In a Heating and Cooling Curve, what is occurring during the flat portions of the curve when the temperature is constant, and what is the energy being used to do?a) there is no energy being addedb) it is speeding up the particlesit is changing the phasec) it is increasing the kenetic energyd) it is decreasing the kinetic energy

Explanation:

Distance = speed × time

d = (27 m/s) (2.0 s)

d = 54 m

Time taken by the car to reach the water below the cliff, time of flight is 3.03 s.

Projectile is an object thrown into the space and which is moving under  the effect of gravity alone near the surface of earth.

Here,

The car is driven over the edge and so it is having a projectile motion from the top of the cliff to the water. The time taken by the car to reach and hit the sea in the projectile motion is called time of flight. When the car just leaves the edge of the cliff, it tends to rest. So the initial velocity is 0.

The height of the cliff, s = 45 m

Using the equation of motion,

s = ut +1/2 at²

45 = 0 + 1/2 x 9.8 x t²

t² = (2x 45)/9.8 = 9.183

Therefore, time of flight,

t = 3.03 s

Hence,

Time taken by the car to reach the water below the cliff, time of flight is 3.03 s.

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When a car is traveling north, its acceleration vector can point south when it is slowing down.

A vector quantity has both magnitude and direction. The direction of a vector is always shown by the direction to which the arrow points.

If the car is travelling north, the direction of the acceleration vector will continue to point northwards.

However, when the car slows down, the direction of the accelerating vector will now point southwards.

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Answer:

a four-sided plane rectilinear figure with opposite sides parallel.

Answer:

A medium vibrates at right angles to the direction of travel (D transverse) such as an electrical wave in space

A medium vibrates parallel to the direction for a longitudinal wave such as a sound wave in air

Answer: B

Explanation: I think its B or A but mostly B

Answer:

The enthalpy of a reaction does not depend on the reactant path taken

Explanation:

i just took the test on a pex :)

The minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.

To maintain equilibrium, the torques acting on the meter stick must balance each other. The torque is given by the formula:

τ = r * F * sin(θ)

where τ is the torque, r is the distance from the pivot point to the point where the force is applied, F is the force applied, and θ is the angle between the force vector and the lever arm.

In this case, the meter stick is in equilibrium when the torques on both sides of the pivot point cancel each other out. The torque due to the weight of the meter stick itself is acting at the center of mass of the meter stick, which is at the 50.0 cm mark.

Let's denote the mass to be placed on the 0.00 cm mark as M. The torque due to the weight of M can be calculated as:

τ_M = r_M * F_M * sin(θ)

where r_M is the distance from the pivot point to the 0.00 cm mark (which is 30.0 cm), F_M is the weight of M, and θ is the angle between the weight vector and the lever arm.

Since the system is in equilibrium, the torques on both sides of the pivot point must be equal:

τ_M = τ_stick

r_M * F_M * sin(θ) = r_stick * F_stick * sin(θ)

Substituting the given values:

30.0 cm * F_M = 20.0 cm * (0.0400 kg * 9.8 m/s^2)

Solving for F_M:

F_M = (20.0 cm / 30.0 cm) * (0.0400 kg * 9.8 m/s^2)

F_M = 0.0264 kg * 9.8 m/s^2

F_M = 0.25872 N

Finally, we can convert the force into mass using the formula:

F = m * g

0.25872 N = M * 9.8 m/s^2

M = 0.0264 kg

Therefore, the minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.

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The mistake that Farah made in this experiment is that she hung up the pieces of cotton before putting the fan on, also the water evaporating can take longer or shorter even if they are all the same.

The consequences of errors or mistakes in the experiments may be determined by the fact that errors are differences between observed values and what is true in nature.

The error causes results that are inaccurate or misleading and can misrepresent nature. Scientifically accepted values are scientists' current best approximations, or descriptions, of nature.

Experimental error is the difference between a measured value and its true value. In other words, it is the inaccuracy or inaccuracies that stop us from seeing an absolutely correct measurement. Experimental error is very common and is to some degree inherent in every measurement.

