In the morning, a farm worker packed 3 pints of strawberries every 4 minutes. In the afternoon, she packed 2 pints of strawberries every 3 minutes. What was the difference between her morning and afternoon packing rates, in pints per hour? Hint: 1 hour = 60 minutes Part A: Find the unit rate of pints per hour for the farm worker in the morning.show all your work

Answer:

A) 0.7696

B) 0.0474

C) Yes it's unusual

D) 0.05746

E) No, it is not unusual

F) No, it is not unusual

Step-by-step explanation:

This is a binomial probability distribution question.

We are told that 92.4% of those admitted graduated.

Thus; p = 92.4% = 0.924

From binomial probability distribution, q = 1 - p

Thus;

q = 1 - 0.924

q = 0.076

Formula for binomial probability distribution is;

P(x) = nCx × p^(x) × q^(n - x)

A) At least 11 graduated out of 12.

P(x ≥ 11) = P(11) + P(12)

P(11) = 12C11 × 0.924^(11) × 0.076^(12 - 11)

P(11) = 0.3823

P(12) = 12C12 × 0.924^(12) × 0.076^(12 - 12)

P(12) = 0.3873

P(x ≥ 11) = 0.3823 + 0.3873

P(x ≥ 11) = 0.7696

B) that exactly 9 of them graduated out of 12. This is;

P(9) = 12C9 × 0.924^(9) × 0.076^(12 - 9)

P(9) = 0.0474

C) We are not given significance level here but generally when not given we adopt a significance level of α = 0.05.

Now, exactly 9 out of 12 that graduated which is P(9) = 0.0474.

We see that 0.0474 is less than the significance level of 0.05. Thus, we can say that it is unusual to randomly select 12 students from the special programs and get exactly 9 that graduate

D) that at most 9 of them out of 12 graduated.

P(x ≤ 9) = P(0) + P(1) + P(2) + P(3) + P(4) + P(5) + P(6) + P(7) + P(8) + P(9)

This is going to be very long so I will make use of an online probability calculator to get the values of P(0) to P(8) since I already have P(9) as 0.0474.

Thus, we have;

P(0) = 0

P(1) = 0

P(2) = 0

P(3) = 0.00000001468

P(4) = 0.00000040161

P(5) = 0.00000781232

P(6) = 0.00011081163

P(7) = 0.00115477385

P(8) = 0.00877476184

Thus;

P(x ≤ 9) = 0 + 0 + 0 + 0.00000001468 + 0.00000040161 + 0.00000781232 + 0.00011081163 + 0.00115477385 + 0.00877476184 + 0.04741450256

P(x ≤ 9) = 0.05746

E) P(x ≤ 9) = 0.05746 is more than the significance level of 0.05, thus we will say it is not unusual.

F) from online binomial probability calculator, probability of getting only 9 out of 12 is more than the significance value of 0.05. Thus, we will say it is not unusual

Answer:

12 + 7 = 19

19 + 10 = 29

answear = 29

The solution of the system of linear equations, is (1.167, 3.667).

Given that the system of linear equations, y = -2x+6 and y = 4x - 1, we need to find the solution for the same,

y = -2x+6............(i)

y = 4x - 1.......(ii)

Equating the equations since the LHS is same,

-2x+6 = 4x-1

6x = 7

x = 1.167

Put x = 1.16 to find the value of y,

y = 4(1.16)-1

y = 4.66-1

y = 3.667

Therefore, the solution of the system of linear equations, is (1.167, 3.667).

You can also find the solution using the graphical method,

Plot the equations in the graph, the point of the intersection of both the lines will be the solution of the system of linear equations, [attached]

Hence, the solution of the system of linear equations, is (1.167, 3.667).

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Answer:

don't click the link the bot put it's a bad link btw

Answer: 32ft

Step-by-step explanation:

got it right

The solution set of the system of linear equations is (x1, x2, x3) = (3/2, 3/2, −1/4).

We can solve this system of linear equations using Gaussian elimination method.

