The vector of linear combination = u is -7/3 i - 8/3 j - k , a) linear combination is xi + yj + zk = (1/3) (-7i -8j-3k) b ) linear combination is 19/3 i + 17/3 j + 6 k
The vector u is \(-7/3\) i - \(8/3\) j - k.
The linear combination 2u + 3v + 5w is 19/3 i + 17/3 j + 6k.
in line with the posed question.
v = (2, 3, 1)
w = (1, 1, 1)
And
3u + 2v + 4w = (1, 2, 3)
From,
v = (2, 3, 1)⇒ v = 2i + 3j + 1k
w = (1, 1, 1)⇒ w = I + j + j
Evaluation :
a). Let u be the vector xi + yj + zk.
Here,
3u + 2v + 4w = (1, 2, 3)
I + 2j + 3k = 3u + 2v + 4w
I + 2j + 3k = 3(xi + yj + zk) + 2(2i + 3j + k) + 4(i + j + k)
I + 2j + 3k = 3xi + 3yj + 3zk + 4i + 6j + 2k + 4i + 4j + 4k
I + 2j + 3k = 3xi + 3yj + 3zk + 8i + 10j + 6k
I + 2j + 3k - 8i -10j -6k = 3xi + 3yj + 3zk
-7i -8j -3k = 3xi + 3yj + 3zk
xi + yj + zk = (1/3) (-7i -8j-3k)
b). The linear combination
2u + 3v + 5w
= 2(-7/3i -8/3j - k ) + 3(2i + 3j + k) + 5(i + j + k)
= -14/3 i -16/3j -2k + 6i + 6j + 3k + 5i + 5j + 5k
= -14/3 i -16/3j -2k + 11i + 11j + 8k
= 19/3 i + 17/3 j + 6k
What is a linear combination of a vector?
A linear combination is of two or more vectors in which the vector obtained by adding two or more vectors (with different directions) which are then multiplied by scalar values.
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A duck flies 60 meters in 4 seconds. What is the duck’s speed?
Answer:
15
Explanation:
speed = distance/time
distance = 60 meters
time = 4 seconds
speed = 60/4= 15 ms-¹
Speed:-
Distance/Time60/415m/ssuppose you have a 6.5 nf capacitor find the charge in microcoulombs stored on it when 1.9v is applied to the capacitors?
When 1.9v is applied to the capacitor with 6.5 n F capacitance, the charge in microcoulombs stored on it is 12.35 µC. The formula for finding the charge stored on a capacitor is: Q = CV
Where, Q = charge stored on the capacitor C = capacitance, V = voltage applied to the capacitor
Explanation:
Substitute the given values in the formula, Q = (6.5 n-F) × (1.9 V)Q = 12.35 n C. The charge is in nano-coulombs. We can convert it into microcoulombs by dividing it by 1000, i.e., Q = 12.35 ÷ 1000Q = 0.01235 µC
To find the charge stored on a 6.5 nF capacitor when a 1.9V voltage is applied, you can use the formula:
Charge (Q) = Capacitance (C) × Voltage (V)
Step 1: Convert the capacitance from nano-farads to microfarads:
6.5 nF = 0.0065 μF
Step 2: Multiply the capacitance by the voltage:
Q = 0.0065 μF × 1.9V
Step 3: Calculate the charge:
Q = 0.01235 μC
Therefore, the charge stored on the 6.5 n-F capacitor when a 1.9V voltage is applied is 0.01235 microcoulombs.
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Examine the Pythagorean theorem below. In this form you can find the length of the hypotenuse c) of a right triangle if you know the lengths of the two short sides (a &). Solve this equation for the short side b. If you need to indicate a square root in your answer, type it like this: root * (e + f) to mean the square root of the sum (e + f) . For example, the equation below can be typed as c = root (a^ ^ 2+b^ ^ 2)
Answer:
what is the number
Explanation:
the levels of radiation detected by a geiger counter when brought near a sample of radium. the amount of radiation it takes to activate a polyethylene container (turn it radioactive). the amount of radiation to which an airplane passenger is exposed on a transcontinental flight. the total amount of radiation a spacecraft computer chip can withstand before failing because of radiation damage
Radium generates high radiation levels, while polyethylene resists activation.
When a geiger counter is brought near a sample of radium, it will detect relatively high levels of radiation. Radium is a highly radioactive element, emitting alpha, beta, and gamma radiation.
The geiger counter measures these emissions and provides a reading indicating the intensity of radiation.
