In a series RLC circuit, the inductance is 14 mH, the capacitance is 63 nF, the resistance is 12 ohms, and the maximum potential is 57 V.
1.)Find the resonant angular frequency answer is in units of rad/s.
2) Find the amplitude of the current at the resonant frequency Answer in units of A
3) FInd the quality factor of the circuit
4) Find the amplitude of the voltage across the inductor at resonance answer in V

If you heat a rock until it glows, its spectrum will display a continuous spectrum with no visible lines or bands. This is because the high temperature causes the atoms in the rock to vibrate rapidly and emit electromagnetic radiation in all directions, resulting in a broad range of wavelengths being emitted.

In contrast to a continuous spectrum, which shows a range of colors blending together smoothly, a line spectrum displays distinct lines or bands at specific wavelengths. This occurs when atoms emit or absorb light at specific wavelengths due to changes in their energy levels.

Therefore, if the rock were to cool down and emit light at a lower temperature, it may display a line spectrum depending on the chemical composition of the rock and the specific elements present. However, when heated to the point of glowing, the rock's spectrum will be a continuous one.

To know more about spectrum  visit :-

https://brainly.com/question/12157930

#SPJ11

Answer:

Explanation:

A. Encouragement

Answer:

 ΔT = \(\pi \ \frac{\Delta L}{\sqrt{Lg} }\)

Explanation:

In a simple harmonic motion, specifically in the simple pendulum, the angular velocity

          w = \(\sqrt{\frac{g}{L} }\)

angular velocity and period are related

          w = 2π / T

we substitute

          2π / T = \sqrt{\frac{g}{L} }

          T = \(2\pi \ \sqrt{\frac{L}{g} }\)

In this exercise indicate that for a long Lo the period is To, then and increase the long

          L = L₀ + ΔL

we substitute

           T = \(2\pi \ \sqrt{\frac{L + \Delta L}{g} }\)

            T = \(2\pi \ \sqrt{\frac{L}{g} } \ \sqrt{1+ \frac{\Delta L}{L} }\)

in general the length increments are small ΔL/L «1, let's use a series expansion

           \(\sqrt{1+ \ \frac{\Delta L}{L} } = 1 + \frac{1}{2} \frac{\Delta L}{L} + ...\)  

we keep the linear term, let's substitute

           T = \(2\pi \ \sqrt{\frac{L}{g} } \ ( 1 + \frac{1}{2} \frac{\Delta L}{L} )\)  

if we do

           T = T₀ + ΔT

           T₀ + ΔT = \(2\pi \sqrt{\frac{\Delta L}{g} } + \pi \ \sqrt{\frac{L}{g} } \ \frac{\Delta L}{L}\)

            T₀ + ΔT = T₀ + \(\pi \sqrt{\frac{1}{Lg} } \ \Delta L\)

            ΔT = \(\pi \ \frac{\Delta L}{\sqrt{Lg} }\)

Answer:

the mass of the body is 4 kg

Explanation:

PE = mass • height • gravity

200J = mass • 5m • 10m/s/s

divide both sides by 50

4kg = mass

The mass of the body is 4 kg

Formula: PE = mass*height*gravity

200J = mass*5m*10m/s/s

divide both sides by 50

∴ mass = 4kg

Capacity energy is saved energy that relies upon the relative position of diverse elements of a machine. Spring has more capacity strength while it's miles compressed or stretched. A steel ball has extra capability strength raised above the floor than it has after falling to Earth.

Learn more about potential energy here: https://brainly.com/question/14427111

#SPJ2

Answer:

true

Explanation:

Answer:its true i think im sorry if you get wrong

Explanation:

The focal length of the mirror, when the object is moved towards it and a virtual image is formed is calculated to be -4u/3.

We know that,

magnification, m =      height of image, v        

                                 height of the object, u

given in the question, m = 4

as the mirror is concave, thus:

v= -4u

Now, by using the mirror formula:

1/(-f) = 1/ v + 1/u    

(as the image formed is virtual, the focal length of the mirror will be negative)

1/(-f) = 1/(-4u) + 1/u

-1/f = 3/4u

f= -4u/3

Concave mirrors create both physical and virtual images. When the concave mirror is put very close to the object, a virtual and enlarged image is generated; as the distance between the item and the mirror increases, the size of the image decreases, and genuine images are formed. These real-world photographs can be displayed on a screen. The concave mirror's focal point and center of curvature are located in front of the mirror.

Learn more about concave mirrors here:

brainly.com/question/3555871

#SPJ9

Answer: becuase----Mercury is the only one in liquid state at room temperature. It's used in thermometers because it has high coefficient of expansion. ... It also has a high boiling point which makes it very suitable to measure higher temperatures. Also, it has a shiny appearance and doesn't stick to the glass surface of glass.

Explanation: hope i helped c:

Answer:

Acceleration 0.238 m/s²

Explanation:

Given:

V₀ = 13.2 m/s

V = 15.1 m/s

t = 8.00 s

__________

a - ?

Is the acceleration of the object:

a = (V - V₀) / t

a = (15.1 - 13.2) / 8.00 ≈ 0.238 m/s²

Acceleration of the object is 0.238 m/s²

Acceleration of an object is rate of change of velocity with respect to time. Due to having both direction and magnitude, it is a vector quantity of SI unit meter/second².

Given parameters:

Initial velocity; V₀ = 13.2 m/s

Final velocity; V = 15.1 m/s

time; t = 8.00 s

acceleration of the object; a = ?

We know, for accelerated object;

acceleration; a = (V - V₀) / t

⇒a = (15.1 - 13.2) / 8.00 ≈ 0.238 m/s²

Hence, acceleration of the object is 0.238 m/s².

Learn more about acceleration here:

https://brainly.com/question/12550364

#SPJ2

kinetic energy of the ball of mass 50 g and velocity of 300m/s is 22.5 J. The work done need to stop the ball is equivalent to its kinetic energy. Thus, 22.5 J of work done is needed.

The kinetic energy of an object is the energy generated by virtue of its motion. It is related to its mass and velocity by the expression written below:

Ke = 1/2 m v²

Thus, kinetic energy increases with mas and velocity.

Given that, mass of the ball = 50 g = 0.05 kg

velocity of  the ball = 30 m/s

then Ke = 1/2  × 0.05 kg × 30 m/s × 30 m/s = 22.5 J.

The energy of the body when it is moving is in the form of kinetic energy. This energy of the body is equivalent to the work done on the body to stope it. Therefore, work done on the ball needed to stop it is 22.5  J.

Find more on kinetic energy:

https://brainly.com/question/15764612

#SPJ2

Given :

Initial velocity, u = 12.5 m/s.

Height of camera, h = 64.3 m.

Acceleration due to gravity, g = 9.8 m/s².

To Find :

How long does it take the camera to reach the ground.

Solution :

By equation of motion :

\(h = ut+\dfrac{gt^2}{2}\)

Putting all given values, we get :

\(12.5t+\dfrac{9.8t^2}{2}=64.3\\\\4.9t^2+12.5t=64.3\)

t = 2.56  and t = −5.116.

Since, time cannot be negative.

t = 2.56 s.

Therefore, time taken is 2.56 s.

Hence, this is the required solution.

The movement of the plates may lead to or cause an earthquake.

At convergent boundaries, two tectonic plates are moving towards each other. There are three types of convergent boundaries, characterized by the type of plates involved: Oceanic-Oceanic Convergence, Oceanic-Continental Convergence, Continental-Continental Convergence.

At divergent boundaries, two tectonic plates are moving away from each other. This type of boundary is often associated with seafloor spreading, where new crust is formed as magma rises to the surface and solidifies. Divergent boundaries on land can result in the formation of rift valleys and volcanoes.

