it takes 840 s to walk completely around a circular track, moving at a speed of 1.20 m/s? what is the radius of the track?

Micah will experience a larger magnification is because the angular size of the object is smaller for Micah than for Lyra.

Why angular size of the object is smaller for Micah than for Lyra?

The magnification produced by a magnifier is given by the formula:

M = (25cm/f) + 1, where f is the focal length of the magnifier.

The magnification is larger when the focal length is smaller. However, in this case, both Micah and Lyra are using the same magnifier, so the focal length is the same for both of them.

The near point is the closest distance at which an object can be brought into focus by the eye. The near point varies from person to person, and it depends on the elasticity of the lens and the shape of the eye. In this case, Micah's near point is located farther away from his eye than Lyra's near point is located relative to her eye. This means that Micah's eye has less ability to focus on close objects than Lyra's eye.

When an object is located at the near point, the image formed on the retina is at its maximum size.

The angular size of the object is given by the formula:

θ = tan⁻¹ (s/d), where s is the size of the object and d is the distance between the object and the eye.

Since Micah's near point is farther away than Lyra's near point, the distance d is larger for Micah. This means that the angular size of the object is smaller for Micah than for Lyra.

When Micah uses the magnifier to inspect the object, the magnification will be larger because the angular size of the object is smaller.

This is because the magnification is proportional to the ratio of the angular size of the image to the angular size of the object.

Since the angular size of the object is smaller for Micah, the angular size of the image produced by the magnifier will be larger, resulting in a larger magnification for Micah.

Therefore, the correct reason why Micah will experience a larger magnification is because the angular size of the object is smaller for Micah than for Lyra when the object is located at his near point.

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When the object is located at his near point, the angular size of the object is smaller for Micah than for Lyra, for which reason Micah will experience a larger magnification.

The statement that is correct for the given question is "When the object is located at his near point, the angular size of the object is smaller for Micah than for Lyra."

Micah and Lyra are two people with different near points but are equally close to an object.

Both inspect the object through the same magnifier by holding the lens close to the eye. In this context, magnification is the ratio of the size of the image seen through the magnifier to the size of the object when viewed directly.

The distance between the object and the lens must be greater than the focal length of the lens to create a virtual image. Micah's near point is located farther away from his eye than Lyra's near point is located relative to her eye.

So, Micah will experience a larger magnification for the reason that when the object is located at his near point, the angular size of the object is smaller for Micah than for Lyra.

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To determine the resistance in SI units that you need to set the cycle ergometer to, given that you want to have a subject exercise at 125 watts with an RPM of 60 for 3 minutes, follow the steps below:

Step 1: Determine the energy used in Joules during the 3 minutes at 125 watts.

P = W / tWhere:

P = power (125 watts)t = time (3 minutes converted to seconds

= 3 × 60 = 180 seconds)

W = energy used in Joules (to be determined)

Substituting the given values:

P = W / t125

= W / 180W

= 125 × 180W

= 22,500 Joules

Step 2: Determine the work done (in Joules) per revolution (360 degrees).

Work done per revolution = energy used in Joules / number of revolutions per minute / 60

Where:number of revolutions per minute = RPM / 60

Substituting the given values:

Work done per revolution = 22,500 / (60 / 60) / 360

Work done per revolution = 22,500 / 1 / 360

Work done per revolution = 22,500 × 360

Work done per revolution = 8,100,000 Joules

Step 3: Determine the torque needed to perform one revolution (360 degrees) of the pedals in SI units (N-m).Torque = work done per revolution / (2 × π)

Where:

2 × π = 6.2832

Substituting the given values:Torque = 8,100,000 / 6.2832

Torque = 1,288,684.08 N-m

Step 4:

Determine the resistance (force) needed at the pedals in Newtons (N) to produce the required torque.Resistance = Torque / pedal radius

Where:pedal radius = 0.175 m (average for a cycle ergometer)

Substituting the given values:

Resistance = 1,288,684.08 / 0.175

Resistance = 7,358,971.89 N (Newtons)

Therefore, you would need to set the resistance to 7,358,971.89 N (Newtons) on the cycle ergometer to achieve the desired subject exercise at 125 Watts with an RPM of 60 for 3 minutes.

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To see cars in your blind spots, the most effective method is to turn your head (option C). While inside and outside rearview mirrors (options A and B) provide valuable assistance in monitoring the traffic behind your vehicle, they have limitations when it comes to detecting vehicles in your blind spots.

Blind spots are areas around your vehicle that are not visible in your mirrors or through peripheral vision. They exist due to the design and positioning of the vehicle's pillars, windows, and rearview mirrors. Depending on your vehicle's size and configuration, blind spots can vary in size and location.

By turning your head and physically looking over your shoulder, you can directly check the blind spots and gather more accurate information about any vehicles that may be in those areas. This action provides an additional level of assurance before changing lanes or making any lateral movements on the road.

While checking your blind spots, it's important to maintain control of the steering wheel and keep your eyes on the road ahead as much as possible. Use a quick glance over your shoulder to check the blind spots without excessively turning your body or taking your eyes off the road for an extended period.

Relying solely on the inside rearview mirror or outside rearview mirrors may not provide a complete view of the blind spots. Depending on factors such as the size and positioning of your vehicle, the blind spots can vary. Therefore, developing the habit of turning your head and visually checking the blind spots is crucial for safe driving.

In conclusion, to see cars in your blind spots, it is best to turn your head (option C). While rearview mirrors are valuable tools for monitoring traffic, they have limitations when it comes to detecting vehicles in the blind spots. By physically looking over your shoulder, you can ensure a comprehensive view of the surrounding traffic and minimize the risk of accidents caused by cars in the blind spots. Remember to maintain control of the steering wheel and keep your eyes on the road while checking the blind spots.

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The acceleration of Mass A is 3.2 m/s². Option B

we can find the acceleration of Mass A using the following kinematic equation:

v = u + at

where:

v = final velocity (2.56 m/s)

u = initial velocity (0 m/s, since Mass A starts from rest)

a = acceleration (which we need to find)

t = time (0.80 seconds)

Rearranging the equation to solve for acceleration, we get:

a = (v - u) / t

Now we can plug in the values:

a = (2.56 - 0) / 0.80

a = 2.56 / 0.80

a = 3.2 m/s²

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Answer:

77ruririfusjd u 6r7r u y9r8

Answer:

D) one complete wavelength to pass a fixed point.

Explanation:

36.99N

Given

Maximum blood pressure  P = 150 mm

Effective area of the aneurysm a = 18.5 cm2.

Expression for the maximum force exerted by blood on an aneurysm is,

f =P * a = (150 mm Hg* (133.322 N/m²/ 1 mmHg)) * ( 18.5 cm² * (1 m² /10000cm²)) = 36.99N

The pressure is computed as the ratio of acting force on an object and the surface area of the object where the force is directed. The pressure is usually measured in terms of Pascal and blood pressure in mm of Hg.

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Answer:

Muscle size and training specifiicty

Explanation:

It depends on all other factors such as anatomy and psychology, muscle fiber recruitment, motor pattern development and muscle memory but to increase modifiable strength, size plays no big role.

Answer:

The final velocity of the train and the moose after collision is approximately 19.51 m/s

Explanation:

The given mass of the moose, m₁ = 250 kg

The velocity of the moose, v₁ = 0

The mass of the oncoming train, m₂ = 10,000 kg

The velocity of the train, v₂ = 20 m/s

The velocity of the moose and the train after collision = v₃

By the principle of conservation of linear momentum, the total initial momentum before the collision = The total final momentum after collision

m₁·v₁ + m₂·v₂ = (m₁ + m₂)·v₃

Therefore, by substitution, we have;

250×0 + 10,000× 20 = (10,000 + 250) × v₃

200,000 = 10,250 × v₃

v₃ = 200,000/10,250 ≈ 19.51 m/s

The final velocity of the train and the moose after collision = v₃ ≈ 19.51 m/s

The instantaneous velocity of the bird at t = 8.00 s is \(\(-11.25 \, \text{m/s}\)\).

To calculate the instantaneous velocity, we need to find the derivative of the position function with respect to time. Let's assume that the position of the bird at time t is given by the function s(t). The derivative of s(t) represents the velocity function, denoted as v(t), which gives us the instantaneous velocity at any given time. In mathematical terms, \(\(v(t) = \frac{{ds}}{{dt}}\)\).

Let's assume that the position function of the bird is given by \(\(s(t) = -2.5t^2 + 30t - 5\)\), where t is the time in seconds and s(t) is the position of the bird at time t. To find the instantaneous velocity at t = 8.00 s, we differentiate s(t) with respect to t, which gives us v(t) = -5t + 30. Substituting t = 8.00 s into the velocity function, we find v(8.00) = -5(8.00) + 30 = -11.25 m/s. Therefore, the instantaneous velocity of the bird at t = 8.00s is -11.25 m/s.

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(a) The magnetic force experienced by the wire when it perpendicular is 0.01 N.

(b) The magnetic force experienced by the wire when the angle is  30⁰ is 5 x 10⁻³ N.

(c) The magnetic force experienced by the wire when it parallel is 0 N.

The magnetic force experienced by the wire is calculated by applying the following;

F = BIL x sin(θ)

where;

When the angle of inclination is perpendicular,  

F = 1 x 10⁻² x 10 x 0.1 x sin(90)

F = 0.01 N

When the angle of inclination is 30⁰,

F = BIL x sin(θ)

F = 1 x 10⁻² x 10 x 0.1 x sin(30)

F = 5 x 10⁻³ N

When the wire is parallel, the angle is 0⁰,

F = BIL x sin(θ)

F = 1 x 10⁻² x 10 x 0.1 x sin(0)

F = 0 N

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The statement that is true in this case is option A;  The initial momentum of both girls was equal.

If there are no outside forces acting on an isolated system, the law of conservation of momentum states that its overall momentum will remain constant.

Each lady in this scenario had her own momentum prior to the impact, which was the result of her mass and velocity. The total momentum of the system (both ladies together) remains unchanged after the collision because they collide and hold on to each other without any external forces acting on them. This suggests that both girls must have the same initial momentum.

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Missing parts;

Two friends on ice skates run directly toward each other. If they hold on to each other after they collide and do not move after their collision, which statement must be true? A) The initial momentum of both girls was equal. B) The initial speed of both girls was equal. C) The mass of both girls is equal. D) Their collision was inelastic.

Answer:

1. 5m/s

Explanation:

1. We can apply the law of conservation of momentum here;

m1*u1 = m1*v1+ m2*v2

m1*u1 is 5 since the balls have equal masses-- m1*u1=5=m1(v1 + v2)

similarly the balls have a velocity of 5m/s each since v1+v2 = 10m/s

(answer choice c)

your can similarly calculate the second problem

For both questions, you have to remember:

-- momentum of one object = (mass) x (velocity)

-- (total momentum after the collision) = (total momentum before it)

and

-- keep the directions of the velocities straight.

#1:

What's the total momentum before the collision ?

Ball-A ... (0.5 kg) x (10 m/s forward) = 5 kg-m/s forward

Ball-B ... (0.5 kg) x (zero)  =  zero

Sum before the collision = 5 kg-m/s forward

The question says that both balls move away from the collision together.

So their velocities are the ame speed in the same direction.

What's the total momentum after the collision ?

Ball-A ... (0.5 kg) x (v m/s)

Ball-B ... (0,5 kg) x (v m/s)The trick to this one is to keep straight on the direction of 'velocity'.

But it has to be equal to the sum before the collision, so

(1 kg) x (v m/s) = 5 kg-m/s forward

v = 5 m/s forward (choice - C)

#2:

What's the total momentum before the collision ?

Ball-A ... (6 kg) x (10 m/s forward) = 60 kg-m/s forward

Ball-B ... (2 kg) x (5 m/s backward) = 10 kg-m/s backward

Sum before the collision = 50 kg-m/s forward

The question says that both balls stick together after the collision.

So now we have one object of 8 kg, moving with a velocity of v .

Total momentum after the collision:

One object ... (8 kg) x (v m/s)

But it has to be equal to the sum before the collision, so

(8 kg) x (v m/s) = 50 kg-m/s forward

v = 6.25 m/s forward (choice - B)

Answer:

I X j = k       (perpendicular to plane)

j X k = 0

i X k = 0       cross products for vectors i, j, k  

Flux = B dot A    and only B in the k direction is relevant

Flux = .550 T * .0435^2  m^2 = .00104 Webers-m^2

The magnitude of the flux through the given surface produced by the magnetic field B is 10.73 T cm².

Magnetic flux is a measure of the amount of magnetic field passing through a given surface. It is defined as the product of the magnetic field B and the area A that it passes through, multiplied by the cosine of the angle between the magnetic field and the surface normal:

Φ = B ⋅ A ⋅ cos(θ)

Where Φ = is the magnetic flux,

B =  is the magnetic field,

A = is the area of the surface,

θ =  is the angle between the magnetic field and the surface normal.

In other words, magnetic flux is a measure of how much magnetic field passes through a surface, taking into account both the strength of the magnetic field and the orientation of the surface with respect to the field.

Magnetic flux is an important concept in electromagnetism and is used to describe the behavior of magnetic fields in a variety of applications, including generators, motors, and transformers. It is also used in the study of magnetism in materials, such as ferromagnetic materials, where the flux density is an important property.

Here in the question,

To calculate the flux through the given surface produced by the magnetic field B, we can use the formula:

Φ = ∫∫ B · dA

Where Φ = is the magnetic flux,

B =  is the magnetic field,

dA =  is an infinitesimal area vector pointing outward from the surface.

Since the surface is a flat square in the xy-plane, its normal vector is the unit vector k^. Therefore, the outward-pointing area vector dA can be expressed as:

dA = dx dy k^

Where dx and dy = are infinitesimal elements of length in the x and y directions, respectively.

Integrating over the surface, we have:

Φ = ∫∫ B · dA

= ∫∫ (0.200T i^ + 0.250T j^ + 0.550T k^) · (dx dy k^)

= ∫∫ 0.550T dx dy

= 0.550T ∫∫ dx dy

= 0.550T (4.35 cm)²

Φ = 10.73 T cm²

Therefore, the magnitude of the flux through the given surface produced by the magnetic field B is 10.73 T cm².

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Answer:

hahahahhahahahahahahahhaahha

The go-kart will travel approximately 444.3 meters during the given time period.

To determine the distance traveled by the go-kart during the given time period, we can use the equation:

\(\[ \text{{distance}} = \frac{1}{2} \cdot \text{{acceleration}} \cdot \text{{time}}^2 \]\)

Given:

Mass of the go-kart, \(\( m = 73.9 \)\) kg

Net force acting on the go-kart, \(\rm \( F = 90.2 \)\) N

Time period, \(\rm \( t = 38.0 \)\) s

First, we need to calculate the acceleration experienced by the go-kart using Newton's second law of motion: \(\rm \[ F = m \cdot a \]\)

Solving for acceleration:

\(\[ a = \frac{F}{m} \]\)

Substituting the given values:

\(\[ a = \frac{90.2 \, \text{N}}{73.9 \, \text{kg}} \]\)

Now, we can calculate the distance traveled:

\(\[ \text{{distance}} = \frac{1}{2} \cdot a \cdot t^2 \]\)

Substituting the values of \(\( a \)\) and \(\( t \)\):

\(\[ \text{{distance}} = \frac{1}{2} \cdot \left(\frac{90.2 \, \text{N}}{73.9 \, \text{kg}}\right) \cdot (38.0 \, \text{s})^2 \]\)

Calculating the result:

\(\[ \text{{distance}} \approx 444.3 \, \text{m} \]\)

Therefore, the go-kart will travel approximately 444.3 meters during the given time period.

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The net forces on the box acting perpendicular and parallel to the floor are

∑ F[perp] = F[normal] - 325 N + (475 N) sin(-35°) = 0

∑ F[perp] = (475 N) cos(-35°) - F[friction] = ma

where m is the mass of the box and a is its acceleration.

Solve for F[normal] :

F[normal] = 325 N + (475 N) sin(35°) ≈ 597 N

Then the frictional force has magnitude

F[friction] = 0.55 F[normal] ≈ 329 N

and so

60.5 N ≈ (325 N) a/g

(note that sin(-35°) = -sin(35°), cos(-35°) = cos(35°), and mg = 325 N so m = (325 N)/g)

Solve for a :

a = (60.5 N) / (325 N) g ≈ 1.82 m/s²

(a) Assuming this acceleration is constant, starting from rest, the box achieves a final velocity v such that

v² = 2a∆x

v² = 2 (1.82 m/s²) (5.80 m)

⇒   v ≈ 4.60 m/s

which happens in time t such that

v = at

4.60 m/s = (1.82 m/s²) t

⇒   t ≈ 0.177 s

(b) Let µ be the coefficient of static friction. The box just begins to slide if the magnitude of the parallel component of the applied force matches the magnitude of friction, i.e.

∑ F[para] = (475 N) cos(-35°) - F[friction] = 0

We have

F[friction] = µ F[normal] = (597 N) µ

so that

(597 N) µ = (475 N) cos(35°)

⇒   µ ≈ 0.651

Answer:

yes

Explanation:

Answer and Explanation: Comets are frozen extras from the development of the nearby planetary group made out of residue, rock and frosts. They range from a couple of miles to many miles wide, however as they circle nearer to the sun, they heat up and regurgitate gases and residue into a shining head that can be bigger than a planet. This material structures a tail that extends a huge number of miles.

The volume of the parallelepiped determined by u, v, and w is| w · ( u × v)|.

In geometry, a parallelepiped is a three-dimensional figure made up of six parallelograms. Similar to a parallelogram, just like a cube is a square. The volume of the parallelepiped enclosed by a, b, and c is: Volume = area of ​​the base and height = |a×b∥c||cosφ|=|(a×b)·c| The formula comes from the properties of the cross product. The area of ​​the base of the parallelogram is |a×b| and the vector a×b is perpendicular to the base. The height of the cube is |c||cosφ|. Therefore, the volume of the parallelepiped determined by u, v, and w is| w · ( u × v)|.

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Answer:

twice

Explanation:

From magnification = height of image / height of object

Distance of image/ distance of object = magnification

If the distance and height of the object represents the initial light distance and the exposed surface respectively.

And similarly the distance and height of the image represents the final light distance and the exposed surface respectively.

Hence the new image exposure would be twice as large.

If we use the formula our point of investigation is Height of image,

H2= D2/D1× H1

H2 = 2D2/D1 × H1

H2 = 2H1

Answer:

It is C the units and D

Explanation:

18.)C

19.)D

Percentage of college graduates believing their education was useful for helping them grow personally and intellectually, but not useful for helping them develop specific skills and knowledge for the workplace is 70%.

According to a 2018 study by the Association of American Colleges and Universities, approximately 70% of college graduates believe that their education was very or somewhat effective in helping them grow personally and intellectually, but not very effective in helping them develop specific skills and knowledge for the workplace.

This suggests that many college graduates may feel that their education did not adequately prepare them for the demands of the labor market, despite being beneficial for personal and intellectual growth. This finding highlights the importance of considering the alignment between higher education and workforce development, as well as the need for continued learning and skill development beyond formal education.

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Answer:

i cant see it just put the question

Explanation:

In general, the statement that validation is not needed for single-use systems in a bioreactor is not accurate. Validation is an essential process in bioprocessing that ensures the reliability, consistency, and safety of the manufacturing process. Single-use systems, which are increasingly used in bioreactors, can introduce unique challenges and considerations.

Validation of single-use systems involves assessing their performance, integrity, and compatibility with the process requirements. Factors such as material integrity, sterile connections, and proper functioning of sensors and control systems should be evaluated to ensure the system's suitability for use.

While single-use systems offer advantages in terms of cost, flexibility, and minimizing cross-contamination risks, they still require validation to demonstrate their reliability and performance. It is essential to follow industry standards, regulatory guidelines, and good manufacturing practices to ensure the quality and safety of bioprocessing operations, regardless of the system being used.

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Answer:

Net displacement = 3.2 m

Explanation:

Given:

Mass of man = 80 kg

Mass of trolley = 320 kg

Speed = 1 m/s

Time = 4 sec

Computation:

Displacement by man = 1 m/s × 4 sec

Displacement by man = 4 m

Net ext force (trolley) = com at rest

So,

320 × X = 80(4 - X)

32X = 32 - 8X

40X = 32

X = 0.8 m

Net displacement = 4 m - 0.8 m

Net displacement = 3.2 m

Answer:

3) 3.2 m

Explanation:

The computation of the displacement relative to the ground after 4 seconds is shown below:

Let us assume the following

Starting x coordinate is at the origin

As it does not involve any external force so x coordinated would remain unchanged

Now the separation between the man and the trolley is

\(= 4 \times 1\)

= 4 m

And, we assume the displacement of man be x

So, for trolley it would be (4 -x)

Now we develop the equation which is

\(80 \times x = 320 \times (4 - x)\)

x = 16 - 4x

Therefore x = 3.2 m