is the ecosystem going down bc of pollution

Answer:

no solution

Step-by-step explanation:

I really hope this helps you out and enjoy the rest of your day! =D <3

Answer:

x=±√35

Step-by-step explanation:

Take the square root of both sides of the equation to eliminate the exponent on the left side.

x=±√35

The complete solution is the result of both the positive and negative portions of the solution.

Given that a rectangle ABCD, where AB = 4, side BC that AP 3 and P lies on diagonal AC such 3/2. We have to find the distance PB.Solution:In the given rectangle ABCD,AB = 4Therefore,

AD = BC = 4 [because opposite sides of a rectangle are equal]P lies on diagonal AC and AP = 3We have to find PBWe will use the Pythagorean theorem and properties of similar triangles to find the distance PB.From triangle APD,

Using Pythagorean theorem,PD2 = AD2 + AP2 = 42 + 32 = 16 + 9 = 25PD = √25 = 5From triangle ABC,Using Pythagorean theorem,AC2 = AB2 + BC2 = 42 + BC2BC2 = AC2 - AB2= (3/2)2 - 42= 9/4 - 16= - 55/4 [As, the value inside the square root can't be negative, Therefore PB can't exist, and we can say that PB is imaginary or it doesn't exist]Hence, the distance PB is imaginary or it doesn't exist.

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Answer:

camino 5 kilometros

Step-by-step explanation:

2-3+5

The rate of change is (-1)

To solve this, we need to look at graphic to know the values of the function f(x) when x is equal to 1 and 3.

Then we have two points of the graph: (1,6) and (3,4).

The rate of change between two points is:

In this case,

Note that its the same whatever coordinate put first:

But when you do the difference between the coordinates, make sure to respect the order: if you use the y coordinate of the point P minus the y coordinate of point Q, you must to do the same for the x coodinate; Px-Qx

Answer:

196

Step-by-step explanation:

Answer:

196

Step-by-step explanation:

According to the question, determine whether the given sequence converges or diverges.

The given sequence is: \(a(n) = \frac{9+3n^{2} }{n+8n^{2} }\)

Taking limits tends to infinity on both sides. And dividing numerator and denominator by \(n^{2}\)

Therefore, the final term can be re-written as: \(a(n) = \frac{9+3n^{2} }{n+8n^{2} } = \frac{3}{8}\).

Hence, the given sequence converges and the limit is \(\frac{3}{8}\).

What converges and diverges in limits?

When the limits of the sequence exist and have finite value that means the sequence is a convergent sequence. The calculated value is a real number. And the tem divergence means limits do not exist.

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So the question is just asking for you to simplify the inequality until you get an answer.

1. Open the bracket on the left side. If you open it, you get 4x+8 > 8x - 3

2. Know - 4x from both side so you dont have x on 1 side. So 8 > 4x - 3

3. Get rid of the -3 from the right side by adding 3 onto both side. So 11>4x

4. Now you can divide by 4 on each side. x<2.75

= x < 2.75 (x is smaller than 2.75) .

You can write 2.75 > x. It is the same thing but I like writing my x first :)

Sebastian, this is the solution to the first problem you uploaded:

Let's recall that the interior angles of a triangle add up to 180 degrees.

Then if E =

Answer:

SQV

Step-by-step explanation:

Angle TQU can be worked out

90 + 46 = 136

180-136=44 ( angles in a triangle adds up to 180)

angle SQV = 44 (vertically opposite angles are equal)

adding angle SQV and QVS ; 44 + 68 = 112

angles in a triangle equal 180-112 =68

so the triangle SQV is an isosceles

the graph of f(x) = x^3 - 3x^2 - 9x + 5 is concave down on the interval (-∞, 1), concave up on the interval (1, +∞), and has a point of inflection at x = 1.

To determine the intervals on which the graph of a function is concave up or concave down, we need to analyze the second derivative of the function. The concavity of a function can change at points where the second derivative changes sign.

Here's the step-by-step process to find the intervals of concavity and points of inflection:

Find the first derivative of the function, f'(x).

Find the second derivative of the function, f''(x).

Set f''(x) equal to zero and solve for x. The solutions give you the potential points of inflection.

Determine the intervals between the points found in step 3 and evaluate the sign of f''(x) in each interval. If f''(x) > 0, the graph is concave up; if f''(x) < 0, the graph is concave down.

Check the concavity at the points of inflection found in step 3 by evaluating the sign of f''(x) on either side of each point.

Let's go through an example to illustrate this process:

Example: Consider the function f(x) = x^3 - 3x^2 - 9x + 5.

Find the first derivative, f'(x):

f'(x) = 3x^2 - 6x - 9.

Find the second derivative, f''(x):

f''(x) = 6x - 6.

Set f''(x) equal to zero and solve for x:

6x - 6 = 0.

Solving for x, we get x = 1.

Therefore, the potential point of inflection is x = 1.

Determine the intervals and signs of f''(x):

Choose test points in each interval and evaluate f''(x).

Interval 1: (-∞, 1)

Choose x = 0 (test point):

f''(0) = 6(0) - 6 = -6.

Since f''(0) < 0, the graph is concave down in this interval.

Interval 2: (1, +∞)

Choose x = 2 (test point):

f''(2) = 6(2) - 6 = 6.

Since f''(2) > 0, the graph is concave up in this interval.

Check the concavity at the point of inflection:

Evaluate f''(x) on either side of x = 1.

Choose x = 0 (left side of x = 1):

f''(0) = -6.

Since f''(0) < 0, the graph is concave down on the left side of x = 1.

Choose x = 2 (right side of x = 1):

f''(2) = 6.

Since f''(2) > 0, the graph is concave up on the right side of x = 1.

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The true statement is b. Parallel ILS approaches provide aircraft with a minimum of 1-1/2 miles of radar separation between successive aircraft on the adjacent localizer course.

Instrument Landing System(ILS) is the name for this type of system. These methods are typically employed by aircraft to successfully land in low visibility conditions. When using ILS approaches to reach the same airport on parallel runways, all the air traffic controllers ensure that a minimum separation is maintained between two or more aircraft in order to reduce the considerable risk of accidents.

Parallel ILS approaches must typically provide at least 1-1/2 miles of radar separation between succeeding aircraft on the adjacent localizer track, according to FAA standards. This distance between the aircraft is effectively measured by radar sensors and is kept horizontally.

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f(x)= x³− 6x²− 15x the maximum value of f on the interval [0,6] is 0

f(x) = x³− 6x²− 15x

F(x) = 3x² - 12x - 15

For maximum value f'(x) = 0

3x² - 12x - 15 = 0

3x² + 3x - 15x -15 = 0

3x(x + 1)-15(x+1)=0

(3x-15)(x+1) = 0

x = -1 and x = 5

f(x) is decreasing (-∞,-1) ∪ (5,∞)

f(x) is increasing (-1,5)

x ∈ [0,6]

f(0) = 0

f(6) = 6³ - 6(6)² -15(6)

f(6) = -90

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A matrix consisting entirely of zeros is called a zero matrix, or an all-zero matrix.

It is denoted with the symbol O and can be written in a matrix form, such as O = [0 0 0 0] where the number of columns and rows depends on the size of the matrix. A zero matrix is a matrix which has all its elements equal to zero. It has a number of special properties that make it useful in linear algebra. For instance, the sum of any two zero matrices is a zero matrix, and any scalar multiple of a zero matrix is a zero matrix. Additionally, the product of two zero matrices is a zero matrix, and the product of a zero matrix and an identity matrix is a zero matrix. These properties make it useful in solving systems of linear equations where all the coefficients are zero. Finally, the inverse of a zero matrix does not exist since its determinant is zero.

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The solutions to the logarithmic equation log2(x2-6x+20) = 3 are x = 3 + i√3 and x = 3 - i√3.

Given: log2(x2-6x+20) = 3

To solve this logarithmic equation, we use the basic definition of logarithms, which is a way of writing an exponential equation in a shorter form.

In this case, we can rewrite the equation as:

2³ = x² - 6x + 20

Since 2³ = 8, the equation becomes:

8 = x² - 6x + 20Subtracting 8 from both sides:

0 = x² - 6x + 12

We can now use the quadratic formula to solve for x,

which is given by:

x = (-b ± √(b² - 4ac)) / 2a

Where a = 1, b = -6, and c = 12.

Substituting these values into the formula, we get:

x = (-(-6) ± √((-6)² - 4(1)(12))) / 2(1)x = (6 ± √(36 - 48)) / 2x = (6 ± √(-12)) / 2x = (6 ± 2i√3) / 2x = 3 ± i√3

Thus, the solutions to the logarithmic equation log

2(x2-6x+20) = 3 are

x = 3 + i√3 and

x = 3 - i√3.

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Angela's use 6 cups of flour and Jaleel's use 19/3 cups of flour.

Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.

Given that;

The graph shows the relationship between the number of cups of flour and the number of cups of sugar in Angela's brownie recipe.

And, The table shows the same relationship for Jaleel's brownie recipe.

Hence, The equation for Angela's brownie recipe is,

Two points on graph are (4, 2) and (2, 1)

⇒ y - 2 = (2 - 1)/ (4 - 2) (x - 4)

⇒ y - 2 = 1/2 (x - 4)

⇒ y - 2 = 1/2x - 2

⇒ y = 1/2x

And, The equation for Jaleel's brownie recipe is,

Two points on graph are (3/2, 1) and (3, 2)

⇒ y - 1 = (2 - 1)/ (3 - 3/2) (x - 4)

⇒ y - 1 = 2/3 (x - 4)

⇒ y - 1 = 2/3x - 8/3

⇒ y = 2/3x - 8/3 + 1

⇒ y = 2/3x - 5/3

So, For Jaleel and Angela buy a 12-cup bag of sugar.

The equation for Angela's brownie recipe is,

⇒ y = 1/2x

⇒ y = 1/2 × 12

⇒ y = 6

The equation for Jaleel's brownie recipe is,

⇒ y = 2/3x - 5/3

⇒ y = 2/3 × 12 - 5/3

⇒ y = 19/3

Thus, Angela's use 6 cups of flour and Jaleel's use 19/3 cups of flour.

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We can infer that there are more flaws caused on the day shift at the 0.05 significance level.

To determine if there are more defects produced on the day shift compared to the afternoon shift, we can conduct a one-tailed paired t-test. Let's go through the steps:

1. Null and alternate hypotheses:

H0: μd ≤ 0 (There is no significant difference or the day shift has fewer defects)

H1: μd > 0 (There are more defects on the day shift)

2. Sample information:

Day:                      1   2   3   4

Day shift:             10  12  15  19

Afternoon shift:    8    9    12  15

3. Calculate the differences:

We calculate the difference between the day shift and afternoon shift for each day:

d = (Day shift) - (Afternoon shift)

d = 10-8, 12-9, 15-12, 19-15

d = 2, 3, 3, 4

4. Calculate the mean and standard deviation of the differences:

Mean (xd) = (2+3+3+4)/4 = 3

Standard deviation (sd) = √[(Σ(d-xd)²)/(n-1)]

                     = √[(0²+1²+1²+2²)/3]

                     ≈ √(6/3)

                     ≈ √2

                     ≈ 1.414

5. Calculate the test statistic:

t = (xd - μd)/(sd/√n)

  = (3 - 0)/(1.414/√4)

  = 3/0.707

  ≈ 4.243

6. Degrees of freedom:

Degrees of freedom (df) = n - 1 = 4 - 1 = 3

7. Decision rule:

Since we are conducting a one-tailed test at the 0.05 significance level, the critical t-value is obtained from the t-distribution table for df = 3 and α = 0.05. The critical t-value is approximately 2.920.

8. Decision regarding H0:

If the calculated test statistic (t) is greater than the critical t-value, we reject H0. Otherwise, we do not reject H0.

