In a football game, one team kicks off to the other. At the moment the receiver catches the ball, he is 40 meters from the nearest tackler. The receiver runs left to right at a speed of 10 meters per second (10 m/s). The tackler runs right to left at a speed of 6 meters per second.
How long does it take before they collide? ___________
How far does the receiver go? _____________________
Answers
Take left to be the negative direction, and right to be positive.
The receiver's position at time t, taking his starting position to be the origin, is
(10 m/s) t
while the tackler's position is
40 m + (-6 m/s) t
The two collide when their positions are equal:
(10 m/s) t = 40 m - (6 m/s) t
(16 m/s) t = 40 m
t = (40 m) / (16 m/s)
t = 2.5 s
In this time, the receiver covers a distance of
(10 m/s) (2.5 s) = 25 m
Related Questions
According to the __________perspective, people who suffer from PTSD are classically conditioned.
Answers
According to the pavlovian perspective, people who suffer from PTSD are classically conditioned.
What is PSTD?
This is referred to as post traumatic stress disorder which is a mental disorder from a terrifying incident.
The pavlovian perspective however view this disorder as being a type of classical conditioned one.
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What does the potential energy diagram of a chemical reaction tell you?
O A. Whether atoms are being created or destroyed
O B. Whether the reaction is endothermic or exothermic
C. Whether there are more reactants or products
D. Whether the law of conservation of matter is being obeyed
Answers
Answer:
B
Explanation:
I'm learning about this now actually and it can be a little confusing but it would be endothermic or exothermic. if endothermic the products have less energy than the reactants and if exothermic products have more energy than reactants
SPH4U Physics 12 Communication 3. (4 marks)Two identical balls, A and B, are released from rest on inclines that have the same vertical drop and the same horizontal distance from one end to the other. The inclines differ in detail as illustrated in Figure 3. (Note that very little energy is lost due to rolling friction.) A А (a) Which ball arrives at the end first? Explain your answer. B OD Figure 3 (b) Racing cyclists apply this principle on inclined oval tracks. Explain how.
Answers
Acceleration of an object down a slope increases as the angle of the slope is increased
(a) The ball that arrives at the end first is ball A
(b) Racing cyclist select areas having a steeper slope on a hill that gives them a velocity boost
Reason:
A drawing to clarify the explanation and to represent the possible drawing of figure 3 in the question is attached
The acceleration of the balls on the inclined plane is given by the following formula;
Force, F = m·g·sin(θ)
Therefore, the acceleration, a, of ball A and ball B at the part having the same slope are equal
The acceleration of ball A at the part of its track that is almost vertical is approximately, g, (acceleration due to gravity). The velocity at the end of the drop is u' = v + g·Δt, therefore;
The velocity of ball A at the recessed sections given by v' = u' + a·t are higher than the velocities of ball B, which is vAt the higher velocity of ball A, the time it takes ball A to arrive at the end is much lesser, and therefore, ball A arrives at the end first.(b) The principle is applied by racing cyclist by selecting a steeper path that gives them a velocity boost much larger than what is being normally applied, by the force applied by pedaling
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An object is thrown vertically and has an upward velocity of 18 m/s when it reaches one fourth of its maximum height above its launch point. What is the initial (launch) speed of the object
Answers
Answer:
v = 25.45 m/s
Explanation:
In order to calculate the initial speed of the object, you take into account the formula for the maximum height reaches by the object. Such a formula is given by:
\(h_{max}=\frac{v_o^2}{g}\) (1)
vo: initial speed of the object = 18 m/s
g: gravitational acceleration = 9.8 m/s²
Furthermore you use the following formula for the final speed of the object:
\(v^2=v_o^2-2gh\) (2)
h: height
You know that the speed of the object is 18m/s when it reaches one fourth of the maximum height. You use this information, and you replace the equation (1) in to the equation (2), as follow:
\(v^2=v_o^2-2g(\frac{h_{max}}{4})=v_o^2-\frac{1}{2}g(\frac{v_o^2}{g})\\\\v^2=v_o^2-\frac{1}{2}v_o^2=\frac{1}{2}v_o^2\)
Then, you solve the previous result for vo:
\(v_o=\sqrt{2}v=\sqrt{2}(18m/s)=25.45\frac{m}{s}\)
The initial speed of the object was 25.45 m/s
Which example is correctly matched with its type of friction?
A. Pushing a car that isn't moving is an example of slkiding friction.
B. A plane flying through the air is an example of static friction.
OC.
A skateboard wheels on cement is an example of rolling friction.
OD.
A sled sliding down a grassy hill is an example of fluid friction.
Answers
Answer:
A. pushing a car that isn't moving
A researcher investigated whether job applicants with popular (i.e. common) names are viewed more favorably than equally qualified applicants with less popular (i.e. uncommon) names. Participants in one group read resumes of job applicants with popular (i.e. common) names, while participants in the other group read the same resumes of the same job applicants but with unpopular (i.e. uncommon) names. The results showed that the differences in the evaluations of the applicants by the two groups were not significant at the .001 level
Answers
The researcher did not find strong evidence to support the idea that job applicants with popular names are viewed more favorably than equally qualified applicants with less popular names.
What factors plan an important role in the hiring process for a job?It sounds like the researcher conducted an experiment to investigate whether job applicants with popular names are viewed more favorably than equally qualified applicants with less popular names.
Based on the information provided, the researcher found that the differences in the evaluations of the applicants by the two groups were not significant at the .001 level.
The factors that play an important role in the hiring process for a job:
(1) Qualifications and experience: Employers typically look for candidates who possess the necessary qualifications and experience for the job. This includes education, training, certifications, and work experience.
(2) Skills and abilities: Employers also consider a candidate's skills and abilities related to the job. These may include technical, interpersonal, communication, and problem-solving skills.
(3) Personal characteristics: Personal characteristics, such as motivation, work ethic, and adaptability, can also play a role in the hiring process. Employers may look for candidates who demonstrate a positive attitude, a willingness to learn, and the ability to work well with others.
(4) Fit with company culture: Companies may also consider whether a candidate fits with their company culture, values, and mission. This can include factors such as teamwork, creativity, and innovation.
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Use the simulation to determine the relationship between the distance from the magnet and the strength of the magnetic field at that point. Use a ruler to measure distance on the screen. Use a power fit to determine the B vs. r relationship for each location. To simplify your data collection, chose a data-collection axis where either Bx or By = 0. Measure the distance from the nearest edge of the magnet. You will need to obtain a ruler for collecting data.
Answers
Explanation:
give me more detail and i well help you out
QUESTIONS
An ant walks eastward for 11.1 cm, then northward for 4,4 cm and finally westward for 11.1 cm. What is the magnitude of the displacement in cm Do
not include the units in your answer.
Answers
Answer:
4.4.
Explanation:
Hello,
In this considering the attached picture, we can see that the eastward movement is represented from O to A, the northward displacement from A to B and the westward displacement from B to C, which means that the resulting displacement is marked from O to C which includes the northwards movement since eastward and westward movement are the same.
In such a way, the magnitude of the displacement is simply 4.4 cm as no other dimension is taken into account due to the return to the same initial's x-axis position.
Regards-
Complete the passage to describe the relationship between kinetic energy, internal energy, thermal energy, and
temperature.
As the average kinetic energy of a substance increases, the internal energy vand so its thermal energy
As the thermal energy of a substance increases, the temperature
Answers
Answer:
Increases
Increases
Increases
Explanation:
I don't know if you answered your own question but I'll just answer this for others confused ahh
As the average kinetic energy of a substance increases, its thermal energy increases which increases the temperature, and as the temperature increases, the internal energy of the substance increases.
The thermal energy, internal energy and kinetic energy of a gas are interrelated.
The average kinetic energy of a gas is its internal energy presented by the equation E = \(\frac{3}{2}k_{b}T\), here \(k_{b}\) is Boltzmann's constant and T is the temperature of the gas.We can see that the average kinetic energy of the internal energy is directly proportional to temperature.So if the thermal energy of the gas is increased, it raises the temperature of the gas, which will increase the vibrations of the molecules of the gas and the velocity of the molecules.The increase in the vibration of the molecules and their velocities results in increase in average kinetic energy and internal energy of the gas.Learn more about internal energy:
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An airplane whose airspeed is 190 km/h heads due north. If there is a wind blowing at 86 km/h from west to east, how many degrees east of north does the airplane travel relative to the ground?
a. 66°
b. 63°
c. 27°
d. 24°
please help me
Answers
With the knowledge of bearing, the airplane will be 24 degrees east of north relative to the ground. The correct answer is option d
What is Relative Motion ?Relative motion can be defined as a change of position of an object with a point or frame of reference which we may assumed to be at rest.
Given that an airplane whose airspeed is 190 km/h heads due north. If there is a wind blowing at 86 km/h from west to east, the magnitude of degrees Ф east of north in which the airplane will travel relative to the ground can be known by using a trigonometry ratio.
The Y component is 190 km/h heads due north.
The X component is 86 km/h from west to east.
TanФ = Y/X
Ф = \(Tan^{-1} (\frac{Y}{X})\)
Ф = \(Tan^{-1} (\frac{190}{86})\)
Ф = \(Tan^{-1} (2.209)\)
Ф = 65.65°
The degrees east of north = 90 - 65.65
The degree east of north = 24.4°
Therefore, the magnitude of degrees east of north in which the airplane will travel relative to the ground is 24° approximately.
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What force acts on a projectile in the horizontal direction?
Answers
The force that acts on a projectile in the horizontal direction is Gravitational force.
A projectile is an object upon which the only force is gravity. Gravity acts to influence the vertical motion of the projectile, thus causing a vertical acceleration. The horizontal motion of the projectile is the result of the tendency of any object in motion to remain in motion at constant velocity.
Due to the absence of horizontal forces, a projectile remains in motion with a constant horizontal velocity. Horizontal forces are not required to keep a projectile moving horizontally. Hence, The only force acting upon a projectile is gravity.
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Two blocks, 1 and 2, are connected by a massless string that passes over a massless pulley. 1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. 2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105
. The figure illustrates the configuration.
A system of two blocks connected by a rope passing over a pulley. The system sits atop a scalene triangle whose long edge forms the base. The pulley is attached to the apex of the triangle. Box M subscript 1 rests on the triangle edge to the left of the pulley, which makes an angle of theta subscript 1 with the base of the triangle. The coefficient of friction between box M sub 1 and the surface is mu subscript 1. Box M subscript 2 rests on the triangle edge to the right of the pulley, which makes an angle of theta subscript 2 with the base of the triangle. The coefficient of friction between box M sub 2 and the surface is mu subscript 2.
Answers
The force acting on the system of two blocks connected by a rope passing over a pulley is -13.26 N.
The system of two blocks connected by a rope passing over a pulley are M1 and M2, where M1 rests on the triangle edge to the left of the pulley, which makes an angle of theta subscript 1 with the base of the triangle. The coefficient of friction between box M1 and the surface is mu subscript 1. M2 rests on the triangle edge to the right of the pulley, which makes an angle of theta subscript 2 with the base of the triangle.
The coefficient of friction between box M2 and the surface is mu subscript 2. The system sits atop a scalene triangle whose long edge forms the base. The pulley is attached to the apex of the triangle.M1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. M2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105.The free-body diagram of M1 shows that the weight of M1 acts straight downwards (vertically) and the normal force acts perpendicular to the slope.
The force of friction opposes the motion and acts opposite to the direction of motion.M1 = 2.25 kgTheta subscript 1 = 42.5 degreesMu subscript 1 = 0.205g = 9.81 m/s²In the free-body diagram of M2, the normal force acts perpendicular to the incline of the slope, the weight of the object acts vertically downwards and parallel to the incline, and the force of friction opposes the motion and acts opposite to the direction of motion.M2 = 5.55 kgTheta subscript 2 = 33.5 degreesMu subscript 2 = 0.105g = 9.81 m/s²The tension in the string is the same throughout the rope. Since the masses are being pulled by the same rope, the acceleration of the objects is the same as the acceleration of the rope.
The tension in the string is directly proportional to the acceleration of the objects and the rope.A system of two blocks connected by a rope passing over a pulley has a total mass of M. The acceleration of the system is given by the formula below:a = [(m1-m2)gsin(θ1) - μ1(m1+m2)gcos(θ1)] / (m1 + m2)Where, μ1 = 0.205 is the coefficient of friction of block M1θ1 = 42.5 degrees is the angle of the incline of block M1M1 = 2.25 kg is the mass of block M1M2 = 5.55 kg is the mass of block M2g = 9.81 m/s² is the acceleration due to gravitysinθ1 = sin 42.5 = 0.67cosθ1 = cos 42.5 = 0.75The acceleration of the system is:a = [(2.25-5.55)(9.81)(0.67) - (0.205)(2.25+5.55)(9.81)(0.75)] / (2.25 + 5.55)a = -1.7 m/s² (the negative sign indicates that the system is accelerating in the opposite direction).
The force acting on the system is given by:F = MaWhere M is the total mass of the system and a is the acceleration of the system. The total mass of the system is:M = m1 + m2M = 2.25 + 5.55M = 7.8 kgThe force acting on the system is:F = 7.8(-1.7)F = -13.26 N (the negative sign indicates that the force is acting in the opposite direction).
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1. Alexandra and Rachel are on a train that sounds a whistle at a constant frequency as
it leaves the train station. Compared to the sound emitted by the whistle, the sound that
the passengers standing on the platform hear has a frequency that is
a. lower, because the sound-wave fronts reach the platform at a frequency
lower than the frequency at which they are produced
b. lower, because the sound waves travel more slowly in the still air above the
platform than in the rushing air near the train
c. higher, because the sound-wave fronts reach the platform at a frequency
higher than the frequency at which they are produced
d. higher, because the sound waves travel faster in the still air above the
platform than in the rushing air near the train
Answers
Answer: the answer would be C trust me i took the test if its not that its b
hope that helps
Explanation: i took the test
answer:
a) lower because the sound-wave fronts reach the platform at a frequency lower than the frequency at which they are produced
explanation :3
If the train is leaving the train station, then the people who are standing on the platform would hear a sound with a lower frequency since the train is moving further away. ^^
A truck traveling at 100 km/hr strikes an unfortunate bug and splatters it. The acceleration resulting from the impact is:_______
a. Greater for the truck
b. Greater for the bug
b. The same for both the bug and the truck
d. Impossible to determine
Answers
Answer:
b. Greater for the bugExplanation:
The conservation of linear momentum states that the momentum before impact equals the momentum after impact
Also, when two objects collide, the change of momentum of particles m1 and m2 are equal in magnitude and opposite in sign and the total momentum change equals zero. Hence during a collision, Each object experiences the same force for the same amount of time, leading to the same impulse, and subsequently the same momentum change. in general, it is only the acceleration and the velocity components that differ for the two objects during the interaction.
Consequently, The object with the least mass always receives the greatest velocity change and acceleration.
What is the moment of inertia of a 4.2-kg uniform cylindrical grinding wheel of radius 32 cm?
Answers
The moment of inertia of the uniform cylindrical grinding wheel is 2,150 kgm².
What is the moment of inertia?
This refers to the angular mass or rotational inertia can be defined with respect to the rotation axis, as a property that shows the amount of torque needed for a desired angular acceleration or a property of a body due to which it resists angular acceleration. The unit is kgm².
From the question:
Mass,M =4.2kg
Radius, R=32Cm
The formula for calculating the moment of inertia for uniform cylindrical grinding wheel:
moment of inertia, I =1/2MR²
I =\(\frac{1}{2}\) * 4.2 * 32²
=2,150.4 kgm²
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Trawler A is 40km west of Another Trawler B. Trawler A sets off at 20km On a Force of 60°. If Trawler B Can travel at 25km. What course should Trawler B Pass to Intercept Trawler A.
Answers
Answer:
Trawler B should set off on a course of 120°.
Trawler A is traveling at 20km/h on a bearing of 60°. This means that Trawler A is traveling north-east. Trawler B is traveling at 25km/h. In order to intercept Trawler A, Trawler B must travel on a bearing of 120°. This means that Trawler B must travel south-east.
The two trawlers will eventually meet at a point that is 40km east of Trawler A's starting position and 20km north of Trawler B's starting position.
A series circuit has a 12-volt power source and two resistors of 1 ohm and 2 ohms respectively. How many amps will flow when
the circuit is closed?
Answers
Answer:
ayoooooooo
Explanation:
A tuning fork with a frequency of 440 Hz produces waves with a wavelength of 0.78 m at 20° C. What will be its wavelength at 13° C?1) 0.77 m2) 1.29 m3) 0.66 m4) 2.06 m
Answers
Given data:
* The frequency of the tuning fork is,
\(f=440\text{ Hz}\)* The wavelength of the fork at 20 degree is,
\(\lambda=0.78\text{ m}\)Solution:
The velocity of the tuning fork wave at 20 degree is,
\(\begin{gathered} v_{\circ}=\lambda f \\ v_{\circ}=0.78\times440 \\ v_{\circ}=343.2\text{ m/s} \end{gathered}\)The velocity of the tuning fork wave at 13 degree is,
\(v=v_{\circ}\sqrt[]{\frac{T}{T_{\circ}}}\)where,
\(\begin{gathered} T=13^{\circ}C \\ T=286.15\text{ K} \end{gathered}\)and,
\(\begin{gathered} T_{\circ}=20^{\circ}C \\ T_{\circ}=293.15\text{ K} \end{gathered}\)Thus, the velocity of the sound wave at 13 degree Celsius is,
\(\begin{gathered} v=343.2\times\sqrt[]{\frac{286.15}{293.15}} \\ v=339.08\text{ m/s} \end{gathered}\)The wavelength of tthe sound wave at 13 degree celsius is,
\(\lambda^{\prime}=\frac{v}{f}\)Substituting the known values,
\(\begin{gathered} \lambda^{\prime}=\frac{339.08}{440} \\ \lambda^{\prime}=0.77\text{ m} \end{gathered}\)Thus, the wavelength of the sound wave at 13 degree celsius is 0.77 m.
Hence, option 1 is the correct answer.
Holding your hand at arm's length, you can readily block sunlight from reaching your eyes. Why can you not block sound from reaching your ears this way?
Answers
The diffraction of visible light around an obstruction the size of your hand is completely inconsequential since the wavelength of visible light is incredibly small in compared to the proportions of your hand.
What is the SI unit and wavelength?Wavelength is the distance represented by the length of one cycle of a wave. The wavelength symbol is, and the SI unit for wavelength is the metre (m).
What does a wavelength look like?Here are a few examples of wavelengths: The Yellow Light illustration is suitable. All visible light has a wavelength that ranges from 400 to 700 nanometers (nm). The wavelength of yellow light is around 570.nanometers. (nm) Wavelength (nm) (nm).
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the length of the glass at 25°C is 500cm after gaining some heat the final length of the glass becomes 500.9cm determine the temperature of the glass
Answers
Smile all day
The final temperature of the glass is 25.005⁰C
Linear expansivity is defined as the change in length of an object per unit length per degree rise in temperature. Mathematically:
\(\alpha=\frac{\triangle L}{L\triangle \theta} \\\alpha = \frac{L_2-L_1}{L_1)(\theta_f-\theta_i)}\)
where:
L2 is the final length = 500.9cm
L1 is the original length = 500cm
θf is the final temperature
θi is the initial temperature of the glass = 25°C
Linear expansivity of glass = 9 × 10⁻⁶
Substitute the given values into the formula as shown:
\(9 \times 10^{-6}=\frac{500.9-500}{500(\theta_f-25)} \\9 \times 10^{-6}=\frac{0.9}{500(\theta_f-25)} \\0.0045=\frac{0.9}{\theta_f-25}\\\frac{0.0045}{0.9}=\theta_f-25\\ 0.005=\theta - 25\\\theta = 25 + 0.005\\\theta = 25.005^0C\)
Hence the final temperature of the glass is 25.005⁰C
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In what sport is reaction time LEAST likely to make an impact on an athlete’s performance?
A.) Karate
B.) Baseball
C.) Tennis
D.) Golf
Answers
Answer:
Explanation:
b
All the other sports require fast reaction times golf doesn’t since all you need to do is swing and hit the ball
Good luck hope this helps
:))
Before a collision, a 200-kg Honda is driving 30 m/s towards a
600-kg Toyota that is not moving. After the crash, the two cars
are stuck together. What is their velocity?
m/s
Answers
As a result, the combined Honda-Toyota system's post-collision speed is 7.5 m/s.
How can you calculate the entire momentum prior to a collision?The system's center of mass was v/2 before to the collision since one automobile had a velocity of v and the other zero. The total momentum is equal to the entire mass times the velocity of the center of mass, or (2m)(v/2) = mv before and after.
Initial momentum of Honda = m1 * v1
= 200 kg * 30 m/s
= 6000 kg·m/s
Final momentum of combined system = (m1 + m2) * v_final
Setting the two momenta equal to each other, we get:
6000 kg·m/s = 800 kg * v_final
Solving for v_final, we get:
v_final = 6000 kg·m/s / 800 kg
= 7.5 m/s
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The greater the distance between two objects in space, the _______ their gravitational
Answers
Answer is Weaker. If it is talking about the objects' gravitational forces.
What gift is given from one generation to the next
Answers
Answer:
awareness and honesty toward others
HELPPP WILL MARK BRAINLIST What type of image is formed by a lens if m= 2.7?
A. The image is smaller than the object and is virtual.
B. The image is smaller than the object and is real.
C. The image is larger than the object and is real.
D. The image is larger than the object and is virtual.
Answers
Answer:
I GOTCHU FAM
The image is larger than the object and is virtual.
Explanation:
JUST DID DA QUIZ BOI
Magnification is the measure of the nature of images and their size. The image formed by a lens if the magnification is 2.7 is larger and virtual.
What is magnification?Magnification is the ratio of image height to object height. The positive magnification means the image is virtual, formed by the convex mirror and vice-versa.
Thus, the image formed by a lens if the m = 2.7 is larger than the object and virtual. The correct option is D.
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A marine weather station reports waves along the shore that are 2 meters high, 8 meters long, and reach the station 8 seconds apart. Determine the speed of these waves.
Answers
One full weather station reports wave passing a spot every second is equivalent to a frequency of 1 Hz. The frequency is 48=12=0.5 Hz if 4 waves pass a spot in 8 seconds.
What is the frequency of a 30-second ocean wave that hits the shore?The number of cycles that make up a time unit is the frequency. The frequency of a wave with a 30-second period is therefore 1 30 = 0.033 cycles per second, or 0.033 Hertz (Hz).
Which of the following statements most accurately sums up how a wave crosses a border and enters a new medium?A wave's speed and wavelength vary as it crosses a border and enters a new medium, but its frequency doesn't.
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A rigid, 26-L steam cooker is arranged with a pressure relief valve set to release vapor and maintain the pressure once the pressure inside the cooker reaches 150 kPa. Initially, this cooker is filled with water at 175 kPa with a quality of 10 percent. determine the exergy.
Answers
The minimum entropy change of the heat-supplying source is -0.87 kJ/K.
Initial entropy of the systemIn this case, given the initial conditions, we first use the 10-% quality to compute the initial entropy.
at initial pressure of 175 kPaS₁ = 1.485 + (0.1)(5.6865) = 2.0537 kJ/kg K
Final entropyThe entropy at the final state given the new 40-% quality:
pressure inside the cooker = 150 kPa
S₂ = 1.4337 + (0.4)(5.7894) = 3.7495 kJ/kg K
Mass of the steam at specific volumem₁ = 0.026/(0.001057 + 0.1 x 1.002643) = 0.257 kg
m₂ = 0.026/(0.001053 + 0.4 x 1.158347) = 0.056 kg
minimum entropy change of the heat-supplying sourceΔS + S₁ - S₂ + S₂m₂ - S₁m₁ - sfg(m₂ - m₁) > 0
ΔS + 2.0537 - 3.7495 + (3.7495 x 0.056) - (2.0537 x 0.257) - 5.6865( 0.056 - 0.257) > 0
ΔS > -0.87 kJ/K
Thus, the minimum entropy change of the heat-supplying source is -0.87 kJ/K.
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The complete question is below:
A rigid, 26-L steam cooker is arranged with a pressure relief valve set to release vapor and maintain the pressure once the pressure inside the cooker reaches 150 kPa. Initially, this cooker is filled with water at 175 kPa with a quality of 10 percent. determine the exergy.
Heat is now added until the quality inside the cooker is 40 percent. The water is stirred at the same time that it is being heated. Determine the minimum entropy change of the heat-supplying source if 100 kJ of work is done on the water as it is being heated. Use steam tables
What are the different ways the body senses its surroundings?
Answers
Answer: Smell, touch, feel, look.
Explanation:
While Kepler supported the Copernican model of the universe Kepler concluded the following
A the circular orbits of the copernican model weren’t correct paths of planets were elliptical
B all other bodies in the universe move around the earth in circular paths
C all other bodies in the universe move around the moon in triangular paths
D the circular orbits of the Copernican model weren’t correct paths of planets were rectangular
Answers
Answer:
Explanation: because Keller concluded that the circular obits of the Copernican model weren't correct paths of planets were elleptical
D Learning Task 1: In your notebook, define the following terms in your own words. fitness 8. coordination 2. health related fitness 9. agility 3. skill related fitness 10. speed 4. body composition Il port 5. cardiovascular endurance 12 balance 6. muscular strength 13 reaction time 7. Nexibility
Bibigyan ko ng verified answer
Answers
The wellbeing of a human body encompasses the fitness of the body:
Physically,Mentally, and Health-wiseWe take good care of the body to maintain proper health conditions and be free from disease, by doing so, we perform some fitness exercises and some of the following terms are defined below.
Fitness can be defined as a measure of the body's capacity to perform daily tasks successfully and efficiently.Coordination is the act of organizing or making diverse people work together, to achieve a particular objective in an organization.Health-related fitness refers to fitness exercises performed to maintain a perfect health condition and status quo of the body.Agility is described as the ability to change directions rapidly and easily at high speeds.
Skill-related fitness refers to a fitness exercise that helps to resharpen your posture and offer a professional outlook in your day-to-day roles.
Speed is defined as the change of an object's distance in relation to time.
Body composition is defined as the proportion of the fat-free mass of the body depending on several factors such as age, gender, physical activities, etc.
Cardiovascular endurance is the capacity of the heart, lungs, and blood to provide appropriate amounts of oxygen to the cells in order to fulfill the demands of continuous physical activity exertion.
Balance is the ability of the body to maintain an appropriate position in space.
Muscular strength is the maximum amount of force the muscle can produce in just a single muscular contraction.
Reaction time is the amount of time it takes a body to respond to stimuli.Nexibility is a physical process where objects have the tendency of being knitted together.
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