Therefore, the mistake that Farah made in this experiment is that she hung up the pieces of cotton before putting the fan on, also the water evaporating can take longer or shorter even if they are all the same.

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The spring constant of the spring is 178.4 N/m.

In this problem, we are given a mass of 0.25 kg that is attached to a spring and set into vibration with a period of 0.22 s.

We can use the equation for the period of a mass-spring system, which relates the period of oscillation to the mass and spring constant, to calculate the spring constant.

We can use the equation for the period of a mass-spring system:

T = 2π√(m/k)

where T is the period, m is the mass, and k is the spring constant.

Rearranging this equation to solve for k, we get:

k = \((4\pi^2m) / T^2\)

Substituting the given values, we get:

k = \((4\pi^2 \times 0.25 \:kg) / (0.22 s)^2\)

k = 178.4 N/m

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a. A high-pitch wave is characterized by a high frequency and a short wavelength. The frequency determines the pitch of the sound, with higher frequencies corresponding to higher pitches.

The wavelength is the distance between two consecutive peaks or troughs of the wave and is inversely proportional to the frequency. Therefore, a high-pitch wave has a shorter wavelength.

The amplitude of the wave, which is the height of the peak or the depth of the trough, is not directly related to the pitch of the sound, but it does determine the volume or intensity of the sound.

b. A high-volume wave is characterized by a high amplitude and a relatively long wavelength. The amplitude determines the volume or intensity of the sound, with higher amplitudes corresponding to louder sounds.

The wavelength of the wave does not directly affect the volume of the sound, but it can affect how the sound is perceived in different environments.

In general, longer wavelengths are more effective at traveling through obstacles such as walls and are better at penetrating long distances, whereas shorter wavelengths are more easily scattered and attenuated in the atmosphere.

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The linear speed will be the insect be 0.5759 meter/second carried collision with the near stationary photograph.

Speed is distance travelled by the object per unit time. Due to having no direction and only having magnitude, speed is a scalar quantity With SI unit meter/second.

Given that an insect lands 0.1m from the center of the turn table.

Rotational speed of the turn table = 55 rev/min

= (55×2π/60) rad/second

= 5.759 rad/second.

Hence, the speed of the insect be = Rotational speed × length

= 5.759 rad/second × 0.1 M.

= 0.5759 meter/second.

Therefore, the speed of the insect be 0.5759 meter/second.

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Answer:

Explanation:

The velocity of the spacecraft can be found by using the formula

\(v = \frac{p}{m} \\ \)

p is the momentum

m is the mass

From the question we have

\(v = \frac{20000}{250} = \frac{2000}{25} \\ \)

We have the final answer as

Hope this helps you

Answer: It is Reflection

Explanation: Reflection occurs when incoming solar radiation bounces back from an object or surface that it strikes in the atmosphere, on land, or water, and is not transformed into heat.

The height of the mansion that the assassin shot the target from is determined as 1,164.9 ft.

The time of motion of the bullet is calculated as follows;

-h = vsinθ(t)  - ¹/₂gt²

-6.1 = (vt) sin63  - ¹/₂(32)t²

-6.1 = 0.89vt - 16t² ---(1)

X = vcosθ t

294 = (vt)cos63

294 = 0.454vt

vt = 294/0.454

vt = 647.577 ---(2)

solve (1) and (2) together;

-6.1 = 0.89(647.577) - 16t²

16t² = 576.344 + 6.1

16t² =  582.44

t² = 582.44/16

t² = 36.4

t = √36.4

t = 6.03 s

v = 647.577/t

v = 647.577/6.03

v = 107.4 ft/s

h = vt + ¹/₂gt²

h = (107.4 x sin63 x 6.03) + ¹/₂(32)(6.03)²

h = 1,158.8 ft

H = 1,158.8 ft + 6.1 ft = 1,164.9 ft

Thus, the height of the mansion that the assassin shot the target from is determined as 1,164.9 ft.

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Answer:

C. 6.9 watts

Explanation:

Power = work/time

if work = force×distance...

Then... power= (force×distance)/time

Power = (20×12)/35

= 6.9 watts

Answer:

a) 17.15cm

b)0.687mm

c)erect

Explanation:

Given:

Diameter = 9.00 cm

\(n_{1}\) for air =1

Index of refraction n₂= 1.61

Radius of curvature R= 4.50

Height of object h₀= 1.55 mm

Object distance u= 24.0 cm

(A)In order to calculate the image distance , we use formula for image of distance

\(\dfrac{n_{1}}{u}+\dfrac{n_{2}}{v}=\dfrac{n_{2}-n_{1}}{R}\)

By plugging in all the required values

\(\dfrac{1}{24.0}+\dfrac{1.61}{v}=\dfrac{1.61-1}{4.50}\)

\(\dfrac{1.61}{v}=\dfrac{1.61-1}{4.50}-\dfrac{1}{24.0}\)

\(\dfrac{1.61 }{v}=\dfrac{169}{1800}\)

\(v=\dfrac{1.61\times1800}{169}\)

\(v=17.15\ cm\)

(B). In order to calculate the height of the image , we'll use formula of magnification

\(m=\dfrac{h_{i}}{h_{o}}\dfrac{h_{i}}{h_{o}}=\dfrac{n_{1}d_{1}}{n_{2}d_{o}}\)

By substituting all the required values, we get

\(\dfrac{h_{i}}{1.55}=\dfrac{1\times17.15}{1.61\times24.0}\)

\(h_{i}=\dfrac{1\times17.15\times1.55}{1.61\times 24.0}\\h_{i}=0.687\ mm\)

c) The image is erect as it is of (+)ve sign.

For the  pendulum taken to the moon, The frequency change that would occur is mathematically given as

\(\frac{Fmoon}{Fearth}=0.408\)

Generally, the equation for the Time period  is mathematically given as

\(T=2\pi\sqrt{L/g}\)

Therefore

\(\frac{Fmoon}{Fearth}=\frac{\sqrt{g/6L}}{\sqrt{g/6L}}\\\\\frac{Fmoon}{Fearth}=\sqrt{1/6}\)

\(\frac{Fmoon}{Fearth}=0.408\)

In conclusion, The frequency change

\(\frac{Fmoon}{Fearth}=0.408\)

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Answer:

.408

Explanation:

Answer:

I think the answer is  

a "cookbook" recipe for performing scientific investigations

Explanation:

Answer:

horizontal component=fcostita

=150cos60

use calculator to evaluate it

for vertical=fsintita

=150sin60

This problem involves the concept of length contraction in special relativity. According to the theory of relativity, an object moving at a high velocity will appear shorter in the direction of motion when measured by an observer at rest relative to the object. The formula for length contraction is:

L' = L / γ

where L is the length of the object in its rest frame, L' is the length as measured by an observer in motion relative to the object, and γ is the Lorentz factor, given by:

γ = 1 / sqrt(1 - v^2/c^2)

where v is the velocity of the object and c is the speed of light.

In this problem, the length of the rocket ship as measured by the ground-based observer is L = 160 m, and the velocity of the rocket is v = 0.82c, where c is the speed of light. We want to find the length of the rocket when it is brought to rest, which corresponds to the rest frame of the rocket. In the rest frame, the rocket's velocity is zero, so we have:

γ = 1 / sqrt(1 - 0^2/c^2) = 1

Therefore, the length of the rocket in its rest frame is:

L_rest = L / γ = L = 160 m

So the length of the rocket when brought to rest is the same as its length when measured by the ground-based observer, which is 160 m.

Thermodynamics is a macroscopic science. Thermodynamics is the study of the relations between heat, work, temperature, and energy.

Thermodynamics  is a branch that deals with heat, work and temperature, and their relation to energy, radiation and physical properties of matter. Thermodynamics is a macroscopic science which means dealing with substances in bulk or with large amount.

