in the absence of oxygen, cells need a way to regenerate which compound?
Answers
In the absence of oxygen, cells need a way to regenerate Adenosine triphosphate (ATP).
Adenosine triphosphate (ATP) is an energy-carrying molecule found in cells. It is referred to as the "molecular unit of currency" for intracellular energy transmission. When one of the three phosphate groups is removed from an ATP molecule, energy is released, allowing for cellular work to be completed.
ATP is used by cells for a variety of purposes. ATP is necessary for muscular contraction and other biochemical processes that require energy.ATP is produced in cells via the process of cellular respiration.
This method uses oxygen and glucose as inputs to create ATP as an output. Without oxygen, however, cells need a different method of regenerating ATP because oxygen is a necessary element in cellular respiration. Therefore, in the absence of oxygen, cells require a different approach for generating ATP.
In the absence of oxygen, cells require a different method of regenerating ATP. One such process is anaerobic respiration, which uses glucose to produce ATP without oxygen. This method, however, is not as efficient as cellular respiration, generating just 2 ATP molecules per glucose molecule.
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Related Questions
Which of the following is not a reason for cells to undergo mitosis?
(A) sexual reproduction
(B) repair/renewal
(c) development
D growth
Answers
The option that is not a reason for cells to undergo mitosis is (A) sexual reproduction.
Why do cells undergo mitosis?Mitosis is the process by which cells divide and produce two genetically identical daughter cells, which is a form of asexual reproduction.
Sexual reproduction, on the other hand, involves the fusion of two gametes, each of which has undergone meiosis to produce genetically diverse cells. Therefore, mitosis is not directly involved in sexual reproduction.
The other options, (B) repair/renewal, (C) development, and (D) growth, are all reasons for cells to undergo mitosis.
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In the absence of oxygen, the cells ability to convert the stored energy of glucose to useable ATP*
Answers
In the absence of oxygen, the cells are able to convert the stored energy of glucose to usable ATP is greatly decreased.
What are anaerobic ATP production pathways?The expression of anaerobic ATP production pathways makes reference to all metabolic pathways in which cells can produce energy in the form of Adenosine Triphosphate or ATP in absence of oxygen. The processes in the cells that are associated with anaerobic ATP production pathways include fermentation and glycolytic pathways, which are energetically less efficient than cellular respiration pathways.
Therefore, with this data, we can see that anaerobic ATP production pathways are less efficient than cellular respiration in regard to the amount of ATP generated by the cell in equal amounts of reactants (e.g., glucose).
Complete question:
In the absence of oxygen, the cells are able to convert the stored energy of glucose to usable ATP _____.
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Write two sentences on global warming
Answers
Answer:
Global warming is a major crisis in the world. It is when companies or industries dump or pollute the air or the nature that is around us.
Explanation:
Answer:
I'm glad you asked!
Explanation:
Global warming is temperature of earths surface and more, like atmosphere.Global warming is Mostly about temperature and crisis.People are hurting animals in the ocean and throwing garbage.
Hope that was helpful.Thank you!!!
Which of the following changes would be expected if a CAU UUG sequences of bases mutated to CAC UUG?
Answers
Answer:
The amino acid sequence would be shorter than expected. The identity of one amino acid would change.
Explanation:
Question
What would most likely occur over time if
many of the producers in an ecosystem
were killed by disease?
O Less energy would be available to
consumers at all levels.
O More energy would be available for
new producers.
O Decomposition would slow
dramatically.
O Herbivores would have less food, but
carnivores would not be affected.
Answers
Answer:
A
Explanation:
Less energy would be available
Blood in the hepatic portal system is much more likely to reflect the amount of glucose and amino acid absorbed than is the blood in the inferior vena cava. a) True b) False
Answers
The given statement that Blood in the hepatic portal system is much more likely to reflect the amount of glucose and amino acid absorbed than is the blood in the inferior vena cava is TRUE.
The hepatic portal system receives blood from the digestive tract and provides a means for the liver to filter the blood before returning it to the heart. Glucose and amino acids absorbed from the small intestine enter the hepatic portal vein and are transported directly to the liver to be processed and stored for later use. The blood in the hepatic portal system is much more likely to reflect the amount of glucose and amino acid absorbed than is the blood in the inferior vena cava.In contrast, the inferior vena cava drains blood from the lower body and the kidneys and returns it to the heart. The blood in the inferior vena cava has already been processed by the liver and is unlikely to reflect the amount of glucose and amino acid absorbed from the small intestine. Thus, the statement "Blood in the hepatic portal system is much more likely to reflect the amount of glucose and amino acid absorbed than is the blood in the inferior vena cava" is True.
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why does grafting the zpa to the anterior region of the limb bud cause a mirror image duplication of the digits?
Answers
Grafting the zone of polarizing activity (ZPA) to the anterior region of the limb bud causes a mirror image duplication of the digits because it causes a duplication of the signaling center that controls the development of the digits.
Grafting the zone of polarizing activity (ZPA), which contains signaling molecules that are important for patterning the developing limb, to the anterior region of the limb bud causes a mirror image duplication of the digits because the ZPA provides positional information that determines the identity of the developing digits.
The ZPA produces a gradient of signaling molecules, including Sonic Hedgehog (Shh), that specify different positional values along the anterior-posterior axis of the developing limb.
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grasses and clovers make their own food through the process of?
Chemosynthesis
Decomposition
Photosynthesis
Regurgitation
Answers
Answer:
Photosynthesis
Explanation:
Hope this helps you ☺️
If yes then do mark my answer as brainliest
Cells can interact by releasing proteins or other molecules as chemical signals. How do cells receive these signals?
Answers
Answer: Cells typically receive signals in chemical form via various signaling molecules.
The illustration above shows a cell and a large particle. Many substances,
such as proteins and polysaccharides, are too large to be transported into a
cell by carrier proteins. In a process call endocytosis, the large particle is
brought into the cell.
9 Which of the following statements correctly summarizes this process?
Answers
D. Endocytosis forms a little vesicle or bubble and gets transported through the membrane that way.
a buffer contains 0.01 mole of lactic acid and 0.04 mole of sodium lactate per liter. what is the ph of this buffe
Answers
The pH of the buffer can be calculated using the Henderson-Hasselbalch equation is 4.462.
In this case, the concentration of lactic acid and sodium lactate can be used to determine the pH of the buffer solution.
Explanation: The Henderson-Hasselbalch equation is given by:
pH = pKa + log([A-]/[HA]),
where pKa is the negative logarithm of the acid dissociation constant (Ka), [A-] is the concentration of the conjugate base, and [HA] is the concentration of the acid.
In this case, lactic acid (HA) acts as the acid, while sodium lactate (A-) acts as the conjugate base. The given concentrations are 0.01 mole/liter for lactic acid and 0.04 mole/liter for sodium lactate.
The Ka value for lactic acid can be determined from the acid dissociation constant table or literature. Let's assume the Ka value for lactic acid is 1.38 x 10^-4.
Using the Henderson-Hasselbalch equation, we can calculate the pH:
pH = pKa + log([A-]/[HA])
= pKa + log(0.04/0.01)
= pKa + log(4)
Substituting the pKa value and solving the equation, we find the pH of the buffer.
pH = pKa + log([A-]/[HA])
= 3.86 + log(0.04/0.01)
= 3.86 + log(4)
≈ 3.86 + 0.602
≈ 4.462
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Plzzzz helpppp meere
Answers
Answer:
I may not be right but i believe the answer is c
Explanation:
30. Which of the following best explains why enzymes are necessary for many cellular reactions?
A. Enzymes supply the oxygen necessary for the reactions.
B. Enzymes change reactants from solid to liquids during the reactions.
C. The reactions take up too much space in the cell if the enzymes are missing.
D. The reactions are too slow to meet the needs of the cell if enzymes are missing.
Answers
Answer:
D. The reaction are too slow to meet the needs of the cell if enzymes are missing
hope it helps
What is the main function of carbohydrates?
Group of answer choices
contain genetic information
energy source
energy storage
insulation
Answers
Answer:
energy source
Explanation:
carbohydrates are one of the three macronutrients in our diet with their main function being to provide energy to the body.
Answer:
energy source because in 1 carbohydrate it contains 4 calories
To develop strategies to manage water quality in polluted lakes, biologists must determine the depths of sediments D(t) and the rate of sedimentation. It has been determined that the depth of sediment (in centimeters) with respect to time (in years before 1990) for a lake can be estimated by the equation D(t) =155 (1--e^-0.01321)
a. Find D(20) and interpret. b. Find limt→[infinity] D(t) and interpret.
a. Find D(20).
D(20) =
(Round to one decimal place as needed.)
Interpret D(20). Select the correct choice below and fill in the answer box within your choice.
A. The depth of the sediment of the lake in (Round to the nearest year as needed.)
is 20 cm.
B. The depth of the sediment of the lake in 2010 is (Round to one decimal place as needed.)
cm.
C. The depth of the sediment of the lake in 1970
Answers
The depth of the sediment of the lake in 2010 is (Round to one decimal place as needed.) 81.9 cm. This is because t represents the number of years before 1990. Therefore, 1990-20 = 1970. This implies that D(20) is the depth of the sediment in 1970.
This means that the depth of sediment would eventually be 155 cm if the sedimentation process continued indefinitely. Water is one of the most valuable resources on Earth. The ever-growing population and its consequent urbanisation, industrialisation, and agricultural practices, however, have contributed to an increase in water pollution. To establish strategies to manage water quality in polluted lakes, biologists must establish the depths of sediments D(t) and the sedimentation rate.
To compute D(20), the equation D(t) =155 (1 - e^-0.01321) was used. D(20) was computed to be 81.9. This means that the depth of the sediment of the lake in 1970 was 81.9 cm.For the second question, limt→[infinity] D(t) was computed. As t approaches infinity, D(t) approaches 155. This implies that if the sedimentation process continued indefinitely, the depth of sediment would eventually be 155 cm. Therefore, biologists must continuously monitor and devise efficient methods to mitigate water pollution. This will help in conserving water, preserving aquatic life, and maintaining the balance of ecosystems.
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Which codon is the code for the amino acid histidine (His)
Messenger
Second base in codon
RNA Codons
U
С
A
G
UUU UCU
Phel
UAU UGU U
UUC)
UCC UAC)
Tyr
U
UGC)
Cys
Ser
C
UUA UCA
Leu
UAA Stop UGA Stop A
UUG
UCG
UAG Stop UGG Trp G
CUU CCU
CAU
U
CGU
CUC ССС
His
CAC) CGC
Leu Pro
с
CCA
Arg
CAA1
CUG
CGA
Gin
CCG CAG CGG
AUU ACU
AAU
AUC)lle ACC
Asn Ser
AAC) AGC
Thr
AUA
ACA AAA
AUG Start Me ACG
AGA
Lys Arg
AAG AGG
GUU GCU GAU1 GGU
GUC GCC
Asp
GAC) GGC
G
Val
Ala
GUA
GCA
Gly
GAA
Glu
GGA
GUG
GCG GAG) GGG
First base in codon
CUA
Third base in codon
AGU
A. CAA
B. UAC
Ο Ο Ο Ο
C. AAC
D. CAU
Answers
Answer:
The codon that codes for the amino acid histidine (His) is CAC. Therefore, the correct answer is D. CAU.
Which defines an atom?
a. building block of energy
b. building block of matter
C. charged particle
d. smallest particle
Answers
Answer:
b
Explanation:
atom is the building block of matter
One of the deadliest animals on earth is the rough skinned newt. It produces highly toxic skin toxins. In the 1970s, three hunters were found dead while camping in Western Oregon when they accidentally boiled a rough skinned newt in their coffee pot. Scientists discovered that they were becoming more toxic due to a common predator: the garter snake. As garter snakes were growing more immune to their toxins, rough skinned newts were growing more toxic in what is known as an “evolutionary arms race”.
Though the genes for the garter snake immunity are most likely polygenic, however, let us assume that the immunity is caused by a single dominant allele for this exercise. Those without the dominant gene (the recessive genotype), are NOT immune to the toxins of the rough skinned newt.
In 1975, in a population of 88 garter snakes on the coast of Oregon, 54 of them exhibit the recessive genotype are therefore not immune to the rough skinned newt’s toxin.
What is the frequency for the recessive genotype (q^2)?
Solve for q:
Solve for p:
How many snakes are heterozygous?
How many snakes are homoozygous dominant?
Answers
Answer:
One of the deadliest animals on earth is the rough skinned newt. It produces highly toxic skin toxins. In the 1970s, three hunters were found dead while camping in Western Oregon when they accidentally boiled a rough skinned newt in their coffee pot. Scientists discovered that they were becoming more toxic due to a common predator: the garter snake. As garter snakes were growing more immune to their toxins, rough skinned newts were growing more toxic in what is known as an “evolutionary arms race”.
Though the genes for the garter snake immunity are most likely polygenic, however, let us assume that the immunity is caused
I need help plz!!!!!!!!why are the structures of plants ideal for photosynthesis?
Answers
Answer:
grrr science I aint helping LOL! im kidding HERE hope this helllpppsssss! (:
Explanation:
Plants have two major structural systems: the root system and the shoot system. ... The shoot system transports water and nutrients to leaves and flowers. The leaves of the plant are the main location for photosynthesis. Plant reproduction occurs through pollination of the flower and fertilization.
Plants have a root system, a stem or trunk, branches, leaves, and reproductive structures (sometimes flowers, sometimes cones or spores, and so on). Most plants are vascular, which means they have a system of tubules inside them that carry nutrients around the plant.
Unlike animals, however, plants use energy from sunlight to form sugars during photosynthesis. In addition, plant cells have cell walls, plastids, and a large central vacuole: structures that are not found in animal cells. Each of these cellular structures plays a specific role in plant structure and function.
Explain which part of DNA stores and transmits genetic information
Answers
Answer:
Explanation:
DNA, or deoxyribonucleic acid, is the molecule that stores and transmits genetic information in all living organisms. Genetic information is stored in the sequence of nucleotides, the building blocks of DNA. Each nucleotide is made up of a sugar, a phosphate group, and a nitrogenous base. There are four types of nitrogenous bases in DNA: adenine (A), thymine (T), guanine (G), and cytosine (C).
The specific sequence of these bases along the DNA strand is what encodes the genetic information. For example, the sequence ATGCAGA might code for a specific protein, while the sequence GACATAG might code for a different protein. These sequences of bases are stored in specific regions of the DNA called genes.
The genetic information is transmitted during cell division, when the DNA is replicated, and during protein synthesis, when the information in the DNA is used to build the specific proteins determined by the genetic code.
A student examined two slides in the laboratory, one slide with normally dividing cells and another slide with cancerous cells. Which statement best predicts what the student will observe on the slide with cancer cells compared to the slide with normally dividing cells?
aThe slide with cancer cells will show more cells in interphase because they are growing in preparation for cell division.
b.The slide with cancer cells will show more cells in interphase because the stages of mitosis take longer to complete.
c.The slide with cancer cells will show fewer cells in interphase because the cells are dividing rapidly.
d.The slide with cancer cells will show fewer cells in interphase because the cells are not dividing.
Answers
The answer is option a, The slide with cancer cells will show more cells in interphase because they are growing in preparation for cell division. The correct answer is A.
The slide with cancer cells will show more cells in interphase because they are growing in preparation for cell division. There are some differences between cancer cells and normal cells.
Normally dividing cells go through the cell cycle: G1, S, G2, and M. During G1, cells grow and develop, but they don't begin DNA synthesis. DNA synthesis occurs during S phase, which is followed by G2, where the cell checks and prepares its newly synthesized DNA for mitosis.
Finally, mitosis, which is a sequence of steps during which a cell divides into two identical cells. Cancer cells, on the other hand, do not enter into the G0 phase; instead, they continue to divide.
As a result, they divide more quickly and require more nutrients. Since more cells need to be produced, more cells will be in interphase, growing and developing in preparation for cell division. Therefore, the correct answer is A.
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which of the following is true of mitosis? the result is gamete formation. there are two cell divisions before the process is complete. the process requires only one cell division to be complete. does not require dna to replicate.
Answers
Out of the given options, the statement that is true of mitosis is that the process requires only one cell division to be complete.
Mitosis is a type of cell division that occurs in somatic cells (body cells) to produce two identical daughter cells that are genetically identical to the parent cell. Mitosis results in the production of cells that are diploid, meaning that they have the same number of chromosomes as the parent cell.
Gametes are sex cells that are produced by meiosis. These cells are haploid, which means they only contain half the number of chromosomes as the parent cell. During fertilization, the male and female gametes combine to form a zygote with a complete set of chromosomes.Therefore, option C, the process requires only one cell division to be complete, is the correct answer. Mitosis does not result in gamete formation and requires only one cell division. Additionally, DNA replication is an important step in the process of mitosis, so option D is also incorrect.
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Lysogenic viruses do not
Answers
Answer:
Unlike a lytic virus, a lysogenic virus does not cause the host cell to lyse away. A lysogenic virus can remain inactive for a period of time. In lysogenic infection, viral DNA gets integrated with the host cell's DNA, where it is copied along with the host cell's DNA when the host cell replicates.
Explanation:
In the digestive system many large molecules, such as proteins, are broken down into much smaller molecules. State what happens to these smaller molecules following digestion.
Answers
Smaller molecules are taken up into the bloodstream by epithelial cells that line the walls of the small intestine. The waste continues to the colon where water is absorbed and the dried waste is compacted into feces. It is stored until excreted from the anus through the digestive system
The digestive system breaks down the food we eat into its simplest forms: glucose (sugar), amino acids (which make up protein), and fatty acids (which make up fat). Absorbed by the flow, the nutrients are carried to every cell in the body.
The human digestive system consists of the gastrointestinal tract and the accessory digestive organs. Digestion breaks down food into smaller and smaller components until they are absorbed and absorbed by the body.
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Which oi the following statements best describes the mechanism by which the ced-9 protein in the nematode C . elegans prevents apoptosis in normal cells? Ced-9 remains inactive until it is stimulated by ced-3 and other caspases. Active ced-9 prevents activation of the caspase activity of cod-3. Cod. 9 inhibits the cell mombrane receptor for the death-signaling molecule. Ced.g is cleaved to produce the active cod-3 caspase.
Answers
The statement that best describes the mechanism by which the ced-9 protein in the nematode C. elegans prevents apoptosis in normal cells is that Active ced-9 prevents activation of the caspase activity of ced-3.
What is apoptosis? Apoptosis is a form of programmed cell death that is critical for the elimination of unwanted or damaged cells from an organism. The death of these cells is induced by signaling pathways, the loss of which can result in a range of human illnesses.
Caspases are enzymes that have been implicated in apoptosis. Caspase activity leads to cell death, and as a result, caspase activity must be tightly regulated in the cell. One of the key players in the regulation of caspase activity is the C. elegans protein Ced-9.
What is Ced-9 protein?Ced-9 is an apoptosis inhibitor protein that is homologous to Bcl-2, a protein found in mammalian cells. Ced-9 protein is known to prevent caspase activity, which can lead to cell death, in C. elegans cells.
What is the function of Ced-9 protein? Active ced-9 prevents activation of the caspase activity of ced-3. Ced-3 is a caspase enzyme that is capable of inducing cell death. In the absence of active ced-9, ced-3 activity is unchecked, resulting in uncontrolled apoptosis.
Ced-9 protein's function is to maintain cell viability in the nematode C. elegans by suppressing caspase activity. Ced-9 is a critical regulator of apoptosis in C. elegans and is essential for the maintenance of cell viability.
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A friend argues that a car is alive because its parts form organized systems and it requires
energy (gasoline and battery power). How would you respond to your friend?
Answers
Answer:
Although it is true that a car has its parts in an organized system and it uses fuel of some sort to run, a car doesn't have the characteristics of what classifies something as a living thing.
1. A car is not made up of cells. Living things are made of cells.
2. A car doesn't respond to its environment. Living things respond to their environment.
3. A car cannot grow and develop. Living things grow and develop.
4. A car cannot reproduce. Living things reproduce.
If the following is the sequence of an mRNA, what would be the DNA
sequence?U ACCCGUUAA
Answers
Which sentence BEST expresses the central ideas of the passage?
Zebra mussels can adapt to a variety of environments,
O but their ability to adapt to slightly salty water is of
special concern.
O
O
O
Zebra mussels have spread from oceans to lakes,
causing other mussel species to become extinct.
O
Zebra mussels are adaptable mollusks, and they can
survive on land for several days.
O
Zebra mussels have spread rapidly, threatening other
species.
Answers
Zebra mussels are adaptive mollusks that can spend days on land without food.
The ideal answer is C.
Zebra mussels are able to survive in seawater.This bivalve mollusk is only found in the Caspian and Black Sea lagoons and associated inflowing rivers. It can only withstand slightly salty fresh and brackish water for its daily needs.
How do zebra mussels affect the environment?Zebra mussels, like the ones in the photo above, can ruin boat motors, clog water filtration lines, and make beaches unusable. Zebra mussels are a tiny but significant nuisance. This crayfish and other objects can be swiftly encrusted by these mussels.
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Which of the following correctly describes the relationship between an enzyme and its function? A. adenylyl cyclase: conversion of CAMP to AMP
B. phosphatase: removal of a phosphate group
C. glycogen phosphorylase: synthesis of glycogen
D. kinase: addition of a tyrosine
Answers
The correct description of the relationship between an enzyme and its function is option B, phosphatase: removal of a phosphate group.
Enzymes are biological catalysts that facilitate chemical reactions in living organisms. Each enzyme has a specific function based on its structure and the reaction it catalyzes. Option B correctly describes the relationship between the enzyme and its function. A phosphatase is an enzyme that removes a phosphate group from a molecule. Phosphatases play a crucial role in cellular signaling and metabolic pathways by regulating the addition and removal of phosphate groups. The removal of a phosphate group by a phosphatase enzyme can have significant effects on the activity and function of the target molecule, such as protein deactivation or modulation of enzyme activity. In contrast, options A, C, and D do not accurately represent the relationship between the enzyme and its function. Option A describes adenylyl cyclase as converting CAMP to AMP, which is incorrect. Option C suggests glycogen phosphorylase is involved in glycogen synthesis, while it is actually responsible for glycogen breakdown. Option D associates kinase with the addition of a tyrosine, whereas kinases are generally involved in the transfer of phosphate groups, not specific to tyrosine.
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disease.
Document 2 represents the result of the electrophoresis of
the DNA of 2 normal parents and their fetus.
4. Write the genotype of each of the individuals. Justify
the answer.
5. Must the parents care about the state of their fetus?
Justify the answer.
mutant allele
Normal allele
Father Fetus
Mother
Document 2
Answers
The genotype of each of the individuals since they are normal will be heterozygous.
The parents would care about the state of their fetus if the fetus is homozygous for the mutant allele and if the associated mutation poses a great risk to the development of the fetus.
What is DNA gel Electrophoresis?To separate DNA, RNA, or protein molecules according to their size and electrical charge, a laboratory procedure called electrophoresis is utilized. The molecules are moved across a matrix, such as a gel, by an electric current.
Agar or polyacrylamide are the main ingredients in the gel. DNA fragments with a size between a few hundred base pairs and 20 kb can be separated using agarose.
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