Indicate how the concentration of each species in the chemical equation will change to reestablish equilibrium after a decrease in pressure or volume. If there is no change in the concentration of the species, leave the box blank. CH 4 ( g ) + 2 H 2 S ( g ) − ⇀ ↽ − CS 2 ( g ) + 4 H 2 ( g ) CH4(g)+2H2S(g)↽−−⇀CS2(g)+4H2(g) after decreasing the pressure after decreasing the volume of the reaction vessel

The anode reaction is: \(Cd(s) → Cd^2+(aq) + 2e^-\)

The cathode reaction is:\(2Br^-(aq) + Br2(l) + 2e^- → 2Br^-(aq)\)

The net cell reaction is: \(Cd(s) + Br2(l) → Cd^2+(aq) + 2Br^-(aq)\)

In a voltaic cell, the anode is where oxidation occurs, while the cathode is where reduction takes place. In this case, the anode consists of a \(Cd|Cd^2\)+ half cell, where the solid cadmium (Cd) electrode is oxidized to form cadmium ions \((Cd^2+)\) in the aqueous solution. The anode reaction is represented by the equation \(Cd(s) → Cd^2+(aq) + 2e^-\).

On the other hand, the cathode is a \(Br^-|Br2\) half cell. Here, bromide ions \((Br^-)\) from the aqueous solution are reduced, along with elemental bromine (Br2) to form additional bromide ions. The cathode reaction can be represented by the equation \(2Br^-(aq) + Br2(l) + 2e^- → 2Br^-(aq)\).

When we combine the anode and cathode reactions, we get the net cell reaction. The cadmium (Cd) from the anode reacts with the bromine (Br2) from the cathode to produce cadmium ions\((Cd^2+)\) and bromide ions (Br^-). The net cell reaction can be represented by the equation\(Cd(s) + Br2(l) → Cd^2+(aq) + 2Br^-(aq).\)

In the external circuit, electrons flow from the cadmium electrode (the anode) to the bromine electrode (the cathode), generating an electric current. The salt bridge, which connects the two half-cell compartments, allows the migration of ions to maintain charge balance. In this case, anions \((Br^-)\) migrate from the bromide half cell to the cadmium half cell through the salt bridge.

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Approximately 18.4832 mL of 0.250 M NaOH is required to neutralize 30.4 mL of 0.152 M HCl.

To determine the volume of 0.250 M NaOH required to neutralize 30.4 mL of 0.152 M HCl, we can use the concept of stoichiometry and the balanced chemical equation for the neutralization reaction between NaOH and HCl:

NaOH + HCl -> NaCl + H2O

From the balanced equation, we can see that the stoichiometric ratio between NaOH and HCl is 1:1. This means that for every mole of NaOH, we require an equal number of moles of HCl to neutralize.

First, let's calculate the number of moles of HCl present in the given volume:

Moles of HCl = concentration of HCl * volume of HCl

= 0.152 M * 30.4 mL

= 4.6208 mmol (millimoles)

Since the stoichiometric ratio is 1:1, the number of moles of NaOH required to neutralize the HCl is also 4.6208 mmol.

Now, let's calculate the volume of 0.250 M NaOH needed to contain 4.6208 mmol:

Volume of NaOH = (moles of NaOH) / (concentration of NaOH)

= 4.6208 mmol / 0.250 M

= 18.4832 mL

Therefore, approximately 18.4832 mL of 0.250 M NaOH is required to neutralize 30.4 mL of 0.152 M HCl.

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Answer:

These are Kepler's Laws of Planetary Motion

Explanation:

Answer:

its Keplers third law,

then first law,

then second law

Explanation:

Answer:

See the answer below

Explanation:

When a solution of iodine is mixed with a solution of tetrachloromethane, the mixture turns purple due to the formation of \(I_2(CCl_4)\).

Iodine solution dissolves in carbon tetrachloride solution (another name for tetrachloromethane) due to the fact that both solutions are similarly non polar in nature. The equation of the reaction is as shown below:

            \(I_2 + CCl_4 --> I_2(CCl_4)\)

The movement of water and electrolytes between fluid compartments is regulated primarily by hydrostatic pressure and osmotic pressure.

Define electrolytes.

When dissolved in water, substances known as electrolytes acquire a natural positive or negative electrical charge.

