Answers
Answer:
Plz give brainliest
Step-by-step explanation:
The unit circle definition is tan(theta)=y/x or tan(theta)=sin(theta)/cos(theta). The tangent function is negative whenever sine or cosine, but not both, are negative: the second and fourth quadrants. Tangent is also equal to the slope of the terminal side.
Related Questions
A cross section of the cylinder with the cone removed is a ring. To find the area of the ring, find the area of the outer circle and of the inner circle. Then subtract the area of the inner circle from the outer circle.
Answers
The area of the outer circle and of the inner circle is : πr² and, πx².
Then subtract the area of the inner circle from the outer circle is :
π (r - x) (r+x)
Here, we have,
Given:
Let the radius of outer circle i.e CA be r
Let the radius of inner circle i.e CB be x
The diagram is given below as attachment.
We know that,
area of circle = πR²
Then subtract the area of the inner circle from the outer circle is:
The area of the outer circle - area of the inner circle
= πr² - πx²
= π (r² - x²)
=π (r - x) (r+x)
So, we get
Then subtract the area of the inner circle from the outer circle is:
π (r - x) (r+x)
Hence, The area of the outer circle and of the inner circle is : πr² and, πx².
Then subtract the area of the inner circle from the outer circle is :
π (r - x) (r+x)
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Please help me respond this
Answers
Option 2 is correct that is 1.79
What is third quartile ?When presented in ascending order, the value that 75% of data points fall within is known as the higher quartile, or third quartile (Q3).
The quartiles formula is as follows:
Upper Quartile (Q3) = 3/4(N+1)
Lower Quartile (Q1) = (N+1) * 1/3
Middle Quartile (Q2) = (N+1) * 2/3
Interquartile Range = Q3 -Q1,
1.74, 0.24, 1.56, 2.79, 0.89, 1.16, 0.20, and 1.84 are available.
Sort the data as follows: 0.20, 0.24, 0.89, 1.16, 1.56, 1.74, 1.84, 2.79 in ascending order of magnitude.
The data set has 8 values.
hence, n = 8; third quartile: 3/4 (n+1)th term
Q3 =3/4 of a term (9) term
Q3 =27/4 th term
Q3 = 1.74 + 1.84 / 2 (average of the sixth and seventh terms)
equals 1.76
Thus Q3 is 1.76 that is option 2
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help for brainliest plsssssssssssss
Answers
Answer:
2,472 / 2 = 1,236
Seth’s bank charges $5 a month to maintain a checking account and $0.50 for each check Seth writes. last month, Seth paid a total of $6.50 in checking account fees. How many checks did he write?
A) 1
B) 2
C) 3
D) 4
Answers
Answer:
C) 3
Step-by-step explanation:
Because she paid 6.50, you subtract that by 5 and it will get you 1.50 and then you divide that by .50 and it gets you your answer.
Two sides of a parallelogram are 29 feet and 50 feet. The measure of the angle between these sides is 80. Find the area of the parallelogram to the nearest square foot.
Answers
The area of the parallelogram, rounded to the nearest square foot, is approximately 1428 square feet.
Area of parallelogram = (side 1 length) * (side 2 length) * sin(angle).
Here the sine function relates the ratio of the length of the side opposite the angle, to the length of the hypotenuse in a right triangle.
In simple terms, we are using the sine function to determine the perpendicular distance between the two sides of the parallelogram.
Given that length of side 1 = 29 feet
length of side 2 = 50 feet
The angle between side 1 and side 2 = 80 degrees
Area = 29 * 50 * sin(80)
Sin 80 is approximately 0.984807.
Therefore , Area = 29 * 50 * 0.984807
Area ≈ 1427.97 = 1428 square feet
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I am a factor of 36, 48, and 30. I am an even number. I am divisible by 3. What number am I?
Answers
3*12=36
3*10=30
3*16=48
3/3=1
Consider the economy whose data appear in the table below. Working-age population 100,000 Labor force 60,000 Unemployed 12,000 Instructions: Round your answers to one decimal place.
a. The unemployment rate is ___%.
b. The labor-force participation rate is ___ %.
Answers
a. The unemployment rate is 20%.
b. The labor-force participation rate is 60%.
According to the question,
Working age population- 100,000
Labour force - 60,000
Unemployed - 12000 instructions
a) The unemployment rate is the percentage of the labor force that is unemployed and it is calculated as follows:
Unemployment Rate = \(\frac{Number of unemployed People}{Labor force}\) × 100
When an unemployed population is 12,000 and the labor force is 60,000,
the unemployment rate is = \(\frac{12000}{60000}\) × 100 = 20%
b) labor force participation rate is the percentage of working adult population that participates in labor either by actively looking for a job, or working. It is calculated as follows:
Labor Force Participation Rate = \(\frac{Labor force}{working age population}\) × 100
When the labor force is 60,000 and the working-age population is 100,000
Labor Force Participation Rate = \(\frac{60000}{100000}\) × 100 = 60%
So, a. The unemployment rate is 20%.
b. The labor-force participation rate is 60 %.
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What is the y-intercept of y = 2/3 x + 2? Responses A (3, 2)(3, 2) B (2, 3)(2, 3) C (-3, 0)(-3, 0) D (0, 2)
Answers
Answer:
Y intercept is (0,2) Answer D.
Step-by-step explanation:
I included a graph for equation y=2/3 x + 2.
Suppose we are interesting in estimating θ, the expected number of events per unit time in a Poisson experiment. Two stages of data are collected for inference: m observations are collected in Stage 1, followed by n observations in Stage 2. All data are assumed to be generated from the same sampling model: Stage 1: Y 11
,Y 12
,…,Y 1m
∣θ ∼
iid Poisson(θ) Stage 2: Y 21
,Y 22
,…,Y 2n
∣θ ∼
iid Poisson(θ). Lastly, any data collected in Stage 1 are independent of any data collected in Stage 2. Suppose we assume prior distribution θ∼Gamma(a,b). For shorthand, let Y 1
=(Y 11
,Y 12
,…,Y 1m
) and Y 2
=(Y 21
,Y 22
,…,Y 2n
) be the collection of all observations for Stage 1 and Stage 2 , respectively. (a) (2 points) Find the posterior distribution given all data (i.e., both Y 1
and Y 2
). (b) (4 points) Find the posterior distribution given Stage 1 data. Then, use this distribution as a new "prior" distribution, and compute an "updated" posterior distribution now given Stage 2 data. (c) (2 points) What do you notice in comparing the results of parts (a) and (b)? Explain.
Answers
The posterior distribution is updated and refined as more data is collected, allowing for more accurate inference about the expected number of events per unit time in the Poisson experiment.
In this scenario, we have two stages of data collection for estimating the expected number of events per unit time in a Poisson experiment. Stage 1 collects m observations, followed by n observations in Stage 2. The data from both stages are assumed to be generated from the same Poisson sampling model. We also assume a prior distribution for the parameter θ, which follows a Gamma distribution.
(a) To find the posterior distribution given all data, we use Bayes' theorem. The posterior distribution is proportional to the product of the prior distribution and the likelihood function. In this case, the posterior distribution is given by:
θ | Y₁, Y₂ ∼ Gamma(a + ΣY₁ + ΣY₂, b + m + n).
(b) To find the posterior distribution given Stage 1 data, we only consider the Stage 1 observations. Using Bayes' theorem again, the posterior distribution is given by:
θ | Y₁ ∼ Gamma(a + ΣY₁, b + m).
We can use this distribution as a new "prior" distribution for Stage 2 data. Then, by incorporating the Stage 2 observations, the updated posterior distribution is given by:
θ | Y₂ ∼ Gamma(a + ΣY₁ + ΣY₂, b + m + n).
(c) Comparing the results of parts (a) and (b), we notice that the posterior distribution given all data (both stages combined) has a larger shape parameter (a) and scale parameter (b + m + n) compared to the posterior distribution given only Stage 1 data. This is expected because the inclusion of Stage 2 data provides additional information and increases the precision of the estimate. The updated posterior distribution takes into account the entire dataset, resulting in a more refined estimate of the parameter θ.
Overall, the posterior distribution is updated and refined as more data is collected, allowing for more accurate inference about the expected number of events per unit time in the Poisson experiment.
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GIVING BRAINLIEST FOR THE CORRECT ANSWER
Answers
Answer:
Since the line is not filled in it has to be greater than or less than it cannot be equal to so x<-1.
Shaver Manufacturing,Inc., offers dental insurance to its employees. A recent study bythe human resource director shows the annual cost per employee peryear followed the normal probability distribution, with a mean of$1,280 and a standard deviation of $420 per year.
a. What fraction of the employees cost more than $1,500 per year fordental expenses?
b. Whatfraction of the employees cost between $1,500 and $2,000 peryear?
c. Estimate the percent that did not have any dental expense.
d. Whatwas the cost for the 10% of employees who incurred the highestdental expense?
Answers
a. 30.15% of the employees cost more than $1,500 per year for dental expenses.
b. 65.49% of the employees cost between $1,500 and $2,000 per year for dental expenses.
c. The percentage of employees who did not have any dental expense is 0.1%.
d. The cost of the 10% of employees who incurred the highest dental expenses is $1,796.4 (approx).
a. Probability that dental expenses cost more than $1,500 per year
So, we have to find the probability of employees costing more than $1,500 per year for dental expenses.
Let X be the amount paid per year for dental expenses. X follows normal distribution with mean μ = $1,280 and standard deviation σ = $420.
We have to find P(X > $1,500).Here, z = (X - μ) / σ = ($1,500 - $1,280) / $420 = 0.52P(X > $1,500) = P(Z > 0.52) = 0.3015 or 30.15%.
Therefore, 30.15% of the employees cost more than $1,500 per year for dental expenses.
b. Probability that dental expenses cost between $1,500 and $2,000 per year
Now we have to find the probability of the employees who cost between $1,500 and $2,000 per year for dental expenses.
Let X be the amount paid per year for dental expenses. X follows a normal distribution with mean μ = $1,280 and standard deviation σ = $420.
We have to find P($1,500 < X < $2,000).Here, z1 = (X1 - μ) / σ = ($1,500 - $1,280) / $420 = 0.52z2 = (X2 - μ) / σ = ($2,000 - $1,280) / $420 = 1.71P(0.52 < Z < 1.71) = P(Z < 1.71) - P(Z < 0.52) = 0.9564 - 0.3015 = 0.6549 or 65.49%.
Therefore, 65.49% of the employees cost between $1,500 and $2,000 per year for dental expenses.
c. Probability of employees having no dental expenses.Now we have to find the probability of employees having no dental expenses.
Let X be the amount paid per year for dental expenses. X follows normal distribution with mean μ = $1,280 and standard deviation σ = $420. We have to find P(X = 0).
Here, z = (X - μ) / σ = (0 - $1,280) / $420 = -3.05Now, P(X = 0) is P(X < 0.5), which is same as P(Z < -3.05 + 0.0013) = P(Z < -3.05) = 0.001 or 0.1%.
Therefore, the percentage of employees who did not have any dental expense is 0.1%.
d. Cost of the 10% of employees who incurred the highest dental expenses
We have to find the dental expenses of the 10% of employees who incurred the highest dental expenses.
Let X be the amount paid per year for dental expenses. X follows a normal distribution with mean μ = $1,280 and standard deviation σ = $420.
We have to find the 90th percentile, z0.9.
Using standard normal table, we can find the z-score corresponding to 0.9, which is 1.28.
The amount, X corresponding to z0.9 is:X = μ + z0.9 σ = $1,280 + 1.28 × $420 = $1,796.4
Therefore, the cost of the 10% of employees who incurred the highest dental expenses is $1,796.4 (approx).
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help me with the pirates
Answers
For Roberts the equation is:
\(5y-x=-25\)to we can write it as slope intercept so:
\(\begin{gathered} 5y=x-25 \\ y=\frac{1}{5}x-5 \end{gathered}\)Now we replace x = 5 so
\(\begin{gathered} y=\frac{5}{5}-5 \\ y=1-5 \\ y=-4 \end{gathered}\)So the two points are ( 0 , -5) and ( 5 , -4)
Fo Hookthe equation is:
\(2x-5y=0\)In slope intercept is:
\(\begin{gathered} 5y=2x \\ y=\frac{2}{5}x \end{gathered}\)so we replace x = 5 so:
\(y=2\)So the two points are: ( 0 , 0) and ( 5 , 2 )
For Elizabeth the equation is:
\(y-6=\frac{1}{2}(x-2)\)and slope intercept:
\(\begin{gathered} y=\frac{1}{2}x-1+6 \\ y=\frac{1}{2}x+5 \end{gathered}\)now we replace x = 2 so:
\(\begin{gathered} y=1+5 \\ y=6 \end{gathered}\)So the coordinates are ( 0 , 5) and ( 2, 6 )
And for Silver the equation is:
\(4x-y+6=9\)In slope intercept is:
\(\begin{gathered} y=4x+6-9 \\ y=4x-3 \end{gathered}\)now we replace x = 1 so:
\(\begin{gathered} y=4-3 \\ y=1 \end{gathered}\)So the coordinates are: ( 0, -3) and ( 1, 1 )
So now you can made the graph of the lines and find the message.
PLEASE HELP
The difference between two same-side interior angles of two parallel lines is 35 degrees. Find the measures of these two angles.
Answers
Answer:
is there a visual version of this question?
Answer:
x + y = 180 Fact about angles and parallel lines.
x - y = 35 Given
Solution
Add the equations together
2x = 180 + 35 Combine
2x = 215 Divide by 2
2x/2 = 215/2 Divide
x = 107.5
The larger angle is 107.5
The smaller angle is 180 - 107.5 = 72.5
A flagpole casts a shadow of 25.5 meters long. Tim stands at a distance of 15.4 meters from the base of the flagpole, such that the end of Tim's shadow meets the end of the flagpole's shadow. If Tim is 2.3 meters tall, determine and state the height of the flagpole to the nearest tenth of a meter.
Answers
Answer:
5.8 meters
Step-by-step explanation:
The formula to calculate this is given as:
Height/ Shadow
Shadow of the pole = 25.5 m
Height of the pole = x m
Tim's shadow = Height of the pole - Tim's distance
25.5 m - 15.4 m = 10.1 m
Tim's height = 2.3 m
Hence:
x/25.5 = 2.3/10.1
Cross Multiply
10.1x = 25.5 × 2.3
x = 25.5 × 2.3/10.1
x = 5.8069306931 m
Approximately = 5.8m
Hence, the height of the flagpole = 5.8m
someone please help. Giving brainliest!!
Answers
Answer:
A. None of these
Step-by-step explanation:
The largest perfect square under 100 would actually be 81 (9 x 9)
90 and 99 are not perfect squares and 64 is smaller than 81.
Answer:
a. none of these
Step-by-step explanation:
10 * 10 = 100, so 100 is a perfect square.
The next smaller perfect square is 9 * 9 = 81, but 81 is not in the choices.
Answer: a. none of these
smokin the zaza, it go straight to the matha
Answers
Answer:
huh?
Step-by-step explanation:
what? is this an actual question?
Answer:
whoopty cj
Step-by-step explanation:
PLEASE MARK BRAINLIEST!!!!!!!!!!!!!!!!!!!!!
The PTA has 180 packs of soda to sell. Each pack of soda cost $9.99. The PTA sold 95 packs of soda before school. The remaining packs of sodas were sold after school. How much money did the PTA collect when selling sodas after School?
Answers
Let's begin by listing out the information given to us:
PTA has 180 soda packs to sell = 180 soda packs
Each pack of soda cost $9.99 = $9.99 /soda
PTA sold 95 packs of soda before school = 95 soda packs
To find how much money the PTA collected after school, we will have to find the number of soda packs sold after school
To get the number of soda packs sold after school, subtract the number of soda packs sold before school from the total number of soda packs.
Mathematically,
Number of soda packs sold after school = 180 - 95 = 85 soda packs
How much money did the PTA collect when selling sodas after School = Number of soda packs sold after school * Cost of each soda pack
= 85 * 9.99 = $849.15
multiple questions problem please help me please will give
Answers
Answer:
42
Step-by-step explanation:
the answer is 42
Answer:
42 sandwiches
Step-by-step explanation:
10 1/2 DIVIDED BY 1/4 equals 42!
(I hoped that helped, there wasn't really any other way to explain it!)
Tim's family is visiting Emeryville. They plan to see a movie and then explore the town. The
movie will cost the family $48, and parking costs $8 per hour.
How long will the family be able to spend in Emeryville if they want to spend less than $80 and
they don't have any other expenses?
Answers
Answer:
4 hours
Step-by-step explanation:
the cost of movie is $48
means they have $32 left with them
parking charge is $8 (32/8= 4)
means they can spend 4 hours in Emeryville
Is -61 - 1 positive or negative?
Answers
Find the exact length of the midsegment of trapezoid JKLM with verticesJ(6, 10), K(10, 6), L(8, 2), and M(2, 2).The length of the midsegment is
Answers
The midsegment is equal to the average of the lengths of the bases, so:
\(M=\frac{JM+KL}{2}\)Where:
\(\begin{gathered} JM=\sqrt[]{(6-2)^2+(10-2)^2} \\ JM=\sqrt[]{80}=4\sqrt[]{5}\approx8.9 \end{gathered}\)and
\(\begin{gathered} KL=\sqrt[]{(10-8)^2+(6-2)^2} \\ KL=\sqrt[]{20}=2\sqrt[]{5}\approx4.47 \end{gathered}\)Therefore:
\(M=\frac{4\sqrt[]{5}+2\sqrt[]{5}}{2}=3\sqrt[]{5}\)
Given w= sqrt2 (cos ( pi / 4 ) + i sin ( pi / 4 ) ) and z = 2 (cos ( pi / 2 ) + I sin ( pi /2 ) ) , what is w – z expressed in polar form?
Answers
w = √2 (cos(π/4) + i sin(π/4)) = √2 (1/√2 + i/√2) = 1 + i
z = 2 (cos(π/2) + i sin(π/2)) = 2i
Then
w - z = (1 + i) - 2i = 1 - i
so that
|w - z| = √(1² + (-1)²) = √2
and
arg(w - z) = -π/4
In polar form, we have
w - z = √2 (cos(-π/4) + i sin(-π/4)) = √2 (cos(π/4) - i sin(π/4))
Answer:
Step-by-step explanation:
If $20,000 is invested in an account that compounds interest at 3.5% CONTINUOUSLY, how much money is in the account after 10 years?
Answers
Answer:
The final balance is $28,366.91.
So a gain of 8366.91
Step-by-step explanation:
Yosef is twice as old as his sister Joy. When Yosef was 8 years younger, he was the age his sister is now.
Which equation can be used to solve for J, Joy’s age now?
1. J-8=2
2. J+2=8J
3. 2J-8=J
4. 2J+8=J
Answers
Answer:
3. 2J-8=J
Step-by-step explanation:
Yosef is twice as old as his sister Joy (2J). When he was 8 years younger (-8) he was the age his sister is now (=J).
PLEASEEE HELPPPpppppp’nn
Answers
for me the answer was B
Matthew Filled a gallon bucket half full with water .He than poured 1/2 of the water.
how much water is left
Answers
Answer:
No water
Step-by-step explanation:
sing income and working hour data, you get a regression mode with intercept -242.3, and slope 31.45. determine the predicted income if 22 hours were worked on an assembly job.
Answers
The predicted income for working 22 hours on an assembly job is $450.6 which is determined using the given regression model with intercept and slope values.
The intercept (-242.3) represents the predicted income when the number of working hours is zero, and the slope (31.45) represents the increase in income for each additional hour worked. To find the predicted income for 22 hours of work, we substitute 22 for the number of working hours in the regression model and solve for the predicted income.
Therefore, the predicted income for working 22 hours on an assembly job can be calculated as follows:
Predicted income = Intercept + (Slope x Number of working hours)
Predicted income = -242.3 + (31.45 x 22)
Predicted income = -242.3 + 692.9
Predicted income = 450.6
Thus, the predicted income for working 22 hours on an assembly job is $450.6.
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Define a relation R on Z as xRy if and only if x^2+y^2 is even. Prove R is an equivalence relation. Describe its equivalence classes.
Answers
A relation R on Z is an equivalence relation if and only if it is reflexive, symmetric, and transitive. Specifically, in this case, xRy if and only if x^2+y^2 is even.
Reflexive: for any x in Z, x^2+x^2 is even, thus xRx. So, R is reflexive.
Symmetric: for any x,y in Z, if xRy, then x^2+y^2 is even, which implies y^2+x^2 is even, thus yRx. So, R is symmetric.
Transitive: for any x,y,z in Z, if xRy and yRz, then x^2+y^2 and y^2+z^2 are both even, thus x^2+z^2 is even, thus xRz. So, R is transitive.
Therefore, R is an equivalence relation.
To describe the equivalence classes, we need to find all the integers that are related to a given integer x under the relation R.
Let [x] denote the equivalence class of x.
For any integer x, we can observe that xR0 if and only if x^2 is even, which occurs when x is even.
Therefore, every even integer is related to 0 under R, and we have:[x] = {y in Z: xRy} = {x + 2k: k in Z}, for any even integer x.
Similarly, for any odd integer x, we can observe that xR1 if and only if x^2 is odd, which occurs when x is odd. Therefore, every odd integer is related to 1 under R, and we have:[x] = {y in Z: xRy} = {x + 2k: k in Z}, for any odd integer x.
In summary, the equivalence classes of R are of the form {x + 2k: k in Z}, where x is an integer and the parity of x determines whether the class contains all even or odd integers.
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Solve dy/dx=1/3(sin x − xy^2), y(0)=5
Answers
The general solution to the differential equation dy/dx = 1/3(sin x − xy^2), y(0)=5 is: y = ±√[(sin x - e^(x/2)/25)/x], if sin x - xy^2 > 0 and y(0) = 5
To solve this differential equation, we can use separation of variables.
First, we can rearrange the equation to get dy/dx on one side and the rest on the other side:
dy/dx = 1/3(sin x − xy^2)
dy/(sin x - xy^2) = dx/3
Now we can integrate both sides:
∫dy/(sin x - xy^2) = ∫dx/3
To integrate the left side, we can use substitution. Let u = xy^2, then du/dx = y^2 + 2xy(dy/dx). Substituting these expressions into the left side gives:
∫dy/(sin x - xy^2) = ∫du/(sin x - u)
= -1/2∫d(cos x - u/sin x)
= -1/2 ln|sin x - xy^2| + C1
For the right side, we simply integrate with respect to x:
∫dx/3 = x/3 + C2
Putting these together, we get:
-1/2 ln|sin x - xy^2| = x/3 + C
To solve for y, we can exponentiate both sides:
|sin x - xy^2|^-1/2 = e^(2C/3 - x/3)
|sin x - xy^2| = 1/e^(2C/3 - x/3)
Since the absolute value of sin x - xy^2 can be either positive or negative, we need to consider both cases.
Case 1: sin x - xy^2 > 0
In this case, we have:
sin x - xy^2 = 1/e^(2C/3 - x/3)
Solving for y, we get:
y = ±√[(sin x - 1/e^(2C/3 - x/3))/x]
Note that the initial condition y(0) = 5 only applies to the positive square root. We can use this condition to solve for C:
y(0) = √(sin 0 - 1/e^(2C/3)) = √(0 - 1/e^(2C/3)) = 5
Squaring both sides and solving for C, we get:
C = 3/2 ln(1/25)
Putting this value of C back into the expression for y, we get:
y = √[(sin x - e^(x/2)/25)/x]
Case 2: sin x - xy^2 < 0
In this case, we have:
- sin x + xy^2 = 1/e^(2C/3 - x/3)
Solving for y, we get:
y = ±√[(e^(2C/3 - x/3) - sin x)/x]
Again, using the initial condition y(0) = 5 and solving for C, we get:
C = 3/2 ln(1/25) + 2/3 ln(5)
Putting this value of C back into the expression for y, we get:
y = -√[(e^(2/3 ln 5 - x/3) - sin x)/x]
So the general solution to the differential equation dy/dx = 1/3(sin x − xy^2), y(0)=5 is:
y = ±√[(sin x - e^(x/2)/25)/x], if sin x - xy^2 > 0 and y(0) = 5
y = -√[(e^(2/3 ln 5 - x/3) - sin x)/x], if sin x - xy^2 < 0 and y(0) = 5
Note that there is no solution for y when sin x - xy^2 = 0.
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Assume that TDW Corporation (calendar year-end) has 2022 taxable income of $650,000 for purposes of computing the §179 expense. The company acquired the following assets during 2022: (Use MACRS Table 1, Table 2, Table 3, Table 4 and Table 5. ) Asset Placed in Service Basis Machinery September 12 $ 2,270,000 Computer equipment February 10 263,000 Furniture April 2 880,000 Total $ 3,413,000 a. What is the maximum amount of §179 expense TDW may deduct for 2022?
Answers
The maximum amount of §179 expense TDW may deduct for 2022 is $257,000.
To determine the maximum amount of §179 expense that TDW Corporation can deduct for 2022, we first Add up the cost of all the assets acquired in 2022:
$2,270,000 (machinery) + $263,000 (computer equipment) + $880,000 (furniture) = $3,413,000
Now we determine the amount of the §179 deduction limit for the tax year.
For tax year 2022, the §179 deduction limit is $1,050,000.
Check if the cost of the assets exceeds the §179 deduction limit.
Since the cost of the assets ($3,413,000) is greater than the §179 deduction limit ($1,050,000), we need to calculate the phase-out limit.
Now we determine the phase-out limit.
For tax year 2022, the phase-out limit is $2,620,000.
Calculate the §179 expense deduction.
Since the cost of the assets ($3,413,000) is greater than the phase-out limit ($2,620,000), we need to reduce the §179 deduction by the excess over the phase-out limit.
The excess over the phase-out limit is $793,000 ($3,413,000 - $2,620,000).
The §179 expense deduction is the lesser of the §179 deduction limit and the cost of the assets reduced by the excess over the phase-out limit.
The §179 expense deduction is $1,050,000 - $793,000 = $257,000.
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