In order to enter class D airspace VFR, what minimum ceiling and visibility must exist?

Answers

Answer 1

In order to enter class D airspace VFR, the minimum ceiling must be 1,000 feet AGL and the visibility must be at least 3 statute miles.

These requirements ensure that pilots have sufficient visual cues and enough time to react to other aircraft and potential obstacles while operating in this airspace. It is important for pilots to adhere to these minimum requirements and to continually monitor weather conditions to ensure safe operations. Failure to comply with these regulations can result in enforcement action and potential safety hazards.

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Related Questions

Application: Assume a small
spacecraft is in open space.
One panel is a dedicated
radiator (dimensions in
image) and is painted with
S13 GLO white paint
(emissivity = .89). If the
radiator is at 30C and has a
full view factor to space, how
much heat can it reject from
the system? (How much is
this radiator radiating to
space?). Use 3K for space
temperature. Round answer
up to one decimal place. No
need to include units.
*.../2
1 m
Radiator
.3 m

Answers

The amount of radiation that the system is radiating into space is 1.164 x 10¹⁷. See the explanation below.

What is radiation?

Rockets or space crafts emit heat as they navigate into space. This heat or emissions is what is referred to as radiation.

What is the calculation supporting the answer above?

Recall that we are given the following:

Space temperature is T₂ = 3KRadiator Temperature = 30°CEmissivity = 0.89

Thus,

Converting the temperature of the Radiator, we have:

30°C = 273 + 30

= 303K

Area of the Panel of the radiator = 0.3 x 0.1

= 0.03

The formula for the heat emitted by the system is given as:

Q = ∈δA (T₁⁴  - T₁⁴)

Where:

δ = Stefan - Bolta Mann constant

→ δ = 5.67 X 10⁻ⁿ

→ The amount of heat is thus given as:

Q = 0.89 x 5.17 x 10⁸ [ (303)⁴ - (3)⁴] x 0.03

Therefore,

Q = 1.1635158780036 × 10¹⁷

Q ≈ 1.164 x 10¹⁷

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FILL IN THE BLANK. by early 1818 karl friedrich schinkel had produced a new design for the in berlin to sit atop the old foundations between existing french and german churches.

Answers

By early 1818 Karl Friedrich Schinkel had produced a new design for the Altes Museum in berlin to sit atop the old foundations between existing french and german churches.

What do you mean by design template?

Customizable pre-made designs and documents are known as design templates. Templates are frequently created to adhere to strict guidelines or specifications in order to maintain consistency across users and media. You have the option of creating bespoke templates for later use or using pre-design templates from libraries and websites.

Design templates include color palettes, master slides and titles with personalized formatting, and styled fonts created for a specific "look." The slide master and color scheme of the new template is substituted for those of the previous presentation when a design template is applied to a presentation.

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1. When choosing a respirator for your job, you must conduct a
test.
A) Weight
B) Practice
Co Fit
haz
D) Breathing

Answers

Answer:

D

Explanation:

Patient monitor is one of the important medical equipment in hospital. It measures vital signs
of a patient such as ECG, blood pressure, breathing and body temperature. However, due to the
Covid19 crisis, the number of patient monitor is not enough. Your team are required to develop
an ad-hoc prototype 6 channel ECG device by using ATMega328 microcontroller.The device
must fulfill the specifications below:-
i. Six channel ECG consisting of three limb leads and three augmented limb leads. The
gain of the entire biopotential amplifier is 2000, considering typical ECG voltage of
1.0 mV
ii. The ADC values of each ECG channel are going to be stored in the entire SRAM in the
ATMega328, before being displayed to the OLED display. After 5 seconds, the next
ECG channel will be sampled. When all six channels are completed, it will repeat with
the first channel.
iii. Sampling rate per channel must be set to 256 samples per second, and using the internal
oscillator clock set at 8 MHz.
a) Based on the specifications above, freely sketch the schematic diagram which connects
the singel chip microprocessor ATMega328, to the six channel biopotential amplier.
Ensure pin numbers and labels are clearly state and as detailed as possible. Notes: You could refer to ATMega328 Detail Pins Layout in Appendix 1 and only draw
the necessary I/O pins for system peripheral connection, including VCC and GND. You
can choose to connect the non-reserved pins to any digital I/O pins.
b) The device will sample a single ECG channel for a certain time, and store in the internal
SRAM. With 10-bit precision, how many seconds of a the ECG signal can be recorded in
the internal SRAM. Write and show all parameters involved to calculate the time.
c) Write the C program of the main function and the other required functions for the system
with the given specifications in (i), (ii) and (iii). A function named SRAMtoOLED( ) is
already provided. This function will read all the value in the SRAM and display on to the
OLED display. You can call this function when ever needed.

Answers

Schematic diagram which connects the single chip microprocessor ATMega328, to the six-channel biopotential amplifier is given below: Explanation.

The six-channel biopotential amplifier is connected to the ATMega328 through analog pins. Here, six different ECG leads will be connected to the amplifier and amplified by a gain of 2000. ADC is used to store the ECG signals and the analog values are converted to digital values by using ADC. The conversion is done based on the ADC reference voltage.

The digital values are stored in the SRAM and then displayed to the OLED display.b) The device will sample a single ECG channel for a certain time, and store it in the internal SRAM. With 10-bit precision, the maximum voltage that can be measured by ADC is 5V. Hence, the voltage resolution of ADC is 5/1024 = 0.0049 V.

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Compute the volume percent of graphite, VGr, in a 3.9 wt% C cast iron, assuming that all the carbon exists as the graphite phase. Assume densities of 7.9 and 2.3 g/cm3 for ferrite and graphite, respectively.

Answers

Answer:

Vgr = 0.122 = 12.2 vol %

Explanation:

Density of ferrite = 7.9 g/cm^3

Density of graphite = 2.3 g/cm^3

compute the volume percent of graphite

for a 3.9 wt% cast Iron

W∝ =  (100 - 3.9) / ( 100 -0 ) = 0.961

Wgr = ( 3.9 - 0 ) / ( 100 - 0 ) = 0.039

Next convert the weight fraction to volume fraction using the equation attached below

Vgr = 0.122 = 12.2 vol %

Compute the volume percent of graphite, VGr, in a 3.9 wt% C cast iron, assuming that all the carbon exists

For the accident of Gulf of Mexico Oil Spill, British Petroleum took the following steps to pay for the serious consequences (i=7% per quarter). Pay $3 billion at the end of the third quarter of 2010 and another $2 billion at the end of the fourth quarter of 2010. Make payments of $1.25 billion each quarter thereafter until a total of $20 billion (the total $20 billion includes the payments in 2010). a) Develop a cash flow diagram. b) What is the equivalent present value at the beginning of the third quarter of 2010? c) What is the equivalent present value at the beginning of the first quarter of 2010? d) What is the equivalent future value at the end of 2013?

Answers

a) Cash Flow Diagram:

```

           |------> $3 billion ------>|

           |                          |

           |------> $2 billion ------>|

           |                          |

$1.25 billion |------> $1.25 billion -->|

  per quarter|       per quarter       |

           |                          |

           |------> $1.25 billion -->|

           |       per quarter       |

           |                          |

           |       ... (repeated)     |

           |                          |

           |------> $1.25 billion -->|

           |       per quarter       |

```

b) To calculate the equivalent present value at the beginning of the third quarter of 2010, we need to discount each cash flow to its present value using the given interest rate of 7% per quarter. The present values are then added together.

c) To calculate the equivalent present value at the beginning of the first quarter of 2010, we need to discount each cash flow to its present value using the given interest rate of 7% per quarter. However, since the cash flows start from the third quarter of 2010, we need to discount the first two quarters' payments to their present value as well. The present values are then added together.

d) To calculate the equivalent future value at the end of 2013, we need to find the future value of each cash flow using the given interest rate of 7% per quarter. The present values are then added together.

e) Calculations for parts b, c, and d. However, by applying appropriate discounting or compounding formulas based on the given interest rate, you can determine the equivalent present or future values at specific time points.

To analyze the cash flow associated with the Gulf of Mexico Oil Spill, we can create a cash flow diagram. Each arrow represents a cash flow, and the time periods are indicated below each arrow. The diagram shows the cash inflows and outflows over time.

a) Cash Flow Diagram:

```

           |------> $3 billion ------>|

           |                          |

           |------> $2 billion ------>|

           |                          |

$1.25 billion |------> $1.25 billion -->|

  per quarter|       per quarter       |

           |                          |

           |------> $1.25 billion -->|

           |       per quarter       |

           |                          |

           |       ... (repeated)     |

           |                          |

           |------> $1.25 billion -->|

           |       per quarter       |

```

b) To calculate the equivalent present value at the beginning of the third quarter of 2010, we need to discount each cash flow to its present value using the given interest rate of 7% per quarter. The present values are then added together.

c) To calculate the equivalent present value at the beginning of the first quarter of 2010, we need to discount each cash flow to its present value using the given interest rate of 7% per quarter. However, since the cash flows start from the third quarter of 2010, we need to discount the first two quarters' payments to their present value as well. The present values are then added together.

d) To calculate the equivalent future value at the end of 2013, we need to find the future value of each cash flow using the given interest rate of 7% per quarter. The present values are then added together.

e) Calculations for parts b, c, and d. However, by applying appropriate discounting or compounding formulas based on the given interest rate, you can determine the equivalent present or future values at specific time points.

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write $\frac 15 \left(\frac 15\right)^2 \left(\frac 15\right)^3 \left(\frac 15\right)^4$ as a decimal.

Answers

In order to write the given expression as a decimal, we can simplify the expression and then evaluate it.

The given expression can be simplified as follows:$$
\begin{aligned}
\(\frac 15 \left(\frac 15\right)^2 \left(\frac 15\right)^3 \left(\frac 15\right)^4 &= \frac{1}{5^1} \cdot \frac{1}{5^2} \cdot \frac{1}{5^3} \cdot \frac{1}{5^4}\\\)
\(&= \frac{1}{5^{1+2+3+4}}\\\)
\(&= \frac{1}{5^{1+2+3+4}}\\\)
\(&= \frac{1}{9,765,625}\)
\end{aligned}
$$Now, we can evaluate the given expression by dividing 1 by 9,765,625 as follows:$$
\begin{aligned}
\(\frac{1}{9,765,625} &= \frac{1}{10,000,000 - 234,375}\\\)
\(&= 0.\overline{000}1\\&= 1 \cdot 10^{-7}\)
\(\end{aligned}$$Therefore, $\frac 15 \left(\frac 15\right)^2 \left(\frac 15\right)^3 \left(\frac 15\right)^4$ as a decimal is $1 \cdot 10^{-7}$\), which means that the decimal is a very small number.

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the process of examining an adverse event or incident and determining whether it constitutes an actual disaster is known as _____.

Answers

The process of examining an adverse event or incident and determining whether it constitutes an actual disaster is known as disaster assessment.

Disaster assessment refers to the process of evaluating and analyzing the impact, extent, and severity of a disaster or adverse event. It involves collecting data, conducting surveys, and performing on-site evaluations to assess the damage, needs, and vulnerabilities of the affected area or population. The main objectives of disaster assessment are to determine the magnitude of the disaster, identify the immediate and long-term needs of the affected communities, prioritize response and recovery efforts, and provide accurate information for decision-making and resource allocation. The assessment covers various aspects such as infrastructure damage, casualties, health and safety risks, availability of basic services, and socioeconomic impacts. The information gathered during the assessment helps authorities, emergency responders, and humanitarian organizations to develop effective strategies and interventions to support the affected communities and facilitate the recovery process.

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A steam power plant is represented as a heat engine operating between two thermal reservoirs at 800 K and 300 K. The temperature of the steam in the boiler is 550 K and the temperature of the saturated water in the condenser is 330 K. The rates of heat transfer in the boiler and condenser are 4 MW and 2 MW, respectively. Please answer the following.

Required:
a. Represent the devices present in the heat engine and include their name along with the data given in the problem.
b. If this steam power plant were to operate as a reversible heat engine, with the boiler and condenser temperatures, what would be its thermal efficiency?
c. Use your result from part (b) to determine if the actual steam power plant can achieve such thermal efficiency. Justify your answer.
d. For the actual steam power plant is the Clausius inequality satisfied? Show you computation and discuss whether your result agrees or disagrees with your answer in part (c).

Answers

Yeet is the answer .....

A demand factor of _____ percent applies to a multifamily dwelling with ten units if the optional calculation method is used.

Answers

Answer: A demand factor of 43 percent applies to a multifamily dwelling with ten units of the optional calculation method is used.

If side A has a length of 18.5 ft and side B has a length of 28 ft, what is the length of the hypotenuse?

Answers

Answer:

the answer should be about 33.56fts

The length of the hypotenuse will be 33.55 feet in the given triangle.

What is Pythagoras's theorem?

Pythagoras's theorem states that in a right-angled triangle, the square of one side is equal to the sum of the squares of the other two sides.

The triangle given in the question is a right triangle.

In a triangle side A has a length of 18.5 ft and side B has a length of 28 ft

A right triangle is represented as a triangle in which one angle is a right angle or two sides are perpendicular.

To determine the length of the hypotenuse.

According to Pythagoras's theorem,

a² + b² = c²

Here a = 18.5 and b = 28

The length of the hypotenuse is c.

(18.5)² + (28)² =  c²

342.25 + 784 = c²

c² = 1126.25

c = 33.55

Therefore, the length of the hypotenuse will be 33.55 feet.

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The radiation meter is showing radiation 2x as much as background. Is this a hot zone? If so why or why not?

Answers

Answer:

This is not a clear indication of the hot zone as the information of the radioactivity of the background is not provided clearly.

Explanation:

According to IAEA as well as NRCP, the hot area is defined on the basis of the radioactivity reading it shows instead of contrast or comparative reading from the background. The value of radiation activity which will be required to declare an area as hot zone is if it is greater than 0.1 mSv/h or \(1.5091\times 10^{29} kg^{-1} s^{-1}\).

What are the four scanning systems as per biomedical engineering​

Answers

Answer:

- Ultrasound scanning system

- Magnetic Resonance Imaging (MRI)

- Computed tomography (CT)

- X - Ray scan

Explanation:

\(.\)

Answer:

- USS Ultarsound

- Medical sonography

Two previously undeformed cylindrical specimens of an alloy are to be strain hardened by reducing their cross-sectional areas (while maintaining their circular cross sections). For one specimen, the initial and deformed radii are 15 mm and 12 mm, respectively. The second specimen, with an initial radius of 11 mm, must have the same deformed hardness as the first specimen.Compute the second specimen's radius after deformation.

Answers

Answer:

Explanation:

Two previously undeformed cylindrical specimens of an alloy are to be strain hardened by reducing their cross-sectional areas (while maintaining their circular cross sections). For one specimen, the initial and deformed radii are 15 mm and 12 mm, respectively. The second specimen, with an initial radius of 11 mm, must have the same deformed hardness as the first specimen.Compute the second specimen's radius after deformation.

The percentage of cold work to be done to deform the two cylindrical is calculated

\(\% CW=\frac{A_o-A_d}{A_o} \times100\\\\=\frac{\pi r_o^2-\pi r^2_d}{r_o^2} \times100\)

we input the values

\(=\frac{15^2-12^2}{15^2} \times 100\\\\=\frac{225-144}{225} \times100\\\\=\frac{81}{225} \times 100\\\\=36 \%\)

We can now calculate the deformed radius of the second specimen for the same deformation

\(r_2=r_o\sqrt{1-\frac{\% CW}{100} }\\\\=11\sqrt{1-\frac{36}{100} } \\\\=11\sqrt{1-0.36} \\\\=11\sqrt{0.64} \\\\=11\times0.8\\\\=8.8mm\)

Which technical practice incorporates build-time identification of security vulnerabilities in the code?

Answers

Technical practice incorporates build-time identification of security vulnerabilities in the code is  Penetration testing.

What is Penetrating Testing?

A penetration test, sometimes referred to as a pen test or ethical hacking, is a legitimate simulated cyberattack on a computer system that is carried out to analyze the system's security. This is distinct from a vulnerability assessment.

In order to identify and illustrate the financial effects of a system's vulnerabilities, penetration testers employ the same tools, strategies, and procedures as attackers. Reconnaissance, scanning, vulnerability assessment, exploitation, and reporting are the five stages of a penetration test.

Penetration testing is a technical activity that includes build-time discovery of security vulnerabilities in the code.

Penetration tests are essential to an organization's security because they teach staff members how to respond to any kind of intrusion from a malicious party. Pen tests are a method of determining whether a company's security procedures are actually effective.

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All steam traps will prevent steam from passing through them but will allow what to pass through them?

Answers

All steam traps are designed to prevent steam from escaping into the atmosphere or condensate from flowing back into the steam system.

They are used in steam systems to remove condensate and maintain steam pressure, which ensures efficient operation of the system. Steam traps allow only condensate or water to pass through them, while blocking steam from passing through. They operate on the principle of temperature difference, using a valve or float to control the flow of condensate. A well-functioning steam trap is essential to the proper operation of a steam system, as it helps to prevent energy losses and equipment damage. Therefore, it is important to regularly inspect and maintain steam traps to ensure their proper functioning.

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Which of the following applications could be used to run a website from a server? a. Hypertext Transfer Protocol b. FileZilla c. Microsoft Exchange Server d. Ngnix​

Answers

A software application that could be used to run a website from a server is: d. Ngnix​.

What is a server?

A server can be defined as a specialized computer system that is typically designed and configured to store and provide specific remote services for its clients (end users), especially on a request basis.

Types of server.

In Computer and Technology, there are different types of server and these include:

Print serverProxy serverApplication serverFile serverWeb server

Ngnix​ refers to a web server that is designed and developed on the 4th October, 2004, in order to avail its clients (end users) to run a website from a server for maximum performance and stability.

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In what way do the 2-4-12 second visual leads apply?

Answers

The 2-4-12 second visual leads explain the time duration for delivering vital information in a movie or presentation, with 2 seconds for attention-getting, 4 seconds for the main message, and 12 seconds for details.

What are the visual leads at two, four, and twelve seconds?

These three "lead times" are conceivable. the 4-second immediate path, the 12-second predicted path, and the 2-second following distance. The 2-second following distance serves as the beginning lead-time. When everything is perfect, that distance is regarded as the minimum.

The 12 second rule is what?

To avoid colliding with such things, the Department of Motor Vehicles recommends all motorists to adhere to a single regulation. It advises motorists to scan the road at least 12 seconds in advance.

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Help I need fast is it true or false

Help I need fast is it true or false

Answers

Answer:

False

Explanation:

It can only survive outside of the body for six days

To reduce the pressure in the fuel line the forklift operator should

Answers

Answer:

Shut off cylinder valve before turning off forklift.

Explanation:

To reduce the pressure in the fuel line, the forklift operator should keep the engine running with the garage door closed and sealed.

What is a forklift operator?

In warehouses and on construction sites, a forklift driver is in charge of delivering, moving, loading, and unloading a range of commodities.

Always release the pressure in the LPG lines before disconnecting while filling LPG tanks. To accomplish this, shut off the tank valve and let the engine run until the lines are completely empty.

Before opening the valve on the new tank, shut off the engine and make sure the LPG tanks are fastened to the forklift.

Therefore, the forklift driver should keep the engine running with the garage door closed and sealed in order to lower the pressure in the fuel line.

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Q1 [1 mark] The top of a formation of interest is at a depth of 6500 ft and the ROP of the drill bit is 310 ft/day. How long will it take to drill to the top of the formation? Q2 [1 mark] A density log shows that the bulk density of a formation is 2.30 g/cc. The density of the rock matrix is 2.62 g/cc and the density of the fluid in the formation is 0.869 g/cc. Calculate the porosity. Q3 [1 mark) We have a structure that is planned to be appraised in the year 2024. We think it might contain a STOTIP of 33 MMstb. Recovery factor is assumed to reach 42% achieved through a waterflooding project. Determine the proved oil reserves as of today. Q4 [1 mark) The reserves to production ratio of country is 99.3 and their annual production is 32 million stock tank barrels of oil. Determine the reserves available in this country. Q5 [1 mark] Calculate the oil formation volume factor given the reservoir volume is 388 million reservoir barrels and the surface volume of fluids is 318 million stock tank barrels.

Answers

Q1: It will take approximately 21 days to drill to the top of the formation (6500 ft ÷ 310 ft/day = 20.97 days).

Q2: The porosity can be calculated using the formula: porosity = (matrix density - bulk density) ÷ (matrix density - fluid density). Plugging in the given values, the porosity is (2.62 g/cc - 2.30 g/cc) ÷ (2.62 g/cc - 0.869 g/cc) = 0.29 or 29%.

Q3: The proved oil reserves as of today can be calculated using the formula: proved reserves = STOIIP x recovery factor. Plugging in the given values, the proved oil reserves as of today are 13.86 MMstb (33 MMstb x 0.42 = 13.86 MMstb).

Q4: The reserves available in the country can be calculated using the formula: reserves = reserves to production ratio x annual production. Plugging in the given values, the reserves available in the country are 3.17 billion stock tank barrels of oil (99.3 x 32 million stock tank barrels of oil = 3.17 billion stock tank barrels of oil).

Q5: The oil formation volume factor can be calculated using the formula: oil formation volume factor = reservoir volume ÷ surface volume of fluids. Plugging in the given values, the oil formation volume factor is 1.22 (388 million reservoir barrels ÷ 318 million stock tank barrels = 1.22).

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A customer complained that the front wheel would skip, hop, and shake while cornering and accelerating at the same time. technician a says that a fault in the transfer case is the most likely cause. technician b says that the vibration may be normal if the vehicle is equipped with cardan u-joints at the front wheels. which technician is correct

Answers

Technician B is correct and he is providing the correct guidance to the customer.

Why technician B is correct?

A faulty driveshaft, commonly found near the front wheels, can make the vehicle difficult to control. This faulty drive shaft can be the result of worn U-joints or bushings. This can cause the drive shaft to vibrate when attempting to turn or accelerate.

What are U-joints?

The part that connects the drive shaft to the differential and sometimes connects the drive shaft to the transmission or two drive shafts to each other is called U-Joints and breaking of u- joints is known as bushing.

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normally counters are retentive. this means that if your accumulated count is up to 300 and power to your system is lost, when power is restored the a

Answers

The correct answer is when retentive power is restored the accumulated count will be 300.

PLC counters are normally retentive; that is, whatever count was contained in the counter at the time of a proces- sor shutdown will be restored to the counter on power-up. The counter may be reset, however, if the reset condition is activated at the time of power restoration.A counter instruction is an input instruction. A counter's input signal can come from an external device such as a sensor. Up and down counters may be programmed together to count up and down. Counters can count past their preset values.

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What steps should be taken to evaluate the team member's level of competence What method did you use to resolve this problem if you somehow didn't receive the desired expertise?

Answers

The steps that should be taken to evaluate the team member's level of competence are:

A self assessment testAn assessor kind of review. Know development needs. An on as well as off job learning.Put the team In Real scenario.Ask for any form of Clients' Feedback.

The method that I will use to resolve this problem if you somehow didn't receive the desired expertise is to ask a person from my team to teach me how to do it as well as consult external people or the internet.

Why is team competence crucial?

Long used as a framework, competencies help direct employees' behavior toward the issues that are most important to an organization and contribute to success.

Therefore, They can offer a standard method to coordinate, pick out, and nurture talent. For workers, as well as managers, and ultimately the organization, the advantages are obvious.

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1. Asbestos can be dangerous but is not a known carcinogen.
A) O True
B) O False

Answers

Asbestos may cause cancer by inhalation. Moreover, asbestos is also known to cause different respiratory diseases (especially asbestosis) by affecting the mucosa of the bronchi.

The statement "Asbestos can be dangerous but is not a known carcinogen" is FALSE.

Asbestos is a group of materials that were widely used in building constructions until 1990.

Asbestos is a toxic substance that may cause mesothelioma and lung cancer.

Mesothelioma is a type of cancer that develops on the outer surface that covers different internal organs.

Moreover, asbestosis is a chronic disease in the lungs caused by long-term exposure to asbestos.

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Answer:

False

Explanation:

What is not a condition under which the malfunction indicator light or service engine light is turned off ?

Answers

The malfunction indicator light or service engine light is not switched off when the Powertrain Control Module Link is grounded.

A power-train control module (PCM), sometimes known as a control unit, is a motor vehicle component. The engine control unit (ECU) and transmission control unit are typically combined into one controller (TCU). On some vehicles, including many Chryslers, there are three different computers: the PCM, the TCU, and the Body Control Module (BCM). In general, these car computers are very dependable. In a car or truck, the PCM frequently regulates more than 100 variables. There are hundreds of different error codes that may appear and signify that a specific component of the car isn't working properly. The "check engine" light on the dashboard typically illuminates when one of these errors occurs.

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The department of transportation regulations require which parameter to be recorded on the shipping paper for hazard class 2.2 nonflammable compressed gases?

Answers

The  shipping paper for hazard class 2.2 nonflammable compressed gases is for the Number of cylinders of each gas.

What are the hazard classes?

They are:

Class 1: Explosives.Class 2: Gases.Class 3: Flammable and Combustible Liquids.Class 4: Flammable Solids.

The classes of hazard are often made so that people will recognize them and follow the right steps so as to avoid those hazards.

Therefore,  The  shipping paper for hazard class 2.2 nonflammable compressed gases is for the Number of cylinders of each gas.

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Convenience items like liquid egg are a lot more expensive?
True
Or False

Answers

It’s true because convenience stores are more expensive so that means overall the items would be more expensive.

Answer:

True

Explanation:

It's just because of the processing

In a parallel circuit, as more resistances are added, what happens to the total circuit current?

Answers

Answer:

the equivalent resistance of the circuit decreases and the total current of the circuit increases. 

Explanation:

hope this helps

What kind of routing protocol adjusts over time to the network topology?
1. Ping
2. Route table
3. Static
4. Dynamic

Answers

The kind of routing protocol that adjusts over time to the network topology is Dynamic.
Dynamic routing protocols, such as OSPF and BGP, automatically adjust to changes in the network topology. They use complex algorithms to determine the best path for data to travel and update routing tables accordingly.

This allows for more efficient and reliable communication within the network. In contrast, static routing protocols require manual configuration and do not automatically adjust to changes in the network topology. Ping and route table are not routing protocols, but rather tools used to test network connectivity and view routing information, respectively.

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