can someone help me with this please ?!
Answer:
7.10
Step-by-step explanation:
sketch the region in the plane consisting of points whose polar coordinates satisfy the given conditions.
2 < r < 3, 5 π /3 ≤ θ ≤ 7 π/3
The region in the plane for points with polar coordinates 2 < r < 3 and 5π/3 ≤ θ ≤ 7π/3.
Identify the range of r and θ: In this case, 2 < r < 3 and 5π/3 ≤ θ ≤ 7π/3. Draw the polar coordinate plane (with an origin, labeled "O") and radial lines representing the angles θ.Mark the angle 5π/3 on the plane, which is located in the fourth quadrant (5π/3 = 300°). Draw a radial line from the origin to represent this angle.
Mark the angle 7π/3 on the plane, which is also located in the fourth quadrant (7π/3 = 420°, but since 360° brings us back to the origin, it is equivalent to 60°). Draw a radial line from the origin to represent this angle.Draw two concentric circles around the origin with radii 2 and 3. These represent the range of r values.
Shade the region in the plane that is bounded by the radial lines, as well as the circles with radii 2 and 3. This is the region consisting of points whose polar coordinates satisfy the given conditions.
Your sketch should now show the region in the plane for points with polar coordinates 2 < r < 3 and 5π/3 ≤ θ ≤ 7π/3.
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6c - 8 - 2c - 16
What is the solution
Answer:
4 (c - 6)
Step-by-step explanation:
Simplify the following:
6 c - 2 c - 16 - 8
Hint: | Group like terms in 6 c - 2 c - 16 - 8.
Grouping like terms, 6 c - 2 c - 16 - 8 = (6 c - 2 c) + (-8 - 16):
(6 c - 2 c) + (-8 - 16)
Hint: | Combine like terms in 6 c - 2 c.
6 c - 2 c = 4 c:
4 c + (-8 - 16)
Hint: | Evaluate -8 - 16.
-8 - 16 = -24:
4 c + -24
Hint: | Factor out the greatest common divisor of the coefficients of 4 c - 24.
Factor 4 out of 4 c - 24:
Answer: 4 (c - 6)
the price of a jar of peanut butter went from $ 5.99 to $ 6.89 . what was the percent change in the price?
Using Percentage formula , The change in the price of a jar of peanut butter is 15.02%.
Percentage : It is defined as a relative value indicating hundredth parts of any quantity. One percent (symbolized 1%) is a hundredth part.
First of we need to calculate difference between initial price and final price to
get the change in price.
Initial Price of jar of peanut butter = $ 5.99
Final price of jar of peanut butter = $ 6.89
Change in price of a jar of peanut butter = final price of jar of peanuts butter - initial price of jar of peanuts butter
= $ 6.89 - $ 5.99 = $ 0.9.
Percent change in price = ((Change in Price)/(initial price))× 100
percent change = (0.9/5.99)× 100 = 15.02
Hence, 15.02% is the change in price of a jar of peanuts butter.
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TRUE / FALSE. when the block is in equilibrium, each spring is stretched an additional ∆x. then the block is set into oscillation with amplitude a; when it passes through its equilibrium point it has a speed v.
The statement is true.
When the block is in equilibrium, each spring is stretched an additional ∆x. This implies that the forces from the two springs are balanced, and the block is not experiencing any net force in the equilibrium position.
When the block is set into oscillation with amplitude a, it will pass through its equilibrium point during the oscillation. At the equilibrium point, the displacement of the block is zero, and it changes direction. At this point, the block has its maximum speed v, as it is accelerating towards the equilibrium position.
The speed of the block decreases as it moves away from the equilibrium position, reaches zero at the maximum displacement (amplitude), and then starts accelerating towards the equilibrium point again. Therefore, when the block passes through its equilibrium point, it has its maximum speed v.
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Mia is factoring the polynomial x2 + 4x – 12. She uses the steps shown.
A 2-column table with 4 rows. The first column has no label with entries Step 1, Step 2, Step 3, Step 4. The second column is labeled x squared + 4 x minus 12 with entries x squared + 6 x minus 2 x minus 12, (x squared + 6 x ) minus (2 x + 12), x(x + 6) minus 2(x + 6), (x + 6)(x + 2).
In which step did Mia make an error?
Step 1
Step 2
Step 3
Step 4
Mia's error is in step 4
What is factorization?Factorization involves splitting a function into several factors
The steps in factorizing the expressions are:
Step 1: x^2 + 6x - 2x -12
Step 2: (x^2 + 6x) - (2x + 12)
Step 3: x(x + 6) - 2(x + 6)
Step 4: (x + 6)(x + 2)
From the step 3 to step 4, the resulting expression should be
(x + 6)(x - 2)
However, the step 4 of the expression is (x + 6)(x + 2)
The expected expression and the actual expression in step 4 are different.
Hence, Mia's error is in step 4
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On a merry-go-round, you stand 15 feet from the center while your friend stands 10 feet from the center. How would you find how much further you travel in one revolution than your friend? What is that distance?
Answer:
Revolution traveled by me = 30π ft.
Revolution traveled by my friend = 20π ft.
Difference between revolutions = 10π ft.
Step-by-step explanation:
In one revolution, I travel 2π(15) = 30π ft., and my friend travels 2π(10) = 20π ft., so my revolution is 30π - 20π, or 10π, ft. longer than my friend's revolution.
Simplify:
За х4b
Simplify:
5x + 9y + x - 2y
Answer:
12ab
6x+7y
Step-by-step explanation: hope I helped
Answer:
( a ) 3a ( 4 ) b
= 12ab
( b )Let's simplify step-by-step.
5x + 9y + x − 2y
= 5x + 9y + x + − 2y
Combine Like Terms:
= 5x + 9y + x + −2y
= ( 5x + x ) + ( 9y + −2y )
= 6x + 7y
Hope it helps
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Thank you
For x(t), if it is periodic, find the fundamental period T, and fundamental frequency wo. Otherwise, prove that the signal is not periodic. x(t) = x1
The signal x(t) = x1 is periodic with any positive value of T and does not have a fundamental frequency.
To determine if the signal x(t) = x1 is periodic, we need to check if there exists a positive value T, called the fundamental period, such that x(t + T) = x(t) for all t.
In the given signal x(t) = x1, there is no explicit dependence on time t. It is a constant signal with a value x1. Since the value of x does not change with time, x(t + T) will always be equal to x(t) regardless of the value of T.
Therefore, the signal x(t) = x1 is periodic with any positive value of T, and T can be considered as its fundamental period. Since the value of x is constant, it does not have any oscillations or frequency components. As a result, the concept of fundamental frequency (wo) is not applicable to this signal.
In summary, the signal x(t) = x1 is periodic with any positive value of T and does not have a fundamental frequency.
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find a cartesian equation for the curve and identify it. r = 2 csc(θ)
The cartesian equation of the curve \(r=2 \hspace{0.1cm} csc \hspace{0.1cm} \theta\) is \(y=2\).
A Cartesian equation is essential in mathematics. It corresponds to a mathematical formula that expresses the connection between elements as a function of their positions on a plane known as Cartesian.
A two-dimensional coordinate scheme called the Cartesian plane employs a horizontal x-axis and an upward y-axis to identify locations in space.
Given that, \(r=2 \hspace{0.1cm} csc \hspace{0.1cm} \theta\).
So, \(csc\hspace{0.1cm}\theta=cosec \hspace{0.1cm}\theta\).
The equation becomes as follows:
\(r=2cosec\hspace{0.1cm} \theta\)
By using the trigonometric equation \(cosec\hspace{0.1cm} \theta=\frac{1}{sin\hspace{0.1cm}\theta}\), we get
\(r= \frac{2}{sin \hspace{0.1cm} \theta}\)
Multiplying both sides by \(sin\hspace{0.1cm}\theta\), we get
\(r \hspace{0.1cm}sin\hspace{0.1cm}\theta =2\hspace{0.1cm}\frac{sin\hspace{0.1cm}\theta}{sin\hspace{0.1cm}\theta}\)
\(rsin\hspace{0.1cm}\theta=2\)
By the parametric equations \(x=rcos\hspace{0.1cm}\theta\) and \(y=rsin\hspace{0.1cm}\theta\), we get
\(y=2\)
It is a horizantal line.
Hence, the cartesian equation of the curve \(r=2 \hspace{0.1cm} csc \hspace{0.1cm} \theta\) is \(y=2\).
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The cartesian equation for the curve is: y = 2 This is a horizontal line passing through the point (0,2).
To find a Cartesian equation for the curve given by the polar equation r = 2 csc(θ), we will convert the polar coordinates (r, θ) into Cartesian coordinates (x, y) using the following relationships:
x = r * cos(θ)
y = r * sin(θ)
Step 1: Express r in terms of θ
r = 2 csc(θ)
Step 2: Since csc(θ) = 1 / sin(θ), rewrite the equation as
r = 2 / sin(θ)
Step 3: Express x and y in terms of r and θ
x = r * cos(θ)
y = r * sin(θ)
Step 4: Substitute r from Step 2 into the y equation
y = (2 / sin(θ)) * sin(θ)
Step 5: Simplify the equation
y = 2
The Cartesian equation for the given polar equation is y = 2, which represents a horizontal line passing through the point (0, 2).
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give answers to these questions, and thereby flesh out a coordinate descent method. for (i), your solution should do something at least a bit more adaptive than merely picking a coordinate at random.
To flesh out a coordinate descent method : (i) One common approach is to choose coordinate with the largest gradient. (ii) One common approach is to use a line search, where we try out step sizes along the chosen coordinate and select the one that leads to the largest decrease in the function value. (iii) One common stopping criterion is to stop when the change in function value.
This can be done by computing the partial derivatives of the function with respect to each coordinate, and selecting the one with the largest absolute value. This approach is known as "greedy" coordinate descent, and it can help speed up convergence by focusing on the most important directions.
This approach can be more computationally efficient, since it doesn't require computing the gradient at each step. Another approach is to use a fixed step size, which can be simpler to implement but may not always lead to the best results.
By choosing the coordinate to optimize along, determining the step size, and setting a stopping criterion, we can develop a coordinate descent method that is well-suited to our particular optimization problem.
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Hep please!!!!!!!!!!!!!!!!!!!!!!!!really need it
Answer:
r = 15
Step-by-step explanation:
r + 2 + 2r - 13 = 34
3r = 45
r = 15
note: brainy award pls ;>
a sequence is Defined by the formula F(n+1)=f(n)-3. If f(4)=22, what is f(1)
a)10
b)13
c)31
d)34
Answer:
The answer is 13 hope it helps!<3
Step-by-step explanation:
still assuming we have taken a random sample of n = 10 basketballs, what is the probability that at most one basketball is non-conforming?
The probability of at most one basketball being non-conforming in a random sample of 10 basketballs, assuming a population proportion of 10%, is approximately 0.7361 or 73.61%.
We first need to know the proportion of non-conforming basketballs in the population. Let's assume that it is 10%.
Using this information, we can calculate the probability of at most one basketball being non-conforming using the binomial distribution formula:
P(X ≤ 1) = P(X = 0) + P(X = 1)
Where X is the number of non-conforming basketballs in our sample.
P(X = 0) = (0.9)¹⁰ = 0.3487
P(X = 1) = 10C1(0.1)(0.9)⁹ = 0.3874
(Note: 10C1 represents the number of ways to choose one non-conforming basketball from a sample of 10.)
Therefore, P(X ≤ 1) = 0.3487 + 0.3874 = 0.7361
So the probability of at most one basketball being non-conforming in a random sample of 10 basketballs, assuming a population proportion of 10%, is approximately 0.7361 or 73.61%.
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Find the magnitude of u × v and the unit vector parallel to u×v in the direction u × v.
u=4i+2j+8k , v=-i-2j-2k
The unit vector parallel to u×v in the direction u × v is then:
(u × v) / |u × v|
= (4i + 24j - 8k) / 2√21
Given, u = 4i + 2j + 8k
and v = -i - 2j - 2k.
We need to find the magnitude of u × v and the unit vector parallel to u×v in the direction u × v.
The cross product of two vectors is defined as follows:
a × b = |a| |b| sin(θ) n
where |a| and |b| are the magnitudes of vectors a and b,
θ is the angle between a and b, and n is a unit vector that is perpendicular to both a and b and follows the right-hand rule.
Since we want a vector parallel to u×v, we don't need to worry about n.
We can use the following formula to find the magnitude of u × v:|u × v| = |u| |v| sin(θ)where θ is the angle between u and v.
We can find θ using the dot product:
u · v = |u| |v| cos(θ)4(-1) + 2(-2) + 8(-2)
= |-4 - 4 - 16||u|
= √(4² + 2² + 8²)
= √84
= 2√21|v|
= √(1² + 2² + 2²)
= 3sin(θ)
= |u × v| / |u| |v|
= 20 / (2√21 × 3)
= 20 / (6√21).
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The magnitude of u × v is sqrt(1060) and the unit vector parallel to u × v in the direction of
\(u \times v\ is (2i - 32j - 6k) / \sqrt(1060)\)
The cross product of vectors u and v is given by:u × v = |u| |v| sinθ n
where |u| and |v| are the magnitudes of u and v, respectively,
θ is the angle between vectors u and v,
and n is a unit vector perpendicular to both u and v.
let's calculate the cross product of u and v.
Using the cross product formula,u × v = det(i j k;4 2 8;-1 -2 -2)
Now we can evaluate the determinant:u × v = 2i - 32j - 6k
The magnitude of u × v is given by:
|u × v| = \(\sqrt((2)^2 + (-32)^2 + (-6)^2)\)
= \(\sqrt(1060)\)
The unit vector in the direction of u × v is given by:
u × v / |u × v| = \((2i - 32j - 6k) / \sqrt(1060)\)
Therefore, the magnitude of u × v is sqrt(1060) and the unit vector parallel to u × v in the direction of
\(u \times v\ is (2i - 32j - 6k) / \sqrt(1060)\)
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Rachel can run 34 mile in 16 of an hour. What is Rachel’s running speed?
Answer:
544 mph
Step-by-step explanation:
Speed= \(\frac{Distance}{Time}\)
Speed= \(\frac{34}{\frac{1}{16} }\)
speed= \(\frac{34}{1}\)×\(\frac{16}{1}\)
Speed= 34×16= 544
Rachel can run 544 mph
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2. Find a true inequality that involves the real number 5/4
Answer:
c
Step-by-step explanation:
5/4>6/5
multiply by 20
25>24
which is true.
If a project yields monthly savings of $4,000 beginning 4 months after implementation with an initial investment of $42,000 and training costs of $2,000, what is the 5 year ROI from implementation
The 5-year ROI (Return on Investment) from the implementation of the project can be calculated by determining the total savings over the 5-year period and comparing it to the initial investment and training costs.
The project yields monthly savings of $4,000 beginning 4 months after implementation.
To calculate the 5-year ROI, we need to determine the total savings over the 5-year period.
First, we calculate the number of months in 5 years, which is 60 months. Since the savings begin 4 months after implementation, we subtract those 4 months.
So, the total number of months with savings is 56 months.
Next, we multiply the monthly savings of $4,000 by the number of months to obtain the total savings over the 5-year period.
56 months multiplied by $4,000 gives us a total savings of $224,000.
To calculate the 5-year ROI, we subtract the initial investment and training costs from the total savings.
The initial investment is $42,000, and the training costs are $2,000. Therefore, the total cost is $44,000.
Finally, we calculate the ROI by dividing the net savings ($224,000 - $44,000 = $180,000) by the total cost ($44,000) and multiplying by 100 to express it as a percentage.
The ROI is then ($180,000 / $44,000) * 100 = 409.09%.
Therefore, the 5-year ROI from the implementation of the project is 409.09%.
This indicates a positive return on the initial investment and training costs, suggesting that the project is financially beneficial over the 5-year period.
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Consider the diagram and proof by contradiction.
Given: △ABC with AB ≅ AC
Triangle A B C is shown. The lengths of sides A B and A C are congruent.
Since it is given that AB ≅ AC, it must also be true that AB = AC. Assume ∠B and ∠C are not congruent. Then the measure of one angle is greater than the other. If m∠B > m∠C, then AC > AB because of the triangle parts relationship theorem. For the same reason, if m∠B < m∠C, then AC < AB. This is a contradiction to what is given. Therefore, it can be concluded that ________.
AB ≠ AC
∠B ≅ ∠C
ABC is not a triangle
∠A ≅ ∠B ≅ ∠C
The conclusion is our that : ∠B and ∠C are congruent
i.e., ∠B ≅ ∠C
We have the following:
A △ABC with AB ≅ AC
Since AB ≅ AC implies AB=AC.
The lengths of sides A B and A C are congruent.
Our assumption is ∠B and ∠C are not congruent.
Then the measure of one angle is greater than the other and
It is also given that:
m∠B > m∠C, then AC > AB because of the triangle parts relationship theorem.
and if m∠B < m∠C, then AC < AB by the same reason.
As we know if in a triangle two sides are equal then the triangle becomes an isosceles triangle.
Since triangle is isosceles then the angles opposite to equal sides are equal i.e.,
if AB=AC then ∠B = ∠C in △ABC
which is contradiction to the assumption that ∠B and ∠C are not congruent.
Therefore, it can be concluded that
∠B and ∠C are congruent.
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Find the slope of the line which contains (3, 0) and (5, 0)
Answer:
0
Step-by-step explanation:
the slope is the change of y, over the change of x. the change of 0, and 0, is 0. and the change of x is 2. so the slope is 0/2, which is 0.
Math is harddddddddddddddddd
that is the graph for y=-x-6 just put it into tinspire
1. [8 Marks] Consider the permutation & € Ss given in two-line notation by (1 2 3 4 5 6 7 8 3 5 2 8 1 4 7 6) a) Rewrite o in cycle notation. Is o an even or odd permutation? What is its order? b) Calculate ² and 0-². c) Find the size of the conjugacy class of o. Provide your calculations, and include a brief justification of your answer. σ=
a) The order of o is 6.
b) o-² = (1 2 3)(4 7 6)(5)
c) The size of the conjugacy class of o is 280.
Lets calculate the given options:
a) We can rewrite the permutation 0 in cycle notation as follows: (1 2)(3 4)(5)(6 8 7). The permutation o is a product of 4 disjoint cycles and is therefore an even permutation. The order of o is the least common multiple of the lengths of its disjoint cycles.
That is;Order(o) = lcm(2,2,1,3) = 6v
Therefore, the order of o is 6.
b) The square of o is found by computing oo:(1 3 2)(4 8 6 7)(5)
Note that 0-¹ can be obtained by reversing the order of the cycles and the order of the numbers within the cycles in o.
Hence;o-¹ = (1 2)(4 3)(5)(6 7 8).
Therefore; o-² = oo-¹ = (1 3 2)(4 8 6 7)(5)(1 2)(4 3)(5)(6 7 8)
Simplifying, we obtain; o-² = (1 2 3)(4 7 6)(5)
c) The size of the conjugacy class of o is the number of even permutations in S8 with cycle structure identical to that of o.
If λi is the length of the i-th cycle in o, then the number of permutations in S8 with cycle structure λ1, λ2, …, λk is given by(8! / λ1 λ2 … λk)(n1!/ 1! 2! … λ1)(n2! / 1! 2! … λ2) … (nk!/ 1! 2! … λk)
where ni is the number of i-cycles in S8, which is given by 8! / (i * λi)
Note that for o, λ1 = λ2 = 2, λ3 = 1 and λ4 = 3.
Hence, the number of even permutations with the same cycle structure as o is given by(8! / (2² * 1 * 3)) (4! / 2²) (4! / 2²) (3! / 1) (8! / (3 * 3! * 2²))= 560
We divide by 2 to account for the fact that exactly half of these permutations are even.
Hence, the size of the conjugacy class of o is given by 560/2 = 280.
Therefore, the size of the conjugacy class of o is 280.
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A cookie recipe calls for 1 1/3
cups of flour. If Erin wants to make a double recipe, how many cups of flour will she need?
1 1/6
cups
2 1/3
cups
2 2/3
cups
1 1/3
cups
Answer:
If a single recipe calls for 1 1/3 cups of flour, then a double recipe will require 2 times 1 1/3 cups, which is:
2 x 1 1/3 cups = 2 x 4/3 cups = 8/3 cups
Converting this to a mixed number, we get:
8/3 cups = 2 2/3 cups
Therefore, Erin will need 2 2/3 cups of flour to make a double recipe. Answer: 2 2/3 cups.
30233088 in index form
Answer:
3.0233088 x 10 raise to power 7
Consider the function. Which statement correctly describes the function’s behavior around its vertical asymptote?
A) As x → –2–, f(x) → ∞ and as x → –2+, f(x) → ∞.
B) As x → –2–, f(x) → –∞ and as x → –2+, f(x) → ∞.
C) As x → –2–, f(x) → –∞ and as x → –2+, f(x) → –∞.
D) As x → –2–, f(x) → ∞ and as x → –2+, f(x) → –∞.
Answer:
B) As x → –2–, f(x) → –∞ and as x → –2+, f(x) → ∞.
Step-by-step explanation:
2020 edg.
A function assigns the values. The correct option is B.
What is a Function?A function assigns the value of each element of one set to the other specific element of another set.
The statement that correctly describes the function's behavior around its vertical asymptote is As x → –2–, f(x) → –∞ and as x → –2+, f(x) → ∞. Thus, the correct option is B.
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x(5x2 - x)
Maaad confused
Answer: 10
10 THE ANSWER
Step-by-step explanation:
Given a circle with center (-7, 2) and radius 1, (a) Write an equation of the circle in standard form. (b) Graph the circle.
So the equation of the circle in standard form is: (x + 7)^2 + (y - 2)^2 = 1.
To write the equation of the circle in standard form, we need to use the formula:
(x - h)^2 + (y - k)^2 = r^2
where (h, k) is the center of the circle and r is the radius.
Given that the center of the circle is (-7, 2) and the radius is 1, we have:
(x - (-7))^2 + (y - 2)^2 = 1^2
Simplifying and rearranging, we get:
(x + 7)^2 + (y - 2)^2 = 1
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Suppose you are charged a $10 per month base charge for your electrical service. You are also charged an additional $0.08 for every kwh of electricity you use. The cost is an example of a mixed cost. variable cost. fixed cost. step cost.
The cost described in the scenario is an example of a mixed cost.
A mixed cost consists of both fixed and variable components. In this case, the $10 per month base charge represents the fixed component of the cost. This charge remains constant regardless of the amount of electricity consumed. It covers the basic service and is not influenced by usage levels.
On the other hand, the additional charge of $0.08 per kilowatt-hour (kWh) of electricity used represents the variable component. This charge varies directly with the amount of electricity consumed. As more electricity is used, the variable cost increases proportionally.
By combining the fixed base charge and the variable charge per kWh, we get a mixed cost structure. The fixed component ensures a minimum cost for the service, while the variable component adds to the total cost based on actual usage. This combination of fixed and variable elements makes the cost a mixed cost.
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explain how it is possible that all proportional relationships are linear functions but not all linear functions are proportional relationships.
Proportional and linear functions are almost identical in form. The only difference is the addition of the “b” constant to the linear function. Indeed, a proportional relationship is just a linear relationship where b = 0, or to put it another way, where the line passes through the origin (0,0).
You’re welcome
rewrite the equation in Ax + By = C form
Answer:
\(y = \frac{1}{3} x - 1\)
\(3y = x - 3\)
\( - x + 3y = - 3\)
\(x - 3y = 3\)
The equation in standard form is
x - 3y = 3.