juanita purchased a forklift for $23,000 to move materials in her warehouse. the salvage value of the forklift is $3,150, and it’s useful life is 10 years How much will juanita write off as a depreciation expense each year for the forklift????
a. $1,323
b. $1,895
c. $1,985
b. $2,615

Answer:

x=4,y=3

Step-by-step explanation:

x=19-5y if we transpose equation 2 for x.

Plug that into equation 1

4(19-5y)+3y=25

76-20y+3y=25

76-25=17y

51=17y

y=3

Plug y=3 into equation 2

x+5(3)=19

x=19-15=4

We are having two equations,

★ From Equation No 2 :-

>> x + 5y = 19

>> x = 19 - 5y

★ From Equation No 1 :-

Substitute here the value of x which we got above as (19 - 5y).

>> 4x + 3y = 25

>> 4 (19 - 5y) + 3y = 25

>> 4 × (19 - 5y) + 3y = 25

>> 76 - 20y + 3y = 25

>> 76 - 17y = 25

>> -17y = 25 - 76

>> -17y = -51

>> 17y = 51

>> y = 51 / 17

>> y = 3

★ Finding out value of x :-

>> x = 19 - 5y

>> x = 19 - 5(3)

>> x = 19 - 5 × (3)

>> x = 19 - 15

>> x = 4

The angles formed by the bisector are equal in measure, adjacent, supplementary, form a linear pair, and are congruent.

When a line bisects an angle, it divides the angle into two equal parts. The resulting angles have several properties

They have equal measures: The two angles formed by the bisector have the same degree measurement.

They are adjacent: The two angles share a common side and vertex.

They are supplementary: The sum of the two angles formed by the bisector is 180 degrees.

They form a linear pair: The two angles, together with the adjacent angle on the other side of the bisector, form a straight line or a linear pair.

They are congruent: The two angles formed by the bisector are congruent to each other.

These properties are useful in solving problems involving angle bisectors in geometry.

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I have solved the question in general, as the given question is incomplete.

The complete question is:

What are some properties of the angles formed by the bisector?

Decomposition is used to perform ANOVA and test the significance of the independent variable and its interaction effect on the dependent variable.

The expression SS stands for "sum of squares", which is a statistical concept used in analysis of variance (ANOVA) to quantify the variation in a dataset. The components of this expression, a, b, c, and d, represent different sources of variation in the dataset, and their meanings are as follows:

a. (df)(s^2): This component represents the sum of squares due to the effect of the independent variable, also known as the factor or treatment. It is calculated by multiplying the degrees of freedom (df), which is the number of levels of the factor minus one, by the variance of the data within each level (s^2). This component quantifies the amount of variation in the dependent variable that can be explained by the independent variable.

b. (df)(s): This component represents the sum of squares due to the interaction between the independent variable and other factors, also known as the interaction effect. It is calculated by multiplying the degrees of freedom (df) by the standard deviation (s) of the data. This component quantifies the amount of variation in the dependent variable that is due to the joint effect of the independent variable and other factors.

c. (n)(s^2): This component represents the sum of squares due to the variation within groups, also known as the error or residual sum of squares. It is calculated by multiplying the sample size (n) by the variance of the data within each group (s^2). This component quantifies the amount of variation in the dependent variable that is not explained by the independent variable or other factors.

d. (n)(s): This component represents the sum of squares due to the variation between the sample mean and the overall mean, also known as the total sum of squares. It is calculated by multiplying the sample size (n) by the standard deviation (s) of the data. This component quantifies the total amount of variation in the dependent variable.

In summary, the expression SS = a. (df)(s^2) + b. (df)(s) + c. (n)(s^2) + d. (n)(s) represents the decomposition of the total sum of squares into its components due to the independent variable, interaction effect, error, and total variation. This decomposition is used to perform ANOVA and test the significance of the independent variable and its interaction effect on the dependent variable.

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The range of a function is the complete set of all possible resulting values of the dependent variable (usually, y.)

From the graph given, the set of values of y that satisfy the given graph is from 1 to 5 (inclusive)

So we will have:

Answer:

9(x-1)(x-1) or 9(x-1)²

Step-by-step explanation:

9x² - 18x + 9

factor out a 9

9(x² - 2x + 1)

use middle term factorization to factor x² - 2x + 1

9(x-1)(x-1) or 9(x-1)²

Middle term factorization explained:

For x² - 2x + 1, you want to find 2 numbers that multiply to +1 and add to -2. You then split x² to x and x and add the 2 numbers individually to x.

It should look something like (x+1st number)(x+2nd number)

the two numbers that multiply to get to 1 and add to get to -2 are -1 and -1

( -1 × -1 = 1 and -1 + -1 = 2 )

so we then add the number to the split x² to get (x-1)(x-1) which is the same as (x-1)², the 9 is then added to the factored form to get 9(x-1)(x-1) or 9(x-1)²

a. The correlation between winning time and year would be negative because the regression equation has a negative slope (-0.11865).The slope of -0.11865, actual winning time in 2010 was 34.91 seconds.

b. Using the regression equation, we can predict the winning time for 2010 as follows:

winning time = \(273.06 - (0.11865)(2010)\)

winning time = \(273.06 - 239.2465\)

winning time = \(33.8135 seconds\)

The actual winning time in 2010 was 34.91 seconds, which is higher than the predicted time.

c. The slope of -0.11865 indicates that winning times decrease by an average of 0.11865 seconds per year. In other words, for each year that passes, the winning time decreases by approximately 0.12 seconds on average. This suggests that athletes are improving and getting faster over time, which is a common trend in many sports.

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Answer:

5a - 30

Step-by-step explanation:

Answer:

5a - 30

Step-by-step explanation:

Distributive property: a(b + c) = a*b + a*c

5(a - 6)= a * 5 - 6*5

          = 5a - 30

Using the definition of the derivative,

\(\displaystyle f'(-2) = \lim_{x\to-2}\frac{f(x) - f(-2)}{x - (-2)}\)

\(\displaystyle f'(-2) = \lim_{x\to-2}\frac{\dfrac6x + 3}{x + 2}\)

\(\displaystyle f'(-2) = \lim_{x\to-2}\frac{\dfrac{6+3x}x}{x + 2}\)

\(\displaystyle f'(-2) = \lim_{x\to-2}\frac{6+3x}{x(x + 2)}\)

\(\displaystyle f'(-2) = \lim_{x\to-2}\frac{3(x+2)}{x(x + 2)}\)

\(\displaystyle f'(-2) = \lim_{x\to-2}\frac{3}{x} = \boxed{-\dfrac32}\)

According to the principle of conservation of linear momentum, Big Al and his skateboard has a combined mass of 100 kilograms.

The situation shows a system formed by a rock, Big Al and his skateboard, whose speed changes as consequence of the principle of conservation of linear momentum due to the absence of external loads acting on the system and any of its parts.

A matematical representation of the situation is derived from the definition of the principle of conservation of linear momentum:

(0.5 kg) · (0 m / s) + m · (0 m / s) = (0.5 kg) · (10 m / s) + m · (- 0.05 m / s)

0 = 5 - 0.05 · m

Where m is the combined mass of big Al and the skateboard, in kilograms.

Now we solve the equation for m:

0.05 · m = 5

m = 100 kg

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Answer:

Step-by-step explanation:

The solution of each question is self-explanatory.

Used properties

Answer:

38°; 142°; 308°

Step-by-step explanation:

belive me

Using Euler's method, we approximate the solution to the initial value problem y' = y - 2x - 3, with the initial condition y(0) = 4

We apply the method twice, first with a step size of h = 0.25 and then with a step size of h = 0.1. We compare the three-decimal-place values of the two approximations at x = 1/2 with the value of y(1/2) of the actual solution.

To apply Euler's method, we start with the initial condition y(0) = 4 and calculate the approximate values of y at each step using the given differential equation.

For the first approximation with h = 0.25, we divide the interval [0, 1/2] into four subintervals. At each step, we use the formula y_i+1 = y_i + h * f(x_i, y_i), where f(x, y) = y - 2x - 3. After the calculations, we find that the approximation for y(1/2) is approximately 5.902.

For the second approximation with h = 0.1, we divide the interval [0, 1/2] into ten subintervals. Using the same formula as before, we obtain the approximation for y(1/2) as approximately 5.934.

The value of y(1/2) using the actual solution can be found by solving the differential equation explicitly or by substituting x = 1/2 into the given solution y(x) = 5 + 2x - \(e^x\). After evaluating, we find that y(1/2) is approximately 5.871.

Comparing the two approximations, we see that the one with h = 0.1 is closer to the value of y(1/2) obtained from the actual solution. Therefore, the approximation with h = 0.1 is considered to be closer to the actual solution

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Answer:

d = 1406.25

Step-by-step explanation:

Given d is proportional to s² then the equation relating them is

d = ks² ← k is the constant of proportion

To find k use the condition d = 900 when s = 20

900 = k × 20² = 400k ( divide both sides by 400 )

2.25 = k

d = 2.25s² ← equation of proportion

When s = 25, then

d = 2.25 × 25² = 2.25 × 625 = 1406.25

Answer:

368

Step-by-step explanation:

46*8=368

since there is 48 boxes of 8 bagels, it would equal 368 bagels.

Answer:

5 hundred millions, 4 millions, 6 thousands, 2 tens = 504,006,020

Step-by-step explanation:

504,060,020 > 5 hundred millions, 4 millions, 6 thousands, 2 tens

                                                                                      (504,006,020)

The 2003rd term of the sequence of odd numbers 1, 3, 5, 7, 9,.. is 4005.

It should be noted that this is an arithmetic sequence and the formula will be written as:

a + (n - 1)d

a = first term = 1

n = number of terms = 2003

d = common difference = 3 - 1 = 2

Therefore, the 2003rd term will be:

= a + (n - 1)d

= 1 + (2003 - 1) × 2

= 1 + (2002 × 2)

= 1 + 4004

= 4005

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Answer:

7x + 21

Step-by-step explanation:

7(x+3)

7x + 7(3)

7x + 21

Answer:

A. 18x - 3y = 6

Step-by-step explanation:

By taking 3 common from the terms 18x and 3y we get,

3 (6x-3y) = 6

or, 6x - y = 6/3

or, 6x - y = 2

And,

The equation becomes,

y = 6x - 2

The equation has exactly one solution in common with the equation y=6x-2 will be 18x - 3y = 6. The correct option is A.

A finite set of equations for which common solutions are sought is referred to in mathematics as a set of simultaneous equations, often known as a system of equations or an equation system.

An equation is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

By taking 3 commons from the terms 18x and 3y we get,

3 (6x-3y) = 6

6x - y = 6/3

6x - y = 2

The equation becomes,

y = 6x - 2

Therefore, the equation has exactly one solution in common with the equation y=6x-2 will be 18x - 3y = 6. The correct option is A.

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Answer:

Acute and Straight

Step-by-step explanation:

Answer

252

Step-by-step explanation:

12*12=144

18*6= 108

108+144=252

Geometry

Cut the figure into a rectangle and a triangle.

12x12=144cm^2

18x6=108cm^2

Add the areas to find the total area.

Total Area = 252cm^2

Answer:

Step-by-step explanation:

Answer:

A=q-n

Step-by-step explanation:

To get A by itself you have to subtract n from both sides of the equation

A+n=q

  -n=-n

A=q-n

Consider the function g: R → R defined by g(x) = ∫e^(sin(1) t)/(1+t^2) sin(x) dt. To find the derivative of g(x) with respect to x, we need to apply the Leibniz rule:g'(x) = d/dx [∫e^(sin(1) t)/(1+t^2) sin(x) dt]= ∫d/dx[e^(sin(1) t)/(1+t^2)] sin(x) dt= ∫cos(1)*e^(sin(1) t)/(1+t^2) sin(x) dt.The integral in the expression for g'(x) can be evaluated using the substitution u = 1+t^2, so that du/dt = 2t:∫cos(1)*e^(sin(1) t)/(1+t^2) sin(x) dt= cos(1)∫e^(sin(1) t)/(1+t^2) sin(x) dt= cos(1)∫e^(sin(1) t)/(u) sin(x) (du/2t)From this point, we use integration by parts with u = sin(x) and dv/dt = e^(sin(1) t)/(u). This gives us v = e^(sin(1) t) and du/dt = cos(x):∫e^(sin(1) t)/(u) sin(x) (du/2t) = (1/2)∫v*du = (1/2)[v*sin(x) - ∫v*du/dt dx]= (1/2)[e^(sin(1) t)*sin(x) - cos(1)∫e^(sin(1) t)*cos(x) dt] = (1/2)[e^(sin(1) t)*sin(x) + cos(1)e^(sin(1) t)*sin(x)] = (1/2)e^(sin(1) t)*sin(x)*(1+cos(1)).Thus,g'(x) = ∫cos(1)*e^(sin(1) t)/(1+t^2) sin(x) dt= (1/2)e^(sin(1) t)*sin(x)*(1+cos(1)).To find the values of x for which g'(x) = 0, we set the expression for g'(x) equal to 0 and solve for x:(1/2)e^(sin(1) t)*sin(x)*(1+cos(1)) = 0 => sin(x) = 0 or cos(1) = -1. This gives us the values of x that satisfy g'(x) = 0:x = nπ (n ∈ Z) or x = (2k+1)π/2 (k ∈ Z).Conclusion:In summary, we have found the derivative of g(x) with respect to x and determined the values of x for which g'(x) = 0. The main answer is g'(x) = (1/2)e^(sin(1) t)*sin(x)*(1+cos(1)) and the supporting answer is x = nπ (n ∈ Z) or x = (2k+1)π/2 (k ∈ Z).

The function `g: R → R` defined by

g(x): = · esin(1) dt 11) ². sin(x)` can be rewritten as;

g(x) = (1/2) · \(e^(sin(1)x) (1 - cos(x²))\)

First, we find the derivative of g(x) as follows;

g(x) = (1/2) · \(e^(sin(1)x) (1 - cos(x²))\)

Therefore,

g'(x) = (1/2) · \(e^(sin(1)x) · cos(x²) · 2x + (1/2) · e^(sin(1)x) · (1 - cos(x²)) · 2x\)

g'(x) = \(x · e^(sin(1)x) · cos(x²) + x · e^(sin(1)x) · (1 - cos(x²))\)

We set `g'(x) = 0` to

determine the values of `x`.

0 =\(x · e^(sin(1)x) · cos(x²) + x · e^(sin(1)x) · (1 - cos(x²))\)

0 = \(x · e^(sin(1)x) · [cos(x²) + (1 - cos(x²))]\)

0 = \(x · e^(sin(1)x) · sin(x²)\)

This is true for `x = 0` or `sin(x²) = 0`.

The possible values of `x` for which `g'(x) = 0` are `x = 0` or `x = ±nπ`

where `n` is an integer.

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The given double integral is ∫ ∫ (x² + y²)dx dy, and we need to evaluate it over the region in the positive quadrant where x+y≤1.

To evaluate this double integral, we can first determine the limits of integration for both x and y based on the given region. In the positive quadrant, x and y both range from 0 to 1.

Now, integrating the inner integral with respect to x, we get:

∫ (x² + y²)dx = (1/3)x³ + y²x + C1,

where C1 is the constant of integration.

Next, we integrate the resulting expression with respect to y:

∫ [(1/3)x³ + y²x + C1] dy = (1/3)x³y + (1/3)y³x + C1y + C2,

where C2 is another constant of integration.

Finally, we evaluate this double integral over the given region by substituting the limits of integration:

∫∫ (x² + y²)dx dy = ∫[0 to 1] ∫[0 to 1-x] (x² + y²)dy dx.

Performing the integration, we can find the numerical value of the double integral within the given region.

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Answer:

Her change was $3

Step-by-step explanation:

The skirt was $25, the blouse was $16, the 2 pairs of socks were $4, the sales tax was $2.

$25 + $16 + $4 + $2 = $47

$50 - $47 = $3

Her change was $3

Hi!

To solve this, we can set up an equation. If L, the length, is 3 less than 2 times W, the width, it would look like this. L = 2w - 3

Now, the perimeter equation is L + L + w + w = 48, so we plug in the L's and get this:

2w - 3 + 2w - 3 + w + w = 48

Now solve, add like terms:

6w - 6 = 48

add 6 to both sides

6w = 54

divide both sides by 6

w = 9

The width is 9, and the length is two times this minus 3, so 2(9) - 3 = 18 - 3 = 15

Therefore your width is 9 and your length is 15

Hope this helps! :D

Answer:

Y=5X because the slope is 5 and the Y-intercept is 0

Answer:

Do you have the pictures? Otherwise I'm afraid I can't help you haha. Show me the pictures and I'll have you an explanation and answer :)

Step-by-step explanation:

Step-by-step explanation:

option C is correct

as,

4x is a common magnification for scanning objectives and, when combined with the magnification power of a 10x eyepiece lens, a 4x scanning objective lens gives a total magnification of 40x.

hope this answer helps you dear! take care and may u have a great day ahead!

Answer:

40x

Step-by-step explanation:

4x is a common magnification for scanning objectives and, when combined with the magnification power of a 10x eyepiece lens, a 4x scanning objective lens gives a total magnification of 40x.

Answer:

4 : 7

Step-by-step explanation:

Given 2 similar figures the if the ratio of perimeters = a : b

The the ratio of areas = a² : b²

Here

ratio of areas = 16 : 49 , then

ratio of perimeters = \(\sqrt{16}\) : \(\sqrt{49}\) = 4 : 7

Answer:

please answer me binary number multiply 11010 multiply 101