9. P-value:

To find the p-value associated with the calculated test statistic, we need to look it up in the t-distribution table or use statistical software. The p-value represents the probability of observing a test statistic as extreme or more extreme than the one calculated, assuming H0 is true. In this case, the p-value is less than 0.005 (Between 0.0005 and 0.005).

Summary:

- Decision rule: Since the calculated test statistic (4.243) is greater than the critical t-value (2.920), we reject H0.

- The p-value is less than 0.005.

- Decision regarding H0: We reject H0.

Therefore, at the 0.05 significance level, we can conclude that there are more defects produced on the day shift.

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Answer:

non proportional is the answer

Answer:

=2x+3/4=5.50

x=19/8 or 2 3/8

hope this helps

Step-by-step explanation:

The value of x is obtained as follows:

128º.

The measure of angle A is given as follows:

m < A = 132º.

For a parallelogram, the opposite angles are congruent, meaning that they have the same measure, hence the value of x is obtained as follows:

5x - 508 = x + 4.

4x = 512

x = 512/4

x = 128.

Then the measure of angle A is given as follows:

m < A = 5(128) - 508

m < A = 132º.

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To graph a rational function example, start by writing the equation in the form y = (ax + b)/(cx + d).

Then, plot the points where the denominator equals zero (when x = -d/c). These points are called vertical asymptotes.Next, plot the points where the numerator equals zero (when x = -b/a). These are called horizontal asymptotes.Finally, plot points between the vertical and horizontal asymptotes to graph the rational function.Plotting the points between the vertical and horizontal asymptotes will allow you to see the shape of the graph. Start by plotting points on either side of the vertical and horizontal asymptotes. Then, plot points at evenly spaced x-values between the vertical and horizontal asymptotes. For example, if the vertical asymptote is at x=-d/c, and the horizontal asymptote is at x=-b/a, you can plot points at x=-1.5d/c, x=-0.5d/c, x=-1.5b/a, and x=-0.5b/a. By plotting these points and connecting them with a smooth curve, you can graph the rational function.

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The answer to your question is option c) 50%. To calculate the probability, we divide the favorable combinations by the total combinations: 2/6 = 1/3, which is equivalent to 33.33% (rounded).



Firstly, we need to determine the total number of options available to the passengers. As stated in the question, the airline offers three snack options (cookies, chips, and crackers) and two drink options (soda or water). Therefore, the total number of options available is six. Secondly, we need to identify the number of options that include both soda or water and cookies. Since the question specifically asks for the probability of a passenger choosing soda or water with cookies, we only need to consider the combinations that include these two options. There are a total of three snack options and two drink options, which means there are a total of six possible combinations. Out of these six combinations, three include cookies and either soda or water.

Finally, we can calculate the probability of a passenger choosing either soda or water with cookies by dividing the number of favorable outcomes (i.e. combinations that include both soda or water and cookies) by the total number of outcomes. Therefore, the probability is 3/6 or 50%.

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Using the normal distribution, it is found that 95.15% of students receive a merit scholarship did not receive enough to cover full tuition.

The z-score of a measure X of a normally distributed variable with mean \(\mu\) and standard deviation \(\sigma\) is given by:

\(Z = \frac{X - \mu}{\sigma}\)

The mean and the standard deviation for the amounts are given as follows:

\(\mu = 3456, \sigma = 478\)

The proportion is the p-value of Z when X = 4250, hence:

\(Z = \frac{X - \mu}{\sigma}\)

\(Z = \frac{4250 - 3456}{478}\)

Z = 1.66

Z = 1.66 has a p-value of 0.9515.

Hence 95.15% of students receive a merit scholarship did not receive enough to cover full tuition.

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n = 14

Hi there !

7ⁿₓ7⁵⁾⁴ = 7³⁴

7ⁿₓ7⁵ˣ⁴ = 7³⁴

7ⁿₓ7²⁰ = 7³⁴

n + 20 = 34

n = 34 -20

n = 14

Good luck !

Answer:

n = 14

Step-by-step explanation: