In a circus act, a uniform board (length 3.00 m, mass 25.0 kg ) is suspended from a bungie-type rope at one end, and the other end rests on a concrete pillar. When a clown (mass 79.0 kg ) steps out halfway onto the board, the board tilts so the rope end is 30∘ from the horizontal and the rope stays vertical. Calculate the force exerted by the rope on the board with the clown on it.

When a mass m particle is released onto a smooth inclined plane (where the frictional force F=0), it will glide down the slope.

We resolve in the direction of motion in order to get the particle's sliding acceleration.

F=ma, 

mg cos(90∘−θ)=ma, 

g cos(90∘−θ)=a, 

g sin(θ)=a.

How many Newtons is the net force while the block is travelling at a constant speed?

Zero. Newton's first law of motion states that any object travelling at a constant speed experiences no net external forces, hence the total amount of forces acting on the object must be zero. The mathematical expression for an item being under no net external force is Fnet=0 or F=0.

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Explanation:

This problem is solved by determining how long it takes the arrow to fall to the ground in exactly the same manner as if the arrow was dropped with no horizontal velocity. The time required for the arrow to fall to the ground will be the same time that the arrow flies horizontally at 60.0 m/s, so

d=1/2at^2

solved for t=√2d/a

t=√(2)(2.00m)/9.80m/s^2 =0.639s

The time required for the fall is multiplied by the horizontal velocity to get the horizontal distance.

d(horizontal)=v(horizontal)×time=60.0m×0.639s =38.3m

The arrow will fly 37.8 meters in the horizontal direction before it strikes the ground.

Projectile motion is a form of motion experienced by an object or particle that is projected near Earth's surface and moves along a curved path under the action of gravity only.

Given is an arrow fired perfectly along the horizontal direction with velocity of 60 m/s. The arrow was 2 m above the ground when it was released.

initial horizontal velocity = u[H] = 60 m/s

initial vertical velocity = u[V] = 0 m/s

Horizontal acceleration = a[H] = 0 m/s²

Vertical acceleration = a[V] = 9.8 m/s²

Vertical distance = S[V] = 2 m

Using second equation of motion for vertical direction to calculate time taken to reach the ground.

S[V] = u[V] × t + 1/2 a[V] × t²

S[V] =  1/2 × a[V] × t²

2 = 1/2 x 9.8 x  t²

4/9.8 =  t²

t² = 0.4081

t = 0.63 seconds

Horizontal distance covered = S[H] = u[H] x t

S[H] = 60 X 0.63 = 37.8 meters

Therefore, the arrow will fly 37.8 meters in the horizontal direction before it strikes the ground.

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a. The magnitude and direction of the centripetal acceleration and force when he is spinning at constant angular velocity is 8.72 m/s^2 and 654.0 N respectively.

b.  The astronaut is experiencing 0.89 g when moving at constant angular velocity.

c. The torque that is needed to bring the centrifuge to a stop 6875 Nm.

Angular velocity is described as a pseudovector representation of how fast the angular position or orientation of an object changes with time.

The magnitude of the centripetal acceleration and force, we will use the formula: a = v^2 / r, where v is the tangential velocity and r is the radius of the centrifuge.

a = (2pi20m15.02pi/60)^2 / 20m = 8.72 m/s^2

To calculate the force, we will use the formula

F_ = ma, where m is the mass of the astronaut, 75.0 k

F_ = 75.0 kg * 8.72 m/s^2 = 654.0 N

b. To calculate  the number of g's the astronaut is experiencing when moving at constant angular velocity, we will divide the centripetal acceleration by the acceleration due to gravity, 9.8 m/s^2

8.72 m/s^2 / 9.8 m/s^2 = 0.89 g

c.

Torque = I * alpha, where I is the moment of inertia and alpha is the angular acceleration.

I = (1/2) * 5500.0 kg * 20.0m^2 = 55000 kgm^2

The angular acceleration can be found using the formula

Alpha = (change in angular velocity) / (change in time)

The change in angular velocity is 15.0 rpm - 0 rpm = 15.0 rpm and the change in time is 2.0 minutes = 120 seconds

alpha = 15.0 rpm / 120 s = 0.125 rad/s^2

Torque = 55000 kgm^2 * 0.125 rad/s^2 = 6875 Nm

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Answer:The correct statement about electric charges is:

"An object with a negative charge and an object with a positive charge will attract each other."

Explanation:

*an object with a negative charge and an object with a positive charge will attract each other" this statement is true.

