Indicate the subatomic particle described by each of the statements. A statement may describe more than one particle. possesses a negative charge has no charge has a mass slightly less than that of a neutron has a charge equal to but opposite in sign to that of an electron is not found in the nucleus Answer Bank has a positive charge proton neutron can be called a nucleon electron is the heaviest of the three subatomic particles has a relative mass of 1836 if the mass of an electron is 1 has a relative mass of 1839 if the mass of an electron is 1

Answer:

8.6 mol

Explanation:

number of moles = molar concentration x volume in litre

number of moles = 2.33 M x 3.70 L = 8.6 mol

Answer:

Explanation:

If sulfur gains 2 electrons then two electrons should be added to it electronic configuration.

When hydrogen bromide (HBr) is added to 2-methylbut-2-ene ((CH3)2CCHCH3), an electrophilic addition reaction takes place, where the π bond of the alkene is broken, and the hydrogen and bromine atoms are added to the resulting carbocation.

The reaction proceeds through a Markovnikov addition, where the hydrogen atom attaches to the carbon atom with the greater number of hydrogen atoms.

In this case, the initial addition of HBr to 2-methylbut-2-ene leads to the formation of a primary carbocation, as the positively charged carbon atom only has one alkyl group attached to it. The primary carbocation is relatively unstable, and it can undergo a rearrangement to form a more stable secondary carbocation.

The major product that is typically obtained is the 2-bromo-2-methylbutane. The hydrogen atom from HBr adds to the carbon with three hydrogen atoms (the more substituted carbon), resulting in the formation of a secondary carbocation.

On the other hand, a minor product is also formed, which is 3-bromo-2-methylbutane. This product arises from the addition of HBr to the primary carbocation, which is less stable. Although the primary carbocation is less favored, it can still be formed and lead to the formation of the minor product.

In summary, the addition of HBr to 2-methylbut-2-ene yields two products: the major product is 2-bromo-2-methylbutane, resulting from the addition of HBr to the more stable secondary carbocation, and the minor product is 3-bromo-2-methylbutane, originating from the less stable primary carbocation.

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The International Union of Pure and Applied Chemistry (IUPAC) provides a standard system for naming organic compounds.

It is essential to learn this nomenclature system to communicate correctly about the chemical structures of compounds and how they relate to each other. Here is the IUPAC name of the following substance.Below is the structure of the given compound: In the given compound, there are four carbon atoms that are connected with single bonds. Carbon atoms are also attached to hydrogen atoms. Since it has four carbons in the main chain, the root name will be "but-". The functional group present in the molecule is the carboxylic acid group (-COOH), which gives the suffix "-oic acid." Therefore, the IUPAC name of the given substance is Butanoic acid.Thus, the IUPAC name of the given compound is Butanoic acid. It is essential to know the IUPAC naming of organic compounds to communicate correctly about the chemical structures of the compounds.

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The amount, in kJ, of heat needed to completely vaporize 50.0g of water at 100°C is 118.8 kJ.

The heat needed to completely vaporize 50.0g of water at 100°C can be calculated using the following formula:

q = m x Hv

where:

First, we need to convert 50.0g to moles by dividing by the molar mass of water which is approximately 18.015 g/mol3:

moles of water = 50.0 g / 18.015 g/mol moles of water = 2.776 mol

Thus:

q = (2.776 mol) x (40.65 kJ/mol) q = 112.8 kJ

In other words, 112.8 kJ of heat is needed to completely vaporize 50.0g of water at 100°C.

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Answer:

Percent yield of reaction is 150%.

Explanation:

Given data:

Percent yield = ?

Actual yield of SO₃ = 586.0 g

Mass of SO₂ = 705.0 g

Mass of O₂ = 80.0 g

Solution:

Chemical equation:

2SO₂ + O₂      →     2SO₃

Number of moles of SO₂:

Number of moles = mass/ molar mass

Number of moles = 586.0 g/ 64.1 g/mol

Number of moles = 9.1 mol

Number of moles of O₂:

Number of moles = mass/ molar mass

Number of moles = 80.0 g/ 32g/mol

Number of moles = 2.5 mol

Now we will compare the mole of SO₃ with O₂ and SO₂.

                      SO₂          :          SO₃

                        2             :            2

                     9.1              :           9.1

                       O₂            :          SO₃

                        1              :            2

                     2.5             :           2×2.5 = 5

The number of moles of SO₃ produced by oxygen are less it will limiting reactant.

Theoretical yield of SO₃:

Mass = number of moles × molar mass

Mass = 5 mol × 80.1 g/mol

Mass = 400.5 g

Percent yield of reaction:

Percent yield = actual yield / theoretical yield  × 100

Percent yield = 586.0 g/ 400.5 g× 100

Percent yield = 1.5× 100

Percent yield = 150%

Answer:

1.1 mol

Explanation:

n=m/M, where n is moles, m is mass, and M is molar mass.

M of CO2 = 12.01+16.00+16.00 = 44.01g/mol

n=50g/44.01g/mol

n = 1.13610543 mol

n ≈ 1.1 mol

Hope that helps

Answer:

Why Heat Causes Tires to Expand and Blow Out

Explanation:

The air pressure in tires increases as the temperature goes up. ... Such a big difference it can cause a tire to pop. Even if it doesn't give out, over-inflation can cause a tire to prematurely wear and interfere with braking.

Answer:

send a pic or more info

Explanation:

The electronic configuration of Y and Z are:

The compound formed by Y and Z will have the formula YZ₃ and the structure is given in the attached image.

An element's electron configuration explains how the electrons are dispersed throughout its atomic orbitals. Atomic electron configurations are stated using a standard notation that arranges all electron-containing atomic subshells in list order, with the number of electrons each shell can house written in superscript.

The orbitals in which the electrons are distributed in atoms of elements are:

The elements Y and Z with atomic numbers 13 and 9 respectively have the following electronic configurations:

Y = 1s²2s²2p⁶3s²3p¹ ( belongs to group 3)

Z = 1s²2s²2p⁵ (belongs to group 7)

The compound formed by Y and Z will be YZ₃.

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Answer:

I believe its 1,2, and 5

Explanation:

C D E

temperature of medium

type of wave

type of medium

Answer:

density

Explanation:

Density is an important measurement. It has an unit: g/mL or kg/L, ...

Evaporation, freezing, melting are the processes in which the substances change their states. Other processes are: condensation, sublimation, deposition.

...

Hope this answer can help you. Have a nice day!

The flow rate of the IV solution in drops per minute is 80 drops/min.

To determine the flow rate in drops per minute, we need to consider the conversion factors and relationships between different units.

First, let's convert the lidocaine dose from grams to milligrams, as the flow rate is given in milligrams per minute:

1 gram = 1000 milligrams

So, 1.0 gram of lidocaine is equal to 1000 milligrams.

Next, we can calculate the total volume of the IV solution in milliliters:

250 mL

To find the flow rate in milligrams per minute, we divide the dose by the total time:

Flow rate = Dose / Time

The dose is 1000 milligrams (1.0 gram) and the time is 1 minute.

Flow rate = 1000 mg / 1 min = 1000 mg/min

Now, to determine the flow rate in drops per minute, we need to convert the IV solution volume from milliliters to drops. Given that 20 drops = 1.0 mL, we can set up a conversion factor:

20 drops / 1 mL

To find the flow rate in drops per minute, we multiply the flow rate in milligrams per minute by the conversion factor:

Flow rate (drops/min) = Flow rate (mg/min) * Conversion factor

Flow rate (drops/min) = 1000 mg/min * (20 drops / 1 mL)

Now we need to convert milliliters to drops:

Flow rate (drops/min) = 1000 mg/min * (20 drops / 250 mL)

Simplifying the expression:

Flow rate (drops/min) = 1000 mg/min * (4/50)

Flow rate (drops/min) = 80 drops/min

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Answer:

Volume = 3.4 L

Explanation:

In order to calculate the volume of CO₂ produced when 15.2 g of CaCO₃ is heated, we need to first write out the balanced equation of the thermal decomposition of CaCO₃:

CaCO₃ (s) + [Heat] ⇒ CaO (s) + CO₂ (g)

Now, let's calculate the number of moles in 15.2 g CaCO₃:

mole no. = \(\mathrm{\frac{mass}{molar \ mass}}\)

                 = \(\frac{15.2}{40.1 + 12 + (16 \times 3)}\)

                 = 0.1518 moles

From the balanced equation above, we can see that the stoichiometric molar ratios of CaCO₃ and CO₂ are equal. Therefore, the number of moles of CO₂ produced is also 0.1518 moles.

Hence, from the formula for the number of moles of a gas, we can calculate the volume of  CO₂:

mole no. = \(\mathrm{\frac{Volume \ in \ L}{22.4}}\)

⇒ \(0.1518 = \mathrm{\frac{Volume}{22.4}}\)

⇒ Volume = 0.1518 × 22.4

                 = 3.4 L

Therefore, if 15.2 g of CaCO₃ is heated, 3.4 L of CO₂ is produced at STP.

Answer:

One carbon atom and the nitrogen atom have nonzero formal charges.

Explanation:

The compound Acetonitrile has sixteen valence electrons as is easily San from its structure. It contains a carbon nitrogen triple bond with a lone pair of electrons on nitrogen. All atoms satisfy the octet rule and there is no hyper valent atom in the molecule.

The formal charge an carbon and nitrogen is calculated as follows;

No. of valence electron on atom - [non bonded electrons + no. of bonds]

Therefore, for carbon and nitrogen, we have;

formal charge on carbon = 4 - (0 + 4) = 0

formal charge on nitrogen = 5 - (2 + 3) = 0

Hence carbon and nitrogen both possess zero formal charges.

The statement that is true of a Lewis base is that a Lewis base donates electron pairs (option A).

A Lewis base is any nucleophylic compound that can donate a pair of electrons and form a coordinate covalent bond.

On the other hand, a Lewis acid is any electrophylic compound that can accept a pair of electrons and form a coordinate covalent bond.

This means that a Lewis base can donate a pair of electrons to a Lewis acid to form a product containing a coordinate covalent bond. This product is also referred to as a Lewis adduct.

Therefore, option A is correct about Lewis base

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Answer:

1-6

3 1 3 3 2 2

Explanation:

Isotopes are defined as same atomic number and different mass number. Two isotopes of hydrogen they have different numbers of neutrons.

Isotopes are two or more different kinds of atoms that have the same atomic number and place in the periodic table but have different numbers of neutrons in their nucleus, resulting in differing nucleon numbers.

Isotopes are atoms that are part of the same element and have the same atomic number Z but a different mass number A. For instance, three isotopes of the element carbon, having respective masses of 12, 13, and 14, are carbon-12, carbon-13, and carbon-14.

Thus, Two isotopes of hydrogen they have different numbers of neutrons.

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Answer:

They have different numbers of neutrons.

Explanation

Explanation:

because carbon atom can move its particle

The best description of the relationship between population size, carrying capacity, and limiting factors is: "The size of a population usually stays near its carrying capacity due to limiting factors."

Carrying capacity refers to the maximum number of individuals that a particular environment can sustainably support. It represents the limit to which a population can grow given the available resources, such as food, water, and habitat. Limiting factors, on the other hand, are the factors that restrict population growth by reducing birth rates, increasing death rates, or limiting access to resources.As a population approaches its carrying capacity, limiting factors come into play and regulate the population size. These limiting factors can include competition for resources, predation, disease, availability of suitable habitat, and other environmental factors. They act as checks on population growth, preventing it from exceeding the carrying capacity of the ecosystem.

Therefore, the size of a population usually stays near its carrying capacity because the limiting factors ensure that the population does not exceed the available resources and ecological limits of the environment. If the population surpasses the carrying capacity, the limiting factors will intensify, causing a decline in resources and an increase in mortality rates, which ultimately brings the population back towards the carrying capacity.It's important to note that the relationship between population size, carrying capacity, and limiting factors is dynamic and can vary depending on various ecological and environmental factors.

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Answer:

i) The size of X ion is greater than that of X atom even though both contain the same number of protons because the ion has fewer electrons compared to the atom. When an atom forms an anion (negative ion), it gains electrons, which causes increased electron-electron repulsion. This repulsion causes the electron cloud to expand, and as a result, the ion becomes larger than the neutral atom.

In the case of element X, when it forms an ion with a -3 charge, it will gain 3 more electrons, increasing the total number of electrons to 18. This will cause the size of the X ion to be larger than the neutral X atom.

ii) To determine the compound of X in the -3 oxidation state, we first need to determine the element's identity. We know that X has 15 electrons in total (2 in the K shell, 8 in the L shell, and 5 in the M shell). Therefore, X has an atomic number of 15, which corresponds to phosphorus (P).

Since phosphorus is in the -3 oxidation state, it gains 3 electrons and becomes P^3-. To form a compound, we need a cation that can balance the negative charge. A common example is aluminum (Al), which has a +3 charge (Al^3+). When phosphorus and aluminum combine, they form the compound aluminum phosphide with the formula AlP.

The growth of the new plant depicts the asexual reproduction characteristic. The characteristic that describes the growth of the new plant in Stephan's mother cutting a twig from a rose bush and planting it in the soil is asexual reproduction.

Asexual reproduction is the mode of reproduction by which organisms generate offspring that are identical to the parent's without the fusion of gametes. Asexual reproduction is a type of reproduction in which the offspring is produced from a single parent.

The offspring created are clones of the parent plant, meaning they are identical to the parent.The new plant in Stephan’s mother cutting a twig from a rose bush and planting it in the soil depicts the process of asexual reproduction, which is the ability of a plant to reproduce without seeds. In asexual reproduction, plants can reproduce vegetatively by cloning themselves using their roots, bulbs, or stems.

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Answer:

Fire is a chemical hazard, because of explosives and nukes. Falling debris is physical, difficulty breathing is a biological hazard, and fungi, pesticides, and cockroaches are biological as well. Muriatic acid is chemical, so is bleach. And any vibrations and noises or corrosion are physical.

The change in temperature for the silicon is 7.042°C.

The change in temperature of a substance can be calculated by using the following formula:

Q = mc∆T

Where;

According to this question, 125 J of energy are released when 25.0 g Si comes into contact with cold water.

125J = 25 g × 0.71 J/g K × ∆T

125 = 17.75∆T

∆T = 125/17.75

∆T = 7.042°C

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Answer: There are 0.373 kJ in 373 joules.

Explanation:

According to the standard conversion units 1 kJ is equal to 1000 J. This means that 1 J is equal to 0.001 kJ.

Hence, 373 joules is converted into kilojoules as follows.

\(1 J = 0.001 kJ\\373 J = 373 J \times \frac{0.001 J}{1 kJ}\\= 0.373 kJ\)

Thus, we can conclude that there are 0.373 kJ in 373 joules.

Answer:

C6H12O6

Explanation:

C6H12O6

Answer:

5

Explanation:

2P₂O₅=P₄+5O₂

There is no reason to run these solutes at the 20 MWCO because they are both much smaller than the MWCO of the membrane.

The MWCO (molecular weight cut off) is the molecular weight of a solute at which it will be retained by a membrane during a process such as ultrafiltration or dialysis. If a solute has a molecular weight higher than the MWCO of a membrane, it will be retained and not pass through the membrane. If the molecular weight of a solute is lower than the MWCO, it will pass through the membrane.

In this case, glucose has a molecular weight of 180 g/mol (6 carbons x 12 g/mol per carbon + 6 oxygens x 16 g/mol per oxygen) and albumin has a molecular weight of approximately 81,942 g/mol (607 amino acids x 135 g/mol per amino acid). Both of these solutes have molecular weights that are much lower than 20,000 g/mol, which is a typical MWCO for ultrafiltration or dialysis membranes.

They would both easily pass through the membrane and be lost during the process. Instead, a membrane with a much lower MWCO would be needed if we wanted to retain these solutes during a process such as ultrafiltration or dialysis.

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The sodium chloride solution would melt at a high temperature and conduct electricity but the sucrose would not do any of these.

The conductivity test is the test that can be use to determine which of the substances can be able to conduct electricity. The substance that can be able to conduct electricity must be ionic in nature and would also have a high melting point.

a) If we dissolve the two substances in water and then connect an external cell to it, we would notice that the sodium chloride solution would conduct electricity but the sucrose solution would not.

b) On the other hand, the sodium chloride solution would be found to melt at a much higher temperature than the sucrose.

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Explanation:

Common Lead Storage Battery Used In Automobiles, The Following Two Half-reactions Occur In Acid Solution: Oxidation Pb(s)+HSO−4(aq) → PbSO4(s) Reduction PbO2(s)+HSO−4(aq) → PbSO4(s). Write A Balanced Equation For The Overall Battery Reaction.