Answer:
she spent 19 hours on her book report
Step-by-step explanation:
you take 6 hours subtract by 1 hour for math then you get 5 do then 24-5 Is 19
Hope this helps
.Use any basic integration formula or formulas to find the indefinite integral. (Use C for the constant of integration. Remember to use absolute values where appropriate.)
x − 1/3x dx
the required indefinite integral is x³/3 - x²/6 + C.
Given: x − 1/3x dx We need to find the indefinite integral. To integrate the above function, we can use the following basic integration formulas.
∫x dx = 1/2x² + C∫k dx
kx + C∫xⁿ dx = xⁿ⁺¹ / (n + 1) + C,
where n ≠ -1The given function is of the form x - 1/3x. We can write it as (3x² - x)/3.Now,
we can integrate (3x² - x)/3 using the basic integration formula.
∫(3x² - x)/3 dx= 3/3 ∫x² dx - 1/3 ∫x dx
∫x² dx - 1/3 ∫x dx= x³/3 - x²/6 + C On substituting the value of x, we get
∫(x - 1/3x) dx= ∫(3x² - x)/3 dx
x³/3 - x²/6 + C
Hence, the required indefinite integral is x³/3 - x²/6 + C.
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Beth has 7 more quarters than dimes and 1 less nickel than dimes. The total value is $3.70. How many of each type
of coin does Beth have?
Need answer pls
Answer: 5 dimes 4 nickels 12 quarters
Step-by-step explanation:
i dont think u need one bro
Beth has 7.5 Dimes, 6.5 Nickel, and 14.5 Quarters.
What are Arithmetic operations?Arithmetic operations can also be specified by the subtract, divide, and multiply built-in functions.
+ Addition operation: Adds values on either side of the operator.
For example 4 + 2 = 6
- Subtraction operation: Subtracts the right-hand operand from the left-hand operand.
for example 4 -2 = 2
Total value =$3.70
Let
Nickel = x -1
Dimes = x
Quarters = x + 7
Every
Nickel = 5 cents
Dimes = 10 cents
Quarters = 25 cents
Total cents = $3.70× 100 = $370
⇒ 5n + 10d + 25q = 370
⇒ 5(x-1) + 10(x) + 25(x+7) = 370
⇒ 5x-5 + 10x + 25x+175 = 370
⇒ 40x + 70= 370
⇒ 40x = 370 - 70
⇒ 40x = 300
Divide both sides by 40
⇒ x= 300/40
⇒ x = 7.5
⇒ Dimes = 7.5
⇒ Nickel = 7.5 -1 = 6.5
⇒ Quarters = 7.5 + 7 = 14.5
Hence, Beth has 7.5 Dimes, 6.5 Nickel, and 14.5 Quarters.
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There are two numbers and the first is larger than the second. Three times
the larger number plus the smaller number is forty. Twice the smaller number
plus one is equal to the larger number. Find both numbers
Answer:
3y+x=40
x=40-3y..........1
2x+1=y........2
subst. 2into1:
x=40-3(2x+1)
x=40-6x-3
7x=37
x=37/7
subst.x into2:
2(37/7)+1=y
y=81/7
Write the equation of the line in slope-intercept form containing the point (2,4) and with a slope of
3/2.
Answer:
y=3/2x+1
Step-by-step explanation:
y=mx+b is the slope-intercept form
y=3/2x+b
we are looking for b now
plug in the points you provided
2=x, 4=y
4=3/2(2)+b
4=3+b
b=1 which is the intercept
All of the following are equivalent to 1.75 except _____. 14/8, 1 75/100, 1 3/4, 4/7
.A panel of judges A and B graded seven debaters and independently awarded the marks. On the basis of the marks awarded following results were obtained: 2X = 252, Y = 237, 2x2 = 9550, Y2 = 3287, zXY = 8734. An sth debater was awarded 35 marks by judge A while Judge B was not present. If judge B were also present, how many marks would you expect him to reward to the sth debater, assuming that the same degree of linear relationship exists in their judgement? a) 33 b) 78 c) 22 d) O 67
The expected number of marks that Judge B would award to the sth debater, assuming the same degree of linear relationship exists in their judgement, is (option) b) 78.
In order to calculate the expected number of marks, we need to use the formula for the regression line, which is given by:
Ŷ = a + bX
where Ŷ is the predicted value (number of marks awarded by Judge B), X is the given value (number of marks awarded by Judge A), a is the y-intercept, and b is the slope of the regression line.
From the given information, we can calculate the slope (b) using the formula:
b = zXY / Y2 = 8734 / 3287 ≈ 2.657
Next, we can calculate the y-intercept (a) using the formula:
a = Y - bX = (237 / 7) - (2.657 * (252 / 7)) ≈ -9.03
Now, we can substitute the given value of 35 marks awarded by Judge A into the regression line formula:
Ŷ = -9.03 + (2.657 * (35 / 7)) = 78
Therefore, the expected number of marks that Judge B would award to the sth debater is 78.
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John went to the store and bought 4 pencils
and 10 binders and spent $64. Carmen went
to the same store and bought 7 pencils and 4
binders and spent $31. If Lisa wants to buy
pencils and binders from the same store,
how much should they tell her each item
costs?
Calculate the double integral. ∫∫R 2x/1 + xy dA, R = [0, 2] × [0, 1]
The double integral. ∫∫R 2x/1 + xy dA, R = [0, 2] × [0, 1] is: 2*(1/2ln(3) - 1/2ln(1))
To calculate the double integral ∫∫R 2x/1 + xy dA, we need to integrate with respect to x and y over the region R = [0, 2] × [0, 1].
We can solve this by using the order of integration.
First we need to fix the limits of integration with respect to y and then integrate with respect to x.
∫∫R 2x/1 + xy dA = ∫(0 to 1) (∫(0 to 2) 2x/(1+xy) dx) dy
∫(0 to 1) (∫(0 to 2) 2x/(1+xy) dx) dy = ∫(0 to 1) ( 2*ln(1+xy)|x=0 to 2) dy
∫(0 to 1) ( 2ln(1+2y) - 2ln(1+0) ) dy
= 2*∫(0 to 1) ln(1+2y) dy
= 2*[y*ln(1+2y) - ∫(0 to 1) ln(1+2y) dy] |y = 0 to 1
= 2*[yln(1+2y) - (1/2 ln(3) - 1/2* ln(1))] |y = 0 to 1
= 2*(1ln(3) - 0ln(1) - 1/2* ln(3) + 1/2* ln(1))
= 2*(1/2ln(3) - 1/2ln(1))
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which factors will influence the margin of error when the population standard deviation is unknown? check all that apply.
We need to know about margin of error to solve the problem. The factors that influence margin of error are confidence level and sample size.
Margin of error is a statistic expressing the amount of random sampling error in the results of a survey. The larger the margin of error, the less confidence one should have that a poll result will reflect the result of a census of the entire population. Margin of error is influenced by three factors, confidence level, sample size and population standard deviation. In absence of population standard deviation, the margin of error is influenced by confidence level and sample size.
Therefore the margin of error is influenced by confidence level and sample size.
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1. Find the degree of the polynomial.
5n^20 p^2 x^6
Answer:
6
Step-by-step explanation:
Please help immediately
Show your work
Answer:
a + 7
Step-by-step explanation:
x^2 + 2x - 8. on [5,a]
(f(a)-f(5))/( a - 5 )
(( a^2 + 2a - 8 ) - 27 ) / a - 5
( a^2 + 2a - 35 ) / a - 5
(a - 5)(a + 7) / a - 5
a + 7
Find the unit rates and write them in both
fraction form and word form.
Helena runs 10 miles in two hours.
II
please help
Answer:
Step-by-step explanation:
10 miles in 2 hours
10/2 = 5 so Helena runs 5 miles in 1 hour
5 mph
5miles/1hour
I am here my friend!
the sum of 3 and 4 multiplied by 1/2 translated into a mathematical expression
Answer:
(3+4)1/2
Step-by-step explanation:
(3+4)1/27×1/23.5To divide
by
, answer this question: How many sets of
are in
? Use the model representing the fraction
to help you answer the question. (Hint: Think about grouping the blue boxes into pairs.)
What is the solution to this equation?
–0.2(x – 20) = 44 – x
Answer: x=50
Step-by-step explanation:
Use the distributive property to multiply -0.2 by x-20.
-0.2x+4=44-x
Add x to both sides.
-0.2x+4+x=44
Combine -0.2x and x to get 0.8x.
0.8x+4=44
Subtract 4 from both sides.
0.8x=44-4
Subtract 4 from 44 to get 40.
0.8x=40
Divide both sides by 0.8.
x=40/0.8
Expand 40/0.8 approx 50 by multiplying both numerator and the denominator by 10.
X=400/8
Divide 400 by 8 to get 50.
x=50
find div(curl f) = ∇ · (∇ × f). f(x, y, z) = xyzi yj zk
If f(x, y, z) = xyzi + yj + zk, the divergence of the curl of the vector field f is zero.
To find the divergence of the curl of the vector field f(x,y,z) = xyzi + yj + zk, we first need to compute the curl of f, which is given by:
curl f = (∇ × f) = ∂(zk)/∂y - ∂(yj)/∂z + (∂(yj)/∂x - ∂(xyzi)/∂y)k + (∂(xyzi)/∂z - ∂(zk)/∂x)j + (∂(zk)/∂x - ∂(yj)/∂y) i
Simplifying this expression, we get:
curl f = (-z)i + xj + yk
Next, we need to find the divergence of the curl of f, which is given by:
div(curl f) = ∇ · (∇ × f) = ∂(∂(zk)/∂y - ∂(yj)/∂z)/∂x + ∂(∂(yj)/∂x - ∂(xyzi)/∂y)/∂y + ∂(∂(xyzi)/∂z - ∂(zk)/∂x)/∂z
Substituting the values from the curl f expression, we get:
div(curl f) = ∂(-z)/∂x + ∂(x)/∂y + ∂(y)/∂z
Simplifying this expression, we get:
div(curl f) = 0
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1^2 + 2^2 + 3^2 +.... + 28^2 + 29^2 + 30^2 = ......
Find the value
Thank you!
Step-by-step explanation:
The sum of consecutive squares is
\(1^2+2^2+\dots+n^2=\frac16n(n+1)(2n+1)\)
Therefore
\(1^2+2^2+\dots+30^2=\frac16(30)(31+1)(2\cdot30+1) = 9455\)
25 = (ky – 1)²
In the equation above, y = −2 is one solution. If k is a constant, what is a possible value of k?
answers
a: 0
b: -13
c: -3
d: 5
In the equation, The possible value of k is,
⇒ k = - 3
We have to given that,
An expression is,
⇒ 25 = (ky - 1)²
And, In the equation above, y = −2 is one solution.
Now, We can plug y = - 2 in above equation, we get;
⇒ 25 = (ky - 1)²
⇒ 25 = (k × - 2 - 1)²
⇒ 25 = (- 2k - 1)²
Take square root both side, we get;
⇒ √25 = (- 2k - 1)
⇒ 5 = - 2k - 1
⇒ 5 + 1 = - 2k
⇒ - 2k = 6
⇒ - k = 6/2
⇒ - k = 3
⇒ k = - 3
Therefore, The possible value of k is,
⇒ k = - 3
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A smorgasbord vendor sells meatballs for $3 each atlantic herring for $5 each. In order to cover his daily expenses, he must all at least $400 worth of food. write an inequality that represents this situation if 68 meatballs and 38 herring are sold, will the street vendor cover his costs?
Question: In A Box Plot, Data Value X Is Considered An Outlier If A. X Q1 -1. 0(IQR) Or X Q3 +1. 0(IQR) B. X Q1-1. 5(IQR) Orx> Q3+1. 5(IQR). X < Q2-1. 5(IQR) Or X > Q2+1. 5(IQR) D. X Q2-1. 0(TQR) IQR) Oc Or X>Q2+1. 0
The right response is B. According to Option B, a data value X is regarded as an outlier if it deviates from the range Q1 - 1.5(IQR) to Q3 + 1.5. (IQR).
The right response is B.
