In the oxidation of iron; how many grams of iron (III) oxide will be produced from 6.20 mol of Fe?
4Fe(s) + 3O2(g) --> 2Fe2O3(s)

The volume of hydrogen gas collected over water is approximately 25.10 liters. We need to consider the stoichiometry of the reaction, the ideal gas law, and the partial pressure of hydrogen gas.

First, let's balance the equation for the reaction between magnesium (Mg) and hydrochloric acid (HCl):

Mg + 2HCl -> MgCl₂ + H₂

From the balanced equation, we can see that 1 mole of magnesium reacts to produce 1 mole of hydrogen gas.

1. Calculate the number of moles of magnesium (Mg):

Molar mass of Mg = 24.31 g/mol

Number of moles of Mg = Mass of Mg / Molar mass of Mg = 25.6 g / 24.31 g/mol = 1.054 mol

2. Calculate the number of moles of hydrogen gas (H₂):

Number of moles of H₂ = Number of moles of Mg = 1.054 mol

3. Apply the ideal gas law to calculate the volume of hydrogen gas (V₂):

PV = nRT

Given:

Pressure (P) = 785.4 torr

Temperature (T) = 36.5 °C = 36.5 + 273.15 K = 309.65 K

R = 0.0821 L·atm/(mol·K) (gas constant)

Number of moles (n) = 1.054 mol

Convert the pressure to atm:

785.4 torr = 785.4 torr * (1 atm / 760 torr) = 1.032 atm

Substituting the values into the ideal gas law equation:

V₂ = (nRT) / P = (1.054 mol * 0.0821 L·atm/(mol·K) * 309.65 K) / 1.032 atm ≈ 25.10 L

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Answer:

The distance the truck traveled is 190

Explanation:

I added 30, 45, 50, 65 together to get the total distance

Answer:

Temperature usually increases when water condenses. What behavior of water is most directly responsible for this phenomenon? The release of heat by the formation of hydrogen bonds. Hydrogen bonds stabilize and keep the of ice farther apart than the water molecules of liquid water.

Mangrove trees' robust roots aid in stabilizing the soil and preventing soil erosion. This is especially crucial in swampy coastal locations, where the soil is frequently loose and prone to wind and wave erosion. Mangrove trees work to stabilize the coastline and stop land erosion by securing the soil in place.

Mangrove trees also aid in removing contaminants from the water, enhancing the quality of the water in coastal areas while serving as an essential home for a variety of wildlife species. Mangrove trees contribute significantly to environmental protection and are an essential component of coastal ecosystems.

Mangrove trees are crucial for environmental preservation because they hold the soil in place and stop erosion in marshy coastal areas. They also provide crucial habitats for numerous wildlife species, stabilize the coastline, and stop the land from being lost to erosion while enhancing water quality by filtering pollutants from the ocean.

Mangrove trees are an essential part of coastal ecosystems overall, and preserving them is essential for preserving a healthy and sustainable environment.

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Answer:

(~21~ Ne)Neon | Ne-pubchem

A student conducts a laboratory investigation involving a gas and assumes the gas behaves ideally, volume vs moles of a gas, at constant pressure and temperature.so, option (b) is correct.

What is pressure?

The definition of pressure is "force applied per unit area." It can be calculated mathematically using P=FA, where F is the force acting perpendicular to surface area A. The pascal (Pa), or one newton per square meter (N/m 2), is the common unit of pressure.

What is temperature?

The velocity of these particles likewise increases as the temperature rises.

Therefore, a student conducts a laboratory investigation involving a gas and assumes the gas behaves ideally, volume vs moles of a gas, at constant pressure and temperature.so, option (b) is correct.

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In order for a nuclear equation to be considered balanced, both sides' sums of the atomic and mass numbers (subscripts and superscripts) must be the same.

What is mean by alpha decay and beta decay?

Alpha decay:

Beta-decay:

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As a result, when a substance absorbs enough energy then its atoms or molecules move around. And, when increase in this energy takes place then atoms tend to collide frequently with each other. Hence, it causes change in state of a substance. Therefore, changes in matter are important for the conservation of energy

mark brainliest if right

Answer:

Air conditionded building

Explanation: Ice cream is processed food so techniacally it could be using technology but Air conditioning is a unit of metal and is built. Hope this is right!

The experimental molar enthalpy of solution in kJ/mol is  5.2718 kJ/mol.

given that :

mass of NaOH = 10.0 g

molar mass of NaOH = 40 g/mol

number of mole = mass / molar mass

                          = 10 /40

                          = 0.25 mol

initial temperature = 18.5 °C

final temperature = 50.0 °C

Molar enthalpy of solution = ΔH / n

n = number of moles

ΔH = Q = mcΔT

specific heat  of the solution = 4.184 J/g °C

ΔH = mcΔT

ΔH = 10 g × 4.184 J/g °C × ( 50 °C - 18.5 °C )

ΔH = 1317.96 J

Molar enthalpy of solution = ΔH / n

                                            = 1317.96 J / 0.25 mol

                                            = 5271.84 J/mol

Molar enthalpy of solution = 5.2718 kJ/mol

Thus, 10.0 grams of solid sodium hydroxide (NaOH) was dissolved in 50.0 mL of water. The experimental molar enthalpy of solution in kJ/mol is  5.2718 kJ/mol.

