The rotational period during which the centripetal acceleration is 3.0 g is 4.35 s. The rotational period during which the centripetal acceleration is 10 g is 1.68 s.
What is the centripetal acceleration?centripetal acceleration is the rate at which a body moves through a circle. Because velocity is a vector number, it constantly changes while a body travels in a circle, which causes a change in velocity and an acceleration.
a = magnitude of the centripetal acceleration
r = radius of the circle
v = velocity
We can use the centripetal acceleration formula,
v = sqrt(ar)
(a) To find the period of rotation at which the centripetal acceleration has a magnitude of 3.0 g, we need to convert g into meters per second squared (m/s^2).
We know that 1 g = 9.8 m/s^2, so 3.0 g = 29.4 m/s^2.
we get,
v = sqrt(ar) = sqrt(29.4 x 7.0) = 20.3 m/s
The period of rotation,
T = 2πr / v
T = period of rotation.
T = 2π x 7.0 / 20.3 = 4.35 s
(b) To find the period of rotation at which the centripetal acceleration has a magnitude of 10 g,
We know that 1 g = 9.8 m/s^2, so 10 g = 98 m/s^2.
we get:
v = sqrt(ar) = sqrt(98 x 7.0) = 26.3 m/s
The period of rotation,
T = 2πr / v
T = period of rotation.
T = 2π x 7.0 / 26.3 = 1.68 s
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Explain why it’s much colder at the bottom of the pool than at the top. also describe what heat transfer processes is taking place
Heat transfer by radiation and convection causes the surface water of the pool to be warm which decreases with depth.
Why is it colder at the bottom of the pool than the top of the pool?
There are two heat transfer process responsible for variation in temperature of water at different depth of a pool, they include;
Heat transfer by radiationHeat transfer by convection Heat transfer by radiationThe surface of the water absorbs heat from the air and the sun. The heat from the sun is transferred to the pool through radiation.
Heat transfer by convectionThe heat from the air is transferred to the pool through convection.
Thus, these two heat transfer processes causes the surface water of the pool to be warm which decreases with depth.
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An automobile moves forward and backward on the street highway. The graph shows the velocity of this automobile as a function of time. At t equals five seconds, how far is the automobile from its t = 0 initial position? (round to 3 significant digits)
The velocity of this automobile as a function of time. At t = 5 seconds, the automobile is 90 meters from its initial position.
To determine the distance traveled by the automobile from its t = 0 initial position, we need to calculate the area under the velocity-time graph up to t = 5 seconds.
The graph shows the velocity of the automobile as a function of time. Let's assume that positive velocity represents forward motion, and negative velocity represents backward motion.
Since velocity represents the rate of change of displacement, the area under the velocity-time graph represents the displacement or distance traveled. In this case, the area will consist of two parts: the area above the x-axis (forward motion) and the area below the x-axis (backward motion).
To calculate the area, we can break it down into two separate integrals:
1. The area above the x-axis (forward motion):
Since the velocity is constant at 20 m/s for the first 4 seconds, the area is a rectangle:
Area1 = velocity * time = 20 m/s * 4 s = 80 m
2. The area below the x-axis (backward motion):
The velocity changes to -10 m/s at t = 4 seconds. From t = 4 seconds to t = 5 seconds, the velocity is -10 m/s. The area is a rectangle:
Area2 = velocity * time = -10 m/s * 1 s = -10 m
To find the total distance traveled, we add the absolute values of the areas:
Total distance = |Area1| + |Area2| = |80 m| + |-10 m| = 80 m + 10 m = 90 m
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Estimate the gravitational force of attraction between two people sitting side by side on a park bench. How does this force compare with the gravitational force exerted on each of them by the Earth
Weight is compared with the gravitational force exerted on each of them by the Earth.
What is Newton's law of gravitation?Newton's law of gravity states that each particle having mass in the universe attracts each other particle with a force known as the gravitational force.
The gravitational force is proportional to the product of the masses of the two bodies and inversely proportional to the square of their distance.
