In a chemical reaction, substance R reacts with compound XY to produce 47. 0 g of compound RX. If the theoretical yield of RX is 56. 0 g, what is its percent yield? Use Percent yield equals StartFraction actual yield over theoretical yield EndFraction times 100. 9. 00% 16. 1% 83. 9% 119%.

Molecule (a or b) in each pair has the higher boiling point also indicate force, hydrogen bonding (h), dipolar (p), or dispersion (d) is responsible for the difference so in NH₃ and PH₃ the a molecule is high melting point and forces are dispersion force and in C₂H₅OH and CH₃OHCH₃ the molecule a has high melting point and has a dispersion force and C₄H₈ and C₁₀H₂₀ the b molecule has high melting point and has a dispersion force and in HCl and F₂ the a molecule has high boiling point and has a dipolar dipole interaction forces

The forces are electrostatic force between oppositely charged ions as in ionic bonds or through the sharing of electrons as in covalent bonds and there are four type of forces

So here given molecule in that we have to seen the forces and high melting point so

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Answer:

Divide its mass by the volume.

Explanation:

Answer:

(i) Ionization enthalpy:

Alkaline earths have higher ionization enthalpy values than alkali metals. This is because the atomic size of alkaline earths is smaller than that of alkali metals.

(ii) Basicity of oxides:

On dissolution in water, the oxides of alkali metals and alkaline earth metals form basic hydroxides. The basicity of alkali metal oxides is higher than that of alkaline earth metal oxides due to lower ionization enthalpy of alkali metals than that of corresponding alkaline earths. Due to this, the M-OH bond in alkali metal hydroxides can more easily ionize.

(iii) Solubility of hydroxides:

Alkaline earths have larger lattice energies than alkali metals due to small size and high charge. Hence, alkaline earth metal hydroxides have lower solubility than alkali metals.

Comparison between the alkali and alkaline earth metals are that alkali metals are soft, have high M.P. & shows magnetism and alkaline are hard, have low M.P. & no magnetism.

Alkali earth metals are those elements which are present in the first period of the periodic table and alkaline earth metals are those which are present on the second group of the periodic table.

Hence the comparison between them are discussed above.

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Answer:

I believe the answer is all amoeba come from other amoeba

The spatial arrangement of the atoms in the ozone molecule (\(O_{3}\)) is angular, which is option b).

The ozone molecule consists of three oxygen atoms bonded together. The central oxygen atom is double bonded to the other two oxygen atoms, forming an O=O-O structure.

Due to this arrangement, the ozone molecule has a bent or angular shape.

The presence of the lone pair of electrons on the central oxygen atom creates repulsion between the electron pairs, causing the two O-O bonds to push slightly away from each other, resulting in an angular molecular geometry.

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Answer:

In order for a secondary metabolite to become active, it must be enzymatically cleaved from a sugar conjugate. This process is necessary in order to release the active compound from the sugar molecule. Once the compound is released, it can then bind to specific receptors and produce the desired effect.

Explanation:

The vast majority of secondary metabolites are conjugated to sugars, and many of these compounds must be cleaved enzymatically from the sugar in order to become active. The most common type of sugar moiety found in these compounds is a glucose, but other monosaccharides (such as galactose and mannose) and disaccharides (such as maltose and sucrose) are also found. In some cases, the sugar may be attached to the compound through an ether linkage, while in others it may be attached via a thioester bond. Regardless of the type of linkage, the sugar must be cleaved for the compound to be active.There are a variety of enzymes that can catalyze the cleavage of these sugar moieties, including hydrolases, lyases, and oxidoreductases. The specific enzyme required depends on the structure of the particular compound. In some cases, more than one enzyme may be required for complete cleavage. For example, when glucose is conjugated to a secondary metabolite via an ether linkage, two enzymes are required: an alcohol dehydrogenase to break the ether bond and a glucosidase to release the glucose moiety.Once the sugar is cleaved from the compound, it is typically metabolized by other enzymes in the cell. In some cases, this metabolism may activate the compound; in others, it may result in its degradation.

Answer:

Electronegativity

Explanation:

Answer:

Electronegativity

Explanation:

Edge 2021

The mL of a 0.150 M Ca(OH)₂ solution required to titrate a 200.0 mL of a 0.060 M HCl solution to its equivalence point is 40.0 mL.

The balanced chemical equation for the reaction between Ca(OH)₂ and HCl is:

Ca(OH)₂(aq) + 2HCl(aq) → CaCl₂(aq) + 2H₂O(l)

From the equation, we can see that 1 mole of Ca(OH)₂ reacts with 2 moles of HCl. Therefore, the number of moles of HCl in the 200.0 mL of 0.060 M HCl solution is:

n(HCl) = M(HCl) x V(HCl) = 0.060 mol/L x 0.2000 L = 0.0120 mol

Since 1 mole of Ca(OH)₂ reacts with 2 moles of HCl, the number of moles of Ca(OH)2 required to react with the HCl is:

n(Ca(OH)₂) = 1/2 x n(HCl) = 1/2 x 0.0120 mol = 0.0060 mol

The concentration of the Ca(OH)₂ solution is 0.150 M, so the volume of Ca(OH)₂ solution required to provide 0.0060 mol of Ca(OH)₂ is:

V(Ca(OH)₂) = n(Ca(OH)₂) / M(Ca(OH)₂) = 0.0060 mol / 0.150 mol/L = 0.0400 L = 40.0 mL

Therefore, 40.0 mL of the 0.150 M Ca(OH)₂ solution is required to titrate the 200.0 mL of 0.060 M HCl solution to its equivalence point.

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The compound as shown  corresponds to the compound 1-ethyne.

The term hydrocarbon refers to a compound that is composed of only hydrogen and carbon. A hydrocarbon may be an alkane, alkene, alkyne or aromatic compound.

Looking at the structure of the compound as shown, the structure corresponds to the compound 1-ethyne.

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Answer:

D.

Explanation:

I took the test

The characteristics of the α and β particles allow to find  the design of an experiment to measure the ²³⁴Th particles is:

In Rutherford's experiment, the positive particles directed to the gold film were measured on a phosphorescent screen that with each arriving particle a luminous point is seen.

The particles in this experiment are α particles that have two positive charge and two no charged is a helium nucleus.

The test that can be carried out is to place a small ours of Thorium in front of a phosphorescent screen and see if it has flashes, with the amount of them we can determine the amount of particle emitted per unit of time.

Thorium has several isotopes, with different rates and types of emission:

In this case they indicate that the material used is ²³⁴Th, which emits β particles that are electrons, the detection of these particles is more difficult since it has one negative charge, it has much lower mass, but they can travel further than the particles α, therefore, for what type of isotope we have, we can start measuring at a small distance and increase the distance until the reading is constant. At this point all the particles that arrive are β, which correspond to ²³⁴Th.

Neutron detection is much more difficult since these particles have no charge and therefore do not interact with electrons and no flashing on the screen is varied.

In conclusion with the characteristics of the α and β particles we can find the design of an experiment to measure the ²³⁴Th particles is:

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The relative viscosity of a magma is mostly governed by its chemical makeup. A magma's viscosity increases with the amount of SiO2 (silica) present.

The amount of silica is important since it affects how viscous a magma will be. The fluidity of a liquid is determined by its viscosity. A fluid can hold more gas in solution and flow less freely as it becomes more viscous, which increases the explosiveness of high-silica magma.

Temperature and the makeup of the magma have a major impact on viscosity. The viscosity of higher SiO2 (silica) content magmas is greater than that of lower SiO2 content magmas (viscosity increases with increasing SiO2 concentration in the magma).

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The pH of the solution after 50.0 mL of NaOH has been added is approximately 0.823.

To determine the pH of the solution after 50.0 mL of 0.250 M NaOH has been added to 100.0 mL of 0.200 M HCl, we need to consider the stoichiometry of the reaction between HCl and NaOH and the resulting solution composition.

The balanced equation for the reaction between HCl and NaOH is:

HCl + NaOH → NaCl + H₂O

From the balanced equation, we can see that one mole of HCl reacts with one mole of NaOH to produce one mole of NaCl and one mole of water.

Initial moles of HCl = initial volume of HCl solution (in L) × concentration of HCl (in mol/L)

Initial moles of HCl = 0.100 L × 0.200 mol/L = 0.020 mol

Moles of HCl reacted with NaOH
= moles of NaOH added
= volume of NaOH solution (in L) × concentration of NaOH (in mol/L)

Moles of HCl reacted with NaOH = 0.050 L × 0.250 mol/L = 0.0125 mol

Moles of HCl remaining
= Initial moles of HCl - Moles of HCl reacted with NaOH

Moles of HCl remaining = 0.020 mol - 0.0125 mol = 0.0075 mol

The volume of remaining HCl solution = Initial volume of HCl solution - Volume of NaOH solution added

Volume of remaining HCl solution = 100.0 mL - 50.0 mL = 50.0 mL = 0.050 L

The concentration of HCl in the remaining solution = Moles of HCl remaining / Volume of remaining HCl solution

Concentration of HCl in the remaining solution = 0.0075 mol / 0.050 L = 0.150 M

The concentration of HCl in the remaining solution is 0.150 M.

pH = -log[H⁺]

Since HCl is a strong acid, it completely dissociates in water to form H+ ions. Therefore, the concentration of H+ in the solution is equal to the concentration of HCl.

pH = -log(0.150) ≈ 0.823

Therefore, the pH of the solution after 50.0 mL of NaOH has been added is approximately 0.823.

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Answer:   The final stage of the life cycle of a tree is when it has fully grown and reached the ... You should be confident in your supplier's approach to sustainability. ... This is the first occasion you will see a stem and perhaps a couple of leaves. ... The next phase is the sapling stage, this is when the sprout continues to grow and has ...

Explanation:

1) A. individual salt crystals

2) A. increases

3) A. increases

hope this helps :)

A solution is defined as the homogeneous mixture which contain one or more solutes in a solvent. The factors which affect the solubility are temperature and pressure. Here individual salt crystals dissolve faster.

The maximum amount of solute which can dissolve in a given quantity of the solvent at a certain temperature is defined as the solubility. It is defined as the property exhibited by a material to dissolve in a given solvent.

The powdered salt found to dissolves faster in a solvent than the salt of larger size. The rate of dissolving is affected by the size of the solute. The faster the solute dissolves if its size is smaller. So the  individual salt crystals dissolves faster.

In most cases, generally the solubility found to decrease with the increase of temperature. When the temperature increases, the kinetic energy of the molecules increases and thereby decreases the intermolecular force of attraction. The increase in the process of agitation decreases the solubility.

1. The correct option is A

2. The correct option is B

3. The correct option is B

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The spectator ions would be the ions that don't comprise the precipitate in this reaction. You have four ionic species here: Pb²⁺, NO₃⁻, H⁺, and SO₄²⁻. Since Pb²⁺ and SO₄²⁻ combine, as you are told, to form the precipitate, that leaves H⁺ and NO₃⁻ (or, in normal text, H+ and NO3-) to be the spectator ions.

Edit: NO3- might be interpreted ambiguously since it's not immediately clear that the NO3 is a polyatomic ion with a -1 charge and not an NO compound with a 3- charge, so it should be written as [NO3]- or (NO3)-.

The net ionic reaction shows the reaction without the spectator ions. In this case, that would be: Pb²⁺(aq) + SO₄²⁻(aq) → PbSO₄(s).

When the nuclide strontium-80 decays by electron capture, the name of the product nuclide is Zirconium-80, and the symbol for the product nuclide is 80Zr.

In atomic physics, electron capture is a phenomenon that occurs when an electron merges with a nucleus and a neutrino to generate a neutron. The process takes place inside the nucleus, and it is one of the mechanisms for radioactive decay of atoms.

The process of electron capture takes place when the nuclide is not in the lowest energy state. This occurs mostly in atomic nuclei with a large neutron-to-proton ratio, such as isotopes of polonium, tin, and iodine. Nuclide strontium-80 is a nuclide that has 38 protons and 42 neutrons.

When this nuclide decays by electron capture, it results in the formation of a product nuclide. The product nuclide is Zirconium-80, which has 40 protons and 40 neutrons.

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Answer:

20 Km/hr

Explanation:

You have to divide the Km and Hr

I hope it help you

Answer:

B & D is the right ones, I believe :)

Answer:

A periodic table is a tabular array of chemical display, arranged based on atomic number, into groups the coloumns and periods rows.

Answer:

periodic table, in full periodic table of the elements, in chemistry, the organized array of all the chemical elements in order of increasing atomic number—i.e., the total number of protons in the atomic nucleus. When the chemical elements are thus arranged, there is a recurring pattern called the “periodic law” in their properties, in which elements in the same column (group) have similar properties. The initial discovery, which was made by Dmitry I. Mendeleyev in the mid-19th century, has been of inestimable value in the development of chemistry.

Answer:

I think they have high, because the nonpolar molecules usually have a much lower surface tension than polar ones.

If you used "differencet balances" when trying to determine the mass of your sample, the type of error that could occur is a systematic error.

A systematic error is an error that is consistent throughout the experiment and can be caused by the improper calibration of the balances or the improper use of the balances. It is important to calibrate the balances before use and to follow the proper procedure for using them in order to minimize the possibility of a systematic error occurring.

In any measurement it is essential to avoid the different types of errors in order to obtain more reliable measurements.

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Answer:

Explanation:

Here, we want to check if the equation of the reaction is balanced or not

Now, for a balanced equation of reaction, the number of atoms of the individual elements on both sides of the equation is equal

Now, let us check the atoms:

We have 1 Sr on both sides

We have 1 SO4 on both sides

We have 1 Mg on both sides

We have 2 OH on both sides

From what we can see, the equation of the reaction is balanced

Thus, the correct answer choice is B

Answer:

To find the percentage of oxygen in the air sample, we need to know the initial and final volumes of the air sample and the percentage decrease in volume. Assuming the volume decrease is due to the consumption of oxygen, we can calculate the percentage of oxygen in the air sample as follows:

Percentage of oxygen = (volume decrease / initial volume) x 100

In this case, the initial volume is 50 and the final volume is 40, so the volume decrease is:

Volume decrease = initial volume - final volume = 50 - 40 = 10

Therefore, the percentage of oxygen in the air sample is:

Percentage of oxygen = (volume decrease / initial volume) x 100 = (10 / 50) x 100 = 20%

So, the air sample contains 20% oxygen.

To find the percentage of oxygen in the sample of air, we need to use the initial volume of air and the change in volume of oxygen.

If the initial volume of air was 50 and the final volume was 40, then the volume of oxygen that was consumed is:

50 - 40 = 10

This means that 10 units of oxygen were consumed out of the initial 50 units of air, or 10/50 = 0.2 (or 20%) of the original volume of air was oxygen.

Therefore, the percentage of oxygen in the sample of air is 20%.

The most stable conformer of cis-cyclohexane-1 3-diol is when the hydroxyl groups are in the equatorial position.

In cis-cyclohexane-1 3-diol, there are two hydroxyl groups attached to the cyclohexane ring. The hydroxyl groups can either be on the same side of the ring (cis) or on opposite sides (trans). To determine the most stable conformer, we need to consider the interactions between the hydroxyl groups. This is because the axial position creates steric hindrance due to the larger groups being in close proximity. In the equatorial position, the hydroxyl groups are further apart from each other and experience less repulsion.

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Answer:

Explanation:

When a comet enters the solar system it curves towards the Sun due to the Sun's gravitational pull. Every celestial object in the universe has a gravitational pull whose force is dependent on the object's mass. The larger the object is the more gravitational pull it will have. The Sun is the largest object in our Solar system and therefore has the most gravitational pull. This is why the comet curves toward the Sun, but the opposite does not happen because the comet's gravitational pull is not strong enough to pull the Sun.                  

Answer: Most methods for making new elements involve a cyclotron, which speeds up atoms to high velocities before they smash into other atoms—these atoms are usually of different elements. This causes the nuclei to combine, creating new heavier elements.

Explanation: How are superheavy elements made?​

Answer:

The ice shrinks (decreases volume) and becomes more dense. The ice density will increase from . 92g/cm^3 to that of liquid water (1g/cm^3).

Explanation:

For the given equation, the mole-to-mole ratio and volume-to-volume ratio for all the gaseous reactants and products are 1:1.

For the given equation:

CH4(g) + O2(g) → CO2(g) + H2O(g)

Reactant/Product:

CH4(g)

O2(g)

CO2(g)

H2O(g)

Mole-to-Mole Ratio:

By comparing the reactant and product coefficients, we may extract the mole-to-mole ratio from the balanced equation.

CH4(g): 1 mole

O2(g): 1 mole

CO2(g): 1 mole

H2O(g): 1 mole

All of the reactants and products have a mole-to-mole ratio of 1:1:1:1.

Ratio of Volume to Volume:

The ideal gas law, which states that under constant temperature and pressure, the volume of a gas is directly proportional to the number of moles in the gas, can be used to calculate the volume-to-volume ratio.

All gaseous reactants and products have a mole-to-mole ratio of 1:1, hence the volume-to-volume ratio will also be 1:1. As a result, the volume of drug A and substance B will be equal.

You can just take the volume of substance A as the value for substance B if you know the volume of substance A and are trying to solve for the volume of substance B. Alternatively, the quantity of substances A and Bwill be the same, given the 1:1 volume-to-volume ratio.

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The net ionic equation for the reaction between copper(II) sulfate and ammonium hydroxide depends on whether a reaction occurs.

If a reaction occurs, the balanced net ionic equation will be provided. Otherwise, if no reaction occurs, the notation "nr" will be used to indicate no reaction.When copper(II) sulfate (CuSO4) and ammonium hydroxide (NH4OH) are mixed in aqueous solution, they may undergo a precipitation reaction if a reaction occurs.

In this case, the copper(II) ion (Cu2+) from copper(II) sulfate reacts with the hydroxide ion (OH-) from ammonium hydroxide to form a precipitate of copper(II) hydroxide (Cu(OH)2).The balanced net ionic equation for the reaction, assuming a precipitation occurs, is:

Cu2+ (aq) + 2 OH- (aq) → Cu(OH)2 (s)

On the other hand, if no reaction occurs, it means that there are no significant chemical changes taking place when the two solutions are mixed. In this case, the notation "nr" (no reaction) would be used to indicate that no reaction occurs.

It is important to note that the precise conditions, concentrations, and stoichiometric ratios of the reactants can influence whether a reaction occurs or not. Conducting the actual experiment and observing the formation or lack of formation of a precipitate would provide definitive evidence of whether a reaction takes place.

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Answer:

3 significant figures

Explanation:

I underlined the significant figures in this number:

0 . 0 0 1 3 0