is potenial energy the one that moves?

Answer:

Ni

Explanation:

An active metal is a highly reactive metal. Active metals are found high up in the activity series.

Active metals react with other metals that are lower than them in the activity thereby displacing the lower metals from a solution of their salts. This is what may have happened in the other two reactions.

Ni is the most active metal listed in the question since it can react a compounds with Pb(NO3)2(aq) to liberate Pb metal.

Answer:

Explanation:

If a zero is found between significant digits, it is significant

Answer: The element B will have ONE unpaired electron in the p orbital.

Explanation:

The electronic configuration of each given element is as follows.

Atomic number of calcium (Ca) is 20.

Ca: \(1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6} 4s^{2}\)

Atomic number of nitrogen (N) is 7.

N: \(1s^{2} 2s^{2} 2p^{3}\)

Atomic number of boron (B) is 5.

B: \(1s^{2} 2s^{2} 2p^{1}\)

Atomic number of argon (Ar) is 18.

Ar: \(1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6}\)

Atomic number of bromine (Br) is 35.

Br: \([Ar] 4s^{2} 3d^{10} 4p^{5}\)

Therefore, boron is the only element that have one unpaired electron in the p-orbital.

Thus, we can conclude that element B will have ONE unpaired electron in the p orbital.

Answer:

6

Explanation:

lol

Answer:

pH = 12.22

Explanation:

... To make up 170mL of solution... The temperature is 25°C...

The dissolution of Barium Hydroxide, Ba(OH)₂ occurs as follows:

Ba(OH)₂ ⇄ Ba²⁺(aq) + 2OH⁻(aq)

Where 1 mole of barium hydroxide produce 2 moles of hydroxide ion.

To solve this question we need to convert mass of the hydroxide to moles with its molar mass. Twice these moles are moles of hydroxide ion (Based on the chemical equation). With moles of OH⁻ and the volume we can find [OH⁻] and [H⁺] using Kw. As pH = -log[H⁺], we can solve this problem:

Moles Ba(OH)₂ molar mass: 171.34g/mol

0.240g * (1mol / 171.34g) = 1.4x10⁻³ moles * 2 =

2.80x10⁻³ moles of OH⁻

Molarity [OH⁻] and [H⁺]

2.80x10⁻³ moles of OH⁻ / 0.170L = 0.01648M

As Kw at 25°C is 1x10⁻¹⁴:

Kw = 1x10⁻¹⁴ = [OH⁻] [H⁺]

[H⁺] = Kw / [OH⁻] = 1x10⁻¹⁴/0.01648M = 6.068x10⁻¹³M

pH:

pH = -log [H⁺]

pH = -log [6.068x10⁻¹³M]

Radical bromination of (S)-3-methylhexane results in 3-bromo-3-methylhexane as the main byproduct, which is optically inactive. The branching hydrocarbon 3-methylhexane has two enantiomers. It belongs to the family of heptane isomers.

One of heptane's two structural isomers, 2,3-dimethylpentane, and this particular molecule both possess the chirality property. They are (R)-3 methylhexane and (S)-3 methylhexane, respectively. Bromomethane is the natural product. This is a substitution process because one of the hydrogen atoms in the methane has been swapped out for a bromine atom. Enantiomers are stereoisomers that cannot be superimposed mirror images of one another. Depending on how each stereocenter is set up, enantiomers are different. In terms of handedness, they can be compared to gloves for the right or left hand.

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Answer:

1.29

Explanation:

You have to find the equation which is d=m/v. d is 9.43=12.2/v. You have to solve for v which you get 1.29

1.29 \(cm^3\) is the volume of a 12.2 g piece of metal with a density of 9.43 g/cm.

Density is the measurement of how tightly a material is packed together.

Density =Mass ÷ volume

9.43=12.2 ÷  V

V = 1.29 \(cm^3\)

Hence, 1.29 \(cm^3\) is the volume of a 12.2 g piece of metal with a density of 9.43 g/cm.

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The word "symptom" refers to a specific manifestation or indication of a condition, disease, or disorder that is experienced or observed by an individual.

Symptoms are subjective or objective changes in the body's normal functioning that may be recognized as abnormal, uncomfortable, or problematic. Symptoms can manifest in various ways depending on the nature of the underlying condition. They can be physical, such as pain, rash, cough, fever, or fatigue, indicating an illness or injury affecting the body. Symptoms can also be psychological, such as anxiety, depression, or confusion, reflecting disturbances in mental health.

Symptoms serve as important clues for medical professionals to identify and diagnose diseases or disorders. They provide valuable information about the nature, severity, and progression of an illness, helping healthcare providers formulate appropriate treatment plans. Additionally, symptoms may also be important for individuals to self-assess their own health status and seek appropriate medical attention.

