in a classroom demonstration the pressure inside a soft drink can is suddenly reduced to essentially zero.assuming the can to be a cylinder with a height of 11 cm and a diameter of 6.1 cm , find the total upward force exerted on the vertical sides of the can due to atmospheric pressure.

Answers

Answer 1

The total upward force exerted on the vertical sides of the soft drink can that suddenly reduced to essentially zero, (assuming the can to be a cylinder with a height of 11 cm and a diameter of 6.1 cm) due to atmospheric pressure = 2.27 × 10³ N

The can's exterior surface is affected by atmospheric pressure. We must know the complete surface area of the can that is accessible to the air outside the can in order to compute this upward force. The can is a cylinder, and its total surface area is given by the equation:

2πrh + 2πr²

Where,

r = radius

h = height

Hence,

A = {2 (3.14) (3.05) (11)} + 2 (3.14) (3.05)²

= 269.1037

= 0.026 m²

Atmospheric pressure = 101325Pa

= 101325 N/m²

So, the total upward force:

F = P x A

= (101325 × 0.026)

= 2.27 × 10³ N

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Related Questions

A 1200 kg car is traveling 21.1 m/s. It collides with a stationary car of mass 1500 kg, and the two vehicles lock together. What is the speed of the combined cars immediately after the collision?

A) 7.5 m/s

B) 16.5 m/s

C) 9.4 m/s

D) 11.8 m/s

Answers

Answer:

C) 9.4 m/s

Explanation:

\(m_1\) = Mass of moving car = 1200 kg

\(u_1\) = Initial velocity of moving car = 21.1 m/s

\(m_2\) = Mass of stationary car = 1500 kg

\(u_2\) = Initial velocity of stationary car = 0

v = Velocity of the combined cars

As the momentum in the system is conserved we have

\(m_1u_1+m_2u_2=(m_1+m_2)v\\\Rightarrow v=\dfrac{m_1u_1+m_2u_2}{m_1+m_2}\\\Rightarrow v=\dfrac{1200\times 21.1+1500\times0}{1200+1500}\\\Rightarrow v=9.378\approx 9.4\ \text{m/s}\)

The velocity of the combined mass is 9.4 m/s.

Which situation will produce the greatest change of momentum for a 1. O-kilogram cart?

(A) accelerating it from rest to 3. 0 m/s

(B) accelerating it from 2. 0 m/s to 4. 0 m/s (C) applying a net force of 5. 0 N for 2. 0 m/s

(D) applying a net force of 10. 0 N for 0,5 m/s

Answers

Applying a net force of 10.0 N for 0.5 m/s will produce the greatest change of momentum for a 1.0-kilogram cart.

The situation that produces the greatest change of momentum for a 1.0-kilogram cart is (D) applying a net force of 10.0 N for 0.5 m/s. This option results in the greatest change in momentum as it involves the greatest impulse. Impulse is the product of force and time or the change in momentum of an object. The impulse can be calculated using the formulaImpulse (J) = force (F) x time (t)or J = FtWhen a force is applied to an object, it creates a change in momentum. The greater the force or the longer the time of application of the force, the greater the change in momentum. A net force of 10.0 N is applied for 0.5 s. Therefore, the impulse generated is given by J = (10.0 N) x (0.5 s) = 5.0 Ns.Due to the impulse, the velocity of the cart will change from its initial velocity. As momentum is conserved, the change in momentum of the cart will be equal to the impulse applied to it.

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true or false? - A ball is moving upwards and to the left. A net force that points upwards and to the left must be acting on the ball.

Answers

Answer:

false is the answer . in my point of view

False because upwards is downwards

A technician places a double-slit assembly 1.45 m from a reflective screen. The slits are separated by 0.0582 mm.
(a)
Suppose the technician directs a beam of yellow light, with a wavelength of 590 nm, toward the slit assembly, and this makes an interference pattern on the screen. What distance (in cm) separates the zeroth-order and first-order bright fringes (a.k.a. maxima)?
cm

Answers

The distance separating the zeroth-order and first-order bright fringes is 0.79 cm.

How to calculate fringe separation?

The distance (in cm) separating the zeroth-order and first-order bright fringes can be calculated using the formula:

dsin(θ) = mλ

where d is the slit separation, θ is the angle between the line perpendicular to the screen and the line from the slits to the bright fringe, m is the order of the bright fringe, and λ is the wavelength of light.

To solve for the distance between the zeroth-order and first-order bright fringes:

Convert the slit separation from millimeters to meters: d = 0.0582 mm = 5.82e-5 mConvert the wavelength of yellow light from nanometers to meters: λ = 590 nm = 5.90e-7 mSolve for the angle θ for the first-order bright fringe (m = 1):

sin(θ) = (mλ) / d

= (15.90e-7 m) / (5.82e-5 m)

= 0.006019

θ = sin⁻¹(0.006019)

= 0.345°

The distance between the zeroth-order and first-order bright fringes can be calculated using trigonometry:

tan(θ) = opposite / adjacent

where the opposite side is the distance between the zeroth-order and first-order bright fringes, and the adjacent side is the distance from the slit assembly to the screen, which is given as 1.45 m.

Therefore, the distance between the zeroth-order and first-order bright fringes is:

opposite = tan(θ) * adjacent

= tan(0.345°) * 1.45 m

= 0.0079 m = 0.79 cm (to two significant figures)

Therefore, the distance (in cm) separating the zeroth-order and first-order bright fringes is 0.79 cm.

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10. A 25 kg apple cart is being pushed with an applied force of 115 N. The coefficient of friction between the ground and the cart is 0.35. What is the acceleration of the cart?

Answers

Answer:

1.1 m/s²

Explanation:

From the question,

F -mgμ = ma.................... Equation 1

Where F = applied force, m = mass of the apple cart, g = acceleration due to gravity, μ =  coefficient of friction., a = acceleration of the apple cart.

Given: F = 115 N, m = 25 kg,  μ  = 0.35

Constant: g = 10 m/s²

Substitute these values into equation 2

115-(25×10×0.35) = 25×a

115-87.5 = 25a

25a = 27.5

a = 27.5/25

a = 1.1 m/s²

Wat is the statement of law intertia

Answers

Answer:

here

Explanation:

Law of inertia states that a body remains in a position of rest or motion along a straight line unless an external force is applied..

Please mark me as brainliest

Law of inertia, also called Newton's first law, postulate in physics that, if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force.

. two harmonic sound waves reach an observer simultaneously. the observer hears the sound intensity rise and fall with a time of 0.200 s between the maximum intensity and the succeeding minimum intensity. what is the difference in frequency of the two sound waves?

Answers

The difference in frequency of the two sound waves is 11.8 Hz.

The observer will hear the maximum sound intensity when the two waves are in phase, i.e., the crest of one wave coincides with the crest of the other wave. This is followed by the minimum intensity that occurs when one wave's crest coincides with the other wave's trough or the trough of one wave coincides with the crest of the other wave. At this point, the two waves are out of phase. In other words, the two waves are said to have a phase difference of 180°.The time between the maximum intensity and the succeeding minimum intensity is equal to the time taken by the waves to travel a distance equal to half the wavelength (λ/2) of the sound waves, where λ is the wavelength of the sound waves.

Δt = λ/2  ---(1)

The frequency of a sound wave is given by the formula:

f = v/λ --- (2)

Where v is the speed of sound.

The difference in frequency of the two sound waves is given by the formula:

f2 - f1 = v/λ2 - v/λ1 = v(λ1 - λ2)/λ1λ2

Using equation (1) in equation (2):

Δt = λ/2λ = 2Δt  --- (3)

Substituting equation (3) in equation (2):

f2 - f1 = v(λ1 - λ2)/λ1λ2= v (λ1 - 2Δt)/λ1 (2Δt)/λ1f2 - f1 = v(2Δt)/λ1  --- (4)

In the above equation, λ1 is the wavelength of the sound wave with the higher frequency, and λ2 is the wavelength of the sound wave with the lower frequency. The frequency f1 corresponds to the lower frequency sound wave, and f2 corresponds to the higher frequency sound wave.

Substituting v = 343 m/s (the speed of sound in air) and Δt = 0.200 s in equation (4):f2 - f1 = (343 x 2 x 0.200)/λ1f2 - f1 = 137.2/λ1Since λ1 and λ2 are related by the equation:

f2/f1 = λ1/λ2λ1 = (λ2 x f2)/f1f2 - f1 = 137.2λ2f2/f1

From the above equation,f2 - f1 = 137.2λ2f2/f1 - f1

Substituting the values of f1 and f2 and simplifying:

f2 - f1 = 11.8 Hz

Therefore, the difference in frequency of the two sound waves is 11.8 Hz.

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URGENT CAN SOMEONE ANSWER THIS QUESTION AND SHOW THEIR WORK PLEASE! How many moles of ammonia (NH) can be produced from the reaction of 4.0 liters of hydrogen at 50.0°C and 1.2atm of pressure with excess nitrogen?

Answers

The aforementioned circumstances can result in the production of 0.119 moles of ammonia (NH3).

We must utilize the ideal gas law and the stoichiometry of the balanced chemical equation for the reaction between hydrogen (H2) and nitrogen (N2) to make ammonia in order to determine how many moles of ammonia (NH3) were produced.

Let's begin by formulating the reaction's balanced equation:

3H₂ + N₂ → 2NH₃

We can see from the equation that we produce 2 moles of ammonia for every 3 moles of hydrogen. As a result, the molar ratio of ammonia to hydrogen is 2:3.

We must convert the supplied parameters of 4.0 liters of hydrogen at 50.0 °C and 1.2 atm of pressure into moles in order to use the ideal gas law. The ideal gas law and the molar volume of an ideal gas at standard temperature and pressure (STP) may be combined using the equation shown below:

PV = nRT

Where:

The temperature must first be converted from Celsius to Kelvin:

T(K) = T(°C) + 273.15

T(K) = 50.0°C + 273.15 = 323.15 K

To solve for the number of moles (n), we may now rearrange the ideal gas law equation as follows:

n = PV / RT

n = (1.2 atm) * (4.0 L) / (0.0821 L·atm/(mol·K) * 323.15 K) ≈ 0.179 mol

Since ammonia and hydrogen have a 2:3 molar ratio, we can calculate the amount of ammonia created by multiplying (2/3) * 0.179 mol by 0.119 mol.

As a result, the circumstances allow for the production of 0.119 moles of ammonia.

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When naming the compound containing lithium and chlorine, change the
suffix of the anion's name to
O A. ide
B. ite
C. cation
D. anion

Ape_x

Answers

Answer: Ide

Explanation:

Just got it right on the quiz

Answer:Ide

Explanation: thats the answer for a pex

why do the stars appear like pointed objects​

Answers

Answer:

because of where we are and our distance away from them, in reality they're giant balls of burning gas, like the sun. some stars are even bigger than the sun

Explanation:

Please help with this, Im a little stuck!!

Please help with this, Im a little stuck!!

Answers

Answer:

Jwbsbsbdjeiskbsj3kabajj2jjj1jj2j2j3jkkkk3j3j2

. If magnets are knocked around a lot or heated, their magnetism will be reduced or lost. Explain why.

Answers

Answer:

Materials that are known as permanent magnets consist of magnetic domains, where electrons are aligned in pairs within atoms. Magnetism is weakened as a result of damage to this alignment caused by heat and electromagnetic fields.

Explanation:

A G2V star would be the same temperature as a G2Ib star, but much smaller and less luminous.
A) True
B) False

Answers

Answer:

True

Explanation:

False. A G2V star and a G2Ib star would not have the same temperature.

Here correct option is B.

In stellar classification, the spectral type is determined by the temperature of the star, with G2 indicating a relatively moderate temperature. The "V" in G2V represents a main-sequence star, also known as a dwarf star, which is small and relatively less luminous compared to other types of stars.

On the other hand, the "Ib" in G2Ib represents a luminous supergiant star. Supergiants are much larger and more luminous than main-sequence stars. Therefore, while both stars may have a G2 spectral type, the G2Ib star would be larger, more luminous, and likely have a different temperature compared to the G2V star.

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State ten reasons why students in Uganda need to study physics. Use exampes of the possible technological advancements which can be made using the knowledge of physics

Answers

Answer: Studying Plasmas is critical to advance technology development for practical purpose as developing functional fusion reactors and to understand the processes in stars,planets and inter-stellar space.
Physics helps you to understand the world around you, and satisfy your curiosity.Studying physics develops your critical thinking and problem-solving skills.Physicists are versatile, which opens a wide range of future careers.Physics is a global enterprise and offers you the opportunity to work abroad, or in international research collaborations.Physics drives technology advancements, impacting society, the environment and the economy.

The pressure of a liquid at the 10.2 meters depth is 80100 Pascal. - What is the density of the fluid in kg/cubic meter?​

Answers

Answer:

8165.138kg/cubic meter

Explanation:

Pressure= 80100 Pascal.= 1N/m^2

Height=10.2 meters

density of the fluid in kg/cubic meter= ?

g=acceleration due to gravity= 9.81m/s^2

The pressure of a system can be calculated using the expression below

P = ρ g h

Where

p =pressure,

h =depth of the liquid,

ρ = density of the liquid,

g = acceleration due to gravity.

If we substitute those values we have

80100 1N/m^2= ρ × 9.81m/s^2

ρ= 80100/9.81

ρ=8165.138kg/cubic meter

Hence, the density of the fluid in kg/cubic meter is 8165.138kg/cubic meter

a mass is placed on a frictionless, horizontal table. a spring ( ), which can be stretched or compressed, is placed on the table. a 5-kg mass is anchored to the wall. the equilibrium position is marked at zero. a student moves the mass out to and releases it from rest. the mass oscillates in simple harmonic motion. find the position, velocity, and acceleration of the mass at time .

Answers

The position is given by \(\(x = A \cos(\omega t)\)\), velocity is \(\(v = -A \omega \sin(\omega t)\)\), and acceleration is \(\(a = -A \omega^2 \cos(\omega t)\)\).

To find the position, velocity, and acceleration of the mass at time \(\(t\)\) in simple harmonic motion, we can use the equations of motion for harmonic oscillators.

Let's denote the equilibrium position as \(\(x = 0\)\) and the initial displacement of the mass as \(\(A\)\). The angular frequency, \(\(\omega\)\), of the oscillation can be calculated by:

\(\(\omega = \sqrt{\frac{k}{m}}\),\)

where;

\(\(k\)\) = spring constant and \(\(m\)\) is the mass.

The position of the mass at time \(\(t\)\) is given by

\(\(x = A \cos(\omega t)\)\)

The velocity of the mass at time \(\(t\)\) is given by

\(\(v = -A \omega \sin(\omega t)\)\)

The acceleration of the mass at time \(\(t\)\) is given by

\(\(a = -A \omega^2 \cos(\omega t)\)\)

In this case, since the mass is initially at rest and released from rest, \(\(A\)\) is the initial displacement of the mass. As the student moves the mass out, \(\(A\)\) would be the initial displacement of the mass.

Using these equations, you can calculate the position, velocity, and acceleration of the mass at any given time \(\(t\)\) in the simple harmonic motion.

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A car is launched by a spring and goes to the top of a loop. Fill in the energy bar chart by drawing a vertical bar(s) in the correct position (both Initial & Final conditions).

Answers

Answer:

A) the initial point all energy is elastic potential and the final point all energy is kinetic

B) a bar graph the two bars have the same height and the sum of their height is the initial energy

C) two bars, one for the  kinetic energy and the other for the gravitational potential energy.

Explanation:

A) For this exercise we must use the energy conservation relations

starting point. When the spring is compressed

        Em₀ = K_e = ½ k x²

end point, at the bottom of the loop

        Em_f = K = ½ m v²

energy is conserved

        Em₀ = Em_f

         ½ k x² = ½ m v²

         v = \(\sqrt{ \frac{k}{m} }\)   x

In a bar graph the initial point all energy is elastic potential and the final point all energy is kinetic

B) intermediate point in a quarter of the radius

In this case we use the lower part of the loop as the starting point and the quarter part of the bow as the end point.

        Em₀ = K

         Em_f = K + U = ½ m v² + m g R

in a bar graph the two bars have the same height and the sum of their height is the initial energy

C) End point highest part of the loop

   starting point, bottom of loop

         Emo = K = ½ m v₀²

from part A of the exercise we saw that it is equal to the elastic energy of the spring

    final point. Highest part of the loop

         Emf = K + U

         Em_f = ½ m \(v_{f}^2\) + mg (2R)

         

where R is the radius of the loop

         Em₀ = Em_f

        1/2 m v₀² = 1/2 m v_{f}^2+ mg 2R

        v₀² = v_f^2 + 4gR

In a bar graph there are two bars, one for the  kinetic energy and the other for the gravitational potential energy. The sum of the heights of these bars is the initial energy, so the energy is transformed but not created or destroyed in the process.

where is A what is the answer?

Answers

A is nowhere to be found

A copper vessel contains 200 gram of water at 24°C. 112 gram of water at 42° C is added, the resultant temperature of water is 30°C. Calculate the thermal capacity of the calorimeter.​

Answers

The heat capacity depends is the heat absorbed by the calorimeter as

the temperature changes.

Response:

The thermal capacity of the calorimeter is 100.416 J·K⁻¹

What the thermal capacity and how can it be calculated?

Mass of the vessel. m₁ = 200 gram

Temperature of the water, T₁  = 24°C

Mass of the warm water, m₂ = 112 grams

Temperature of the warm water, T₂ = 42°C

Resultant temperature of the water, T₃ = 30°C

The heat capacity of the water = 4.184 J·Kg⁻¹·K⁻¹

Heat lost by the warm water = Heat gained by the cold water + The heat gained by the calorimeter

Let C represent the thermal capacity of the calorimeter

We have;

Change in heat, ΔH = m·c·ΔT

Therefore;

112 × 4.184 × (42 - 30) = 200 × 4.184 × (30 - 24) + C×(30 - 24)

5623.296 = 5020.8 + 6·C

6·C = 5623.296 - 5020.8 = 602.496

\(The \ heat \ capacity \ of \ the \ calorimeter, \ C = \dfrac{602.496}{6} = \mathbf{ 100.416}\)

The thermal capacity of the calorimeter, C = 100.416 J·K⁻¹

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What does it mean if the gravitational potential energy of an Earth-apple system is 10J?10J? (a) Someone did 10J10J of work lifting the apple. (b) Earth did negative work when someone was lifting the apple. (c) A 100−�100−g apple is 10m10m above the ground. (d) Parts (a) and (c) are both correct. (e) We need more information about the coordinate system and the object.

Answers

The gravitational potential energy of an Earth-apple system is 10 J, a) it means someone did the 10 J of work in lifting the apple and c) A 100 gm apple is 10 m above the ground.

Gravitational potential energy is the energy possessed by an object due to its position relative to the ground surface. It is formulated as:

P = mgh

Where m is the mass of the object, g is the acceleration due to gravity of Earth, and h is the height of the object above ground level. So if someone lifts the apple of 100 gm mass, up to 10 m, then the work done by the person will be the equal to the potential energy of the apple at 10 m height.

m = 100 gm = 0.1 kg

g = 10 m/s²

h = 10 m

P = 0.1 × 10 × 10

P = 10 j

Hence the option (d) is correct.

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how do braces protect you while doing sports

Answers

Answer:

they don't, if you get hit in the face then the brackets are gonna rub up against the inside of your mouth then you'll bleed

Explanation:

Courtney wants to practice doing science. Which example best illustrates her
using inquiry?
A. Courtney decides to drop several different objects off her
apartment's porch to see which falls the fastest.
B. Courtney pays close attention in her physical science class to see
if her teacher explains the speed of falling objects.
C. Courtney reads about the history of the study of gravity and learns
about why scientists first studied falling objects.
D. Courtney finds a calculation that explains the speed of falling
objects. She tries to understand the calculation by writing it down.

Answers

Answer:

A

Explanation:

because she wants to practice science and A is the practical option.

PLS HELP 25 POINTS!

Match these items.

1 .
ecology
ancient plants and animals
2 .
fossil fuel
consumers
3 .
chlorophyll
water loss
4 .
animals
relationship of organisms to their environment
5 .
transpiration
nitrogen-fixing bacteria
6 .
groundwater
energy converting pigment
7 .
habitat
producer
8 .
respiration
use of energy in food
9 .
plants
where an organism lives
10 .
rhizobium
stored in porous rock

Answers

The correct matches are: 1. ecology - the relationship of organisms to their environment,2.  fossil fuel - ancient plants and animals, 3. chlorophyll - energy-converting pigment, 4. animals - consumers, 5. transpiration - water loss, 6. groundwater - stored in porous rock,7. habitat - the location where an organism lives, 8. respiration - use of energy in food, 9. plants - producer, and 10. rhizobium - nitrogen-fixing bacteria.

Fossil fuels are energy sources that are formed from the remains of dead plants and animals that were buried and exposed to extreme heat and pressure over millions of years. These fuels include coal, oil, and natural gas and are non-renewable resources because they take so long to form. Fossil fuels are used extensively in many industries, including transportation, electricity generation, and manufacturing, but their use is also associated with environmental problems, such as air pollution and climate change.

Rhizobium is a type of nitrogen-fixing bacteria that is found in the root nodules of leguminous plants such as peas, beans, and clover. These bacteria form a symbiotic relationship with the plant, in which the bacteria convert atmospheric nitrogen into a form that the plant can use for growth and development.

The bacteria infect the root hairs of the plant and form nodules where they reside. Inside the nodules, the bacteria receive carbohydrates from the plant in exchange for fixing nitrogen gas from the air into ammonia. The plant then uses ammonia to make amino acids and other nitrogen-containing compounds that are essential for growth. This process is known as nitrogen fixation, and it helps to replenish the soil with nitrogen, which is necessary for the growth of plants. Without the help of nitrogen-fixing bacteria like Rhizobium, many plants would not be able to survive in nitrogen-poor soils.

Therefore, The correct answers are 1. ecology - the relationship of organisms to their environment,2.  fossil fuel - ancient plants and animals, 3. chlorophyll - energy-converting pigment, 4. animals - consumers, 5. transpiration - water loss, 6. groundwater - stored in porous rock,7. habitat - the location where an organism lives, 8. respiration - use of energy in food, 9. plants - producer, and 10. rhizobium - nitrogen-fixing bacteria.

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A negative charge of -2.5 C and a positive charge of 2.0 C are separated by 100 m. What is the force between the two charges?

Answers

Explanation:

F = k |q1| |q2| / r^2

k = 9 * 10^9

q1 = - 2.5 C

q2 = 2 C

r = 100

r^2 = (10^2)^2 = 10^4

F = (9*10^9) * ( 2.5 ) ( 2) / ( 100)^2

F = 45* 10^9 / 10^4

F = 45 * 10^9 * 10 ^ -4 = 45 * 10^5 N

F = 45 * 10 ^ 5 N

An arrow shot vertically upwards at a speed of 40m/s, hit the target after 2s. How high is the target? How fast did the arrow hit the target?​

Answers

Answer:

Explanation:

kinematics

d=V1*t + 1/2* a * \(t^{2}\)

plug in your knowns into the above equation

d=40*2+1/2*(-9.8)*\(2^{2}\)

60.4m

Vf = Vi+ a*t

Vf = 40 + (-9.8)*2

Vf = 20.4 m/s

17)
A positively charged ion will bond with
A)
a negatively charged ion.
Elin
B)
a neutral atom.
C)
another positively charged ion.
D)
nothing else.

Answers

Answer:

Learn vocabulary, terms, and more with flashcards, games, and other study tools. ... the complete transfer of valence electron(s) between atoms. It is ... The compound is neutral overall, but consists of positively charged ions called cations and negatively ... an ion with net negative charge, having more electrons than protons.

Explanation:

A room has a rectangular shape of 4000 mom by 3600mm according to the architecture plan It is supposed to be fitted with tiles which are square in shape and size of 12 cm. How many tiles are required to cover the entire floor​

Answers

Explanation:

First find the area of the entire floor:

Area of a rectangle= length × width

( 4000mm× 3600mm)

14400000mm²

Area of one square tile??= side ×side

12cm×12cm

144cm²

Convert cm to mm

1cm²=100mm²

144cm²=144cm²/1cm²×100mm²

=14,400mm²

Number of tiles required to cover the entire floor= 14400000mm²/14400mm²

=1000

a test charge determines charge on insulating and conducting balls

Answers

When a test charge is brought near an insulating or conducting ball, it will experience attraction or repulsion depending on the charge of the ball. By measuring the force experienced by the test charge, it is possible to determine the charge on the insulating or conducting ball.

In the case of insulating balls, the charge is determined by rubbing the balls with a material that can transfer charge. This process is called charging by friction. The insulating balls will acquire a static charge, which can be positive or negative. By bringing a test charge near the insulating ball, it is possible to determine the sign of the charge.

In the case of conducting balls, the charge is determined by using a device called an electroscope. The electroscope can detect the presence of charge on the conducting ball by measuring the flow of charge through a metal leaf in response to the presence of the ball. By measuring the direction of flow of charge, it is possible to determine the sign of the charge on the ball.

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how fast should the car be traveling just as it leaves the cliff in order to just clear the river and land safely on the opposite side?express your answer in meters per second.

Answers

Given, The height of the cliff = 25m.

The horizontal distance between the cliff and the opposite side = 30 m.

Acceleration due to gravity = 9.8 m/s²

The formula used: We use the formula below to find the velocity of the car as it leaves the cliff:

v² = u² + 2as

Where:v = final velocity = 0, u = initial velocity = 0, acceleration (a) = g = -9.8 m/s², s = distance = 25 m

Substitute the values in the formula:

The final velocity (v) just before it touches the opposite bank is 0.

So, the above formula becomes,

0 = u² + 2 × (-9.8) × 25u²

= 2 × 9.8 × 25u² = 490u

= √490u

= 22.14 m/s (approx).

The car should be traveling at 22.14 m/s when it leaves the cliff in order to just clear the river and land safely on the opposite side.

The car should be traveling at 22.14 m/s.

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is found that for a certain ultraviolet wavelength, which is unknown, a potential vs of 3 volts is necessary to stop the photoelectrons from reaching the anode a, thus eliminating the photoelectric current. a. determine the frequency of the 500 nm radiation. b. determine the work function for the material. c. determine the energy of the photons associated with the unknown wavelength. d. determine the unknown wavelength

Answers

the frequency is  6x10⁻¹⁴ s⁻¹, the work function is 1.890 x 10⁻¹⁹ J, the energy of photons is  1.875 x 10⁻¹⁸ J and the wavelength is 780 nm.

a. The frequency of the 500 nm radiation is  6x10⁻¹⁴ s⁻¹.

b. The work function for the material can be determined using the equation W = hf - eV, where W is the work function, h is Planck's constant, f is the frequency of the radiation, and eV is the energy necessary to stop the photoelectrons from reaching the anode. In this case, eV = 3 V, so W = 6.63x10⁻³⁴ x 6x10¹⁴ - 3 = 1.890 x 10⁻¹⁹ J.

c. The energy of the photons associated with the unknown wavelength can be determined by using the equation E = hf, where E is the energy of the photon, h is Planck's constant, and f is the frequency of the radiation. Since we do not know the frequency of the unknown wavelength, we can use the equation E = hc/lambda, where c is the speed of light and lambda is the wavelength of the radiation. Since we are given that the potential required to stop the photoelectrons is 3V, we can calculate the energy of the photon as E = 3/1.6x10¹⁹ = 1.875 x 10⁻¹⁸ J.

d. The unknown wavelength can be determined using the equation lambda = hc/E, where h is Planck's constant, c is the speed of light, and E is the energy of the photon. Substituting the values, we get lambda = 6.63x10⁻³⁴ x 3x10⁸/1.875 x 10 = 7.8 x 10⁻⁷ m, or 780 nm.

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