Answers
Answer:
\(5.86\times 10^{-7}\ \text{m}\)
Explanation:
d = Slit separation = 0.11 mm
\(\theta\) = Angle = \(0.61^{\circ}\)
m = Order = 2
\(\lambda\) = Wavelength
We have the relation
\(d\sin\theta=m\lambda\\\Rightarrow \lambda=\dfrac{d\sin\theta}{m}\\\Rightarrow \lambda=\dfrac{0.11\times 10^{-3}\times \sin0.61^{\circ}}{2}\\\Rightarrow \lambda=5.86\times 10^{-7}\ \text{m}\)
The wavelength of the light is \(5.86\times 10^{-7}\ \text{m}\).
Related Questions
Seven little spheres of mercury, each with a diameter of 2 mm. When they coalesce to form a single sphere, how big will it be (i.e. what is its diameter)? How does its surface area compare with the total surface area of the previous Seven little spheres?
Answers
Answer:
The total surface area of the seven little spheres is 1.91 times the total surface area of the bigger sphere.
Explanation:
Volume of a Sphere
The volume of a sphere of radius r is given by:
\(\displaystyle V=\frac{4}{3}\cdot \pi\cdot r^3\)
The volume of each little sphere is:
\(\displaystyle V_l=\frac{4}{3}\cdot \pi\cdot 2^3\)
\(V_l=33.51\ mm^3\)
When the seven little spheres coalesce, they form a single bigger sphere of volume:
\(V_b=7*V_l=234.57\ mm^3\)
Knowing the volume, we can find the radius rb by solving the formula for r:
\(\displaystyle V_b=\frac{4}{3}\cdot \pi\cdot r_b^3\)
Multiplying by 3:
\(3V_b=4\cdot \pi\cdot r_b^3\)
Dividing by 4π:
\(\displaystyle \frac{3V_b}{4\cdot \pi}= r_b^3\)
Taking the cubic root:
\(\displaystyle r_b=\sqrt[3]{\frac{3V_b}{4\cdot \pi}}\)
Substituting:
\(\displaystyle r_b=\sqrt[3]{\frac{3*234.57}{4\cdot \pi}}\)
\(r_b=3.83\ mm\)
The surface area of the seven little spheres is:
\(A_l=7*(4\pi r^2)=7*(4\pi 2^2)=351.86\ mm^2\)
The surface area of the bigger sphere is:
\(A_b=4\pi r_b^2=4\pi (3.83)^2=184.33\ mm^2\)
The ratio between them is:
\(\displaystyle \frac{351.86\ mm^2}{184.33\ mm^2}=1.91\)
The total surface area of the seven little spheres is 1.91 times the total surface area of the bigger sphere.
problem 1
A train starts at rest, accelerates with constant acceleration a for 5minutes,then travels at constant speed for another 5minutes,and the decelerates with a.suppose it travels a distance of 10km in all find a
problem 2
A ball is dropped from a height of 10m.At the same time, another ball is thrown vertically upwards at an initial speed of 10m/sec.How high above the ground will the two balls collide
problem 3
find the resultant of the two velocity vectors and also, find the angle that the resultant makes with the vector
Answers
The constant acceleration of the train is 50/9 m/s².
The two balls will collide at a height of approximately 10.204 meters above the ground.
How to calculate the valueUsing the kinematic equations of motion, we have:
distance = initial velocity * time + 1/2 * acceleration * time^2
For the first phase of acceleration, the initial velocity is zero, the time is 5 minutes = 300 seconds, and the distance traveled is unknown. So we have:
d1 = 0 + 1/2 * a * (300)^2
For the second phase of constant speed, the initial velocity is v, the time is 5 minutes = 300 seconds, and the distance traveled is also unknown. So we have:
d2 = v * 300
For the third phase of deceleration, the initial velocity is v, the time is also 5 minutes = 300 seconds, and the distance traveled is again unknown. So we have:
d3 = v * 300 + 1/2 * (-a) * (300)^2
The total distance traveled is the sum of these three distances:
distance = d1 + d2 + d3 = 1/2 * a * (300)^2 + v * 600 - 1/2 * a * (300)^2 = v * 600
Since the total distance traveled is given as 10 km = 10000 m, we have:
v * 600 = 10000
Solving for v, we get:
v = 10000/600 = 50/3 m/s
Now we can use the second equation above to find a:
d2 = v * 300 = (50/3) * 300 = 5000 m
Therefore, the constant acceleration of the train is:
a = 2 * (5000 - 1/2 * a * (300)^2) / (300)^2 = 50/9 m/s^2
The constant acceleration of the train is 50/9 m/s^2.
