As per given data, Jack's total earnings over "n" days: $\(10.00 * n\)
Jill's total earnings over "n" days:\(\frac{ ((2^n - 1) cents)}{100}\).
It seems like Jack earned a fixed amount of $10.00 per day, while Jill's earnings doubled each day. To find out how much Jill earned in total, we can calculate the sum of her earnings over a given period.
Let's assume the period for both Jack and Jill is "n" days.
For Jack, his earnings are constant at $\(10.00\) per day. Therefore, his total earnings over "n" days would be:
Jack's earnings = $\(10.00 * n\)
For Jill, her earnings are doubling each day. We can observe that her earnings form a geometric progression with a common ratio of 2. Her earnings on each day can be calculated using the formula for the sum of a geometric series:
Jill's earnings on day 1 = 1 cent = $0.01 (given)
Jill's earnings on day 2 = 2 cents = $0.02
Jill's earnings on day 3 = 4 cents = $0.04
Jill's earnings on day n = 2^(n-1) cents
Jill's total earnings over "n" days can be calculated using the formula for the sum of a geometric series:
Jill's earnings = (1 cent) + (2 cents) + (4 cents) + ... + (2^(n-1) cents)
= (2^n - 1) cents
To convert Jill's total earnings from cents to dollars, we divide by 100:
Jill's total earnings = \(\frac{((2^n - 1) cents)}{100}\)
So, in summary:
Jack's total earnings over "n" days: $10.00 × n
Jill's total earnings over "n" days:\(\frac{ ((2^n - 1) cents)}{100}\)
Keep in mind that if you have a specific value for "n" (the number of days), you can substitute it into the formulas to calculate the exact earnings for both Jack and Jill.
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please help me answer this question asap
Answer:
It's quite easy
Step-by-step explanation:
people less than 30 years = frequency of people 0 to 15 + 15 to 30 = 8+15 =23
Therefore there are 23 people less than 30 years old.
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Let Y 1 ,Y 2 ,Y 3 ,Y 4 be the order tatitic of a U(0,θ) random ample X 1 ,X 2 ,X 3 ,X 4 . (a) Find the joint pdf of (V 1 ,V 2 ,V 3 ) , where V 1 = Y 2 Y 1 ,V 2 = Y 3 Y 2 , and V 3 = Y 4 Y 3 . (b) Find the marginal pdf of V 2
a. f(v₁, v₂, v₃) = f₁(v₁) × f₂(v₂) × f₃(v₃) is the joint pdf of (V₁, V₂, V₃).
b. The marginal pdf of V₂ is 1, indicating that V₂ is uniformly distributed between 0 and 1.
Given that Y₁, Y₂, Y₃, and Y₄ are order statistics of a random sample X₁, X₂, X₃, and X₄ from a uniform distribution U(0, θ), we know that the joint pdf of the order statistics is given by:
f(y₁, y₂, y₃, y₄) = n! / [(k₁ - 1)! × (k₂ - k₁ - 1)! × (k₃ - k₂ - 1)! × (n - k₃)!] × [1 / (θⁿ)],
where n is the sample size (n = 4 in this case), θ is the upper bound of the uniform distribution (θ in U(0, θ)), and k₁, k₂, k₃ are the orders of the order statistics (in ascending order).
Now, we need to determine the values of k₁, k₂, k₃ for the given V₁, V₂, V₃.
k₁ = 1 (as Y₁ is the smallest order statistic)
k₂ = 2 (as Y₂ is the second smallest order statistic)
k₃ = 3 (as Y₃ is the third smallest order statistic)
Now, we can express V₁ = Y₁/Y₂, V₂ = Y₂/Y₃, and V₃ = Y₃/Y₄ in terms of the order statistics:
V₁ = Y₁ / Y₂ = X₁ / X₂
V₂ = Y₂ / Y₃ = X₂ / X₃
V₃ = Y₃ / Y₄ = X₃ / X₄
Since X₁, X₂, X₃, and X₄ are independently and uniformly distributed between 0 and θ, the joint pdf of (V₁, V₂, V₃) can be expressed as the product of their individual pdfs:
f(v₁, v₂, v₃) = f₁(v₁) × f₂(v₂) × f₃(v₃),
where f₁(v₁) is the pdf of V₁, f₂(v₂) is the pdf of V₂, and f₃(v₃) is the pdf of V₃.
(b) To find the marginal pdf of V₂, we integrate the joint pdf f(v₁, v₂, v₃) over v₁ and v₃:
f₂(v₂) = ∫[0, ∞] ∫[0, ∞] f(v₁, v₂, v₃) dv₁ dv₃
Since we know the joint pdf f(v₁, v₂, v₃) is the product of the individual pdfs, we can write:
f₂(v₂) = ∫[0, ∞] ∫[0, ∞] f₁(v₁) × f₂(v₂) × f₃(v₃) dv₁ dv₃
Now, integrate the expression with respect to v₁ and v₃ over their respective domains (0 to ∞):
f₂(v₂) = ∫[0, ∞] f₁(v₁) dv₁ × ∫[0, ∞] f₃(v₃) dv₃
Since V₁ = X₁ / X₂ and V₃ = X₃ / X₄, we can express f₁(v₁) and f₃(v₃) in terms of the pdf of the uniform distribution:
f₁(v₁) = 1 / θ for 0 ≤ v₁ ≤ 1
f₃(v₃) = 1 / θ for 0 ≤ v₃ ≤ 1
Integrating over their respective domains:
∫[0, ∞] f₁(v₁) dv₁ = ∫[0, 1] (1 / θ) dv₁ = 1
∫[0, ∞] f₃(v₃) dv₃ = ∫[0, 1] (1 / θ) dv₃ = 1
Therefore, the marginal pdf of V₂ is:
f₂(v₂) = 1 × 1 = 1.
The marginal pdf of V₂ is a constant 1, indicating that V₂ is uniformly distributed between 0 and 1.
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Let Y₁ ,Y₂ ,Y₃ ,Y₄ be the order statitic of a U(0,θ) random ample X₁ , X₂ ,X₃ ,X₄ .
(a) Find the joint pdf of (V₁ ,V₂ ,V₃ ) , where V₁ = Y₁/Y₂ ,V₂ =Y₂/Y₃ and V₃ = Y₃/Y₄ .
(b) Find the marginal pdf of V₂.
A group went together to the Clayton Art and Wine Festival. They bought 30 tickets. Child tickets are $2 each and Adult tickets are $4. 50 each. If they spent $107. 50 total, how many of each type of ticket did they buy?
Answer:
they bought 23 adult tickets and 2 child tickets
Step-by-step explanation:
the explanation is in the screenshot below
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Lucy’s ranch has 1,718 acres and Paul’s ranch has 2,484 acres. What is the difference in size between the two ranches
Answer:
766 acres is the difference.
Step-by-step explanation:
2,484 minus 1,718 equals 766 acres.
hope this helped!
:)
Answer:
ranch has a ton of calories
Step-by-step explanation:
How do i solve this?
Attached is my written question in picture form. I apologize for my handwriting
The Solution:
Given the linear function below:
\(\begin{gathered} f(x)=4.6x+26 \\ \text{Where} \\ f(x)=\text{ the number of graduates from college } \\ x=\text{ number of years after 1998} \end{gathered}\)So, the slope of the linear function above is the coefficient of x in the given linear function. Therefore, the slope of the given function is 4.6
The interpretation of the slope is 4.6% of the people graduate from college every year after the year 1998.
An a my baker is making a cake for a Terran visitor. The cake is removed from the over at 357 and cools to 130 after 25 min in a room at 72. How long will it take for the cake to cook off to 90?
Answer:
It will take 43.37 mins for the cake to cook off to 90
Step-by-step explanation:
From Newton's law of cooling
\(T_{(t)} = T_{s} + (T_{o} - T_{s})e^{kt}\)
Where
\(t =\) time
\(T_{(t)}\) = Temperature of the given body at time \((t)\)
\(T_{s}\) = Surrounding temperature
\(T_{o}\) = Initial temperature of the body
and \(k\) = constant
From the question,
\(T_{o}\) = 357
\(T_{s}\) = 72
\(T_{o} - T_{s}\) = 357 - 72 = 285
∴ \(T_{(t)} = 72 + 285e^{kt}\)
From the question, the cake cools to 130 after 25 min. Then, we can write that
\(T_{(25)} = 72 + 285e^{k(25)}\)
∴ \(130 = 72 + 285e^{25k}\)
Then,
\(130 - 72 = 285e^{25k}\)
\(58 = 285e^{25k}\)
\(\frac{58}{285} = e^{25k}\)
Take the natural log (ln) of both sides
\(ln^{\frac{58}{285} } =ln^{ e^{25k}}\)
\(-1.5920 = 25k\)
∴ \(k =\frac{-1.5920}{25}\)
\(k = -0.06368\)
Now, to determine how long it take for the cake to cook off to 90
That is,
\(T_{(t)} = 72 + 285e^{kt}\)
\(90 = 72 + 285e^{-0.06368t}\)
\(90 - 72= 285e^{-0.06368t}\)
\(18 = 285e^{-0.06368t}\)
\(\frac{18}{285} = e^{-0.06368t}\)
\(\frac{6}{95} =e^{-0.06368t}\)
Take the natural log (ln) of both sides
\(ln^{\frac{6}{95} } = ln^{e^{-0.06368t}}\)
\(-2.7621 = -0.06368t\\\)
∴ \(t = \frac{-2.7621}{-0.06368}\)
\(t = 43.37 mins\)
Hence, it will take 43.37 mins for the cake to cook off to 90.
Written as the product of its prime factors, 2250=2x3²x5³. Two integers, A and B, can be written as products of prime factors. A=2xpxq¹ B=2xp² xq² The lowest common multiple (LCM) of A and B is 2250. Write down the values of p, q and r.
The values of p, q, and r are p = 2, q = 5, and r = 3, respectively.
Given that the lowest common multiple (LCM) of A and B is 2250, and the prime factorization of A is A = 2 × p × q¹, and the prime factorization of B is B = 2 × p² × q², we can compare the prime factorizations to determine the values of p, q, and r.
From the prime factorization of 2250 (2 × 3² × 5³), we can observe the following:
The prime factor 2 appears in both A and B.
The prime factor 3 appears in A.
The prime factor 5 appears in A.
Comparing this with the prime factorizations of A and B, we can deduce the following:
The prime factor p appears in both A and B, as it is present in the common factors 2 × p.
The prime factor q appears in both A and B, as it is present in the common factors q¹ × q² = q³.
From the above analysis, we can conclude:
p = 2
q = 5
r = 3.
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find dy/dx.x = t2, y = 6 − 8t
The differentiation of the function is -4/t.
Given are two equations x = t², y = 6 - 8t, we need to find \(\mathrm {\frac{dy}{dx} }\).
So,
To find \(\mathrm {\frac{dy}{dx} }\), we can use the chain rule of differentiation.
The chain rule states that if y is a function of u and u is a function of x, then the derivative of y with respect to x \(\mathrm {\frac{dy}{dx} }\) is given by:
\(\mathrm {\frac{dy}{dx} = \frac{dy}{du} \times \frac{du}{dx}}\)
Since here the equations are simpler so we will just find the derivatives with respect to t and then divide both the derivates.
In this case, we have x = t² and y = 6 - 8t.
Differentiating x = t² w.r.t. t, we get,
\(\mathrm {\frac{dx}{dt} = 2t}\)
Similarly,
Differentiating y = 6 - 8t w.r.t. t, we get,
\(\mathrm {\frac{dy}{dt} = -8}\)
Now, dividing both the derivates, we get,
\(\mathrm {\frac{dy}{dt} \ \div \mathrm {\frac{dx}{dt} }}\)
\(\mathrm {\frac{dy}{dt} \ \times \mathrm {\frac{dt}{dx} }}\\\\ = \frac{-8}{2\mathrm t} \\\\ = \frac{-4}{t}\)
Hence the differentiation of the function is -4/t.
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Which of the following is a characteristic of a regular tessellation?
Explanation:
For regular tessellations, the types of polygons that we can use are
squares or rectanglesequilateral trianglesregular hexagonsWe can only pick one of those shapes.
Shapes like regular octagons or pentagons will not work on their own because there is gap or overlap if we tried to glue them together. Think of tiles on the floor. There cannot be any gap or overlap when forming a tessellation.
If you wanted to use octagons to tessellate the plane, then you'd need squares to fill in the gaps. At this point, it's not considered a regular tessellation.
Simplify 3f-2f+f I need a answer for that please
Answer:
2f
Step-by-step explanation:
3f-2f+f | Given
1f + f | Subtract 3f and 2f
2f | Add 1f and 1f.
can some help me pls asap
Answer:
260cm²
Step-by-step explanation:
Area of parallelogram = 20 × 13
= 260cm²
Answer: 260 cm^2
Step-by-step explanation: We will be using the same formula as A = b * h for a parallelogram. The base is 20 and the height is 13 (NOT 15 because that is slant height). A = 20 * 13. The answer is 260 cm^2.
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What is 26.3×7.8 equal?
Answer: 205.14
Step-by-step explanation:
Multiply
Add
Insert Decimal Point
205.14
Answer:
205.14
Step-by-step explanation:
Step 1: Multiply without the decimal points, then put the decimal point in the answer:
263x78
Step 2: Line up the numbers:
2 6 3
x 7 8
Step 3: Multipy the top number by the bottom number one digit at a time starting from left to right:
\(\frac{\begin{matrix}\:\:&\:\:&2&6&3\\ \:\:&\times \:&\:\:&7&8\end{matrix}}{\begin{matrix}0&2&1&0&4\\ 1&8&4&1&0\end{matrix}}\)
Step 4: Add:
\(\frac{\begin{matrix}\:\:&\textbf{1}&\:\:&\:\:&\:\:&\:\:\\ \:\:&\textbf{0}&2&1&0&4\\ +&\textbf{1}&8&4&1&0\end{matrix}}{\begin{matrix}\:\:&\textbf{2}&0&5&1&4\end{matrix}}\)
Step 5: Insert Decimal Point:
205.14
2. Select the conversions that are equivalent to 10 yards.
Mark all that apply.
(А) 20 feet
C 30 feet
(В
240 inches
D 360 inches
Answer:
30 feet and 360 inches
Step-by-step explanation:
10 yards x 36 = 360 inches
10 yards x 3 = 30 feet
If a population has 500 individuals in it in 2010, and the per capita birth rate is 0.3 and the per capita death rate is 0.2, is the population growing or shrinking?
The population is growing as the births are more than deaths in an year.
What is Population Growth?Increases in a population's or a dispersed group's membership are referred to as population growth.
Given:
Total population = 500Per capita birth rate = 0.3Per capita death rate = 0.2To find: Is population growing or shrinking?
Finding:
Number of new-borns in an year = total population (per capita birth rate) = 500(0.3) = 150Number of deaths in an year = total population (per capita death rate) = 500(0.2) = 100Difference in the number of births and deaths = 150 - 100 = 50Hence the population is growing as the births are more than deaths in an year.
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Identifying Steps Involved in Deleting a Column from a Table
Tristan has moved the Television and related equipment Use the drop-down menus to identify the steps
row. Next, he needs to delete the blank row.
involved in deleting the blank row in this scenario.
Use
Percentage
Step 1:
Space cooling
17.5
Step 2
Step 3
Water heating
9.5
Step 4: Click the Delete Row option
9.2
9.1
8.8
Lighting
Space heating
Refrigerators and
freezers
Television and
related equipment
All other uses
5.9
40.0
1 - C
2 - B
3 - A
Step-by-step explanation:
Therefore, the correct answer is as follows:
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A farmer needs to box 740 apples. A box holds 9 apples. If every box is full except for the last, how many apples are in the last box?
Find the length of each leg of a right triangle given that one angle is 22° and the length of the hypotenuse is 10 inches.
The length of each leg of a right triangle given that one angle is 22° and the length of the hypotenuse is 10 inches are 3.75 and 9.27 inches respectively.
How to calculate the length of each leg of a right triangle?In order to determine the length of the opposite side and adjacent side, we would apply both the cosine and sine trigonometry ratio because the given side lengths represent the hypotenuse of a right-angled triangle.
cos(θ) = Adj/Hyp
Where:
Opp represent the adjacent side of a right-angled triangle.Hyp represent the hypotenuse of a right-angled triangle.θ represent the angle.By substituting the parameters into the sine trigonometry ratio formula, we have the following;
sin(θ) = Opp/Hyp
sin(22) = y/10
y = 10sin(22)
y = 3.75 inches.
For the adjacent side, we have:
cos(θ) = Adj/Hyp
cos(22) = x/10
x = 10cos(22)
x = 9.27 inches.
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10.85 . ((1.7) =
answers:
1. 18.445
2. 12.55
3. 20.29
4. 1.845
Answer:
18.445
Step-by-step explanation:
Multiply
Find the positive numbers such that the sum of and its reciprocal is as small as possible.Does this problem require optimization over an open interval or a closed interval
Answer:
Yes and closed interval
Step-by-step explanation:
The computation is shown below:
For the sum and the reciprocal as small as the possible equation is as follows
\(\(\frac{d}{dx}\left(x+\frac{1}{x}\right)=0.\)\)
Now take out the derivates,
So,
\(\(1-\frac{1}{x^2}=0,\)\)
or we can say that
\(\(x^2-1=0\rightarrow x=\pm1.\)\)
As the only positive number is to be determined i.e
x = 1
So this problem needed the optimization over a closed interval and the same is to be considered.
A donut shop has fixed costs of $32 per V day, and $2 per muffin sold. This formula can be represented by y = 2x + 32 , where x is the number of muffins sold, and y is the cost per day. Write this relationship in functional notation, as a function C(m) , where C(m) represents the cost for m muffins sold. Select the ordered pair that would represent this function C, given m. (32, (2)) 32 (m, 2m + 32) (2m + 32, m) (c(m), m)
16x−12−24x+4
Explain your reasoning.
Answer:
-8x-8
Step-by-step explanation:
Since 16x and -24x have like variables, we can subtract to get -8x. Then, we can add the constants to get -8.
Step-by-step explanation:
16x-12-24x+4
=16x-24x-12+4
=8x-8
find the distance between the points
A (7, -4) and B (4, -8)
The distance between points A and B is 5 units.
How to find the distance between the points?
Remember that the distance between two points (a, b) and (c, d) is:
distance = √( (a - c)² + (b - d)²)
In this case the two points are A(7, -4) and B (4, -8), replacing these values in the distance equation we get:
distance = √( (7 - 4)² + (-4 + 8)²) = √(9 + 16) = 5
The distance between the two points is 5 units.
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HELP PLEASE I BEG U I DONT WANNA FAIL
Answer:
The second one
Step-by-step explanation:
A function is a group of ordered pairs that do not have the same ordered pair. The second one has 2 fives in the x coordinate, therefore the second one is not a function
In this polygon, all angles are right angles.
What is the area of the polygon? Show your work.
The area of the polygon is solved to be 1044 squared cm
How to find the are of the c]polygonThe area of the composite polygon is solved by dividing the object into two sections. Then adding up the areas
Section 1 has dimensions:
length * width = 46 * 14 = 644
section 2 has dimensions:
length = 46 - 21 = 25
width = 30 - 14 = 16
Area = 25 * 16 = 400
Area of the composite figure
section 1 + section 2
= 644 + 400
= 1044 squared cm
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Use the law of sines to solve for the variable
By means of the law of cosine, the missing side of the triangle has a length of approximately 6.502 units.
How to use the law of cosine in a triangle
Herein we find the case of a triangle with two known side lengths and a known measure of an angle between the two given sides. The measure of the unknown side is determined by the law of cosine, whose definition is shown below:
x² = a² + b² - 2 · a · b · cos θ
If we know that a = 15, b = 12 and θ = 25°, then the equation for the triangle is:
x² = 12² + 15² - 2 · 12 · 15 · cos 25°
Now we proceed to simplify and find the resulting value of x by algebra properties:
x² = 369 - 360 · cos 25°
x² = 369 - 326.271
x² = 42.279
x ≈ 6.502
The length of missing side of the triangle is approximately equal to 6.502 units.
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the figure above shows the graph of the twice-differentiable function g and the line tangent to the graph of g at the point (0,3). the value of limx→0g(x)e−x−3x2−2x is
Using L'Hopital's rule, we can find that the limit is equal to (g(0) - 3)/2.
Since the line tangent to g at (0,3) has slope 2, we know that g(0) - 3 = 2(0) = 0. Therefore, the limit is 0/2 = 0. Based on the given information, we have a twice-differentiable function g(x) and its tangent line at the point (0,3). To find the value of the limit as x approaches 0 for g(x)e^(-x) - 3x^2 - 2x, we can use L'Hopital's rule since it involves indeterminate forms of the type 0/0 or ∞/∞. Apply L'Hopital's rule twice on the given expression. Then, evaluate the resulting expression at x=0. This will give you the value of the limit for the given expression. Make sure to check if the conditions for using L'Hopital's rule are met before applying it.
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9 people buy either an ice block for 60c or
an ice cream for $1.20. The total cost is
$8.40. How many ice blocks were bought?
Answer:
7
Step-by-step explanation:
do 8.40 divided by 1.20 which gives you 7
you can double check by multiplying 1.20 by 7
A population has a current size of 150. If λ is 1. 2, what will the expected population size be after two generations?.
The expected population size be after two generations which has a current size of 150 and λ of 1.2 is 216.
Nt = N₀ × λ^t
Nt = Population size at generation t
N₀ = Current population size
t = Number of generations
λ = Finite rate of increase
λ = 1.2
N₀ = 150
Nt = 150 × 1.2²
Nt = 150 × 1.44
Nt = 216
Population size is defined as the number of individuals present in a designated region. Finite rate of increase is the ratio of population size from increase from one year to the next.
Therefore, the expected population size be after two generations is 216
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In the figure below RS∥XY. Which of the following corresponding proportions is NOT true? Mark all that apply.