Answer:
\(kinetic \: energy = \frac{1}{2} m {v}^{2} \\ m = mass \: of \: the \: object \\ v = velocity \: \)
Help my brain ain’t braining
The arrows are drawn in the figure which shows gravitational forces on each person on earth.
Gravitational force is force of attraction between two masses. Gravitational force(F) between two bodies is directly proportion to the product of masses(m₁,m₂) of two bodies and inversely proportional to square of distance(r) between them. mathematically it is written as,
F∝ m₁.m₂
F ∝ 1/r²
F = G m₁,m₂÷r²
where G is gravitational constant, whose value is 6.6743 × 10⁻¹¹ m³ kg-1s⁻².
Force is expressed in Newton N in SI unit. its dimensions are [M¹L¹T⁻²].
This is analogous with coulomb's law which gives force between two charges.
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Find the moment of 300N force about B
Answer:
300
Explanation Hope I'm not wrong.
A car accelerates from rest (v. 0 m/s) with a constant acceleration of
a = 5m/s2 for 12 seconds. What is the final speed of the car after the
12 seconds?
Heya!!
For calculate final velocity, lets applicate formula
\(\boxed{V=V_o+a*t}\)
Δ Being Δ
V = Final Velocity = ?
Vo = Initial velocity = 0 m/s
a = Aceleration = 5 m/s²
t = Time = 12 s
⇒ Let's replace according the formula:
\(\boxed{V=0\ m/s +5\ m/s*12\ s}\)
⇒ Resolving
\(\boxed{V=60\ m/s}\)
Result:
The velocity after 10 sec is 60 meters per second (m/s)
Good Luck!!
A sample of gas is enclosed in a container of fixed volume. Identify which of the following statements are true. Check all that apply.If the container is heated, the gas particles will lose kinetic energy and temperature will increase.
Answer:
B. If the container is cooled, the gas particles will lose kinetic energy and temperature will decrease.
C. If the gas particles move more quickly, they will collide more frequently with the walls of the container and pressure will increase.
E. If the gas particles move more quickly, they will collide with the walls of the container more often and with more force, and pressure will increase.
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I would like to ask for help in understanding on what basis the universe is considered to be expanding? As far as I understand, it is only an idea (hypothesis, theory) and not a scientific fact as the media presents it. Given that we on Earth receive evidence of various radiations from the past, we cannot say with certainty that the Universe is still expanding. Let's say the Universe stopped expanding 4 billion years ago and started contracting, would the results of all our observations be the same as they are or not?
Expansion of universe is not a hypothetical one but the universe is expanding in the sense increase distance over the space and dark matter.
What is universal expansion?The increase in distance over time between any two particular gravitationally unbound regions of the observable universe is known as the universe's expansion.
As a result, the size of space itself expands intrinsically. It is not necessary for space to exist outside of the cosmos or for it to extend into anything.
The metric changes in scale rather than space or the things in space moving in the conventional sense. Objects move farther apart from one another at ever-increasing speeds as the spatial component of the universe's spacetime metric scales up.
Any viewer in the cosmos would see that all of space appears to be expanding, except for the galaxies receding with a speed proportional to the distance from the observer.
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Why is the size of a telescope's lens or mirror important for gathering information about distant objects?A. Because magnification is better with smaller lenses.B. Because big telescopes are hard to manage.C. Because the goal is to gather as much electromagnetic radiation as possible.
Given:
The size of the telescope's lens or mirror is important for gathering information about distant objects.
To find:
The reason
Explanation:
The telescope's lenses or the mirrors gather light and we are able to see the things that are really far away. The more big the size of the lens or the mirror, the more light they can gather.
