Julie made $29 washing cars. This is $11 less than twice the amount
Julie made. How much money did Julie make?

The exact side length of the regular decagon inscribed in a circle of radius 1+2 units is equal to the radius itself, which is 1+2 units. The angles at the center of the circle, formed by the radii of the decagon, are 36 degrees each.

To construct a regular decagon inscribed in a circle of radius 1+2, we can follow these steps:

1. Draw a circle with a radius of 1+2 units. Let the center of the circle be O.

2. Draw a line segment from the center O to any point on the circumference of the circle. This will be one side of the decagon.

3. Using a compass, divide the circumference of the circle into ten equal parts. Mark these points as A, B, C, D, E, F, G, H, I, and J.

4. Connect the center O with each of the ten points A, B, C, D, E, F, G, H, I, and J. These lines will be the radii of the circle.

5. Measure the length of any one of the radii, such as OA. This will give us the exact side length of the regular decagon.

To calculate the side length of the decagon, we can use trigonometry. Since the radius of the circle is 1+2 units, the radius of the inscribed decagon is also 1+2 units.

In a regular decagon, each angle at the center of the circle is 36 degrees (360 degrees divided by 10). Therefore, we get five angles for free, as the lines radiating from the center divide the circle into ten equal angles.

Now, let's move on to constructing a rhombus with a side length of 3+2 units and an angle of measure 72 degrees.

1. Draw a line segment AB with a length of 3+2 units.

2. At point B, construct an angle of measure 72 degrees.

3. From point A, draw a line segment AC perpendicular to AB.

4. Extend the line segment AB to point D so that AB = CD.

5. Connect points C and D to form the rhombus.

To calculate the exact lengths of the diagonals of the rhombus, we can use the properties of a rhombus. In a rhombus, the diagonals are perpendicular and bisect each other. Also, the diagonals of a rhombus are equal in length.

Since AB and CD are the sides of the rhombus, they are equal in length, so AB = CD = 3+2 units.

The diagonals AC and BD bisect each other at point O. In a rhombus, the diagonals bisect each other at a 90-degree angle. Therefore, triangle ACO is a right triangle.

We know the length of the side AC (which is the height of the rhombus) is 3+2 units, and angle ACO is 72 degrees. Using trigonometry, we can calculate the length of the diagonal AC.

By applying the sine function, we have:

sin(72) = height / AC

sin(72) = (3+2) / AC

AC = (3+2) / sin(72)

By substituting the value of sin(72) ≈ 0.951, we get:

AC = (3+2) / 0.951

AC ≈ 5.272 units

Since the diagonals of a rhombus are equal, the length of the diagonal BD is also 5.272 units.

On the other hand, the exact lengths of

The diagonals of the rhombus with a side length of 3+2 units and an angle of measure 72 degrees are approximately 5.272 units each.

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The carton can hold 8402.7cm3 or 8.4 litres of milk now

Initially, the width and length of the carton are 8.88cm each.

Now, the width and length of the carton are doubled. That is:

The width and length are 2 x 8.88cm = 17.76 cm each

But the height remains the same:  26.64cm

Volume of the carton = width x length x height

                                    = 17.76 x 17.76 x 26.64

                                    = 8402.7 cm3 = 8.4 litres

Therefore, the quantity of milk the carton can hold now is 8402.7 cm3 or 8.4 litres.

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Part A

1. Written Expression: "Three less than the product of thirteen squared and four."

  Symbolic Form: 4 * (13^2) - 3

  Evaluation: 4 * 169 - 3 = 676 - 3 = 673

2. Written Expression: "The product of eight minus six and x."

  Symbolic Form: (8 - 6) * x

  Evaluation: 2 * x = 2x

3. Written Expression: "The square root of thirty-six plus the sum of eight and four squared."

  Symbolic Form: sqrt(36) + (8 + 4^2)

  Evaluation: 6 + (8 + 16) = 6 + 24 = 30

4. Written Expression: "Nineteen less than the product of seven and four minus the quotient of sixteen and four."

  Symbolic Form: (7 * 4 - 16 / 4) - 19

  Evaluation: (28 - 4) - 19 = 24 - 19 = 5

5. Written Expression: "X to the fourth power plus the product of six and the square root of nine."

  Symbolic Form: x^4 + 6 * sqrt(9)

  Evaluation: x^4 + 6 * 3 = x^4 + 18

6. Written Expression: "Fifteen plus eight cubed minus the sum of fourteen and six squared."

  Symbolic Form: 15 + 8^3 - (14 + 6^2)

  Evaluation: 15 + 512 - (14 + 36) = 15 + 512 - 50 = 527 - 50 = 477

7. Written Expression: "The product of three and fifteen minus nine plus the quotient of fifteen and three."

  Symbolic Form: 3 * 15 - 9 + 15 / 3

  Evaluation: 45 - 9 + 5 = 36 + 5 = 41

8. Written Expression: "The product of seventeen and y, plus the square root of eighty-one minus the product of six and x minus four."

  Symbolic Form: 17*y + sqrt(81) - (6*x - 4)

  Evaluation: 17y + 9 - (6x - 4) = 17y + 9 - 6x + 4 = 17y + 13 - 6x

Part B

9. Written Expression: "Four times the sum of three times x and two, minus nine."

10. Written Expression: "The square root of one hundred forty-four minus the difference of sixty-two and x."

11. Written Expression: "The quotient of twenty-eight and four minus the sum of x and seven."

12. Written Expression: "X cubed minus four times y minus the sum of six and two."

13. Written Expression: "The quotient of sixty-four and eight minus the product of x and six."

14. Written Expression: "Seventy-two times the difference of four and fifteen times x."

15. Written Expression: "Four times the sum of the square root of one hundred forty-four and ninety-three, minus y."

16. Written Expression: "Fifty-four plus seven times y minus the sum of eight and nine times x."

Part C

17. If Jamond has three more books than the sum of Mason and Adam, then how many books does he have?

   Symbolic Form: J = M + A + 3

18. If Nancy answered five more word problems than the quotient of

Samantha and Trisha’s answers, then how many word problems did Nancy answer?

   Symbolic Form: N = (S / T) + 5

19. Jolie was trying to learn a new word every day. She started keeping track of how many new words she had learned. If she learned 6 more new words than four to the 6th power, then how many new words did Jolie learn?

   Symbolic Form: J = 4^6 + 6

20. Ricky and Sam were practicing their writing in school. If Ricky’s practice contained six fewer letters than the product of Sam’s answers and 10, how many letters did Ricky write?

   Symbolic Form: R = 10 * S - 6

Answer:

The average rate will be:  0.7 inches/hour

Hence, Option (4) is correct.

Step-by-step explanation:

As the average rate = change in y-values/change in x values

                                 = Δy/Δx

From the table, it is clear that over the time interval 't=2' to 't=7', the values

snow depth 'd' inches change from d=1.5 to d=5.

Therefore,

Average rate = Δy/Δx

                      = (5-1.5) / (7-2)

                      = 3.5/5

                      = 0.7 inches/hour

Therefore, the average rate will be:  0.7 inches/hour

Hence, Option (4) is correct.

The solution to the given differential equation 2xy(dy/dx) = y², with the initial condition y(2) = 3, is y = (27 * e⁽ˣ⁻²⁾\()^{1/4}\).

To solve the given differential equation

2xy(dy/dx) = y²

We will use separation of variables and integrate to find the solution.

Start with the given equation

2xy(dy/dx) = y²

Divide both sides by y²:

(2x/y) dy = dx

Integrate both sides:

∫(2x/y) dy = ∫dx

Integrating the left side requires a substitution. Let u = y², then du = 2y dy:

∫(2x/u) du = ∫dx

2∫(x/u) du = ∫dx

2 ln|u| = x + C

Replacing u with y²:

2 ln|y²| = x + C

Using the properties of logarithms:

ln|y⁴| = x + C

Exponentiating both sides:

|y⁴| = \(e^{x + C}\)

Since the absolute value is taken, we can remove it and incorporate the constant of integration

y⁴ = \(e^{x + C}\)

Simplifying, let A = \(e^C:\)

y^4 = A * eˣ

Taking the fourth root of both sides:

y = (A * eˣ\()^{1/4}\)

Now we can incorporate the initial condition y(2) = 3

3 = (A * e²\()^{1/4}\)

Cubing both sides:

27 = A * e²

Solving for A:

A = 27 / e²

Finally, substituting A back into the solution

y = ((27 / e²) * eˣ\()^{1/4}\)

Simplifying further

y = (27 *  e⁽ˣ⁻²⁾\()^{1/4}\)

Therefore, the solution to the given differential equation with the initial condition y(2) = 3 is

y = (27 * e⁽ˣ⁻²⁾\()^{1/4}\)

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The probability mass function (PMF) for X is:P(X = 0) = 13/20,P(X = 1) = 1/5,P(X = 2) = 3/20

To find a probability mass function (PMF) for the random variable X that satisfies the given expectations, we can define the probabilities for each value of X and solve for them.

Let's denote the probability of X taking the value x as P(X = x). According to the problem, we have the following expectations:

E[X] = 1/2

E(X^2) = 4/5

The expectation of X is given by:

E[X] = Σ(x * P(X = x))

For X = 0, we have:

0 * P(X = 0) + 1 * P(X = 1) + 2 * P(X = 2) = 1/2

This equation can be rewritten as:

P(X = 1) + 2 * P(X = 2) = 1/2

Similarly, the expectation of X^2 is given by:

E(X^2) = Σ(x^2 * P(X = x))

For X = 0, we have:

0^2 * P(X = 0) + 1^2 * P(X = 1) + 2^2 * P(X = 2) = 4/5

Simplifying, we get:

P(X = 1) + 4 * P(X = 2) = 4/5

We now have a system of two equations with two unknowns:

P(X = 1) + 2 * P(X = 2) = 1/2

P(X = 1) + 4 * P(X = 2) = 4/5

Solving this system of equations, we can find the values of P(X = 1) and P(X = 2).

Multiplying the first equation by 2, we get:

2 * P(X = 1) + 4 * P(X = 2) = 1

Subtracting the second equation from this, we have:

(2 * P(X = 1) + 4 * P(X = 2)) - (P(X = 1) + 4 * P(X = 2)) = 1 - 4/5

P(X = 1) = 1 - 4/5

P(X = 1) = 1/5

Substituting this back into the first equation, we find:

1/5 + 2 * P(X = 2) = 1/2

2 * P(X = 2) = 1/2 - 1/5

2 * P(X = 2) = 5/10 - 2/10

2 * P(X = 2) = 3/10

P(X = 2) = (3/10) / 2

P(X = 2) = 3/20

Finally, since the probabilities must sum to 1, we have:

P(X = 0) = 1 - P(X = 1) - P(X = 2)

P(X = 0) = 1 - 1/5 - 3/20

P(X = 0) = 20/20 - 4/20 - 3/20

P(X = 0) = 13/20

Therefore, the probability mass function (PMF) for X is:

P(X = 0) = 13/20

P(X = 1) = 1/5

P(X = 2) = 3/20

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The final equation for the tangent plane to the graph of f at the point (a, b) is z = 2e^a(x - a) - y + 2e^a - 2b. This equation represents the plane that is tangent to the graph of f at the specified point (a, b).

To find the equation for the tangent plane to the graph of the function f(x, y) = 2e^x - y at a given point (x0, y0), we need to calculate the partial derivatives of f with respect to x and y at that point.

The partial derivative of f with respect to x, denoted as ∂f/∂x or fₓ, represents the rate of change of f with respect to x while keeping y constant. Similarly, the partial derivative of f with respect to y, denoted as ∂f/∂y or fᵧ, represents the rate of change of f with respect to y while keeping x constant.

Let's calculate these partial derivatives:

fₓ = d/dx(2e^x - y) = 2e^x

fᵧ = d/dy(2e^x - y) = -1

Now, we have the partial derivatives evaluated at the point (x0, y0). Let's assume our point of interest is (a, b), where a = x0 and b = y0.

At the point (a, b), the equation for the tangent plane is given by:

z - f(a, b) = fₓ(a, b)(x - a) + fᵧ(a, b)(y - b)

Substituting fₓ(a, b) = 2e^a and fᵧ(a, b) = -1, we have:

z - f(a, b) = 2e^a(x - a) - (y - b)

Now, let's substitute f(a, b) = 2e^a - b:

z - (2e^a - b) = 2e^a(x - a) - (y - b)

Rearranging and simplifying:

z = 2e^a(x - a) - (y - b) + 2e^a - b

The final equation for the tangent plane to the graph of f at the point (a, b) is z = 2e^a(x - a) - y + 2e^a - 2b.

This equation represents the plane that is tangent to the graph of f at the specified point (a, b).

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Based on the converse of corresponding angles theorem, the value of x would be: 20.

The converse of corresponding angles theorem states that if two corresponding angles that lie on two lines that are crossed by a transversal are congruent to each other, then the lines are parallel lines.

Therefore, based on the converse of corresponding angles theorem, lines m and n will be parallel to each other if:

3x + 5 = 65

Solve for the value of x that makes both measures equal:

3x + 5 - 5 = 65 - 5 [subtraction property of equality]

3x = 60

3x/3 = 60/3 [division property of equality]

x = 20

Therefore, based on the converse of corresponding angles theorem, the value of x would be: 20.

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Answer:

W(t) = 10 + 1.5*t

Step-by-step explanation:

Given:

The weight gain of the baby is 1.5 pounds per month.

After 4 months, baby's weight = 16 pounds

Let us the say the weight of the baby when it was born be x.

Then:

x + 1.5*(4) = 16

x = 10

Then weight of the baby as a function of number of months(t) will be=

initial weight + incremental weight per month*no of months(t).

W(t) = 10 + 1.5*t

a. Using the Empirical Rule, we can say that 95% of NBA point guards are between approximately 67.18 inches and 82.02 inches tall.

b. In order to use the Empirical Rule, we assume that the histogram of NBA point guards' average heights is shaped like a normal distribution (bell-shaped).

a. Using the Empirical Rule, we can determine the range within which 95% of NBA point guards' heights would fall. According to the Empirical Rule, for a normally distributed data set:

- Approximately 68% of the data falls within one standard deviation of the mean.

- Approximately 95% of the data falls within two standard deviations of the mean.

- Approximately 99.7% of the data falls within three standard deviations of the mean.

Since the average height of NBA point guards is 74.6 inches with a standard deviation of 3.71 inches, we can use this information to calculate the range:

Mean ± (2 * Standard Deviation)

74.6 ± (2 * 3.71)

The lower bound of the range would be:

74.6 - (2 * 3.71) = 74.6 - 7.42 = 67.18 inches

The upper bound of the range would be:

74.6 + (2 * 3.71) = 74.6 + 7.42 = 82.02 inches

Therefore, using the Empirical Rule, we can say that 95% of NBA point guards are between approximately 67.18 inches and 82.02 inches tall.

b. In order to use the Empirical Rule, we assume that the histogram of NBA point guards' average heights is shaped like a normal distribution (bell-shaped). This means that the data is symmetrically distributed around the mean, with the majority of values clustering near the mean and fewer values appearing further away from the mean.

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Answer:Section 6.1

Solutions and Hints

by Brent M. Dingle

for the book:

Precalculus, Mathematics for Calculus 4

th Edition

by James Stewart, Lothar Redlin and Saleem Watson.

If you remember nothing else from this section remember:

arc length = radius * angle

s = r * q

where the angle, q, is measured in radians.

There are other formulas, but that one is pretty important.

48. A circular arc of length 3 feet subtends a central angle of 25.

Find the radius of the circle.

Start with s = r*q , s = 3 feet, q = 25 = 25*(p/180) = (5/36)p radians

3 = r * (5/36)p Å 3*(36/5) = r*p Å 21.6 = p*r Å r = 21.6/p feet

52. Memphis, Tennessee and New Orleans Louisiana lie approximately on

the same meridian. Memphis has latitude 35 N and New Orleans 30 N.

Find the distance between the cities, given the radius of the earth is

3960 miles.

Again start with s = r*q,

with r = 3960 miles and q = 35 – 30 = 5 = 5*(p/180) = (1/36)p.

and we need to find s = arc length = distance between the cities.

s = 3960*(1/36)p = 110p miles.

60. A sector of a circle of radius 24 miles has an area of 288 square miles.

Find the central angle of the sector.

For this you need a new formula.

The area of a sector of circle = A = ½*r

2

*q ,

where q is the central angle of the sector measured in radians

and r of course is the radius of the circle.

For this problem r = 24 miles, A = 288 sq. miles and we need to find q.

288 = (½)*24

2

*q Å 288 = 288*q Å 1 radian = q (or about 57.3)

62. Three circles with radii 1, 2 and 3 feet are externally tangent to one

another. Find the area of the sector of the circle of radius 1 that is

cut off by the line segments joining the center of that circle to the

centers of the other two circles.

So you start out with:

Notice you know the length of ALL the sides of the triangle, because you know

the radius of each circle. From this you might discern that: 5

2

= 3

2

+ 4

2

. Thus you

have the (length of the hypotenuse)

2

= (length of side A)

2

+ (length of side B)

2

.

And from that you may conclude the triangle is a right triangle, or rather the angle

we are interested in is 90. Thus we use the area formula given in the text:

The area of a sector of circle = A = ½*r

2

*q ,

For this problem r = 1 foot, q = 90 = p/2, and we need to find A

A = ½ * 1

2

* p/2 = p/4 square feet.

Step-by-step explanation:

The linear speed of a point on the equator in miles per hour is 1037 mph. Therefore, option D is the correct answer.

Given that, the radius of the earth is approximately 3960 miles.

Linear speed is the measure of the concrete distance travelled by a moving object. The speed with which an object moves in the linear path is termed linear speed. In easy words, it is the distance covered for a linear path in the given time. Linear Speed Formula is articulated as s=rθ/t.

Any point in the equator would complete a 360° or 2π, revolution in 24 hours. Therefore, the linear speed would be s=rθ/t.

where r is the radius of the Earth and θ is the angular distance (in rad) after time t

Hence, the linear speed would be

s= (3960×2π)/24

= (3960×2×3.14)/24

= 24868.8/24

= 1036.7

≈1037 mph

The linear speed of a point on the equator in miles per hour is 1037 mph. Therefore, option D is the correct answer.

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(a) The real discrete Fourier transform (DFT) is calculated for the given data set to analyze the helicopter's acoustic signature.

(b) To obtain the ck values and illustrate the relative size of each term in the Fourier series, we calculate the magnitude of each coefficient and plot their amplitudes on a bar graph against the corresponding frequency component, k.

To analyze the helicopter's acoustic signature, the real DFT is computed for the provided data set. The DFT transforms the time-domain measurements of acoustic pressure into the frequency domain, revealing the different frequencies present and their corresponding amplitudes. This analysis helps in understanding the spectral characteristics of the helicopter's acoustic signature and identifying prominent frequency components.

Using the Fourier series representation, the amplitudes (ck's) of the different frequency components in the Fourier series are determined. These amplitudes represent the relative sizes of each term in the series, indicating the contribution of each frequency component to the overall acoustic signature. By plotting the amplitudes on a bar graph, the relative strengths of different frequency components become visually apparent, enabling a clear comparison of their importance in characterizing the helicopter's acoustic signature.

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The value of c = 4.28 cm and the value of d = 30.3 cm

Consider the big triangle

The hypotenuse of the triangle = 39 cm

The base of the triangle = 25 cm

The vertical side = 7c

According to Pythagorean theorem

The square of the hypotenuse is equal to the sum of the square of the base and the square of the vertical side

\(39^2=25^2+(7c)^2\)

1521 = 625 + \(49c^2\)

\(49c^2\) = 1521 - 625

\(49c^2\) = 896

\(c^2\) = 896 / 49

\(c^2\) = 128/7

c = 4.28 cm

Consider the small triangle

The vertical side = 4c

= 4 × 4.28

= 17.12 cm

\(d^2=25^2+17.12^2\)

\(d^2\) = 625 + 293.09

\(d^2\) = 918.09

d = 30.3 cm

Hence, the value of c = 4.28 cm and the value of d = 30.3 cm

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Answer:

39.125%

Step-by-step explanation:

Answer:

313/8

Step-by-step explanation:

(313 ÷ 800) x 100 = \(\frac{313 \times 100}{800} =\frac{31300}{800} =\frac{313}{8}\) %

If Jarvis picks a point Y on XZ ;  point W on XV such that WY is parallel to VZ , if XY = 2,938 feet, WY = 1,469 feet, and XZ = 8,814 feet then the distance across the lake is 4407 feet .

Jarvis needs to find the distance across lake ;

Jarvis picks a point Y on XZ , and a point W on XV such that WY is parallel to VZ .

also given that XY = 2,938 feet, WY = 1,469 feet, and XZ = 8,814 feet .

let the distance across the lake be = ZV ;

From the above data the two similar triangles formed are drawn below ;

From the figure :

The triangle XYW is similar to triangle XZV ;

that means , WY/ZV = XY/XZ ;

substituting the values of  XY = 2,938 feet, WY = 1,469 feet, XZ = 8,814 feet;

we get ;

⇒ 1469/ZV = 2938/8814 ;

⇒ ZV = 1469/(2938/8814)  ;

On further simplifying ,

we get ;

ZV = 4407 .

Therefore , the distance across the lake is 4407 feet .

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Answer:

x=-3

Step-by-step explanation:

Answer: The radius is 8 inches

Step-by-step explanation:

The formula for the area of a circle is \(\pi r^2=A\)

Where

A is the area (200.96 for this)

\(\pi\) is pi (we'll round it to 3.14 for this)

and r is the radius

Let's sub in our values and solve for r

\(3.14r^2=200.96\)

Divide both sides by 3.14 to isolate \(r^2\)

\(\frac{3.14r^2}{3.14} =\frac{200.96}{3.14} \\\\r^2=64\)

Take the square root of both sides to cancel the square

\(r^2=64\\\sqrt{r^2} =\sqrt{64} \\r=8\)

The extreme points of the region are (0, 0, 5), (0, 3, 0), (2, 0, 3), (5, 0, 0). To find the extreme points, we need to set each variable to its maximum or minimum value while satisfying all the given constraints.

Step 1: To find the extreme points, we need to set each variable to its maximum or minimum value while satisfying all the given constraints.

Step 2: From the first constraint, X3 can take a maximum value of 5.

Step 3: From the second constraint, X2 can take a maximum value of 3.

Step 4: From the third constraint, X1 can take a maximum value of 5.

Step 5: Therefore, the extreme points of the region are (0, 0, 5), (0, 3, 0), (2, 0, 3), (5, 0, 0).

The extreme points of the region are (0, 0, 5), (0, 3, 0), (2, 0, 3), (5, 0, 0).

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Answer:

Step-by-step explanation:

3x+4y=38

The correct choice is the sequence is not monotonic. The sequence is bounded. The sequence converges, and the limit is -2 (option c).

The given sequence (-2) does not vary with the index n, as it is a constant sequence. Therefore, the sequence is both monotonic and bounded.

Since the sequence is bounded and monotonic (in this case, it is non-decreasing), we can conclude that the sequence converges.

The limit of a constant sequence is equal to the constant value itself. In this case, the limit of the sequence (-2) is -2.

Therefore, the correct choice is:

OC. The sequence is not monotonic. The sequence is bounded. The sequence converges, and the limit is -2.

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The limit of the sequence is -2.

Given sequence is ((-2)}

To find the limit of the given sequence, we have to use the following formula:

Lim n→∞ anwhere a_n is the nth term of the sequence.

So, here a_n = -2 for all n.

Now,Lim n→∞ a_n= Lim n→∞ (-2)= -2

Therefore, the limit of the given sequence is -2.

Also, the sequence is not monotonic. But the sequence is bounded.

So, the correct choice is:

The sequence is not monotonic.

The sequence is bounded.

The sequence converges, and the limit is -2.

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Answer:

swimmer b swims 100 yards. approximately how many more feet did swimmer a swim than swimmer b? 2.

Step-by-step explanation:

Answer:

\(2( {x + 7})^{2} + 5\)

Step-by-step explanation:

Our Standard form for each of these transformations is

\(a( {x + h)}^{2} + k\)

Insert each value into the appropriate.

K is for vertical movement

h is for horizontal

a is for stretching/compression

After factorising the given expression we have the factors:

a) = 3(x + 4m)

b) = 6h(h + 3a)

Expanding brackets in reverse is a process known as factorising. Fully factorising an expression entails putting it in brackets by eliminating the factors with the highest common denominator.

The easiest method of factoring is:

Factorisation:

a) 3x+12m

= 3(x + 4m)

b) 6h²+18ah​

6h(h + 3a)

Thus, After factorising the given expression we have the factors:

a) = 3(x + 4m)

b) = 6h(h + 3a)

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To find the percentage of your classmates in favor of increasing tuition fees by $50 to implement new security measures, you need to know the number of classmates in favor (p) and the total number of students who answered the question (n).

The formula to calculate the percentage is: (p/n) * 100.
To calculate the percentage, divide the number of classmates in favor (p) by the total number of students who answered the question (n). Multiply the result by 100 to get the percentage. To calculate the percentage of your classmates in favor of increasing tuition fees by $50, you need to know the number of classmates in favor (p) and the total number of students who answered the question (n). Once you have these values, you can use the formula (p/n) * 100 to find the percentage. For example, if 20 out of 50 students are in favor of the fee increase, the percentage would be (20/50) * 100 = 40%. This means that 40% of the students who answered the question are in favor of the fee increase.

To find the percentage of your classmates in favor of increasing tuition fees by $50, divide the number of classmates in favor by the total number of students who answered the question and multiply by 100. This will give you the percentage.

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Answer: 6x^2+3x

Step-by-step explanation:

The measure of angle a is:

a = (140° - 96°) / 2 = 44° / 2 = 22°

Therefore, the answer is 22.

1

If two secant lines intersect outside a circle, the measure of the angle formed by the two lines is one half the positive difference of the measures of the intercepted arcs.

In the given diagram, we can see that the intercepted arcs are 96° and 140°. Therefore, the measure of angle a is:

a = (140° - 96°) / 2 = 44° / 2 = 22°

Therefore, the answer is 22.

Answer: 22

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Answers: 0.5 + 0.83 and 1.33 have equal values

I hope this helps, and Happy Holidays! :)

The Probability that the student will arranged in order from shortest to tallest is 2.505210.

Probability is a branch of math which deals with the numerical description of certain events is to occur. It is the ratio of the numbers of favorable outcomes to the total number of outcomes. When solving probability problems we need to consider series of random experiments or experiments that involve several different aspects, such as drawing two cards from a deck or rolling several dice. the ability to calculate relative frequencies requires counting the number of possible outcomes of the experiment

If a class has 11 students who are to be randomly assigned seating in the order of shortest to tallest.

The total outcomes= 11! = 39916800

here the total favorable outcome is 1.so,

Probability = 1 / 39916800

                   = 2.505210

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