The distance between the first quartile (Q1) and the third quartile in a box plot is known as the interquartile range (IQR) (Q3).
According to Option B, a data value X is regarded as an outlier if it deviates from the range Q1 - 1.5(IQR) to Q3 + 1.5. (IQR).
Although the range given in Option A is erroneous, the idea of an outlier being outside of a specific range based on the IQR is correct.
Option C's range, which is Q2 - 1.5(IQR) to Q2 + 1.5(IQR), is incorrect for locating outliers.
The phrase "TQR," which is uncommon in box plots, is mentioned in Option D. The range of Q2 -1.0(IQR) to Q2 +1.0(IQR) provided is incorrect for either locating outliers.
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Find the total interest:
$520 at 2%
for 6 years
The interest is %2 of 520 which, if you do the math, is 10.4 cents. You want to find out how much interest it is for 6 years so you have to multiply them.
10.4 x 6 = 62.4
The total interest for 6 years is $62.4
your welcome
Humans are always consumers most humans are omnivores but some humans eat only plants matter making them herbivores however all humans are considered to be-
All humans are considered to be consumers. A consumer is an organism that obtains its energy and nutrients by feeding on other organisms.
As humans, we consume food to provide our bodies with the energy and nutrients necessary for survival. Whether we eat meat, plants, or a combination of both, we are still consumers. In the case of herbivores, they consume only plant matter, but they are still considered consumers because they are obtaining their energy and nutrients from other living organisms (plants). Therefore, regardless of our dietary choices, all humans are classified as consumers in ecological terms.
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A person travels 10 miles due north, then 5 miles due west, then 14 miles due north and then 12 miles due east. How far is that person from their starting point?’
help with these im posting more so check
Answer:
9 is c
10 is b
i think the last one is a but not too sure
Step-by-step explanation:
The Land of Nod lies in the monsoon zone, and has just two seasons, Wet and Dry. The Wet season lasts for 1/3 of the year, and the Dry season for 2/3 of the year. During the Wet season, the probability that it is raining is 3/4; during the Dry season, the probability that it is raining is 1/6. (a) I visit the capital city, Oneirabad, on a random day of the year. What is the probability that it is raining when I arrive? (b) I visit Oneirabad on a random day, and it is raining when I arrive. Given this information, what is the probability that my visit is during the Wet season? (c) I visit Oneirabad on a random day, and it is raining when I arrive. Given this information, what is the probability that it will be raining when I return to Oneirabad in a year's time? (You may assume that in a year's time the season will be the same as today but, given the season, whether or not it is raining is independent of today's weather.)
Answer:
Step-by-step explanation:
(a) To find the probability that it is raining when you arrive in Oneirabad on a random day, we need to use the law of total probability.
Let A be the event that it is raining, and B be the event that it is the Wet season.
P(A) = P(A|B)P(B) + P(A|B')P(B')
Given that the Wet season lasts for 1/3 of the year, we have P(B) = 1/3. The probability that it is raining during the Wet season is 3/4, so P(A|B) = 3/4.
The Dry season lasts for 2/3 of the year, so P(B') = 2/3. The probability that it is raining during the Dry season is 1/6, so P(A|B') = 1/6.
Now we can calculate the probability that it is raining when you arrive:
P(A) = (3/4)(1/3) + (1/6)(2/3)
= 1/4 + 1/9
= 9/36 + 4/36
= 13/36
Therefore, the probability that it is raining when you arrive in Oneirabad on a random day is 13/36.
(b) Given that it is raining when you arrive, we can use Bayes' theorem to calculate the probability that your visit is during the Wet season.
Let C be the event that your visit is during the Wet season.
P(C|A) = (P(A|C)P(C)) / P(A)
We already know that P(A) = 13/36. The probability that it is raining during the Wet season is 3/4, so P(A|C) = 3/4. The Wet season lasts for 1/3 of the year, so P(C) = 1/3.
Now we can calculate the probability that your visit is during the Wet season:
P(C|A) = (3/4)(1/3) / (13/36)
= 1/4 / (13/36)
= 9/52
Therefore, given that it is raining when you arrive, the probability that your visit is during the Wet season is 9/52.