Hence, gathering as much electromagnetic radiation as possible is the correct option.
a sports car has a mass of 1300kg.Starting from the rest the car generates a force of 4400 N.The frictional force opposing this motion is 280 N.What is the car’s acceleration
since the car moves, the force needed to move is greater than the frictional forces opposing it
a = 3.17m/s²
The acceleration of the car with a mass of 1300 kg which starts from rest generating a force of 4400 N and having a frictional force of 280 N is 3.17 m/s²
We'll begin by calculating the net force acting on the car. This can be obtained as follow:Force (F) = 4400 N
Frictional force (Fբ) = 280 N
Net force (Fₙ) =?Fₙ = F – Fբ
Fₙ = 4400 – 280
Fₙ = 4120 NThus, the net force acting on the car is 4120 N
Finally, we shall determine the acceleration of the car. This can be obtained as follow:Mass (m) = 1300 Kg
Net force (F) = 4120 N
Acceleration (a) =?Force = Mass × Acceleration
4120 = 1300 × a
Divide both side by 1300
\(a = \frac{4120}{1300}\\\\\)
a = 3.17 m/s²Therefore, the acceleration of the car is 3.17 m/s².
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URGENT HELP!
How is it that two moving objects can have a net momentum of zero?
Answer:
because they may not actually be moving be just percieved as so
Explanation:
Answer:
i think that maybe there arent moving but there on something thats moving
Explanation:
The image shows a molecular model of a compound using balls and sticks. Each ball is an atom. If you were to use balls and sticks to model a molecule of an element how must your model differ from what’s shown
Element molecules consist of a single type of atom and are held together by covalent bonds. The model would have uniform-colored balls connected by sticks representing these bonds.
The image represents a molecular model of a compound. Balls represent atoms, while sticks show chemical bonds between atoms. If you are to use balls and sticks to model a molecule of an element, the model would differ from what is shown because the element is made up of one type of atom. In other words, it is a pure substance that can't bond to other atoms of the same kind. Molecules of elements are usually composed of a single element and are not formed by bonding between two or more different atoms.In contrast to compounds, atoms in an element molecule are joined by a chemical bond called a covalent bond. Furthermore, the same atom is represented by a single-colored ball as there is only one type of atom involved in the element molecule. The sticks represent covalent bonds between the atoms of the same kind in a molecule of the element.For more questions on covalent bonds
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Which of the following is the best estimate of the mass of all humans living on Earth?
he best estimate of the mass of all humans living on Earth is (d) 3 3 1011 kg
What is the estimate of the mass of all humans living on Earth?The best estimate of the mass of all humans living on Earth can be calculated by multiplying the estimated number of humans by the average mass of a human being.
According to the United Nations, the world population as of mid-2022 was around 7.92 billion. The average mass of an adult human being is approximately 62 kilograms (136.7 pounds).
Therefore, the estimated mass of all humans living on Earth is:
7.92 billion (humans) x 62 kg (average mass per human) = 4.9104 x 10^11 kg
Out of the given options, the closest estimate is (d) 3 3 10^11 kg.
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(a) 2 3 108 kg (b) 1 3 109 kg (c) 2 3 1010 kg (d) 3 3 1011 kg (e) 4 3 1012 kg
Question 1
In basketball, how many points is a free throw worth?
A. Zero a free throw determines possession only
B. One
C. Two
D. Three
Three boxes are stacked on top of a cart. As the cart is moving, it comes to an abrupt stop. The boxes fall forward off of the cart. Explain why the boxes fell forward.
The weight of an object can be determined by multiplying the mass of the object by which of the following?
A the object's velocity
B the object's size
C the object's change in speed
D the object's acceleration due to gravity
Answer:
A, the objects velocity
Explanation:
a 40 kg object is sliding on a surface accelerating to the right. force of friction is 20N, the applied force is 100N. draw and label all forces. what is the acceleration?
When the pressure (100 N) and weight (40 kg) are entered into the appropriate fields, the gravity is 2 m/s².
What is the acceleration force?Force and acceleration are linked by the equation F=ma. The characters "F," "m," and "a" stand for acceleration, mass, and force, respectively. Force is the ability of one object to exert a pull or force on another. Acceleration is the rate at which an object's speed changes.
Describe acceleration in detail.Speed increase is the pace of progress of speed. Acceleration typically indicates a change in speed, but not always. Because its velocity is changing in the opposite direction, even if an object moves in a circle at the same speed, it will still accelerate.
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When a radio is playing in the room next door, which sound waves can be heard best?
(Please it’s due by 11 p.m)
Answer:
low sound waves like bass pass through walls better
Explanation:
A 3.0 kg block is pushed 1.0 m at a constant
velocity up a vertical wall by a constant force
applied at an angle of 26.0
◦ with the horizontal, as shown in the figure.
The acceleration of gravity is 9.81 m/s
2
Drawing not to scale.
If the coefficient of kinetic friction between
the block and the wall is 0.20, find
a) the work done by the force on the block.
Answer in units of J.
b) the work done by gravity on the block.
Answer in units of J.
c) the magnitude of the normal force between
the block and the wall.
Answer in units of N.
(a) The work done by the applied force is 32.6 J.
(b) The work done by gravity on the block is 29.4 J.
(c) The magnitude of the normal force is 29.4 N.
What is the force applied to the block?The force applied to the block is determined by applying the formula for the net force on the block.
F(net) = 0
Fcosθ - mg - Fsinθμ = 0
Fcosθ - Fsinθμ = mg
F(cosθ - sinθμ) = mg
F = (mg) / (cosθ - sinθμ)
F = (3 x 9.8) / (cos26 - 0.2 x sin26)
F = 36.25 N
The work done by the applied force is calculated as;
W = Fd cosθ
W = (36.25 x 1) x cos(26)
W = 32.6 J
The work done by gravity on the block is calculated as follows;
W = mgd
W = 3 x 9.8 x 1
W = 29.4 J
The magnitude of the normal force is calculated as follows;
N = mg
N = 3 x 9.8
N = 29.4 N
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A candle is sitting in front of a concave mirror at a distance of 12.2 cm. It is found that an image of the candle appears at 25.0 cm. What is the focal length of the mirror?
Answer:
Focal length (f) = 1/2 (Object distance + Image distance)
f = 1/2 (12.2 cm + 25.0 cm)
f = 18.6 cm
A ball that is attached to a string travels in a horizontal, circular path, as shown in Figure 1. At time t0 , the ball has a speed v0 . The forces exerted on the ball at t0 are represented by the free-body diagram, as shown in Figure 2. At a later time t1 , the tangential speed of the ball is increased to 2v0 . What is the magnitude of the force that the ball exerts on the string at time t1 ?
Answer:
F₁ = 4 F₀
Explanation:
The force applied on the string by the ball attached to it, while in circular motion will be equal to the centripetal force. Therefore, at time t₀, the force on ball F₀ is given as:
F₀ = mv₀²/r --------------- equation (1)
where,
F₀ = Force on string at t₀
m = mass of ball
v₀ = speed of ball at t₀
r = radius of circular path
Now, at time t₁:
v₁ = 2v₀
F₁ = mv₁²/r
F₁ = m(2v₀)²/r
F₁ = 4 mv₀²/r
using equation (1):
F₁ = 4 F₀
7. A rock of mass 5 kg is pushed over the edge of a cliff which is 200 m high. a) Ignore air resistance and calculate the speed of the rock at the bottom of the cliff. In reality, air resistance cannot be ignored. The rock eventually reaches terminal velocity of 30 m.s-¹.
b) Calculate the kinetic energy of the rock at the bottom of the cliff.
c) Calculate the work done by air resistance.
d) Calculate the average force exerted by the air on the rock.
Speed of the rock at the bottom of the cliff is 44.3 m/s.
Kinetic energy of the rock at the bottom of the cliff is 4915 J.
Work done by air resistance is -2250 J
Average force exerted by the air on the rock is 11.25 N.
How to determine kinetic energy and speed?a) The speed of the rock at the bottom of the cliff can be calculated using the equation:
v = √(2gh)
where v = final velocity, g = acceleration due to gravity (9.81 m/s²), and h = height of the cliff (200 m).
Plugging in the values:
v = √(2 x 9.81 x 200) = 44.3 m/s
Therefore, the speed of the rock at the bottom of the cliff is 44.3 m/s.
b) The kinetic energy of the rock at the bottom of the cliff can be calculated using the equation:
KE = (1/2)mv²
where KE = kinetic energy, m = mass of the rock (5 kg), and v = velocity (44.3 m/s).
Plugging in the values:
KE = (1/2) x 5 x (44.3)² = 4915 J
Therefore, the kinetic energy of the rock at the bottom of the cliff is 4915 J.
c) The work done by air resistance can be calculated using the work-energy principle:
Work done by air resistance = KE_initial - KE_final
where KE_initial = initial kinetic energy of the rock, and KE_final = final kinetic energy of the rock (at terminal velocity).
Since the rock was initially at rest, its initial kinetic energy is zero. At terminal velocity, the kinetic energy of the rock is:
KE_final = (1/2)mv_terminal²
where m = mass of the rock (5 kg), and v_terminal = terminal velocity (30 m/s).
Plugging in the values:
KE_final = (1/2) x 5 x (30)² = 2250 J
Therefore, the work done by air resistance is:
Work done by air resistance = 0 - 2250 = -2250 J
The negative sign indicates that the work done by air resistance is in the opposite direction to the motion of the rock.
d) The average force exerted by the air on the rock can be calculated using the equation:
Work done by air resistance = Force x Distance
where Force = average force exerted by air on the rock, and Distance = distance travelled by the rock.
Rearrange the equation to solve for Force:
Force = Work done by air resistance / Distance
Plugging in the values:
Force = -2250 / 200 = -11.25 N
Therefore, the average force exerted by the air on the rock is 11.25 N. The negative sign indicates that the force is in the opposite direction to the motion of the rock.
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The spacecraft was moved closer to the launcher by the same amount Wednesday as it was on Tuesday, and yet its speed went up much more. Claim 3 suggests that the magnetic force was much stronger on Wednesday than on Tuesday.
Consider the two subclaims for Claim 3 and answer the question below.
Claim 3.A: The magnetic force was much stronger on Wednesday because the magnet was stronger.
Claim 3.B: The magnetic force was much stronger on Wednesday because the magnetic force is stronger closer to the magnets.
Which claim do you think is more convincing, and why?
Answer:
The magnetic force was much stronger on Wednesday because the magnetic force is stronger closer to the magnets.
Explanation:
The magnetic force was much stronger on Wednesday than on Tuesday because the magnetic force is stronger closer to the magnets. Therefore claim 3B is more convincing.
What is magnetic force?Magnetic force can be described as a consequence of electromagnetic force which is caused due to the motion of charges. A moving charge surrounds itself with a magnetic field and the force that arises due to interacting magnetic fields.
The magnetic force between two moving charges is the effect exerted upon either charge by a magnetic field generated by the other. The magnetic force depends on the charge, the motion of each of the objects, and the separation between them.
The magnitude of the force is determined by the cross product of velocity and the magnetic field is equal to q.[v × B]. The resultant force can be described as perpendicular to the direction of the velocity and the magnetic field.
Therefore, the magnetic force was much stronger closer to the magnets.
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HII!!! I need serious help with this assignment so I'm offering half my points so pLS accurately answer!! SO for this assignment i need to know the order it goes in conducter, battery, or light bulb, battery conducter, light bulb, (ETC...etc....)
Please tell me which order they go in! Also please tell me why it is correct ??
Answer:
Hey, I'm not sure I understand exactly what your assignment is but hopefully this helps . . .
put the other end against the side of the bubls base to light up the light bulb.
This will act as the bulbs conductor, lighting up bc you are making a complete electrical circuit between positive and negative terminals of the battery.
Ok hopefully this helps you out
Question 4 of 10
What is thermodynamics?
A. The movement of matter
B. The flow of fluids
C. The movement of particles
D. The flow of energy, heat, and work
SUBMIT
Answer:
Explanation:
D.
Thermodynamics is the study of how different types of energy is transferred through the chemical systems
Answer: Thermodynamics is the flow of energy, heat, and work.
Explanation: This is seen in the formula for the first law of thermodynamics, U = Q - W, or “The change of the internal energy of a system (U) is equal to the heat absorbed (Q) minus the work done by that system (W).”
a 0.5 kg car is moving at a constant velocity 5 m/s. What is the kinetic energy of the car?
The corect phase sequence shown
Gas, Liguid, Solid
Lqud, Gas, Solid
Sold, Liguid, Gas
Gas, Solid, Liquid
above i
Answer:
Explanation:
gas, liquid, soild
liquid, Gas, solid
Gas, Solid, liquid
tighten a nut which is pushing against a spring.the spring is exerting a force of 1000N on the nut. the screw is 30% efficiency with pitch of 0.2m. what is being exerted on the end of the spanner??
The force exerted on the end of the spanner is 333N (1000N x 0.3).
Calculation of Force exertedCalculate the torque being exerted by the spring:
We know that the Expression for Torque is given as
Torque = Force x Distance
= 1000N x 0.2m
= 200Nm
Calculate the force being exerted on the end of the spanner:
Force = Torque x Efficiency
= 200Nm x 0.3
= 333N
Torque is a measure of the rotational force applied to an object, such as a nut, bolt, or screw. It is the product of the force applied, and the distance from the point of rotation. Mathematically, torque is represented as a vector, with direction and magnitude.
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You are sitting on a Ferris wheel moving at a constant speed of 8 m/s. When you are at the bottom of the rotation, what is the normal force of the seat on you if you have a mass of 50 kg and the radius of the Ferris wheel is 10 m
Answer:
40NExplanation:
Formula for calculating normal force is expressed as:
\(F = ma\\since \ a = \frac{v^2}{r} \\F = \frac{mv^2}{r}\)
m is the mass of the body = 50kg
v is the velocity of the Ferris wheel = 8m/s
r is the radius of the Ferris wheel
Substitute into the formula:
\(F = \frac{50 \times 8}{10}\\ F = \frac{400}{10}\\ F = 40N\\\)
Hence the normal force of the seat is 40N
In a classroom, who is a receiver of messages?
HELP ASAP 100 POINTS NEED ANSWERED ASAP
Answer:
yes
Explanation:
Answer:
Hmm looks tricky
Explanation:
Jack sits in the chair of a Ferris wheel that is rotating at a constant 0.150 rev/srev/s . As Jack passes through the highest point of his circular part, the upward force that the chair exerts on him is equal to one-fourth of his weight.
What is the radius of the circle in which Jack travels? Treat him as a point mass.
Answer:
Explanation:
At the top of the arc, 3/4 of the acceleration of gravity is use to supply the necessary centripetal acceleration.
0.75g = ω²R
R = 0.75g/ω²
R = 0.75(9.81) / (0.15 rev/s)(2π rad/rev)²
R = 8.283006...
R = 8.28 m
2(a)Find the density of air filled in polythene container with mass of 0.419kg when it is empty. When filled with extra air its mass increased to 0.428kg also the top of polythene container mass connected to the perplex box of volume 1000cm³ and the number of times of air inside was 7.2 times
When filled with extra air its mass increased to 0.428kg also the top of polythene container mass connected to the perplex box of volume 1000cm³ and the number of times of air inside was 7.2 times. The density of the air filled in the polythene container is approximately 1.25 kg/m³.
The density of air filled in the polythene container can be determined by considering the change in mass and volume of the container before and after filling it with air. Given that the mass of the empty container is 0.419 kg and the mass of the container when filled with extra air is 0.428 kg, and the volume of the perplex box is 1000 cm³.
Calculate the mass of the air inside the container by subtracting the mass of the empty container from the mass of the container when filled with air:
Mass of air = Mass of filled container - Mass of empty container
= 0.428 kg - 0.419 kg
= 0.009 kg
Calculate the volume of the air inside the container using the given number of times the air inside is 7.2:
Volume of air = Volume of perplex box * Number of times air inside
= 1000 cm³ * 7.2
= 7200 cm³
Convert the volume of air to cubic meters (m³) by dividing by 1000000:
Volume of air = 7200 cm³ / 1000000
= 0.0072 m³
Calculate the density of air using the formula:
Density = Mass / Volume
Density = 0.009 kg / 0.0072 m³
≈ 1.25 kg/m³
Therefore, the density of the air filled in the polythene container is approximately 1.25 kg/m³.
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