It takes 90 minutes to vacuum 30 vehicles. At this rate, how many minutes does it take to vacuum 7 vehicles?

Answer:

here it is

Step-by-step explanation:

if u have any question tell me

Answer:

26

Step-by-step explanation:

Easy

The answer to the equation is 2

\(2-14=-12\)

The outlier of 2 decreases the mean page count.

What is mean and median?

The mean is that the variety you get by dividing the total of a collection of values by the quantity of values within the set.

In distinction, the median is that the middle variety in an exceedingly set of values once those values square measure organized from smallest to largest.

Main Body:

From the picture we can  know that outlier of 2 does not effect the median page count.

But outlier of 2 decreases the mean page count.

it can be found out by taking mean

(1+2+3+2+1+2+2+1)/8= 1.75

and if we remove outlier of 2 ,then

(1+3+2+1+2+2+1)/7 = 1.86

Hence ,the outlier of 2 decreases the mean page count.

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Answer:

the answer is d

Step-by-step explanation:

The two equivalent ratios of 15 / 60 are 30/120 and  45 / 180.

An ordered pair of numbers a and b, represented as a / b, is a ratio if b is not equal to 0. A proportion is an equation that sets two ratios at the same value. The numerical relationship between two values demonstrates how frequently one value contains or is contained within another.

The given fraction or ratio is 15 / 60. The equivalent ratio to the 15 / 60 will be written as:-

15 / 60 = 15 x 2 / 60 x 2

15 / 60 = 30 / 120

Multiply the numerator and the denominator by the same number.

15 / 60 = 15 x 3 / 60 x 3

15 / 60 = 45 / 180

Therefore, the two equivalent ratios of 15 / 60 are 30/120 and  45 / 180.

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\(\textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h}{3}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=3\\ h=7 \end{cases}\implies V=\cfrac{\pi (3)^2(7)}{3} \\\\\\ V=21\pi \implies {\Large \begin{array}{llll} V\approx 65.97 \end{array}} ~in^3 ~~ \approx 66~in^3\)

Answer:

the scale factor is 1.25

Step-by-step explanation:

Hope this helps

Answer: $350

Step-by-step explanation:

Answer:

10yd x 14 yd x 3yd = 420yd ^3

Step-by-step explanation:

When calculating for the volume you multiply all three numbers. That’s why when you write your answer you cube it.

Answer:125=n

Step-by-step explanation: 375 divided by 3 is 125

Answer:

The answer is... x = 7 I used an app called Cymath is goes down step by step to help.

Step-by-step explanation:

I hope I helped you! :)

Answer:

the anwser is d

Step-by-step explanation:

The mass of salt in the tank at time t.

dS/dt = 10 - S/400

S(0) = 100 grams

The solution is S(t) = 4000 - 3900\(e^{\frac{-t}{400}}\)

A tank holds water V(0) = 4000 liters in which salt S(0) = 100 grams.

So dS/dt = S(in) - S(out)

S(in) = 1 × 10 = 10 gram/liters

S(out) = S/V × 10 = 10S/V gram/liters

V = V(0) + q(in) - q(out)

V = 4000 + 10t - 10t

V = 4000 liters

dS/dt = 10 - 10S/V

dS/dt = 10 - 10S/4000

dS/dt = 10 - S/400

Now given; S(0) = 100.

Here, p(t) = 1/400, q(t) = 10

\(\int p(t)dt = \int\frac{1}{400}dt\)\(\int p(t)dt = \frac{1}{400}t\)

\(\mu=e^{\int p(t)dt}\)

\(\mu=e^{\frac{t}{400}}\)

So, S(t) = \(\frac{\int\mu q(t)dt+C}{\mu}\)

S(t) = \(\frac{\int e^{\frac{t}{400}} \cdot10dt+C}{e^{\frac{t}{400}}}\)

S(t) = \(e^{\frac{-t}{400}} \left({\int e^{\frac{t}{400}} \cdot10dt+C}\right)\)

S(t) = \(e^{\frac{-t}{400}} \left({10\times\frac{e^{\frac{t}{400}}}{1/400} +C}\right)\)

S(t) = \(e^{\frac{-t}{400}} \left({4000\times{e^{\frac{t}{400}} +C}\right)\)

Now solving the bracket

S(t) = 4000 + \(e^{\frac{-t}{400}}\)C.....(1)

At S(0) = 100

100 = 4000 + \(e^{\frac{-0}{400}}\) C

100 = 4000 + \(e^{0}\) C

100 = 4000 + C

Subtract 4000 on both side, we get

C = -3900

Now S(t) = 4000 - 3900\(e^{\frac{-t}{400}}\)

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The complete question is:

A tank holds 4000 liters of water in which 100 grams of salt have been dissolved. Saltwater with a concentration of 1 grams/liter is pumped in at 10 liters/minute and the well mixed saltwater solution is pumped out at the same rate. Write initial the value problem for:

The mass of salt in the tank at time t.

dS/dt =

S(0) =

The solution is S(t) =

The solution is, : d) 255 ≤ f(x) ≤ 340.

An inequality is a relation which makes a non-equal comparison between two numbers or mathematical expressions.

here, we have,

The function

f(x)= 8.5x

represents the amount of money that Steve earns given the number of hours, x, he works.

The dependent variable is the total amount that he earns, f(x) while the independent variable is the number if hours, x that he works. The range is the possible values of the dependent variable that satisfies the equation.

Steve works between 30 and 40 hours per week.

This means that the lowest amount that he earns is 8.5×30 = $255

The highest amount that he earns is 8.5× 40 = 340.

Therefore, the range is

255 ≤ f(x) ≤ 340

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The score needed on the final exam to achieve a C grade is 79.33, rounded to 2 decimal places.

Homework is worth 30% of the grade, which is also a significant portion. The average homework score is 90, which means the average of all homework scores is 90.

Test reviews are only worth 5% of the grade, so they have the smallest impact on the overall average. The average test review score is 72, which means the average of all test review scores is 72.

Finally, the final exam is worth 15% of the grade, and we need to find out what score is needed on the final exam to achieve a C grade, which is 72%.

To calculate the overall average, we can use the weighted average formula.

Overall Average = (Tests Average x 0.5) + (Homework Average x 0.3) + (Test Reviews Average x 0.05) + (Final Exam Score x 0.15)

Substituting the values we know, we get:

Overall Average = (59 x 0.5) + (90 x 0.3) + (72 x 0.05) + (Final Exam Score x 0.15)

Simplifying this equation, we get:

Overall Average = 29.5 + 27 + 3.6 + (Final Exam Score x 0.15)

Overall Average = 60.1 + (Final Exam Score x 0.15)

To get a C grade, the overall average needs to be 72%. So we can set up an equation and solve for the Final Exam Score:

72 = 60.1 + (Final Exam Score x 0.15)

Solving for Final Exam Score, we get:

Final Exam Score = (72 - 60.1) / 0.15

Final Exam Score = 79.33

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When we take a marble from the bag, the number of red marbles decreases by 1 and the total number of marbles decreases by 1 as well.

So after the first draw, the probability of getting a red marble on the second draw becomes 4/7 (since there are now 4 red marbles out of 7 total marbles).

To find the probability of getting 2 red marbles in a row, we multiply the individual probabilities of getting a red marble on each draw:

P(2 red marbles) = P(red marble on first draw) * P(red marble on second draw)

P(2 red marbles) = (5/8) * (4/7) = 20/56 = 5/14

So the probability of getting 2 red marbles in a row is 5/14.

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Answer:

10

Step-by-step explanation:

10/-5 = -2

-2+-2 = -4

Answer:

10

Step-by-step explanation:

First, arrange this word problem as an equation. Using N as the unknown number, we see:

(N/-5) + (-2) = -4

Next, we add -2 to both sides of the equation:

(N/-5) = -2

Now multiply both sides by -5:

N=10

Hope that helps!

Answer:

39 cents

Step-by-step explanation:

3.38÷8.5=0.39

The ODE has a solution for any point (xo, yo) where yo is a real number and y(x) is continuous in the neighborhood of (xo, yo), and it has a unique solution for any point (xo, yo) where yo is a real number and the interval of consideration includes xo. The solution to the ODE via separation of variables is y = -1/((1/10)x^2 + C), and the particular solution can be found by substituting the initial condition y(xo) = yo into the general solution.

(a) For what points (xo, yo) does this ODE have any solution? Explain.

To determine the points (xo, yo) for which the given ODE has a solution, we need to consider the conditions under which the equation is well-defined and solvable. In this case, the equation is \(y' = xy^2/5.\)

Since y' is a derivative with respect to x, for the equation to have a solution at a particular point (xo, yo), the function y(x) must be differentiable at that point. This means that yo must be a real number and the function y(x) must be continuous in the neighborhood of (xo, yo).

Therefore, the ODE has a solution for any point (xo, yo) where yo is a real number and y(x) is continuous in the neighborhood of (xo, yo).

(b) For what points (xo, yo) does this ODE have a unique solution? Explain.

To have a unique solution for the ODE, we need to satisfy the conditions for existence and uniqueness of solutions. In this case, the equation is \(y' = xy^2/5.\)

The existence and uniqueness theorem states that if a function and its derivative are continuous on a closed interval [a, b], then there exists a unique solution to the initial value problem y(xo) = yo for any point (xo, yo) within that interval.

Therefore, the ODE has a unique solution for any point (xo, yo) where yo is a real number and the interval of consideration includes xo.

(c) Find this solution via separation of variables.

To find the solution of the given ODE via separation of variables, we can rewrite the equation as follows:

\(dy/y^2 = (x/5) dx\)

Integrating both sides:

∫(dy/y²) = ∫(x/5) dx

Using the power rule for integration, we have:

\(-1/y = (1/10)x^2 + C\)

Where C is the constant of integration. Solving for y:

\(y = -1/((1/10)x^2 + C)\)

This represents the general solution of the given ODE. To find the particular solution, we need to use the initial condition y(xo) = yo. Plugging in the values xo and yo into the general solution, we can solve for the constant C and obtain the unique solution for the initial value problem.

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According to the output analysis, the model presented above is of Discrete-event simulation (DES) type.

What is Discrete-event simulation (DES)?

Discrete-event simulation (DES) is indeed a type of computer-based simulation where events occur at specific points in time. In DES, a system's behavior is modeled by specifying the sequence of events that occur during the system's lifespan.

In a discrete-event simulation, the state of the system changes only when events occur, rather than continuously evolving over time. Events represent significant occurrences or activities within the system, such as customer arrivals, service completions, or resource allocations. Each event is associated with a specific time or occurrence point, and the simulation progresses by processing events in chronological order.

DES is particularly useful for modeling complex systems where the timing of events and their interactions play a crucial role. It allows for capturing the dynamic nature of the system, simulating the flow of entities (such as customers, vehicles, or messages) through the system, and observing the effects of event sequencing and resource allocation on system performance.

By simulating the system and observing the events and their consequences, DES enables analysts to evaluate different scenarios, study the impact of various parameters, and optimize system design or operation. It provides insights into system performance measures, such as throughput, waiting times, resource utilization, or customer satisfaction.

Overall, discrete-event simulation is a powerful technique for modeling and analyzing complex systems with discrete changes, events, and interactions over time.

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The model above is known as a discrete-event simulation model according to the output analysis.

A discrete event simulation is a type of computer-based modeling where a series of discrete events in a system are simulated.

In such models, the system under consideration evolves through a series of discrete events that are instantaneous.

For example, in the retail establishment model, each customer arriving at the store would be considered a separate, discrete event.

The simulation would model the sequence of events that occur between the time the store opens at 9 am and when the last customer leaves before closing time at 5 pm.

The objective of the simulation would be to estimate some measure of the quality of customer service during this time period.

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Calcium (Ca) can form a Ca2+ cation by losing its two valence electrons.

Elements in group 2A (2) of the periodic table form ions with a charge of 2+. Therefore, the correct answer is c. 2+.

Group 2A elements, also known as alkaline earth metals, have two valence electrons in their outermost shell, which they tend to lose in chemical reactions to form cations with a charge of 2+. For example, magnesium (Mg) can form a Mg2+ cation by losing its two valence electrons. Similarly, calcium (Ca) can form a Ca2+ cation by losing its two valence electrons.

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By using the concept of data structure, it can be concluded that-

First option is correct

What is data structure?

Data structure is a group of elements that provides an efficient way of storing and organizing data so that the data can be accessed and used efficiently. Data structure is a very important tool for computer science and computer engineer and especially in IT industry. Nowadays, lots of research work is being done on data structure.

The three main components of data model structure in SAP S/4HANA are,

configuration data, master data and transaction data

First option is correct

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Answer:

I think The choose C. 15

Step-by-step explanation:

wv=40

vG=20 =ST

PT=25

ST²+SP²=PT² —> 20²+SP²=25 —> 400+SP²=625

PS²=225 —> SP=15 in

I hope I helped you^_^

The value of SP is 15 inch.

The well-known geometric theorem that the sum of the squares on the legs of a right triangle is equal to the square on the hypotenuse.

Given:

VW=40

VG=20 =ST

and, PT=25

Now, using pythagoras theorem

ST²+SP²=PT²

20²+SP²=25

400+SP²=625

PS²=225

SP=15 in

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Answer:

C

Step-by-step explanation:

The 3 is directly outside the parentheses, meaning you need to distribute the 3 to the x and the 4 because they are inside the parentheses. There is no addition, subtraction, or division involved in this so C is correct.

Answer:

C

Step-by-step explanation:

i took the test

A constant function is a function that returns the same output every time it is called, regardless of the input. In this case, we want to create a constant function that returns an infinite list of all the natural numbers starting at 0.

Here's an example of how you could implement the nats function in Haskell:

makefile

Copy code

nats :: [Integer]

nats = [0..]

The [0..] syntax creates an infinite list that starts with 0 and continues indefinitely. Every time the nats function is called, it returns this same infinite list, so it's considered a constant function.

Another way to write the nats function is to use the iterate function, which generates a list by repeatedly applying a function to an initial value.

makefile

Copy code

nats :: [Integer]

nats = iterate (+1) 0

In this case, iterate (+1) 0 generates a list by repeatedly adding 1 to 0. The first element of the list is 0, the second element is 0 + 1 = 1, the third element is 1 + 1 = 2, and so on. This generates an infinite list of all the natural numbers starting at 0, which is exactly what we want.

In either case, you can take any number of elements from the nats list by using the take function. For example, take 5 nats would return the first 5 elements of the nats list, which would be [0, 1, 2, 3, 4].

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The given statement " The normal curve is symmetric about its​ mean, u" is true because it is equally distributed on both the sides of the mean.

The normal curve is always symmetric about the line representing its mean, u.

This means that the curve is equally distributed on both sides of the line representing the mean.

And the area under the curve to the left of the mean is equal to the area under the curve to the right of the mean.

This is a defining characteristic of the normal distribution.

Which is widely used in statistics due to its many useful properties.

Therefore, the normal curve is symmetric which is about its mean is a true statement.

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The above question is incomplete, the complete, question is:

The normal curve is symmetric about its​ mean, u. T/F.

Answer:

True statements

Additional information

Closed circle:  ≤ or ≥

Open circle:  < or >

The triangle degree measure of ZABC is 180° - 69° - 66. 145°mLABC = 44.855°. (E) mLABC = 44.855°

The given triangle ZABC is shown below.

69° is given and the sum of all angles of a triangle is equal to 180°.

Therefore: mBAC

= 180° - mBCA - mABC

= 180° - 69° - mABC

= 111° - mABC ...(1)

Let's use the law of sines to find the length of side AB.

sin BCA / BC

= sin BAC / BA sin 69° / 50

= sin mABC / ABAB

= sin mABC × 50 / sin 69°AB

≈ 56.042 cm

Now, we will use the law of cosines to find the angle:

mLABC.a² = b² + c² - 2bc cos

ABLAB² = x² + y² - 2xy cos mLABC Cos

mLABC = (x² + y² - LAB²) / 2xycos

mLABC = (31² + 50² - 56.042²) / (2 × 31 × 50)cos

mLABC ≈ 0.41929

mLABC ≈ 66.145°

Therefore, the degree measure of ZABC is 180° - 69° - 66.145°mLABC = 44.855°

Answer: (E) mLABC = 44.855°

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