It is essential to note that symptoms alone may not provide a definitive diagnosis, as they can overlap across different conditions. Further evaluation, including medical tests and examinations, is often necessary to confirm a diagnosis and determine the appropriate course of action.

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IUPAC (International Union of Pure and Applied Chemistry) naming is also known as systematic naming.

It is a set of rules and guidelines used to name chemical compounds systematically. It provides a standardized method for naming organic and inorganic compounds based on their molecular structure and composition.

The longest continuous carbon chain in the compound is identified as the parent chain.

The IUPAC name of the given compounds are:

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Answer:

C. Strong nuclear force.

Explanation:

First, let's review the definitions of the given concepts of the group of answer choices:

- Electrostatic force: It's the interaction that occurs between electrically charged particles (positive and negative charges).

- Force of gravity: is a fundamental interaction where there is a mutual attraction between all things that have mass or energy.

- Strong nuclear force: is what keeps nuclei together (protons and neutrons together).

- Weak nuclear force: this force is responsible for particle decay.

Based on these definitions, the force that holds the nucleus together would be C. Strong nuclear force.

Hello,

During telophase, the cell, each pole of which inherits the same number of single  chromosomes, begins to divide into 2: this is  cytodieresis.

Answer:

Concepts and reason

Lewis structure is a structure that explains the bonding between atoms of a molecule and lone pair of electrons that is present in the molecule is called a Lewis structure.

With the help  of Lewis structure the electronic geometry of a molecule can be determine.

Fundamentals

According to Lewis structure, every atom and their position in the structure of a molecule by using its chemical symbol.

Lines connecting the atoms that are bonded to them are drawn. Lone pairs are expressed by pairs of dots and are located beside the atoms.

Lewis structure  of \(H_{2}O\) is, the total number of valence electrons is eight in \(H_{2}O\).

4.41 × 10⁻⁴⁵m is the wavelength of the photon and the energy correspond to red color.

The term wavelength is defined as the distance between two identical points that are adjacent crests and troughs.

The SI unit of wavelength is metre mostly represented as m.

The wavelength is mostly represented by λ is the Greek letter lambda.

Given:

E =  4.50x10⁻¹⁹ J/photon

h = Planck constant = 6.626 × 10⁻³⁴

ν = ?

E = hν

ν = E/h

By substituting the values in above question and we get,

= 4.50x10^-19 /  6.626 × 10⁻³⁴

=  0.679 × 10⁻¹⁵

c = 3 × 10⁸

E = hc/λ

λ = hc/E

By substituting the values in above question and we get,

λ = 6.626 × 10⁻³⁴ ×  3 × 10⁸ / 4.50x10⁻¹⁹

λ = 4.41 × 10⁻⁴⁵m

Thus, the wavelength of the photon is 4.41 × 10⁻⁴⁵m and color does this energy correspond to red.

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The energy of combustion for one mole of butane to be approximately 2888.81 kJ/mol.

To calculate the energy of combustion for one mole of butane (C4H10), we need to use the information provided and apply the principle of calorimetry.

First, we need to convert the mass of the butane sample from grams to moles. The molar mass of butane (C4H10) can be calculated as follows:

C: 12.01 g/mol

H: 1.01 g/mol

Molar mass of C4H10 = (12.01 * 4) + (1.01 * 10) = 58.12 g/mol

Next, we calculate the moles of butane in the sample:

moles of butane = mass of butane sample / molar mass of butane

moles of butane = 0.367 g / 58.12 g/mol ≈ 0.00631 mol

Now, we can calculate the heat released by the combustion of the butane sample using the equation:

q = C * ΔT

where q is the heat released, C is the heat capacity of the calorimeter, and ΔT is the change in temperature.

Given that the heat capacity of the bomb calorimeter is 2.36 kJ/°C and the change in temperature is 7.73 °C, we can substitute these values into the equation:

q = (2.36 kJ/°C) * 7.73 °C = 18.2078 kJ

Since the heat released by the combustion of the butane sample is equal to the heat absorbed by the calorimeter, we can equate this value to the energy of combustion for one mole of butane.

Energy of combustion for one mole of butane = q / moles of butane

Energy of combustion for one mole of butane = 18.2078 kJ / 0.00631 mol ≈ 2888.81 kJ/mol

Therefore, the energy of combustion for one mole of butane is approximately 2888.81 kJ/mol.

In conclusion, by applying the principles of calorimetry and using the given data, we have calculated the energy of combustion for one mole of butane to be approximately 2888.81 kJ/mol.

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The empirical formula is KCO2

Explanation:

As with all these problems, we assume a

100

⋅

g

mass of unknown compound, and then we work out the molar quantity:

Moles of potassium

=

47.0

⋅

g

39.10

⋅

g

⋅

m

o

l

−

1

=

1.20

⋅

m

o

l

Moles of carbon

=

14.5

⋅

g

12.011

⋅

g

⋅

m

o

l

−

1

=

1.21

⋅

m

o

l

Moles of oxygen

=

38.5

⋅

g

16.0

⋅

g

⋅

m

o

l

−

1

=

2.41

⋅

m

o

l

We divide thru by the smallest molar quantity to give the empirical formula:

K

C

O

2

.

Now the molecular formula is always a whole number of the empirical formula:

i.e.

molecular formula

=

n

×

empirical formula

And thus with the molecular mass, we can solve for

n

.

166.2

⋅

g

⋅

m

o

l

−

1

=

n

×

(

39.1

+

12.011

+

2

×

16.00

)

⋅

g

⋅

m

o

l

−

1

166.2

⋅

g

⋅

m

o

l

−

1

=

n

×

(

83.1

)

⋅

g

⋅

m

o

l

−

1

Clearly,

n

=

2

, and the

molecular formula

=

K

2

C

2

O

4

The compound is LIKELY the potassium salt of oxalic acid,

K

+

−

O

(

O

=

)

C

−

C

(

=

O

)

O

−

K

+

, i.e.

potassium oxalate.

Answer linkExplanation:

As with all these problems, we assume a

100

⋅

g

mass of unknown compound, and then we work out the molar quantity:

Moles of potassium

=

47.0

⋅

g

39.10

⋅

g

⋅

m

o

l

−

1

=

1.20

⋅

m

o

l

Moles of carbon

=

14.5

⋅

g

12.011

⋅

g

⋅

m

o

l

−

1

=

1.21

⋅

m

o

l

Moles of oxygen

=

38.5

⋅

g

16.0

⋅

g

⋅

m

o

l

−

1

=

2.41

⋅

m

o

l

We divide thru by the smallest molar quantity to give the empirical formula:

K

C

O

2

.

Now the molecular formula is always a whole number of the empirical formula:

i.e.

molecular formula

=

n

×

empirical formula

And thus with the molecular mass, we can solve for

n

.

166.2

⋅

g

⋅

m

o

l

−

1

=

n

×

(

39.1

+

12.011

+

2

×

16.00

)

⋅

g

⋅

m

o

l

−

1

166.2

⋅

g

⋅

m

o

l

−

1

=

n

×

(

83.1

)

⋅

g

⋅

m

o

l

−

1

Clearly,

n

=

2

, and the

molecular formula

=

K

2

C

2

O

4

The compound is LIKELY the potassium salt of oxalic acid,

K

+

−

O

(

O

=

)

C

−

C

(

=

O

)

O

−

K

+

, i.e.

potassium oxalate.

Answer:

Chemical elements.

Answer:

3.1

speed is distance over time, cross multiply

Answer:

To calculate Δ∘rxn, we can use the following formula:

ΔG∘rxn = ΔH∘rxn - TΔS∘rxn

where ΔH∘rxn is the enthalpy change of the reaction, T is the temperature in Kelvin, and ΔS∘rxn is the entropy change of the reaction.

We know that ΔH∘rxn = -44.2 kJ and we want to find ΔS∘rxn at 25.0 ∘C (298 K). We can use the following formula to calculate ΔS∘rxn:

ΔG∘rxn = -RTlnK

where R is the gas constant (8.314 J/mol K), T is the temperature in Kelvin, and K is the equilibrium constant.

We can find K using the following formula:

ΔG∘rxn = -RTlnK K = e^(-ΔG∘rxn/RT)

We know that ΔG∘rxn = -44.2 kJ/mol and R = 8.314 J/mol K, so we can calculate K:

K = e^(-(-44.2 kJ/mol)/(8.314 J/mol K * 298 K)) K = 1.9 x 10^7

Now we can use K to calculate ΔS∘rxn:

ΔG∘rxn = -RTlnK ΔS∘rxn = -(ΔH∘rxn - ΔG∘rxn)/T ΔS∘rxn = -((-44.2 kJ/mol) - (-8.314 J/mol K * 298 K * ln(1.9 x 10^7)))/(298 K) ΔS∘rxn = -0.143 kJ/K

Therefore, ΔS∘rxn is -0.143 kJ/K.

To determine whether the reaction is spontaneous at 25 ∘C and standard pressure, we can use Gibbs free energy (ΔG). If ΔG < 0, then the reaction is spontaneous in the forward direction; if ΔG > 0, then it is spontaneous in the reverse direction; if ΔG = 0, then it is at equilibrium.

We know that ΔG∘rxn = -44.2 kJ/mol and T = 25 ∘C (298 K). We can use the following formula to calculate ΔG:

ΔG = ΔG∘ + RTlnQ

where Q is the reaction quotient.

At equilibrium, Q = K (the equilibrium constant). Since we calculated K earlier to be 1.9 x 10^7, we can use this value for Q.

ΔG = ΔG∘ + RTlnQ ΔG = (-44.2 kJ/mol) + (8.314 J/mol K * 298 K * ln(1.9 x 10^7)) ΔG = -43.6 kJ/mol

Since ΔG < 0, the reaction is spontaneous in the forward direction at 25 ∘C and standard pressure.

Answer:

Volume = 3.4 L

Explanation:

In order to calculate the volume of CO₂ produced when 15.2 g of CaCO₃ is heated, we need to first write out the balanced equation of the thermal decomposition of CaCO₃:

CaCO₃ (s) + [Heat] ⇒ CaO (s) + CO₂ (g)

Now, let's calculate the number of moles in 15.2 g CaCO₃:

mole no. = \(\mathrm{\frac{mass}{molar \ mass}}\)

                 = \(\frac{15.2}{40.1 + 12 + (16 \times 3)}\)

                 = 0.1518 moles

From the balanced equation above, we can see that the stoichiometric molar ratios of CaCO₃ and CO₂ are equal. Therefore, the number of moles of CO₂ produced is also 0.1518 moles.

Hence, from the formula for the number of moles of a gas, we can calculate the volume of  CO₂:

mole no. = \(\mathrm{\frac{Volume \ in \ L}{22.4}}\)

⇒ \(0.1518 = \mathrm{\frac{Volume}{22.4}}\)

⇒ Volume = 0.1518 × 22.4

                 = 3.4 L

Therefore, if 15.2 g of CaCO₃ is heated, 3.4 L of CO₂ is produced at STP.

Answer: 32 mg

Explanation:

32 / 8 = 4 = how much half-life has passed. 512 / 2^4 = 32.

Answer:

volume

Explanation:

i think its right

The units for atomic mass are atomic mass units (amu).  the atomic mass of copper for this location is 63.55 amu.

The chemical symbol Cu stands for copper. Copper is a soft, malleable, ductile metal that is a good conductor of heat and electricity. Copper is one of the most widely used metals in electrical and electronic equipment due to its superior conductivity and non-corrosive properties. This metal is widely used in wiring, roofing, plumbing, and electronic applications. Its atomic mass is 63.55 amu.The atomic mass of copper for this location can be determined using the following formula:

Atomic mass = (mass of isotope 1 x relative abundance of isotope 1) + (mass of isotope 2 x relative abundance of isotope 2)The atomic mass of copper for this location

= (62.93 x 0.6915) + (64.93 x 0.3085) = 63.55 amu

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Answer:

no illustration, so its impossible to say- but on mooshiners they "hot that mash up usin a big ol wood fahr"

The specific heat of the metal : 0.384 J/g° C,

and a metal with a specific heat of 0.384 is copper

The law of conservation of energy can be applied to heat changes, i.e. the heat received / absorbed is the same as the heat released  

Q in = Q out  

Q lost(metal) = Q gained(water)

Heat can be calculated using the formula:  

Q = mc∆T  

Q = heat, J  

m = mass, g  

c = specific heat, joules / g ° C  

∆T = temperature difference, ° C / K  

\(\tt Q~metal=Q~water\\\\8.5\times c\times (100-23.2)=50\times 4.18\times(23.2-22)\\\\652.8\times c=250.8\Rightarrow c=\dfrac{250.8}{652.8}=0.384~J/g^oC\)

Answer: An electron con only exist in a limited number of quantized energy levels.

Explanation:

The enthalpy of this reaction is 1.48 kJ/mol.

The formula to calculate heat energy is

Q = m × c × ΔT

ΔT = T₂ - T₁

ΔT = T₂ - T₁ = 24.70 - 21.00 = 3.70 °C

Q = m × c × ΔT

Q = 191 × 4.184 × 3.70

Q = 2,956.83 J

Q = (2,956.83 ÷ 1,000) kJ

Q = 2.96 kJ

The enthalpy ΔH = Q ÷ n

ΔH = Q ÷ n

ΔH = 2.96 ÷ 2.00

ΔH = 1.48 kJ/mol

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Answer:

The balanced equation for this reaction is C2H2 + 502 + 4H2O + 3C02. What volume of carbon dioxide is produced when 2.8 L of oxygen are consumed? 25Explanation:

Answer:

the answer woul be 89 if you do the math right

Explanation: