The first term of a geometric sequence is 5 and the multiplier, or ratio, is –2. What is the sum of the first 5 terms of the sequence?
Step-by-step explanation:
s1 = 5
s2 = s1 × -2 = 5×-2 = -10
s3 = s2 × -2 = -10 × -2 = 20
...
now, we could do all that manually.
but there is also a formula for geometric sequence.
in fact, there are 2 - one for finite and one for infinite sequences.
and I was not completely honest, each of these 2 had some sub-forms depending on the size of the multiplier or ratio.
since we need the sum of the first 5 terms, which of the 2 do you think we need ?
of course, finite, because 5 is a normal number we can "touch". it is not infinity.
so, the formulas for finite sums of geometric sequences are :
if |r| < 1, Sn = a(1 - r^n)/(1 - r)
if |r| > 1, Sn = a(r^n - 1)/(r - 1)
if r = 1, Sn = na
if r = -1, then Sn = a or 0 depending on if n is odd or even.
the sequence is in general
s1 = a
sn = sn-1 × r
in our case a = 5, r = -2.
so, what form of the formula do we need ?
|-2| = 2, and 2 > 1, so ...
S5 = 5(-2^5 ‐ 1)/(-2 - 1) = 5(-32 - 1)/-3 = 5×-33/-3 =
= 5 × 11 = 55
quick check, as the 5 terms are
5
-10
20
-40
80
and their sum is : 55
correct !
solve using Substitution y = 6x - 11 -2x - 3y = -7
Answer:
(2, 1)
Step-by-step explanation:
To solve by substitution, we solve one equation for one of its variables and then substitute the solved value for that variable into the other equation. Because this system of equations already has one solved for the variable, this makes our job much easier. We only need to implement the solved value for y into the other equation and solve for x.
y = 6x - 11
-2x - 3(6x - 11) = -7 Distribute.
-2x - 18x + 33 = -7 Combine like terms.
-20x + 33 = -7 Subtract 33 from both sides of the equation.
-20x = -40 Divide by -20 on both sides of the equation.
x = 2
Then, with this value, we will place it into the equation that was already solved for y in order to get a definite value for y.
y = 6(2) - 11
y = 12 - 11
y = 1
Using this information, the coordinate pair for this equation (the point of intersection between the two lines) is (2, 1).
The spinner below shows 5 equally sized slices. Mal spun the dial 1000 times and got the following results.
Outcome White Grey Black
Number of Spins 389 406 205
Fill in the table below. Round your answers to the nearest thousandth.
The experimental probability that the next spin falls in a black region is given as follows:
0.205 = 20.5%.
How to calculate a probability?A probability is calculated as the division of the desired number of outcomes by the total number of outcomes in the context of a problem/experiment.
205 out of the previous 1000 trials fell in the black region, hence the experimental probability is given as follows:
p = 205/1000
p = 0.205.
p = 20.5%.
Missing InformationThe problem asks for the experimental probability that the next spin falls in a black region.
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Please if you know the answer tell me it and the steps also thank you.
Step-by-step explanation: Well to begin, you take 15$ and multiply it by 4, since he wants to buy 4 of those tickets, which is 60$. Then, take the 10$ and multiply it by 2 since he wants 2 of those tickets, which is 20$, you then apply 10% to 60 and 20 by taking 10 percent of 60, then adding it to 60 once have that, which is 66, you take the 3% and find 3% of 66, then add the answer of that to 66, which is 67.98$, you then do the same thing to the 20$.
Sorry if this didnt help, im sure it didnt because im a very bad explainer, but i tried..
If cose < 0 and cote > 0, then the terminal point determined by e is in:
A. quadrant 4.
B. quadrant 1.
C. quadrant 3.
D. quadrant 2.
If cos < 0 and cot > 0, then the terminal point is determined by
C. quadrant 3.
What are reference angles according to quadrats?We have I, II, III, IV quadrants.In quadrant I the referece angle Ф is Ф.
In quadrant II the referece angle Ф is (π - Ф).
In quadrant III the referece angle Ф is (π + Ф).
In quadrant IV the referece angle Ф is (2π - Ф).
We know, cos is -ve on III and IV quadrants, and cot = 1/tan is +ve on I and III quadrant.