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Atmospheric oxygen is too reactive which keeps natural atoms from framing all alone and staying in one piece today. The main speculation about the reason for the Cambrian explosion includes a mass elimination of Ediacaran fauna and an expansion in climatic oxygen.

During the Cambrian explosion, creatures not just began to eat meat, like floating tiny fish, yet they additionally created jaws for getting and biting greater prey. The resulting weapons contest prompted hard body parts and shells for insurance, for example, the intricate spikes and towers of trilobite shells. The Cambrian Period frame denotes a significant point throughout the entire existence of life on the planet, it is when a large portion of the significant gatherings of creatures initially show up in the fossil record. This occasion is in some cases called the "Cambrian Explosion," as a result of the generally brief time frame over which this variety of structures shows up.

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Answer:

We need more? What else is in the question? This is unanswerable.

Explanation:

Answer:

3700000000

Explanation: Move decimal to the right of the amount the exponent is for 10 Give brainliest pls

The combined gas law equation is:

(P1 * V1) / (T1) = (P2 * V2) / (T2)

The volume of the gas at 30 °C is approximately 760.67 mL.

To determine the volume of the gas at 30 °C, we can use the combined gas law equation, which relates the initial and final conditions of temperature and volume for a gas.

The combined gas law equation is:

(P1 * V1) / (T1) = (P2 * V2) / (T2)

Where:

P1 and P2 are the initial and final pressures, respectively

V1 and V2 are the initial and final volumes, respectively

T1 and T2 are the initial and final temperatures in Kelvin, respectively

We need to convert the temperatures from Celsius to Kelvin by adding 273.15 to each value.

Given:

V1 = 550 mL

T1 = -55 °C = 218.15 K

T2 = 30 °C = 303.15 K

Assuming the pressure remains constant, we can rearrange the equation to solve for V2:

V2 = (P1 * V1 * T2) / (P2 * T1)

Since the pressure is not specified in the problem, we can assume it remains constant, allowing us to cancel out the pressure terms. Thus, the final equation becomes:

V2 = (V1 * T2) / T1

Plugging in the given values:

V2 = (550 mL * 303.15 K) / 218.15 K

Simplifying the calculation, we find:

V2 ≈ 760.67 mL

Therefore, the volume of the gas at 30 °C is approximately 760.67 mL.

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Q_w = 307.3 J

C_m = .233 J/g•K

%error = 39.95%

For simplicity's sake, I'm relabeling

Q_w as Q1

m_w as m1

C_w as c1

T_eq as T2

T_w as T1

Q_m as Q2

m_m as m2

C_m as c2

experimental value as exp

actual value as actual

Question 1

Q1 = m1•c1•(T2-T1)

Identify what you know

m1 = 124g

c1 = 4.13 J/g • K

T2 = Final temperature = 22.3°C

T1 = Initial temperature = 21.7°C

Convert Celsius to Kelvin (C+273.15=K)

T2 = 295.45 K

T1 = 294.85 K

Plug in

Q1 = 124g•(4.13 J/g•K)•(295.45K - 294.85K)

Solve

Q1 ≈ 307.3 J

Question 2

-Q1 = Q2 = m2•(c2)•(T2-100)

Ignore Q2 for a second, and you're left with

-Q1 = m2•(c2)•(T2-100)

which is the same thing.

Identify what you know

Q1 = 307.3 J

m2 = 17g

T2 = 22.3°C

Plug in

-(307.3J) = 17g • c2 • (22.3°C-100°C)

Solve

-307.3 J = (-1320.9 g•°C) • c2

c2 = .233 J/g•°C or J/g•K (I'll explain later)

Question 3

%err = ((exp - actual)/actual) • 100%

Identify what you know

exp = .233 J/g•K

actual = .388 J/g•K

Plug in

%err = ((.233 J/g•K - .388 J/g•K)/ .388 J/g•K) • 100%

Solve

%err = -39.95 %

Take the absolute value

%err = 39.95%

Referring to earlier change in units:

The reason we can not use the K value of T2 (295.45K) is because the formula provided (T2-100) does not account for T2 being in K. It only accounts for T2 being in °C.

rate He = 6 x rate SF₆

Graham's law: the rate of effusion of a gas is inversely proportional to the square root of its molar masses or  

the effusion rates of two gases = the square root of the inverse of their molar masses:  

\(\rm \dfrac{r_1}{r_2}=\sqrt{\dfrac{M_2}{M_1} }\)

or  

\(\rm M_1\times r_1^2=M_2\times r_2^2\)

M He = 4 g/mol

M SF₆ = 146 g/mol

\(\tt \dfrac{r_{He}}{r_{SF_6}}=\sqrt{\dfrac{146}{4} }=6.04\approx 6\\\\r_{He}=6~r_{SF_6}\)

The benzene molecule is flat and planar. As a result of this planarity, the substituent is also in the plane of molecule and do not show any directionality.

The benzene molecule is a flat and planar molecule owing to the fact that all the bond lengths and bond angles in the molecules are the same. This results from resonance in the molecule.

Hence, owing to the planarity of the molecule, the substituent is also in the plane of molecule and do not show any directionality.

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The rate constant for the reaction is either 7.14×10−3 s−1 or 2.50×10−3 s−1, depending on which rate was used to calculate it.

The rate of the reaction is given by the equation:

Rate = -k[A]

where k is the rate constant and [A] is the concentration of the reactant.

Rate at t=140 s:

Rate = (8.00×10−2 M - 0 M) / (140 s - 0 s)

= 5.71×10−4 M/s

Rate at t=400 s:

Rate = (4.00×10−2 M - 0 M) / (400 s - 0 s)

= 1.00×10−4 M/s

Since this is a zero-order reaction, the rate of the reaction is constant, and we can use either rate to calculate the rate constant:

k = Rate / [A]

Using the rate at t=140 s:

k = 5.71×10−4 M/s / 8.00×10−2 M = 7.14×10−3 s−1

Using the rate at t=400 s:

k = 1.00×10−4 M/s / 4.00×10−2 M

= 2.50×10−3 s−1

The rate constant for the reaction is either 7.14×10−3 s−1 or 2.50×10−3 s−1.

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The mass of 4.35 moles of potassium chloride is 324.14 grams. Potassium chloride (KCl) is a chemical compound made up of potassium and chlorine.

Potassium chloride (KCl) is a chemical compound composed of potassium and chlorine. It is commonly used as a salt substitute for people on low-sodium diets, as well as a fertilizer, a source of potassium in food additives, and a component of some medical solutions. Potassium chloride can also be used in the production of various chemicals, including explosives and pharmaceuticals.

The molar mass of potassium chloride (KCl) is 74.55 g/mol (39.10 g/mol for K and 35.45 g/mol for Cl).

To calculate the mass of 4.35 moles of KCl, we can use the following formula:

mass = moles × molar mass

So, the mass of 4.35 moles of KCl is:

mass = 4.35 moles × 74.55 g/mol

mass = 324.14 g

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Answer:

Here is the correct order (ascending order):

gene, DNA, chromosome, nucleus, cell, organism.

A gene is a segment of DNA that contains the instructions for building a protein or RNA molecule. DNA is the molecule that carries genetic information and makes up genes. A chromosome is a structure made of DNA and protein that carries genes. A nucleus is a membrane-bound organelle that contains chromosomes. A cell is the smallest structural and functional unit of living organisms, consisting of a nucleus (or nucleoid in prokaryotes) and cytoplasm. An organism is an individual living entity, such as a plant, animal, or bacterium, that consists of multiple cells.

Answer:

Option b is show the chemical property of sodium....

The compound that is shown as X can be seen in the option labelled C

The process of esterification involves the condensation of an alcohol (or phenol) with an acid to produce an ester. To create the ester bond, the water molecule must be removed from the alcohol and acid (dehydration).

Usually, an acid catalyst is used to catalyze the reaction, which makes it easier to remove water and encourages the creation of the ester. The acid catalyst aids in protonating the acid's carbonyl oxygen, which increases its electrophilicity and makes it more vulnerable to alcohol's nucleophilic attack.

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Answer: (A,B,D) [1, 2, 4]

Explanation:

Answer:

a

Explanation:

Answer:

C.

Explanation:

The other ones just don't make sense as answers to the question

Answer:

B

Explanation:

ice molecules move slowly and cluster tightly together, they produce a low amount of heat

Answer:

\(\boxed {\boxed {\sf 333 \ grams}}\)

Explanation:

We are asked to find the mass of a sample of metal. We are given temperatures, specific heat, and joules of heat, so we will use the following formula.

\(Q= mc \Delta T\)

The heat added is 4500.0 Joules. The mass of the sample is unknown. The specific heat is 0.4494 Joules per gram degree Celsius. The difference in temperature is found by subtracting the initial temperature from the final temperature.

The sample was heated from 58.8 degrees Celsius to 88.9 degrees Celsius.

Now we know three variables:

Substitute these values into the formula.

\(4500.0 \ J = m (0.4494 \ J/g \textdegree C)(30.1 \textdegree C)\)

Multiply on the right side of the equation. The units of degrees Celsius cancel.

\(4500.0 \ J = m (13.52694 J/g)\)

We are solving for the mass, so we must isolate the variable m. It is being multiplied by 13.52694 Joules per gram. The inverse operation of multiplication is division, so we divide both sides by 13.52694 J/g

\(\frac {4500.0 \ J }{13.52694 J/g}= \frac{m (13.52694 J/g)}{13.52694 J/g}\)

The units of Joules cancel.

\(\frac {4500.0 \ J }{13.52694 J/g}= m\)

\(332.6694729 \ g =m\)

The original measurements have 5,4, and 3 significant figures. Our answer must have the least number or 3. For the number we found, that is the ones place. The 6 in the tenth place tells us to round the 2 up to a 3.

\(333 \ g \approx m\)

The mass of the sample of metal is approximately 333 grams.

Answer:noble gases

Explanation: