It is the local term for carving
A. Buri
B. Burnay
C. Kiping
D. Ukit​

1.The driver has traveled a distance of 23 km.

2.The driver's total displacement is 17 km east.

1.The distance traveled by the driver can be calculated by adding the distances traveled in each leg of the journey:

Distance traveled = (8 km) + (3 km) + (12 km) = 23 km

2.The driver's total displacement takes into account not only the distance traveled but also the direction. To calculate the displacement, we need to consider the net distance and direction from the starting point to the final position.

The driver initially travels 8 km east, then 3 km west, and finally 12 km east. Since the driver is traveling back and forth, the net displacement can be found by subtracting the distance traveled west from the distance traveled east:

Net displacement = (Distance traveled east) - (Distance traveled west)

= (8 km + 12 km) - (3 km)

= 20 km - 3 km

= 17 km

The driver's total displacement is 17 km east.

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Explanation:

The attached figure shows the free diagram of the person standing in a low cavern.

The forces acting on the person are as follows :

1. Its weight, mg (in downward direction)

2. F₁ = Force exerted by the Earth on the person (in upward direction)

3. F₂ = Force exerted by the ceiling on the person (in downward direction)

According to the given statement:

I) acceleration a=2m/s²

ii) deceleration a=−1  m/s²

iii) the distance travelled =200  m.

Velocity's rate of change with time, in both terms of speed and direction. A point or object moving straight ahead is accelerated when it increases or decelerates. Even if the speed remains constant, motion on the a circle increases because the orientation is always shifting.

Briefing:

You use the standard formulas for distance as a function of speed, acceleration and time:

st = v0t + 0.10at²  for acceleration ( a >0) and deceleration ( a <0), or at constant speed ( a =0).

Now  a  is not given for acceleration and deceleration, so we need to compute this from

vt=v₀+at

Acceleration:  

20=10a⟹a=2m/s²

Distance travelled:  

0.10∗10∗10²=100  m

Distance travelled while at constant speed:

s=vt=20∗20=400  m

Deceleration:  

0=20+20a⟺a=−1  m/s²

Distance travelled:

20∗20+0.1(−1)20²=400−2∗100

=200  m.

So the total distance travelled is  100+400+200=700m

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Answer:

2KI   +  Cl₂   →   2KCl     +    I₂

Explanation:

The reaction equation is given as:

        KI   +  Cl₂   →    KCl     +    I₂

The problem at hand is to balance this chemical reaction. To solve this problem we use a mathematical approach;

        aKI   +  bCl₂   →    cKCl     +    dI₂

 Conserving K : a = c

                     I :  a  = 2d

                   Cl : 2b = c  

 Now let a = 1, c  = 1 , d  = \(\frac{1}{2}\), b   = \(\frac{1}{2}\), ;

   Multiply through by 2;

             a  = 2, b = 1 , c = 2, d  = 1

            2KI   +  Cl₂   →   2KCl     +    I₂

The theorem showing that △ ABC ≅ △ def is Density functional theorem.

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The work done is positive and is equal to 20000 J

Work done is defined as the product of force and the distance moved by the force.

Mathematically:

The work done by the force = 20 * 1000 = 20000J

The work done is positive and is equal to 20000 J

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Jack speed as he hits the water is 14.13m/s

What is speed?
The speed of an object, also known as v in kinematics, is the size of the change in that object's position over time or the size of the change in that object's position per unit of time, making it a scalar quantity. The instantaneous speed is the upper limit of the average speed as the duration of the time interval approaches zero. The average speed of an item in a period of time is equal to the distance travelled by the object divided by the duration of the period. Velocity and speed are not the same thing.

The only force on Jack is gravity, which points straight down, and has an acceleration of 9.91m/s².  Whether he's falling off a bridge or simply standing still on the surface of the earth, the acceleration due to gravity is the same.

If you're looking for the speed of Jack as he hits the water, you just need to solve for v in the equation\($v^2 = v_0^2 + 2ad$\).  
Here,
v is Jack's speed as he hits the water,
\($v_0$\) is Jack's initial speed (which is zero since he's not moving when he jumps),
a is Jack's acceleration (which is 9.91m/s²), and
d is Jack's displacement (which is the height of the bridge, which you said is 10m).  
This gives you an answer of \($v = \sqrt{2ad} = \sqrt{2(9.91)(10)} = 14.13 \ \mathrm{m/s}$\)

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Answer:

\(v_2 = 23.182m/s\)

Explanation:

Given

\(m_1 = 0.17kg\)

\(m_2 = 0.11kg\)

\(u_1 = 15m/s\) -- Initial Velocity of the first

\(u_2 = 0m/s\) -- Initial Velocity of the second

\(v_1 = 0m/s\) -- Final Velocity of the first

Required

Determine the final velocity of the second hockey puck (\(v_2\))

This question illustrates law of conservation of momentum and it'll be solved using the following formula:

\(m_1u_1 + m_2u_2 = m_1v_1 + m_2v_2\) ---- law of conservation of momentum

Substitute in the right values

\(0.17 * 15 + 0.11*0 = 0.17 * 0 + 0.11*v_2\)

\(0.17 * 15 + 0 = 0 + 0.11*v_2\)

\(2.55 = 0.11*v_2\)

Solve for v2

\(v_2 = 2.55/0.11\)

\(v_2 = 23.182m/s\)

Hence, the final velocity of the second hockey puck is 23.182m/s

The correct answer is nuclear fusion, radiation, and conduction.

It is a nuclear process in which energy is produced by colliding light atoms. It is the opposite of fission, which results in the disintegration of heavy isotopes. The sun and other stars produce light and heat through fusion.

According to the energy of the emitted particles, radiation is frequently classified as either ionising or non-ionizing. More than 10 eV is often carried by ionising radiation, which is sufficient to ionise atoms and molecules and rupture chemical bonds.

Conduction is an observable occurrence in all states of matter and is the process of transmitting energy through the motion of particles in touch with one another (solids, liquids and gases). Conductors are substances that permit conduction. Conduction is divided into three categories: conduction of heat, conduction of electricity, and conduction of sound.

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Answer:

Magnitude: 1.4

Explanation:

To find the magnitude of the resultant vector, we have to use the Pythagorean theorem. The Pythagorean theorem is \(a^2 + b^2 = c^2\).

-

What is given:

a = 1 unit (east)

b = 1 unit (north)

c = ?

-

Now let us substitute and solve:

1) \(1^2 +1^2 = c^2\)

2) \(1 + 1 = c^2\)

3) \(c^2 = 2\)

4) \(c =\sqrt{2}\)

5) \(c = 1.4\)

Answer:

Explanation:

The time spent by the campers when they turn around downstream is 15 minutes.

The concept of total distance traveled by Nick and Chloe can be used to determine the time they turn around downstream.

Let time for downstream = t1

Let time for upstream = t2

distance covered in upstream = distance covered in downstream = d

12(t1) = d

4(t2) = d

12t1 = 4t2

t1 + t2 = 1

t2 = 1 - t1

12t1 = 4(1 - t1)

12t1 = 4 - 4t1

16t1 = 4

t1 = 4/16

t1 = 0.25 hours

t1 = 0.25(60 min) = 15 mins

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Answer: a

Explanation:

The total resistance of the circuit is 49 Ω. The current strength in the circuit, when connected to a voltage source of 56 V, is approximately 1.14 A.

To calculate the total resistance of the circuit, we need to determine the equivalent resistance of the resistors connected in a series.

Given:

R1 = 4 Ω

R2 = 30 Ω

R3 = 10 Ω

R4 = 5 Ω

Calculate the equivalent resistance (RT) of R1 and R2, as they are connected in series:

RT1-2 = R1 + R2

RT1-2 = 4 Ω + 30 Ω

RT1-2 = 34 Ω

Calculate the equivalent resistance (RTotal) of RT1-2 and R3, as they are connected in parallel:

1/RTotal = 1/RT1-2 + 1/R3

1/RTotal = 1/34 Ω + 1/10 Ω

1/RTotal = (10 + 34) / (34 * 10) Ω

1/RTotal = 44 / 340 Ω

1/RTotal ≈ 0.1294 Ω

RTotal ≈ 1 / 0.1294 Ω

RTotal ≈ 7.74 Ω

Calculate the equivalent resistance (RTotalCircuit) of RTotal and R4, as they are connected in series:

RTotalCircuit = RTotal + R4

RTotalCircuit = 7.74 Ω + 5 Ω

RTotalCircuit ≈ 12.74 Ω

Therefore, the total resistance of the circuit is approximately 12.74 Ω.

To determine the current strength (I) when connected to a voltage source of 56 V, we can use Ohm's Law:

I = V / RTotalCircuit

I = 56 V / 12.74 Ω

I ≈ 4.39 A

Therefore, the current strength in the circuit, when connected to a voltage source of 56 V, is approximately 4.39 A (or 1.14 A, considering significant figures).

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When the segment is shrunk to one-third of its original length, the ratio of the final linear charge density (?f) to the initial linear charge density (?i) is f/?i = 3

This is because the charge is the same, but the length of the segment has decreased to one-third of its original length. Therefore, the charge density has increased by a factor of 3.

The ratio of the electric force on the proton after the segment is shrunk (Ff) to the force before the segment was shrunk (Fi) is also 3. This is because the electric force is directly proportional to the charge density, so if the charge density increases by a factor of 3, the electric force will also increase by a factor of 3.

If the original segment of wire is stretched to 15 times its original length, the charge density will decrease by a factor of 15. To keep the linear charge density unchanged, we need to add 14 times the original charge to the wire. This is because the original charge will be spread out over 15 times the original length, so we need to add 14 times the original charge to make up for the decrease in charge density.

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We can calculate the width/thickness of a coin using a screw gauge by placing it in between the teeth of the gauge.

We can determine the width/thickness of a coin by using a screw gauge because screw gauge is an instrument that measures thickness of an object that are very thin. First we can placed the coin in between the teeth of the gauge and then move the gauge until the coin can be held tightly. After that note the reading on the scale.

So we can conclude that we can calculate the width/thickness of a coin using a screw gauge by placing it in between the teeth of the gauge.

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A. All of the forces acting on an object

Explanation:

APEX

Answer:

\(T=208N\)

Explanation:

From the question we are told that:

Neck flex angle \(\angle_n=40 \textdegree\)

Head mass \(M_h=4.5kg\)

Center of mass \(M_c= 11cm\)

Distance of neck from P \(d_p=1.5cm\)

Let

\(T_g=Gravitational\ force\ torque\\T_{nm}=Tension\ on\ neck\ muscle\ torque\)

Generally the net Torque T_n is mathematically given by

\(T_n=0\)

Therefore

\(T_g-T_{nm}=0\)

Generally the equation for Torque T is mathematically given by

\(T=\frac{M_h*g*l_g}{d_p}\)

where

\(l_g=M_c*sin\angle_n\)

\(l_g=11*10^{-2}*sin40\)

\(l_g=0.07m\)

Therefore

\(T=\frac{4.5*9.8*0.07}{1.5*10^{-2}}\)

\(T=208N\)

The gravity at 380 km above the surface is, 86.42% weaker.

In order to calculate the distance from the center of the planet, the radius of the Earth will be added with the given distance above the Earth’s surface.

The relation of acceleration due to gravity is given by,

\(g= \dfrac{Gm}{R^2}\)

Here, G is the gravitational constant, m is the mass of the Earth, R is the distance from the center of the planet.

On plugging the values in the above relation.

\(g= \dfrac{6.67\times 10^{-11} \times 5.98 \times 10^{24}}{(6.38 \times 10^6 + 380000)^2}\)

The value of g at 380 km above earth surface is, 8.74.

The value of g at surface is 9.8.

The percentage difference = 8.74/9.8

= 0.86%

The gravity is, 86.42% weaker.

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D) Speed, direction, or both

Mass doesn’t just CHANGE like that.

The point where the object's speed is one-half its final speed may located at 3/4 of the initial height of the object, the answer would be "lower than the midpoint of the path."

Assuming the object is subject to a constant acceleration due to gravity, the speed of the object at any given point can be described by the following equation:

v² = u² + 2as

Where:

v = final velocity

u = initial velocity

a = acceleration due to gravity (approximately 9.8 m/s² near the Earth's surface)

s = distance traveled

Let's suppose the object is dropped from rest at a height h above the ground. Then its initial velocity is u=0, and the equation simplifies to:

v² = 2gh

where g is the acceleration due to gravity and h is the initial height of the object.

To find the point at which the object's speed is one-half its final speed, we can set v = 1/2 * √(2gh) and solve for s:

1/2 * √(2gh) = √(2gh - 2gs)

Simplifying this equation, we get:

1/4 * 2gh = 2gh - 2gs

s = 3/4 * h

This means that the point where the object's speed is one-half its final speed is located at 3/4 of the initial height of the object. Therefore, the answer is "lower than the midpoint of the path."

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Answer:

21.48 km 2.92° north of east

Explanation:

To find the resultant direction, we need to calculate a sum of vectors.

The first vector has module = 13 and angle = 315° (south = 270° and east = 360°, so southeast = (360+270)/2 = 315°)

The second vector has module 16 and angle = 40°

Now we need to decompose both vectors in their horizontal and vertical component:

horizontal component of first vector: 13 * cos(315) = 9.1924

vertical component of first vector: 13 * sin(315) = -9.1924

horizontal component of second vector: 16 * cos(40) = 12.2567

vertical component of second vector: 16 * sin(40) = 10.2846

Now we need to sum the horizontal components and the vertical components:

horizontal component of resultant vector: 9.1924 + 12.2567 = 21.4491

vertical component of resultant vector: -9.1924 + 10.2846 = 1.0922

Going back to the polar form, we have:

\(module = \sqrt{horizontal^2 + vertical^2}\)

\(module = \sqrt{460.0639 + 1.1929}\)

\(module = 21.4769\)

\(angle = arc\ tangent(vertical/horizontal)\)

\(angle = arc\ tangent(1.0922/21.4491)\)

\(angle = 2.915\°\)

So the resultant direction is 21.48 km 2.92° north of east.

Answer:

A

Explanation:

Hypothesis, If the mass of the cylinder increases, then the temperature of the water will also increase because an increase in mass leads to greater potential energy, which is converted to thermal energy in the system.

According to the principle of conservation of energy, energy cannot be created or destroyed but can be transformed from one form to another. In this case, potential energy from the mass of the cylinder can be converted into thermal energy in the system. When the cylinder is lifted and submerged in the water, it possesses gravitational potential energy due to its elevated position.

As the cylinder is released and descends into the water, this potential energy is converted into kinetic energy, causing the water molecules to move and collide with higher energy. These collisions generate heat and increase the overall temperature of the water. By increasing the mass of the cylinder, more potential energy is stored.

As a result, there is a greater amount of energy available to be converted into thermal energy when the cylinder is released into the water. Thus, the temperature of the water is expected to increase as the mass of the cylinder increases.

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a) The average force with which the woman pushed the man is 210 N.

b.  the woman's recoil speed is still 3.68 m/s

c.  If  she now throws her 2.50-kg purse at him at a 20.0° angle, the speed is 0.

We first calculate  the Momentum  = (70.0 kg)(-1.50 m/s) + (55.0 kg)(v) + (2.50 kg)(-1.50 m/s)

0 = (70.0 kg)(0 m/s) + (55.0 kg)(v) + (2.50 kg)(-1.50 m/s) - (70.0 kg)(-1.50 m/s)

v = 3.68 m/s

Δp = (70.0 kg)(1.50 m/s) - (70.0 kg)(0 m/s) = 105 kg·m/s

The average force exerted on the man by the woman is:

Average force =   Δp / Δt

Average force  = 105 kg·m/s / 0.500 s

Average force  = 210 N

b) The woman's recoil speed is :

0 = (70.0 kg)(-1.50 m/s) + (55.0 kg)(v) + (2.50 kg)(-1.50 m/s)

v = 3.68 m/s

c) If the woman throws her 2.50-kg purse at the man at a 20.0° angle, we apply the conservation of momentum equation in two dimensions and get the speed as 0.

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Placing lights at either side of the mirror to directly brighten the complexion is the simplest way to help reduce shadows on the face. The temperature of this bulb should be comfortable as well (2,700 to 3,500 Kelvin).

Lighting in salons should be positioned to eliminate shadows. Placing lights at either side of the mirror to directly brighten the complexion is the simplest way to help reduce shadows on the face. The temperature of this bulb should be comfortable as well (2,700 to 3,500 Kelvin).

Compared to other spaces or buildings, a beauty salon has a lot more practical uses for lighting. It facilitates work, helps staff members see consumers clearly, and ensures that everything is carried out correctly.

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Answer:

S = Vy t + 1/2 g t^2 = 1/2 g t^2    vertical speed with zero initial speed

t = (2 S / g)^1/2      with g = 32 ft/sec^2

t = (900 / 32)^1/2 = 5.30 sec    time to reach ground

V = a t = 32 ft/s^2 * 5.30 s = 170 ft/sec

170 ft/sec / (88 ft/sec / 60 mph) = 116 mph           since 88 ft/sec = 60 mph

Answer:

The magnitude of the charge is 54.9 nC.

Explanation:

The charge on each bead can be found using Coulomb's law:

\( F_{e} = \frac{k*q_{1}q_{2}}{r^{2}} \)

Where:

q₁ and q₂ are the charges, q₁ = q₂  

r: is the distance of spring stretching = 4.8x10⁻² m

\(F_{e}\): is the electrostatic force

\( F_{e} = \frac{k*q^{2}}{r^{2}} \rightarrow q = \sqrt{\frac{F_{e}}{k}}*r \)    

Now, we need to find \(F_{e}\). To do that we have that Fe is equal to the spring force (\(F_{k}\)):

\( F_{e} = F_{k} = -kx \)

Where:

k is the spring constant

x is the distance of the spring = 4.8 - 4.0 = 0.8 cm

The spring constant can be found by equaling the sping force and the weight force:

\( F_{k} = -W \)

\( -k*x = -m*g \)

where x is 5.2 - 4.0 = 1.2 cm, m = 1.8 g and g = 9.81 m/s²

\( k = \frac{mg}{x} = \frac{1.8 \cdot 10^{-3} kg*9.81 m/s^{2}}{1.2 \cdot 10^{-2} m} = 1.47 N/m \)      

Now, we can find the electrostatic force:

\( F_{e} = F_{k} = -kx = -1.47 N/m*0.8 \cdot 10^{-2} m = -0.0118 N \)

And with the magnitude of the electrostatic force we can find the charge:

\(q = \sqrt{\frac{F_{e}}{k}}*r = \sqrt{\frac{0.0118 N}{9 \cdot 10^{9} Nm^{2}/C^{2}}}*4.8 \cdot 10^{-2} m = 54.9 \cdot 10^{-9} C = 54.9 nC\)

Therefore, the magnitude of the charge is 54.9 nC.

I hope it helps you!  

The magnitude of the charge (in nC) on each bead is equal to 55.21 nC.

Given the following data:

Extension, e = \(0.052 - 0.048\) = 0.012 m

Scientific data:

To calculate the magnitude of the charge (in nC) on each bead, we would apply Coulomb's law:

First of all, we would determine the spring constant of this lightweight spring by using this formula:

\(W = mg = Ke \\\\K=\frac{mg}{e} \\\\K=\frac{0.0018 \times 9.8}{0.012} \\\\K=\frac{0.01764}{0.012}\)

Spring constant, K = 1.47 N/m.

For the electrostatic force:

\(F = ke\\\\F = 1.47 \times 0.08\)

F = 0.01176 Newton.

Coulomb's law of electrostatic force.

Mathematically, the charge in an electric field is given by this formula:

\(q = \sqrt{\frac{F}{k} } \times r\)

Substituting the given parameters into the formula, we have;

\(q = \sqrt{\frac{0.01176 }{8.99 \times 10^9} } \times 0.048\\\\q=\sqrt{1.3228 \times 10^{-12}} \times 0.048\\\\q=1.1502 \times 10^{-6} \times 0.048\\\\q= 5.521 \times 10^{-8}\;C\)

Note: 1 nC = \(1 \times 10^{-9}\;C\)

Charge, q = 55.21 nC.

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The tension in the strings are 31.47 and 19.25 N respectively.

Mass of the block, m = 3 kg

From the figure, consider the vertical components,

T₁ sin45° + T₂ sin30° = mg

(T₁/√2) + (T₂/2) = 3 x 9.8 = 29.4

Also, consider the horizontal components,

T₁ cos45° = T₂ cos30°

T₁/√2 = T₂ x√3/2

T₁ = T₂ x √3/2 x √2

So,

T₁ = 0.612T₂

Applying in the first equation,

(T₁/√2) + (T₂/2) = 29.4

(0.612T₂/1.414) + 0.5T₂ = 29.4

0.434 T₂ + 0.5 T₂ = 29.4

0.934 T₂ = 29.4

Therefore, the tension,

T₂ = 29.4/0.934

T₂ = 31.47 N

So, the tension,

T₁ = 0.612 T₂

T₁ = 0.612 x 31.47

T₁ = 19.25 N

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Answer:

Explanation:

The acceleration of an electron in an electric field is given by the equation:

a = qE/m

where a is the acceleration, q is the charge of the electron, E is the electric field, and m is the mass of the electron.

Given that the acceleration of the electron is 4.3 m/s^2, and the mass of the electron is 9.11 × 10^-31 kg, and the charge of the electron is -1.6 × 10^-19 C, we can solve for the electric field E:

E = ma/q

E = (4.3 m/s^2) × (9.11 × 10^-31 kg) / (-1.6 × 10^-19 C)

E = -2.44 × 10^4 N/C

The negative sign indicates that the direction of the electric field is opposite to the direction of the electron's motion. Therefore, the magnitude of the electric field required to accelerate an electron with an acceleration of 4.3 m/s^2 is 2.44 × 10^4 N/C and the direction is opposite to the direction of motion of the electron.