the distance from the central maximum where a bright fringe from one pattern first coincides with a bright fringe from the other can be found by calculating the LCM of d₁ and d₂ using their respective values.
To find the distance from the central maximum on the screen where a bright fringe from one pattern coincides with a bright fringe from the other pattern, we can use the formula for the fringe spacing in a double-slit experiment.
The fringe spacing (d) is given by the equation:
d = λL / D
Where:
λ = wavelength of light
L = distance from the double slits to the screen
D = distance between the two slits (slit separation)
For the first pattern with a wavelength of 450 nm (0.450 μm), the fringe spacing will be:
d₁ = (0.450 μm) × (2.0 m) / (2.0 mm)
Similarly, for the second pattern with a wavelength of 540 nm (0.540 μm), the fringe spacing will be:
d₂ = (0.540 μm) * (2.0 m) / (2.0 mm)
Since we are interested in finding the distance from the central maximum where the two bright fringes coincide, this distance will be an integral multiple of the fringe spacing.
To determine the smallest distance from the central maximum where this occurs, we need to find the least common multiple (LCM) of the fringe spacings (d₁ and d₂).
LCM(d₁, d₂) will give us the distance from the central maximum where the bright fringes from both patterns coincide.
Therefore, the distance from the central maximum where a bright fringe from one pattern first coincides with a bright fringe from the other can be found by calculating the LCM of d₁ and d₂ using their respective values.
Learn more about bright fringe:
https://brainly.com/question/31315270
#SPJ4
two point charges of 2.00 μc and -2.00 μc are 0.100 m apart. what is the electric field at the point midway between the two charges?
Two point charges of 2.00 μc and -2.00 μc are 0.100 m apart the electric field at the point midway between the two charges: 7.20 x 10⁵ N/C.
The electric field at the point midway between two point charges can be determined by calculating the electric fields produced by each charge and then summing them up as vectors.
In this case, we have two point charges, +2.00 μC and -2.00 μC, separated by a distance of 0.100 m. Since the charges have the same magnitude but opposite signs, the electric fields they produce at the midpoint will have equal magnitudes but point in opposite directions.
The electric field produced by a point charge is given by the equation: E = k × |q| / r²
where E is the electric field, k is the electrostatic constant, |q| is the magnitude of the charge, and r is the distance between the charge and the point where the field is being calculated.
For the midpoint, the distances from each charge are equal, i.e., r = 0.050 m. Therefore, the electric field produced by each charge is:
E₁ = k × |2.00 μC| / (0.050 m)²
E₂ = k × |-2.00 μC| / (0.050 m)²
Substituting the values and considering the opposite directions of the fields, we have: E = E₁ - E₂
Calculating the magnitudes and taking into account the values of k and the charges, we find:
E = (9.0 x 10⁹ N·m²/C²) × (2.00 μC) / (0.050 m)²
E ≈ 7.20 x 10⁵ N/C
Therefore, the electric field at the point midway between the two charges is approximately 7.20 x 10⁵ N/C.
To know more about electric field, refer here:
https://brainly.com/question/4440057#
#SPJ11
I need help with 16 and 17! Pls show your work and use these formula for both: m1v1+m2v2=(m1+m2)vf
The mass of the skateboard by conservation of momentum will be 2.84 kg.
In physics, what is momentum?Momentum can be defined as the force behind a body's motion.
Momentum is measured by "mass velocity" since it depends on both the speed and the direction of the body's motion. Since velocity is a vector and mass is a scalar, momentum is a vector quantity.
skateboard mass is 2.84 kg.
m1 = student mass = 45.5 kg
m2= skateboard Mass
u = student Velocity = 4.25 m/s
v = student and skateboard velocity = 4 m/s
As momentum is conserved we have
m1*u=m1*v+m2*v
m2=(m1u-m1v)/v
m2=(45.5*4.25-45.5*4)/4
m2=2.84 kg
To know more about momentum visit:
https://brainly.com/question/24030570
#SPJ1
A person is riding a bicycle, and its wheels have an angular velocity of 19. 4 rad/s. Then, the brakes are applied and the bike is brought to a uniform stop. During braking, the angular displacement of each wheel is 14. 6 revolutions.
