Karen was cutting out some fabric for a friend. She cut a piece that was 6 centimeters wide and had an area of 36 square cm. How long was the piece?

Answer:

\(\boxed{\mathtt{Area \approx 227ft^{2}}}\)

Step-by-step explanation:

\(\textsf{We are asked to find the area of a circle.}\)

\(\textsf{First, we should identify the formula for the area of a circle.}\)

\(\large\underline{\textsf{Formula:}}\)

\(\mathtt{Area = \pi (radius)^{2}}\)

\(\textsf{The radius is \underline{half} of the diameter.}\)

\(\mathtt{\frac{17}{2} = 8.5ft.}\)

\(\textsf{Let's begin solving for the area.}\)

\(\large\underline{\textsf{Substitute:}}\)

\(\mathtt{Area = \pi (8.5)^{2}}\)

\(\mathtt{Area = 72.25 \pi}\)

\(\boxed{\mathtt{Area \approx 227ft^{2}}}\)

Answer: the probability of being offered both jobs is 0.05, or 5%

Step-by-step explanation:

To solve this problem, we can use the formula:

P(A or B) = P(A) + P(B) - P(A and B)

where P(A or B) is the probability of getting at least one job offer, P(A) is the probability of getting an offer for job A, P(B) is the probability of getting an offer for job B, and P(A and B) is the probability of getting an offer for both jobs.

Substituting the given values, we get:

0.40 = 0.25 + 0.20 - P(A and B)

Solving for P(A and B), we get:

P(A and B) = 0.25 + 0.20 - 0.40 = 0.05

Therefore, the probability of being offered both jobs is 0.05, or 5% (rounded to two decimal places).

the option that represents a socket is c.) "192.168.1.1:80".

A socket is typically represented by a combination of an IP address and a port number.

In the given options:

a.) "01-23-45-67-89-AB" does not represent a valid socket as it is in a MAC address format, not an IP address and port number format.

b.) "21" alone does not represent a valid socket as it is only a single number without an IP address or port number.

c.) "192.168.1.1:80" represents a valid socket as it consists of an IP address ("192.168.1.1") and a port number (":80").

d.) "10.1.1.15" alone does not represent a complete socket as it only contains an IP address without a port number.

Therefore, the option that represents a socket is c.) "192.168.1.1:80".

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The diameter of the circular base of Carlos's cylindrical plastic cup is 5 cm.

To find the diameter of the circular base of Carlos's cylindrical plastic cup, we first need to calculate the radius of the base. Since we know that the volume of the cup is 200 mL and the height is 7 cm, we can use the formula for the volume of a cylinder to find the radius.
The formula for the volume of a cylinder is V = πr^2h, where V is the volume, r is the radius, and h is the height. Rearranging the formula to solve for r, we get r = √(V/πh).
Substituting the given values, we get r = √(200/π*7) ≈ 2.46 cm.
Since the diameter is twice the radius, the diameter of the circular base is approximately 4.92 cm. However, the question asks for the answer to the nearest centimeter, so we round up to get a diameter of 5 cm.
Therefore, the diameter of the circular base of Carlos's cylindrical plastic cup is 5 cm.

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The value of x if the triangle is equilateral is x = -16 and  x = -10

An equilateral triangle is a regular polygon with all three sides of equal length.  It is also equiangular, meaning that all three internal angles are congruent to each other and are each 60 degrees

If the triangle is equilateral therefore

5x + 16 = 4x and 5x + 16 = 3x - 4

5x -4x = -16

x = -16

Also, in equation 2

Also, 5x -  3x =-4 -16

2x = -20

therefore,

x = -10

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We are asked to simply the following polynomial

Let us find the product of the above polynomial and simplify it

Therefore, the simplified polynomial is

The degree of a polynomial is the highest exponent (power)

For the given case, the highest exponent is 2

Therefore, the degree

The interest rate she got from the bank is 0.83% and the monthly repayment she needs to make is 99.6 dollars.

What is simple interest?

Simple interest is, by definition, the amount of interest paid on a specific principal sum of money when an interest rate is applied. Compound interest, on the other hand, is the interest that is computed using both the principal and the interest that has accumulated over the preceding period.

What kinds of simple interests are there?

When the time is measured in days, simple interest can be divided into two groups. They have common and straightforward interests. The comparable number of days in a year for ordinary simple interest is 360 days. In contrast, precise simple interest (SI) is a SI that requires exactly 365 days in a regular year or 366 days in a leap year.

The simple interest is given by the formula:

SI = PRT/ 100

where, P is the principal = $4999 - $999 = $4000.

R is the rate.

T is the time = 3.

Given that the total accumulated amount is $7000.

That is:

4000 + SI(3) = 7000....(1)

SI = (4000)(R)(3)/100

SI = 120R.......(2)

Substitute the value of SI in equation 1:

4000 + 120(3)R = 7000

36R = 3000

R = 83.33

R = 0.83%

The monthly repayments are:

SI = (4000)(0.83)(3)/100

SI = 99.6

Hence, the monthly payments are 99.6.

The interest rate she got from the bank is 0.83% and the monthly repayment she needs to make is 99.6 dollars.

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Answer:

Given: Two Isosceles triangle ABC and Δ PBC having same base BC. AD is the median of Δ ABC and PD is the median of Δ PBC.

To prove: Point A,D,P are collinear.

Proof:

→Case 1.  When vertices A and P are opposite side of Base BC.

In Δ ABD and Δ ACD

AB= AC   [Given]

AD is common.

BD=DC  [median of a triangle divides the side in two equal parts]

Δ ABD ≅Δ ACD [SSS]

∠1=∠2 [CPCT].........................(1)

Similarly, Δ PBD ≅ Δ PCD [By SSS]

∠ 3 = ∠4 [CPCT].................(2)

But,  ∠1+∠2+ ∠ 3 + ∠4 =360° [At a point angle formed is 360°]

2 ∠2 + 2∠ 4=360° [using (1) and (2)]

∠2 + ∠ 4=180°

But ,∠2 and ∠ 4 forms a linear pair i.e Point D is common point of intersection of median AD and PD of ΔABC and ΔPBC respectively.

So, point A, D, P lies on a line.

CASE 2.

When ΔABC and ΔPBC lie on same side of Base BC.

In ΔPBD and ΔPCD

PB=PC[given]

PD is common.

BD =DC [Median of a triangle divides the side in two equal parts]

ΔPBD ≅ ΔPCD  [SSS]

∠PDB=∠PDC [CPCT]

Similarly, By proving ΔADB≅ΔADC we will get,  ∠ADB=∠ADC[CPCT]

As PD and AD are medians to same base BC of ΔPBC and ΔABC.

∴ P,A,D lie on a line i.e they are collinear.

Function notation is a way of representing mathematical functions using symbols. In function notation, a function is represented by a single letter, such as "f" or "g," followed by a set of input values in parentheses. For example, f(x) represents a function of x, where the value of f for a given x can be found by evaluating the function.

Function notation is commonly used in mathematics to simplify expressions and make it easier to understand mathematical relationships between variables.

The following function notations represent the following given conditions:

a) N(5) represents the population of Miami 5 years after 1990.

b) N(9) represents the population of Miami 9 years after 1990, or in the year 1999.

c) N(1997) + 45,000 represents the population of Miami which is 45,000 more than the population in 1997.

d) N(1990 + k) represents the population of Miami k years after 1990.

e) N(1998) - N(1995) represents the change in the population of Miami from 1995 to 1998.

f) N(11) - N(7) represents the change in the population of Miami from 7 years after 1990 to 11 years after 1990.

g) N(2008) = 431,200 represents the population of Miami in 2008 as being 431,200.

h) The solution of the equation N(t) = 412,000 represents the year (or years) when the population of Miami was 412,000.

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Answer: 52.94

Step-by-step explanation:

Length of train A = 480m

Tunnel length = 1320m

Time taken to cross tunnel = 2 mins = 120sec

Length of train B = 420m

Train B is slower than train A

Difference between their speed = 18km/hr

18km/hr = (18×1000)/3600 = 5m/s

Speed of train A :

Speed = distance / time

Speed = 1320 / 120 = 11m/s

Therefore, speed of train B :

(11 - 5)m/s = 6m/s

Relative speed of the two trains is therefore;

(Speed of A + speed of B)

Note : they are moving in opposite direction

( 11 + 6)m/s = 17m/s

Therefore time taken to cross each other :

(Sum of the length of both trains / relative speed of the trains)

Time taken = (480m + 420m) / (17m/s)

Time taken = 900m / 17m/s

Time taken = 52.94s

Answer:

She can type 6,225 words in 1 hour and 23 minutes

Step-by-step explanation:

1 hour = 60 minutes so you convert the hour into minutes and add 60 + 23 to get 83. From here you just multiply 75 (words per minute) and 83 (amount of minutes) and you get 6,225

Answer:

7

Step-by-step explanation:

42/6=7

Standard error of the mean is 0.05267 in (a). The actual mean degradation rate has a 90% probability of being between 0.978 and 1.174 micromoles/minute/gram, according to (b).

The group mean's likelihood to vary from a sampling distribution is indicated by the standard deviation of a mean, or merely standard error. It reveals how much is the sample imply would change if a research were to be repeated with fresh samples drawn from a particular population.

(a)

Sample size, n = 9

Sample standard deviation, S = 0.158

Standard error of the mean,

\(\sigma_{\bar{x}}=\frac{S}{\sqrt{n}}=\frac{0.158}{\sqrt{9}}=0.05267\)

(b)

Since we do not know the distribution of the parent population or the population standard deviation, and further the sample size, n = 8 < 30,

Therefore we will use the t-distribution to construct the confidence interval for the true population mean α

Sample size, n = 9

Sample mean, r  = 1.076

Sample standard deviation, S = 0.158

Standard error of the mean,

\(\sigma_{\bar{x}}=\frac{S}{\sqrt{n}}=\frac{0.158}{\sqrt{9}}=0.05267\)

Level of confidence, c (in percentage) = 90

α = (1-(c/100) = 0.1

Degrees of freedom, df = n-1 = 9 - 1 = 8

The critical t-score, \(\mathrm{t}_{\mathrm{c}}\) is the

t-score corresponds to the given level of confidence and degrees of freedom :

\(\begin{aligned}& P\left(x > t_{d f}\right)=\Rightarrow / 2 \\& \Rightarrow \\& P\left(x > t_8\right)=0.1 / 2=0.05 \\& \Rightarrow t_c=1.86\end{aligned}\)

The confidence interval is calculated as:

\(\mathrm{Cl}=\bar{x} \pm\left(\mathrm{t}_{\mathrm{c}}\right)^*\left(\sigma_{\bar{x}}\right)\)

= 1.076 ± (1.86)*(0.05267)

= 1.076±  0.098

= (1.076 - 0.098, 1.076 + 0.098)

= (0.978, 1.174)

The actual mean degradation rate has a 90% probability of being between 0.978 and 1.174 micromoles/minute/gram, according to this information.

The mean degradation rate must be higher than 1 for the process to be cost-effective.

However, because the 90% confidence interval does not completely fall above 1, the experts cannot be certain that the process will be cost-effective.

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Answer:

6.2

Step-by-step explanation: TOOK THE TEST

The given expression \(m^6p^{-3}v^{10} .\ m^2p^5v^2\) for all values of m, p, and v is equivalent to \(m^{8}p^{2}v^{12}\). Therefore, option D is the right choice for this question.

Monomials are algebraic expressions with single terms. They can be said to be specialized cases of polynomials.

We are given the algebraic expression - \(m^6p^{-3}v^{10}\) . \(m^2p^5v^2\)

To simplify it we will use the rules of the indices as follows -

\(a^{m}.\ a^{n} = a^{m+n}\)

Now,

\(m^6p^{-3}v^{10}\) . \(m^2p^5v^2\)

Segregating the like variables, we get,

= \((m^6.\ m^2) .\ (p^{-3}.\ p^{5}) .\ (v^{10}.\ v^{2})\)

by using the rules of indices, we will get,

= \((m^{6+2}) .\ (p^{-3+5}) .\ (v^{10+2})\)

= \((m^{8}) .\ (p^{2}) .\ (v^{12})\)

= \(m^{8}p^{2}v^{12}\)

Hence, the given expression \(m^6p^{-3}v^{10} .\ m^2p^5v^2\) is equivalent to \(m^{8}p^{2}v^{12}\).

Therefore, option D is the right choice for this question.

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We are asked to determine the maximum value of "x" for a profit function given the functions of revenue and cost. To do that let's remember that profit is defined as:

Let P(x) be the function of profit, then the difference between the functions of revenue and cost is the function of profit, therefore:

Replacing the functions we get:

Now we apply the distributive property in the parenthesis:

Adding like terms:

Now, to determine the maximum profit we will determine the derivative of the profit function with respect to "x":

Now we distribute the derivative on the left side:

Now we determine the derivative using each corresponding rule:

Now we set the result to zero:

Now we solve for "x" first by subtracting 48 from both sides:

Now we divide both sides by -6:

Now, since the original function is a parabola that opens downwards, this point must be a maximum. To verify that we can determine the second derivative and we get:

Since the second derivative is smaller than zero, the point is a maximum as hypothesized. Therefore, the maximum value of "x" is 8.

Answer:0.22

Step-by-step explanation:

Answer:$0.22

Step-by-step explanation:

EDGE

Answer:

14x-2

Step-by-step explanation:

In order to find the perimeter we need to add the length and width together. So adding 5x and 9x gives us 14x. -4+2=-2

The perimeter of a rectangle with a length of 9x - 4 and a width of 5x+2 is, 28x-4

Perimeter is a mathematical term, which means total outer boundary of a figure, we define it only for two dimensional figures.

Perimeter = Sum of length of the all the sides

Given that,

length of rectangle = 9x - 4

width of  rectangle =  5x+2

As we know,

Perimeter = Sum of length of the all the sides

Perimeter =  (9x - 4) + (5x+2) + (5x+2) + (9x - 4)  

Perimeter =  28x-4

Hence, The perimeter is  28x-4

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Answer:

88 people

Step-by-step explanation:

Start with the equation of

\(3,000\geq 33x+80\)

subtract 80

\(3.000\geq 33x\)

then divide by 33

\(88.48\geq x\)

round down

\(x=88\)

Answer:

1695.6

Step-by-step explanation:

Hamiltonian due to interaction of spin magnetic field:

H = -u.B

H = α/√2\(\left[\begin{array}{ccc}1&1\\1&-1\\\end{array}\right]\)

What is a matrix?

In mathematics, a matrix (multiple matrices) is a rectangular array or table of numbers, symbols, or expressions, arranged in rows and columns, and used to represent mathematical objects or properties of such objects. The

matrix represents a linear mapping without additional information and allows explicit computation in linear algebra. The study of matrices is therefore a large part of linear algebra, and most properties and operations in abstract linear algebra can be expressed in matrices. For example, matrix multiplication represents the construction of linear maps.

Not all matrices are related to linear algebra. This is especially true for graph theory, occurrence matrices, and adjacency matrices. This article focuses on matrices in the context of linear algebra. Unless otherwise stated, all matrices either represent linear maps or can be considered linear maps.

Square matrices (matrices with the same number of rows and columns) play an important role in matrix theory. Square matrices of a given dimension form non-commutative rings, one of the most common examples of non-commutative rings. The determinant of a square matrix is ​​the numerical value associated with the matrix that underlies the study of square matrices. For example, a square matrix has nonzero determinant and is invertible only if the eigenvalues ​​of the square matrix are the roots of the polynomial determinant.

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The equation of a plane in three-dimensional space can be written in the form Ax + By + Cz = D, where A, B, and C are the coefficients of the variables x, y, and z, respectively, and D is a constant.

To find the equation of the plane p containing the point P(1,2,2) and with normal vector (-1,2,0), we can substitute these values into the general equation and solve for D.

First, we can substitute the coordinates of the point P into the equation: (-1)(1) + (2)(2) + (0)(2) = D. Simplifying this equation gives us:-1 + 4 + 0 = D,3 = D.Therefore, the constant D is 3. Substituting this value back into the general equation, we have: (-1)x + (2)y + (0)z = 3, -x + 2y = 3. Thus, the equation of the plane p containing the point P(1,2,2) and with normal vector (-1,2,0) is -x + 2y = 3.

In conclusion, by substituting the given point and normal vector into the general equation of a plane, we determined that the equation of the plane p is -x + 2y = 3. This equation represents the plane that passes through the point P(1,2,2) and has the given normal vector (-1,2,0). The coefficients of x and y are on the left-hand side, while the constant term 3 is on the right-hand side of the equation.

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Answer:

I think it's 6 or 0.6

Answer:

B= 2

Step-by-step explanation:

Answer:

The value of x=27

Step-by-step explanation:

Answer:

∠S = 105°

∠T = 95°

Step-by-step explanation:

Cyclic quadrilateral:

   Quadrilateral MNST is a cyclic quadrilateral. In cyclic quadrilateral, the opposite angles are supplementary.

     m∠S + m∠M = 180°

 3x + 2x +  5 = 180

        5x  + 5  = 180           {Combine like terms}

                 5x = 180 - 5     {Subtract 5 from both sides}

                 5x = 175

                    x = 175 ÷ 5  {Divide both sides by 5}

                    x = 35°

∠S = 3x

    = 3 * 35

    = 105°

∠T = 3x - 10

     = (3*35) - 10

     = 105 - 10

     = 95°

Answer:

Step-by-step explanation:

Amount of money earned by John for each shift he works at the bookstore is represented by the function,

f(h) = 10h

Where f(h) = Amount of money earned in dollars

h = number of hours worked by John

1). For h = 1 hour

   f(1) = 10 × 1

        = $10

2). For h = 2.5 hours

   f(4.5) = 10 × 4.5

            = $45

3). For h = 10 hours

   f(10) = 10 × 10

           = $100

The set of real numbers includes both rational and irrational numbers.


1. Real numbers: Real numbers include all rational and irrational numbers. They can be represented on a number line and are not limited to whole numbers or integers.

2. Rational numbers: Rational numbers are numbers that can be expressed as a fraction or a ratio of two integers. They can be written in the form a/b, where a and b are integers and b is not equal to 0. For example, 3/4, -2/5, and 0.6 are all rational numbers.

3. Irrational numbers: Irrational numbers are numbers that cannot be expressed as a fraction or a ratio of two integers. They cannot be written in the form a/b. Examples of irrational numbers include √2, π (pi), and e.

Therefore, the set of real numbers includes both rational and irrational numbers.

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The equilibrium price is $0 and the equilibrium quantity is 5 units.

To find the equilibrium price and quantity, we need to set the quantity demanded equal to the quantity supplied and solve for the equilibrium values.

Setting Q_d = Q_s, we can equate the equations for demand and supply:

-2Q - 2Q_d = -5 + 3Q_s

Since we know that Q_d = Q_s, we can substitute Q_s for Q_d:

-2Q - 2Q_s = -5 + 3Q_s

Now, let's solve for Q_s:

-2Q - 2Q_s = -5 + 3Q_s

Combine like terms:

-2Q - 2Q_s = 3Q_s - 5

Add 2Q_s to both sides:

-2Q = 5Q_s - 5

Add 2Q to both sides:

5Q_s - 2Q = 5

Factor out Q_s:

Q_s(5 - 2) = 5

Q_s(3) = 5

Q_s = 5/3

Now that we have the value for Q_s, we can substitute it back into either the demand or supply equation to find the equilibrium price. Let's use the supply equation:

P = -5 + 3Q_s

P = -5 + 3(5/3)

P = -5 + 5

P = 0

Therefore, the equilibrium price is $0 and the equilibrium quantity is 5 units.

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