The force that a fluid applies against a wall—hydrostatic pressure—is essentially moves fluid between compartments. The pressure that blood applies to the blood vessel walls as a result of the heart's pumping motion is known as the hydrostatic pressure of blood. The opposing "colloid osmotic pressure" in capillaries is greater than the blood's "constant" pressure, which is principally created by the circulation of albumin at the capillary's arteriolar end. This pressure pushes plasma and nutrients into the surrounding tissues from the capillaries.

Therefore, the movement of water and electrolytes between fluid compartments is regulated primarily by hydrostatic pressure and osmotic pressure.

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Answer:

Electrons

Explanation:

To solve this we must be knowing each and every concept related to moles. Therefore, 0.11moles of oxygen were burned and 0.222 moles of water were formed.

A mole is merely a measuring unit. In reality, it is among the International System on Units' seven foundation units (SI). When basically determines are insufficient, new units are created.

Chemical reactions frequently occur at levels that use grams would be inappropriate, but using actual figures of atoms/molecules/ions would also be misleading. As a result, scientists devised the mole for bridge the divide between extremely small and extremely huge numbers.

2H\(_2\) + O\(_2\) \(\rightarrow\)  2H\(_2\)O

The mole ratio between hydrogen gas and oxygen gas is 2:1

moles of hydrogen gas = 0.222 moles

moles of oxygen gas =0.11moles

moles of water formed = 0.222 moles

Therefore, 0.11moles  of oxygen were burned and 0.222 moles of water were formed.

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The rate of reaction in step 1 is (- 1/A)[ ΔB/Δt ] =  - ( ΔC/ t ) = - (ΔD/Δt ).

The rate of reaction in step 2 is - ( ΔD / Δt ) =  - (ΔC / Δt )  - ( ΔE / Δt ).

The rate of reaction in step 3 is - (ΔE /Δt ) = (- 1/A)[ ΔB/Δt ] =  - (ΔF/ t).

The rate of reaction refers to the speed at which the products are formed from the reactants in a chemical reaction.

Mathematically, the formula for the rate of chemical reaction is given as;

aA + bB → cC + dD

Rate = (- 1 / a) [ ΔA / Δt ] =  (- 1 / b) [ ΔB / Δt ] =  (- 1 / c) [ ΔC / Δt ] =  (- 1 /d) [ ΔD / Δt ]

The rate of reaction for the following steps is determined as;

Step 1:

AB + C → D

Rate =  (- 1 / A) [ ΔB / Δt ] =  (- 1 / 1) [ ΔC / Δt ] =  (- 1 / 1) [ ΔD / Δt ]

Rate = (- 1 / A) [ ΔB / Δt ] =  - ( ΔC / Δt ) =  - (ΔD / Δt )

Step2:

D + C → E

Rate = (- 1 / 1) [ ΔD / Δt ] =  (- 1 / 1) [ ΔC / Δt ] =  (- 1 / 1) [ ΔE / Δt ]

Rate =  - ( ΔD / Δt ) =  - (ΔC / Δt )  - ( ΔE / Δt )

Step3:

E  + AB → F

Rate =  (- 1 / 1) [ ΔE / Δt ] =  (- 1 / A) [ ΔB / Δt ] =  (- 1 / 1) [ ΔF / Δt ]

Rate =  - ( ΔE / Δt ) =  (- 1 / A) [ ΔB / Δt ] =  - ( ΔF / Δt )

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Answer:

Temperature and Volume

Explanation:

PV = n R T

P = n R T / V      pressure depends on the temperature and volume

The pressure of a gas depends on the temperature and volume of the gas.

PV = nRT

Where

From the equation given above, we obtained the following:

PV = nRT

Divide both sides by V

P = nRT / V

R is constant and n = 1

P = T / V

Thus, we can see that the pressure (P) is dependent on the temperature (T) and the volume (V)

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Answer: Protons and electrons

Explanation: Protons are positively charged and electrons are negatively charged.

Answer: protonproton andand electron

Explanation:

ProtonProton isis positivelypositively chargedcharged andand electornelectron isis negativelynegatively chargedcharged withwith massmass numbernumber 11 forfor each

The given statement "The molar enthalpy of sublimation of a given substance can be determined if its enthalpies of fusion and vaporization are known" is true.

The molar enthalpy of sublimation of a substance can be determined if its enthalpies of fusion (melting) and vaporization (boiling) are known. The enthalpy of sublimation refers to the energy required to change a substance from the solid phase directly to the gaseous phase, bypassing the liquid phase.

The enthalpy change during sublimation can be calculated by considering the enthalpies of fusion and vaporization. When a substance undergoes sublimation, it first requires energy to melt from the solid phase to the liquid phase (enthalpy of fusion) and then additional energy to vaporize from the liquid phase to the gaseous phase (enthalpy of vaporization). The sum of these two enthalpies represents the overall energy change during sublimation.

Therefore, by adding the enthalpy of fusion and the enthalpy of vaporization, one can determine the molar enthalpy of sublimation for a given substance.

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The concentration of Ca(OH)2 in the solution is approximately 1.33 x 10^(-6) M.

To find the concentration of Ca(OH)2 in a solution with a pH of 8.57, we need to use the concept of pOH, which is the negative logarithm of the hydroxide ion concentration ([OH-]). The pOH can be calculated by subtracting the pH from 14, which gives us 14 - 8.57 = 5.43.

Since Ca(OH)2 produces two OH- ions for every molecule of Ca(OH)2 that dissolves, the concentration of OH- ions will be twice the concentration of Ca(OH)2. Thus, we have [OH-] = 2x, where x represents the concentration of Ca(OH)2.

Taking the antilogarithm of the pOH, we find that [OH-] = 10^(-pOH) = 10^(-5.43).

Since [OH-] = 2x, we can write 2x = 10^(-5.43) and solve for x.

x = (10^(-5.43))/2 ≈ 1.33 x 10^(-6) M

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Answer: It will usually form the anion F- since it is extremely electronegative and a strong oxidizing agent. Fluorine is a Lewis acid in weak acid, which means that it accepts electrons when reacting. Fluorine has many isotopes, but the only stable one found in nature is F-19.

Explanation:

The most common ionic form of fluorine is the fluoride ion (F-). Fluorine, as an element, is highly electronegative, meaning it has a strong tendency to attract electrons towards itself.

In the process of forming an ion, fluorine gains one electron to achieve a stable electron configuration, resulting in the fluoride ion.

For example, when fluorine reacts with sodium (Na), fluorine gains one electron from sodium to form the fluoride ion (F-) while sodium loses one electron to become the sodium cation (Na+). This forms an ionic bond between the two ions, resulting in the compound sodium fluoride (NaF).

The fluoride ion is also commonly found in compounds such as calcium fluoride  and aluminum fluoride . In these compounds, fluorine forms ionic bonds with other elements, resulting in the formation of stable compounds.

Overall, the fluoride ion is the most common ionic form of fluorine due to its high electronegativity and its ability to form stable compounds with other elements.

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The gas will have a final pressure of 26.8 kPa.

The pressure of a gas is inversely related to its volume at constant temperature, as well as its number of moles, according to Boyle's law.Using the ideal gas law, the final pressure can be calculated as follows:

\(P_1V_1=P_2V_2\)

\(P_1\)= the gas's initial pressure is 209 kPa.

\(P_2\) =gas's final pressure =?

\(V_1\) = 10.0 L, which is the gas's initial volume.

\(V_2\) =78.0 L, which is the gas's final volume.

Now that all the needed variables have been entered, we can apply this formula to determine the final gas pressure.

209 kPa*10.0L= \(P_2\) *78.0L

\(P_2 =26.8 kPa\)

Therefore, the final pressure of the gas is 26.8kPa.

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The reaction between benzoic acid and sodium hydroxide is a base-catalyzed esterification reaction.

What is base-catalyzed esterification reaction?

Base-catalyzed esterification is a chemical reaction that involves the formation of an ester from a carboxylic acid and an alcohol, using a base as a catalyst. The base helps to facilitate the reaction by deprotonating the carboxylic acid, making it more reactive towards the alcohol.

The general equation for a base-catalyzed esterification reaction is as follows:

Carboxylic acid + Alcohol ⇌ Ester + Water

In this reaction, the base abstracts a proton (H+) from the carboxylic acid, forming a carboxylate anion. The carboxylate anion then reacts with the alcohol, resulting in the formation of an ester and water.

The mechanism of the reaction is as follows:

Step 1: Proton transfer

In the first step, a proton is transferred from benzoic acid to sodium hydroxide, forming the sodium salt of benzoic acid and water.  

`C6H5COOH + NaOH → C6H5COO−Na+ + H2O`

Step 2: Formation of an intermediate

In the second step, the sodium salt of benzoic acid reacts with benzoic acid to form an intermediate species called benzoyl sodium.

`C6H5COO−Na+ + C6H5COOH → C6H5COO−C6H5COONa`

Step 3: Esterification

The benzoyl sodium intermediate then reacts with another molecule of benzoic acid, releasing sodium hydroxide to form the ester benzyl benzoate and sodium benzoate as by-product.

`C6H5COO−C6H5COONa + C6H5COOH → C6H5COOC6H5CH2OC6H5 + NaC6H5COO`

Overall Reaction:

`C6H5COOH + C6H5COOH + NaOH → C6H5COOC6H5CH2OC6H5 + NaC6H5COO + H2O`

Hence, the complete mechanism for the reaction between benzoic acid and sodium hydroxide is as described above.

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The cycloalkanes which exhibits the greatest molar heat of combustion is cyclopropane. Hence, the correct option is (E).

Cycloalkanes are cyclic hydrocarbons with the general formula CnH2n. The molar heat of combustion is the amount of heat released when one mole of a substance is completely burned in oxygen gas. The molar heat of combustion increases with decreasing ring size because smaller rings have a higher strain energy due to the bending and stretching of bond angles. Therefore, the correct answer is E) cyclopropane, which has the smallest ring size among the given options. Cyclopropane has the highest strain energy among the given cycloalkanes due to its bond angles of 60 degrees, which deviate significantly from the optimal bond angle of 109.5 degrees in tetrahedral carbon. As a result, cyclopropane has a higher potential energy than the other cycloalkanes, and it releases more heat when burned, making it the cycloalkane with the greatest molar heat of combustion.

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Answer:

D. CI

Explanation:

a p e x

Chlorine is the element which is not conserved in the given chemical equation AgNO\(_3\) + CaCl\(_2\) → AgCl + CaNO\(_3\). The correct option is option D.

An equation per a chemical reaction is said to be balanced if both the reactants as well as the products have the same number of atoms and total charge for each component of the reaction. In a nutshell, the two components of the reaction have an equal balance of mass and charge.

The components and byproducts of a chemical reaction are listed in an imbalanced chemical equation, but the amounts necessary to meet the conservation of mass are not specified. Chlorine is the element which is not conserved in the given chemical equation AgNO\(_3\) + CaCl\(_2\) → AgCl + CaNO\(_3\).

Therefore, Chlorine is the element which is not conserved in the given chemical equation AgNO\(_3\) + CaCl\(_2\) → AgCl + CaNO\(_3\). The correct option is option D.

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Answer:

cactus

Explanation:

Its a plant so it makes it own food

Answer:

D. The kinetic energy is greater after a substance changes from a

solid to a liquid

Explanation:

During a phase change from solid to liquid, the particles making up the mobile becomes more mobile and as a result there is an increase in kinetic energy of the system.

Answer:

D. The kinetic energy is greater after a substance changes from a solid to a liquid

Explanation:

Answer: .5m

Explanation:

Answer:

1) 5.0 mL, 4.0 mL, 3.0 mL and 2.0 mL respectively.

2) 3.0 mL

Explanation:

Hello there!

1) In this case, by considering that the equation we use for dilutions contain the initial and final concentrations and volumes:

\(C_1V_1=C_2V_2\)

For the first four solutions, we compute the volume of the stock one (V1) as shown below:

\(V_1=\frac{C_2V_2}{C_1}\)

Thus, we obtain:

\(V_1^1=\frac{3.5x10^{-5}M*10.00mL}{7.0x10^{-5}M} =5.0mL\\\\V_1^2=\frac{2.8x10^{-5}M*10.00mL}{7.0x10^{-5}M} =4.0mL\\\\V_1^3=\frac{2.1x10^{-5}M*10.00mL}{7.0x10^{-5}M} =3.0mL\\\\V_1^4=\frac{1.4x10^{-5}M*10.00mL}{7.0x10^{-5}M} =2.0mL\)

2) In this case, for a final concentration of 2.1x10-5 M and a volume of 10.00 mL, the volume of the stock solution would be:

\(V_1=\frac{2.1x10^{-5}M*10.00mL}{7.0x10^{-5}M} =3.0mL\)

Best regards!

The molar concentration of magnesium nitrate in the solution is 0.0350 M.

We can start by calculating the number of moles of magnesium nitrate:

moles of Mg(NO₃)₂ = mass / molar mass

= 0.17 g / (24.305 g/mol + 2x14.007 g/mol + 6x16.00 g/mol)

= 0.00105 mol

Next, we can calculate the molarity (M) of the solution using the formula:

M = moles of solute / volume of solution (in liters)

First, we need to convert the volume from milliliters (mL) to liters (L):

30.0 mL = 0.0300 L

Now we can plug in the values:

M = 0.00105 mol / 0.0300 L

= 0.0350 M

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Answer:

pH → 1.83

Explanation:

Let's write the lactic acid as HLac, because it is a monoprotic weak acid.

HLac + H₂O  ⇄  H₃O⁺  +  Lac⁻      Ka

Initially we have 0.25 moles, so x amount has reacted. At the end, when the equilibrium is finished, we may have (0.25 - x) moles of acid, x moles of protons have been released and x moles of lactate were formed.

In order to find x, we use the acid constant, Ka. The expression for Ka is:

Ka = [H₃O⁺] .  [Lac⁻] / [HLac]

8.3×10⁻⁴  = x² / (0.25-x)

8.3×10⁻⁴ (0.25 - x) = x²

8.3×10⁻⁴ . 0.25 - 8.3×10⁻⁴x - x² → this is a quadractic function

a = -1,  b = 8.3×10⁻⁴, c = 2.07×10⁻⁴

We solve: (-b - √(b² - 4ac) / (2a)

(-8.3×10⁻⁴ - (√ ((8.3×10⁻⁴)² - 4 (-1) (2.07×10⁻⁴) ) / (2 . -1) = 0.0148

[H₃O⁺] = 0.0148 M

- log [H₃O⁺] = pH → - log 0.0148 = 1.83

The pH is defined as the power of Hydrogen. The pH of a 0.25 M solution of lactic acid is 1.83.

\(\bold { CH_3COOH \rightarrow CH_3 COO + H^+\ \ \ \ \ \ \ \ \ \ \ \ (Ka = 8.3 x 10 -4 ).}\)

Initial concentration of lactic acid is 0.25 M,  So, \(x\). At the end of equilibrium \(x\) amount of lactic acid dissociates.

So, concentration of the Hydrogen ion in the (0.25 - \(x\))  

\(x\) can be found out by using the dissociation constant formula,

\(\bold {Ka = \dfrac {[H^+][CH_3COO^-]}{[Ch_3COOH]}}\\\)

\(\bold {8.3x10^-^4= \dfrac {[x][x]}{[2.5- x]}}\\\\\bold {8.3x10^-^4= \dfrac {[x^2]}{[2.5- x]}}\\\\\bold {x^2= 8.3x10^-^4\times [2.5- x]}}\\\\\bold {8.3x10^-^4 \times 0.25 - 8.3x10^-^4 x - x^2 = 0}\)      

The equation above is a quadratic equation, solving it we get,

The concentration of protons = 0.0148 M

Put this into the pH formula,

\(\bold {pH = -log [H^+]}\)

\(\bold {pH = -log [ 0.0148]}\\\\\bold {pH = 1.83}\)

Therefore, the pH of a 0.25 M solution of lactic acid is 1.83.

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Answer:A. Because only two electrons can fit in the first orbit around the nucleus, and each period on the table is organized by number of orbits

Explanation: This is because the The periodic table of elements is designed according to the number of shells from up going down together with  their increasing number of atomic numbers, Now only Hydrogen and Helium have one shell and are therefore the only two elements that should be placed in the first period .

Also note that in filling of their s-orbital, the maximum number of electrons that it can contain is 2 as in 1s²

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Explanation:

First, we need to know that Calcium oxide is:

CaO.

Molar mass of it is:

Ca = 40 g/mol

O = 16 g/mol

CaO = 56 g/mol

To discover the number in moles of 5.45 g of CaO we just need to use the following formula:

n = m/MM

m = 5.45

MM = 56 g/mol

n = 5.45/56

n = 0.09732 moles

Answer:

0.09732 moles

Explanation:

\(v = vdm \times n\)

Vdm=22.4dm.

mole(n)=4 mol

therefore the total volume

\(v = 22.4 \times 4 \\ v = 89.6dm\)

To begin with, sucrose is C12H22O11. Additionally, we must determine how many moles of sucrose there are in a pound of sucrose:

The moles of sucrose are 454g, 342.30g, mol1, and 1.33mol.

Is sucrose a good sugar to use?

Brief Summary According to a University of California, Davis study that was published in the Journal of Clinical Endocrinology and Metabolism, sucrose, the more "natural form of sugar," may be just as harmful to your health as HFCS.

Is sugar a healthy food?

Your body only receives sugar when you consume sucrose like soda or candy, and typically too much of it. The threat is present here. You run the risk of major health problems if you consume too much added sugar (fructose or sucrose) in your diet.

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