Jack walks onto an elevator at floor level 2. The elevator goes up 3 floors, down 8 floors, and back up 11 floors. What floor is Jack on now?

To generate a series of 100 numbers uniformly distributed in the interval [0,1] using a linear congruential generator, we can use the parameters a = 41, c = 33, m = 100, and Z0 = 48.

A linear congruential generator is a simple method for generating pseudo-random numbers. It uses a recurrence relation of the form Zₙ₊₁ = (aZₙ + c) mod m, where Zₙ is the current random number, a is a multiplier, c is an increment, and m is the modulus. In this case, we start with an initial seed value of Z0 = 48 and generate subsequent numbers using the given parameters. To compute the mean and standard deviation of the generated series, we calculate the sample mean and sample standard deviation of the 100 numbers. The sample mean is the average of the numbers, while the sample standard deviation measures the spread or dispersion of the numbers around the mean. We can then compare these computed values with the expected theoretical values for a continuous uniform distribution on the interval [0,1]. The theoretical mean of a continuous uniform distribution is (a + b) / 2, where a and b are the endpoints of the interval. In this case, the mean is (0 + 1) / 2 = 0.5. The theoretical standard deviation of a continuous uniform distribution is (b - a) / sqrt(12), which for the interval [0,1] is 1 / sqrt(12) ≈ 0.2887. Any differences between the computed and theoretical mean and standard deviation may arise due to the nature of pseudo-random number generation. Linear congruential generators are deterministic and have certain limitations in terms of randomness. Deviations from the expected theoretical values can be attributed to the algorithm used and the chosen parameters. If the generated numbers deviate significantly from the expected mean and standard deviation, it may indicate that the linear congruential generator is not adequately simulating a continuous uniform distribution.

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A person who studies or involves in stduy and writes word, logic, or mathematical puzzles is known as an Enigmatologist.

In short form, the use of the term Enigmatologist is a general term for anyone who deals with any puzzle science, such as mathematics. However, the word occultism is a new coin coined nearly 30 years ago by the American Will Shortz, the only trained occultist in the world. Shortz graduated from Indiana University with a degree in riddles in 1974 and is now a columnist for the New York Times after many years as editor of the American magazine Games. Hence, someone who studies and writes mathematical, word or logic puzzles.

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The answers that describe the quadrilateral DEFG area rectangle and parallelogram.

The correct answer choice is option A and B.

A quadrilateral is a parallelogram, which has opposite sides that are congruent and parallel.

Quadrilateral DEFG

if line DE || FG,

line EF // GD,

DF = EG and

diagonals DF and EG are perpendicular,

then, the quadrilateral is a parallelogram

Hence, the quadrilateral DEFG is a rectangle and parallelogram.

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Answer:

-------------------------

Each coordinate of the midpoint is the average of endpoints:

Therefore M is (13, 14).

Answer:

Valid is (32,12) , (6,36) , (20,20)

Invalid is (-4,40) , (36,-8), (15,22.5)

Step-by-step explanation:

I just got it right on edmentrum

Answer:

Valid solutions

(20,20)

(32,12)

(6,36)

Invalid solutions

(-4,40)

(36,-8)

(15,22.5)

Step-by-step explanation:

First, plot each point on the graph to determine whether it lies in the solution set.

All the points lie within the shaded region, so they are all solutions to the inequality.

Now, consider restrictions to the domain and range. Since x is the number of wallets and y is the number of hats, each x- and y-value must be a positive whole number. That leaves only the following points as valid solutions.

(20,20)

(32,12)

(6,36)

Answer:

2.5 feet bud hope it helps

The probability that a student chosen randomly from the class plays both basketball and baseball is 2/13.

What are outcomes?

An outcome is a potential outcome of an experiment or trial in probability theory. Each conceivable result of a specific experiment is distinct, and many results are incompatible (only one outcome will occur on each trial of the experiment).

Given that the total number of students in the class is 26. 6 of them play basketball and 15 of them play baseball. There are 9 students who play neither sport.

The number of students who play at least one sport is (26 - 9) = 17.

Assume that n(A) = 6

n(B) = 15.

n(A∪ B) = 17

n(A∪ B) = n(A) + n(B) - n(A∩B)

17 = 15 + 6 - n(A∩B)

n(A∩B) = 21 - 17

n(A∩B) = 4

Therefore 4 students plays both basketball and baseball.

The number of outcomes of favorable event is 4.

The number of total outcomes is 26.

Probability = The number of favorable outcomes/ Total number of outcomes

The probability is 4/26 = 2/13

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To have a valid 98% confidence interval based on a sample of size n, it is necessary to assume that the population has an approximately normal distribution (option A).

The margin of error in a confidence interval is influenced by the sample size and the confidence level. The margin of error is inversely proportional to the square root of the sample size. This means that increasing the sample size (option A) will result in a smaller margin of error, as the square root of a larger number is larger than that of a smaller number.

On the other hand, the margin of error is directly proportional to the critical value, which is determined by the confidence level. The higher the confidence level, the larger the critical value and consequently, the larger the margin of error. Thus, decreasing the confidence level (option D) will result in a larger margin of error.

Therefore, the options that will result in a larger margin of error are B and D: decreasing the sample size while keeping the same confidence level, and decreasing the confidence level while keeping the same sample size.

It's important to note that the validity of a confidence interval relies on certain assumptions. In this case, to have a valid 98% confidence interval based on a sample of size n, it is necessary to assume that the population has an approximately normal distribution (option A). This assumption is required for the central limit theorem to hold, which allows the sampling distribution of the sample mean to approximate a normal distribution. Options B, C, and D do not accurately describe the assumptions necessary for the validity of the confidence interval.

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To solve this problem, we can use the method of Lagrange multipliers. This method allows us to find the maximum or minimum of a function subject to constraints.

In this case, the function we want to maximize is Z = 2x + 3y and the constraints are x = 24, y = 25, and 3x + 2y = 52.We begin by setting up the Lagrangian function, which is given by:L(x, y, λ) = Z - λ(3x + 2y - 52)where λ is the Lagrange multiplier. We then take the partial derivatives of the Lagrangian with respect to x, y, and λ and set them equal to zero.∂L/∂x = 2 - 3λ = 0∂L/∂y = 3 - 2λ = 0∂L/∂λ = 3x + 2y - 52 = 0Solving for λ, we get λ = 2/3 and λ = 3/2. However, only one of these values satisfies all three equations. Substituting λ = 2/3 into the first two equations gives x = 20 and y = 22. Substituting these values into the third equation confirms that they satisfy all three equations. Therefore, the maximum value of Z subject to the given constraints is Z = 2x + 3y = 2(20) + 3(22) = 84.

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The maximum value of Z = 2x + 3y, subject to the conditions x ≤ 24, y ≤ 25, and 3x + 2y = 52, is 96.

To maximize the function Z = 2x + 3y, subject to the conditions x ≤ 24, y ≤ 25, and 3x + 2y = 52, we will use the method of linear programming.

Let us first graph the equation 3x + 2y = 52.

The intercepts of the equation 3x + 2y = 52 are (0, 26) and (17.33, 0).

Since the feasible region is restricted by x ≤ 24 and y ≤ 25, we get the following graph.

We observe that the feasible region is bounded and consists of four vertices:

A(0, 26), B(8, 20), C(16, 13), and D(24, 0).

Next, we construct a table of values of Z = 2x + 3y for the vertices A, B, C, and D.

We observe that the maximum value of Z is 96, which occurs at the vertex B(8, 20).

Therefore, the maximum value of Z = 2x + 3y, subject to the conditions x ≤ 24, y ≤ 25, and 3x + 2y = 52, is 96.

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To maximize his earnings, John should install 5 Secure alarms and 5 Maximum Secure alarms, and then demonstrate 5 Secure alarms and 2 Maximum Secure alarms.

Let's first consider the time constraints. Since John cannot work more than 40 hours per week, we have the following inequality:

1h(install Secure) x + 2.2h(install Maximum Secure) y + 0.25h(demo Secure) x + 0.4h(demo Maximum Secure) y <= 40

where x and y are the number of Secure and Maximum Secure alarms John installs, respectively.

John is required to work a minimum of 20 hours per week as an installer and a maximum of 20 hours as a demonstrator. So we have the following constraints:

1h(install Secure) x + 2.2h(install Maximum Secure) y >= 20 (minimum hours as installer)

0.25h(demo Secure) x + 0.4h(demo Maximum Secure) y <= 20 (maximum hours as demonstrator)

Now, we can set up the objective function to maximize John's earnings:

E(x,y) = 3(install Secure) x + 3(install Maximum Secure) y + 2(demo Secure) x + 2(demo Maximum Secure) y

= 5x + 5.6y

Using linear programming techniques, we can solve for the optimal values of x and y that maximize the objective function and satisfy the constraints. The optimal values turn out to be x=5 and y=5 for installing alarms, and x=5 and y=2 for demonstrating alarms. Therefore, John should install 5 Secure alarms and 5 Maximum Secure alarms, and then demonstrate 5 Secure alarms and 2 Maximum Secure alarms, to maximize his earnings.

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It is 6 units because if you divide 9 by 3 you get 3 and you multiple that by 2 to make it 6:9 which is equal to 2:3

The homogeneity of variance assumption in the independent measures t-test assumes that option (c) the variances of the two populations from which the samples are drawn are equal.

In mathematical terms, the t-test assumes that the two populations from which the samples are drawn have equal variances. The homogeneity of variance assumption is important because it affects the calculation of the t-statistic.

When the variances of the two populations are equal, the t-test uses a pooled estimate of the variance to calculate the standard error of the difference between the two sample means.

If the homogeneity of variance assumption is violated, meaning the variances of the two populations are not equal, the t-test may produce inaccurate results.

In this case, an alternative test such as Welch's t-test may be used. Welch's t-test does not assume equal variances and is therefore more robust when the homogeneity of variance assumption is violated.

Therefore, the right choice is option (c).

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Answer:

math book

Step-by-step explanation:

Answer:

your question is multiple choice question or just the correct or director answer so you tell your so that I can do in easy way

Answer:

it is 99 pounds

Step-by-step explanation:

they're making it sound false but really is 99 pounds I searched it up

Answer:

$75

Step-by-step explanation:

If their bill is $55 and they leave a $20 tip that's pretty much adding 20 +55

so $20 + $55 dollars is $75.

I hope that helped.

Answer: $75

Step-by-step explanation:

Add the tip to the bill to get the total.

$55 + 20 = $75

Answer:

\( \boxed{Area \: of \: trapezium = 72 \: {cm}^{2}} \)

Step-by-step explanation:

\(Area \: of \: trapezoid = \frac{1}{2} (sum \: of \: parallel \: sides) \times height\)

Parallel sides are = 9 cm and 15 cm

Height = 6 cm

\(Area \: of \: trapezium = \frac{1}{2}(9 + 15) \times 6 \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{1}{2 } \times 24 \times 6 \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 12 \times 6 \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 72 \: {cm}^{2} \)

The probability that the sample average amount of time taken on each day is at most 11 min is 0.5167

To solve for the probability proportion, we make use of the z statistic. The procedure to do is to calculate for the z value and using the standard probability tables, we can look up for the p value. The formula for z score is:

z =(x – μ) / (σ / √n))

where,

x = sample score = 11

μ = sample mean= 10

σ = standard deviation = 4

n = sample size

Calculating for the z and p value when n = 5:

z =(11 – 10) / (2 /√(5))

z = 0.55

Using the tables, p(5) = 0.7088

Calculating for the z and p value when n = 6:

z =(11 – 10) / (4/ √6))

z = 0.61

Using the tables, p(6) = 0.7290

If both days should be occurring, therefore the total probability that each day is at most 11 min is:

p total = p(5) * p(6)

p total = 0.7088 * 0.7290

p total = 0.5167

Hence the average amount of time taken on each day is at most 11 min.

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The quadratic equations are solved and the value of x are 1 and -7 respectively

A quadratic equation is a second-order polynomial equation in a single variable x , ax² + bx + c=0. with a ≠ 0. Because it is a second-order polynomial equation, the fundamental theorem of algebra guarantees that it has at least one solution. The solution may be real or complex.

The roots of the quadratic equations are

x = [ -b ± √ ( b² - 4ac ) ] / ( 2a )

where ( b² - 4ac ) is the discriminant

when ( b² - 4ac ) is positive, we get two real solutions

when discriminant is zero we get just one real solution (both answers are the same)

when discriminant is negative we get a pair of complex solutions

Given data ,

Let the quadratic equation be represented as A

Now , the value of A is

a)

x² + 6x = 7

Adding 9 on both sides of the equation , we get

x² + 6x + 9 = 16

On simplifying the equation , we get

( x + 3 )² = ( 4 )²

Taking square roots on both sides , we get

x + 3 = ±4

Subtracting 3 on both sides , we get

x = 1 and x = -7

Therefore , the value of x are 1 and -7 respectively

Hence , the quadratic equations is solved

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Answer:

Given:  P(A ∩ B) = 0, P(B) = 0.9, P(A ∪ B) = 0.9.

We have: P(A ∪ B) = P(A) + P(B) - P(A ∩ B)

=>  0.9 = P(A) + 0.9 - 0

=> P(A) = 0.9 - 0.9 = 0

Hope this helps!

:)

Answer:

(1/21)(21×5^(x+2)-4×5^2x)

Step-by-step explanation:

5^(x+2)-4×5^x÷21×5^x

= 5^(x+2)-4×5^2x/21

= 1/21(21×5^(x+2)-4×5^2x)

Answer:

2396

Step-by-step explanation:

2675-279=2396

The cost of 1 ft² grass sod is $3 and the cost of 1 geranium is $10.

This is found using simultaneous equations.

What are simultaneous equations?

A finite set of equations for which common solutions are sought is referred to as a set of simultaneous equations, often known as a system of equations.

Let,

    x = Cost of 1 ft² grass sod

   y = Cost of 1 geranium

In Shayna's case

Grass sod = 2ft²

Geranium bought = 1

Cost = $16

Equation

2x + y = 16 ⇒ (1)

In Arjun's case

Grass sod = 1 ft²

Geranium = 7

Cost = $73

Equation

x + 7y = 73 ⇒ (2)

Solving the equation (1) and (2)

From (1)

y = 16 - 2x

Substituting the above in (2)

x + 7 (16-2x) = 73

-13x = -39

  x = 3  

   y = 16 - 2*3 = 10

Therefore from the solution of the above simultaneous equations, we can conclude that the cost of 1 ft² grass sod is $3 and the cost of 1 geranium is $10.

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9514 1404 393

Answer:

  (1, 7)

Step-by-step explanation:

Fill in x=1 and do the arithmetic.

  h(1) = 4(1) +3 = 7

The coordinate pair is ...

  (x, h(x)) = (1, h(1)) = (1, 7)