Step 1: Add the first row to the second row:

leftbracket3.gif 2 1 −1 3 rightbracket3.gif

1 −1 1 0 2

0 1 2 1

Step 2: Subtract 2 times the second row from the third row:

leftbracket3.gif 2 1 −1 3 rightbracket3.gif

1 −1 1 0 2

0 0 4 −1

Step 3: Divide the third row by 4:

leftbracket3.gif 2 1 −1 3 rightbracket3.gif

1 −1 1 0 2

0 0 1 −1/4

Step 4: Subtract the third row from the first row:

leftbracket3.gif 2 1 −1 3 rightbracket3.gif

1 −1 0 −1/4 7/4

0 0 1 −1/4

Step 5: Add 4 times the second row to the first row:

leftbracket3.gif 2 0 −5/4 3 rightbracket3.gif

1 0 1 −1/4 −1/4

0 0 1 −1/4

This echelon form gives us the solution:

x3 = −1/4

x2 = 7/4 + x3 = 7/4 − 1/4 = 3/2

x1 = 3 − x2 = 3 − 3/2 = 3/2

So, the solution set of the system of linear equations is (x1, x2, x3) = (3/2, 3/2, −1/4).

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Answer:

4/15

Step-by-step explanation:

2/5 drive

1/3 bus

and rest walk

fraction of those who walk is 1-(2/5+1/3)

2/5+1/3=(6+5)/15=11/15

15/15-11/15=4/15

Answer:

M

Step-by-step explanation:

Answer:

b .3

Step-by-step explanation:

every thing else is even and if u add them up u will get to 32 eventually

Answer:

B.) 3

Step-by-step explanation:

To do this problem, we should find out what factors can equal 32. So let's start with finding out. This problem is going to require multiplication and division.

Letter A is a multiple of 32, because:

32 ÷ 2 = 16, which means that 16 x 2 = 32.

Because 2 can be divided equally into 32, this answer is wrong.

_________________

Letter C is a multiple of 32, because:

32 ÷ 4 = 8, which means that 8 x 4 = 32.

Because 4 can be divided equally into 32, this answer is also wrong.

_________________

And, because the last answer equaled 8, that means that:

32 ÷ 8 = 4, which means that 4 x 8 = 32.

Which is also wrong.

_________________

This leaves us with 32 ÷ 3 = 10.6666666667. This answer cannot be multiplied evenly into 32, so it is correct.

I hope that this helps.

Answer:

C = 10000n - 10000 ;

$110,000

Step-by-step explanation:

Given :

Cost = C

C partly varies as n ; C α n ; C = k1 * n = k1n

C partly constant = k2

Hence,

C = k1n + k2

For n = 8 ; C = 70000

For n = 10 ; C = 90000

8k1 + k2 = 70000 - - - - - (1)

10k1 + k2 = 90000 - - - - (2)

Subtract 1 from 2

8k1 - 10k1 = 70000 - 90000

-2k1 = - 20000

k1 = 10000

Put k1 = 10000 in (1)

8(10000) + k2 = 70000

80000 + k2 = 70000

k2 = 70000 - 80000

k2 = - 10000

The expression :

C = 10000n - 10000

Weekly cost for 12 people :

n = 12

C = 10000(12) - 10000

C = 120000 - 10000

C = $110,000

Answer:

B

D

D

Step-by-step explanation:

please verify and rate 5 stars and say thank you

The equation does not hold true, the ordered pair (3, 10) is not a solution of the equation y = 2x + 6.In this way, we can determine whether an ordered pair is a solution of the given equation or not.

Given the equation y = 2x + 6To determine if an ordered pair is a solution of this equation or not, substitute the values of x and y in the equation. If the equation holds true, then the ordered pair is a solution.

If it is not true, then the ordered pair is not a solution.For example, let's consider the ordered pair (1, 8).

Here, x = 1 and y = 8.Substituting these values in the given equation,

we get: y = 2x + 6 => 8 = 2(1) + 6 => 8 = 8 Since the equation holds true,

the ordered pair (1, 8) is a solution of the equation y = 2x + 6.

Now, let's consider another ordered pair, say (3, 10). Here, x = 3 and y = 10.Substituting these values in the given equation, we get: y = 2x + 6 => 10 = 2(3) + 6 => 10 = 12

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Answer:

19/20 , 1 1/4 , 1 4/5

Step-by-step explanation:

1.8 = 1 4/5 (fraction)

1.8 converts to 18/10. This can be simplified twice, firstly by making it 9/5 since both 18 and 10 are divisible by two, but can be simplified further to 1 4/5

1.25 = 1 1/4 (fraction)

1.25 converts to 125/100. This can be simplified to 5/4 or 1 1/4

0.95 = 19/20 (fraction)

0.95 converts to 95/100. This can be simplified to 19/20

Ascending Order (smallest to largest)

smallest - 19/20

middle - 1 1/4

largest - 1 4/5

I believe this is the right answer, but haven't done fractions in a while so may want to double check to make sure

To solve this problem, we need to convert all the measurements to a consistent unit. Let's convert the height to inches since the height of the bounce is given in inches.

64 ft = 64 * 12 inches = 768 inches

Now, we can set up an equation to represent the height of each bounce. Let's use "b" to represent the number of bounces, and "h" to represent the height of each bounce in inches.

The height of each bounce is three-fourths (3/4) the height of the previous bounce. So, we can write the equation as:

h = (3/4) * h_previous

where h_previous is the height of the previous bounce.

We know that the initial height of the ball is 768 inches, and we want to find the number of bounces when the height of the bounce is less than 9 inches. We can set up an inequality to represent this situation:

h < 9

Substituting the expression for h from the equation above, we get:

(3/4) * h_previous < 9

Now, we can start with the initial height of 768 inches and keep applying the equation for each bounce until the height of the bounce is less than 9 inches.

1st bounce:

h = (3/4) * 768 = 576 inches

2nd bounce:

h = (3/4) * 576 = 432 inches

3rd bounce:

h = (3/4) * 432 = 324 inches

4th bounce:

h = (3/4) * 324 = 243 inches

5th bounce:

h = (3/4) * 243 = 182.25 inches

6th bounce:

h = (3/4) * 182.25 = 136.6875 inches

7th bounce:

h = (3/4) * 136.6875 = 102.515625 inches

8th bounce:

h = (3/4) * 102.515625 = 76.88671875 inches

9th bounce:

h = (3/4) * 76.88671875 = 57.6650390625 inches

10th bounce:

h = (3/4) * 57.6650390625 = 43.248779296875 inches

So, the ball will bounce up to a height less than 9 inches after 10 bounces.

Answer:

3/5=0.600

Step-by-step explanation:

I hope this answer helps

The answer is 0.6.

Upto 3 decimal places it is 0.600.

Answer:

B

Step-by-step explanation:

12: 2 2 3

36: 2 2 3 3

GCF 223

The GCF is 2x2x3=12

Answer:

10 wide 30 long

Step-by-step explanation:

1. Start guess and check.

2. When you get to 10 follow this:

10x3=30. 30+30+10+10=80

80=80

Answer:

The answer is not complete. I will explain the concept of profit to you.

Step-by-step explanation:

We can determine profit deducting direct costs (cost price) of commodities from sales (selling prices) of the commodities.

Profit = Selling Price - Cost Price

Example:

A trader buys some dresses for #2,500 in May and agrees to pay for it in three months’ time. He sells off all the dresses in August for #4,500. The profit for the month is #2,000.

The formula for percentage profit is \(\frac{profit * 100}{cost price}\)

The formula for gross profit is Revenue – Cost of Sold Items

Profit Margin =  \(\frac{Total Income}{Net Sales}\) * 100

While Gross Profit Margin can be calculated as \(\frac{Gross Profit}{Net Sales}\) * 100

Any of these formulas can be used to calculate profit-related questions.

We know that 33 students out of 75 consider Math to be their favorite subject. We want to find it this portion of students is 40% of the total.

In order to do that we find what is the 40% of 75.

We just divide the percentage, 40%, by 100:

40 ÷ 100 = 0.4

and then we multiply the result by the total, 75:

0.4 x 75 = 30

This is

40% of 75 is 0.4 x 75 = 30

Then the 40% of 75 is 30 instead of 33 students.

Answer: the conclusion is NOT valid

Answer:

2+2= 4 but 3+3 = 6

Step-by-step explanation:

please mark me brainliest

Answer:

The probability that a randomly selected high school senior's score on mathematics part of SAT will be

(a) more than 675 is 0.0401

(b)between 450 and 675 is 0.6514

Step-by-step explanation:

Mean of Sat =\(\mu = 500\)

Standard deviation = \(\sigma = 100\)

We will use z score over here

 What is the probability that a randomly selected high school senior's score on mathe- matics part of SAT will be

(a) more than 675?

P(X>675)

\(Z=\frac{x-\mu}{\sigma}\\Z=\frac{675-500}{100}\)

Z=1.75

P(X>675)=1-P(X<675)=1-0.9599=0.0401

b)between 450 and 675?