When mass increases and distance reduces, gravity rises. Gravity also lowers when the distance between two points grows and the mass decreases.
The gravitational force is balanced by weight;
\(\rm F = W \\\\ G\frac{mM}{r^2} =mg\)
Hence, weight is compared with the gravitational force exerted on each of them by the Earth.
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A machine has a velocity ratio of 5 and the efficiency is 80% what effort would be needed to lift a load of 200N
Explanation:
To determine the effort needed to lift a load of 200N, given a velocity ratio of 5 and an efficiency of 80%, we can use the formula:
Efficiency = (Output Work / Input Work) * 100
Efficiency can also be calculated as the ratio of the output force to the input force. In this case, the output force is the load being lifted (200N), and the input force is the effort required.
Given that the velocity ratio is 5, it means that for every 5 units of distance the effort moves, the load moves 1 unit of distance. This implies that the effort is exerted over a greater distance than the load.
Let's denote the effort force as "E" and the distance moved by the effort as "dE." Similarly, the load force is "L," and the distance moved by the load is "dL."
Using the velocity ratio, we have the following relationship:
dE / dL = 5
Now, we can calculate the input work (Wi) and the output work (Wo):
Input Work (Wi) = Effort (E) * Distance moved by the effort (dE)
Output Work (Wo) = Load (L) * Distance moved by the load (dL)
Given that the efficiency is 80%, we can rewrite the formula for efficiency as:
0.80 = (Wo / Wi) * 100
Now, let's solve for the effort (E) using the given values:
Load (L) = 200N
Efficiency = 0.80
Velocity Ratio = 5
First, calculate the output work (Wo):
Wo = Load (L) * Distance moved by the load (dL)
Since the velocity ratio is 5, the distance moved by the load (dL) will be 1/5 of the distance moved by the effort (dE):
dL = (1/5) * dE
Wo = L * (1/5) * dE
Wo = 200N * (1/5) * dE
Wo = 40N * dE
Next, calculate the input work (Wi):
Wi = Effort (E) * Distance moved by the effort (dE)
Wi = E * dE
Now, substitute the values into the efficiency formula:
0.80 = (Wo / Wi) * 100
0.80 = (40N * dE) / (E * dE) * 100
0.80 = 40 / E * 100
0.80 * E = 40
E = 40 / 0.80
E = 50N
Therefore, the effort needed to lift a load of 200N with a velocity ratio of 5 and an efficiency of 80% is 50N.
What is an example of intellectual development?
Answer:
Emotional and Social Development
During the preschool years, your little one is learning to read emotional cues and is getting better at relating to other people, according to the New York University Child Study Center 1⭐
⭐This is a verified and trusted source
New York University Child Study Center: The Preschool Years: (Ages Four and Five) Expectations and Challenges
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. He can empathize with others and make friends with other children his own age. By his fifth birthday, your preschooler often seeks friends of the same gender and shows a preference for playing with other children, rather than adults. Your preschooler also engages in pretend play and can probably tell the difference between reality and fantasy, according to the American Academy of Pediatrics.
Physical Development
There's a big difference between a 2-year-old and a 5-year-old. During the preschool years, your child develops in many physical ways. She goes from toddling around unsteadily to being able to jump, stand on one foot, walk up and down stairs and walk backward, according to the New York University Child Study Center 1⭐
⭐This is a verified and trusted source
New York University Child Study Center: The Preschool Years: (Ages Four and Five) Expectations and Challenges
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. By the time she's 5, your little one should also be able to ride a tricycle, build a block tower, paint on paper, skip, throw a ball, dress and undress and begin drawing recognizable objects, adds the University of Illinois Extension.
As a 2.0-kg object moves from (4.4 i + 5j) m to ( 11.6 i - 2j) m, the constant resultant force
acting on it is equal to (41 - 9j) N. If the speed of the object at the initial position is 4.0 m/s,
what is its kinetic energy at its final position?
Answer:
Answer:
v_f = 10.38 m / s
Explanation:
For this exercise we can use the relationship between work and kinetic energy
W = ΔK
note that the two quantities are scalars
Work is defined by the relation
W = F. Δx
the bold are vectors. The displacement is
Δx = r_f -r₀
Δx = (11.6 i - 2j) - (4.4 i + 5j)
Δx = (7.2 i - 7 j) m
W = (4 i - 9j). (7.2 i - 7 j)
remember that the dot product
i.i = j.j = 1
i.j = 0
W = 4 7.2 + 9 7
W = 91.8 J
the initial kinetic energy is
Ko = ½ m vo²
Ko = ½ 2.0 4.0²
Ko = 16 J
we substitute in the initial equation
W = K_f - K₀
K_f = W + K₀
½ m v_f² = W + K₀
v_f² = 2 / m (W + K₀)
v_f² = 2/2 (91.8 + 16)
v_f = √107.8
v_f = 10.38 m / s
A 50 kg object traveling at 100 m/s collides (perfectly elastic) with a 50 kg object initially at rest.
What is the sum of the momentum of both objects prior to the collision?
a. 100 kgm/s b. 500 kgm/s C. 5,000 kgm/s d. 100,000 kgm/s
Answer:
a
Explanation:
We know the mass and luminosity of the star. We also know the mass of the spacecraft and the area of its stellar sail. We must find the net force exerted on the spacecraft, as well as the direction of its acceleration. We are asked to find both the net force exerted on the spacecraft and the direction of the acceleration. Which principle is best used to find the direction of the acceleration once the net force has been found
Answer:
Newton's principle of force, the variation of the momentum and the acceleration have the same direction
Explanation:
To find the force exerted by the star on the sail of the ship, the expression of the momentum of the radiation is used, which in the case of a total reflection
p = \(\frac{2U}{c}\)
where p is the momentum and U the incident energy and c the speed of light.
The strength I could get from
F = \(\frac{dp}{dt}\)
the direction of the acceleration is the direction of the momentum, therefore the principle to find the acceleration of is Newton's principle of force, the variation of the momentum and the acceleration have the same direction.
Highway safety engineers want to design roadside barriers that will crumple
in the event that a car drives off the road and collides with them, slowing
down the car more gradually. The average person has a mass of 68 kg and
travels on a highway at a velocity of 27 m/s. If the engineers know that the
maximum force that a person can safely withstand is 1650 N, approximately
how much time is required to crumple the barrier to safely slow the person
with this force?
A 1.5s
B. 0.7 s
C. 1.1 s
D. 2.1 s
The time required to crumple the barrier and safely slow down the person with a force of 1650 N is approximately C, 1.1 seconds.
How to find time?To determine the time required to crumple the barrier and safely slow down the person with a maximum force of 1650 N, use the equation of motion:
F = m × a
where:
F = force
m = mass
a = acceleration
Given:
m = 68 kg
F = 1650 N
Find the acceleration (a) first. Rearranging the equation:
a = F / m
Substituting the values:
a = 1650 N / 68 kg
a ≈ 24.26 m/s²
Now, use the equation of motion to find the time (t):
v = u + at
where:
v = final velocity (0 m/s as the person comes to a stop)
u = initial velocity (27 m/s)
a = acceleration (24.26 m/s²)
t = time
Rearranging the equation:
t = (v - u) / a
Substituting the values:
t = (0 m/s - 27 m/s) / 24.26 m/s²
t ≈ -27 m/s / 24.26 m/s²
t ≈ -1.11 s
The negative sign indicates that the time is in the opposite direction to the initial velocity. Taking the absolute value, the time required to crumple the barrier and safely slow down the person with a force of 1650 N is approximately 1.11 seconds.
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Barney walks at a velocity of 1.7 meters/second on an inclined plane which has an angle of 18.5 with the ground what is the horizontal component of Barney’s velocity
Answer:
Explanation:
The horizontal velocity is 1.61.
What is the largest atom of period 4
The largest atom of period 4 is Potassium (K).