At transform boundaries, two tectonic plates are sliding past each other. These boundaries are characterized by lateral movement and can result in earthquakes

What is plate movement:https://brainly.com/question/3970445

#SPJ1

Due to the fact that it is more difficult to initiate motion than to maintain it, the coefficient of kinetic friction is almost always lower than the coefficient of static friction.

The form of friction between static or motionless surfaces is known as static friction. On the other hand, kinetic friction is the resistance between two surfaces while at least one of them is moving.

Due to the fact that there are more forces operating to maintain an object stationary on a given surface than there are forces resisting an object in motion, the coefficient of static friction is always greater than or equal to the coefficient of kinetic friction.

To know more about static friction you may visit the link:

https://brainly.com/question/13000653

#SPJ4

The ball will hit the ground after 0.408 sec and the horizontal range of the projectile is 1.414 m.

When a particle throws obliquely near the surface, it follows along a curved path under constant acceleration directed towards the center of the earth. The path followed by the particle and the motion is called projectile motion.

Consider the 'u' is the initial velocity of the particle and θ is the angle with the horizon,

The time of the flight =  (2u sinθ)/g

The horizontal range (R) = (u² sin2θ)/g

Given, the initial velocity of the projectile, u 4 m/3

The angle above the horizon, θ = 30°

The time  the ball falls back and hits the ground (t):

t = (2u sinθ)/g = (2 × 4 sin30)/9.8 = 0.408 s

The horizontal range (R) of the projectile = (u² sin2θ)/g

R = (4² sin60)/9.8

R = 1.413 m

Learn more about Projectile motion, here:

https://brainly.com/question/11049671

#SPJ1

The  action that contributes to mid-ocean ridge formation is when the  tectonic plates move parallel to each other.

The correct option is B.

Tectonic plates are described as composing of the oceanic lithosphere and the thicker continental lithosphere, each topped by its own kind of crust.

The mid-ocean ridge forms due to volcanic activity located along the Earth's tectonic plates causing two tectonic plates to move or pull apart from each other creating a zone which is referred to as divergent plate boundaries.

Learn more about tectonic plate at :  https://brainly.com/question/1162125

#SPJ1

Answer:

6km/hr

Explanation:

3km = 30mins

x(km) = 1hr

1hr = 60 x 60 = 3600secs

30min = 30 x 60 = 1800secs

3 x 3,600/x X 1,800

x = 10,800/1,800

x = 6km/hr

To solve the problem we must know about speed, distance, and time.

We know that speed, distance, and time all are in a relationship with each other. this relationship can be given as,

\(\rm{Speed = \dfrac{Distance}{Time}\)

Given to us

A student walks 3 km in 30 minutes.

We know distance can be written as the product of speed and time, therefore,

\(\rm Distance = \rm speed \times \rm Time\)

Substituting the values we get,

\(\rm 3\ km = Speed \times 0.5\ hour\)

\(\rm speed = \dfrac{3\ km}{0.5\ hour}\)

speed = 15 km\h

Hence, the speed of the student is 15 km\hour.

Learn more about speed, distance, and time:

https://brainly.com/question/15100898

\( = \sf \frac{1}{2} m {v}^{2} \)

\( \sf = \frac{2.4J}{9.6J} \\ \sf= \frac{24}{96} = \frac{1}{4} \\ \sf = 1 : 4\)

Answer:

The kinetic energies of the bullets are 2.4 J and 9.6 J.

The bullet having greater velocity has more kinetic energy.

The ratio of their kinetic energies is 1 : 4.

Hope you could get an idea from here

Doubt clarification - use comment section.

The kinetic energy of the two bullets are 2.4 J and 9.6 J respectively.

The ratio of the kinetic energy of the bullets is 1:4.

The kinetic energy of an object is the energy possessed by the object due to its motion.

The kinetic energy of the two bullets is calculated as follows;

\(K.E_1 = \frac{1}{2} \times 0.003 \times 40^2 = 2.4 \ J\\\\K.E_2 = \frac{1}{2} \times 0.003 \times 80^2 = 9.6 \ J\)

Ratio of the kinetic energy of the bullets is calculated as follows;

\(K.E_1 : K.E_2 = 2.4: 9.6 \ = \ 1: 4\)

Learn more about kinetic energy here: https://brainly.com/question/25959744

The helium flash occurs during the red giant phase in the stellar evolution of low- and intermediate-mass stars.

To understand the helium flash, we must first examine the stages of stellar evolution leading up to it. Initially, a star forms from a cloud of gas and dust, primarily composed of hydrogen. As the cloud contracts under gravity, its core heats up, and eventually nuclear fusion starts, converting hydrogen into helium. This process, called the main sequence stage, generates energy and allows the star to shine.

Over time, the hydrogen in the core depletes, and fusion moves to a shell around the core. The core, now primarily composed of helium, continues to contract and heat up, while the outer layers of the star expand due to the increased energy generated by the hydrogen shell fusion. This expansion causes the star to enter the red giant phase.

As the helium core contracts, its temperature rises until it reaches a critical point, typically around 100 million Kelvin, where helium nuclei can overcome their electrostatic repulsion and undergo nuclear fusion. This fusion converts helium into carbon and oxygen, producing a rapid burst of energy called the helium flash. The energy release is so sudden that it causes the star to experience a rapid increase in brightness, even though the event occurs deep within the core and is not directly observable.

In summary, the helium flash occurs during the red giant phase of low- and intermediate-mass stars, when the core temperature reaches a critical point, allowing helium nuclei to undergo nuclear fusion and produce a sudden burst of energy.

Learn more about stellar evolution at: https://brainly.com/question/12790561

#SPJ11

Answer:

b

Explanation:

i took the quiz

Both the transverse and longitudinal waves move faster at higher temperatures.

A wave in which the motion of the particles is perpendicular to the direction of the wave propagation is referred to as a transverse wave.

Here,

As a result of the shear stress that is produced, transverse waves are frequently observed in elastic materials.

In this situation, the oscillations are caused by the displacement of the solid particles from their relaxed state in directions perpendicular to the wave's propagation.

The wave in which the particles of the medium oscillate parallel to the direction of propagation of the wave is called a longitudinal wave.

Sound waves similarly oscillate parallel to the direction of propagation, forming the compressions and rarefactions. Hence sound waves are called longitudinal waves.

Hence,

Both the transverse and longitudinal waves move faster at higher temperatures.

To learn more about transverse waves, click:

https://brainly.com/question/13863548

#SPJ5

A G star with a brightness of 100 L Sun is classified as Figure 19.15 lum inosity Classes. Its surface area must be 100 times greater since it emits 100 times more energy while maintaining the same temperature.

Even more bright than the massive stars are the stars of group C. These are the largest stars, or supergiants, with the highest luminosities. If a red supergiant like Betelgeuse took the place of the Sun in our solar system, it would be larger than Jupiter's orbit.

A main-sequence (core hydrogen-burning) star with the spectral type O and luminosity class V is referred to as an O-type main-sequence star (O V). The mass of these stars ranges from 15 to 90 times that of the Sun, and their surface temperatures range from 30,000 to 50,000 K. They have a brightness that ranges from 40,000 to 1,000,000 times that of the Sun.

to know more about the sun here:

brainly.com/question/17376727

#SPJ4

The maximum span of the simply supported beam, using the given timber section with an allowable stress of 1700 psi and a uniform load of 300 lbs/ft, is approximately 2.16 feet.

The parameters provided, the maximum span (L) of the simply supported beam can be calculated as follows:

Assuming a beam width of 6 inches (0.5 ft) and height of 10 inches (0.83 ft), and a uniform load of 300 lbs/ft:

Calculate the maximum bending moment (M) using the formula:

\(M = (1700 psi * [(1/12) * (0.5 ft) * (0.83 ft)^3] * (0.83 ft)) / (0.83 ft/2)\)

\(M = 144.65 ft-lbs\)

Use the bending moment formula for a simply supported beam to find the maximum span (L):

\(L = sqrt((8 * M) / w)\)

\(L = sqrt((8 * 144.65 ft-lbs) / (300 lbs/ft))\)

\(L = 2.16 ft\)

Therefore, the maximum span of the simply supported beam, using the given timber section with an allowable stress of 1700 psi and a uniform load of 300 lbs/ft, is approximately 2.16 feet.

Learn more about allowable stress

https://brainly.com/question/33279148

#SPJ11

Answer:

The main function of the cell nucleus is to control gene expression and mediate the replication of DNA during the cell cycle

The terminal speed of the marble is 0.588 m/s.

The term "force" has a specific meaning in science. At this level, calling a force a push or a pull is quite appropriate. A force is not something an item "has in it" or that it "contains." One thing experiences a force from another. There are both living things and non-living objects in the concept of a force.

We know that,

F = mg                          ......(1)

where,

F = force

m = mass

g = acceleration due to gravity

Also,

v = F/k                            ......(2)

where,

v = terminal speed

k = proportionality constant

Substituting the value of F from equation (1) in equation (2)

v = mg/k                             .......(3)

Given,

m = 30 g = 0.030 kg

k = 0.500 kg/s

g = 9.8 m/s²

To find,

v =?

Put the values in equation (3)

v = mg/k        

v = 0.03(9.8)/ 0.500

= 0.294/0.500

= 0.588 m/s

​

Learn more about the calculation of force, refer to:

brainly.com/question/15562875

#SPJ4

The car travels a distance of (v0²/2μg) before coming to a complete stop, and it takes a time of (v0/μg) to come to a complete stop. The first step is to determine the acceleration of the car. When the brakes are locked, the friction force is maximum.

Hence, the force acting on the car due to the friction force is given by F = μmg where μ is the coefficient of friction, m is the mass of the car, and g is the acceleration due to gravity. In this case, the friction force acts opposite to the direction of the motion of the car.

Therefore, the net force acting on the car is given by F = -μmg.

Since the net force is equal to the mass times acceleration, we get the acceleration of the car as a = -μg.Next, we need to determine the distance traveled by the car before it comes to a complete stop.

The equation for the distance traveled by the car is given by

s = v0t + (1/2)at² where s is the distance traveled, v0 is the initial velocity, t is the time taken to come to a complete stop, a is the acceleration of the car, and t is the time taken to come to a complete stop.

Finally, we need to calculate the time taken by the car to come to a complete stop. The equation for the time taken by the car is given by t = v0/a where t is the time taken to come to a complete stop, v0 is the initial velocity, and a is the acceleration of the car. Hence, the distance traveled by the car before it comes to a complete stop is given by s = v0t + (1/2)at² = v0(v0/μg) + (1/2)(-μg)t² = v0²/2μg.The equation for the time taken by the car is given by t = v0/a where t is the time taken to come to a complete stop, v0 is the initial velocity, and a is the acceleration of the car. Hence, the time taken by the car to come to a complete stop is given by t = v0/a = v0/(-μg) = -(v0/μg). Therefore, the car travels a distance of (v0²/2μg) before coming to a complete stop, and it takes a time of (v0/μg) to come to a complete stop.

To know more about friction, visit at:

https://brainly.com/question/28356847

#SPJ11

Answer:

true

Explanation:

this is true, igneous rocks are formed from molten lava when it cools

Answer: True

Explanation:

Answer:

mass=56.12kg

Explanation:

PE=mgh

4620=m×9.8×8.4

make m subject of the formula...

m =4620/(9.8×8.4)

m=4620/82.32

m=56.12kg

Answer:D.Refractive Indez

Explanation:

It is usually expressed the other way: the ratio of the speed of light in a vacuum to the speed of light in a medium. In that case, it is called the "index of refraction".

You're going for "refractive index", but you've got the ratio flipped over.

Answer:

answer below

Explanation:

2: net force

3: balanced force

4: unbalnced force

i hope this is right