P(450<X<675)

At x = 675

\(Z=\frac{x-\mu}{\sigma}\\Z=\frac{675-500}{100}\)

Z=1.75

At x = 450

\(Z=\frac{x-\mu}{\sigma}\\Z=\frac{450-500}{100}\)

Z=-0.5

P(450<X<675)=0.9599-0.3085=0.6514

Hence the probability that a randomly selected high school senior's score on mathematics part of SAT will be

(a) more than 675 is 0.0401

(b)between 450 and 675 is 0.6514

Answer:

  f(n) = -n^2 -3n +5

Step-by-step explanation:

Suppose the formula is ...

  f(n) = an^2 +bn +c

Then we have ...

  f(1) = 1 = a(1^2) +b(1) +c

  f(2) = -5 = a(2^2) +b(2) +c

  f(3) = -13 = a(3^2) +b(3) +c

__

Here's a way to solve these equations.

Subtract the first equation from the second:

  -6 = 3a +b . . . . . 4th equation

Subtract the second equation from the third:

  -8 = 5a +b . . . . . 5th equation

Subtract the fourth equation from the fifth:

  -2 = 2a

  a = -1

Then substituting into the 4th equation to find b, we have ...

  -6 = 3(-1) +b

  -3 = b

and ...

  1 = -1 +(-3) +c . . . . . substituting "a" and "b" into the first equation

  5 = c

The formula is ...

  f(n) = -n^2 -3n +5

\(\huge\textsf {Hey there!}\)

\(\mathsf{-22 + \dfrac{14}{2}(-10)}\)

\(\mathsf{\dfrac{14}{2}= \boxed{\bf 7}}\)

\(\mathsf{= -22 + 7(-10)}\)

\(\mathsf{7(-10) =\boxed{\bf -70}}\)

\(\mathsf{= -22 + (-70)}\)

\(\mathsf{= -22 - 70}\)

\(\mathsf{= \boxed{\bf -92}}\)

\(\boxed{\boxed{\huge\textsf{Answer: \bf -92}}}\huge\checkmark\)

\(\textsf{Good luck on your assignment and enjoy your day!}\)

~\(\frak{Amphitrite1040:)}\)

Answer:

-92 is the answer.

Step-by-step explanation :

Let's go step by step.

-22 + 14/2(-10)

14/2 is 7, and 7 multiplied by -10 is -70, so we end up with this :

-22 + -70 = -22 - 70

-22 - 70 is -92.

-92 is the answer.

Hope this helps, please mark brainliest!

Answer:

The mean is 33 and the MAD is 6.

Step-by-step explanation:

I took it on edge and got it right. Sorry I don't have a better explanation.

The person above me is correct.

Step-by-step explanation:

The compound amount after 3 years is $2275.22.

In this case, you are given:

Principle = $2,000

rate = 0.0353

time = 3

You need to find A, the compound amount after 3 years.

To do this, you need to plug in the values of P, r and t into the formula and use a calculator:

A=P×e^rt

A=2000×(e)^0.0353×3

A≈2275.22

Therefore, by the compound interest the answer will be $2275.22.

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The expression represents a quadratic polynomial with two terms. The constant term is \(-\frac{1}{6}\), the leading term is \(x^{2}\), and the leading coefficient is \(-1\).

The given expression is \(-x^{2}-\frac{1}{6}\).

We have to complete the given sentence;

The expression represents a ........... polynomial with ........terms. The constant term is .........., the leading term is..........., and the leading coefficient is ....................  .

we first complete the given sentence then we explain the sentence.

The expression represents a quadratic polynomial with two terms. The constant term is \(-\frac{1}{6}\), the leading term is \(x^{2}\), and the leading coefficient is \(-1\).

Firstly about Quadratic Polynomial

When the highest degree term in a second-degree polynomial equals to 2, the polynomial is said to be quadratic.

Now about Constant Term

A number that is constant and does not have any variables in an algebraic expression is a constant term.

Now about Leading Coefficient

The numbers placed in front of the variable with the biggest exponent are known as leading coefficients.

Hence, the expression represents a quadratic polynomial with two terms. The constant term is \(-\frac{1}{6}\), the leading term is \(x^{2}\), and the leading coefficient is \(-1\).

