Is a lump of coal chemical energy

Answer:

- t = 3.12s

- x = 40.19m

- h_max = 11.97m

Explanation:

- In order to calculate the flight time of the body, you use the following formula:

\(t=\frac{2v_o sin\theta}{g}\)         (1)

vo: initial speed  = 20m/s

g: gravitational acceleration = 9.8 m/s^2

θ: angle with the horizontal of the direction of the motion of the body = 50°

You replace the values of the parameters in the equation (1):

\(t=\frac{2(20m/s)sin50\°}{9.8m/s^2}=3.12s\)

The flight time of the body is 3.12s

- The maximum range of the motion is given by:

\(x=v_xt=v_ocos\theta t\\\\x=(20m/s)(cos50\°)(3.12s)=40.19m\)

where you have used the flight time.

The maximum horizontal distance traveled by the body us 40.19m

- The maximum height is:

\(h_{max}=\frac{v_o^2sin^2\theta}{2g}\)              (2)

you replace the values of the parameters:

\(h_{max}=\frac{(20m/s)^2sin^250\°}{2(9.8m/s^2)}=11.97m\)

The maximum height is 11.97 m

Answer:

Momento = 170.8 Kgm/s

Explanation:

Dados los siguientes datos;

Masa = 3,05 kg

Velocidad = 56 m/s

Para encontrar el impulso;

El momento se puede definir como la multiplicación (producto) de la masa que posee un objeto y su velocidad. El momento se considera una cantidad vectorial porque tiene magnitud y dirección.

Matemáticamente, el momento viene dado por la fórmula;

\( Momento = masa * velocidad \)

Sustituyendo en la fórmula, tenemos;

\( Momento = 3.05 * 56 \)

Momento = 170.8 Kgm/s

Answer:

\(9.5\; {\rm m}\).

Explanation:

Let \(u\) and \(v\) denote the velocity of this hockey player before and after stopping, respectively. The question states that \(u = 9.5\; {\rm m\cdot s^{-1}}\) and implies that \(v = 0\; {\rm m\cdot s^{-1}\) since the hockey player has come to a stop.

The duration of this acceleration is \(t = 2\; {\rm s}\).  

Since the acceleration of this hockey player was constant, SUVAT equation would apply. In particular, the SUVAT equation \(x = (1/2)\, (v + u) \, (t)\) gives the displacement \(x\) of this hockey player during that \(2\; {\rm s}\) of acceleration:

\(\begin{aligned} x &= \frac{1}{2}\, (9.5\; {\rm m\cdot s^{-1}} + 0\; {\rm m\cdot s^{-1}})\, (2\; {\rm s}) = 9.5\; {\rm m} \end{aligned}\).

In other words, this hockey player would have travelled \(9.5\; {\rm m}\) while stopping.

Answer:ur mom

Explanation:because

Answer:

True

Explanation:

It is true that. A technician can be electrocuted when working on HEVs or EVs, therefore the correct answer is option A

An EV stands for an electric vehicle. Electric vehicles (EVs) are autos that are powered totally or partially by electricity. Electric cars are extremely cost-effective to run because they have fewer moving parts to maintain and use little to no fossil fuels (petrol or diesel).

When evaluating its environmental impact, every factor must be taken into consideration. Considering that EVs have a minimal overall environmental impact, this suggests that the severity of these production emissions decreases.

Recycling is one strategy for lowering the lifespan emissions of electric vehicles. Again, incorrect assumptions can be refuted by facts.

Thus, That is accurate. The correct response is option A because a technician could electrocute themselves while working on HEVs or EVs.

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The amount of work done by the drag force on the rocket during its ascent is -206.64 J.

The work done by the drag force on the rocket during its ascent can be calculated using the work-energy theorem, which states that the change in kinetic energy of an object is equal to the net work done on it. In this case, the net work is the sum of the work done by the thrust force and the work done by the drag force.

The change in kinetic energy of the rocket is the difference between its initial and final kinetic energies:

ΔKE = KEf - KEi

Since the rocket starts from rest and reaches its peak height with zero velocity, both the initial and final kinetic energies are zero:

ΔKE = 0 - 0 = 0

The work done by the thrust force is the product of the force and the displacement:

Wt = Ft × d = (12.3 N) × (16.8 m) = 206.64 J

The work done by the drag force is the unknown value we are trying to find:

Wd = ?

Using the work-energy theorem, we can solve for the work done by the drag force:

ΔKE = Wt + Wd

0 = 206.64 J + Wd

Wd = -206.64 J

Therefore, the work done by the drug force is -206.64 J. This negative value indicates that the drag force is acting in the opposite direction of the rocket's motion, slowing it down.

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a. The current in the loop is 11.38 A.

b. The distance from the wire at which the magnetic field is 2.70 mT is 2.70 m.  

The current in the loop, we can use the formula:

I = μ * N / A

First, we need to find the number of turns in the loop. The diameter of the loop is given, so we can find its circumference:

C = π * D

here C is the circumference and D is the diameter.

The circumference of the loop is:

C = π * 0.900 cm = 7.85 cm

The number of turns in the loop is then:

N = C / A

here A is the area of the loop.

The area of the loop is:

A = π * (0.900 cm) = 0.729 cm

Substituting these values into the formula for the current, we get:

I = μ * N / A

= μ * (7.85 cm / 0.729 cm)

= 11.38 A

Therefore, the current in the loop is 11.38 A.

To find the distance from the wire at which the magnetic field is 2.70 mT, we can use the formula:

B = μ * I * L

First, we need to find the length of the wire. The current in the wire is given, so we can find its cross-sectional area:

A = I / π

here A is the cross-sectional area and I is the current in the wire.

The cross-sectional area of a straight wire is proportional to its diameter, so we can use the diameter of the loop to find the cross-sectional area of the wire:

A = π * D / 2

here D is the diameter of the loop.

A = π * 0.900 cm / 2

= 0.682 cm

The cross-sectional area of the wire is therefore 0.682 cm.

The magnetic field is given, so we can find the distance from the wire at which it is 2.70 mT using the formula:

B = μ * I * L

= μ0 * 11.38 A * 2.70 m

= 31.37 mT

Therefore, the distance from the wire at which the magnetic field is 2.70 mT is 2.70 m.  

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Answer:

ikr same.....lol......

The wavelength range of the instrument is from 0.086 meters to 12.7 meters.

The frequency range of the sound waves emitted by an instrument is 27 Hz to 3980 Hz. The wavelength of a wave is inversely proportional to its frequency. This means that the lower the frequency, the longer the wavelength, and the higher the frequency, the shorter the wavelength.The formula for wavelength is:λ = v/f, where v is the speed of sound in air and f is the frequency of the sound wave.Substituting the given values:λ = 343 m/s / 27 Hz = 12.7 mλ = 343 m/s / 3980 Hz = 0.086 mTherefore, the range of wavelengths spanned by the instrument is from 0.086 meters to 12.7 meters.

The range of wavelengths spanned by the instrument is from 0.086 meters to 12.7 meters. The formula for wavelength is λ = v/f, where v is the speed of sound in air and f is the frequency of the sound wave. The wavelength is inversely proportional to the frequency of the wave.

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In order to find out which substance would raise in temperature most quickly, Mr. Chang's class conducted a scientific experiment outside in the sunlight using three different substances.

If particles of each substance were permitted to sit in the sun for 10 minutes, how would their motion be described? B. Physical alterations are non-chemical changes that are made to an item or substance. They alter an object's physical characteristics, such as its size, color, texture, volume, or density. To find out more about the science underlying the treat or to find some more at-home experiments, see the resources listed below. Just keep in mind that science is best when it is shared, so tell your friends about your experiment.

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Answer:

April

Explanation:

Answer:

The final velocity is 50 m/s.

Explanation:

Below is the calculation of velocity:

v = u + a*t

v = final velocity

u = initial velocity

a = accreleration

Since, u = 0, a = 10m/s^2, and t = 5 seconds. Now plug these values in the formula.

v = u + a*t

v = 0 + 10 x 5

v = 50 m/s

The final velocity is 50 m/s.

Answer:

C.

Explanation:

Because the speed pf the boat will depends of the driver.

30.05 sec much time it takes for the amplitude to decay to 43.2 percent of its original initial value

The greatest displacement or distance that a point on a wave or vibrating body may travel in relation to its equilibrium position It is equivalent to the vibration path's half-length.

Given data

Time period (T) = 2.84 sec

Reduction  = 93.6  %

We know that logarithmic decrement is given by:

a₁ = a₀ \(e^-{bt}\)

where b = constant

As a₁ = 0.936 a₀

or, 0.936 a₀ = a₀ \(e^-{b*2.84}\)

or, b = 0.002

Now a₁  = 0.432 a₀

or, 0.432 a₀ = a₀ \(e^-{0.002*t}\)

or, t = 30.05 sec

So, it will take 30.05 sec to decay 43.2 %.

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Answer:

6,400

Explanation:

i made sure  the other person was right and i got the same answer

To construct an inductor of a given inductance using copper wire and a plastic tube, the student will also need a magnetic core.

An inductor is a passive electronic component that is used to store energy in a magnetic field. It consists of a coil of wire wound around a magnetic core, which is usually made of a ferromagnetic material such as iron or ferrite. The magnetic core enhances the magnetic field created by the coil and increases the inductance of the inductor.

The plastic tube can be used to create a form for the coil of wire. The copper wire will be wound around the plastic tube to create the coil. However, without a magnetic core, the inductance of the coil will be very low, and it may not function as an inductor at all.

The choice of magnetic core material will depend on the specific application and the frequency range of the circuit. In some cases, air can be used as the core material, but in most cases, a magnetic material is required to achieve the desired level of inductance.

In summary, to construct an inductor of a given inductance using copper wire and a plastic tube, the student will need a magnetic core in addition to the copper wire and plastic tube.

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Answer: 500 ft

Explanation:

High beam headlights help one to see better at night as the range of vision is greatly expanded. They can however, blind drivers coming on the opposite lane.

It is therefore prudent to ensure that when using high beam headlights, you dim them when a car is coming towards you. The appropriate distance to do so is a minimum of 500 ft from the car.

This lab is investigating the relationship between mass, Speed , and momentum.

Momentum is manufactured from the mass and speed of an object. it's miles a vector quantity, owning a significance and a direction. If m is an object's mass and v is its speed, then the object's momentum is p.

Momentum in an easy way is a quantity of movement. right here amount is measurable because if an item is moving and has mass, then it has momentum. If an object no longer flows then it has no momentum. however, in regular existence, it has an important but many people didn't understand it.

Momentum gives the connection between the mass, pace, and direction of an object. Any exchange in momentum results in pressure. So, an exchange in momentum is used to determine the force appearing upon the item.

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The human eye can detect objects that are 30 centimeters apart at a distance of 1 kilometer owing to its approximately 1 arcminute angular resolution.

The human eye has a maximum angular resolution of 28 arc seconds, or 0.47 arc minutes. As a result, at a distance of 1 kilometer, we are unable to resolve things smaller than 30 cm. The closer the object is placed; more distinguishable it appears to the eyes.

Angle resolution is one of the limits to which your eyes can see. Light rays that are reflected off or produced by things are visible to your eye. These light rays enter your pupil and are focused on your retina by your eye's lens. Depending on the angle at which the corresponding light beams from two items interact, your pupil size—which is comparable to the aperture of a camera—determines how well you can distinguish between two objects.

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Complete question:

the human eye has an angular resolution of roughly 1 arcminute. which of the following objects are we not able to resolve, and uses the unit of arcminute correctly?

Objects closer than 1 km

Objects away from the vision

Objects at a distance of 2 km

Objects just near to eyes

Energy is transported from the tropics to the polar regions chiefly by ocean and atmospheric currents.

Ocean currents transport thermal energy from the tropics to the polar regions, while atmospheric currents transport latent and sensible heat from the tropics to the polar regions. These transfers occur through different mechanisms that rely on Earth's rotation, wind patterns, and temperature differences. The primary way in which energy is transported from the tropics to the polar regions is through ocean currents, particularly the ocean conveyor belt. This is a system of currents that circulate in the Atlantic Ocean and are driven by differences in temperature and salinity. Warm water from the tropics flows northward, where it cools and sinks, eventually returning southward at depth. This circulation helps to regulate the climate of both the tropics and the poles. Atmospheric currents also play a role in the transport of energy from the tropics to the polar regions. Warm, moist air rises in the tropics and flows poleward at high altitude, where it cools and descends. This creates a circulation pattern known as the Hadley cell, which drives the trade winds and helps to distribute heat around the globe. In the polar regions, cold, dry air descends and flows equatorward at low altitude, completing the circulation pattern.

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(a) The hydrostatic pressure is 28,490 Pa.

(b) At the bottom the force is 1,139,600 N.

(c)  At the end the force is 1,621,200 N.

(a) To find the hydrostatic pressure on the bottom of the tank, we can use the formula:

P = ρgh

where P is the pressure, ρ is the density of the liquid, g is the acceleration due to gravity, and h is the height of the liquid column.

The height of the liquid column is 3.5 m, and the density of kerosene is 820 kg/m3. The acceleration due to gravity is 9.8 m/s2. Therefore, we have:

P = 820 kg/m3 * 9.8 m/s2 * 3.5 m = 28,490 Pa

So the hydrostatic pressure on the bottom of the tank is 28,490 Pa.

(b) To find the hydrostatic force on the bottom of the tank, we can use the formula:

F = PA

where F is the force, P is the pressure, and A is the area. The area of the bottom of the tank is:

A = 10 m * 4 m = 40 m2

Using the pressure we found in part (a), we have:

F = 28,490 Pa * 40 m2 = 1,139,600 N

So the hydrostatic force on the bottom of the tank is 1,139,600 N.

(c) To find the hydrostatic force on one end of the tank, we need to first find the pressure on that end. The pressure on any point of the tank is given by:

P = ρgh

where h is the vertical distance from the point to the surface of the liquid.

The pressure on one end of the tank will depend on the distance of that end from the surface of the liquid. Let's assume that the end we are interested in is at the same level as the surface of the liquid. Then the pressure on that end is simply the atmospheric pressure, which we will assume is 101,325 Pa.

The area of one end of the tank is:

A = 4 m * 4 m = 16 m2

Using the pressure we found and the area of the end, we have:

F = 101,325 Pa * 16 m2 = 1,621,200 N

So the hydrostatic force on one end of the tank is 1,621,200 N.

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With the projectile launch we can find that the response for the initial velocity of the salmon is  3.68 m/s

Projectile launching is an application of kinematics for movement in two dimensions.  In this case they indicate the jump distance x = 2.61 m and the jump height y = 0.277 m and the angle of 39.3º and ask the initial velocity.

Let's use trigonometry for the initial velocity.

              cos 39.3 = \(\frac{v_x}{v}\)

              sin 39.3 = \(\frac{v_y}{v}\)

              vₓ = v cos 39.3

              = v sin 39.3

Suppose that when you reach the height of the waterfall you are in the highest part of the jump, therefore the vertical velocity is zero.

                \(v_y^2 = v_{oy}^2 -2 g y\)

                 0 = - 2 g y

                 \(v_{oy}\) = \(\sqrt{2gy}\)

Let's calculate

                 \(v_{oy} = \sqrt{2 \ 9.8 \ 0.277}\)

                  = 2.33 m / s

The relationship of the initial velocity and the angle.

                    = v sin 39.3

                   v = \(\frac{ v_{oy}}{son 39.3}\)

                   v = 2.33 / sin 39.3

                   v = 3.68 m / s

In conclusion using projectile launch we can find the initial velocity of the salmon is 3.68 m / s.

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Answer:

20

Explanation:

force=work done÷distance

Answer:

The Brewster's angle, also known as the polarization angle, is the of incidence which allows the incident light to be transmitted perfectly through the dielectric surface, without reflection. This is given by,

The momentum of a 2kg mass moving at 25 m/s is 50kgm/s.

Momentum in physics refers to the tendency of a body to maintain its inertial motion.

It is the product of its mass and velocity, or the vector sum of the products of its masses and velocities i.e.

p = mass × velocity

According to this question, a 2kg mass is moving at 25 m/s. The momentum of the body can be calculated as follows:

Momentum = 2kg × 25m/s

Momentum = 50kgm/s

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The acceleration 'a' of the tank moving up the inclined plane is 1.238 m/s².

To determine the acceleration 'a' of the tank, we need to consider the given values of x and y and apply the principles of rigid body motion.

By using trigonometry, we can calculate the components of acceleration along the x and y directions.

The acceleration along the y direction is due to the gravitational force acting vertically downwards, which can be calculated as g = 9.8 m/s².

Using the given angle of the inclined plane (30∘), we can find the acceleration along the x direction. By combining the x and y components of acceleration, we can determine the total acceleration 'a' of the tank.

In the context of rigid body motion on an inclined plane, determining the acceleration requires considering the forces acting on the object and applying Newton's second law.

By breaking down the motion into components along the x and y directions, we can analyze the effects of gravity and the inclination of the plane.

The trigonometric relationships between these components enable us to calculate the acceleration 'a' of the tank.

Understanding the principles of rigid body motion and utilizing trigonometry are essential for solving such problems.

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Answer:

XD

Explanation:

XV