Jonquel rolls a 20-sided number object labeled 1 through 20 determine the theoretical probability of Jonquel rolling a number divisible by 3.

Answer:

2 1/2

Step-by-step explanation:

Hi, 4 in half is 2. 2/3 in half is 1/6

Answer:

Can you please explain more about what do you mean about write a equation for 37.

Step-by-step explanation:

Answer: g=-3

Step-by-step explanation: 2-4g=14

                                             -2       -2

                                              -4g=12

                                              -4g/-4=g 12/-4=-3

Answer:

g = -3

Step-by-step explanation:

2-4g=14

Subtract 2 from each side

2-2-4g=14-2

-4g = 12

Divide each side by -4

-4g/-4 = 12/-4

g = -3

Answer:

Can you please give us figure of following ?

Answer:

its the last one 212°

212°

212°

212°

212°

212°

Step-by-step explanation:

212°

Answer:

1. 4 2. 4 3. 5 4.1

Step-by-step explanation:

first box is 4 second box is 4 third is 5 fourth is 1.

You're welcome.

Answer:

both 0 is one and c = 1 while d = 4 is another

Step-by-step explanation:

The new coordinates are M'(-1, -7), N'(-8, -5), O'(-4, -2), and P'(3, -4)

A 180 degrees rotation denoted by R(180, 0) is a rotation that has the same effect as the 180 degrees counterclockwise of a figure.

And it has the algebraic rule of its rotation to be changed from (x, y) to (-x, -y) i.e  (x, y) ⇒ (-x, -y)

The coordinates of the parallelogram are given as

M(1, 7), N(8, 5), O(4, 2), and P(-3, 4)

The rotation is given as 180° rotation

As mentioned above,

We have (x, y) ⇒ (-x, -y)

Substitute M(1, 7), N(8, 5), O(4, 2), and P(-3, 4) in (x, y) ⇒ (-x, -y)

So, we have

M'(-1, -7), N'(-8, -5), O'(-4, -2), and P'(3, -4)

Hence, the coordinates of the image are M'(-1, -7), N'(-8, -5), O'(-4, -2), and P'(3, -4)

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Given the system of equations:

a) The given system has the equations of lines, so it will be a linear system

b) We will write the equations in slope-intercept from to compare them

From (1): y = -x + 4

From (2): y = x + 4

The slope of the first equation = -1, and the slope of the second equation = 1

so, the given system of consistent independent system

the system has only one solution

c) the system will be consistent

d) the system will be independent

Answer:

the 3 is in the hundred thousands

Step-by-step explanation:

Answer:

250

Step-by-step explanation: because 5*50=250

Answer:

250 miles

Step-by-step explanation:

Answer:

-------------------------

Each coordinate of the midpoint is the average of endpoints:

Therefore M is (13, 14).

By applying the binomial distribution formula, it can be concluded that the probability of seeing at least one albino squirrel is 0.095.

Combination is the number of ways to choose a sample of r elements from a set of n distinct objects where order does not matter and replacements are not allowed.

C(n,r) = n! / (r! (n-r)!)   where

n = number of samples

r = number of selected samples

The binomial distribution formula is used to find the probability of the specific outcome in a discrete distribution.

P(X) = C(n,r) * \(p^{r}\) * \(q^{n-r}\) where:

C = combination value

p = probability of success on a single trial

q = probability of failure on a single trial

If n is the number of the squirrel, p is the probability of seeing albino squirrels and q is the probability of seeing non-albino squirrels, then:

n = 10000

p = 1/100000

q = 1 - 1/100000 = 99999/100000

The probability of seeing at least one albino squirrel:

= P (X ≥ 1)

= 1 - P(X< 1)

= 1 - P(X=0)

= 1 - C(10000,0) * (1/10000)⁰ * (99999/100000)¹⁰⁰⁰⁰⁻⁰

= 1 - (1 * 1 * (99999/100000)¹⁰⁰⁰⁰)

= 1 - 0.904836

= 0. 095164

≈ 0.095

Thus the probability of seeing at least one albino squirrel is 0.095.

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Approximately 12 percent of the people in Olde Town own both a goat and a chicken.

Let's assume there are 100 people in Olde Town. According to the given information, 40 percent of people own a goat, which means there are 40 goat owners. Additionally, 35 percent of goat owners also own a chicken, which means there are 35 percent of 40, which is 14 people, who own both a goat and a chicken.

Moreover, it is mentioned that 30 percent of people own a chicken. So, there are 30 chicken owners in Olde Town. However, we have already accounted for 14 of them who also own a goat. Therefore, there are 30 minus 14, which is 16 people who own only a chicken.

To find the number of people who own both a goat and a chicken, we add the number of people who own both to the number of people who own only a chicken: 14 + 16 = 30.

To calculate the percentage, we divide the number of people who own both by the total population of Olde Town (100) and multiply by 100: (30 / 100) * 100 = 30 percent. So, approximately 30 percent of the people in Olde Town own both a goat and a chicken, which is equivalent to 12 people.

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The new function that can be formed after f(x) transforms horizontally 4 units to the right and then vertically 7 units upwards is
H(x) = h(x) = x² + 11x + 37.

How to shift an equation horizontally?
For a function, f; a brand new function d(x) = f(x - h), where h is a constant, is a horizontal shift of the function f; for positive 'h' the graph shifts right and for negative 'h' the graph shifts left.
How to shift an equation vertically?
For a function, f; a brand new function d(x) = f(x) + k, where k is a constant, is a vertical shift of the function f; for positive 'h' the graph shifts up and for negative 'h' the graph shifts down.

Given, the equation is f(x) = x² + 3x + 2
The new equation formed will be = h(x)
Also, the function horizontally shifts 4 units to the right.
Therefore, h(x) = f(x + 4) = (x + 4)² + 3(x + 4) + 2 = x² + 11x + 30
Again, the function formed in h(x) vertically shifts up by 7 units.
Thus, new equation for h(x) is = h(x) + 7 = x² + 11x + 37
Therefore, the required equation for H(x) = h(x) = x² + 11x + 37

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There is a 21.19% chance that the daily production falls within 32.3 and 36.9 liters.

To find the probability that the daily production of a herd of cows is between 32.3 and 36.9 liters, we need to use the normal distribution properties.

Given that the mean daily production of the herd of cows is 30 liters and the standard deviation is 8.2 liters, we can standardize the distribution and use the standard normal distribution table or calculator. We calculate the z-scores for the values 32.3 and 36.9, which tells us how many standard deviations away from the mean each value is.

Using a standard normal cumulative distribution function, we can find that the probability of the daily production falling between 32.3 and 36.9 liters is approximately 0.2119. This means that there is a 21.19% chance that the daily production falls within this range.

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The probability that daily production is between 32.3 and 36.9 liters is 0.18949 or 18.9%.

To determine the probability that the herd's daily production will be between 32.3 and 36.9 liters, we must compute the z-scores for each number and use a standard normal distribution table to calculate the area under the curve between those z-scores.

To find out the z - scores we need use z-score formula:

Z = X−μ / σ

where μ  is the mean, σ is the standard deviation and X is the observed value. In the problem μ  is 30 liters, X₁ = 32.3 liters & X₂ = 36.9 liters and σ = 8.2 liters.

Substituting the values in the equation to find the z-score for 32.3 liters is:

z₁ = (32.3 - 30) / 8.2 = 0.2804

z₁ = 0.28049

Substituting the values in the equation to find the z-score for 36.9 liters is:

z₂ =( 36.9 - 30) / 8.2 =  0.8414

z₂ = 0.8414

We can determine the area under the curve between these two z-scores using a conventional normal distribution table. The area between z = 0.28049 and z = 0.8414 and the probability is approximately 0.1894.

As a result, the probability that the herd's daily output is between 32.3 and 36.9 liters is about 0.1894.

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There is only one vowel (A) in the first ticket, and there are no vowels in the second ticket. Therefore, there is only 1 way to choose 2 vowels from the 2 available. So the probability of getting both tickets as vowels is:Probability = 1/30

A box contains six tickets: AABBBE. Two tickets are removed, one after the other. The probability that both tickets are vowels is $\fraction{1}{15}$.In order to find out the probability that both tickets are vowels, it is important to know the total number of possible outcomes as well as the number of favorable outcomes. The formula for probability is:Probability of event

= number of favorable outcomes / total number of possible outcomes.The total number of possible outcomes when two tickets are removed, one after the other from a box containing six tickets can be found using permutations. The first ticket can be removed in 6 ways, and the second ticket can be removed in 5 ways, so the total number of ways to remove two tickets is 6 x 5

= 30. This is the total number of possible outcomes.The number of favorable outcomes is the number of ways to choose 2 vowels from the 2 available, divided by the total number of possible outcomes. There is only one vowel (A) in the first ticket, and there are no vowels in the second ticket. Therefore, there is only 1 way to choose 2 vowels from the 2 available. So the probability of getting both tickets as vowels is:Probability

= 1/30

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Answer:

C

Step-by-step explanation:

Just took the test

To complete the double reflection transformation over the lines x = 1 and x = 3, we need to reflect each point twice.

For point a(-5,2), the first reflection over x = 1 will give us a'(-9,2).

The second reflection over x = 3 will give us a"(-7,2).
For point b(-1,5), the first reflection over x = 1 will give us b'(-3,5).

The second reflection over x = 3 will give us b"(-5,5).
For point c(0,3), the first reflection over x = 1 will give us c'(2,3).

The second reflection over x = 3 will give us c"(4,3).
So, the coordinates after the double reflection transformation are:
a"(-7,2), b"(-5,5), and c"(4,3).

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Answer:

Rate of change is used to mathematically describe the percentage change in value over a defined period of time, and it represents the momentum of a variable. The calculation for ROC is simple in that it takes the current value of a stock or index and divides it by the value from an earlier period.

Answer:A rate of change is a rate that describes how one quantity changes in relation to another quantity. If x is the independent variable and y is the dependent variable, then. rate of change=change in ychange in x. Rates of change can be positive or negative.

The inflow rate of water is given by the function of the volume of the

tank derived from the shape of the tank.

Response:

The given parameter are;

Shape of the tank = Conical

Rate at which water is leaking out of the tank = 7,000 cm³/min

Height of the tank = 6 m

Diameter of the tank = 4 m

Solution:

We have;

\(\dfrac{D}{h} = \mathbf{\dfrac{2 \cdot r}{h}}\)

\(r = \mathbf{\dfrac{D}{2 \cdot h}}\)

Which gives;

\(r= \mathbf{\dfrac{h}{3}}\)

\(V = \dfrac{1}{3} \cdot \pi \cdot r^2 \cdot h = \dfrac{1}{3} \cdot \pi \cdot \left(\dfrac{h}{3} \right)^2 \cdot h = \mathbf{ \pi \cdot \dfrac{h}{27} ^3}\)

Which gives;

\(\dfrac{dV}{dh} = \mathbf{\pi \cdot \dfrac{h}{9} ^2}\)

By using chain rule of differentiation, we have;

\(\dfrac{dV}{dt} = \mathbf{\dfrac{dV}{dh} \times \dfrac{dh}{dt}}\)

Which gives;

\(\dfrac{dV}{dt} = \mathbf{\pi \cdot \dfrac{h}{9} ^2\times 20}\)

\(\dfrac{dV}{dt} = \pi \cdot \dfrac{200}{9} ^2\times 20 \approx 279,252.68\)

\(\dfrac{dV}{dt} = \mathbf{Inflow \ rate - Outflow \ rate}\)

Therefore;

\(Inflow \ rate = \mathbf{\dfrac{dV}{dt} + Outflow \ rate}\)

Which gives;

Inflow rate ≈ 279,252.68 + 7000 = 286,252.68 ≈ 286,253

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Answer:

the answeis c

Step-by-step explanation:

hoped that helped

Answer:

I believe that the answer is C: 72 cm²

(a) If f(x) is a convex function with x ∈ ℝⁿ, then all local minima of f(x) are also global minima. In other words, if there exists a point xo such that f(x) ≥ f(xo) for all x in a neighborhood of xo, then f(x) ≥ f(xo) for all x ∈ ℝⁿ.

(b) A graph of a non-convex function can be visualized to understand why the statement in part (a) is not true. It will show a scenario where a local minimum is not a global minimum.

(a) To prove that all local minima of a convex function are also global minima, we can utilize the property of convexity. Suppose there is a point xo such that f(x) ≥ f(xo) for all x in a neighborhood of xo. We assume that xo is a local minimum. Now, consider any arbitrary point x in ℝⁿ. We can express x as a convex combination of xo and another point y in the neighborhood, using the convexity property: x = λxo + (1 - λ)y, where λ is a scalar between 0 and 1. Using this expression, we can apply the convexity property of f(x) to get f(x) ≤ λf(xo) + (1 - λ)f(y). Since f(x) ≥ f(xo) for all x in the neighborhood, we have f(y) ≥ f(xo). Therefore, f(x) ≤ λf(xo) + (1 - λ)f(y) ≤ λf(xo) + (1 - λ)f(xo) = f(xo). This inequality holds for all λ between 0 and 1, implying that f(x) ≥ f(xo) for all x ∈ ℝⁿ, making xo a global minimum.

(b) A graph of a non-convex function can demonstrate a scenario where the statement in part (a) is not true. In such a graph, there may exist multiple local minima, but one or more of these local minima are not global minima. The non-convex nature of the function allows for the presence of multiple valleys and peaks, where one of the valleys may contain a local minimum that is not the overall lowest point on the graph. This occurs because the function may have other regions where the values are lower than the local minimum in consideration. By visually observing the graph, it becomes apparent that there are points outside the neighbourhood of the local minimum that have lower function values, violating the condition for a global minimum.

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After integration, the equation a1x2 + y2f(x,y) da = a(11 - a2) = [(11 - 2sqrt(30))/2] follows. π(22 - 2[(11 - 2sqrt(30))/2]²) = 1.

Given that a 1 and the circle x2 + y2 a, the integral of the function f(x,y) = 11 - x2 - y2 is as follows:

∬[x^2 + y^2 < a^2] (11 - x^2 - y^2) dA

To calculate the integral's value, we can use polar coordinates. The boundaries of inclusion are 0 r a and 0 2. In polar coordinates, r dr d denotes the differential area element dA.

Consequently, we have:

∬[x^2 + y^2 < a^2] (11 - x^2 - y^2) dA

= ∫[0,2π] ∫[0,a] (11 - r^2) r dr dθ

= ∫[0,2π] [(11a^2)/2 - (a^4)/4] dθ

= 2π [(11a^2)/2 - (a^4)/4]

= πa^2 (22 - 2a^2)

We must now work out the equation to determine the value of a such that the integral equals 1.

a^2 π (22 - 2a^2) = 1

When we divide both sides by and rearrange them, we get:

22a^2 - 2a^4 = 1

2a^4 - 22a^2 + 1 = 0

The quadratic formula can be used to answer this quadratic equation:

a^2 = [22 +/- sqrt(22^2 - 4(2)(1))]/(2(2))

a^2 = [22 − sqrt(480)]/4

a^2 = [22 ± 4sqrt(30)]/4

a^2 = (11 ± 2sqrt(30))/2

We pick the negative root since an is a 1, which is:

a^2 = (11 - 2sqrt(30))/2

In light of this, a1x2 + y2f(x,y) da = a(11 - a2) = [(11 - 2sqrt(30))/2]

π(22 - 2[(11 - 2sqrt(30))/2]²) = 1.

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The probability of renting exactly three apartments in a week is approximately 0.2018 or 20.18%.

If the average number of units rented per week is 2.3 and the distribution is Poisson, then the parameter lambda is also equal to 2.3.

The probability of renting exactly three apartments in a week is given by the Poisson probability function:

\(P(X = 3) = (e^(-lambda) * lambda^x) / x!\)

Substituting the values, we get:

\(P(X = 3) = (e^(-2.3) * 2.3^3) / 3!\)

P(X = 3) = (0.09963 * 12.167) / 6

P(X = 3) = 0.2018

Therefore, the probability of renting exactly three apartments in a week is approximately 0.2018 or 20.18%.

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The function f(x) = 8sin(x) + cot(x) does not have an inflection point across the interval -1 ≤ x ≥ 1

To find the inflection points of the equation f(x) = 8sin(x) + cot(x) within the assumed interval of -1 ≤ x ≤ 1, we need to calculate the second derivative of the function and then identify the values of x where the second derivative changes sign.

Let's start by finding the first derivative of f(x). Since f(x) = 8sin(x) + cot(x), we have:

f'(x) = 8cos(x) - csc²(x)

Next, let's find the second derivative by taking the derivative of f'(x):

f''(x) = -8sin(x) + 2csc(x)cot(x)

Now, we need to identify the values of x where the second derivative changes sign. These points correspond to the potential inflection points.

Within the given interval -1 ≤ x ≤ 1, we can evaluate the second derivative at the critical points and determine if there is a sign change.

First, let's check x = -1:

f''(-1) = -8sin(-1) + 2csc(-1)cot(-1)

Next, let's check x = 1:

f''(1) = -8sin(1) + 2csc(1)cot(1)

By evaluating the second derivative at these points, we can determine if there is a sign change, which indicates an inflection point.

Note: Since cot(x) and csc(x) are not defined at certain points, we need to be careful in evaluating the second derivative at those points.

However, in this case, we can observe that the function f(x) = 8sin(x) + cot(x) is undefined when x = 0, due to the cot(x) term. Therefore, we can conclude that there are no inflection points within the given interval of -1 ≤ x ≤ 1.

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Answer:

D. The money that Kai started with before he mowed any lawns.

Step-by-step explanation:

We Know

The equation is y = mx + b

The x represents the number of lawns that Kai mows.

What does the y-intercept represent in this equation?

The y-intercept is when the x = 0, meaning the y-intercept is the amount of money he has when mowing 0 lawn. So, the answer is D.

Answer:

The Answer is D

Step-by-step explanation:

Answer:

\(2x + 18 = 15x + 33 - 8x \\ 2x + 18 = 7x + 33 \\ 2x - 7x = 33 - 18 \\ - 5x = 15 \\ x = - 3\)

Answer:

CS M=2/3 , KP M=2/3

Step-by-step explanation:

Neither because, they have the same slope but CS is negative so, the slopes are in a line.

Mei concluded that

We are 90% confident that the true proportion of times the die would land on the number 4 is between 0.398 and 0.562. Since this includes 0.5, the die appears to be fair.

It is based on a statistical analysis of the data collected by Mei.

The proportion of times the die landed on the number 4 is calculated as 48/100 = 0.48.

Using a statistical method called a confidence interval, we can estimate the range of values that the true proportion of times the die would land on the number 4 is likely to fall within, with 90% confidence.

The confidence interval calculated for this data is 0.398 to 0.562.

Since this interval includes the value of 0.5  (which would be the proportion of times a fair die would land on the number 4), By using statistical method we cannot reject the hypothesis that the die is fair.

Hence,

By using statistical method, we can conclude that the die would land on the number 4 is between 0.398 and 0.562 as 0.5 the die appears to be fair.

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