In the 1960 Olympics, Wilma Rudolph of the United States won the women's 100 meter run in 11.0 seconds. In 1988, Florence Griffith-Joyner, also of th
United States, won with a time of 10.49 seconds, which is still the fastest women's time to this date. Find the percent of decrease in the winning time.
Round to the nearest tenth.

As the number of degrees of freedom for a t-distribution increases, the difference between the t-distribution and the standard normal distribution (b) becomes smaller.

As the number of degrees of freedom for a t distribution increases, the difference between the t distribution and the standard normal distribution becomes smaller. This is because as the degrees of freedom increase, the t distribution approaches the normal distribution in shape and becomes more concentrated around the mean. Therefore, the t distribution becomes more similar to the standard normal distribution, which has a mean of 0 and a standard deviation of 1. So, the correct answer is b. becomes smaller.

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If radius of sphere B is 5times radius of sphere A, then ratio of volume of sphere B to volume of sphere A is 125 , the correct answer is (c) .

Let the radius of the sphere B = r₁ , and

Let the radius of the sphere A = r₂ ;

So , The ratio of the volume of sphere B to the volume of sphere A is written as :

⇒ (Volume of sphere B)/(Volume of sphere A) = (4/3)πr₁³/ (4/3)πr₂³ ;

Simplifying the expression,

We get ,

⇒ (Volume of sphere B)/(Volume of sphere A) = (r₁/r₂)³ ,

It is given that the radius of sphere B is 5 times the radius of sphere A, which means that , r₁ = 5r₂ ,

Substituting the radius in the expression above,

We get ,

⇒ (Volume of sphere B)/(Volume of sphere A) = (5r₂/r₂)³ = (5)³ = 125 ;

Therefore, the ratio of volume of sphere B to sphere A is (c) 125.

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The given question is incomplete , the complete question is

If the radius of sphere B is 5times the radius of sphere A, then the ratio of the volume of sphere B to the volume of sphere A is

Select one:

(a) 0.008

(b) 25

(c) 125

(d) 5

(e) 0.2

Correct option is D) and E)

(3,7π/6),(3,11π/6)

Point of intersection is the point where two lines or two curves meet each other.

The point of intersection of two lines of two curves is a point.

If two planes meet each other then the point of intersection is a line.

The term "point of intersection" refers to the intersection of two lines. The equations a1x+b1y+c1=0 and a2x+b2y+c2=0, respectively, are used to represent these two lines. The two lines' intersection point is shown in the following figure. The intersection of three or more lines can also be located.

let

5 + 4 sin(θ) = −6 sin(θ)

Then get

θ= -1/2

Then you can make it

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I understand that the question you are looking for is:

On the interval [0, 2π), which points are intersections of r = 5 4 sin(θ) and r = −6 sin(θ)? check all that apply.

A) -3,7/6

B) (-3,11/6)

C) (3,7/6)

D) (3,11/6)

Answer:

The airspeed is 201.17 mph and bearing is  and this can be determined by using the vector form of velocity

Plane to fly 700 miles due north in 3.5 hours if the wind is blowing from a direction of 338 degrees at 10 ​mph

Answer:

Hi

Please mark brainliest ❣️

Step-by-step explanation:

density= mass / volume

density= 160 / 100

density= 1.6

The number of 1-point shot is 19 and the number of 2-point shot is 37.

At a basketball game, a team made 56 successful shots. They were a combination of 1- and 2-point shots. The team scored 93 points in all.

Therefore, the system of equation to find the number of each type of shot can be found as follows:

Hence,

let

x = number of 1- point shots

y = number of 2- point shots

Therefore,

x + y = 56

x + 2y = 93

subtract the equations'

y = 93 - 56

y = 37

Therefore,

x = 56 - 37

x = 19

Therefore,

number of 1-points shot = 19

number of 2-point shot = 37

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The length of one edge of the tabletop is 4.89 feet.

We know that square is a shape that has all the side equal. Based on this using the formula to find the length of edge of the tabletop.

The area of square table is given by the formula -

Area of square table = side²

We will keep the value of area of square table to find the value of side which will be length of edge

24 = side²

Side = ✓24

Taking square root for the value on right side of the equation

Side = 4.89

Hence, the length of one edge of the tabletop is 4.89 feet.

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Answer:

B

Step-by-step explanation:

you gotta plug in the 3+h into the original equation so it will look like (3+h)^2+3(3+h)+5

And just go from there.

Answer:

1.66667

Step-by-step explanation:

using online slope calculater

Applying exponent properties, it is found that there are 2^9 = 512 bacteria after 120 minutes.

We keep the base and add the exponents.

This is what happens in this problem, when we multiply 2^6 by 2^3, as follows:

\(2^6 \times 2^3 = 2^{6 + 3} = 2^9 = 512\)

Hence, there are 512 bacteria after 120 minutes.

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Answer: First One.

Step-by-step explanation: The first and last options are acceptable, since a line of best fit needs to be as close to all the points as possible (ignoring any anomalies/outliers) but in an exam question the first line of best fit looks slightly better.

Supplementary angles are angles that sum up to 180 degrees

Step 1:

If m<x and m<y are supplementary, hence;

m<x + m<y = 180 ....................1

Step 2:

If m<y is a supplement to m<z, hence:

m<y + m<z = 180 ...........................2

Equating 1 and 2

m<x + m<y  = m<y + m<z

Subtract m<y from both sides

m<x + m<y-m<y  = m<y + m<z - m<y

m<x = m<z

This proves the statement m<x = m<z

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The 'x' coordinate is negative and 'y' coordinate is positive.

A fraction is a part of a whole. In arithmetic, the number is expressed as a quotient, in which the numerator is divided by the denominator. In a simple fraction, both are integers. A complex fraction has a fraction in the numerator or denominator. In a proper fraction, the numerator is less than the denominator.

We know that :

π = 180

Therefore,

3π/4 = (3×180)/4 = 3 × 45

3π/4 = 135

In second quadrant, we have negative value if x coordinate and positive value of y coordinate.

Hence, the angle lies in the second quadrant. Second quadrant is enclosed by the negative x axis and positive y axis.

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Answer:

x is negative, and y is positive.

Step-by-step explanation:

The answer above is correct.

Answer:

6 + 6 + 6 + 6= 24

Step-by-step explanation:

ad four sixes

Whave established that the series l~=l an - z converges uniformly for Re(z) ≤ c

What is uniformly?

The keyword "uniformly" refers to the concept of uniform convergence. In the context of the given question, it is stated that the series l~=l an - z converges uniformly for Re(z) ≤ c. Uniform convergence means that the convergence of the series is independent of the value of z within a certain range (Re(z) ≤ c in this case).

To show that the series l~=l an - z converges uniformly for Re(z) ≤ c, where an is a bounded sequence of complex numbers and we choose the principal branch of n - z, we need to demonstrate that for any ε > 0, there exists an N such that for all n > N and for all z with Re(z) ≤ c, the inequality |l~=l an - z| < ε holds.

Given that an is a bounded sequence, there exists an M > 0 such that |an| ≤ M for all n.

Let's consider the series l~=l an - z. We can write it as:

l~=l an - l z.

Now, since |an| ≤ M for all n, we have:

|an - z| ≤ |an| + |z| ≤ M + c.

By choosing N such that M + c < ε, we can ensure that for all n > N and for all z with Re(z) ≤ c, the inequality |an - z| < ε holds.

Now, using the triangle inequality, we have:

|l~=l an - z| ≤ |an - z|.

Since we have shown that |an - z| < ε for n > N and Re(z) ≤ c, it follows that |l~=l an - z| < ε for n > N and Re(z) ≤ c.

Therefore, we have established that the series l~=l an - z converges uniformly for Re(z) ≤ c.

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Answer:

i guess 87

Step-by-step explanation:

87.2

nearest must be 87

if 87.5

nearest is 88

See

The rule is If the number aside(right) to the number where to be rounded is less than 5 then it remains same else increases one

So

it will yield as 87

Answer:

1.5 dollars

Step-by-step explanation:

24/16=1.5

Answer:

if 16 tickets cost 24 dollars how about one

if 16tkts = 24 dollars

how about 1 tkt = ?

1×24=24

24÷16 = 1.5 dollars or you round off to the nearest 5 cents Making the answer to be 2 Dollars per ticket

The SECA taxes on the $57,000 in income will be $7068. Self Employed Contributions Act is known by the initials SECA. These taxes typically calculated based on the net earnings, in just this case $57,000.

SECA taxes have a base rate of 6.2% for employees and 6.2% for employers. Due to their dual employment status as both an employee and an employer, self-employed individuals are subject to double taxes.

Doug must thus pay taxes totaling 12.4%, which are:

                             SECA = 57000 × \(12.4%\)% \(= 7067\)

As a result, Doug is eligible for an SECA deduction of $706.

In every industry that uses analysis of the data, such as education, administration, healthcare, and research & innovation, statistician or mathematician were employed. schools of higher learning. In colleges and universities, statisticians and mathematician might research theoretical or abstract ideas in these domains.

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The length of time to run a marathon would best be modeled as continuous. Explanation: Continuous variables are those that are measured and can take on any value between their minimum and maximum values. The length of time to run a marathon can take any value between the minimum and maximum values.

Therefore, it is a continuous variable.The height of a tree can take any value between the minimum and maximum values; hence it would be modeled as continuous.The number of socks in a drawer would be modeled as discrete. Discrete variables can only take certain values and cannot be measured. Socks are not continuous and hence we cannot have a fraction of a sock in a drawer; hence it is a discrete variable.The number of people you have dated in the past year would also be modeled as discrete. This is because you cannot date a fraction of a person.

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Given ,The equation for the height of the rocket is given ash = -4.9t^2 + 102t + 100where t is the time in seconds after its engine burns out 100 m above the ground.

1) The discriminant is given by; D = b^2 - 4acHere, a = -4.9, b = 102 and c = 100Substituting the values, we get; D = (102)^2 - 4(-4.9)(100)D = 10404 + 1960D = 12364So, the discriminant is 12364.2) If the discriminant is positive, then the quadratic equation will have two real roots, which means the rocket will reach a height of 600m. If the discriminant is negative, then the quadratic equation will have no real roots, which means the rocket will not reach a height of 600m.If the discriminant is zero, then the quadratic equation will have one root, which means the rocket will just barely reach a height of 600m.In this case, the discriminant is positive, which means that the rocket will reach a height of 600m. Thus, the rocket will reach a height of 600m. Therefore, the rocket will reach a height of 600 m.

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Using the cosine rule, the distance the plane has flown during Jack's phone call can be calculated by taking the square root of the sum of the squares of the initial and final distances, minus twice their product, multiplied by the cosine of the angle difference.

To determine the distance the plane has flown during Jack's phone call, we can use the cosine rule in trigonometry.

The cosine rule relates the lengths of the sides of a triangle to the cosine of one of its angles.

Let's denote the initial distance from Jack to the plane as d1 and the final distance as d2.

We know that the altitude of the plane remains constant at 2400 meters.

According to the cosine rule:

\(d^2 = a^2 + b^2 - 2ab \times cos(C)\)

Where d is the side opposite to the angle C, and a and b are the other two sides of the triangle.

For the initial angle of elevation (70°), we have the equation:

\(d1^2 = (2400)^2 + a^2 - 2 \times 2400 \times a \timescos(70)\)

Similarly, for the final angle of elevation (50°), we have:

\(d2^2 = (2400)^2 + a^2 - 2 \times 2400 \times a \times cos(50)\)

To find the distance the plane has flown, we subtract the two equations:

\(d2^2 - d1^2 = 2 \times 2400 \times a \times (cos(70) - cos(50))\)

Now we can solve this equation to find the value of a, which represents the distance the plane has flown.

Finally, we calculate the square root of \(a^2\) to find the distance in meters.

It's important to note that the angle of elevation assumes a straight-line path for the plane's movement and does not account for any changes in altitude or course adjustments that might occur during the phone call.

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Answer:

f(4) =1

Step-by-step explanation:

f(1) = 10

f(n) = f(n − 1) – 3

Let n=2

f(2) = f(2 − 1) – 3 = 10-3 = 7

Let n =3

f(3) = f(3 − 1) – 3 = f(2) -3 = 7-3 = 4

Let n = 4

f(4) = f(4 − 1) – 3 = f(3) -3 = 4-3 = 1

Answer:

9

Step-by-step explanation:

f(4)=4(4-1)-3

f(4)=4(3)-3

f(4)=12-3

f(4)=9

680 grams.

