Jan's flower garden has only daffodils and tulips
in it. There are 15 daffodils and 12 tulips. What
is the ratio of the number of tulips to the total
number of flowers in Jan's garden?
A.5:4
B. 5:9
C. 4:5
D. 4:9

Answer:

The slope of given equation in standard form

                \(m = \frac{-7}{9}\)

Step-by-step explanation:

Explanation:-

Given equation of the line 7x + 9y = 14

The given equation in slope-intercept form, y = mx + b

Slope - intercept form   \(y = \frac{-7}{9} x + \frac{14}{9}\)

Comparing  m = - 7/9

Here m = -7/9

        C = 14/9

The slope of given equation in standard form

                \(m = \frac{-7}{9}\)

Answer: It is b

Step-by-step explanation: It is b ( 2:5 ) because it is asking the odds of spinning red or green and there are 5 colors in total so 1 green and 1 red makes 2 colors so it is 2:5

The value of a + b + c based on the product formula is 8.

From the information given, the product of the proper divisor is illustrated.

Based on the information, the addition of the symbols will be:

= a + b + c

= 3 + 3 + 2

= 8

In conclusion, the correct option is 8.

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The final equation for the tangent plane to the graph of f at the point (a, b) is z = 2e^a(x - a) - y + 2e^a - 2b. This equation represents the plane that is tangent to the graph of f at the specified point (a, b).

To find the equation for the tangent plane to the graph of the function f(x, y) = 2e^x - y at a given point (x0, y0), we need to calculate the partial derivatives of f with respect to x and y at that point.

The partial derivative of f with respect to x, denoted as ∂f/∂x or fₓ, represents the rate of change of f with respect to x while keeping y constant. Similarly, the partial derivative of f with respect to y, denoted as ∂f/∂y or fᵧ, represents the rate of change of f with respect to y while keeping x constant.

Let's calculate these partial derivatives:

fₓ = d/dx(2e^x - y) = 2e^x

fᵧ = d/dy(2e^x - y) = -1

Now, we have the partial derivatives evaluated at the point (x0, y0). Let's assume our point of interest is (a, b), where a = x0 and b = y0.

At the point (a, b), the equation for the tangent plane is given by:

z - f(a, b) = fₓ(a, b)(x - a) + fᵧ(a, b)(y - b)

Substituting fₓ(a, b) = 2e^a and fᵧ(a, b) = -1, we have:

z - f(a, b) = 2e^a(x - a) - (y - b)

Now, let's substitute f(a, b) = 2e^a - b:

z - (2e^a - b) = 2e^a(x - a) - (y - b)

Rearranging and simplifying:

z = 2e^a(x - a) - (y - b) + 2e^a - b

The final equation for the tangent plane to the graph of f at the point (a, b) is z = 2e^a(x - a) - y + 2e^a - 2b.

This equation represents the plane that is tangent to the graph of f at the specified point (a, b).

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Answer:

\( \boxed{ \bold{ \huge{ \boxed{ \sf{73.5 \: {cm}^{2} }}}}}\)

Step-by-step explanation:

Base of the parallelogram = 10.5 cm

Height of the parallelogram = 7 cm

Finding the area of the parallelogram

\( \boxed{ \sf{area \: of \: a \: parallelogram = base \times height}}\)

\( \longrightarrow{ \sf{10.5 \times 7}}\)

\( \longrightarrow{ \sf{73.5 \: {cm}^{2}}} \)

Hope I helped!

Best regards! :D

a) To find P(500), we substitute x = 500 into the function P(x):

P(500) = 0.75 - 96 = -95.25

Therefore, the profit the vendor makes from selling 500 pretzels is -95.25.

b) To write the equation for the line in point-slope form with a slope of 3 and passing through the point (-7, 8), we can use the point-slope form equation:

y - y1 = m(x - x1)

Substituting the values, we have:

y - 8 = 3(x - (-7))

y - 8 = 3(x + 7)

y - 8 = 3x + 21

y = 3x + 29

Therefore, the equation for the line is y = 3x + 29.

c) To determine whether the relation is a function, we need to check if each x-value in the relation corresponds to a unique y-value. Looking at the given points, we can see that for x = -5, there are two different y-values (4 and -4). Since the x-value -5 is associated with multiple y-values, the relation is not a function.

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The equation of the normal to the curve is

( Y - \(e^{-3}\) - 1/\(e^{-3}\) ) / ( X - \(e^{-3}\) ) = 1/3

An equation contains one or more than two terms connected by an equal sign.

Example:

2x + 4y = 88 is an equation.

We have,

Equation of the curve:

y(x) = x + 1/x ______(1)

And,

y = -3x is parallel to the tangent.

This means,

y = -3x is in the form of y = mx + c

So,

Slope = m = dy/dx

m = -3 ______(2)

Now,

y = x + 1/x

dy/dx = 1 + logx

-3 = 1 + logx

-3 - 1 = logx

-3 = logx

\(e^{-3}\) = \(e^{logx}\)

x = \(e^{-3}\) ______(3)

Now,

The equation of the normal.

( Y - y(x) ) / (X - x) = -1/(dy/dx)

So,

From (1), (2), and (3)

( Y - y(\(e^{-3}\)) ) / (X - \(e^{-3}\)) = -1/-3

( Y - (\(e^{-3}\) + 1/\(e^{-3}\)) / ( X - \(e^{-3}\) ) = 1/3

( Y - \(e^{-3}\) - 1/\(e^{-3}\) ) / ( X - \(e^{-3}\) ) = 1/3

Thus,

The equation of the normal to the curve is

( Y - \(e^{-3}\) - 1/\(e^{-3}\) ) / ( X - \(e^{-3}\) ) = 1/3

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Answer:

2 only

Step-by-step explanation:

the slope is 2 in function 1 and function 2 is the only other slope that is 2 as well

First we need to find f(2), this is when x=2 on the funciton F

from the table we can notice when x=2 f is 3

now, we need to find g(3), it is when x is 3 on the funcion G

from the table we can notice wen x=3 G is -2

so

The area of the part of the plane 2x+y+2z=4 in the first octant is S= \(\int_{0}^{2}\int_{0}^{-2x+4}\frac{3}{2}dydx\).

In the given question we have to check which of the following integrals represents the area of the part of the plane in the first octant.

The given plane is 2x+y+2z=4 that lies in the first octant.

In the first octant the all variables are positive.

First we need to find the equation of hypotenuse in the linethat intersects xy plane means z=0. So:

2x+y=4

y=4-2x

Now find the surface area. We need the function in the form of z=f(x,y). So:

2x+y+2z=4

2z=4-2x-y

z=(4-2x-y)/2

On taking the partial derivative we get

f(x) = -1 and f(y) = -1/2

Now the defining the limits will be;

0≤x≤2 and 0≤y≤ (-2x+4)

So the area will be;

S= \(\int \int _{D}\sqrt{f(x)^{2}+f(y)^{2}+1}dydx\)

S= \(\int_{0}^{2}\int_{0}^{-2x+4}\sqrt{(-1)^{2}+(-1/2)^{2}+1}dydx\)

S= \(\int_{0}^{2}\int_{0}^{-2x+4}\sqrt{1+1/4+1}dydx\)

S= \(\int_{0}^{2}\int_{0}^{-2x+4}\sqrt{(4+1+4)/4}dydx\)

S= \(\int_{0}^{2}\int_{0}^{-2x+4}\sqrt{9/4}dydx\)

S= \(\int_{0}^{2}\int_{0}^{-2x+4}\frac{3}{2}dydx\)

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Answer:

i think the cost of each bag is $2.61

Step-by-step explanation:

suppose the cost of each bag is $x

7.83 = 3x

7.83/3 = x

2.61 = x

so the cost of each bag is $2.61

Answer: 50 to 140

Step-by-step explanation:

Answer:

range = 90

Step-by-step explanation:

the range is the difference between the maximum and minimum values of the data set.

the maximum value = 140 and minimum value = 50 , then

range = 140 - 50 = 90

Answer: 13 feet

Step-by-step explanation:

Answer:

they're at 7 feet below sea level

Step-by-step explanation:

it starts at -30 sea level then goes to -15 sea level and they dive again to end up at -20 sea level but they rise 13 so they end up at -7

Answer:

B

Step-by-step explanation:

Hope this helps :D

The total contribution to GDP from the transactions described in the scenario can be calculated by summing the value of final goods and services produced. The total value of investment expenditure can be determined by considering the value of unsold computers that are held in inventory by the manufacturers.

To calculate the total contribution to GDP, we need to consider the value of final goods and services produced, which includes the value of the computers sold to consumers, businesses, the government, and abroad. The value of 200,000 computers sold to consumers is 200,000 × $2,000 = $400,000,000. Similarly, the value of computers sold to businesses, the government, and abroad can be calculated as 300,000 × $2,000 = $600,000,000, 300,000 × $2,000 = $600,000,000, and 100,000 × $2,000 = $200,000,000, respectively. Therefore, the total contribution to GDP from these transactions is $400,000,000 + $600,000,000 + $600,000,000 + $200,000,000 = $1,800,000,000.

The total value of investment expenditure can be determined by considering the value of unsold computers held in inventory by the manufacturers. In this case, the value of unsold computers is 1,000,000 * $2,000 = $2,000,000,000. Therefore, the total value of investment expenditure is $2,000,000,000.

It's important to note that GDP is a measure of the value of all final goods and services produced within an economy over a specific period. Investment expenditure, on the other hand, represents the value of capital goods, such as machinery and equipment, that are purchased by businesses to increase their productive capacity.

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The slope of the line is 10/3 or 3.33. Plot the line by clicking twice for each segment. To delete a segment, click on it.

The slope of the line, represented by the "rise" and "run," can be calculated as follows:

1. Start by drawing a line.

2. Label one end of the line as point A and the other end as point B.

3. Measure the vertical distance between point A and point B. This distance is the "rise."

4. Measure the horizontal distance between point A and point B. This distance is the "run."

5. Write down the value of the rise, which is 10 in this case.

6. Write down the value of the run, which is 3 in this case.

7. To find the slope, divide the rise by the run. In this case, 10 divided by 3 equals 3.33.

8. Simplify the slope to the simplest form. Since 3.33 cannot be simplified further, the slope remains as 3.33.

9. The slope of the line, in simplest form, is 3.33.

To plot the line:

1. Click twice on the graph to plot the segment representing the rise of 10.

2. Click twice on the graph to plot the segment representing the run of 3.

3. The line connecting the two points represents the slope of the line.

To delete a segment:

1. Click on the segment you want to delete.

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Answer:

1/2

Step-by-step explanation:

I got the answer right on the test

The y int appears to be 3,

and the slope appears to be -3/5

so the equation can be y=-3/5x+3

Answer:  25%

Step-by-step explanation:

1/4 make the denominator 100

100/4 =25

times 25 by 1/4 = 25/100

Answer = 25%

Answer:

1. Cosine

2. x = 49°

3. Sine

4. y = 41°

Step-by-step explanation:

1. The trig function that will be used to solve for x is cosine.

2. Determination of angle x

x° =..?

Adjacent = 13

Hypothenus = 20

Cos x = Adjacent /Hypothenus

Cos x = 13/20

Take the inverse of Cos

x = Cos¯¹ (13/20)

x = 49°

3. The trig function that will be used to solve for y is sine.

4. Determination of angle y.

y° =..?

Opposite = 13

Hypothenus = 20

Sine y = Opposite /Hypothenus

Sine y = 13/20

Take the inverse of Sine

y = Sine¯¹ (13/20)

y = 41°

Total pay be the at the end of the two weeks with rate of  $13.25 per hour and commission of $150 for selling each new car is $1319.75.

As given,

Rate of salesperson per hour pay = $13.25

Commission on selling each new car =$150

Amount of the pay earned by salesperson:

First week :

25 (13.25) + 3 (150)

= 331.25 + 450

= $781.25

Second week:

18 (13.25) + 2(150)

= 238.5 +300

= $538.50

Total pay of salesperson at the end of two weeks

=$(781.25 +538.5)

=$1319.75

Therefore, total pay be the at the end of the two weeks with rate of  $13.25 per hour and commission of $150 for selling each new car is  $1319.75.

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Answer:

Circumference of circle = πd = π × 16 =16 π in.

or

circumference of circle = 2πr = 2×π×8= 16 π in.

Yes, an object can have zero velocity and immobile be accelerating together. While participating the object, you will find that the object will continue to move ahead for some time and then stops instantly.

Then the object will start to move in the reverse direction.

at all the velocity is constant, the acceleration is zero. For example, a car traveling at a constant 80 km/h in a straight line has nonzero velocity and zero acceleration.

If acceleration is 0, the velocity is not converted. If the velocity is constant (0 acceleration) then the object will continue needing slowing down or speeding up.

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(a) The mean of Z in case (a) is -60 and the variance is 400.

(b) The mean of Z in case (b) is 280 and the variance is 3600.

(c) The mean of Z in case (c) is 60 and the variance is 65.

(d) The mean of Z in case (d) is -20 and the variance is 65.

(e) The mean of Z in case (e) is 80 and the variance is 505.

To find the mean and variance of the random variable Z for each case, we can use the properties of means and variances.

(a) Z = 40 - 5X

Mean of Z:

E(Z) = E(40 - 5X) = 40 - 5E(X) = 40 - 5 * 20 = 40 - 100 = -60

Variance of Z:

Var(Z) = Var(40 - 5X) = Var(-5X) = (-5)² * Var(X) = 25 * Var(X) = 25 * (4)² = 25 * 16 = 400

Therefore, the mean of Z in case (a) is -60 and the variance is 400.

(b) Z = 15X - 20

Mean of Z:

E(Z) = E(15X - 20) = 15E(X) - 20 = 15 * 20 - 20 = 300 - 20 = 280

Variance of Z:

Var(Z) = Var(15X - 20) = Var(15X) = (15)² * Var(X) = 225 * Var(X) = 225 * (4)² = 225 * 16 = 3600

Therefore, the mean of Z in case (b) is 280 and the variance is 3600.

(c) Z = X + Y

Mean of Z:

E(Z) = E(X + Y) = E(X) + E(Y) = 20 + 40 = 60

Variance of Z:

Var(Z) = Var(X + Y) = Var(X) + Var(Y) = (4)² + (7)² = 16 + 49 = 65

Therefore, the mean of Z in case (c) is 60 and the variance is 65.

(d) Z = X - Y

Mean of Z:

E(Z) = E(X - Y) = E(X) - E(Y) = 20 - 40 = -20

Variance of Z:

Var(Z) = Var(X - Y) = Var(X) + Var(Y) = (4)² + (7)² = 16 + 49 = 65

Therefore, the mean of Z in case (d) is -20 and the variance is 65.

(e) Z = -2X + 3Y

Mean of Z:

E(Z) = E(-2X + 3Y) = -2E(X) + 3E(Y) = -2 * 20 + 3 * 40 = -40 + 120 = 80

Variance of Z:

Var(Z) = Var(-2X + 3Y) = (-2)² * Var(X) + (3)² * Var(Y) = 4 * 16 + 9 * 49 = 64 + 441 = 505

Therefore, the mean of Z in case (e) is 80 and the variance is 505.

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The number of calories that Darrell will burn in 1 minute while kayaking is given as follows:

4 calories.

The number of calories that Darrell will burn in 1 minute while kayaking is obtained applying the proportions in the context of the problem.

For each input-output pair in the table, the constant of proportionality is of 4, hence the number of calories that Darrell will burn in 1 minute while kayaking is given as follows:

4 calories.

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In the expression 2x + 5 at x = 3 Brett is wrong as the correct answer is 11.

An expression is written in the form of numbers and variables with arithmetic operations.

According to the given question we have to evaluate 2x + 5 at x = 3 and match our answer with Brett which is 41.

To obtain the value of 2x + 5 at x = 3, we have to substitute x with 3 in the given expression which is,

= 2(3) + 5

= 6 + 5.

= 11.

So, our answer is correct which is 11 and Brett is wrong.

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The point on the graph where the tangent plane is parallel is (52, 52, -5382).

What is the tangent plane?

The surface that contains all tangent lines of the curve at a point, $P$, that lies on the surface and passes through the point is represented by the tangent plane. We discovered earlier in our talks of derivatives and tangent lines that we can use tangent lines to mimic the behavior of a graph. We may employ tangent planes for a similar reason now that we're working with multivariable functions and three-dimensional coordinate systems.

Here, we have

Given: Let P be the tangent plane to the graph of g(x, y) = 26 – 13x² – 26y² at the point (4, 2, –286). Let f(x, y) = 26 – x² - y².

We have to find the point on the graph where the tangent plane is parallel.

Let P be the tangent plane to the graph z = g(x, y) = 26 – 13x² – 26y² at the point (4, 2, –286).

φ(x,y,z) = 13x² + 26y² + z - 26

Δφ = 26xi + 52yj + k

Δφ(4, 2, –286) = 104i + 104j + k

Then,

P: 104(x-4) + 104(y-2)+1(z+286) = 0

104x + 104y + z = 338...(1)

Now, Let

ψ(x,y,z) =  x² + y² + z - 26

Δψ = 2xi + 2yj + k

Let (x₀,y₀,z₀) be the point of the graph z = f(x,y) = 26 – x² - y² where the tangent plane in the plane is parallel to equation (1).

Δψ (x₀,y₀,z₀)  =  (2x₀,2y₀,1)

= 2x₀/104 = 2y₀/104 = 1/1

x₀ = 52 = y₀

Now, z₀ = 26 – x₀² - y₀² = 26 – 52² - 52²= -5382

Hence,  the point on the graph where the tangent plane is parallel is (52, 52, -5382).

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The required measure of the sine of angle ∠ MQP for Right triangle MNR is evaluated as 0.83.

As given in the question, the Right triangle MNR is represented with the right angle at vertex M. Angle R measures 34 degrees, and angle N measures 56 degrees.
We have to determine sin ∠MQP.

The angle can be defined as the one line inclined over another line.

Here,
For right-angle triangle MNR,
To calculate the sin of the angle in the right angle triangle we need hypotenuse and perpendicular.
But in the question value of angle ∠MQP is given, So directly,
sin 56 = 0.83.

Thus, the required value of the sine of angle  ∠MQP is 0.83.

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Answer:

hlpp

Step-by-step explanation: