of curved lighting systems would have to be in incremental increases of 4 ft.