In terms of the four forces acting on an airplane, what needs to happen so the forces are balanced? what do we call it when all four forces are balanced on an airplane?

The magnitude of the acceleration that the engine must produce is  0.065 m/s².

Acceleration is given by the ratio of Resultant or total force acting on any object and the its mass.

It can also be defined as the rate change of velocity with time.

acceleration a = (Δv) / (Δt)

Given is a lunar probe is moving 1670 m/s at a 73° angle. it needs to land on the moon  3.71 x 10⁸ m away in a 46° direction in 8.64 x 10⁴ s.

The initial velocity will be

1670 x cos (73°-46°) = 1487.981 m/s

Using the second equation of motion, we have

s = ut + 1/2 at²

The final velocity will be zero after landing on Moon.

Substituting the values, we have

3.71 x 10⁸=  1487.981 x  8.64 x 10⁴ + 1/2 a ( 8.64 x 10⁴)²

Solving the equation, we get

acceleration, a = 0.065 m/s²

Thus, the magnitude of the acceleration that the engine must produce is   0.065 m/s²

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Answer:

The direction is 30.6

Explanation:

The work done on the object by the applied force is 1500 J, and the power developed is 8000 W.

The torque produced by the force can be determined by multiplying the force by the moment arm. This can be represented using the formula:Torque = Force × Moment armGiven that a force of 9 N is applied to an object with a moment arm of 0.21 m, the torque produced by the force can be calculated as follows:Torque = 9 N × 0.21 m= 1.89 N·mTherefore, the torque produced by the force is 1.89 N·m.Answer in 200 words.Torque is the tendency of a force to rotate an object around an axis or pivot. The torque produced by a force is proportional to the force applied and the moment arm.The moment arm is the shortest distance between the line of action of the force and the axis of rotation. It is the perpendicular distance from the axis of rotation to the line of action of the force. The moment arm is an important factor in determining the torque produced by a force.A torque of 1 N·m is produced when a force of 1 N is applied perpendicular to a moment arm of 1 m. This is known as the moment of force or the turning effect of a force.The torque produced by a force is measured in newton-metres (N·m) in the SI system of units. In order to calculate the torque produced by a force, the magnitude of the force and the moment arm need to be known.The formula for calculating the torque produced by a force is:Torque = Force × Moment armWhere torque is measured in N·m, force is measured in newtons (N), and moment arm is measured in metres (m).

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A 4.0-L balloon at 300 K is placed in a cooler at 245 K; the volume of the balloon after it has been in the cooler is 3.27 L, and the formulas are PV = nRT, which is an ideal gas law formula, and then by using V1/T1 = V2/T2, the answer is derived.

PV = nRT

(P = pressure, V = volume, n = number of moles of gas, R = ideal gas constant, T = temperature)

Suppose, the number of moles and pressure remain constant,

V1/T1 = V2/T2

(V1 = initial volume, T1 = initial temperature, V2 = final volume, T2 = final temperature)

After putting values,

V2 = (V1 x T2) / T1

V2 = (4.0 L x 245 K) / 300 K

V2 = 3.27 L

Hence, the volume of the balloon after it has been in the cooler is 3.27 L, and the formulas are PV = nRT, which is an ideal gas law formula.

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Answer:

True

Explanation:

I did this on a test and got it right, I swear

Ionizing smoke detectors contain an isotope that undergoes alpha decay (such as americium-241) because alpha particles are more ionizing than beta or gamma particles.

What is Isotopes?

Isotopes are variants of an element that have the same number of protons in their atomic nuclei but differ in the number of neutrons. This means that isotopes of the same element have the same atomic number (which determines the element's chemical properties) but different atomic masses.

In an ionizing smoke detector, the alpha particles emitted by the radioactive source ionize the air in the detector's chamber, creating a current that is detected by a circuit. When smoke particles enter the chamber, they attach to the ions and reduce the current, triggering the detector's alarm.

Alpha particles are heavier and have a higher charge than beta or gamma particles, which means they interact more strongly with matter and create more ionization as they travel through air. This makes them more effective at ionizing the air in the detector's chamber, and therefore more sensitive to the presence of smoke particles.

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Answer:

The average speed is \(v = 1260 \ km/s\)

The average speed is different from the average velocity in this question

Explanation:

From the question we are told that

   The equatorial  radius of Jupiter is  \(R_j = 7.1*10^{4} \ km\)

   The period of oscillation of Jupiter is \(T_J = 9 \ hours , 50 \ min = 35400 \ seconds\)

Generally the average speed is mathematically represented as

      \(v = \frac{2 \pi * R_j }{T_J}\)

=>   \(v = \frac{2 *3.142 * 7.1*10^{4} }{35400}\)

=>   \(v = 1260 \ km/s\)

Generally in average speed the direction is not considered while in average velocity the direction is considered for the  case of this question the movement equitorial point has no direction in that it start from one point and after its periodic motion it still remains at that point

The internal resistance of a 12V car battery whose terminal voltage drops to 8.4V when the starter draws 95 A is 0.31 Ohm and the Resistance of the starter is 0.08 Ohm

A battery is an electronic device that transforms chemical energy into electrical energy. The voltage of a battery is the potential difference between its terminals. The terminal voltage of a battery is determined by the external resistance to which it is connected and the internal resistance of the battery.

When a battery is connected to a load, its voltage falls. This voltage drop is caused by the internal resistance of the battery. Battery terminal voltage (V) = Internal resistance (r) x Current (I) + Terminal voltage of the battery (V)

Let the internal resistance of the battery be r and its terminal voltage be V. Let I be the current flowing through the battery. When the starter draws 95A, the terminal voltage of the battery drops to 8.4V.

Substituting the given values in the above formula we get 8.4 = r × 95 + 12

Where r is the internal resistance of the battery.

Therefore, r = (8.4 - 12)/95= 0.31 Ohm

The current passing through the starter is given as 95A. The voltage drop across the starter can be found by subtracting the voltage at the end of the starter from the voltage at the beginning of the starter. This voltage drop is caused by the resistance of the starter.

Voltage drop across the starter = Voltage at the beginning of the starter - Voltage at the end of the starter

V = 12 - 8.4V= 3.6V

Resistance of the starter, R = V / I = 3.6 / 95 = 0.08 Ohm.

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Answer:

Below

Explanation:

135 lbs  *  1 kg/2.2 lb  = ~ 61.4 kg

there are 1000 mg in each gram

5.3 mg   *  1 gm / 1000 mg = .0053 g

If the burner is on for 125 seconds with a power rating of 1000 watts, then 125000 joules of energy are used.

We need to know the power rating of the burner to calculate the energy used. Let's assume the power rating of the burner is 1000 watts.

Power = 1000 watts

Time = 125 seconds

Energy = Power x Time

Energy = 1000 watts x 125 seconds

Energy = 125000 joules.

Energy is a fundamental concept in physics and is typically measured in joules (J). The joule (J) is the SI unit of energy and is defined as the amount of energy transferred or work done when a force of one newton acts on an object to move it one meter in the direction of the force.

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The isotropic form of Hooke's law relating stress to strain in ij notation and matrix form is:

σ_ij = C_ijkl * ε_kl

Hooke's law is a fundamental concept in solid mechanics that describes the linear relationship between stress and strain in an elastic material. In the isotropic form, stress (σ) and strain (ε) are represented using tensor notation, where the subscripts i and j denote the components of stress or strain along different directions.

The equation is given as σ_ij = C_ijkl * ε_kl, where C_ijkl represents the elastic constants or stiffness coefficients. In this notation, the indices i, j, k, and l can take values from 1 to 3, representing the three spatial dimensions.

The elastic constants C_ijkl represent the material's response to applied stress and provide information about its mechanical properties. These constants define the material's stiffness and determine how it deforms under stress. The specific values of the elastic constants depend on the material being considered.

The elastic constants have physical meanings related to the material's properties. For example, the elastic constant C_1111 represents the material's Young's modulus, which measures its resistance to linear deformation. The constants C_1212 and C_1122 represent the shear modulus, reflecting the material's resistance to shear deformation.

Understanding the values and physical meanings of the elastic constants is crucial in characterizing the behavior of materials under stress. By determining the elastic constants experimentally or through theoretical modeling, engineers and scientists can predict and analyze the material's response to applied forces and design structures accordingly.

Hooke's law and the elastic constants play a vital role in various fields such as materials science, civil engineering, and mechanical engineering. By studying the relationship between stress and strain, researchers can analyze the behavior of materials under different loading conditions and make informed decisions about material selection, structural design, and performance optimization. The elastic constants provide essential information about the mechanical properties of materials, enabling the development of reliable and efficient structures and systems.

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Answer:

85.8 m/s

Explanation:

We know that the length of the circular path, L the plane travels is

L = rθ where r = radius of path and θ = angle covered

Now,its speed , v = dL/dt = drθ/dt = rdθ/dt + θdr/dt

where dθ/dt = ω = angular speed = v'/r where v' = maximum speed of plane and r = radius of circular path

Now, from θ = θ₀ + ωt where θ₀ = 0 rad, ω = angular speed  and t = time,

θ = θ₀ + ωt = 0 + ωt = ωt

So, v = rdθ/dt + θdr/dt

v = rω + ωtdr/dt

v = (r + tdr/dt)ω

v = (r + tdr/dt)v'/r

v = v' + tv'/r(dr/dt)

v = v'[1 + t(dr/dt)/r]

Given that v' = 110 m/s, t = 33.0s, r = 120 m and dr/dt = rate at which line is shortened = -0.80 m/s (negative since it is decreasing)

So, v = 110 m/s[1 + 33.0 s(-0.80 m/s)/120 m]

v = 110 m/s[1 + 11.0 s(-0.80 m/s)/40 m]

v = 110 m/s[1 + 11.0 s(-0.02/s)]

v = 110 m/s[1 - 0.22]

v = 110 m/s(0.78)

v = 85.8 m/s

The work done in lifting a 1000 N crate 3.0 m high is 3000 Joules (J).

Here, we have been told that the mass of the crate is = 1000 N (i)

We have to lift up the crate to a height of = 3.0 m (ii)

The mass of the crate is given here in Newtons which is also the SI unit of Force.

We know that work is the product of force and distance moved in the direction of the force. The formula used for calculating the work done is

= W = Force * Distance moved (iii)

Using the values of (i), (ii) and putting them in the given formula (iii), we get = W = (1000)*(3)

= W = 3000 Joules

Therefore, we know that the work done in lifting a crate of mass/force to a height of 3.0 m is 3000 J.

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Answer:

a) Answer: 0.16331 m/s

b) Answer: 8522.66 joules

Explanation:

The final speed is  0.1633 m/s.

When the freight car receives this scrap metal, 7915.72 Joule kinetic energy is lost.

A body has momentum while it is moving, according to our understanding. It is said that a body's momentum is equal to the sum of its mass and speed. A body's direction is important when discussing momentum. Its direction belongs to the body's direction of motion.

(a) Given parameter:

Mass of the railroad car, M = 2900 Kg.

Mass of the scrap metal, m= 11750 Kg.

Initial speed of the car, u = 0.0825 m/s.

Initial speed of the scrap metal = 0 m/s.

Final speed of the system, v = ?

Then, initial momentum of the  system = initial momentum of the car +  initial momentum of the scrap metal .

= (29000×0.825 + 117500×0) kg.m/s.

= 23925 kg.m/s.

Final momentum of the system = total mass of the system× final speed

= (29000 + 117500)× v kg.m/s

= 146500v kg.m/s.

Hence, from principle of conservation of momentum,

initial momentum of the  system = Final momentum of the system

⇒ 23925 = 146500v

⇒ v = 0.1633 m/s.

The final speed of the  loaded freight car is 0.1633 m/s.

(b) Lost in kinetic energy = initial kinetic energy of the car - final kinetic energy of the loaded car.

= 1/2*29000*0.825² -1/2*(29000 + 117500)* 0.1633² Joule.

= 7915.72 Joule.

Hence, 7915.72 Joule kinetic energy is lost in this process.

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After 3 seconds, the height of the object would be 447 feet.

To find the height of the object after a certain number of seconds, we can use the equation for the vertical motion of a projectile:

h(t) = -16t^2 + vt + h0

where h(t) is the height at time t, v is the initial velocity, and h0 is the initial height.

Given:

Initial velocity (v) = 192 feet per second

Initial height (h0) = 15 feet

Let's plug in these values into the equation:

h(t) = -16t^2 + 192t + 15

To find the height after a specific number of seconds (t), substitute the value of t into the equation and calculate the result.

For example, if we want to find the height after 3 seconds:

h(3) = -16(3)^2 + 192(3) + 15

Simplifying the equation:

h(3) = -16(9) + 576 + 15

    = -144 + 576 + 15

    = 447 feet

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The velocity with which the feather strikes the ground of the planet is 7.63 m/s and the acceleration due to gravity on the surface of the planet is 5.125 \(m/s^{2}\).

As from the surface of the planet, under acceleration due to it's gravity, the feather takes 1.49 seconds to reach the bottom-end when dropped into a 69m deep crater.

As the motion of the feather dropped would follow the freefall conditions, we should first know the basic equations of motion:

(Assuming u as the initial velocity, \(v\) as the final velocity, \(t\) as time, s as displacement and \(a\) as the acceleration due to gravity in the equations)

s = u\(t\) + 1/2 \(a\)\(t\)²       .......(i)

\(v\)² = u² + 2\(a\)s          .......(ii)

\(v\) = u + \(a\)\(t\)                .......(iii)

The sign convention should be followed according to the given data.

For the question, u = 0 since the feather is dropped

s = 5.69 m;

\(t\) = 1.49 s

Putting the values in equation (i)

5.69 = 1/2 a × 1.49 × 1.49

11.38 = a × 2.2201

a = 5.125 \(m/s^{2}\)

Hence, the acceleration due to gravity for the planet is 5.125 \(m/s^{2}\)

Now, putting the values of a and t in equation (iii), we get

\(v\) = 5.125 × 1.49

  = 7.63 m/s

Hence, the feather hits the bottom of the crater at the speed of 7.63 m/s.

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The correct question is:

An astronaut on planet with no atmosphere drops feather into a 5.69m deep crater and records that the feather falls freely for 1.49s. What is magnitude of free-fall acceleration on the planet? With what speed does the feather strike the bottom of the crater?

Answer:

A change of color, formation of bubbles, color change, formation of gas, change of temperature.

Explanation:

Answer:

Chemical reactions involve the chemical interaction of two or more chemical substances, result in a new substance being formed, and are usually irreversible. The signs of chemical reactions include gas formation, energy release in the form of light or flame, heat absorption, precipitate formation, and color change.

Explanation:

Sample Response

The correct answer is e. None of the above alternatives gives a true statement. None of the statements in options a, b, c, and d are true when it comes to a modulus M over a ring R having a finite basis.

When a modulus M can be formed entirely from a finite set of elements, the modulus M is said to be finitely generated. M's finite basis does not, however, automatically imply that M is finitely generated. A basis is a set of linearly independent elements, and it might not be enough to produce all of the components of the modulus.

According to the assertion in option b, M must include nonzero items of nonzero order if it has a finite basis. This is untrue, though. The smallest positive number k, such that the element raised to the power of k equals the identity element, is referred to as the order of an element.

According to option c, every non-null element in a modulus with a finite basis has a null. Nevertheless, this claim is likewise untrue. It is possible for a modulus with a finite basis to have non-null elements without a null element.

According to option d, a ring R is a body, or a field, and only then can a modulus have a finite basis. However, this assertion is also untrue. Even though the ring R is not a field, a modulus can nonetheless have a finite basis. None of the given alternatives provides a true statement about a modulus M over a ring R having a finite basis.

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To make the net gravitational force on particle A from particles B, C, and D zero, particle D should be placed at the x coordinate of -11 cm and the y coordinate of 0 cm.

The net gravitational force on particle A from particles B, C, and D can be calculated using the formula for gravitational force:

F = G * (m₁ * m₂) / r²

Where F is the gravitational force, G is the gravitational constant, m₁ and m₂ are the masses of the two particles, and r is the distance between them.

Since the net gravitational force on particle A should be zero, we can set up an equation:

FAB + FAC + FAD = 0

Using the given information that the distance d is 22 cm and the masses of particles B, C, and D are known in terms of mA, we can calculate the x and y coordinates for particle D.

By applying the principle of superposition, we can calculate the net gravitational force on particle A from particles B, C, and D at the x coordinate and y coordinate of particle D. By adjusting the position of particle D, we can find the coordinates that result in a net gravitational force of zero on particle A.

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Answer:

20 m/s = 44 mph

He will get moved more to earth or away

Explanation:

Answer:

They will get pulled to the earth or moved away

Explanation:

Answer:

the results increase, positive

Answer:

Solid state of matter

Answer:

C

Explanation:

The distance that the pig moves up will be less than the distance that the strongman pulls down.

Explanation: The strongman is further from the fulcrum than the pig is, so the distance that he pulls down will be greater than the distance that the pig moves up.

The distance that the pig moves up will be less than the distance that the strongman pulls down. Hence, option (C) is correct.

The given problem is based on the work done by the applied force. When some magnitude of force is applied on any object, then there will be some obvious displacement of object. This is known as work done by the object. The expression for the work done by the object is,

w = Fd

here, F is the applied force and d is the displacement.

In the given problem, the applied force will be due to the weight of man and pig. So, the modified form of work done is,

work = Wd

W = work/d

here, W is the weight.

Clearly, more the weight, less will be the displacement and vice versa. So due to heavy weight of man, he will pull the pig easily. Such that the upward distance covered by pig will be less than the distance that the strongman pulls down.

Thus, we can conclude that the distance that the pig moves up will be less than the distance that the strongman pulls down. Hence, option (C) is correct.

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It takes 30 minutes for Tony to get to school.

2100 divided by 70 is 30, which would represent the amount of minutes.

Also he is walking very fast to be getting 70 in a minute.

Hope this helps and have a nice day.

-R3TR0 Z3R0

For the first case, kinetic energy is 1/3 of the total at ±(√2/2)A displacement. For the second case, kinetic energy is 4/5 of the total at ±(√3/3)A displacement.


In SHM, the total mechanical energy is given by E = 1/2 k A^2, where k is the spring constant and A is the amplitude of the motion. The kinetic energy at any displacement x is given by K.E. = 1/2 k (A^2 - x^2).  

For the first case, equating K.E. to 1/3 of the total energy, we get 1/2 k (A^2 - x^2) = 1/6 k A^2. Solving for x, we get x = ±(√2/2)A. For the second case, equating K.E. to 4/5 of the total energy, we get 1/2 k (A^2 - x^2) = 4/5 k A^2. Solving for x, we get x = ±(√3/3)A. Therefore, at these displacements, the kinetic energy is equal to the specified fractions of the total mechanical energy.

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Answer:

50 N ---->

Explanation:

Opposing sides get subtracted so~

25-25 cancels out to zero so there is 0N

100 -50 equals 50 N ->

Along vertical direction, net force is 0N and along horizontal direction, the net force is 50N directed towards right.

To determine the answer, we need to know about how to calculate the net force.

To determine the net force along any direction, we have to sum all the forces that are directed along that direction.

Forces that directed along vertical direction are

Net force = 25 N (vertically upward) + 25 N (vertically downward)

                = 25 N - 25N = 0N

Here, we take '+ sign' for upward direction and '- sign' for downward direction.

Forces that directed along horizontal direction are

Net force= 100 N towards right + 50 N towards left

               = 100N - 50N

               = 50 N (towards right)

Here, we take '+ sign' for horizontally right direction and '- sign' for horizontally left direction.

Thus, we can conclude that 0 N is the net force along vertical direction and 50 N is the net force along horizontal direction.

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The maximum x-coordinate of the particle is 80 meters.

Given the particle's initial velocity of 40 m/s along the positive x-axis and an acceleration of 10 m/s² along the negative x-axis, we can determine the particle's position at t = 2s using kinematic equations.

First, we calculate the displacement of the particle using the equation:

Δx = v₀t + (1/2)at²

Substituting the given values, we have:

Δx = (40 m/s)(2s) + (1/2)(-10 m/s²)(2s)²

    = 80 m - 20 m

    = 60 m

Therefore, the position of the particle at t = 2s is 60 meters.

To find the maximum x-coordinate of the particle, we need to consider the point where the particle changes its direction. This occurs when the acceleration changes from negative to positive, which is when the particle comes to rest.

Using the equation:

v = v₀ + at

Substituting the given values and solving for v:

0 = 40 m/s + (-10 m/s²)t

10 m/s²t = 40 m/s

t = 4s

Now, we can calculate the position at t = 4s:

Δx = (40 m/s)(4s) + (1/2)(-10 m/s²)(4s)²

    = 160 m - 80 m

    = 80 m

Therefore, the maximum x-coordinate of the particle is 80 meters.

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Answer:

Friend will wait 5 minutes

Answer:

you're Friend will wait 5 minutes

Explanation:

a.)

Reactants : CO2 (carbondioxide) + H2O (water)

Products : O2 (oxygen) + C6H12O6 (glucose)

b.)

Reactants: Na ( Solid Hydrogen) + H2O (water)

Products: H2 (hydrogen gas) + NaOH (sodium hydroxide)