Therefore, The combined condition cos < 0 and cot > 0 satisfies on the II quadrant.
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A club swimming pool is 34 ft wide and 48 ft long. The club members want an exposed aggregate border in a strip of uniform width around the pool. They have enough material for 344 ft2. How wide can the strip be?
Answer:
29
he area of the pool is 34 ft * 48 ft = <<34*48=1632>>1632 ft2.
Thus, the total area of the pool and the border strip is 1632 ft2 + 344 ft2 = <<1632+344=1976>>1976 ft2.
Hence, the border strip is 1976 ft2/34 ft = <<1976/34=58>>58 ft long.
Therefore, the border strip can be 58 ft/2 = <<58/2=29>>29 ft wide. Answer: {29}.
For each value of u determine whether it is a solution to -2u-6<-20
Answer:
u > 7
Step-by-step explanation:
-2u -6 < -20 Add 6 to both sides
-2u - 6 + 6 < -20 + 6
-2u < -14 Divide both sides by -2. When you multiply or divide both sides by a negative number, you must flig the sign.
\(\frac{-2u}{-2}\) > \(\frac{-14}{-2}\)
u > 7
Helping in the name of Jesus.
The answer is:
u > 7
In-depth explanation:
You haven't told me what the values of u are, but I'll solve the equation for u.
Add 6 on each side:
\(\bf{-2u-6 < -20}\)
\(\bf{-2u < -14}\)
Divide each side by -1 and reverse the sign:
\(\bf{2u > 14}\)
Now divide each side by 2
\(\bf{u > 7}\)
5. Find the time in which the loan of N3,900 at the rate of 5% yields N585=
6 What time will the simple interest N70,000 at the rate of 7% be used
for a loan of N20,000.00=
7.If N300.00 amount to N390 at the rate of 3%. Find the time.=
8.The simple interest on N5600.00 in 1 year is N80.00, find the rate percent per annum=
9.What year will N5100 yield an interest of N170.00 at the rate of 2 1/2 per annum=
10.What rate per annum will N4,600 yield an interest of N230.00 for 2 years=
11. What time will N8100 yield an interest of N729 at the rate of 9% per annum=
12.Report from the bank says the interest on N2300 is N23.00 for 2 years find the rate of interest per annum.=
Answer:
5. To find the time in which the loan of N3,900 at the rate of 5% yields N585, we can use the formula for simple interest:
I = P * r * t
where I is the interest, P is the principal (the amount borrowed), r is the interest rate (as a decimal), and t is the time (in years).
Plugging in the given values, we get:
585 = 3900 * 0.05 * t
Solving for t, we get:
t = 3 years
Therefore, it will take 3 years for the loan to yield N585 in interest.
6. To find the time it will take for the simple interest on N70,000 at the rate of 7% to be N20,000, we can again use the formula for simple interest:
I = P * r * t
Plugging in the given values, we get:
20000 = 70000 * 0.07 * t
Solving for t, we get:
t = 4 years
Therefore, it will take 4 years for the simple interest on N70,000 at the rate of 7% to be N20,000.
7. To find the time it takes for N300 to amount to N390 at the rate of 3%, we can use the formula for compound interest:
A = P * (1 + r/n)^(n*t)
where A is the final amount, P is the principal (the initial amount), r is the interest rate (as a decimal), n is the number of times the interest is compounded per year, and t is the time (in years).
Plugging in the given values, we get:
390 = 300 * (1 + 0.03/1)^(1*t)
Simplifying, we get:
1.3^t = 1.3
Taking the logarithm of both sides, we get:
t = log(1.3) / log(1.3)
t ≈ 1.82
Therefore, it takes approximately 1.82 years for N300 to amount to N390 at the rate of 3%.
8. To find the rate percent per annum for a simple interest of N80 on N5600 in 1 year, we can use the formula for simple interest:
I = P * r * t
Plugging in the given values, we get:
80 = 5600 * r * 1
Solving for r, we get:
r = 0.0143 or 1.43%
Therefore, the rate percent per annum is 1.43%.
9. To find the year in which N5100 will yield an interest of N170 at the rate of 2 1/2 per annum, we can use the formula for simple interest:
I = P * r * t
Plugging in the given values, we get:
170 = 5100 * 0.025 * t
Solving for t, we get:
t = 2/3 years
Since the question asks for the year, we need to add 2/3 years to the current year. Assuming the current year is 2021, we get:
2021 + 2/3 ≈ 2022.67
Therefore, N5100 will yield an interest of N170 at the rate of 2 1/2 per annum in the year 2022.
10. To find the rate per annum at which N4,600 will yield an interest of N230 for 2 years, we can again use the formula for simple interest:
I = P * r * t
Plugging in the given values, we get:
230 = 4600 * r * 2
Solving for r, we get:
r = 0.025 or 2.5%
Therefore, the rate per annum is 2.5%.
11. To find the time it takes for N8100 to yield an interest of N729 at the rate of 9% per annum, we can use the formula for simple interest:
I = P * r * t
Plugging in the given values, we get:
729 = 8100 * 0.09 * t
Solving for t, we get:
t = 1 year
Therefore, it takes 1 year for N8100 to yield an interest of N729 at the rate of 9% per annum.
12. To find the rate of interest per annum for an interest of N23 on N2300 for 2 years, we can use the formula for simple interest:
I = P * r * t
Plugging in the given values, we get:
23 = 2300 * r * 2
Solving for r, we get:
r = 0.005 or 0.5%
Therefore, the rate of interest per annum is 0.5%.
What are the coordinates of the point on the directed line segment from ( − 7 , 9 ) (−7,9) to ( 3 , − 1 ) (3,−1) that partitions the segment into a ratio of 2 to 3?
The coordinates of the point on the directed line segment from (-7, 9) to (3, -1) that partitions the segment into a ratio of 2 to 3 are (-3, 5).
To find the coordinates of the point that divides the directed line segment from (-7, 9) to (3, -1) into a ratio of 2 to 3, we can use the section formula.
Let's label the coordinates of the desired point as (x, y). According to the section formula, the x-coordinate of the point is given by:
x = (2 * 3 + 3 * (-7)) / (2 + 3) = (6 - 21) / 5 = -15 / 5 = -3
Similarly, the y-coordinate of the point is given by:
y = (2 * (-1) + 3 * 9) / (2 + 3) = (-2 + 27) / 5 = 25 / 5 = 5
Therefore, the coordinates of the point that divides the line segment in a ratio of 2 to 3 are (-3, 5).
To understand this conceptually, consider the line segment as a distance from the starting point (-7, 9) to the ending point (3, -1). The ratio of 2 to 3 means that the desired point is two-thirds of the way from the starting point and one-third of the way from the ending point. By calculating the x and y coordinates using the section formula, we find that the desired point is located at (-3, 5).
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A box contains more than 25 but fewer than 40 tennis balls. When the balls are counted by threes there is one left over. When counted by fives there are two left over. How many balls are in the box?
Using the given restrictions we can see that there are 37 balls on the box.
How many balls are in the box?Let's assume that the total number of balls is B.
We know that in the box there are more than 25 and fewer than 40 tennis balls, so we have the inequality.
25 < B < 40
If we count in 3's, then there is one left over, so we can write:
B = 3*n + 1 (where n is an integer number)
And if we count in 5's there are 2 leftovers:
B = 5*m + 2 (where m is an integer, from this we conclude that the number ends in a 2 or a 7)
Then we have 3 restrictions:
25 < B < 40
B = 3*n + 1
B = 5*m + 2
notice that if n = 12
B = 3*12 + 1 = 37
if m = 7
B = 5*7 + 2 = 37
and 37 is a solution of the inequality, then we conclude that there are 37 balls on the box.
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Express as a difference: a+5
The expression expressed as a difference is (a - 2) - (-7).
We have,
We can express a + 5 as a difference by subtracting a suitable term from it.
One way to do this is to subtract 2 and add 2, like this:
a + 5 = a + 5 - 2 + 2 (adding and subtracting 2)
= (a - 2) + 7 (rearranging)
Now,
We can express a + 5 as the difference between a - 2 and -7, like this:
a + 5 = (a - 2) - (-7)
Thus,
The expression expressed as a difference is (a - 2) - (-7).
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10 households use 613 1/5 l of water in 3 days. If each household uses up the same amount of water each day find how much water would be used by 3 households
Answer:
So, 3 households would use 20 4/5 x 3 = 62 1/5 L of water per day.
Step-by-step explanation:
Each household uses 613 1/5 ÷ 10 = 61 3/5 L of water in 3 days.
Therefore, each household uses an average of 61 3/5 ÷ 3 = 20 4/5 L of water per day.
Find the equation of the line.
Use exact numbers.
Answer:
Step-by-step explanation:
need help with geometry
To find the height of the cylinder when the volume is given as 1500 in³ and the radius is 7 inches, we can use the formula for the volume of a cylinder:
Volume = π * r² * h
Substituting the given values, we have:
\(1500 = 3.14 * 7^2 * h1500 = 3.14 * 49 * h1500 = 153.86 * h\)
To solve for h, we divide both sides of the equation by 153.86:
h = 1500 / 153.86
h ≈ 9.75
Rounding the answer to the nearest hundredth, the height of the cylinder is approximately 9.75 inches.
Therefore, the height of the cylinder is 9.75 inches.
Note: It is important to use the accurate value of π, which is approximately 3.14159, for precise calculations. However, in this case, since you specified to use 3.14 for π, I have used that approximation to calculate the height.
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Find the midpoint of the line segment with the given endpoints (-2,-6) and (8,8)
Answer: (3,1)
Step-by-step explanation: Use the midpoint formula
how many like terms are in the expression 4j^2 +3j^2-9j^2
Answer: 16j^3+2
Step-by-step explanation:
he button provides an automatic means of checking for mathematical errors within formulas of a worksheet.
The Error checking button provides an automatic means of checking for mathematical errors within formulas of a worksheet.
The modeling process begins with the framing of a conceptual model that shows the relationships between the various parts of the problem being modeled.
Arrows pointing from the selected cell to cells that depend on the selected cell are generated by using the Trace dependents button of the Formula Auditing group.
nodes in an influence diagram represent part of the model
The Trace Precedents button, located in the Formula Auditing group, creates arrows pointing to the selected cell from cells that are part of the formula in that cell
The Error checking button provides an automatic means of checking for mathematical errors within formulas of a worksheet.
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I feel like the answers obvious but apparently from other peoples answers its not 11 lol.
Answer:
11
Step-by-step explanation:
What is the Area of this Shape?
Answer:
38.5
Step-by-step explanation:
rectangle = (2.5x2)+1.5=6.5
6.5x5=32.5
both triangle = 4/2 = 2
(1.5x2)x2=6
total area = 32.5 + 6 = 38.5
The business college computing center wants to determine the proportion of business students who have personal computers (PC's) at home. If the proportion differs from 30%, then the lab will modify a proposed enlargement of its facilities. Suppose a hypothesis test is conducted and the test statistic is 2.5. Find the P-value for a two-tailed test of hypothesis.
The probability of observing such an extreme result by chance alone is 0.0124.
To find the P-value for a two-tailed test of hypothesis, we need to first determine the significance level (alpha) of the test. Let's assume a significance level of 0.05, which is a common choice.
Since this is a two-tailed test, we need to find the probability of observing a test statistic as extreme or more extreme than 2.5 in either direction. We can find this probability using a standard normal distribution table or a calculator.
Using a standard normal distribution table, we can find that the probability of observing a z-score of 2.5 or greater is 0.0062. The probability of observing a z-score of -2.5 or smaller is also 0.0062. Therefore, the P-value for the two-tailed test of hypothesis is:
P-value = 2 * 0.0062
P-value = 0.0124
This means that if the true proportion of business students who have personal computers at home differs from 30%, with a significance level of 0.05, and we obtain a test statistic of 2.5, then the probability of observing such an extreme result by chance alone is 0.0124.
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Solve the system of inequalities by graphing.
y ≥ 2
y < 4
Select a line to change it between solid and dotted. Select a region to shade it.
The area between the solid line (y=x+4) and the dotted line (y=-2x-2) represents the system of inequalities solution set.
Two linear inequalities system on a coordinate plane. The first has a solid line graphed with a negative slope of one, a negative y-intercept, and a shaded origin area. The area encompassing the origin is shaded, and the second is a dashed vertical line 3 units to the left of the origin.
x ≥ –3; y ≥ x – 2
x > –3; 5y ≥ –4x – 10
x > –3; y ≥ –x + 1
x > –2; y ≥ –x – 1
The solution set for the system of inequalities is represented by the region between the solid line (y=x+4) and the dotted line (y=-2x-2).