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It looks like the limit you want to compute is

\(\displaystyle L = \lim_{x\to0}\left(\frac x{\tan(x)}\right)^{\cot^2(x)}\)

Rewrite the limand with an exponential and logarithm:

\(\left(\dfrac{x}{\tan(x)}\right)^{\cot^2(x)} = \exp\left(\cot^2(x) \ln\left(\dfrac{x}{\tan(x)}\right)\right) = \exp\left(\dfrac{\ln\left(\dfrac{x}{\tan(x)}\right)}{\tan^2(x)}\right)\)

Now, since the exponential function is continuous at 0, we can write

\(\displaystyle L = \lim_{x\to0} \exp\left(\dfrac{\ln\left(\dfrac{x}{\tan(x)}\right)}{\tan^2(x)}\right) = \exp\left(\lim_{x\to0}\dfrac{\ln\left(\dfrac{x}{\tan(x)}\right)}{\tan^2(x)}\right)\)

Let M denote the remaining limit.

We have \(\dfrac x{\tan(x)}\to1\) as \(x\to0\), so \(\ln\left(\dfrac x{\tan(x)}\right)\to0\) and \(\tan^2(x)\to0\). Apply L'Hopital's rule:

\(\displaystyle M = \lim_{x\to0}\dfrac{\ln\left(\dfrac{x}{\tan(x)}\right)}{\tan^2(x)} \\\\ M = \lim_{x\to0}\dfrac{\dfrac{\tan(x)-x\sec^2(x)}{\tan^2(x)}\times\dfrac{\tan(x)}{x}}{2\tan(x)\sec^2(x)}\)

Simplify and rewrite this in terms of sin and cos :

\(\displaystyle M = \lim_{x\to0} \dfrac{\dfrac{\tan(x)-x\sec^2(x)}{\tan^2(x)}\times\dfrac{\tan(x)}{x}}{2\tan(x)\sec^2(x)} \\\\ M= \lim_{x\to0}\dfrac{\sin(x)\cos^3(x) - x\cos^2(x)}{2x\sin^2(x)}\)

As \(x\to0\), we get another 0/0 indeterminate form. Apply L'Hopital's rule again:

\(\displaystyle M = \lim_{x\to0} \frac{\sin(x)\cos^3(x) - x\cos^2(x)}{2x\sin^2(x)} \\\\ M = \lim_{x\to0} \frac{\cos^4(x) - 3\sin^2(x)\cos^2(x) - \cos^2(x) + 2x\cos(x)\sin(x)}{2\sin^2(x)+4x\sin(x)\cos(x)}\)

Recall the double angle identity for sin:

sin(2x) = 2 sin(x) cos(x)

Also, in the numerator we have

cos⁴(x) - cos²(x) = cos²(x) (cos²(x) - 1) = - cos²(x) sin²(x) = -1/4 sin²(2x)

So we can simplify M as

\(\displaystyle M = \lim_{x\to0} \frac{x\sin(2x) - \sin^2(2x)}{2\sin^2(x)+2x\sin(2x)}\)

This again yields 0/0. Apply L'Hopital's rule again:

\(\displaystyle M = \lim_{x\to0} \frac{\sin(2x)+2x\cos(2x)-4\sin(2x)\cos(2x)}{2\sin(2x)+4x\cos(2x)+4\sin(x)\cos(x)} \\\\ M = \lim_{x\to0} \frac{\sin(2x) + 2x\cos(2x) - 2\sin(4x)}{4\sin(2x)+4x\cos(2x)}\)

Once again, this gives 0/0. Apply L'Hopital's rule one last time:

\(\displaystyle M = \lim_{x\to0}\frac{2\cos(2x)+2\cos(2x)-4x\sin(2x)-8\cos(4x)}{8\cos(2x)+4\cos(2x)-8x\sin(2x)} \\\\ M = \lim_{x\to0} \frac{4\cos(2x)-4x\sin(2x)-8\cos(4x)}{12\cos(2x)-8x\sin(2x)}\)

Now as \(x\to0\), the terms containing x and sin(nx) all go to 0, and we're left with

\(M = \dfrac{4-8}{12} = -\dfrac13\)

Then the original limit is

\(L = \exp(M) = e^{-1/3} = \boxed{\dfrac1{\sqrt[3]{e}}}\)

Answer:

x = -11/3, y = -4/3

Step-by-step explanation:

\(y-2x=6\\y = 2x + 6\)

\(3(2x + 6) = -4\\6x + 18 = -4\\6x = -22\\x = -11/3\)

\(3y = -4\\y = -4/3\)

Answer: 68y+106=36-y

Answer:

640 are expected to be defective.

Step-by-step explanation:

Multiply 6400 by .10 which equals 640.