Problem 2: The height of the first ball dropped is given as 10m. Let's assume the height of the collision point is h meters above the ground.
Using the kinematic equation for free fall, we have:
h = 10 + 1/2 * g * t^2
where g is the acceleration due to gravity, which is approximately 9.81 m/s^2, and t is the time it takes for the second ball to reach the collision point after being thrown upwards.
The initial upward velocity of the second ball is 10 m/s, and we know that at the collision point, its velocity will be zero, since it will have reached its maximum height and will be momentarily at rest before falling back down.
Using the kinematic equation for motion with constant acceleration, we have:
0 = 10 + (-g) * t
Solving for t, we get:
t = 10/g = 10/9.81 seconds
Substituting this value of t into the first equation, we get:
h = 10 + 1/2 * 9.81 * (10/9.81)^2
Simplifying, we get:
h = 10.204 m
The two balls will collide at a height of approximately 10.204 meters above the ground.
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Three particles having charges of equal magnitude q are fixed at the conrners of an equilateral triangle as shown. two of the charges are negative: the other is positive. which of the following vectors best represents the direction of the resultant electric field at point p, the center of the triangle?
Answers
Vector B of the following vectors best represents the direction of the resultant electric field at point p, the center of the triangle.
What is vector?A quantity or phenomenon that has two independent properties i.e magnitude and direction is named as vector.
At the middle, where it is zero, one can see that the three charges each produce cancelling fields thanks to symmetry.In addition to the triangle's center, the second panel of the picture shows three additional sites in the middle of each triangle leg where E=0, however they are more challenging to calculate analytically.Adding the electric field vectors resulting from each of the two lower point charges will yield the electric field at point P.
E = E1+ E2.
According to the bottom panel of the picture, a point charge's electric field has the formula E = kr2qr.
E =k ea2q uphill and to the right at 60, and E2 =kea2q upward and to the left at 60.
Therefore, E= E1 + E2 = kea2q[(cos60i+sin60j) + (cos60i+sin60j)] = kea2q[2(sin60j)
= 1.73kea2qj. i.e vector B
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what is the Vector product of A=2.00i+3.00j+1.00k and B= 1.00i -3.00j -2,00k
Answers
The vector product of A=2.00i+3.00j+1.00k and B=1.00i-3.00j-2.00k is C=9.00i+4.00j-9.00k.
To find the vector product (also known as the cross product) of two vectors, A and B, we can use the following formula:
C = A × B
Where C is the resultant vector, A and B are the given vectors, and × denotes the cross product.
Given A = 2.00i + 3.00j + 1.00k and B = 1.00i - 3.00j - 2.00k, we can substitute these values into the formula to find the vector product:
C = (2.00i + 3.00j + 1.00k) × (1.00i - 3.00j - 2.00k)
Now, let's expand the cross product using the properties of vector products:
C = (2.00i × 1.00i) + (2.00i × -3.00j) + (2.00i × -2.00k) +
(3.00j × 1.00i) + (3.00j × -3.00j) + (3.00j × -2.00k) +
(1.00k × 1.00i) + (1.00k × -3.00j) + (1.00k × -2.00k)
Now, let's calculate each of these cross products:
C = (2.00 × 1.00) \(i^2\) + (2.00 × -3.00) i × j + (2.00 × -2.00) i × k +
(3.00 × 1.00) j × i + (3.00 × -3.00) \(j^2\) + (3.00 × -2.00) j × k +
(1.00 × 1.00) k × i + (1.00 × -3.00) k × j + (1.00 × -2.00) \(k^2\)
Since i × j = k, j × k = i, and k × i = j, we can simplify the expression further:
C = 2.00k - 6.00i + 4.00i - 9.00j + k - 3.00j - 2.00j - 2.00k
Combining like terms, we get:
C = (2.00i + 4.00i) + (-6.00i - 9.00j - 3.00j) + (2.00k + k - 2.00k)
Simplifying further:
C = 6.00i - 12.00j + k
Therefore, the vector product of A and B is C = 6.00i - 12.00j + k, which can be written as C = 9.00i + 4.00j - 9.00k in terms of i, j, and k.
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The vector product of A and B is -3i - 5j - 9k.
Explanation:The vector product, also known as the cross product, of two vectors A and B is denoted as A x B. It is a vector that is perpendicular to both A and B. To calculate the vector product, you can use the formula A x B = (Ay * Bz - Az * By)i + (Az * Bx - Ax * Bz)j + (Ax * By - Ay * Bx)k.
In this case, we have A = 2.00i + 3.00j + 1.00k and B = 1.00i - 3.00j - 2.00k. Substituting the values into the formula, we get A x B = (3 * -2 - 1 * -3)i + (1 * 1 - 2 * -2)j + (2 * -3 - 3 * 1)k = -3i - 5j - 9k.
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Help please!!
During transcription, the DNA strand being transcribed has the following nucleotides: CTT CAG.
What would be the matching nucleotides on the mRNA?
Select one
1. GAA GUC
2.GUU GTC
3. AUU ATC
4. ACC AUC
Answers
Answer:
l think the correct answer is 1.GAA GUC
A child is riding on a merry go round. As the speed of the merry go round is doubled, the magnitude of the centripetal force acting on the child
a. Remains the same
b. Is quadrupled
c. Is doubled
d. Is halved
Answers
The speed of the merry-go-round is doubled, and the magnitude of the centripetal force acting on the child will be quadrupled.
The formula for the centripetal force is as follows:
F = mv^2/r,
where m is the object's mass,
v is its rotational speed,
and r is its radius.
Since the centripetal force F is directly proportional to the second power of the velocity, doubling the velocity will result in a quadrupling of F.
Therefore, tripling the velocity will result in a nine-fold increase in centripetal force! Additionally, doubling the speed will result in a sixteen-fold increase in centripetal force.
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the mass of the velociraptor and cage together is 175 kg. What is the gravitational potential energy added when when the velociraptor and cage is lifted from the ground to a height of 9 m?
Answers
The gravitational potential energy added when the velociraptor and cage is lifted from the ground to a height of 9 m is approximately 15,998.95 joules.
What is Potential Energy?
Potential energy is a form of energy that is stored in an object due to its position or configuration in a system. It is the energy that an object has the potential to possess, or the ability to do work, as a result of its position or state.
The gravitational potential energy (GPE) added when the velociraptor and cage is lifted from the ground to a height of 9 m can be calculated using the formula:
GPE = mgh
Where m is the mass of the velociraptor and cage, g is the acceleration due to gravity (approximately 9.81 m/\(s^{2}\)), and h is the height lifted.
Given that the mass of the velociraptor and cage together is 175 kg, and the height lifted is 9 m, we can substitute these values into the formula:
GPE = mgh
GPE = (175 kg) x (9.81 m/\(s^{2}\)) x (9 m)
GPE = 15,998.95 J (joules)
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Compare and contrast chemical reactions and nuclear reactions in terms of particles involved . Select all the statements that apply Both chemical and nuclear equations are written with equal signs. Nuclear reactions create a difference in the number of protons, neutrons, and electrons after the reaction. A chemical reaction is the rearranging of atoms to form new substances. E=mc^ aleph 2 applies to both chemical and nuclear reactions. In a nuclear reactionparticles can transmute into others. Chemical reactions produce energy on levels comparable to nuclear reactions The total number of protons, neutrons, and electrons stay the same throughout the chemical reaction.
Answers
Answer:
. A chemical reaction is the rearranging of atoms to form new substances. E=mc^ aleph
7. DRAW A PICTURE TO SHOW WORK.
Brandon buys a new Seadoo. He goes 12
km north from the beach. He jumps
wakes for 6 km to the east. Then chases
a boat 12 km south. He then turns and
goes 3 km to the West. What distance
did he cover? What was his
displacement?
Answers
Distance covered 28 km
displacement is 22.8 km North-East
Explanation;
it is possible for an object to maintain constant velocity when only one non-zero force acts on the object. True or false? Explain.
it is possible for an object to maintain constant velocity when three non-zero act on the object. True or false? Explain
Answers
Answer:
false
Explanation:
False - For an object to maintain a constant velocity, 0 Newtons of net force (i.e., a balance of forces) is required. i. True - Unbalanced forces cause stationary objects to accelerate from rest. In the absence of an unbalanced force, a stationary object would remain at rest.
an object is thrown straight up. which of the following is true abought the sign of workdone by the force of gravity on the object, while the object moves up and then down
Answers
Answer:
Upward: Negative
Downward: Positve
Explanation:
Let upward be positive
We want to find the work done on the object upwards.
The equation of work done due to gravity is
\(f _{g}d \cos( \alpha ) \)
It is read as force of gravity times displacement times cos of the angle between the force and displacement.
Since gravity is happening down of the center of mass and the displacement is upwards, the angle is 180° so
\(f_{g}d \cos(180) \)
Cosine of 180 is -1
so
\( - f_{g}d \)
If we go downwards, the sign will be positive because cos(0)=1
TIME REMAINING
58:50
Shelly tells a friend that her computer needs to be fixed because it has been producing a lot of heat and is smoking. Where
is the error in her statement?
• Heat cannot be described as having been produced.
Thermal energy cannot be produced by electronics.
Her computer should be producing a lot of heat and does not need to be fixed.
Her computer is producing thermal energy, not heat.
Mark this and return
Save and Exit
Next
Submit
Answers
Answer:
Her computer is producing thermal energy, not heat.
Explanation:
Answer:
Her computer is producing thermal energy,not heat
Explanation:
the orientation of an mrna codon relative to a trna anticodon is best described as: a. antiparallel. b. parallel. c. perpendicular. d. non-complementary.
Answers
The orientation of an mRNA codon corresponding to a tRNA anticodon is best described as A: antiparallel.
An anticodon is a three-base sequence, paired with a particular amino acid, that a tRNA molecule brings to the associated codon of the mRNA during translation. The anticodon sequence is said to be complementary to the mRNA, using base pairs in the anti-parallel direction. The tRNA anticodon 3-UAC-5 will make pair with the mRNA codon.
Thus, the orientation of an mRNA codon relative to a tRNA anticodon is said to be antiparallel.
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Select all of the following that are involved in translation:
amino acids
tRNA
mRNA
ribonucleotides
deoxyribonucleotides
RNA Polymerase
Answers
Answer:
Amino Acids
tRNA
mRNA
ribonucleotides
Explanation:
Amino Acids
- During translation, an mRNA sequence is read using the genetic code, which is a set of rules that defines how an mRNA sequence is to be translated into the 20-letter code of amino acids, which are the building blocks of proteins.
tRNA
- At the beginning of translation, the ribosome and a tRNA attach to the mRNA. The tRNA is located in the ribosome's first docking site. This tRNA's anticodon is complementary to the mRNA's initiation codon, where translation starts. The tRNA carries the amino acid that corresponds to that codon. ransfer ribonucleic acid (tRNA) is a type of RNA molecule that helps decode a messenger RNA (mRNA) sequence into a protein. tRNAs function at specific sites in the ribosome during translation, which is a process that synthesizes a protein from an mRNA molecule.
mRNA
- Translation is the process by which a protein is synthesized from the information contained in a molecule of messenger RNA (mRNA). ... Then a transfer RNA (tRNA) molecule carrying the amino acid methionine binds to what is called the start codon of the mRNA sequence.
ribonucleotides
- During transcription, a ribonucleotide complementary to the DNA template strand is added to the growing RNA strand and a covalent phosphodiester bond is formed by dehydration synthesis between the new nucleotide and the last one added.
if a gold atom is considered to be a cube with sides 2.5x10^-9m, how many gold atoms could stack on top of one another in gold foil with a thickness of 1.0x10^-7m?
Answers
This question involves the concepts of thickness and length.
"40" gold atoms could stack on top of one another in the gold foil.
NO. OF GOLD ATOMS THAT CAN STACKWe will use the unitary method here to find out the no. of gold atoms that could stack on top of each other in the gold foil of thickness 1 x 10⁻⁷ m, when the side length of each cubic atom is 2.5 x 10⁻⁹ m.
Therefore,
2.5 x 10⁻⁹ m thick gold foil can stack = 1 gold atom1 m thick gold foil can stack = \(\frac{1}{2.5\ x\ 10^{-9}\ m}\) gold atoms1 x 10⁻⁷ m thick gold foil can stack = \(\frac{1\ x\ 10^{-7}\ m}{2.5\ x\ 10^{-9}\ m}\) gold atoms1 x 10⁻⁷ m thick gold foil can stack = 40 gold atomsLearn more about thickness here:
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The bands on Jupiter are ultimately caused by...
the Coriolis effect.
its magnetic fields.
precession.
the Great Red Spot.
Answers
DOES ANYONE KNOW HOW TO DO THIS?
Question:
Convert 68 MHz to Hz.
Answers
Answer:
68000
Explanation:
1 MHz = 1000 Hz
just multiply by 1000 :)
Calculate the net force on the particle q1.
Answers
Answer:
-12.1
Explanation:
i’m almost sure this is it, i’m checking my old answers
if not let me know and i’ll give you some more answers
In what ways does ecotourism help living things in ecosystems?
Answers
Ecotourism has the potential to eliminate the requirement to hunt wildlife for a living. Ecotourism generates revenue by maintaining the rainforest; deforestation is discouraged because it reduces tourist revenue.
What role does ecotourism play in biodiversity conservation?Ecotourism firms safeguard biodiversity by preserving animals in their natural habitats and preserving natural ecosystems in biosphere reserves, wildlife sanctuaries, and national parks.
Can tourism save the environment?Ecotourism contributes to the preservation of a destination's ecological and biological diversity. For example, since Costa Rica's jungle is so popular with visitors, inhabitants work hard to protect it instead of attempting deforest it for a short-term profit.
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Write two artificial and two natural source of light.
Answers
Two natural sources of light: the sun and the stars
Two artificial sources of light: light bulb and torches
Answer:
Natural lights: Sunlight, Moonlight, or Lightning
Artificial: Light bulb, Candles, or a lighter/matches
Explanation:
An object has a length of 5.0 cm, a height of 3.0 cm and a width of 15.0cm.it has a mass of 24 grams .what is its density
Answers
Answer:
24g/225cm^3
Explanation:
Density = mass/volume.
Calculate volume first so u do 5cm x 3cm x 15cm.
Volume is 225cm^3.
Then divide mass by volume.
The density of the object is 24g/225cm^3.
Finding the density without having the mass having only volume
Answers
.............................................
A car is moving at a constant speed along a straight line. Which statement is true about the forces acting on the car?
Answers
The statement that is true about the forces acting on the car is that the net force acting on the car from all directions is zero. Option A is correct.
What is force?Force is defined as the push or pulls applied to the body. Sometimes it is used to change the shape, size, and direction of the body.
The complete question is
"A car is moving at a constant speed along a straight line. Which statement is true about the forces acting on the car?
A.
The net force acting on the car from all directions is zero.
B.
The net force acting on the car is greater than the car's weight.
C.
The net force acting on the car is in the direction of the car's motion.
D.
The net force acting on the car is in the opposite direction of the car's motion."
The net force operating on the automobile in all directions is zero,
The statement that is true about the forces acting on the car is that the net force acting on the car from all directions is zero. Option A is correct.
Hence option A is correct.
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URGENT HELP IT IS DUE BY TONIGHT PLEASE HELP
Answers
Answer:
45.8
Explanation:
becuse 9.8+36=45.8 simple
you are driving at 18m/s down Lyndale avenue. A car backs out a driveway 25 meters in front of you. You continue at that speed while your brain processes the danger which takes 0.25 seconds. You then slam on the brakes and your car has an acceleration of -5.4m/s^2. Do you stop before reaching the driveway(and hitting the car)? Show your work. This is a two-part problem with constant speed and braking.
Answers
Hello!
For this, first let's calculate time of stop:
t = (V - Vi) / a
Replacing:
t = (0 m/s - 18 m/s) / -5,4 m/s^2
Resolving:
t = -18 m/s / -5,4 m/s^2
t = 3,33 s + 0,25 s = 3,58 s
Now lets calculate distance traveled, with formula:
d = Vi*t + (a*t^2)/2
Replacing:
d = 18 m/s * 3,58 s + (-5,4 m/s^2 * (3,58 s)^2) /2
Resolving:
d = 64,44 m + (-34,604 m)
d = 29,83 m
Then, the vehicle will CRASH
A converging lens has a focal length of 20cm. find graphically the image location for an object at each of the following distances from the lens: (a) 50cm (b) 20cm (c) 15cm (d) -40cm: determine the magnification in each case. Check your results by calculating the image position and lateral magnification from Eqs. (10) and (11), respectively.
Answers
Answer:
4
Explanation:
d
for
haha
very
know
love
do
from
can
and
4 answer
If the current in each wire is the same, which wire produces the strongest magnetic field?
-a wire that is 1 mm thick and not coiled
-a wire that is 2 mm thick and not coiled
-a 1-mm-thick coiled wire with ten loops
-a 2-mm-thick coiled wire with two loops
Answers
Answer:
C
Explanation:
I did this before
Answer:
it is c
Explanation:
cuz i know
.You have always been impressed by the speed of the elevators in your apartment building. You wonder about the maximum acceleration for these elevators during normal operation, so you decide to measure it by using your bathroom scale. While the elevator is at rest on the ground floor,you get in, put down your scale, and stand on it. The scale reads 50 kg. You continue standing on the scale when the elevator goes up, carefully watching the reading. During the trip to the 10th floor, the greatest scale reading was
Answers
Answer:
5.51 m/s^2
Explanation:
Initial scale reading = 50 kg
assume the greatest scale reading = 78.09 kg
Determine the maximum acceleration for these elevators
At rest the weight is = 50 kg
Weight ( F ) = mg = 50 * 9.81 = 490.5 N
At the 10th floor weight = 78.09 kg
Weight at 10th floor ( F ) = 78.09 * 9.81 = 766.11 N
F = change in weight
Change in weight( F ) = ma = 766.11 - 490.5 (we will take the mass as the starting mass as that mass is calculated when the body is at rest)
50 * a = 275.61
Hence the maximum acceleration ( a ) = 275.61 / 50 = 5.51 m/s^2
Question 2 of 25
If JKLM is a parallelogram, what is the length of LM?
K
18
8
M
O A. 10
O B. 18
O C. 8
D. 26
SUBMIT
Answers
Answer:its 10
Explanation:
Answer:
8
Explanation:
___ is experimental coefficient of kinetic friction the slope of the line of best fit between kinetic frction and normal force
Answers
Answer is Force, The kinetic fiction force, also known as sliding friction, only affects moving objects (thus the term "kinetic"). Pushing a box across floorboards is an example of this force opposing sliding motion.
This sort of friction has a particular coefficient of friction (such as rolling friction). The materials used to create the contacting surfaces are particular to this coefficient. The coefficient will be higher on a rougher surface. This is the equation that will assist you in determining the coefficient of kinetic friction: The force holding the items together, or the force perpendicular to the surfaces in contact, is known as the normal force.
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