So, it's telling us to calculate the weight, in grams, of the other rock.

So firstly,

6 of the rocks EACH have a weight of 720 grams.

So, 6 x 720 = 4320

Now save 4320 for later.

Next, we need to convert the 5 kilograms into grams.

So, 5 x 1000 = 5000

now do, 5000 - 4320 = 680.

Your final answer would then be = 680g

I hope this helped.

Answer:

add two tiles per figure until u get to eight.

Step-by-step explanation:

The given equation for the height of the ball is h = -t² + 8t. To determine the time interval during which the ball is increasing in height, we need to find the critical points where the height is at a maximum or minimum.

To do this, we can take the first derivative of the height equation with respect to time (t) to find the rate of change of height:

h'(t) = -2t + 8

Now, we set the first derivative equal to zero to find the critical points:

0 = -2t + 8
2t = 8
t = 4

This means the ball reaches its maximum height at t = 4 seconds. Since the ball is increasing in height before reaching the maximum height, the time interval during which the ball is increasing in height is from t = 0 seconds (when the ball is thrown) to t = 4 seconds.

So, the time interval when the ball is increasing in height is from 0 to 4 seconds.

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Answer:

The y-intercept of the line is at the point with coordinates (0,-5)

Step-by-step explanation:

The machine numbers immediately to the right and left of 2ⁿ in the floating-point representation depend on the specific floating-point format being used. In general, the machine numbers closest to 2ⁿ are the largest representable numbers that are less than 2ⁿ (to the left) and the smallest representable numbers that are greater than 2ⁿ (to the right). The distance between 2ⁿ and these machine numbers depends on the precision of the floating-point format.

In a floating-point representation, the numbers are typically represented as a sign bit, an exponent, and a significand or mantissa.

The exponent represents the power of the base (usually 2), and the significand represents the fractional part.

To find the machine numbers closest to 2ⁿ, we need to consider the precision of the floating-point format.

Let's assume we are using a binary floating-point representation with a certain number of bits for the significand and exponent.

To the left of 2ⁿ, the largest representable number will be slightly less than 2ⁿ. It will have the same exponent as 2ⁿ, but the significand will have the maximum representable value less than 1.

The distance between this machine number and 2ⁿ will depend on the spacing between representable numbers in the chosen floating-point format.

To the right of 2ⁿ, the smallest representable number will be slightly greater than 2ⁿ. It will have the same exponent as 2ⁿ, but the significand will be the minimum representable value greater than 1.

Again, the distance between this machine number and 2ⁿ will depend on the spacing between representable numbers in the floating-point format.

The exact distance between 2ⁿ and the closest machine numbers will depend on the specific floating-point format used, which determines the precision and spacing of the representable numbers.

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A) The probability that daily production is less than 31 liters is approximately 0.413 or 41.3%.
B) The probability that daily production is more than 27.4 liters is approximately 0.163 or 16.3%.



To calculate the probabilities for the daily production of a herd of cows, assumed to be normally distributed with a mean of 32 liters and a standard deviation of 4.5 liters, we can use the normal distribution.
A) To find the probability that the daily production is less than 31 liters, we need to calculate the area under the normal curve to the left of 31. We can standardize the variable by converting it into a z-score using the formula: z = (x - μ) / σ, where x is the value we want to find the probability for, μ is the mean, and σ is the standard deviation.
In this case, we have x = 31, μ = 32, and σ = 4.5. Substituting these values into the formula, we get z = (31 - 32) / 4.5 = -0.22. We can then use a standard normal distribution table or a calculator to find the corresponding probability. Looking up the z-score of -0.22, we find that the probability is approximately 0.413. Therefore, the probability that daily production is less than 31 liters is approximately 0.413 or 41.3%.
B) Similarly, to find the probability that daily production is more than 27.4 liters, we can standardize the variable. Using the formula, z = (x - μ) / σ, we have x = 27.4, μ = 32, and σ = 4.5. Substituting these values, we calculate z = (27.4 - 32) / 4.5 = -0.98. By looking up the z-score of -0.98, we find the corresponding probability of approximately 0.163. Therefore, the probability that daily production is more than 27.4 liters is approximately 0.163 or 16.3%.

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