Thermodynamics is classified into the following four branches:

1- Classical Thermodynamics

2- Statistical Thermodynamics

3- Chemical Thermodynamics

4- Equilibrium Thermodynamics

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Answer:

The effects of the thin atmosphere are that the surface of the planet is going to be much hotter and not only that but also more radioactive than a planet with a thicker atmosphere. The thick atmosphere on other planets prevents a lot of radiation from going straight to the surface of the planet.

Explanation:

Answer:

below

Explanation:

The change in Kinetic Energy is equal to the work done

  KE = 1/2 mv^2

      Change in KE =   1/2 m (19^2 - 3.2^2) = 747.1 kjoules

The magnitude of the power dissipated in resistor R4 is approximately 10,028 watts.

To find the power dissipated in resistor R4, use the formula:

P = I² × R

where P = power, I = current flowing through the resistor, and R = resistance of the resistor.

The total resistance, Rt, can be calculated using the formula:

1/Rt = 1/R1 + 1/R2 + 1/R3

Substituting the given values:

1/Rt = 1/3 + 1/0.8 + 1/2

Simplifying the equation:

1/Rt ≈ 1.6667

Rt ≈ 0.6 Ω

Next, calculate the total voltage, Vt, by summing the individual voltage sources:

Vt = ε1 + ε2 + ε3

Substituting the given values:

Vt = 9 + 6 + 4

Vt = 19 V

Now calculate the current flowing through resistor R4 using Ohm's Law:

I = Vt / Rt

Substituting the calculated values:

I = 19 / 0.6

I ≈ 31.6667 A

Finally, calculate the power dissipated in resistor R4:

P = I² × R4

Substituting the calculated values:

P = (31.6667)² × 10

P ≈ 10,028 W

Therefore, the magnitude of the power dissipated in resistor R4 is approximately 10,028 watts.

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Differentiate the components of position to get the corresponding components of velocity :

\(v_x = \dfrac{\mathrm dx}{\mathrm dt} = \left(1.5\dfrac{\rm m}{\mathrm s^3}\right) t^2 - \left(4\dfrac{\rm m}{\mathrm s^2}\right)t\)

\(v_y = \dfrac{\mathrm dy}{\mathrm dt} = \left(1\dfrac{\rm m}{\mathrm s^2}\right)t-2\dfrac{\rm m}{\rm s}\)

At t = 5.0 s, the particle has velocity

\(v_x = \left(1.5\dfrac{\rm m}{\mathrm s^3}\right) (5.0\,\mathrm s)^2 - \left(4\dfrac{\rm m}{\mathrm s^2}\right)(5.0\,\mathrm s) = 17.5\dfrac{\rm m}{\rm s}\)

\(v_y = \left(1\dfrac{\rm m}{\mathrm s^2}\right)(5.0\,\mathrm s)-2\dfrac{\rm m}{\rm s} = 3.0\dfrac{\rm m}{\rm s}\)

The speed at this time is the magnitude of the velocity :

\(\sqrt{{v_x}^2 + {v_y}^2} \approx \boxed{17.8\dfrac{\rm m}{\rm s}}\)

The direction of motion at this time is the angle \(\theta\) that the velocity vector makes with the positive x-axis, such that

\(\tan(\theta) = \dfrac{3.0\frac{\rm m}{\rm s}}{17.5\frac{\rm m}{\rm s}} \implies \theta = \tan^{-1}\left(\dfrac{3.0}{17.5}\right) \approx \boxed{9.73^\circ}\)

Answer:

To create healthy water and more for more H (hydrogen)

Explanation:

Given

a) m = 6000 kg, v = 11 m/s

b) m = 0.200 kg, v = 300 m/s

c) m = 18000 kg, v = 0 m/s

Procedure

Momentum is a physics term; it refers to the quantity of motion that an object has.

where m is mass and v is velocity

a) p = mv

p = 6000 kg * 11 m/s

p = 66000 kg*m/s

b) p = mv

p = 0.2 kg * 300 m/s

p = 60 kg*m/s

c) p = mv

p = 18000 kg * 0 m/s

p = 0 kg*m/s

The biggest momentum is with the elephant. And the car has the greatest inertia (mass).