let ∑={0,1} be a finite set of symbols and let l1 and l2 be sets of strings from ∑*. l1l2 is the set {xy | x is in l1, and y is in l2}. l1 = {10, 1}, l2 = {011, 11}, l1l2 = ?

Explanation:

There are 8.35 pounds in a gallon of water. Water weighs 1 gram per cubic centimeter or 1 000 kilogram per cubic meter, i.e. density of water is equal to 1 000 kg/m³; at 25°C (77°F or 298.15K) at standard atmospheric pressure.

Answer:

The distributions of solid wastes produced daily at a commercial facility are normally distributed with a mean of 10 yd3 and a standard deviation of 7 yd3. If you were to make a container size recommendation for this facility, what size would you propose? What important tradeoffs should be considered when selecting the size of the container?

It's quite perplexing to determine the perfect size of container for a facility whose waste quantity varies and is subject to changes frequently. A certain degree of burstiness is present in the distribution of solid waste generated on a daily basis in a commercial facility. However, using the available mean and standard deviation values, we can infer that a container size of 24 yd3 should be sufficient to hold the daily waste generated, considering that it's two standard deviations above the mean.

When selecting a container size, various tradeoffs must be considered. A large container is more efficient, as it would not require to be emptied as frequently, but it might be expensive and may take up more space. A smaller container may be less expensive and take up less space, but it would need to be emptied more frequently, which can result in higher transportation costs and more time spent on waste management. It is therefore essential to strike a balance between the frequency of emptying and the container size to ensure that the waste is managed effectively and efficiently.

The azimuth from north of line CD will be 190°, 57'36.

The azimuth is the angle between North, measured clockwise around the observer's horizon, and a celestial body (sun, moon). It determines the direction of the celestial body.

The angle at B is the interior angle of triangle ABC, so we can find the angle at C by subtracting it from 180°.

The angle at D is the interior angle of triangle BCD, so we can find the angle at C by subtracting it from 180°:

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The plural attributes move to a new table named is d. StadiumSeatReservation.

The plural attribute "SeatReservation" is moved to a new table named "StadiumSeatReservation" which records spectator seat assignments with the primary key "SeatNumber". "Content loaded" typically refers to the process of loading content into a particular platform or application, such as a website, mobile app, or video game. This can include loading images, text, videos, or any other type of digital content. In the context of the given information, "key SeatNumber and a plural attribute SeatReservation which records spectator seat assignments" suggests that there is a database or data structure being used to manage seat assignments for spectators.

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Order the parts needed is NOT a duty of the General Service Technician.

General service technicians are knowledgeable workers who are in charge of carrying out repair tasks on cars and other light vehicles. Customers must interact with these specialists in order to discuss pricing estimates for undertaking car maintenance services. They are required to undertake any required repairs or part replacements as well as visual vehicle inspections. They must possess the necessary skills to operate equipment that mounts and balances vehicle tyres. General service personnel should be able to install car batteries and inspect the electrical systems of vehicles.

Therefore, order the parts needed is NOT a duty of the General Service Technician.

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The image intensifier tube is a device that is used to amplify and brighten an image. The tube consists of three main components: the input screen, the electrostatic lenses, and the output screen.

The main function of each of the components of an image intensifier tube are as follows:

Input Screen: The input screen is a fluorescent layer that gets excited upon being hit by photons. The screen absorbs the X-ray photons and releases a flash of light that can be transformed into electrons. The output of the input screen is photoelectrons, which is responsible for amplifying the image.

Electrostatic Lenses: The electrostatic lenses are a series of charged conductors that help to focus the electrons in a specific direction. The lenses focus the electrons towards the output screen, which is a phosphor-coated screen. It helps to increase the brightness and magnification of the image. The potential difference of the electrostatic lenses controls the level of magnification of the image.

Output Screen: The output screen is the last component of the image intensifier tube. It consists of a phosphor-coated layer that emits light when it is struck by electrons. The output screen can be viewed on a monitor, which displays the amplified and brightened image.

The input screen is the first component of the image intensifier tube. Its function is to convert the X-ray photons into electrons. The input screen is made up of a layer of cesium iodide (CsI) that is deposited on a glass or metal substrate. Upon being hit by the X-ray photons, the input screen becomes excited and emits light. The light is then converted into electrons by a photoemissive material such as cesium or potassium. The electrons then pass through a series of electrostatic lenses that help to focus the electrons towards the output screen.

The output screen is the last component of the image intensifier tube. Its function is to convert the electrons into visible light. The output screen is coated with a phosphor material such as zinc cadmium sulfide (ZnCdS). The electrons that are focused by the electrostatic lenses strike the phosphor material, which then emits light. The light is then magnified and displayed on a monitor.

The image intensifier tube is a device that is used to amplify and brighten an image. The tube consists of three main components: the input screen, the electrostatic lenses, and the output screen. The input screen converts the X-ray photons into electrons, which are then focused by the electrostatic lenses towards the output screen. The output screen converts the electrons into visible light, which is then magnified and displayed on a monitor.

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Answer:

a rock is made up of two or more minerals but a mineral is a natural substance with chemical and physical properties

Answer:

i have no idea

Explanation:

The change in structural efficiency for both bending stiffness and strength when a solid flat panel of unit area and thickness t is foamed to give a foam panel of unit area and thickness h, at constant mass, can be calculated using (Offe*(p/Ps)^1/2)/(Ofs*(p/Ps)^1/2)

To calculate the change in structural efficiency for both bending stiffness and strength when a solid flat panel of unit area and thickness t is foamed to give a foam panel of unit area and thickness h, at constant mass, we need to use the given equation for the modulus E and strength Oy of foams which scale with relative density p/Ps as 3/2 Eles and offe) Ofis where E, of and p are the modulus, strength and density of the foam and Es, ofs and pathose of the solid panel.

First, let's consider the bending stiffness of the panels. The bending stiffness of a panel is proportional to its modulus of elasticity (E) and its moment of inertia (I). The moment of inertia is proportional to the thickness cubed (t^3) for a solid flat panel and (h^3) for a foamed panel. So, the bending stiffness of the solid flat panel is given by E*t^3 and the bending stiffness of the foamed panel is given by (3/2)*Eles*(p/Ps)*h^3.

Now, we can calculate the change in bending stiffness by dividing the bending stiffness of the foamed panel by the bending stiffness of the solid flat panel:

Change in bending stiffness = ((3/2)*Eles*(p/Ps)*h^3)/(E*t^3)

Next, let's consider the strength of the panels. The strength of a panel is proportional to its yield stress (Oy) and its cross-sectional area (A). The cross-sectional area is the same for both panels (unit area), so we only need to consider the yield stress. The yield stress is proportional to the relative density (p/Ps) to the power of 1/2 for both solid and foamed panels. So, the yield stress of the solid flat panel is given by Ofs*(p/Ps)^1/2 and the yield stress of the foamed panel is given by Offe*(p/Ps)^1/2.

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.

Answer:

Engine oil level.

Brake fluid.

Power steering fluid.

Gas metal arc welding (GMAW), sometimes referred to by its subtypes metal inert gas (MIG) welding or metal active gas (MAG) welding, is a welding process in which an electric arc forms between a consumable MIG wire electrode and the workpiece metal(s), which heats the workpiece metal(s), causing them to melt and join.

Explanation:

GMA MIG weiding is aiejrjjrkdkff

CFC-12 recovery equipment has SAE 3/8-inch service fittings, which means that it is designed to work with refrigerants that use this specific fitting. On the other hand, HFC-134a recovery equipment has a different design. It uses 1/2 inch Acme threads or 10mm threads, or sometimes a quick-couple design, depending on the specific equipment.

This difference in fittings is due to the fact that CFC-12 and HFC-134a are different types of refrigerants with different chemical properties. CFC-12 is a chlorofluorocarbon (CFC) that has been phased out due to its harmful impact on the ozone layer. HFC-134a, on the other hand, is a hydrofluorocarbon (HFC) that is considered to be more environmentally friendly.

The different fittings on the recovery equipment are necessary to ensure that the refrigerant is safely and efficiently recovered from the system. Using the wrong fittings can result in leaks, contamination of the refrigerant, and potential safety hazards. Therefore, it is important to use the appropriate equipment for the specific refrigerant being handled.

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Polymorphism is a concept in object-oriented programming that allows objects of different classes to be treated as if they are objects of the same class. It provides a flexible way of working with objects that share a common behavior, but have different implementations.

When it comes to arrays in Java, traditionally, they can only contain objects of the same type. However, with polymorphism, this limitation can be overcome. Because polymorphism allows objects of different classes to be treated as if they are objects of the same class, it's possible to create an array of the parent class and add objects of the child classes to it.

For example, let's say we have a parent class called Shape, and two child classes called Circle and Square. We can create an array of Shape objects and add both Circle and Square objects to it. This is possible because both Circle and Square classes inherit from the Shape class and therefore share a common behavior.

This flexibility allows for more efficient and organized code, as we can now work with objects of different classes as if they are of the same class, simplifying our code.

In conclusion, polymorphism can benefit the usage of arrays in Java by allowing for arrays of parent classes to contain objects of child classes. This provides flexibility and allows for more efficient code.

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Answer:

Total voltage = 24 V

Explanation:

Given:

Volts per rpm = 0.01

Total rpm = 2400

Find:

Total voltage

Computation:

Total voltage = Volts per rpm x Total rpm

Total voltage = 0.01 x 2400

Total voltage = 24 V

The range of force exerted at the end of the rope is; 285.7 N to 1,000 N.

The net horizontal force of the cylinder when it is at equilibrium position can be found by applying Newton's second law of motion. Thus;

∑F = 0

F - μF_n = 0

We are given;

F_n = 5 kN = 5000 N

μ = 0.2

Thus;

F - 0.2(5,000) = 0

F - 1,000 = 0

F = 1,000 N

The strength of the applied force will be increasing as the number of turns of the rope increases. Thus;

Minimum force = Total force/number of turns of rope

Since rope is wrapped three and half times, then;

number of turns = 3.5

Thus;

minimum force = 1,000/3.5

minimum force = 285.7 N

Thus, the range of force exerted at the end of the rope is 285.7 N to 1,000 N.

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The Power method in MATLAB iteratively applies matrix-vector multiplications to estimate the dominant eigenvalue and eigenvector of a sparse matrix A.

Here's an example of a MATLAB function that implements the Power method:

function [dominantEigenvalue, dominantEigenvector] = powerMethod(k, n, A)

   % Initialize the initial guess vector

   x = ones(n, 1);

   % Perform the Power method for k iterations

   for i = 1:k

       % Update the vector using matrix-vector multiplication

       x = A * x;

       % Normalize the vector

       x = x / norm(x);

   end

   % Compute the dominant eigenvalue using Rayleigh quotient

   dominantEigenvalue = (x' * A * x) / (x' * x);

   % Set the dominant eigenvector

   dominantEigenvector = x;

end

To use this function, you can call it with the desired number of iterations (`k`), the size of the matrix (`n`), and the sparse matrix (`A`) as inputs. It will return the dominant eigenvalue (`dominantEigenvalue`) and its corresponding eigenvector (`dominantEigenvector`).

Note that this implementation assumes that the matrix `A` is a square sparse matrix and the initial guess is a vector of 1's. You may need to modify the function according to your specific requirements, such as handling different initial guesses or adding error checking for input validity.

You can use the `disp` function to print out the results within the function or display them outside of the function as per your needs.

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Hai

Your answer will be A.

If you lower the Air Pressure your Object will Float Down ward. The Air Pressure allows it to Fly.

The pressure field created by faster air movement over an airfoil is; A:  higher

When the air hits the front of the wing, the air will flow in a steeper curve upward, than the bottom wing flow which will lead to the creation of a vacuum on top of the wing that pulls more air towards the top of the wing.

Finally, this air above does the same thing but it will move faster as a result of the vacuum pulling it in, and as such the vacuum now lifts the wing. Thus, Faster air movement over an airfoil creates a higher pressure field.

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Answer:

Weight Percentage of Ash = 3.4

Explanation:

Given - Coal containing 21% ash is completely combusted, and the ash is 100% removed in a water contact scrubber. If 10,000 kg of coal is burned per hour with a scrubber flow rate of 1.0 m3/min.

To find - the weight percentage of the ash in the water/ash stream leaving the scrubber is most nearly ?

Solution -

Given that,

Coal Burned Rate = 10,000 kg/hr

                              = \(\frac{10,000}{60 min} * 1 hr *\frac{kg}{hr}\)

                              = 166.6666 kg/min

⇒Coal Burned Rate = 166.6666 kg/min

Now,

Given that,

Ash content in coal = 21 %

⇒Ash in (coal that burned) = 166.6666 × \(\frac{21}{100}\) kg/min

                                             = 34.9999 ≈ 35 kg/min

⇒Ash in (coal that burned) = 35 kg/min

Now,

We know,

Density of water = 1000 kg/m³

Now,

Water flow Rate = \(1\frac{m^{3} }{min} * density\)

                           = 1000 kg/min

⇒Water flow Rate = 1000 kg/min

Now,

Total Mass flow Rate of (Water + Ash stream) = ( 1000 + 35) kg/min

                                                                           = 1035 kg/min

⇒Total Mass flow Rate of (Water + Ash stream) = 1035 kg/min

So,

Weight Percentage of Ash = (Weight of Ash ÷ Total weight of Stream) × 100

                                            = (35 ÷ 1035) × 100

                                            = 3.38 ≈ 3.4

∴ we get

Weight Percentage of Ash = 3.4

In Excel, to build a dashboard we need to add a tab and label it as Dashboard. Then, we set a gray background and copy-paste the three pivot charts we have built in the previous steps. Also, we insert slicers for Employee Last Name and Region.

We ensure these slicers dynamically interact with all three charts by selecting each slicer, right mouse clicking, choosing report connections, and selecting the appropriate check boxes. Finally, we test the dashboard to ensure that all of the charts interact with the slicers and when we drill down into the region and employee last names we see the corresponding pivot tables dynamically update as well.The steps to build a dashboard in Excel are as follows:

Step 1: Add a tab and label it as Dashboard

Step 2: Set the gray background

Step 3: Copy-paste the three pivot charts we have built in the previous steps

Step 4: Insert slicers for Employee Last Name and Region

Step 5: Ensure these slicers dynamically interact with all three charts by selecting each slicer, right mouse clicking, choosing report connections and selecting the appropriate check boxes

Step 6: Test the dashboard to ensure that all of the charts interact with the slicers

Step 7: When we drill down into the region and employee last names we see the corresponding pivot tables dynamically update as well.To create a dynamic dashboard, it is important to choose the correct chart types, slicers, and chart sizes and locations. Slicers are used to filter the data in the pivot tables and charts. Charts in Excel can be easily resized, formatted, and customized to make it more attractive and informative to users.To ensure that all of the charts interact with the slicers, we should select each slicer and check if the charts are changing accordingly. Finally, we need to test the dashboard to ensure that it is working as expected.

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Answer:

My guess is toxicty from gas fumes. Hope this helps

Explanation:

One of the four characteristics of hazardous waste is Toxicity. That is option B.

A hazardous waste is any material or substance that is capable of harming living organisms and making the environment dangerous for to live in.

The characteristics of a hazardous waste include:

Therefore, one of the four characteristics of hazardous waste is Toxicity.

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(a) The mass flow rate of the air entering the control volume is 0.0651 lb/s.    (b) The exit flow area required for the given conditions is 0.0004775 ft².

a. In this problem, we are given the properties of air entering and exiting a control volume. To determine the mass flow rate, we need to apply the principle of mass conservation. By using the ideal gas law and assuming steady state operation, we can calculate the mass flow rate based on the given information, including the inlet and exit conditions, the gas constant, and the specific heat ratio of air.

To solve this problem, we can apply the conservation laws of mass and momentum. Let's go step by step.

(a) First, we need to find the mass flow rate (ṁ).

The mass flow rate can be calculated using the equation:

ṁ = ρ₁ * A₁ * V₁

where:

ṁ = mass flow rate

ρ₁ = density of air at inlet conditions

A₁ = inlet area

V₁ = inlet velocity

We need to find ρ₁, the density of air at inlet conditions. The ideal gas law can be used to calculate the density:

ρ₁ = P₁ / (R * T₁)

where:

P₁ = pressure at inlet conditions

R = specific gas constant

T₁ = temperature at inlet conditions

Given values:

P₁ = 116 psi

T₁ = 1080 °R

A₁ = 3.1 in²

V₁ = 131 ft/s

We need to convert the given values to consistent units before proceeding with the calculations.

Conversions:

P₁ = 116 psi = 116 * 144 lb/ft² = 16624 lb/ft²

T₁ = 1080 °R

A₁ = 3.1 in² = 3.1 / (12^2) ft² = 0.01736111 ft²

V₁ = 131 ft/s

Now we can calculate ρ₁:

ρ₁ = P₁ / (R * T₁)

= 16624 lb/ft² / (53.35 lb/(ft·°R) * 1080 °R)

≈ 0.288 lb/ft³

Now we can calculate the mass flow rate (ṁ):

ṁ = ρ₁ * A₁ * V₁

= 0.288 lb/ft³ * 0.01736111 ft² * 131 ft/s

≈ 0.0651 lb/s

So, the mass flow rate is approximately 0.0651 lb/s.

(b)  To find the exit flow area, we can use the equation of continuity, which states that the mass flow rate is equal to the product of density, velocity, and area. By rearranging the equation, we can solve for the exit flow area, considering the known values of mass flow rate, density, and exit velocity.

(b) Next, we need to find the exit flow area (A₂).

The mass flow rate (m) remains constant throughout the control volume, so we can write:

m = ρ₂ * A₂ * V₂

where:

ρ₂ = density of air at exit conditions

A₂ = exit area

V₂ = exit velocity

To find A₂, we need to rearrange the equation:

A₂ = m/ (ρ₂ * V₂)

We need to find ρ₂, the density of air at exit conditions. Using the ideal gas law:

ρ₂ = P₂ / (R * T₂)

where:

P₂ = pressure at exit conditions

T₂ = temperature at exit conditions

Given values:

P₂ = 29 psi = 29 * 144 lb/ft² = 4176 lb/ft²

T₂ = 720 °R

V₂ = 1148 ft/s

Conversions:

P₂ = 4176 lb/ft²

T₂ = 720 °R

V₂ = 1148 ft/s

Now we can calculate ρ₂:

ρ₂ = P₂ / (R * T₂)

= 4176 lb/ft² / (53.35 lb/(ft·°R) * 720 °R)

≈ 0.145 lb/ft³

Now we can calculate the exit flow area (A₂):

A₂ = ṁ / (ρ₂ * V₂)

= 0.0651 lb/s / (0.145 lb/ft³ * 1148 ft/s)

≈ 0.0004775 ft²

So, the exit flow area is approximately 0.0004775 ft².

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User

Provide final answer in 1-2 lines

ChatGPT

(a) The mass flow rate of the air entering the control volume is [insert calculated value] kg/s.

(b)) The mass flow rate of the air entering the control volume is [insert calculated value] kg/s.

In this problem, we are given the properties of air entering and exiting a control volume. To determine the mass flow rate, we need to apply the principle of mass conservation. By using the ideal gas law and assuming steady state operation, we can calculate the mass flow rate based on the given information, including the inlet and exit conditions, the gas constant, and the specific heat ratio of air.

(b) The exit flow area required for the given conditions is [insert calculated value] in2.

To find the exit flow area, we can use the equation of continuity, which states that the mass flow rate is equal to the product of density, velocity, and area. By rearranging the equation, we can solve for the exit flow area, considering the known values of mass flow rate, density, and exit velocity.

It is important to note that the calculations involve the assumption of ideal gas behavior for air and the steady state condition. Real-world factors such as turbulence, friction, and heat transfer may affect the accuracy of the results. Therefore, it is essential to consider these factors in more complex scenarios or actual engineering applications.

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Cyberactivists are not necessarily cybercriminals. Cyberactivists are individuals or groups that use technology to promote their political or social agendas. While some cyberactivists may engage in illegal activities such as hacking or distributing malware, not all cyberactivism involves criminal activity.

What are some of the security vulnerabilities of using WebApps?

One of the security vulnerabilities of using WebApps is that they can be vulnerable to various forms of attack, such as SQL injection attacks, cross-site scripting attacks, and buffer overflow attacks. These vulnerabilities can be utilized by hackers to gain unauthorized access to sensitive data, disrupt services, or steal confidential information.

Addressing information security issues related to confidentiality, integrity, authenticity, and anonymity is important in relation to threats and attacks because it helps protect sensitive information from unauthorized access or modification. Confidentiality ensures that only authorized personnel can access certain data, while integrity ensures that the data is not altered or tampered with. Authenticity ensures that data comes from a reliable source, while anonymity protects the identity of individuals who may be targeted by cyber criminals.

In conclusion, cyberactivists are not always cybercriminals. The security vulnerabilities of WebApps can expose organizations to various forms of attack, and addressing information security issues related to confidentiality, integrity, authenticity, and anonymity is crucial to protecting sensitive information from threats and attacks.

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Answer:

Investigation or empircial research

Explanation:

gimme brainliest pls

Answer:

Freon Refrigerant

Explanation:

As of January 1, 2020 Freon Refrigerant can no longer be manufactured or imported to the United States. This is because R-22 (the principal component in Freon) has been banned in the states. Along with other greenhouse gasses, due to their contribution to damaging Earth’s ozone layer and global warming.

hope this helps:)

Answer:

Freon Refrigerant Is Now Banned in the US

As of January 1, 2020, a once very popular air conditioning refrigerant can no longer be made in or imported into the United States.

Please give me brainliest -  you get 25% as well! I swear!

Answer:

It is economical

Explanation:

Given data for determining

cost of product = £5 per kg

cost of solvent = £20 per /kg

additional solvent makeup = 10 kg/d

current loss of product = 0.7 kg/h

anticipated recovery of product = 80%

additional service ( utility cost ) = negligible

Determine if it is economical to install the recovery system

cost of product = £5 per kg

cost of solvent = £20 per /kg

additional solvent required = 10 kg / d

cost of additional solvent in a day  = £200 / day  ( £20 per kg * 10 kg / d )

product lost = 0.7 kg/h

product recovered = 0.7 * 80% = 0.56 kg/h

therefore product recovered in a day = 0.56 * 24 = 13.44 kg / day

Next :

calculate income generated from product recovery

13.44 kg/day *  £20 /kg =  £268.88 / day

Determine if it is economical

Income - cost

= £268.88 - £200

=  £68.88  ( hence it is economical )

Known :

D = 12 in = 1 ft

L = 850 ft

Q = 5.6 cfs

hA = 750 ft

hB = 765 ft

PA = 85 psi = 12240 lb/ft²

Solution :

A = πD² / 4 = π(1²) / 4

A = 0.785 ft²

Velocity of water :

U = Q / A = 5.6 / 0.785

U = 7.134 ft/s

Friction loss due to pipe length :

Re = UD / v = (7.134)(1) / (0.511 × 10^(-5))

Re = 1.4 × 10⁶

(From Moody Chart, We Get f = 0.015)

hf = f(L / d)(U² / 2g) = 0.015(850 / 1)((7.134²) / 2(32.2))

hf = 10 ft

PA + γhA = PB + γhB + γhf

PB = PA + γ(hA - hB - hf)

PB = 12240 + (62.4)(750 - 765 - 10)

PB = 10680 lb/ft²

PB = 74.167 psi

In an electric field, a capacitor is a device that stores electrical energy. It has two terminals and is a passive electrical component. Capacitance refers to a capacitor's effect.

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