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Use implicit differentiation to find dy/dx and d^2y/dx^2.
Using implicit differentiation dy/dx = -(2x + y)/(x + 2y) and d2y/dx² = -2(x² - 3xy - y²)/(x + 2y)³.
Implicit differentiation is the process of differentiating an equation in which it is not easy or possible to express y explicitly in terms of x.
Given the equation x² + xy + y² = 5,
we can differentiate both sides with respect to x using the chain rule as follows:
2x + (x(dy/dx) + y) + 2y(dy/dx) = 0
Simplifying this equation yields:
(x + 2y)dy/dx = -(2x + y)
Hence, dy/dx = -(2x + y)/(x + 2y)
Next, we need to find d^2y/dx^2 by differentiating the expression for dy/dx obtained above with respect to x, using the quotient rule.
That is:
d/dx(dy/dx) = d/dx[-(2x + y)/(x + 2y)](x + 2y)d^2y/dx² - (2x + y)(d/dx(x + 2y))
= -(2x + y)(d/dx(x + 2y)) + (x + 2y)(d/dx(2x + y))
Simplifying this equation yields:
d2y/dx² = -2(x² - 3xy - y²)/(x + 2y)³
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2 students go to a pizza place every week. let x and y be the weekly spend of each student at the pizza place. assume that x and y have a bivariate normal distribution with
After solving;
(a) P(40.5<Y<48.9) = 0.3721
(b) P(40.5<Y<48.9|X=68.6) = 0.6075
(c) P(40.5<Y<48.9∣X>=68) = 0.3925
(d) In b and c we use conditional probability in bi-variate case. In a it is uni-variate normal distribution.
Given that;
μ(x) = 60.6
σ(x) = 11.2
μ(y) = 46.8
σ(y) = 8.4
ρ = 0.94
That is (X,Y) follows BVN(60.6,46.8,11.2,8.4,0.94)
(a) We have to find P(40.5<Y<48.9).
P(40.5<Y<48.9) = P[(40.5-μ(y))/σ(y) < (Y-μ)/σ(y) < (48.9-μ(y))/σ(y)]
Here Z = (Y-μ)/σ(y) follows N(0,1)
P(40.5<Y<48.9) = P{(40.5-46.8)/8.4 < Z < (48.9-46.8)/8.4}
P(40.5<Y<48.9) = P( -6.3/8.4 < Z < 2.1/8.4)
P(40.5<Y<48.9) = P(-0.75 < Z < 0.25)
P(40.5<Y<48.9) = p(0<Z<0.75)+p(0<Z<0.25)
P(40.5<Y<48.9) = 0.2734+0.0987
P(40.5<Y<48.9) = 0.3721
b) We have to find P(40.5<Y<48.9∣X=68.6).
We know that Y|X follows N(μ(y)+ρ σ(y)/σ(x) (x-μ(x)),σ^2(y)(1-ρ^2))
μ(y)+ρ σ(y)/σ(x) (x-μ(x)) = 46.8+0.94* 8.4/11.2 (X-60.6)
μ(y)+ρ σ(y)/σ(x) (x-μ(x)) = 46.8+0.705(X-60.6)
σ^2(y)(1-ρ^2) = 8.4^2(1-0.94^2)
σ^2(y)(1-ρ^2) = 70.56(1-0.8836)
σ^2(y)(1-ρ^2) = 70.56*0.1164
σ^2(y)(1-ρ^2) = 8.2132
Y|X follows N(46.8+0.705(X-60.6),8.2132)
X = 68.6
Y|X follows N(46.8+0.705(68.6-60.6),8.2132)
N(46.8+5.64,8.2132)
N(52.44,8.2132)
P(40.5<Y<48.9|X=68.6)=p{(40.5-52.44)/√(8.2132)<Z<√(48.9-52.44)/√(8.2132)
P(40.5<Y<48.9|X=68.6) = P(-11.94/2.8658 < z < -3.54/2.8658)
P(40.5<Y<48.9|X=68.6) = p(-4.17 < z < -1.24)
P(40.5<Y<48.9|X=68.6) = 1-0.3925
P(40.5<Y<48.9|X=68.6) = 0.6075
c) Now we have to find the P(40.5<Y<48.9∣X>=68)
P(40.5<Y<48.9∣X>=68) = 1-0.6075
P(40.5<Y<48.9∣X>=68) = 0.3925
d) In b and c we use conditional probability in bi-variate case. In a it is uni-variate normal.
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The right question is given below:
Question 2
What is the lateral surface area of the triangular prism with the given net?
Select one:
15
9
5
12
9
9
8
8
B
8
10
Answer:
the answer is B) 24.
Step-by-step explanation:
To find the lateral surface area of the triangular prism, we need to find the perimeter of the base and then multiply it by the height of the prism.
Looking at the net, we can see that the base is a triangle with sides of length 3 cm, 4 cm, and 5 cm. So the perimeter of the base is:
3 cm + 4 cm + 5 cm = 12 cm
The height of the prism is given as 2 cm. Therefore, the lateral surface area is:
12 cm x 2 cm = 24 cm²
So the answer is B) 24.
IF THIS HELPED, CAN YOU PLEASE GIVE 5⭐? thank you
if a number is divided by an d minused from an another number
This process required 3 to be subtracted 5 consecutive times, so again we see that 15 ÷ 3 = 5. The number that is being divided (in this case, 15) is called the dividend, and the number that it is being divided by (in this case, 3) is called the divisor. The result of the division is the quotient.
Division is a simple operation in which a number is divided. It's easiest to think of it as a number of objects being divided among a certain number of people.
Division is one of the four basic operations of arithmetic, the ways that numbers are combined to make new numbers. The other operations are addition, subtraction, and multiplication.
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please answer this problem step by step
The intervals of each behavior of the function are given as follows:
Decreasing: (-∞, -3).Constant: (-3, 3).Increasing: (3, ∞).How to classify the function as increasing, decreasing or constant?The function is increasing when the graph moves right and up.The function is decreasing when the graph moves right and down.The function is constant when the graph of the function is an horizontal line.More can be learned about functions at https://brainly.com/question/24808124
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4. Calculate the Social Security and Medicare tax that would be applied to an annual salary of $56,400.
Answer:759
Step-by-step explanation:
NEED HELP ASAP WILL MARK AS BRAINLIEST IF THE ANSWER IS CORRECT!
Gareth believes that if he flips a coin 820 times, it will land heads up exactly 410 times. What would you tell Gareth about his prediction?
Answer:
YEs
Step-by-step explanation:
He is correct. as long as his coin has 2 sides
I answered so the other guy could get brainlest
627 x 26
how do you solve this problem using standard algorithm
627 x 26 equals 16,302 when solved using the standard algorithm.
The steps below can be used to solve the multiplication issue 627 x 26 using the conventional algorithm:
627 and 26 should be written one above the other, with the larger number appearing above and the smaller number beneath.
Start by adding each digit of the top number to the ones digit of the bottom number (six). Write the answers below the line after multiplying 6 by 7 and then by 2.
1254 -- a 6 x 7 partial product
1254 -- a half 6 x 2 product
Repeat the process by moving the bottom number one position to the left after that. Multiply 2 by 7 and then by 2, and then write the results one space to the left of the line below the line.
1254 x 627
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A number has 7 in its thousands place and is less than 54,00. How many such numbers are there?
There are 9,000 numbers that have 7 in the thousands of places and are less than 54,000.
Consider the possible digits in the hundreds, tens, and one's places.
Thousands of places: There is only one possibility, which is 7.
Hundreds place: Any digit from 0 to 9 is possible.
Tens place: Any digit from 0 to 9 is possible.
One place: Any digit from 0 to 9 is possible.
Since the number is less than 54,000, the digit in the hundreds place cannot be 5.
So, there are 9 possible digits (0 to 9, except 5) for the hundreds place, and 10 possible digits (0 to 9) for the tens and one's places.
So, the total number of such numbers is:
9 x 10 x 10 x 10 = 9,000
Therefore, there are 9,000 numbers that satisfy the given condition.
Learn more about permutation here:
brainly.com/question/1216161
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