(a) How much time does it take for the bike to come to rest?
(b) What is the anguar acceleration (in rad/s2) of each wheel?
The answer for A. It takes approximately 15.15 seconds for the bike to come to rest and for B. The angular acceleration of each wheel is approximately -1.28 rad/s². The negative sign indicates deceleration or braking.
A. To find the time it takes for the bike to come to a rest, we can use the relationship between angular displacement (θ), angular velocity (ω), and time (t):
θ = ωt
Given that the angular displacement of each wheel is 14.6 revolutions, we need to convert it to radians:
θ = 14.6 revolutions * 2π radians/revolution
θ = 14.6 * 2π radians
Now, we can rearrange the formula to solve for time:
t = θ / ω
t = (14.6 * 2π radians) / 19.4 rad/s
Simplifying the expression:
t ≈ 15.15 seconds
Therefore, it takes approximately 15.15 seconds for the bike to come to rest.
B. To find the angular acceleration (α) of each wheel, we can use the formula:
α = ωf - ωi / t
Since the bike comes to a uniform stop, the final angular velocity (ωf) is 0 rad/s. The initial angular velocity (ωi) is given as 19.4 rad/s, and the time (t) is 15.15 seconds.
α = (0 - 19.4 rad/s) / 15.15 s
Simplifying the expression:
α ≈ -1.28 rad/s²
Therefore, the angular acceleration of each wheel is approximately -1.28 rad/s². The negative sign indicates deceleration or braking.
To learn more about angular acceleration from the given link
https://brainly.com/question/13014974
#SPJ4
A track and field athlete is competing in the hammer throw event. The athlete is 181cm tall, with an arm length of 90 cm and is using a standard ball and chain for the event which is 121cm long. As the athlete begins to spin , their body becomes the center of the motion, with both arms holding on to the ball and chain handleIf the initial linear ve locity of the ball and chain is 29m/s upon its release, how fast (total angular velocity rads) was the athlete spinning it
Total angular velocity is 13.7 rad/s.
Given that an object is moving in a circular motion, we can infer that the system involving the athlete, the ball, and the rope is also moving in a round fashion.
We are informed that the athlete is 181 cm tall, has a 90 cm arm span, and will be using a 121 cm long ball and chain for the competition. With both arms hanging on to the ball and chain handle as the athlete starts to spin, their body becomes the centre of the action. The ball and chain's initial linear velocity is 29 m/s when it is released.
The radius of the path= 90 cm + 121 cm
= 211cm or 2.11 m
Using;
linear velocity = radius * angular velocity
V = rω
ω = V/r
ω = 29m/s/2.11 m
ω = 13.7 rad/s
angular velocity of athlete is 13.7 rad/s
learn more about angular velocity here
https://brainly.com/question/13649539
#SPJ4
A cannon ball is launched from the edge of a cliff that is 6 m above the ground. It has a
horizontal velocity of 10.2 m/s. It takes 3.7 s for the cannonball to reach the ground.
How far from the cliff does it land?
Record your answer to the nearest hundredth.
Answer:
Sh = Vh t horizontal distance traveled
Sh = 10.2 m/s * 3.7 s = 37.74 m
Can you help me with the
1)Hypothesis:what you expect
2) Apparatus/material
3) Variables:
Controlled-Keep constant
Manipulated-Change this
Reporting -What you expect to change
4)Expected results
5)Limitations
6)Source of errors
7)Precaution
Hypothesis:
The hypothesis for this experiment would be that the order of arrangement of the boy's shirts by color, from the darkest to the lightest, will have an effect on how hot he feels.
2. Apparatus/Materials:
Five shirts of the same material, design, and size, but in different colors (black, red, orange, green, and white).A thermometerA stopwatchA heat sourceA fanVariables:
Controlled Variables: The temperature of the heat source
Manipulated Variable: The color of the shirt worn by the boy.
Responding Variable: The change in temperature that the boy experiences.
Expected Results:
The boy should feel hotter when he wears the darker colored shirts in comparison to the lighter colored shirts.Limitations:
The experiment should be conducted in a controlled environment to eliminate any external factors that could affect the results, such as wind or humidity.Sources of Errors:
Inaccuracy if the thermometer is not calibrated correctly or if it is not placed in the same position each time.The heat source may not be consistent, causing the temperature to fluctuate and affect the results.Precautions:
The experiment should be conducted in a safe environment, and the heat source should be handled carefully to prevent burns or accidents.The experiment should be conducted several times to ensure consistency and to reduce the impact of any errors or external factors.What is an experiment?An experiment is described as a procedure carried out to support or refute a hypothesis, or determine the efficacy or likelihood of something previously untried.
The hypothesis has it that the darker colored shirts (black, red, and orange) will absorb more heat from the environment and cause the boy to feel hotter than the lighter colored shirts (green and white).
Learn more about experiments at: https://brainly.com/question/17274244
#SPJ1
what is the defining characteristic of the trojan asteroids?
The defining characteristic of Trojan asteroids is their location in space. They are asteroids that share the orbit of a planet, leading or following the planet in its path around the sun. Specifically, Trojan asteroids are located in stable points known as Lagrange points, which are positions in space where the gravitational forces of two large objects, such as a planet and the sun, are balanced by the centripetal force of a smaller object.
Trojan asteroids are named after the mythical Trojan Horse from the Trojan War, because their discovery in the late 19th century was seen as a "hidden" population of asteroids that were difficult to detect due to their location in the same orbit as Jupiter. Today, Trojan asteroids have been found associated with several planets in the Solar System, including Mars, Neptune, and even Earth.
To know more about trojan asteroids refer here
https://brainly.com/question/16078620#
#SPJ11
Please help me like rn it’s an embergency
Answer:
first one
Explanation:
electromagnetism is the forces and fields associated with charge
I WILL MARK YOU THE BRAINLIEST NO LINKS AND IF YOU DONT UNDERSTAND THE QUESTION DONT ANSWER
Use the table. Is the metal you found gold? How do you know?
Answer:
Perform a simple test of the material in the pan to assess whether it is real gold. Raw gold appears brassy yellow and bright. If you think it is gold, place your hand between it and the sun to create shade over the gold. If it still appears bright in the pan, chances are that it is real gold.
Explanation:
A stellar black hole may form when a massive star dies. The mass of the star collapses down to a single point. Imagine an astronaut orbiting a black hole having five times the mass of the Sun. Assume the orbit is circular.
(a) Find the speed of the astronaut if his orbital radius is r = 1 AU.
(b) Find his speed if his orbital radius is r = 7.4 km.
(c) Compare your answers to the speed of light in a vacuum. What would the astronaut's orbital speed be if his orbital radius were smaller than 7.4 km?
(A) The speed of the astronaut if his orbital radius is r = 1 AU is approximately 29,790 m/s
(B) His speed is approximately 3,484,060 m/s
(a) The speed of the astronaut orbiting a black hole with five times the mass of the Sun at a distance of 1 astronomical unit (AU) can be calculated using the formula for orbital speed. The orbital speed of a satellite or object in circular orbit is given by the equation:
v = √(G * M / r)
where v is the orbital speed, G is the gravitational constant, M is the mass of the black hole, and r is the orbital radius.
Substituting the values:
M = 5 times the mass of the Sun = 5 * 1.989 x 10^30 kg
r = 1 AU = 1.496 x 10^11 m
G = 6.67430 x 10^-11 m^3 kg^-1 s^-2
v = √((6.67430 x 10^-11 * 5 * 1.989 x 10^30) / (1.496 x 10^11))
Calculating this expression gives a value of approximately 29,790 m/s.
(b) For an orbital radius of 7.4 km (7.4 x 10^3 m), we can use the same formula to calculate the orbital speed:
v = √((6.67430 x 10^-11 * 5 * 1.989 x 10^30) / (7.4 x 10^3))
This calculation yields a value of approximately 3,484,060 m/s.
(c) Comparing the speeds calculated in parts (a) and (b) to the speed of light in a vacuum (c), which is approximately 299,792,458 m/s, we find that both speeds are significantly smaller than the speed of light. This is expected, as objects with mass cannot reach or exceed the speed of light.
If the orbital radius were smaller than 7.4 km, the orbital speed of the astronaut would be higher, following the inverse relationship between orbital speed and orbital radius. As the radius decreases, the speed required to maintain a circular orbit increases to counterbalance the stronger gravitational force.
Learn more about black hole here:
https://brainly.com/question/32885855
#SPJ11
Anyone know the answer to number 4…..please help me ASAP!
Answer:
All planets have an elliptical orbit
all planets have roughly the same SHAPE of orbit
a child sleds down a steep, snow-covered hill with an acceleration of 2.82m/s squared. if her initial speed is 0.0 m/s and her final speed is 15.5 m/s, how long does it take her to travel from the top of the hill to the bottom?
A child sleds down a steep, snow-covered hill with an acceleration of 2.82m/s squared. if her initial speed is 0.0 m/s and her final speed is 15.5 m/s, It takes the child 5.50 seconds to travel from the top of the hill to the bottom.
We can use the following kinematic equation to solve this problem:
v^2 = u^2 + 2as
Where:
v is the final speed
u is the initial speed
a is the acceleration
s is the distance traveled
We are given u = 0.0 m/s, a = 2.82 m/s^2, and v = 15.5 m/s. We need to find s.
Rearranging the equation gives:
s = (v^2 - u^2) / (2a)
Substituting the values gives:
s = (15.5^2 - 0.0^2) / (2 x 2.82) = 74.47 m
Now, we can use another kinematic equation to find the time taken:
v = u + at
Where t is the time taken.
Substituting the values gives:
15.5 = 0.0 + 2.82t
Solving for t gives:
t = 15.5 / 2.82 = 5.50 seconds
For more such questions on acceleration, click on:
https://brainly.com/question/30595126
#SPJ11
Importance of Forest
Answer:
to help keep fresh air
Explanation:
(ii) Let R be a rotation and S be a reflection of the euclidean plane E. Give a precise deion of RS, relating it to the classification of isometries of E². Be careful of special cases.
RS is a composition of rotation and reflection in the Euclidean plane E². The precise description of RS depends on the specific properties of the rotation R and reflection S.
In general, if R and S have the same axis or line of symmetry, the composition RS results in a translation. If R and S have intersecting lines of symmetry, RS yields a glide reflection. If R and S have perpendicular lines of symmetry, RS produces a rotation.
It is important to consider special cases, such as parallel lines of symmetry, coinciding axes, or perpendicular lines of reflection, as they may lead to different outcomes. The classification of isometries in E² involves understanding how rotations and reflections combine to create different transformations in the plane.
Learn more about rotation and reflection visit:
https://brainly.com/question/1859113
#SPJ11
A curium-242 (Z= 96) can be produced by positive-ion bombardment when an alpha particle collides with which of the following nuclei? Note: A neutron is also a product of this bombardment, in addition to the curium-242.
A. Pu -239
B. U -239
C. Am-241
D. Cf-249
E. Pu-241
Answer:
A. Pu -239
Explanation:
An isotope is an element with the same atomic number but different mass number. most isotope are unstable, having short half life.
Curium-242 is an isotope produced when Plutonium 239 is bombarded by an alpha particle. This reaction between Plutonium 239 and alpha particle gives curium-242, neutron and a high amount of energy as the products.
Curium oxidizes easily, and it is a dangerous metal which can cause cancer initiation when absorbed by biological materials e.g bones or tissue.
The life cycle of stars may be boiled down into a tug of war, lasting billions of years, between two basic forces. In your own words, describe these forces, and identify which of the two eventually "wins" the battle.
Answer:
Stars are very massive stellar objects, which means that they have a very intense force of gravity. This is the first of the forces entering this "war".
In addition to that, due to the force of gravity that drives the star to contract, the process known as fusion occurs (the union of atoms of one element that results in another element, hydrogen fuses in stars to produce helium). The fusion created in the high temperatures of the center of the star generates an enormous amount of energy (which causes the stars to shine) and a force going outward of the star counteracting gravity, this is the second force in the "war" .
In a stable star these two forces (gravity going inward and the pressure created by the fusion going outward ) are in balance, preventing the star from exploding or collapsing. But eventually the star exhausts its "fuel" (hydrogen atoms) to produce fusion within it (although stars also fuse helium and other heavier elements, but once the hydrogen is finished the star is near its end), which decreases the force outward from the star, making the force that wins this battle to be the force of gravity.
When the force of gravity wins, the star collapses on itself and from here, depending on the star's mass, several things can happen, such as the star becoming a white dwarf, a supernova, even a black hole.
The life cycle of stars may be boiled down into a tug of war, lasting billions of years, between two basic forces -
Pressure due to fusion reactions pushes outwards.Gravity pulls inwards to keep the star in equilibrium.And gravity wins the battle in the end.Stars are very massive stellar objects and remain the longest in the stage when it is burning Hydrogen into Helium.
Stars have a very intense force of gravity that drives the star to contract, the process known as fusion occurs.Due to fusion, high temperatures of the center of the star create an enormous amount of energy and a force of pressure going outward of the star counteracting gravityGravity going inward and the pressure created by the fusion going outward is in balance, preventing the star from exploding or collapsing.Due to exhausting hydrogen atoms, fusion stops eventually and it decreases the force outward from the star, making the force that wins this battle to be the force of gravity.Thus,
The life cycle of stars may be boiled down into a tug of war, lasting billions of years, between two basic forces -
Pressure due to fusion reactions pushes outwards.Gravity pulls inwards to keep the star in equilibrium.And gravity wins the battle in the end.Learn more:
https://brainly.com/question/13172138
What is the charge on an object that experiences a force of 5 Newtons in an electric field of 50 Newtons per coulomb?
Answer:
Explanation:
F = qE
F is the force in Newtons
q is the test charge
E is the electrical field produced by the source charge
\(5=q(50)\\q=1*10^-^1Coulombs\)
The magnitude of charge on the object is of 0.1 C.
Given Data:
The magnitude of electric field is, E = 50 N/C.
The magnitude of Electric force is, F = 5 N.
The region where any particle feels the effect of electric force on itself, due to other charged entities, is known as Electric field. And the relation between the electric force and electric field is given as,
F = E × q
Here,
q is the magnitude of charge on the object.
Solving as,
q = F/E
q = 5 / 50
q = 0.1 C
Thus, we can conclude that the magnitude of charge on the object is of 0.1 C.
Learn more about the electric field here:
https://brainly.com/question/8971780
An air pistol fires a pellet forwards.
What is the motion of the air pistol?
A - The air pistol moves backwards with speed greater than the pellet.
B - The air pistol moves backwards with speed less than the pellet.
C - The air pistol moves forward with speed greater than the pellet.
D - The air pistol moves forward with speed less than the pellet.
The air pistol is moving backwards faster than the pellet. Subtract that stronger force's amplitude from the weaker department's magnitude to discover the centripetal acceleration.
What are a definition and an example of motion?Motion can be characterized as a shift in an object's location with regard to time. Motion can be heard in a variety of sounds, such a book falling off a table, water running from a faucet, rattling windows, etc. There is motion even in the air we breathe!
What generates motion?Motion is the result of forces You need to exert a push or a pull, which is by definition a force, in order to move something. The object will be static or continue going without accelerating in the absence of a force.
To know more about Motion visit:
https://brainly.com/question/22810476
#SPJ1
swinging a tennis racket against a ball is an example of a third class lever. please select the best answer from the choices provided.
a.true
b.false
The given statement "swinging a tennis racket against a ball is an example of a third-class lever" is TRUE.
A third-class lever is a class of lever where the input force is located between the fulcrum and the load. The fulcrum is the pivot point of the lever. The load is the weight or resistance that is being moved, lifted, or carried.The following are some examples of third-class levers: Sweeping with a broom. Tennis racket. Field hockey stick. Butter knife, etc. Thus, we can say that swinging a tennis racket against a ball is an example of a third-class lever.
To know more about tennis racket visit:
https://brainly.com/question/11490587
#SPJ11
When a rock is 3kg and is 30m above, what was the rock's gravitational potential energy when it is halfway between where you dropped it and the stream?
Answer:
882J
Explanation:
PE=m×g×h
=3kg×9.8m/s^2×30m
=882kgm^2/s^2
=882J
derive an expression from the energy stored E, in a stretched wire of original length L cross sectional area A, e, tension e,and young modulus Y of the material of the wire
The expression for the energy stored (E) in a stretched wire of original length (L), cross-sectional area (A), tension (T), and Young's modulus (Y) is given by E = Y * e * ln(L) * A
How to explain the expressionThe work done to stretch the wire can be calculated by integrating the force applied over the displacement. In this case, the force applied is the tension (T) in the wire, and the displacement is the change in length (ΔL) from the original length (L) to the stretched length (L + ΔL).
The tension in the wire is given by Hooke's law, which states that the tension is proportional to the extension of the wire:
T = Y * (ΔL / L)
where Y is the Young's modulus of the material of the wire.
Now, let's calculate the work done to stretch the wire:
dW = T * dL
Integrating this expression from L to L + ΔL:
W = ∫ T * dL = ∫ Y * (ΔL / L) * dL
W = Y * ΔL * ∫ (dL / L)
W = Y * ΔL * ln(L) + C
Here, C is the constant of integration. Since the energy stored in the wire is zero when it is unstretched (ΔL = 0), we can set C = 0.
Finally, the expression for the energy stored in the wire (E) is:
E = W = Y * ΔL * ln(L)
or, if we substitute the cross-sectional area (A) and strain (e) of the wire, where e = ΔL / L:
E = Y * e * ln(L) * A
Thus, the expression for the energy stored (E) in a stretched wire of original length (L), cross-sectional area (A), tension (T), and Young's modulus (Y) is given by:
E = Y * e * ln(L) * A
Learn more about energy on
https://brainly.com/question/13881533
#SPJ1
what are some examples of the second law of motion
what is true of crabb's view of the two books (god's word and god's works)?
Larry Crabb, a Christian author and counselor, has a view of the two books, God's Word and God's Works. He believes that both books are revelations of God and that they should be studied together in order to gain a fuller understanding of Him.
Crabb argues that God's Word is a revelation of God's character and nature. It tells us who He is and what He is like. God's Works, on the other hand, are a revelation of God's power and love. They show us what He can do and what He is willing to do for us.
Crabb believes that we should study both books in order to gain a balanced understanding of God. He says that "the Bible is not enough, but it is essential." We need to study God's Word in order to learn about His character and nature, but we also need to study God's Works in order to see His power and love in action.
Crabb's view of the two books is a helpful reminder that God is not just a distant being who is far removed from our lives. He is a personal God who is involved in our world and who loves us deeply. By studying both God's Word and God's Works, we can come to know Him better and grow in our relationship with Him.
Here are some of the benefits of studying God's Word and God's Works together:
It helps us to gain a fuller understanding of God.It helps us to grow in our relationship with God.It helps us to live according to God's will.It helps us to overcome temptation.It gives us hope and encouragement.It brings us peace and joy.To know more about the Larry Crabb refer here :
https://brainly.com/question/13799243#
#SPJ11
Construct a qualitative work-energy bar chart for a process that is consistent with the equation below. Then write in words with a sketch a process that is consistent with both the equation and the bar chart.
The qualitative work-energy bar chart can be constructed as follows:
Initial state:Kinetic energy: 1/2mv²
Gravitational potential energy: mgh
No frictional work
Intermediate state:
Kinetic energy: 1/2mv²
Gravitational potential energy: (mgh - 100m)
Frictional work: f
Final state:Kinetic energy: 1/2mv²
Gravitational potential energy: 0
Frictional work: (1/2mv² - mgh + 100m + f)
Process description:A person pushes a 120 kg crate along a flat surface at an initial velocity of 20 m/s for 100 m, which is at an angle of 53° to the horizontal. The crate experiences frictional force f during the journey. At the end of the 100 m, the crate is at the bottom of a 12.2 m high hill.
Sketch:[insert a sketch of a person pushing a crate along a flat surface with an angled direction and then the crate at the bottom of a hill with a height of 12.2 m]
To know more about Gravitational potential energy, visit:
https://brainly.com/question/19768887
#SPJ1
50 kg of water at 75o C is cooled to 25o C. How much heat was given off?
a
1.05 x 105 J
b
-1.05 x 107 J
c
1.67 x 105 J
d
-1.67 x 107 J
Answer:
b the answer is b
Explanation:
b is the awnser because it cools after the heat on the water witch lets the steam out
The heat energy given off from the system can be determined using calorimetric equation. The heat energy released when 50 Kg water cooled from 75 to 25 degree Celsius is - 1.05 × 10⁵ J.
What is calorimetry?Calorimetry is an analytical techniques used to determine the heat energy evolved or absorbed by a substance. The specific heat capacity of a substance is the amount of heat energy required to raise the temperature by one degree Celsius per one gram of it. The specific heat of water is 4.18 J/ g °C .
The calorimetric equation relating the heat energy q with the mass of m, specific heat capacity c and temperature difference ΔT is given by,
q = m c ΔT.
Given that mass of water here is 50 Kg or 50000 g. The temperature difference is 50°C. c for water is 4.18 J/ g °C. Thus, heat energy evolved by cooling is calculated as follows:
q = 50000 g × 4.18 J/ g °C × 50°C
= - 1.05 × 10⁵ J.
The negative sign indicate that heat is released by the system.
Therefore, the heat give off by the cooling of water is - 1.05 × 10⁵ J.
To find more on calorimetry, refer here:
https://brainly.com/question/11477213
#SPJ2
Two identical point charges are separated by 0.50 m. If the force between them is 8.0 N, what is the magnitude of each charge?
Answer:
The magnitude of each charge is 1.49*10⁻⁵ C.
Explanation:
The electromagnetic force is the interaction that occurs between bodies that have an electric charge.
Coulomb's law is used to calculate the electric force acting between two charges at rest.
This law says that the electrostatic force depends on the distance "r" between the electrons and the charge of both. That is, the magnitude of each of the electric forces with which two point charges interact at rest is directly proportional to the product of the magnitude of both charges and inversely proportional to the square of the distance that separates them. The force is of repulsion if the charges are of the same sign, and of attraction if they are of the opposite sign.
\(F=k*\frac{q1*q2}{r^{2} }\)
This law is represented as follows:
F = electric force of attraction or repulsion in Newtons (N). k = is the Coulomb constant or electrical constant of proportionality, whose value is: 9*10⁹ \(\frac{N*m^{2} }{C^{2} }\) q = value of electric charges measured in Coulomb (C). r = distance that separates the charges and that is measured in meters (m).In this case:
F= 8 Nq1=q2= q= ?r= 0.50 mReplacing:
\(8 N=9*10^{9} \frac{N*m^{2} }{C^{2} }*\frac{q*q}{(0.50m)^{2} }\)
Solving:
\(8 N=9*10^{9} \frac{N*m^{2} }{C^{2} }*\frac{q^{2} }{0.25m^{2} }\)
\(8 N=3.6*10^{10} \frac{N }{C^{2} }*q^{2}\)
\(\frac{8 N}{3.6*10^{10} \frac{N }{C^{2} }} =q^{2}\)
\(\sqrt{\frac{8 N}{3.6*10^{10} \frac{N }{C^{2} }}} =q\)
1.49*10⁻⁵ C=q
The magnitude of each charge is 1.49*10⁻⁵ C.
Drag each circle to the correct location on the image. Each circle can be used more than once, but not all circles will be used.
Geologists have observed that a portion of Africa is breaking away from the main continent. This is happening because the African Plate is in the process of splitting up into two parts. Scientists have named the two new tectonic plates the Nubian Plate and Somalian Plate. Both of these plates are not only moving away from each other but also away from the Arabian Plate.
Based on this information, determine the type of boundaries these two new plates would share with each other and the Arabian Plate.
Based on the given information, the type of boundaries these two new plates would share with each other and the Arabian Plate are divergent boundaries.
Who are geologists?A geologist is a scientist who studies the solid, liquid, and gaseous matter that constitutes Earth and other planets.
Geologists have observed that a portion of Africa is breaking away from the main continent. This is happening because the African Plate is in the process of splitting up into two parts. Scientists have named the two new tectonic plates the Nubian Plate and Somalian Plate. Both of these plates are not only moving away from each other but also away from the Arabian Plate.
There are 3 types of boundaries.
At convergent boundaries, the two tectonic plates comes closer to each other.
At divergent boundaries, the plates move away from each other.
At transform boundaries, the plates are moving parallel to their boundary.
Based on this, all boundaries will be divergent boundaries.
Learn more about geologist.
https://brainly.com/question/13428729
#SPJ1
1. Ethan is dragging a bag of grass from the garage to the street on the evening before garbage pick-up day. The diagram at the right is a free-body diagram. It uses arrows to represent the forces acting upon the bag. Each force is labeled according to type. The magnitude of the force is represented by the size of the arrow. Use the free body diagram to determine the net force acting upon the bag. The values of the individual forces are:
Fgrav = Fnorm = 60.5 N
Fapp = 40.2 N
Ffrict = 5.7 N.
From the calculations and the free body diagram, the net force that acts on the body is 34.5 N
What is the net force?The net force refers to the force that is acting on a body. Let us note that the gravitational force and the normal force cancel out each other. Thus the two force that act on the body are the applied force and the frictional force.
Thus;
The net force that acts on the body is;
40.2 N - 5.7 N = 34.5 N
Learn more about net force:https://brainly.com/question/18031889
#SPJ1
Consider a circular cylinder in a hypersonic flow, whit its axis perpendicular to the flow. Let φ be the angle measured between radii drawn to the leading edge (the stangnation point) and to any arbitrary point on the cylinder. The pressure coefficient distribution along the cylindrical surface is given by Cp=2cos^2 φ for 0 ≤ φ ≤ pi/2 and 0 ≤ φ ≤ 2pi and Cp= 0 for pi/2 ≤ φ ≤ 3pi/2. Calculate the drag coefficient for the cylinder, based on projected frontal area of the cylinder.
To calculate the drag coefficient for the cylinder, we first need to determine the drag force acting on the cylinder. The drag force can be expressed the drag coefficient for the cylinder, based on projected frontal area, is 8/3π.
A cylinder is a three-dimensional geometric shape that consists of a circular base and a curved lateral surface that connects the base to another circular top. The shape of the cylinder is characterized by its height (h) and its radius (r), which is the distance from the center of the circular base to any point on the base.Cylinders can be found in various applications, such as pipes, hydraulic systems, engines, and other mechanical systems. The properties of a cylinder, such as its volume, surface area, and moment of inertia, can be calculated using mathematical formulas that depend on its dimensions.Cylinders are also important in fluid dynamics, where they can be used to study the behavior of fluids around solid objects. In this context, the drag coefficient and lift coefficient of a cylinder can be used to predict the aerodynamic forces acting on the cylinder when it is placed in a fluid flow.
To know more about forces visit :
https://brainly.com/question/13191643
#SPJ11
Calculate the energy transfered when 3 of copper is heated from 20°C to 220°C
Answer:
Q = 231.6 J
Explanation:
Given that,
Mass, m = 3 g
The temperature rises from 20°C to 220°C.
We know that, the specific heat of copper is, c = 0.386 J/g K
We know that the energy transferred in heating of copper is given by :
\(Q=mc\Delta T\\\\Q=3\times 0.386\times (220-20)\\\\Q=231.6\ J\)
So, the required energy is equal to 231.6 J.