The amount of radiation required to activate a polyethylene container, turning it radioactive, is dependent on various factors, such as the thickness and composition of the container.
However, polyethylene is generally considered a poor candidate for activation through radiation exposure, as it is relatively resistant to becoming radioactive.
During a transcontinental flight, an airplane passenger is exposed to cosmic radiation, primarily in the form of high-energy cosmic rays. The exact amount of exposure varies based on factors like altitude, flight duration, and the flight path taken.
However, the level of radiation exposure during a typical transcontinental flight is generally considered low and poses no significant health risks.
The total amount of radiation a spacecraft computer chip can withstand before failing due to radiation damage depends on the chip's design and the radiation-hardening techniques employed.
Specialized chips used in spacecraft are typically designed to withstand higher levels of radiation than commercial chips. They can tolerate radiation doses ranging from several thousand to millions of grays, depending on the specific chip and its protective measures.
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How to Tell If an Element Is Paramagnetic or Diamagnetic
To determine if an element is paramagnetic or diamagnetic, one can perform a magnetic susceptibility test.
Paramagnetic and diamagnetic elements refer to the magnetic properties of elements and molecules. Paramagnetic materials are attracted to a magnetic field, while diamagnetic materials are repelled by a magnetic field.
Paramagnetic substances have a positive magnetic susceptibility, meaning they are attracted to a magnetic field and experience an increase in magnetic polarization. Diamagnetic substances have a negative magnetic susceptibility, meaning they are repelled by a magnetic field and experience a decrease in magnetic polarization.
Another way to determine the magnetic properties of an element is to observe its behavior in a magnetic field. If an element experiences attraction to a magnetic field, it is paramagnetic, and if it experiences repulsion, it is diamagnetic.
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The atomic spectrum of lithium has a strong red line at 670.8 nm.
(a) What is the energy of each photon of this wavelength?
(b) What is the energy of 1 mole of these photons?
(a) The energy of each photon of the wavelength 670.8 nm is approximately 2.93 × 10⁻¹⁹ Joules.
(b) The energy of 1 mole of these photons is approximately 1.76 × 10⁵ Joules.
(a) To calculate the energy of each photon of the given wavelength, we can use the formula:
Energy = (Planck's constant × speed of light) / wavelength
First, we need to convert the wavelength from nanometers (nm) to meters (m):
670.8 nm = 670.8 × 10⁻⁹ m
Now we can substitute the values into the formula:
Energy = (6.626 × 10⁻³⁴ J·s × 3.0 × 10⁸ m/s) / (670.8 × 10⁻⁹ m)
≈ 2.93 × 10⁻¹⁹ J
Therefore, the energy of each photon of the wavelength 670.8 nm is approximately 2.93 × 10⁻¹⁹ Joules.
(b) To calculate the energy of 1 mole of these photons, we can use Avogadro's number (6.022 × 10²³) to convert the number of photons to moles:
Energy of 1 mole = Energy of each photon × Avogadro's number
Energy of 1 mole = (2.93 × 10⁻¹⁹ J) × (6.022 × 10²³)
≈ 1.76 × 10⁵ J
Therefore, the energy of 1 mole of these photons is approximately 1.76 × 10⁵ Joules.
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1) Suppose you place an object in front of a concave mirror. Which of the following statements must be true? (There could be more than one correct choice.) A) The image of the object will always be smaller than the object. B) No matter where you place the object, a real image of the object will be formed. C) The image of the object will always be inverted. D) If you position the object between the mirror and the focal point of the mirror, its image must be upright and virtual. E) No matter where you place the object, the image of the object will always be virtual and upright.
Answer:
C
Explanation:
because the concave mirror is always inverted
d ) when object is between focus and mirror , image formed is always virtual and erect
What is a Concave mirror ?
A concave mirror has a reflective surface that is curved inward and away from the light source .
a) Incorrect because image can be equal to , smaller then , and bigger then the object
b) and c) Incorrect when object is between focus and mirror , image formed is virtual and erect
d ) Correct option when object is between focus and mirror , image formed is always virtual and erect
e) Incorrect except one case in all other cases nature is real and inverted
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13. Bonnie and Dimitri want to find out about the motion of cars traveling on a stretch of highway. They
measure out a segment on the highway and measure the time it takes for a car to pass along that segment.
Using this data, which of the following pieces of data are they collecting?
A Instantaneous acceleration
B Average speed
C Average acceleration
D Instantaneous speed
Using this data the quantity which is trying to find is average speed thus option C is correct.
Average speed is defined as the total distance traveled in total time taken it means that we can calculate the average speed obtained by an object.
Average Speed = Total distance travelled/Total time taken
It's S.I unit is m/s
Average speed is a scalar quantity it means that it has only magnitude not direction. MKS unit is refers to meter, kilogram, seconds. It forms the base of international systems of units though SI has since been redefined by different fundamental constants.Using this data the quantity which is trying to find is average speed thus option c is correct.
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a. Calculate the gravitational force between two objects of mass 25 kg and 20 kg separated by a distance of 5 m. (1.33 × JO⁹N) 1030 1.
Answer:
The gravitational force between two objects of mass 25 kg and 20 kg separated by a distance of 5 m is \(1.334 * 10^-9\)
Explanation:
Given
Mass of the body (MA)= 25kg
Mass of the other body (MB)= 20kg
Distance of separation between them (R)= 5m
We know that
The gravitational force between two masses
\(F= (G*MA*MB)/R^2\) N
where
\(G=6.67 * 10^-11 m^3 kg^-1 s^-2\)
Putting all the values in the above formula,
\(F=(6.67*10^-11 *25*20)/5*5\) N
\(F=1.33*10^-9 N\)
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A boy is pulling his two sisters on a sled.
If one sister weigh 30.0 kg, the other
weights 40.0 kg, and the coefficient of
kinetic friction is 0.120, how much force
is required to pull the sled?
[?] N
Answer:
Explanation:
The oly way we can figure this out is if the boy is pulling the sled at a constant velocity. If not, we need a value for acceleration, and you don't have that here. If the boy is pulling the sled at a constant velocity, then the value for acceleration is 0, making this a really simple problem. I'm going with that, since there is no way to answer you otherwise. If velocity is not constant, please either repost the question or put it in the notes section under the question as it stands. If acceleration is 0, then
F - f = ma becomes
F - f = m(0) which is
F - f = 0 and
F = f which says that the applied force is the same as the frictional force. We need then to find the frictional force, which has an equation of
f = μ\(F_n\) where normal force is the same as the weight of the 2 girls. We will find that, then:
Each girl's mass is different so the normal force/weight equation is
w = (30.0)(9.8) + (40.0)(9.8) to get
w = 290 + 390 and
w = 680. Plug that into the frictional force equation:
f = (.120)(680) so
f = 82N
A bullet of mass 50 gm is moving with the velocity of 720 km/hr. Calculate the kinetic energy of the bulet
Answer:
K = 5706.6 J
Explanation:
Given that,
The mass of a bullet, m = 50 g = 0.05 kg
The velocity of the bullet, v = 720 km/hr = 477.77 m/s
We need to find the kinetic energy of the bullet. The kinetic energy of an object is due to its motion. It can be given by the formula as follows :
\(K=\dfrac{1}{2}mv^2\\\\=\dfrac{1}{2}\times 0.05\times 477.77 ^2\\\\K=5706.6\ J\)
So, the required kinetic energy of the bullet is equal to 5706.6 J.
FILL IN THE BLANK. kitchen lighting ____ permitted to be supplied by the two 20-ampere small-appliance circuits required for the kitchen and dining room area.
Kitchen lighting is permitted to be supplied by the two 20-ampere small-appliance circuits required for the kitchen and dining room area according to the National Electric Code (NEC) 210.11.
These circuits are designed to provide power for small appliance, such as toasters, blenders, and coffee makers, and can also be used to supply power to the kitchen lighting. However, it's important to note that the total load on these circuits should not exceed the maximum amperage rating of 20 amps. This means that the combined load of all the appliances and lighting fixtures connected to these circuits should not exceed 20 amps. In addition to using the small-appliance circuits, it's also common to use separate dedicated circuits for specific electrical loads, such as for the refrigerator or for a kitchen island lighting. It's important to consult a licensed electrician for proper installation and to ensure that the electrical system is safe and meets all relevant codes and regulations.
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A car traveling 35 km/hr accelerates to a speed of 45 km/hr in .25 hr. What is its acceleration
Answer:
a=40Km/hr^2
Explanation:
A car of weight 300N moved through a distance of 10m when pushed by 3 students
a. Calculate the work done by the three students
b. Explain the energy transfer involved
The work done by the three students is 3,000 J.
The energy transferred in the process is 3,000 J.
What is work done?Work done is the product of force and distance moved by the object.W = Fd
The work done by the three students is calculated as follows;
W = 300 x 10
W = 3,000 J
What is energy transfer?This is means by which energy is converted from one form to another.The energy transferred in the process is determined by work energy theorem.
E = W
E = 3,000 J
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What units are used to measure mass and weight?
A boat uses its motor to increase its speed from 5 m/s to 7 m/s. If the boat has a mass of
250 kg, what was the impulse applied by the motor?
Answer:
J = 500 kg-m/s
Explanation:
Given that,
Initial speed of the motor, u = 5 m/s
Final speed of the motor, v = 7 m/s
Mass of the boat, m = 250 kg
We need to find the impulse applied by the motor. We know that impulse is equal to the change in momentum. It is represented by letter J.
J = m(v-u)
J = 250 (7-5)
J = 500 kg-m/s
Hence, the impulse applied by the motor is 500 kg-m/s.
What are the similarities and differences between light waves, water waves, and sound waves?
Answer:
Light waves- electromagnetic waves
water waves- combination of both longitudinal and transverse motions
sound waves- mechanical waves
They all oscillations that carry energy from one place to another.
Explanation:
hi
Similarities between light waves , water waves and sound waves:
Being a wave light waves , water waves and sound waves they all have amplitude , wavelength and frequency .They all have damped oscillations i.e. as far they go their amplitude and intensity decreases with distance.Differences between light waves, water waves, and sound waves:
Light waves are electromagnetic waves, while water waves and sound waves are mechanical waves. Light waves are not a mechanical wave; it can travel through a vacuum such as the empty parts of outer space.Sound and water waves are mechanical waves it means, they require a medium to travel through.The medium may be a solid, a liquid, or a gas, and the speed of the wave depends on the material properties of the medium through which it is traveling.
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a block weighing 14 n, which slides without friction on a 40o incline, is connected to the top of the incline by a light spring of unstretched length 0.45 m and force constant 120 n/m, as shown below. (a) how far from the top of the incline does the block rest in equilibrium? (b) if the block is displaced slightly down the incline, what is the period of the ensuing oscillations?
The block rests at a distance of 0.075 m from the top of the incline in equilibrium. The period of oscillations of the block when it is displaced slightly down the incline is 0.77 seconds.
To find how far from the top of the incline the block rests in equilibrium, we need to balance the weight of the block with the force from the spring. At equilibrium, the spring force must be equal and opposite to the weight of the block.
The weight of the block is given as 14 N, which we can resolve into its components parallel and perpendicular to the incline.
Weight perpendicular to the incline = 14 N * cos(40°) = 10.7 N
Weight parallel to the incline = 14 N * sin(40°) = 8.98 N
The force from the spring is given by Hooke's law:
F = -kx
where F is the force from the spring, k is the spring constant, and x is the displacement from the equilibrium position.
At equilibrium, the displacement from the unstretched length of the spring is zero, so the force from the spring is also zero.
Equating the weight parallel to the incline with the force from the spring, we get:
8.98 N = -kx
Substituting the given values for k and solving for x, we get:
x = -8.98 N / (-120 N/m) = 0.075 m
To find the period of oscillations of the block when it is displaced slightly down the incline, we can use the formula for the period of a mass-spring system:
T = 2π * sqrt(m/k)
where T is the period of oscillations, m is the mass of the block, and k is the spring constant.
To find the mass of the block, we can use its weight:
Weight = m * g
where g is the acceleration due to gravity.
Solving for m, we get:
m = Weight / g = 14 N / 9.81 m/s^2 = 1.43 kg
Substituting the given values for m and k, we get:
T = 2π * sqrt(1.43 kg / 120 N/m) = 0.77 s
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yellow light minus magenta light equals
calculate the binding energy e of the nitrogen nucleus 14 7n (1ev=1.602×10−19j).
The binding energy of the nitrogen nucleus 14^7N is 1.281 MeV.
The binding energy of a nucleus can be calculated using the Einstein's mass-energy equivalence equation, E = m. c ^2, where E is the energy, m is the mass defect, and c is the speed of light.
where:
E is the binding energy in joules
m is the mass of the nucleus in kilograms
c is the speed of light in meters per second
The mass of a nucleus is always less than the sum of the masses of its constituent parts. This is because some of the mass is converted into energy when the nucleus is formed. The binding energy of a nucleus is a measure of how much energy is required to break the nucleus apart.
The mass of the nitrogen nucleus 14^7N is 14.00307 amu. The mass of a proton is 1.00783 amu and the mass of a neutron is 1.0087 amu. There are 7 protons and 7 neutrons in a nitrogen nucleus, so the total mass of the constituent parts is 7 * 1.00783 amu + 7 * 1.0087 amu = 14.07261 amu. The difference between the mass of the nucleus and the mass of its constituent parts is the binding energy. The binding energy of the nitrogen nucleus 14^7N is therefore 14.07261 amu - 14.00307 amu = 0.06954 amu.
The binding energy of the nitrogen nucleus 14^7N in joules is calculated by multiplying the mass of the nucleus in amu by the speed of light squared in meters per second and then converting the result to joules using the conversion factor 1 eV = 1.602 × 10^-19 J. The binding energy of the nitrogen nucleus 14^7N in joules is therefore 0.06954 amu * (3.0 × 10^8 m/s)^2 * (1.602 × 10^-19 J/eV) = 1.281 MeV.
Therefore, the binding energy of the nitrogen nucleus 14^7N is 1.281 MeV.
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According to the Two Column Model of Air Pressure, the Column of Air becomes ____________________ when the air inside the column cools. Narrower
According to the Two Column Model of Air Pressure, the column of air becomes narrower when the air inside the column cools.
In the Two Column Model of Air Pressure, the atmosphere is represented by two vertical columns of air, one on either side of the equator. The column of air is influenced by temperature changes, among other factors. When the air inside the column cools, it becomes denser and contracts. This contraction causes the column of air to become narrower.
To understand this concept, let's consider an example. Imagine a column of air in the atmosphere that extends from the Earth's surface to the top of the atmosphere. If the air inside this column cools, let's say due to a cold front moving in, the molecules in the air slow down and come closer together. As a result, the column of air becomes narrower.
In conclusion, according to the Two Column Model of Air Pressure, the column of air becomes narrower when the air inside the column cools. This is because cooling causes the air to contract and the molecules to come closer together.
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if the. same two elements were detected in a distant star that was moving away from earth, how would the spectral lines appear
The spectral lines would appear shifted towards the red end of the spectrum.
Spectral lines :
When the light of a star is separated into its various colors, it is known as a spectrum.
Each element produces a characteristic set of lines at specific wavelengths, known as its spectral lines, when it is heated to a high temperature.
If a substance's spectrum is split into a band of light, the band will contain dark lines at particular wavelengths, referred to as spectral lines.
Spectral lines can be used to determine the composition, temperature, and motion of stars.
When the same two elements were detected in a distant star that was moving away from Earth, the spectral lines would appear to be shifted toward the red end of the spectrum.
This phenomenon is known as redshift.
Redshift is a phenomenon in which the wavelength of light emitted by an object moving away from an observer is stretched, resulting in a shift towards the red end of the spectrum.
It happens because the object's motion is causing the wavelength of the light waves to become longer as they travel through space.
It is due to the Doppler effect, which results in a shift in the wavelength of the light that is emitted or absorbed by a celestial object.
The Doppler effect is the change in frequency or wavelength of a wave in relation to an observer's motion.
When an object is moving closer to an observer, it appears to have a higher pitch or shorter wavelength.
When the object is moving away from the observer, it appears to have a lower pitch or longer wavelength.
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Which two factors mainly affect ocean tides on Earth?
a. Earth's revolution about both the Moon and the Sun.
b. The Moon.
c. The Sun.
d. The pull of distant planets.
Answer:
a. Earth's revolution about both the Moon and the Sun.
b. The Moon.
Which types of electromagnetic waves have longer wavelengths than the waves that make up visible light? select three options. radio waves gamma rays microwaves infrared light ultraviolet light x-rays
Answer:
infrared light have longe rwave length
The three electromegnetic waves that have longer wavelengths that make up visible light will be microwaves, radio waves, and infrared light.
What is an electromagnetic wave?
EM waves are another name for electromagnetic waves. Electromagnetic radiations are made up of electromagnetic waves created when an electric field collides with a magnetic field.
Electromagnetic waves may alternatively be defined as the combination of oscillating electric and magnetic fields. Maxwell's equations are solutions to electromagnetic waves.
Of all electromagnetic waves, radio waves have the longest wavelength.
Hence the three electromegnetic waves that have longer wavelengths that make up visible light will be microwaves, radio waves, and infrared light.
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What will happen if the positive and negative connections on the voltmeter are reversed?
If the applied voltage is polarised in the opposite direction (negative on red and positive on black), the metre will display "backwards."
What happens when polarity reverses?Some devices may be electrically charged at all times if an outlet has reverse polarity. Electricity will flow to the switch in a properly connected outlet; with reversed polarity, it will be present in the item even when it is not switched on.Reverse polarity protection is an internal circuit that ensures the device is not destroyed if the polarity of the power source is reversed. The reverse polarity protection circuit disables power to the transmitter or transducer's sensitive electronic circuitry.If you reside in a house that has had amateur electrical work done, there's a strong chance you have some outlets with reversed polarity. That essentially means that some of your channels may surprise you. Uh oh! While not all shocks are lethal, they are all painful and unpleasant. Only a qualified electrical contractor in North Scottsdale, AZ can perform electrical repairs in your home.
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A motorcycle patrolman starts from rest at A two seconds after a car, speeding at the constant rate of 120km/h, passes point A. If the patrolman accelerates at the rate of 6m/s^2 until he reaches his maximum permissible speed of 150km/h, which he maintains, calculate the distance from point A to the point at which be overtakes the car
The distance from point A to the point at which the patrolman overtakes the car is 2700 meters.
The distance from point A to the point at which the motorcycle patrolman overtakes the car is 2700 meters. Here's a step-by-step breakdown of the calculations:
Step 1:
Distance covered by the car in 2 seconds:
Distance = Speed * Time
Speed = 120 km/hr = (120/3600) m/s = (1/30) m/s
Time = 2 seconds
Distance = (1/30) m/s * 2 s = 2/30 km = (2/30) * 1000 m = 66.67 m
Step 2:
Calculating the time taken by the motorcycle patrolman to reach a speed of 150 km/h:
Using the equation v = u + at
Initial velocity (u) = 0 m/s
Final velocity (v) = 150 km/h = (150000/3600) m/s = (125/3) m/s
Acceleration (a) = 6 m/s^2
(125/3) m/s = 0 m/s + 6 m/s^2 * t
Solving for t:
t = (125/3) / 6 sec = (125/3) * (1/6) sec = 125/18 sec
Step 3:
Calculating the distance covered by the motorcycle patrolman in the first (125/18) seconds:
Using the equation s = ut + (1/2)at^2
Initial velocity (u) = 0 m/s
Acceleration (a) = 6 m/s^2
Time (t) = 125/18 sec
s = 0 * (125/18) + (1/2) * 6 * ((125/18)^2) = 1562.5/9 m
Step 4:
Calculating the time taken by the motorcycle patrolman to overtake the car:
Let the time taken be t sec
Speed of the car = 120 km/hr = (100/3) m/s
Distance covered by the car in time t = (100/3) m/s * t
Distance covered by the motorcycle patrolman in time t = Distance covered by the car in time t + Distance covered by the motorcycle patrolman in the first (125/18) sec
Time taken = (Distance to be covered) / (Speed of the motorcycle patrolman)
= (Distance covered by the motorcycle patrolman in time t - Distance covered by the motorcycle patrolman in the first (125/18) sec) / [(150000/3600) m/s]
= [(100/3) * t + 1562.5/9 - 1562.5/9] / [(150000/3600)] sec
= [(100/3) * t] / [(150000/3600)] sec
= (1/45) * t sec
The two times should be equal, so we can set up the equation:
(100/3) * t + 1562.5/9 = (1/45) * t
Solving for t:
(3200/45) * t + 1562.5/9 = t
[(3200/45) - (1/45)] * t = 1562.5/9
t = (1562.5 * 45) / (9 * 3199) sec
Step 5:
Distance from point A to the point at which the motorcycle patrolman overtakes the car:
Distance = Distance covered by the motorcycle patrolman in the first (125/18) sec + Distance covered by the motorcycle patrolman in time t
Distance = 1562.5
/9 + [(100/3) * t + 1562.5/9 - 1562.5/9] m
= 1562.5/9 + (100/3) * (1562.5 * 45) / (9 * 3199) m
= 1562.5/9 + 10425/3199 m
= [(1562.5 * 3199) + 10425] / 28791 m
= 2700 m
Therefore, the distance from point A to the point at which the motorcycle patrolman overtakes the car is 2700 meters.
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State two units bigger than kilogram and how are they related to kilogram
Answer:
quintal and metric tone.
Explanation:
1 quintal= 100kg
1 metric =1000kg
quintal measures mass of cars, trucks etc, but metric measures bigger things like cargo ships
hope it helps
what causes an object to stay ar rest
Answer:
Inertia is the tendency of all objects to resist any change in motion. Inertia causes a moving object to stay in motion at the same velocity (speed and direction) unless a force acts on it to change its speed or direction. It also causes an object at rest to stay at rest.
What is it called when you pull a line off your reel and cast it?
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