Electric charge is the physical property of matter that experiences force when it is placed in electric field. F = qE where q is amount of charge, E = electric field and F = is force experienced by the charge. there are two types of charges, positive charge and negative charge which are generally carried by proton and electron resp. like charges repel each other and unlike charges attract each other. the flow charges is called as current. Elementary charge is amount of charge a electron is having, whose value is 1.602 x 10⁻¹⁹ C.

Hence option B is correct.

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The magnitude of the magnetic force on a proton is 1.68 ✕ 10^−16 N, directed towards the negative y-direction. The magnitude of the magnetic force on an electron is also 1.68 ✕ 10^−16 N, but directed towards the positive y-direction.

Begin by using the formula for the magnetic force on a charged particle moving in a magnetic field:

F = q * v * B * sin(θ)

where F is the magnetic force, q is the charge of the particle, v is the velocity of the particle, B is the magnetic field strength, and θ is the angle between the velocity vector and the magnetic field vector.

For a proton, the charge is +e, where e is the elementary charge (1.6 ✕ 10^−19 C). The velocity of the proton is given as 3.99 ✕ 10^5 m/s in the positive x-direction. The magnetic field strength is 2.93 ✕ 10^−8 T in the positive z-direction.

The angle θ between the velocity vector and the magnetic field vector is 90 degrees since the velocity is perpendicular to the magnetic field.

Substituting the values into the formula, we get:

F_proton = (+e) * (3.99 ✕ 10^5 m/s) * (2.93 ✕ 10^−8 T) * sin(90°)

F_proton ≈ 1.68 ✕ 10^−16 N

Since the proton has a positive charge, the magnetic force is directed opposite to the direction of electron flow, which is in the negative y-direction.

Repeat the steps for an electron, but note that the charge is -e. The direction of the force on an electron will be opposite to that of a proton.

F_electron = (-e) * (3.99 ✕ 10^5 m/s) * (2.93 ✕ 10^−8 T) * sin(90°)

F_electron ≈ -1.68 ✕ 10^−16 N

The force on an electron is also 1.68 ✕ 10^−16 N, but directed towards the positive y-direction.

Remember to consider the proper units and take into account the directions of charge, velocity, and magnetic field when calculating the magnetic force on a charged particle.

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The momentum of the baseball with a mass of 0.14 kg and velocity of 41.26 m/s is determined as 5.78 kgm/s.

The momentum of the baseball is calculated by applying the following formula as shown below;

P = mv

where;

The momentum of the baseball is calculated as follows;

mass of the baseball = 0.14 kg

velocity of the baseball = 41.26 m/s

momentum, P = mv

P = 0.14 kg  x  41.26 m/s

P = 5.78 kgm/s.

Thus, the momentum of the baseball with a mass of 0.14 kg and velocity of 41.26 m/s is determined as 5.78 kgm/s by applying the formula for linear momentum.

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The complete question is below:

Imagine a baseball pitcher and a batter. The baseball has a mass of 0.14 kg. The ball is pitched to the right with a velocity of 41.26 m/s. What is the momentum of the baseball?

Answer:

PE = 137.2931 J

Explanation:

PE = 137.2931 J

Answer: H=5.1m

Explanation:

Given:

Ball 1 height= 10m

Ball 2 initial velocity=10m/s

use the kinematic equation:

S=(vi)t+12at2

I choose my sign convention to be up=positive, down=negative, so  a=−9.81ms2 (a is taken as the value of gravity)

Ball 1 dropped from 10m :

−(10−H)=0+12(−9.81)t2

Note that (10-S) is negative because that displacement is *below* the starting point.

12(9.81)t2=10−H

 ——- equation (1)

Ball 2 thrown upward at 10 m/s :

H=(10)t+12(−9.81)t2

or

12(9.81)t2=10t−H

 ——- equation (2)

equation (1) minus equation (2):

0=(10−H)−(10t−H)

t=1       equation (1):

12(9.81)12=10−H

H=5.1m

Given Information:

Ball One:

\(\vec y_{0} = 10 \ m\) (Indicating the initial position)

We also know the ball was dropped from rest. So, \(\vec v_{0_{1} } = 0 \ m/s\).

Ball Two:

\(\vec v_{0} = 10 \ m/s\) (Indicating the initial velocity)

We also know the ball was throw from the ground. So, \(\vec y_{0_{1} } = 0 \ m\).

The Information we want to Find:

\(\vec y_{c} = ?? \ m\) (Indicating the position the two projectiles collide)

Using the Following Kinematic Equation to Solve:

\(\Delta \vec x = \vec v_{0}t + \frac{1}{2} \vec at\)

For ball one...

\(\Delta \vec y = \vec v_{0}t + \frac{1}{2} \vec a_{y} t\)

\(\Longrightarrow \vec y_{c}- \vec y_{0} = \vec v_{0_{1} }t + \frac{1}{2} \vec a_{y}t\)

\(\Longrightarrow \vec y_{c}- \vec y_{0} = (0)t + \frac{1}{2} \vec a_{y}t\)

\(\Longrightarrow \vec y_{c}- \vec y_{0} = \frac{1}{2} \vec a_{y}t\)

\(\Longrightarrow \vec y_{c} = \frac{1}{2} \vec a_{y}t +\vec y_{0}\) => Equation 1

For ball two...

\(\Delta \vec y = \vec v_{0}t + \frac{1}{2} \vec a_{y}t\)

\(\Longrightarrow \vec y_{c}- \vec y_{0_{1} } = \vec v_{0}t + \frac{1}{2} \vec a_{y}t\)

\(\Longrightarrow \vec y_{c} = \vec v_{0}t + \frac{1}{2} \vec a_{y}t +\vec y_{0_{1} }\)

\(\Longrightarrow \vec y_{c} = \vec v_{0}t + \frac{1}{2} \vec a_{y}t + 0\)

\(\Longrightarrow \vec y_{c} = \vec v_{0}t + \frac{1}{2} \vec a_{y}t\) => Equation 2

Set equations 1 and 2 equal to each other and solve for the time that they collide.

\(\left \{ {{\vec y_{c} = \frac{1}{2} \vec a_{y}t +\vec y_{0}} \atop { \vec y_{c} = \vec v_{0}t + \frac{1}{2} \vec a_{y}t } \right.\)

\(\Longrightarrow \frac{1}{2} \vec at +\vec y_{0}= \vec v_{0}t + \frac{1}{2} \vec at\)

\(\Longrightarrow \vec y_{0}= \vec v_{0}t\)

\(\Longrightarrow t=\frac{\vec y_{0}}{\vec v_{0}}\)

\(\Longrightarrow t=\frac{10}{10}\)

\(\Longrightarrow t=1 \ s\)

Thus, the balls collide at time, t=1 s. We can now use this time to plug into equation 1 or 2 to find the height at which they collide. I will use equation 1.

\(\Longrightarrow \vec y_{c} = \frac{1}{2} \vec a_{y}t +\vec y_{0}\)

\(\Longrightarrow \vec y_{c} = \frac{1}{2} (-9.8)(1) +10\)

\(\Longrightarrow \vec y_{c} = 5.1 \ m \ \therefore \ Sol.\)

*Note* \(\vec a_{y}\) is the acceleration of gravity (\(-9.8 \ m/s^2 \ or \ -32 \ ft/s^2\))

Final Answer: The balls collide at the height 5.1 m.

Answer:

281.25 J

Explanation:

We are told that the two objects with masses m and 3m.

Also that energy stored in the spring is 375 joules.

Now, initially the centre of mass of the system took place at rest, it means v1 = v and v2 = v/3

Thus, from principle of conservation of energy, we have;

½mv² + ½(3m)(v/3)² = 375J

(m + 3m/9)½v² = 375

(4/3)m × ½v² = 375

Multiply both sides by ¾ to get;

½mv² = 375 × ¾

½mv² = 281.25 J

Therefore, energy of lighter body is 281.25 J

The following is not a source of outdoor air pollution : D) Household cleaning products.

Presence of one or more substances in air at concentration or for a duration above the natural level is called air pollution.

Outdoor air pollution refers to pollutants that are released into the atmosphere by sources outside of buildings or structures. The sources of outdoor air pollution can be natural or human-made. Some examples of sources of outdoor air pollution are:

A) Exhaust from cars and trucks

B) Smoke from factories and power plants

C) Pollen from trees and plants

D) Solid fuel burning

E) Forest fires

Therefore, the correct option is D) Household cleaning products.

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Note: The question given on the portal is incomplete. Here is the complete question.

Question: Sierra lives in a southwestern town in a valley where air pollutants sometimes settle. The mountains that surround the town keep air pollution from blowing away. Sometimes Sierra can actually see the pollution in the air. Which choice is NOT a source of outdoor air pollution?

A) Exhaust from cars and trucks

B) Smoke from factories and power plants

C) Pollen from trees and plants

D) Household cleaning products.

The nucleons have less mass, because matter is converted into binding energy. Option D is correct.

During the process of combining a neutron and a proton to form a nucleus, a small amount of mass is converted into binding energy. This is due to the strong nuclear force that holds the nucleus together. The mass of the nucleus is slightly less than the sum of the masses of the individual nucleons, and the difference in mass is referred to as the mass defect.

This mass defect is related to the binding energy of the nucleus through Einstein's famous equation E=mc², where E is energy, m is mass, and c is the speed of light. The mass defect represents the amount of mass that is converted into binding energy to hold the nucleus together. Option D is correct.

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Answer:

1.58901572907

Explanation:

n = 1 / sin(c)

\(n=\frac{1}{sin(c)}\)

Explanation:

You want  N/m

 N = 66 * 9.81

 m = 2.3 x 10^-2 m

66* 9.81 / 2.3 x 10^-2  = 28150 =  28 000 N/m    to two S D

Answer:

The size of the force that pushes the wall is 12,250 N.

Explanation:

Given;

mass of the wrecking ball, m = 1500 kg

speed of the wrecking ball, v = 3.5 m/s

distance the ball moved the wall, d = 75 cm = 0.75 m

Apply the principle of work-energy theorem;

Kinetic energy of the wrecking ball = work done by the ball on the wall

¹/₂mv² = F x d

where;

F is the size of the force that pushes the wall

¹/₂mv² = F x d

¹/₂ x 1500 x 3.5² = F x 0.75

9187.5 = 0.75F

F = 9187.5 / 0.75

F = 12,250 N

Therefore, the size of the force that pushes the wall is 12,250 N.

A current of a 6 flows through a light bulb for 12 s. The total charge that passes through the light bulb during the given time is 72 coulombs.

To calculate the total charge that passes through the light bulb, we need to use the formula Q = I * t, where Q represents the charge in coulombs, I represents the current in amperes, and t represents the time in seconds.

Step 1: Identify the known values:

Current (I) = 6 amperes

Time (t) = 12 seconds

Step 2: Calculate the charge using the formula:

Q = I * t

Step 3: Substitute the known values into the formula:

Q = 6 amperes * 12 seconds

Q = 72 coulombs

Therefore, the total charge that passes through the light bulb during the given time is 72 coulombs.

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Answer:

\(N(t)=41\, \,e^{-0.065*t}\)

Explanation:

We use exponential decay for this example, considering that the initial amount of substance is 41 grams, and the continuous rate of decay is 6.5%:

\(N(t)=N_0\, \,e^{-k*t}\\N(t)=41\, \,e^{-0.065*t}\)

where N(t) is the Krypton's mass of the sample in grams, in terms of number of years "t"

Using the exponential distribution concept, the expression which models the function can be expressed thus : \( N(t) = 41 e^{0.065t} \)

Given the Parameters :

Using the exponential decay relation :

Hence, following the exponential Decay relation ; the function which models the mass of krypton based on the initial amount, decay rate and time can be expressed thus :

Therefore, the function which models the scenario is \( N(t) = 41 e^{0.065t} \)

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Where,

. m is the mass in kilograms

. g is the acceleration due to gravity

. h is the height in meters

Hope it helpz~ uh..

The left hemisphere of the brain is primarily needed in scenario, Solving a complex mathematical problem. Option a is correct.

The brain is divided into two hemispheres, left and right, and they are specialized for different cognitive functions. The left hemisphere of the brain is primarily responsible for language processing, logical reasoning, and analytical thinking. Solving a complex mathematical problem involves logical reasoning, analytical thinking, and the use of language, all of which are primarily controlled by the left hemisphere of the brain.

Mathematical problems often require precise calculations, sequencing of steps, and the use of symbols and formulas, all of which require a strong left-brain function. In contrast, appreciating a work of art, listening to music, and recognizing facial expressions are all more complex perceptual and emotional processes that involve the right hemisphere of the brain. Option a is correct.

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--The complete question is, In which of the following scenarios is the left hemisphere of the brain primarily needed?

a. Solving a complex mathematical problem.

b. Appreciating a work of art

c. Listening to music

d. Recognizing facial expressions.--

Answer:

a

Explanation:

i just took the test

Answer:it’s c a cup of hot cocoa

Explanation:

Answer:

c, cup of hot cocoa

Explanation:

it might seem like the hot cocoa is the hottest, but because the substance is so small, it has the least thermal energy

The frequency of rotation of Mars is 0.0000113 Hertz.

Given the following data:

To find the frequency of rotation in Hertz:

First of all, we would convert the the value of period in days and minutes to seconds because the period of oscillation of a physical object is measured in seconds.

Conversion:

1 day = 24 hours

24 hours to minutes = \(60\) × \(24\) = \(1440\) minutes

\(1440 + 37 = 1477 \; minutes\)

1 minute = 60 seconds

1477 minute = X seconds

Cross-multiplying, we have:

\(X = 60\) × \(1477\)

X = 88620 seconds

Now, we can find the frequency of rotation of Mars by using the formula:

\(Frequency = \frac{1}{Period}\\\\Frequency = \frac{1}{88620}\)

Frequency of rotation = 0.0000113 Hertz

Therefore, the frequency of rotation of Mars is 0.0000113 Hertz.

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The specific heat capacity of silver is 0.235 J/g°C.

The theory used in this question is the specific heat capacity equation, which states that the amount of energy required to raise the temperature of an object is proportional to the mass, specific heat capacity, and change in temperature.

The equation is Q = mcΔT, where Q is the amount of energy, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.

Explanations given below

Calculate the specific heat capacity of silver by dividing the energy absorbed (197.9 J) by the mass of the silver (55.0 g) and the temperature rise (15°C).

Divide 197.9 J by 825 g°C (55.0 g * 15°C).

             (197.9 J) / (55.0 g * 15°C) = 0.235 J/g°C

The result is 0.235 J/g°C, which is the specific heat capacity of silver.

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The sensitization message to truck owners and the police in my community using the scene of turning effect of forces and stability is Let us work together so that the prioritization of road safety as well as the stability in our community can be secured by the promotion of responsible behavior so that all all road users can be safe.

In the non-associative learning process of sensitization, the delivery of a stimulus repeatedly causes a response's volume to gradually increase. In addition to the recurrent stimulus, sensitization is frequently accompanied by an improvement in responsiveness to a whole class of stimuli.

This is a sort of community-level intervention where we work hand-in-hand with the local population using creative means of contact and communication that enable the target audience to relate to the problems on a personal level.

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Answer: The answer is 120

Explanation:

The net force on particle q₂ is 1.05 x 10¹³ N, directed towards particle q1.

To find the net force on particle q₂, we need to calculate the force between q₁ and q₂, and the force between q₂ and q₃, and then add these two forces together.

The force between two point charges can be calculated using Coulomb's law, which states that

F = k × q₁× q₂ / r²

where F is the force, k is Coulomb's constant (9.0 x 10⁹ N m² / C²), q₁ and q₂ are the magnitudes of the charges, and r is the distance between the charges.

The force between q₁ and q₂ is

F₁ = k × q₁ × q₂ / r₁²

where r₁ = 0.10 m.

Substituting the values, we get

F₁ = 9.0 x 10⁹ N m² / C²  × 8.0 C  × 3.5 C / (0.10 m)² = 2.52 x 10¹³ N

The force between q₂ and q₃ is

F₂ = k  × q₂  × q₃ / r₂²

where r₂ = 0.15 m.

Substituting the values, we get

F₂ = 9.0 x 10⁹ N m² / C²  × 3.5 C  × (-3.5 C) / (0.15 m)² = -1.47 x 10¹³ N

Note that the negative sign indicates that the force is attractive, since q₂ and q₃ have opposite signs.

The net force on q₂ is the vector sum of F₁ and F₂

\(F_{net}\) = F₁ + F₂ = 2.52 x 10¹³ N - 1.47 x 10¹³ N = 1.05 x 10³ N

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Mechanical kinetic energy is the energy of an object due to its motion.

a) Mechanical kinetic energy = (1/2)*mass*(velocity)^2

Mechanical kinetic energy = (1/2)*(6.80 x 10^3 kg)*(23.7 m/s)^2

Mechanical kinetic energy = 3.27 x 10^7 J

b) The mechanical kinetic energy of a moving object can be calculated using the following formula:

KE = 0.5 * m * v²,

where m is the mass of the object and v is the velocity.

In this case, we know the mass of the family car (1237 kg) and the mechanical kinetic energy of the box car (50444 J). To calculate the speed of the family car, we can rearrange the formula to solve for v:

v = √(2*KE/m)

v = √(2*50444/1237)

v = 42.62 m/s

What is Mechanical kinetic energy?

Mechanical kinetic energy is the energy associated with the movement of a body or object. It is also known as the energy of motion and is equal to one half of the mass of the object multiplied by the square of its velocity.

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Answer:

What are the best flowers? (My opinion)

Explanation:

You're welcome.

Answer:

Tulips,

Lilies,

Lotuses on my opinion...

Answer:

5.5

Explanation:

power =energy÷time

power=55÷10

power=5.5