Large numbers are those numbers that have a bigger value than the numbers that we use in daily life. such numbers tend to create a sense of fear among children and they often skip solving problems that have large numbers in them. for example, 1 million, 1 billion, etc., are large numbers that are used either to show the population of a country or express large amounts of money in a bank account.

Answers

Answer 1

These periods are named as ones, thousands, lakhs, and so on. The one's period consists of the first three digits of the large number, starting from the right.

Everyone learns how to count numbers at a very young age starting from a single digit up to seven digits. This is done with the help of the place value system.

While writing large numbers, we always keep the place value system in mind to ensure that it is written correctly. According to the Indian place-value system, when a number is written in the standard form, each group of digits separated by a comma is called a period.

These periods are named as ones, thousands, lakhs, and so on. The one's period consists of the first three digits of the large number, starting from the right. The thousands period consists of the next two digits. The lakhs period consists of the next two digits and it continues.

Some other large numbers are read and written as follows:

1,000,000,000 = one billion

1,000,000,000,000 = one thousand billion

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Related Questions

pla shop mathematics ​

pla shop mathematics

Answers

The number of trees more than 10m tall but not more than 20m tall is 18 trees.

How many of the trees are more than 10m tall but not more than 20m tall?

0 < h ≤ 5 = 5

height greater than 0m less than or equal to 5m

5 < h ≤ 10 = 9

height greater than 5m less than or equal to 10m

10 < h ≤ 15 = 13

height greater than 10m less than or equal to 15m

15 < h ≤ 20 = 5

height greater than 15m less than or equal to 20m

20 < h ≤ 25 = 1

height greater than 20m less than or equal to 25m

The number of trees that are more than 10m tall but not more than 20m tall are;

10 < h ≤ 15 = 13

15 < h ≤ 20 = 5

So,

13 + 5 = 18 trees

Therefore, the total number of trees which are 10m tall but not more than 20m tall is 18 trees.

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At a zoo, 3 pandas eat a total of 181 1 2pounds of bamboo shoots each day. The male panda eats 3 times as much as the baby. The female eats twice as much as the baby. How many pounds of bamboo shoots does the female panda eat?

Answers

Answer:

6037.2 pounds of bamboo shoots does the female panda eat.

Step-by-step explanation:

Total pandas = 3

Total bamboo shoots eaten = 18112 pounds

Let baby panda eats bamboo = x

Male panda eats bamboo= 3x

Female panda eats bamboo = 2x

So, the equation will become

\(x+3x+2x=18112\)

Now solving the equation to find value of x

\(x+3x+2x=18112\\6x=18112\\x=\frac{18112}{6}\\x=3018.6\)

The value of x we get : x=3018.6

So, baby panda eats bamboo shoots = 3018.6 pounds

Male panda eats bamboo shoots = 3x = 3(3018.6) = 9055.8 pounds

Female panda eats bamboo shoots = 2x = 2(3018.6)= 6037.2 pounds

So, 6037.2 pounds of bamboo shoots does the female panda eat.

Find the solution to the system of the equations shown below: y = negative 4 x + 11. y = one-half x + 2. a. (4, 1) c. (2, 3) b. (11, 2) d. (3, 2) Please select the best answer from the choices provided A B C D

Answers

The system of equations solved by the elimination method gives (-2, 1)

Solving the system of equations

From the question, we have the following parameters that can be used in our computation:

y = -4x + 11

y = 1/2x + 2

Subtract the equations to eliminate y

So, we have the following representation

-4 1/2x - 9 = 0

So, we have

-4 1/2x = 9

Divide the equations

x = -2

Recall that

y = 1/2x + 2

So, we have

y = 1/2(-2) + 2

This gives

y = 1

Hence, the solutions are x = 2 and y = 1

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How do you combine radicals

Answers

Answer:

the numbers outside of the radical get multiplied together and the numbers under the radical get multiplied together. Then see if you can simplify more.

Step-by-step explanation:

Two functions, f and g are defined on R, the set of real numbers, by f(x)=x²-5 and g(x) = 3x - 1. Find f(g(x)).​

Answers

Answer:

f(g(x)) = 9x² - 6x - 4

Step-by-step explanation:

f(g(x) )

= f(3x - 1)

= (3x - 1)² - 5 ← expand factor using FOIL

= 9x² - 6x + 1 - 5

= 9x² - 6x - 4

A worker can complete the assembly of 15 cell phones in 6hrs. At this rate, how many can the worker complete in a 40hrs work week?? With full workin!!​

Answers

Answer: 100 cell phones.

Step-by-step explanation:

The worker makes 2.5 phones an hour. 2.5 x 40 = 100.

Which one is the graph of f(x) = [x]?

Which one is the graph of f(x) = [x]?

Answers

Answer:

F

Step-by-step explanation:

because its linear

A store sells 12 cans of soup for $7. 50 how much would it cost to purchase 6 cans of soup?.

Answers

Answer: $3.75

Step-by-step explanation:

Answer:

The cost of 6 cans of soup is 3.75

Step-by-step explanation:

12 = 7.50

1 can = x

12x = 7.50

We need to find the cost of 1 can. So we divide 7.50 by 12.

x = 0.625

Then multiply by 6.

0.625 x 6 = 3.75

As a result the cost of 6 cans of sup is $3.75

Briefly, describe the distribution in context. Recall, categorical variables are summarized by counts and/or percents

Answers

Thus, distribution is a function that shows the possible values for a variable and how often they occur and categorical values are summarized by counts and/or percents

In statistics, the distribution is a function that shows the possible values for a variable and how often they occur.

The distribution of a data set is the shape of the graph when all possible values are plotted on a frequency graph. Usually, we are not able to collect all the data for our variable of interest. Therefore we take a sample. This sample is used to make conclusions about the whole data set.

The categorical variable is a data in which individuals are placed into groups or categories.

One way to summarize categorical data is to simply count (frequency), or tally up, the number of individuals that fall into each category. Another way is to show the percentage of individuals who fall into each category, thereby creating a relative frequency.

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what is the Greatest Common Factor (GCF) between two
numbers is
Please help me

Answers

The gcf of 40 & 48 is 8. You could use thoses two numbers, You welcome!

Is a hole in a function a discontinuity?

Answers

Yes, a hole in a function is considered a type of discontinuity. A hole occurs when a point is missing from the graph of a function, which causes the graph to have a break in it.

A discontinuity is a break or jump in the graph of a function. A hole in a function is a type of discontinuity where a point is missing from the graph, causing the graph to have a break in it. This type of discontinuity is usually caused by a function having a denominator that is equal to zero, as this creates an undefined point on the graph. This can also occur when two parts of the function are not connected, causing an open gap in the graph. In both cases, the graph is not continuous and has a discontinuity at the point where the hole is present.

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Yes, the function has a hole in discontinuity.

The term function in math is called as a rule that gives value of a dependent variable that corresponds to specified values of one or more independent variables.

Here we to identify is a hole in a function a discontinuity.

the term discontinuity is defined as is discontinuous at a point if it becomes undefined or the limit at that point does not exist. And whether this point is known as the point of discontinuity.

While we looking the hole on a graph looks like a hollow circle. And which  represents the fact that the function approaches the point, here it is not actually defined on that precise value. Where the major reason why this function is not defined at is because is not in the domain of the function.

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12 + 4x = 6x + 10 - 2x



Help

12 + 4x = 6x + 10 - 2xHelp

Answers

Answer:

undefined

Step-by-step explanation:

First isolate x.

12 + 4x = 6x + 10 - 2x

12 + 4x = 4x + 10

     -4x     -4x

12 \(\neq\) 10

Analysis of variance is used to test for equality of several population? means. standard deviations. proportions. variances.

Answers

Analysis of variance is used to test for equality of several population means.

ANOVA could also be utilized to predict the dependent variable of even more with around 2 categories and seems to be compared to the general population extra influential throughout this circumstance.

Throughout addition, ANOVA variants typically include covariates that encourage somebody to manipulate numerically for confounding factors as well as to recognize interactions wherein the factor progressives the implications of some other factor.

ANOVA (Analysis of Variance) was developed by Ronald Fisher.

ANOVA means the Analysis of Variance, is collection of statistical models & linked estimation processes, like variation among & between groups. It is used in analyzing differences among various means.

Therefore, Analysis of variance is used to test for equality of several population means.

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Marie donated 36% of her comic books to a
school. If she donated 135 comic books, how
many did she own before her donation?

Answers

Answer: 375

Step-by-step explanation:

Let x equal the number of comic books before her donation.

x × 0.36 = 135

135/0.36 = 375

You own a bond that has a duration of 6 years. Interest rates are currently 7%, but you believe the Fed is about to increase interest rates by 30 basis points. Your predicted price change on this bond is

Answers

On the given duration and the expected increase in interest rates, the predicted price change on the bond is approximately -1.68%.

To estimate the predicted price change on a bond given a change in interest rates, you can use the concept of bond duration. Bond duration measures the sensitivity of a bond's price to changes in interest rates.

In this case, you own a bond with a duration of 6 years, and you expect the interest rates to increase by 30 basis points (0.30%). To calculate the approximate percentage change in bond price, you can use the following formula:

Percentage Change in Bond Price \(^\sim_\sim\) - (Modified Duration × Change in Interest Rates)

Modified Duration is calculated as:

Modified Duration = Duration / (1 + Yield)

Here, the Yield refers to the yield to maturity (YTM) of the bond, which is equivalent to the interest rate in this case.

Let's assume the bond's yield to maturity is 7% (0.07). Now we can calculate the modified duration and the predicted price change:

Modified Duration = 6 years / (1 + 0.07) = 5.6075

Percentage Change in Bond Price \(^\sim_\sim\) - (5.6075 × 0.0030) \(^\sim_\sim\) -0.0168 or approximately -1.68%

Therefore, based on the given duration and the expected increase in interest rates, the predicted price change on the bond is approximately -1.68%. Note that this is an estimation, and actual price changes may depend on various other factors and market conditions.

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w-5=8w+5
show your work
no links!!!!

Answers

Answer:

-10/7

Step-by-step explanation:

w - 5 = 8w + 5

w - 8w = 5 + 5

-7w = 10

w = - 10/7

Answer:

Step-by-step explanation:

To solve this equation, group like terms together:  'w' terms on the right and constants on the left:

-10 = 7w.  Then:

w = -10/7 (exact) or w ≈ 1.43

Imara used these steps to find the length of the hypotenuse of the right triangle.


Step 1: Find the area of the square with side lengths of 20: 400
Step 2: Find the area of the square with side lengths of 15: 225
Step 3: Find the sum of the areas of the two squares: 625
Step 4: State the length of the hypotenuse: 625

Which best describes Imara’s error?
She should have found the area of the square with side lengths of 15 first.
She did not correctly calculate the area of the square with side lengths of 15.
She should have found the sum of 15 and 20 and then squared the sum.
She did not find the side lengths of the square with an area of 625.

Imara used these steps to find the length of the hypotenuse of the right triangle.Step 1: Find the area

Answers

Answer:

C

Step-by-step explanation:

I did the test

Answer:

c

Step-by-step explanation:

In the equation 6x-2=-4x 2 spencer claims that the first step is to add 4x to both sides

Answers

yes, for your x to be positive and to make it remain on the left hand side you actually have to add 4x to both side to eliminate x from the right hand side.

For a Party, Jessica needs a sizable amount of money to buy balloons and party poppers. She goes to the store to buy Balloons for $0.20 for each balloon and party popper for $0.50 each. The total Price for the haul is $20. In total Jessica purchased 52 balloons and party poppers. Let x represent the number of balloons and y represents the number of party poppers, how many part supplies did Jessica buy?

I need elimination method and Substitution method
Someone please help

Answers

The number of party popper she bought is 32 and the number of balloons she bought is 18.

How many part supplies did she buy?

The first step is to form a system of equations using the information provided in the question.

0.20x + 0.50y = $20 equation 1

x + y = 52 equation 2

The solution using the elimination method :

Multiply equation 2 by 0.20

0.20x + 0.20y = 10.40 equation 3

Subtract equation 3 from equation 2 :

0.30y = 9.60

Divide both sides of the equation by 0.30

y = 9.60 / 0.30

y = 32

The solution using the substitution method:

Make x the subject of the formula in equation 2

x = 52 - y equation 3

Substitute for x in equation 1 :

0.20(52 - y) + 0.50y = $20

10.40 - 0.20y + 0.50y = $20

Combine similar terms together

0.50y - 0.20y = $20 - $10.40

0.30y = $9.60

y = 9.60 / 0.30

y = 32

x = 50 - 32

x = 18

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Peterson and Peterson (1959) conducted an experiment in which participants were asked to remember random letters of the alphabet. They then instructed the participants to count backwards from a three-digit number by threes aloud. The longer the participants spend counting backward, the fewer random letter units they could recall. This inability to recall the original random letters was due in part to____.

Answers

The inability to recall the original random letters in the Peterson and Peterson (1959) experiment was due in part to the decay of information in short-term memory (STM).

STM has a limited capacity and duration, which means that information can be lost over time if it is not rehearsed or refreshed.

In this experiment, participants were asked to remember random letters and then count backward from a three-digit number by threes aloud, which served as a distractor task to prevent rehearsal of the letters.As participants spent more time counting backward, the random letters in their STM started to decay, leading to fewer letter units being recalled. This demonstrates the limited duration of STM and how interference from other cognitive tasks can negatively impact the retention of information. The decay of information in STM occurs when it is not actively maintained or rehearsed, making it difficult for individuals to retrieve that information later on.In conclusion, the results of the Peterson and Peterson (1959) experiment highlight the importance of rehearsal in maintaining information in short-term memory and demonstrate the limitations of STM's capacity and duration. The inability to recall the original random letters after engaging in the distractor task can be attributed to the decay of information in STM due to a lack of rehearsal and interference from the counting task.

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A number that represents a property of the sample (like mean or proportion) is:____.

Answers

A number that represents the property of the sample is the statistics.

Statistics

Statistics refer to that number that describes a particular property of a sample set of numbers. It is the common property shared by all the numbers of the sample set. It involves the collection of data and information and then categorizing them according to their properties and inferences.

'Mean and proportion' is mathematical calculations that can be carried out on statistic number sets.

Mean refers to the average of the number set that is provided to us. It is calculated by adding the numbers and dividing them by the number of terms.

Proportion refers to the fraction of the number set according to some characteristics shared by the numbers.

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create a table of values and graph the following function rule. you must find at least 4 points in your table/graph. then, determine if the function is linear or non-linear, explaining your reasoning. show your work. y=2x^2-5.

then answer if the function is linear or nonlinear. explain?

please someone answer this ASAP I will give brainlist and 100 points!!!!! please.

Answers

The function y = 2x² - 5 is a nonlinear equation and the table of values is

x    0     1    2    3

y    -5    -3   5    13

How to determine the category of the equation?

From the question, we have the following equation that can be used in our computation:

y = 2x² - 5

As a general rule, a linear equation can take any of the following forms

Slope-intercept form: y = mx + xStandard form: Ax + Bx = CPoint slope form: y - Y = m(x - X)

By comparing y = 2x² - 5 to the above forms, we can see that the equation does not take any of the forms represented above

This means that the function is not a linear function

i.e. The function is a nonlinear function

Also, we set x = 0, 1, 2 and 3

So, we have

y = 2(0)² - 5= -5

y = 2(1)² - 5= -3

y = 2(2)² - 5= 5

y = 2(3)² - 5 = 13

So, the table of values is

x    0     1    2    3

y    -5    -3   5    13

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begin{tabular}{|r|l|r|r|} \hline 3 & Below are your numerical inputs for the problem: \\ \hline 4 & Initial Cost (\$) & 390000 \\ \hline 5 & Year 1 Revenues (\$) & 192000 \\ \hline 6 & Year 1 Costs (\$) & 125000 \\ \hline 7 & Inflation & 2.75% \\ \hline 8 & Project Duration (years) & 6 \\ \hline 9 & Depreciation Method & \\ \hline 10 & Tax Rate & \\ \hline 11 & Net Working Capital (\% oft+1 Revenues) & MACRS \\ \hline 12 & Salvage Value (\$) & 28.00% \\ \hline 13 & Cost of Capital & 15.00% & 245000 \\ \hline \end{tabular} How much are the year 1 operating cash flows (OCF)? How much is the depreciation expense in year 3 ? What is the change in Net Working Capital (NWC) in year 2? What is the net cash flow from salvage (aka, the after-tax salvage value, or ATSV)? What is the project's NPV? Would you recommend purchasing the ranch? Briefly explain.

Answers

Information is needed to evaluate the project's financial viability, considering factors such as the initial investment, expected cash flows, cost of capital, and project duration.

To calculate the year 1 operating cash flows (OCF), we need to subtract the year 1 costs from the year 1 revenues:

OCF = Year 1 Revenues - Year 1 Costs

OCF = $192,000 - $125,000

OCF = $67,000

To find the depreciation expense in year 3, we need to determine the depreciation method. The provided information is incomplete regarding the depreciation method, so we cannot calculate the depreciation expense in year 3 without knowing the specific method.

The change in Net Working Capital (NWC) in year 2 can be determined by multiplying the Net Working Capital percentage (given as a percentage of t+1 revenues) by the year 1 revenues and subtracting the result from the year 2 revenues:

Change in NWC = (Year 2 Revenues - Net Working Capital percentage * Year 1 Revenues) - Year 1 Revenues

Without the specific Net Working Capital percentage or Year 2 Revenues values, we cannot calculate the exact change in NWC in year 2.

The net cash flow from salvage (ATSV) is calculated by multiplying the Salvage Value percentage by the Initial Cost:

ATSV = Salvage Value percentage * Initial Cost

ATSV = 28% * $390,000

ATSV = $109,200

To calculate the project's NPV, we need the cash flows for each year, the cost of capital, and the project duration. Unfortunately, the information provided does not include the cash flows for each year, so we cannot calculate the project's NPV.

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The complete question is:

Below are your numerical inputs for the problem: 4 & Initial Cost (\$) & 390000 5 & Year 1 Revenues (\$) & 192000 6 & Year 1 Costs (\$) & 125000  7 & Inflation & 2.75% 8 & Project Duration (years) & 6 9 & Depreciation Method & 10 & Tax Rate & 11 & Net Working Capital (\% oft+1 Revenues) & MACRS 12 & Salvage Value (\$) & 28.00% 13 & Cost of Capital & 15.00% & 245000 How much are the year 1 operating cash flows (OCF)? How much is the depreciation expense in year 3 ? What is the change in Net Working Capital (NWC) in year 2? What is the net cash flow from salvage (aka, the after-tax salvage value, or ATSV)? What is the project's NPV? Would you recommend purchasing the ranch? Briefly explain.

ayoooo whats the answer please ty

ayoooo whats the answer please ty

Answers

I’m pretty sure it’s 3 sorry if it’s wrong

Stacey needs 80 ounces of peaches to
make jam. At the grocery store, peaches
cost $2.80 per pound. How many
pounds of peaches does Stacy need?
Stacey needs [?] pounds of peaches.
HINT: There are 16 ounces in 1 pound.

Answers

Answer:

5 pounds (80 ounces = 5 pounds)

Add the three vectors shown to form a resultant vector \( \vec{R} \), and report your result using polar vector representation. Take \( X=100 \) Ib. (Round the final answers to four decimal places.)

Answers

The polar vector representation of the resultant vector is\(\[\vec R = 100\left( {\sqrt 3 + 1} \right)\left( { - \hat j} \right)\]\) .Therefore,\(\[\tan \theta = \frac{{\vec R_y}}{{\vec R_x}}\)\(= \frac{{ - 100}}{{0}}\) = not define

Three vectors are shown in the question, which are to be added to form the resultant vector, and its polar representation is to be reported after calculating the resultant vector.

The given value of X is 100 Ib.

Therefore, the given three vectors are\(\[\vec {V_1} = 100\sqrt 3 \hat j\]\), \(\[\vec {V_2} = 50\hat i - 100\hat j\]\),  \(\[\vec {V_3} = -50\hat i - 100\hat j\]\\\)

Now, we need to find the resultant vector. It is given by the sum of all the given vectors. Therefore,\(\[\vec R = \vec {V_1} + \vec {V_2} + \vec {V_3}\]\[\vec R = 100\sqrt 3 \hat j + 50\hat i - 100\hat j - 50\hat i - 100\hat j\]\[\vec R = -100\sqrt 3 \hat j - 100\hat j\]\[\vec R = -100 (\sqrt 3 + 1)\hat j\]\)

Now, let's represent this in polar form. The polar representation of a vector is given by\(\[\vec R = R\hat r\]\)

where,\(\[\begin{gathered} R = \left| {\vec R} \right| \hfill \\ \hat r = \cos \theta \hat i + \sin \theta \hat j \hfill \\ \end{gathered} \]\)

First, let's find the magnitude R. Therefore,\(\[\left| {\vec R} \right| = R = 100\left( {\sqrt 3 + 1} \right)\]\)

Now, let's find the angle θ between the vector and the x-axis.

Therefore,\(\[\tan \theta = \frac{{\vec R_y}}{{\vec R_x}}\)\(= \frac{{ - 100}}{{0}}\) = not define

Since the tangent is not defined, the angle θ is equal to 270°.

Therefore,\(\[\hat r = \cos 270\hat i + \sin 270\hat j = - \hat j\]\)

Therefore, the polar vector representation of the resultant vector is\(\[\vec R = 100\left( {\sqrt 3 + 1} \right)\left( { - \hat j} \right)\]\)

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What statement about the graph is true?

What statement about the graph is true?

Answers

The true statement about the graph is

It is a function with the domain {-6 < x < 0} and the range {0 ≤ y ≤ 5}.

What is range?

The range refers to all possible value in the out put of a graph.

The out put is the y coordinate and the possible values here is within the interval

0 ≤ y ≤ 5

What is domain?

The domain refers to all possible value in the input of a graph.

The input is the x coordinate and the possible values here is within the interval

-6 ≤ x ≤ 0

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During a blind taste test of 8 different
sodas, some people were asked to choose
a favorite. Each dot represents one person.
Taste Test
.
A
B
С
F
G
H
D E
Soda
If the ratio of people choosing B to people
choosing H stays the same, how many
people will choose H if the number of people
who choose B increases to 20?
F 6
G4
H5
J 3

During a blind taste test of 8 differentsodas, some people were asked to choosea favorite. Each dot represents

Answers

Answer:

the answer is 5

Step-by-step explanation:

the ratio is 4:1 so if you increase B to 20 you divide by 4 to get 5.

20:5=4:1

Find all the second-order partial derivatives of the following function. у h(x,y) = 4x e^y + 2y +6

Answers

The second-order partial derivatives of the given function are; \(hxx = 0, \\hxy = (4e^y)\\ hyx = (4e^y) \\hyy = 0\)

How to calculate second-order partial derivatives

The second-order partial derivative of this equation

\(h(x,y) = 4x e^y + 2y +6\)

we need to differentiate the function twice with respect to x and y, respectively by using the product rule and chain rule.

For instance, to find hxy, we differentiate h(x,y) with respect to x first, taking y as a constant

\(∂/∂x (h(x,y)) = 4e^y\)

We can also differentiate this result with respect to y, when x is considered as a constant:

\(∂/∂y (∂/∂x (h(x,y))) = ∂/∂y (4e^y) = 0\)

When we do similar differentiation to get this hxx, hyx, hyy

we have the second-order derivatives as follow;

\(hxx = 0\\hxy = (4e^y)\\hyx = (4e^y)\\hyy = 0\)

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500+x is less than or equal to 4500

Answers

Answer:

\(\boxed{\red{500 + x \leqslant 4500}}\\ x \leqslant 4500 - 500 \\ \blue{\underline{x \leqslant 4000}}\)

x≤4000 is the right answer.

Answer:

Less

Step-by-step explanation:

Because we don’t know the value of x.

Other Questions
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