(c) Given that it is raining when you arrive, the probability that it will be raining when you return to Oneirabad in a year's time depends on the season. If you arrived during the Wet season, the probability of rain will be different from if you arrived during the Dry season.
Let D be the event that it is raining when you return.
If you arrived during the Wet season, the probability of rain when you return is the same as the probability of rain during the Wet season, which is 3/4.
If you arrived during the Dry season, the probability of rain when you return is the same as the probability of rain during the Dry season, which is 1/6.
Since the season you arrived in is independent of the weather when you return, we need to consider the probabilities based on the season you arrived.
Let C' be the event that your visit is during the Dry season.
P(D) = P(D|C)P(C) + P(D|C')P(C')
Since P(C) = 1/3 and P(C') = 2/3, we can calculate:
P(D) = (3/4)(1/3) + (1/6)(2/3)
= 1/4 + 1/9
= 9/36 + 4/36
= 13/36
Therefore, the probability that it will be raining when you return to Oneirabad in a year's time, given that it is raining when you arrive, is 13/36.
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A person in an apartment
building sights the top and bottom of an office
building 500 ft. away. The angle of elevation
for the top of the office building is 23° and the
angle of depression for the base of the building
is 50º. How tall is the office building?
Answer:
Step-by-step explanation:
tan23=h1/500
h1=500tan23
tan50=h2/500
h2=500tan50
The height of the building is h1+h2 so
H=500(tan23+tan50)ft (exact)
H=808.1 ft (rounded to nearest tenth of a foot)
Given 12 different 2-digit numbers, show that one can choose two of them such that their difference is a two-digit number with identical first and second digit
Step-by-step explanation:
there are 91 2-digit numbers : 10 ..99
and there are 9 2-digit numbers with identical first and second digit : 11, 22, 33, 44, 55, 66, 77, 88, 99
99 has to be excluded, because there are no 2 2- digit numbers that I can subtract from each other and get 99.
so, e are dealing with 8 possibilities.
88 = 99-11
98-10
77 = 99-22
98-21
97-20
...
78-1
66 = 99-33
98-32
...
67-1
...
11 = 99-88
98-87
...
12-1
all the double- digit numbers are 11 apart. so, by picking 12 numbers, I have to have at least one that I can combine with one of the other 11 to get a double-digit number.
When an alternating current of frequency f and peak current I_0 passes through a resistance R, then the power delivered to the resistance at time t seconds is P = I^2_0 R sin^2 2 pi ft. Write an expression for the power in terms of csc^2 2 pi ft. P = I^2_0 R/(csc^2 2 pi ft) P = I^2_0 R (csc^2 2 pi ft) P = I^2_0/(1 - csc^2 2 pi ft) P = I^2_0 R(1 - csc^2 2 pi ft)
The expression for the power delivered to a resistance in terms of csc^2 2 pi ft is P = I^2_0 R (csc^2 2 pi ft).
According to the given information, the power delivered to a resistance R when an alternating current of frequency f and peak current I_0 passes through it is represented by the equation P = I^2_0 R sin^2 2 pi ft.
To express this equation in terms of csc^2 2 pi ft, we can use the trigonometric identity csc^2 x = 1/sin^2 x. Substituting this identity into the equation, we get P = I^2_0 R (1/sin^2 2 pi ft).
Since csc^2 x is the reciprocal of sin^2 x, we can rewrite the equation as P = I^2_0 R (csc^2 2 pi ft). This expression represents the power delivered to the resistance in terms of csc^2 2 pi ft.
Therefore, the correct expression for the power delivered to the resistance in terms of csc^2 2 pi ft is P = I^2_0 R (csc^2 2 pi ft).
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What is the equation in standard form of the line that passes through the point (4,-8) and 2 has the slope of 1/4
Answer:
x-4y=36
Step-by-step explanation:
standard form is Ax+By=C
Calculate the average speed of a boat that travels 600 meters in 40 seconds.
Answer:
15 meters in 1 second
Step-by-step explanation:
Divide 600 by 40 which is 15
so it travels 15 meters in 1 second
hope this helps!
Answer:15 meters per second
Step-by-step explanation:
600/40= 15