What are the elements of period 4?
One of the chemical elements in the fourth row (or period) of the periodic table of the elements is known as element of period 4. The periodic table is organized into rows to show recurrent (periodic) tendencies in the chemical behavior of the elements as their atomic number rises.
One element is present in each of the eighteen groups, making up the fourth period's 18 elements, which start with potassium and end with krypton. d-block, which includes transition metals, makes its first appearance in the table.
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What type of increase either in frequency, intensity, time, type, or any combination of the FITT Principle categories should occur as a safe way to apply the principles of overload and progression?
Either in frequency, intensity, or time, or a combination of all three, it is a gradual increase.
What is intensity and example?According to the definition, intensity is the quality of being extremely powerful, concentrated, or difficult, or the strength or difficulty level of anything. Intensity can be demonstrated by being able to run at your maximum capacity for extended distances. An example of intensity is the speed a treadmill is moving at.
How do you measure intensity?A quick method to gauge relative intensity is the conversation test. In general, you can converse but not sing while engaging in moderate-intensity exercise. In general, you won't be able to speak for more than a few words without pausing to take a breath if you're engaging in vigorous-intensity activities.
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For an impulse-momentum experiment, students collect data on a collision between blocks A and B . A force probe attached to block A is used to measure the force exerted by block A on block B as a function of time during the collision. The data collected shows a positive force that is used to determine the impulse on block B . The force sensor is removed from block A and attached to block B , and the experiment is run again. Which of the following correctly describes how this affects the data and if the impulse on block B can still be determined?
A. The data can only be used to determine the impulse on block A, not block B.
B. The data can only be used to determine the impulse on block B, not block A.
C. The data cannot be used to determine the impulse on block A or block B.
D. The data can be used to determine the impulse on block B and block A.
E. The data can be used to determine the force on block B.
Answer:
the answer the correct one is D
Explanation:
The relationship between momentum and moment is
I = Δp
I = F t
This is for one of the body, that is, the force and the change in speed is for the same body.
In this case, in the first part, the sensor is placed in body A, therefore the force of this body can be measured and as time is also measured, let's calculate the impulse of body A.
In the second part of the experiment, the probe is placed in body B and the experiment is repeated, so we can also calculate the momentum of body b.
consequently in this experiment the momentum of body a and b can be measured.
to check the answer the correct one is D
As an object moves, the distance it travels increases with time.
Agree
Disagree
Answer: Agree
Explanation:
The idea is that it will be at a farther place at a later period.
Which graph below represents how the velocity of the sphere changes over time when falling with constant acceleration?
Justify your choice.
Graph B represents the velocity of the sphere changes over time when falling with constant acceleration.
Acceleration is the measure of how quickly a body's velocity varies with regard to time, and constant acceleration occurs when a body's velocity changes proportionately over a period of time, or at a constant rate. It measures in m/s2.It is claimed that a body has continual positive acceleration when it begins to move with an initial velocity of zero and gradually increases to a positive value over time.Constant positive acceleration is demonstrated by a ball falling freely in a vertical direction.To know more about constant acceleration. visit : https://brainly.com/question/9754169
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During which sequence of phases does the moon's visibility increase
During the "waxing" phases, the two weeks immediately following the New Moon.
New Moon ==> waxing crescent ==> First Quarter ==> waxing gibbous ==> Full Moon
The phase of the moon decides the moon's visibility. The sequence of phases does the moon's visibility increases is; the waxing crescent, first quarter, waxing gibbous, full Moon.
What is the moon phase?The moon changes shape every day. This is due to the fact that the celestial body has no light of its own and can only reflect sunlight.
Only the side of the moon facing the sun can reflect this light and seem bright. The opposite side appears black. this is a full moon.
We can only see the black section when it lies between the sun and the earth when a new moon occurs. We witness intermediate phases like a half-moon and crescent in between these two extremes.
Following are the sequence of phases does the moon's visibility increase is;
1. Waxing crescent
2. First Quarter
3. Waxing gibbous
4. Full Moon
The phase of the moon decides the moon's visibility. Hence the visibility changes with the change in the phase of the moon.
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what type of road connects bristol and hosford
Answer:
l.Basahin ang mga sumusunod na sitwasyon o pahayag. Bilugan ang tamang sagot.
1. Ang dignidad ay sinasabing dangal ng tao. Sino sa mga tauhan ang nagpapahalaga dito? a Iniwasan ni Noel na mangopya sa kanyang kamag-aral.
b. Laging sumusunod si Puring sa payo ng magulang.
c. Mas pinili ni Lora na magtrabaho sa pabrika kaysa maging nobya ng mayamang matanda.
d. Hindi nagsasalita ng masama sa kapwa si Pedro.
2. Bakit itinuturing ang tao na pinakabanal na nilalang ng Diyos?
a. Sapagkat ang tao ang pinakamarunong na nilikha.
b. Sapagkat ang tao ang may kakayahang mamahal sa ibang nilalang.
c. Sapagkat alam ng tao ang tama at mali.
d. Sapagkat ang tao ang siyang kawangis ng Diyos.
3. Ang unang antas ng pagpapatibay ng dignidad bilang tao ay...
a. Pagkakaroon ng mabuting ugnayan sa kapwa.
b. Pagkakaroon ng relasyon sa Diyos.
c. Paggalang sa sarili.
d. Paggalang sa karapatang pantao.
4. Ano ang kinalaman ng free will sa makataong kilos?
a. Dito nagmumula ang gawi ng tao.
b. Ito ang sumusubaybay sa gawi ng tao.
c. Nagsisilbing pagtataya sa bunga ng ginagawa ng tao.
d. Nagdidikta kung ano ang gagawin ng tao.
5. Ito ay lubhang mahalaga sa paglinang at paghubog sa kabutihang asal ng tao.
a. Makataong kilos
b. Pagtugon sa kilos
c. Responsibilidad
d. tungkulin
6. Ito ay bahagi ng buhay ng tao na dapat gampanan at ibinigay upang isabuhay.
a. Makataong kilos
b. Pagtugon sa kilos
c. Responsibilidad
d. pananagutan
7. Ito ay personal na responsibilidad na hindi dapat iasa sa ibang tao.
a. Linangin ang sarili
c. Pakikipagtulungan sa mga proyekto
b. pagganap sa mga gawain
d. pagtulong sa pagapapabuti ng pamilya
8. Alin sa mga sumusunod ang HINDI halimbawa ng isang tungkulin?
a. Pagsawalang bahala sa kapitbahay na humihingi ng tulong.
b. Huwag gamitin ang cellphone ng kapatid kung walang pahintulot
c. Malayang makaboto sa tamang edad. d. Sumunod sa batas trapiko
9. Paano mo maipapakita ang iyong pagpapahalaga sa iyong mga tungkulin at pananagutan?
a Pagtupad sa mga ito upang hindi maparusahan. b. Pagtupad sa mga ito upang mapaunlad ang sariling kakayahan at talento bilang tao.
c. Pagsunod sa mga ito kahit mali at hindi ko ito gusto.
d. Pagsunod sa mga ito kahit na nahihirapan at hindi ko kaya.
10. Ano ang tawag sa responsibilidad o tungkulin na dapat gawin o isagawa ng isang tao.
a. kalayaan
b. pananagutan
c. katarungan
d. paggalang
ASAP ASAP PLS NEED HELP NONCENSE REPORT
Explanation:
I D K
A force of 125N lifts a 10.0kg mass while gravity pulls down with a force of 100.0N. How long will it take for the mass to move 2.00 meters from rest
Explanation:
Hope this example helps you
Mark my example as brainalist
A car starts from rest and travels for t1 seconds with a uniform acceleration a1. The driver then applies the brakes, causing a uniform acceleration a2. If the brakes are applied for t2 seconds, determine the following. Answers are in terms of the variables a1, a2, t1, and t2.
THIS IS NOT A MULTIPLE-CHOICE QUESTION - I NEED THE EQUATION FOR EACH SECTION
a) How fast is the car going just before the beginning of the braking period?
b) How far does the car go before the driver begins to brake?
c) Using the answers to parts (a) and (b) as the initial velocity and position for the motion of the car during braking, what total distance does the car travel?
Here, we are required to determine how fast the car is moving, and how far the car goes before the braking period.
A. Vf = acceleration, a1 × time, t1
B. Therefore, D1 = a1 × (t1)².
C. D = 1/2{a1 × (t1)² + a2 × (t2)²}.
A. At uniform acceleration, the rate of change of velocity is constant with time.
However, since the car starts from rest, it's initial velocity, Vi = 0.
Therefore, the velocity (speed) at which the car is moving before the braking period, is,
Vf = acceleration, a1 × time, t1
B. To determine how far
the car has moved before the braking period is, D1 = average Velocity, (Vf/2) × time, t1.
However, velocity, Vf = a1 × t1.
Therefore, D1 = 1/2 {a1 × (t1)²}.
This is so because the velocity, Vf is the velocity of travel from rest and lasts over time, t1 at which point the braking period commenced.
C. During the braking period, there's deceleration (i.e decay in speed) which returns the velocity of the car back to zero, ultimately bringing the car to a halt.
During the braking period, the total distance covered is also,
D2 = 1/2 {a2 × (t2)²}.
Therefore, the total distance covered during the motion is, D1 + D2
Total distance, D = D1 + D2.
D =1/2 {a1 × (t1)² + a2 × (t2)²}.
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how would you describe the diameter of a round wire
the diameter is the biggest line that can touch the two opposite point of a round wire(circle)
or
d= circumference/π
Object 1 with mass 1=3.25 kg
is held in place on an inclined plane that makes an angle
of 40.0∘
with the horizontal. The coefficient of kinetic friction between the plane and the object is 0.535.
Object 2 with mass 2=4.75 kg
is connected to object 1 with a massless string over a massless, frictionless pulley. The objects are then released.
Calculate the magnitude
of the initial acceleration.
Calculate the magnitude
of the tension in the string once the objects are released.
The magnitude of the initial acceleration of the object is 4.2 m/s².
The tension in the string once the object starts moving is 13.65 N.
What is the magnitude of the initial acceleration?The magnitude of the initial acceleration of the object is calculated by applying Newton's second law of motion as follows;
F(net) = ma
m₂g - μm₁g cosθ = a(m₁ + m₂)
where;
m₁ and m₂ are the masses of the blocksg is acceleration due to gravityμ is coefficient of frictionθ is the angle of inclinationa is the acceleration(4.75 x 9.8) - (0.535 x 3.25 x 9.8 x cos40) = a(3.25 + 4.75)
33.5 = 8a
a = 33.5/8
a = 4.2 m/s²
The tension in the string once the object starts moving is calculated as;
T = m₁a
T = 3.25 x 4.2
T = 13.65 N
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Explain why a lorry loaded with bags of maize packed high up is likely to topple when negotiating a corner.
Answer:
Due to its centre of mass being too high and because of that it is at a high risk of toppling at the corner
The linear distance traveled by a wheel of radius 50cm after 99 complete revolutions is?
1)99m
2)210m
3)311
4)433
Answer:
3) 311 m
Explanation:
Circumference = 2πR = π m/rev
99 rev(π m/rev) = 99π m or about 311 meters
a current of a 6 flows through a light bulb for 12 s, how many coulombs of charge pass through the light bulb during this time
A current of a 6 flows through a light bulb for 12 s. The total charge that passes through the light bulb during the given time is 72 coulombs.
To calculate the total charge that passes through the light bulb, we need to use the formula Q = I * t, where Q represents the charge in coulombs, I represents the current in amperes, and t represents the time in seconds.
Step 1: Identify the known values:
Current (I) = 6 amperes
Time (t) = 12 seconds
Step 2: Calculate the charge using the formula:
Q = I * t
Step 3: Substitute the known values into the formula:
Q = 6 amperes * 12 seconds
Q = 72 coulombs
Therefore, the total charge that passes through the light bulb during the given time is 72 coulombs.
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When you measured the mass of the cylinders,
what value could you determine if you had
measured the volume also?
Answer:
Density
Explanation:
As the density equal mass ÷ volume
Answer:
Density
Explanation:
Density is the mass of a given volume of substance;
The formula is:
Density = mass/volume
If you have mass and volume, you can therefore calculate density
If the distance between the first order maximum and the tenth order maximum of a double-slit pattern is 18 mm and the slits are separated by 0.15 mm with the screen 50 cm from the slits, what is the wavelength of the light used
Answer:
Wavelength of light is 600 nm
Explanation:
Given
Distance between the first order maximum and the tenth order maximum of a double-slit pattern = 18 mm
Separation between the slits = 0.15 mm
Distance of screen from the slits = 50 cm
Wavelength
\(= \frac{18*10^{-3} * 0.15 *10^{-3}}{0.50*9} \\= 6 *10^{-7}\\= 600\)nm
A student pours a spoonful of dirt into a cup of water. The water and dirt are stirred together. The water turns a light brown color. Some dark pieces float to the top of the cup and another dark layer forms on the bottom of the cup. Which statement BEST describes the contents of the cup?
The statement that is correct is that the contents of the cup form a mixture.
What is the nature of the cup?Though the question is incomplete but I would try to give you a good explanation as much as I can. We must recall that when we talk about a mixture, we have to note that the term mixture would refer to the combination of two or more substances that do not chemically react together.
In this case, we have been told that we have a water that was pure and then we add dirt to it. It is clear that the water and the dirt do not react in any way hence what we have formed is a mixture.
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A radio-controlled car powered by an electric motor accelerates from rest to 0.800 m/s in 23.0 ms. The total mass of the car is 675 g. What is the average power (in W) delivered to the car by the motor during its acceleration
Answer:
9.39Watts
Explanation:
The work done by the car is converted to kinetic energy. Hence;
Work done = Kinetic energy =1/2mv²
Time t = 23ms =23×10^-3s
Mass = 675g = 0.675kg
v = 0.8m/s
Work done = 1/2(0.675)0.8²
Work done = 0.216Joules
Average power = Work done/Time
Average power = 0.216/0.023
Average power = 9.39Watts
Hence the average power (in W) delivered to the car by the motor during its acceleration is 9.39Watts
1. It is important to make your own decisions. At the same time, it is good to ask for help. Identify a
situation where you absolutely need to be thinking for yourself and one in which turning to others
is best when it comes to making decisions about your health.
Answer:
Explanation:
Decision making is the process of making choices and it is important for a person to make their own decisions in life as it makes them accountable for the choices they made.
What is decision making?
Decision making is the process of making your own choices by identifying a decision, gathering the information, and assessing alternative resolutions for the decision.
Each person has the right to make their own decisions and have choices about how they live their life in their own way. Each person has different ideas about what is important and what makes them feel best in life. Making own choices about things in life is very important because it gives the life meaning.
Being responsible in making own decisions means being accountable, taking charge of the course of the actions and the consequences of choices, however it is also important to turn to others in cases of making decisions about health as this helps in making the best decision by understanding things from other perspectives.
The helium-filled balloons below are carrying negative electric charges, as shown. Attach two of the balloons to the hooks below to show what would happen if a red balloon and a blue balloon were brought near each other. Plzz help
Answer:
these are in the hooks the balloons repel each other if the hooks are isolated.
Explanation:
In electrostatics, charges of the same sign repel and of a different sign attract each other.
With this explanation we analyze the situation presented, they indicate that the balloons have a negative taste, so when these are in the hooks the balloons repel each other if the hooks are isolated.
If the hooks are connected to Earth, the poop of the balloons is neutralized, so there is neither attraction nor repulsion.
Answer:
Here you go : )
Explanation: