(L7) a=3 cm, b=5 cm, c=6 cmThe triangle is a(n) _____ triangle.

Answer:$231.2

Step-by-step explanation:

An equation is a mathematical statement that is made up of two expressions connected by an equal sign.

The total cost of farmers' chicks is $231.2

What is an equation?

An equation is a mathematical statement that is made up of two expressions connected by an equal sign.

Example:

2x = 5 is an equation.

We have,

Total chicks = 70

4 Rhode Island Red chicks = 3 Buckeye chicks.

Multiply 10 on both sides.

40 Rhode Island Red chicks = 30 Buckeye chicks.

We see that,

40 + 30 = 70

Now,

Rhode Island Red chicks cost = $3.20

Buckeye chicks cost = $3.44

Now,

= 40 x 3.20 + 30 x 3.44

= 128 + 103.2

= $231.2

Thus,

The total cost of farmers' chicks is $231.2

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The number line shows the value of 5 - (-8) = 13.

Addition:

Subtraction:

Here the given operation is subtraction. Where a subtrahend is a negative number i.e., -8.

Step1: Start from '5' on the number line.

Step2: Since the subtrahend is a negative number, move to the right side on the number line from '5'.

Step3: Thus, the number obtained on the line is 13.

Step4: Algebraically the result is 5 - (-8) = 5 + 8 = 13.

The number line for this operation is shown below.

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Answer:

-18

Step-by-step explanation:

From 3 to 10th term is 7 d's       ( d = common difference)

3 - 7d = third term

3 - 7(3)  =  -18

Answer:

D

Step-by-step explanation:

two and four are corrisponding angles (if n and p are parallel)

The statement that angle 2 ≅ angle 4 is Corresponding Angles Postulate

The angles which are formed in corresponding corners with the transversal when two parallel lines are intersected by any other line is called corresponding angle. The angles created when a transversal intersects two parallel lines are known as corresponding angles. Typical examples of corresponding angles include opening and closing a lunchbox, resolving a Rubik's cube, and endless parallel railroad tracks. These are created in the transversal's corresponding or matching corners. According to the definition of corresponding angles, when two parallel lines cross a third one, the angles that are in the same relative position at every intersection are referred to as being corresponding angles to one another.

A/c to corresponding angle,

∠2 = ∠4

Hence, option D is correct.

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Answer:

Boys= 12

Girls= 6

Step-by-step explanation:

Let no: of girls be 'x'

No: of boys= 2x

boys after= 2x-6

girls after = x+6

according to the question,

2(2x-6)=x+6

4x-12=x+6

3x=18

x=6

No: of girls at first= 6

No: of boys at first=2*6=12

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Sum of the interior angles of any triangle equal 180° .

Thus ;

\((x + 20) + 3x + 60 = 180\)

\(4x + 80 = 180\)

Subtract sides 80

\(4x + 80 - 80 = 180 - 80\)

\(4x = 100\)

Divide sides by 4

\( \frac{4}{4} x = \frac{100}{4} \\ \)

\(x = 25\)

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Answer: definitely x=25

Step-by-step explanation:

a. Cumulative Frequency Distribution:

Number of Days    Number of Containers   Cumulative Frequency

0 to 5                  31                                      31

6 to 11                66                                      97

12 to 17              43                                      140

18 to 23              19                                      159

24 to 29              10                                      169

b. Cumulative Relative Frequency and Cumulative Percentage:

To calculate the cumulative relative frequency, we divide the cumulative frequency by the total number of containers (169) and multiply by 100.

To calculate the cumulative percentage, we directly use the cumulative relative frequency multiplied by 100.

Number of Days    Number of Containers   Cumulative Frequency   Cumulative Relative Frequency   Cumulative Percentage

0 to 5                  31                                      31                                             (31/169)*100 ≈ 18.34%

6 to 11                66                                      97                                             (97/169)*100 ≈ 57.39%

12 to 17              43                                      140                                           (140/169)*100 ≈ 82.84%

18 to 23              19                                      159                                           (159/169)*100 ≈ 94.08%

24 to 29              10                                      169                                           (169/169)*100 = 100%

Therefore, the correct cumulative relative frequencies and cumulative percentages for each class are approximately:

0 to 5: Cumulative Relative Frequency ≈ 18.34%, Cumulative Percentage ≈ 18.34%

6 to 11: Cumulative Relative Frequency ≈ 57.39%, Cumulative Percentage ≈ 57.39%

12 to 17: Cumulative Relative Frequency ≈ 82.84%, Cumulative Percentage ≈ 82.84%

18 to 23: Cumulative Relative Frequency ≈ 94.08%, Cumulative Percentage ≈ 94.08%

24 to 29: Cumulative Relative Frequency = 100%, Cumulative Percentage = 100%

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The natural logarithm function is ln(p) = ln(100) - 0.35t

From the question, we have the following parameters that can be used in our computation:

The table of values

The function can be represented as

p = ae^kt

Using the points on the table, we have

ae^(k * 0) = 100

So, we have

a = 100

This gives

p = 100e^kt

Using another point, we have

70.5y = 100e^(k * 1)

70.5y = 100e^k

So, we have

e^k = 0.705

Take the natural logarithm of both sides

k = ln(0.705)

k = -0.35

The function becomes

p = 100e^(-0.35t)

Take the natural logarithm of both sides

ln(p) = ln(100) - 0.35t

Hence, the function is ln(p) = ln(100) - 0.35t

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Answer:

y=5 and x=-1 are parallel

Step-by-step explanation:

Let's do a quick review on some things:

Parallel lines are the lines that never intersect and perpendicular lines are the lines that intersect at 90°.

Lines with the same slope are parallel and if the slope of one line is the negative reciprocal of the second line, then they are perpendicular.

So, this answers to your question that it's parallel!

Hopefully this helps :)

The value of x is 42.

To determine the value of x, we need to analyze the given information regarding the scale factor between Figure A and Figure B.

The scale factor is expressed as the ratio of the corresponding side lengths or dimensions of the two figures.

Let's assume that the length of a side in Figure B is represented by 'x'. According to the given information, Figure A is a scale copy of Figure B with a scale factor of 2/7. This means that the corresponding side length in Figure A is 2/7 times the length of the corresponding side in Figure B.

Applying this scale factor to the length of side x in Figure B, we can express the length of the corresponding side in Figure A as (2/7)x.

Given that the length of side x in Figure B is 12, we can substitute it into the equation:

(2/7)x = 12

To solve for x, we can multiply both sides of the equation by 7/2:

x = (12 * 7) / 2

Simplifying the expression:

x = 84 / 2

x = 42

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Bo and Erica are yoga instructors. Between the two of them, they teach 36 yoga classes each week. If Erica teaches 15 fewer than twice as many as Bo, then the classes each instructor teaches per week is OC. 17 Bo; 19 Erica

Let's use algebra to solve this problem. Let x represent the number of classes Bo teaches per week, and y represent the number of classes Erica teaches per week. The problem states that together, they teach 36 classes, so we have:
x + y = 36
It's also stated that Erica teaches 15 fewer than twice as many classes as Bo:
y = 2x - 15
Now we can solve these equations simultaneously to find the values of x and y. First, we can substitute the expression for y in the first equation:
x + (2x - 15) = 36
Combining the terms with x, we get:
3x - 15 = 36
Next, add 15 to both sides of the equation:
3x = 51
Now divide both sides by 3:
x = 17
Now that we have the value of x, we can find the value of y by substituting it into the equation for y:
y = 2(17) - 15
y = 34 - 15
y = 19
Thus, Bo teaches 17 classes per week, and Erica teaches 19 classes per week. The correct answer is:
OC. 17 Bo; 19 Erica

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The probability distribution for the difference between actual and predicted weekly sales of the company is a uniform distribution between $2800 and $2800. Actualsale of under predicted  is 4/7 and with in predicted sale is 13/14

(a) To find the probability that the actual sale is under predicted by at least $1200, we need to determine the area under the PDF to the left of $1200. Since the PDF is constant within the range, the probability is equal to the ratio of the difference between $1200 and $2800 to the total range of $2800. Therefore, the probability is (2800 - 1200) / 2800 = 1600 / 2800 = 4/7, or approximately 0.5714.
(b) To find the probability that the actual sale is within $1300 of the predicted sale, we need to determine the area under the PDF between $-1300 and $1300. Again, since the PDF is constant within the range, the probability is equal to the ratio of the difference between $1300 and $-1300 to the total range of $2800. Therefore, the probability is (1300 - (-1300)) / 2800 = 2600 / 2800 = 13/14, or approximately 0.9286.
In summary, the probability that the actual sale is under predicted by at least $1200 is 4/7, and the probability that the actual sale is within $1300 of the predicted sale is 13/14.

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Answer:

27A+81A =108

Step-by-step explanation:

The x value for the point located 2/3 the distance from A to B is 2.67. This can be found by calculating the midpoint between A and B, which is (2, 1.5), and then taking 2/3 of the x component (2).

1. Calculate the midpoint between A and B: (0 + 4) / 2 = 2 and (0 + 3) / 2 = 1.5

2. Take 2/3 of the x component of the midpoint: 2/3 * 2 = 2.67

The  value x for the point located 2/3 the distance from A to B can be found using a few simple steps. First, we need to calculate the midpoint between A and B. This can be done by adding the x and y components of the two points and then dividing by 2. For our points A and B, this gives us the midpoint (2, 1.5). Now, we need to take 2/3 of the x component of the midpoint (2). This gives us 2/3 * 2 = 2.67. This means that the x value for the point located 2/3 the distance from A to B is 2.67. This process can also be used to determine the y value for the point, which is 1.

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Answer:

6 and 15

3 and 15

Step-by-step explanation:

the least common multiple is the smallest number that is entirely divisible by both numbers

multiples of 2 = 2 , 4 , 6 , 8 , 10

multiples of 10 = 10 20, 30

lcm = 10  

multiples of 3 = 3 6 9 15 18 21 24 27 30

multiples of 15 = 15, 30

lcm = 30

Answer:

Sum of the interior angles = 2,880° Therefore, assuming a convex or regular polygon and using the summation formula (n - 2) 180°, we have

(n - 2) 180° = 2,880° Solve for n

n - 2 = 16 Add 2 to both sides of the equation

n = 18

Step-by-step explanation:

(n - 2) 180° = 2,880° Solve for n

n - 2 = 16 Add 2 to both sides of the equation

n = 18

Step-by-step explanation:

Answer:

see explanation

Step-by-step explanation:

The nth term ( explicit formula) of a geometric sequence is

\(a_{n}\) = a₁ \((r)^{n-1}\)

where a₁ is the first term and r the common ratio

Here a₁ = - 2 and r = \(\frac{a_{2} }{a_{1} }\) = \(\frac{\frac{4}{3} }{-2}\) = - \(\frac{2}{3}\) , then

\(a_{n}\) = - 2 \((-\frac{2}{3}) ^{n-1}\) ← explicit formula

Answer:

Step-by-step explanation:

The formula for an explicit geometric formula (as opposed to a recursive one) is

\(a_n=a_1(r)^{n-1}\) where a(n) is representative of the position of a number in the sequence, a(1) is the first number in the sequence, and r is the common ratio. The common ratio is the same number that must be either multiplied in or divided out to get to the next number in the term. Notice that the top numbers in our sequence are doubling which implies we are multiplying the top numbers by -2, and the bottom numbers are going up by multiples of 3. So our common ratio is -2/3. Try it and see:

\(-2(-\frac{2}{3})=\frac{4}{3}\)  and

\(\frac{4}{3}(-\frac{2}{3})=-\frac{8}{9}\) etc.

Therefore, the explicit geometric formula for this sequence is

\(a_n=-2(-\frac{2}{3})^{n-1\)

You can use this formula to find any number in the sequence; for example, if you wanted to know the 100th number in this sequence, simply replace n with 100 and do the math. That's what an explicit formula is used for.

The number of puppies per kids is 20 puppies.

Given that, there are 180 puppies in the shelter with 9 kids.

Number of puppies per kids = Total number of puppies/Number of kids

= 180/9

= 20 puppies

Therefore, the number of puppies per kids is 20 puppies.

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Answer:

$490 dollars

Step-by-step explanation:

Tia takes 50 dollars for her bus fare every month for 7 months. Do 7 X 5 to get your answer which is 49 then add a zero to 49.

1) The lower class limits: 100, 200, 300, 400, 500, 600 .

2) The upper class limits:  199, 299, 399, 499, 599, 699.

3) The class width: 100.

4) Class midpoints: 149.5, 249.5, 349.5, 449.5, 549.5, 649.5.

5) Class boundaries : 99.5, 199.5, 299.5, 399.5, 499.5, 599.5, 699.5.

6) The number of individuals included in the summary : 155

The lower class limit in each class: 0,100, 200, 300, 400, 500, 600.

The upper-class limit is the biggest value in each class.

so the upper-class limit is:  99, 199, 299, 399, 499, 599, 699.

As we know the class width is the difference between the lower limit of one class and the lower limit of the previous class.

For example, 300 is the lower limit of one class and the lower limit of the previous class is 200 , so 300 - 200 = 100.

We know that, the class midpoints are the average of the limits of a class.

So, using midpoint formula the class midpoints are:

\(\frac{100+199}{2} = 149.5\\\\\frac{200+299}{2} = 249.5\\\\\frac{300+3199}{2} = 349.5\\\\\frac{400+499}{2} = 449.5\\\\\frac{500+599}{2} = 549.5\\\\\frac{600+699}{2} = 649.5\\\)

We know that the class boundaries are nothing but the end points of an open interval which contains the class interval.

So, the class boundaries for the first class = (99.5, 199.5)

the class boundaries for the second class = (199.5, 299.5)

the class boundaries for the third class = (299.5, 399.5)

the class boundaries for the fourth class = (399.5, 499.5)

the class boundaries for the fifth class = (499.5, 599.5)

The total of individuals is equal to the sum of all the frequencies of each class: 3 + 54 + 76 + 21 + 0 + 0 + 1 = 155

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The complete question is:

Identify the lower class​ limits, upper class​ limits, class​ width, class​ midpoints, and class boundaries for the given frequency distribution. Also identify the number of individuals included in the summary. Blood Platelet Count of Males ​(1000 ​cells/mu​L) Frequency 0​-99 3 100​-199 54 200​-299 76 300​-399 21 400​-499 0 500​-599 0 600​-699 1 Identify the lower class limits​ (in 1000 ​cells/mu​L).

Answer:

h=-3

Step-by-step explanation:

Combine like terms ( -2.5h )

1.8=-2.5h-5.7

Add 5.7 to 1.8 ( 7.5 )

Bring down -2.5h

the divide ( 7.5/-2.5 )

h= -3

Answer:

The answer isssss h=-3

Answer:

B. 15

Step-by-step explanation:

Step by Step Solution

More Icon

Reformatting the input :

Changes made to your input should not affect the solution:

(1): "11.3" was replaced by "(113/10)".

Rearrange:

Rearrange the equation by subtracting what is to the right of the greater than sign from both sides of the inequality :

                    b-((113/10))>0  

Step by step solution :

STEP

1

:

           113

Simplify   ———

           10  

Equation at the end of step

1

:

      113

 b -  ———  > 0  

      10  

STEP

2

:

Rewriting the whole as an Equivalent Fraction

2.1   Subtracting a fraction from a whole

Rewrite the whole as a fraction using  10  as the denominator :

         b     b • 10

    b =  —  =  ——————

         1       10  

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

2.2       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

b • 10 - (113)     10b - 113

——————————————  =  —————————

      10              10    

Equation at the end of step

2

:

 10b - 113

 —————————  > 0  

    10    

STEP

3

:

3.1    Multiply both sides by  10  

3.2    Divide both sides by  10  

     b-(113/10)  > 0

Solve Basic Inequality :

3.3      Add  113/10  to both sides

            b > 113/10

Inequality Plot :

3.4      Inequality plot for

        b  - 11.300  >  0

One solution was found :

b > 113/10

Which number is a solution of the inequality?

b > 11.3

The answers are 15,9,-14, and 4

15

Answer:y= 29

y=41

y=47

y=65

Step-by-step explanation:

Oh it's just plugging x into the equation!

y= 5+ 6x

y= 29

y=41

y=47

y=65

To prove the properties of the projection matrix, we'll assume that p is the projection matrix corresponding to a subspace S of \(R^{m}\).

(a) p² = p

To show that p² = p, we need to demonstrate that applying the projection matrix p twice is equivalent to applying it once.

Let's consider an arbitrary vector x in \(R^{m}\). Applying the projection matrix p to x yields its projection onto the subspace S:

p(x) = projection of x onto S

Now, if we apply the projection matrix p again to p(x), we have:

p(p(x)) = projection of p(x) onto S

Since p(x) is already the projection of x onto S, applying the projection matrix p once more won't change the result. Hence, we can write:

p(p(x)) = p(x)

This equation holds for any vector x in \(R^{m}\), meaning that p² = p.

(b) \(p^{T}\) = p

To prove that \(p^{T}\) = p, we need to show that the transpose of the projection matrix p is equal to p.

Let's consider an arbitrary vector x in \(R^{m}\). Applying the projection matrix p to x yields its projection onto the subspace S:

p(x) = projection of x onto S

Now, let's compute the transpose of p(x):

\((p(x))^{T}\) = \((projection of x onto S)^T\)

The transpose of a projection onto a subspace doesn't change the result because it only affects the column vectors of the projection matrix. The transpose of p(x) is still the projection of x onto S. Hence, we can write:

\((p(x))^T\) = p(x)

Since this equation holds for any vector x in \(R^{m}\), we can conclude that \(p^T\) = p.

Therefore, we have shown that (a) p² = p and (b) \(p^T\) = p, proving the properties of the projection matrix corresponding to a subspace S of \(R^{m}\).

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In linear equation, 15.2% did the total number of students on the honor roll decrease.

What in mathematics is a linear equation?

50 × 24% = 12

50 × 14%= 7

12+ 7 = 19

50+75 = 125

19 ÷125= 15.2%

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Answer:

80 degrees

Step-by-step explanation:

What we see in this drawing is a triangle formed by three lines. In order to solve this problem, we need to know that when two lines intersect, the two angles formed are supplementary (meaning they add up to 180 degrees). For example, the 150-degree angle, and the angle right next to it (the angle on the left side of the triangle) add up to 180 degrees. This means that the left-most angle of the triangle is 180-150, which is 30 degrees

We can figure out the topmost angle of the triangle using the same method. We know that the angle outside the triangle is 130 degrees, so the angle right next to it (in this case, right below it), is 180-130, or 50 degrees.

Next, we use the fact that triangles are 180 degrees on the inside to figure out the third angle (the one on the right, right next to angle 1). We know that the other two angles are 30 and 50 degrees, and if you add that up, you get 80 degrees. The last angle, then, is 180-80, or 100 degrees.

Lastly, we know that the rightmost angle of the triangle and angle 1 add up to 180 degrees. In other words, 100+Angle1=180. Therefore, Angle 1 is 180-100 or 80 degrees.

The mean, median and mode are as follows:

1. 11.75

2. 11.5

3. 11 and 14

4. 16.75

5. 13 and 16

6. 23

7. 32

8.  79

9.  35

10.  14

11.  2

The three measures of central tendency used in statistics are mean, median, and mode. While describing a set of data, we always specify the focal point of any data set. The measure of central tendency is this. Every day, data are presented to us. We discover them in books, articles, bank statements, phone and utility bills, as well as in newspapers. There are so many; they are all around us. The challenge now is if we can identify some key characteristics of the data by focusing on only a few data points. The means, medians, and modes—measures of central tendency or averages—can be used to do this. When describing a set of data, a measure of central tendency locates the set's center.

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Answer:

$240.87 is how much you made. Hope this helps and I wish you luck.