Let’s say that the father in the second couple you’re working with also has a genetic predisposition to have children of a specific gender—but in this case, girls. Given that information, these are the probabilities the couple has before taking the test:

• The probability of the couple having a girl is 95%.
• The probability of the couple having a boy is 5%.
• The probability that the test is correct is 85%.
• The probability that the test is incorrect is 15%.



Question 1
Use this information to determine the values for the tree diagram.

Answer:

96% percent and fraction is 24/25

Answer: Down below

Step-by-step explanation:

64 % = 16 / 25

21 / 50 = 0. 42

9 / 25 = 36 %

2 / 5 = 40 %

/ = divide okay

The solution to the system is approximately x = 1.58, y = 1.95.

We can substitute y from the first equation into the second one:

2x + 3(5/2x - 1) = 12,

which simplifies to:

2x + 7.5x - 3 = 12,

and further simplifies to:

9.5x = 15.

Solving for x, we get:

x = 15/9.5 ≈ 1.58.

Substituting x = 1.58 back into the first equation y = 5/2x - 1, we find:

y = 5/2*1.58 - 1 ≈ 1.95.

Therefore, the solution to the system is approximately x = 1.58, y = 1.95.

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Solve the following system using substitution.

y = 5/2 x -1

2x + 3y = 12.

Answer:

Step-by-step explanation:

The minimum value of C is 23, which can be achieved when x = 2 and y = 4. This satisfies both of the given constraints and falls within the specified range for x and y.

CD with the points at the end (like a number line) with the numbers C, D go in the last box.

The ones in forms of angles with the letters C, T, M in the first one

The correct figure matched to each label is given below.

When two lines or rays intersect at a single point, an angle is created. The vertex is the term for the shared point. An angle measure in geometry is the length of the angle created by two rays or arms meeting at a common vertex.

Given:

We have 5 diagrams.

The first diagram represents the segment CD.

The second diagram represents a ray CD.

The angle measure of CTM is represented by the third diagram.

The angle measure of TCM is represented by the fifth diagram.

And the free line from the both sides CD is given in the fourth diagram.

The matched images are given in the attached image.

∠CTM = Image 1 (attached)

CD = Image 2 (attached)

Therefore, the matched images are given above.

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The velocity of the wind will be 50 km per hour.

The quantity which has magnitude, direction and follows the law of vector addition is called a vector.

A motorcyclist riding North along a straight road at 50 km per hour observes that the wind appeared to have a velocity of 50 km per hour from the direction North 60 degrees West.

Then the velocity of the wind will be

Let x be the speed of the wind. Then we have

x² = 50² + 50² - 2 x 50 x 50 x cos 60°

x² = 2500 + 2500 - 2500

x² = 2500

x = 50 km per hour

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The critical value of f(x) = 5x⁶ - 3x⁵ is x = 0.5 which is also its maxima point

f(x) = 5x⁶ - 3x⁵

differentiation w.r.t x

=> f'(x) = 30x⁵ - 15x⁴

Putting f'(x) = 0

30x⁵ - 15x⁴ = 0

=> x⁴(30x - 15) =0

=> 30x - 15 = 0

=> x = 15/30

=> x = 0.5 , 0

Critical number is 0.5 , 0

(B) To find where f(x) is increasing

for x > 0.5 ,

(30x-15) > 0 => x⁴(30x - 15) > 0

Therefore , f(x) is increasing at ( 0.5 , ∞ )

(C)To find where f(x) is decreasing

for x < 0.5 ,

(30x-15) < 0 => x⁴(30x - 15) < 0

Therefore , f(x) is decreasing at ( -∞ , 0.5)

(D) Differentiation f'(x) again w.r.t to x

f'(x) = 30x⁵ - 15x⁴

f"(X) = 150x⁴ - 60x³

Substituting critical values of x

=> 150(0.5)⁴ - 60(0.5)³

=>9.375 - 7.5

=> -1.875 < 0 , Hence , x = 0.5 is point of maxima

(E) no point of minima

Similarly , we can solve other parts

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The equilibrium number of firms will be the smallest integer such that the price is 6 or higher. This occurs when n = 2. At this equilibrium, the price is P = 6, the output of each firm is y = 3/2, the industry's output is Y = 3, and the profit of each firm  = -2.

a) Supply curve of an individual firm

The price received by the individual firm will be P. Its demand curve is given by

D(p) = 20 - p.

Each firm chooses output to maximize its profit. Profit maximization occurs when the price is equal to the marginal cost. Mathematically,

P = MC(y)

4y = P

y = P/4

Thus the supply curve of the firm is y = P/4

b) The smallest price at which the product can be sold. The product can be sold at the minimum of the supply curve, which is y = 0, given P ≥ 0. Therefore the smallest price is P = 0.

c) Equilibrium price and output

Equilibrium occurs when each firm is producing at its profit-maximizing output given the output of other firms. Let the number of firms in the industry be n. The output of the industry is Y = ny. The industry supply curve is given by

S(P) = nP/4

The equilibrium price intersects the industry supply curve with the demand curve. Thus the equilibrium price satisfies

S(P) = Y

nP/4 = 20 - P

=> P = 80/(4 + n).

The equilibrium number of firms is the number that makes the industry supply curve equal to the demand curve. Thus

20 - P = nP/4

=> P = 80/(4 + n)

=> n = (80 - 20P)/P

= 20/P - 4.

Thus the equilibrium number of firms is a function of P and can range between 1 and infinity, but it must be an integer. The equilibrium output of each firm is given by

y = P/4 = 20/(4n + n²)

The equilibrium output of the industry is given by

Y = n

y = 5/P = (n² + 4n)/80.

d) Equilibrium number of firms with new demand curve D(p) = 21 - p.

The intersection of this curve with the marginal cost curve is at p = 21/5. This is greater than the minimum possible price of 0. Thus there is a positive profit to be earned in this industry, and new firms can enter the market.

e) Equilibrium price and output with new demand curve with the new demand curve D(p) = 21 - p, the industry supply curve and the equilibrium price are as given in part (d). The equilibrium output of each firm is given by y = P/4 = 21/20, and the equilibrium output of the industry is given by Y = 21/4.

f) Equilibrium number of firms, price, output, and profit with demand curve D(p) = 24 - p. This demand curve intersects the marginal cost curve at p = 6. The minimum possible price is P = 0. Thus there is a range of prices from 0 to 6 where firms can profit positively.

The equilibrium number of firms will be the smallest integer such that the price is 6 or higher. This occurs when n = 2. At this equilibrium, the price is P = 6, the output of each firm is y = 3/2, the output of the industry is Y = 3, and the profit of each firm is (6)(3/2) - (2)(2(3/2)² + 8) = -2.

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Answer:

  4 pairs

Step-by-step explanation:

You want the number of pairs of integers (m, n) such that m > n and m² -n² = 96.

The difference of squares is factored as ...

  m² -n² = (m -n)(m +n)

In order for the difference to be 96, these factors must be factors of 96.

The prime factorization of 96 is ...

  96 = 2^5 · 3

The number of divisors of 96 is the product of the exponents of these factors, each increased by 1:

  (5+1)(1+1) = 12

That is, there are 12/2 = 6 factor pairs ab such that a<b. They are ...

   96 = 1·96 = 2·48 = 3·32 = 4·24 = 6·16 = 8·12

The values of m and n relate to the values of 'a' and 'b' by ...

  m = (a+b)/2

  n = (b-a)/2

In order for m and n to be integers, the values of 'a' and 'b' must both have the same parity. That is, they must both be even, or both be odd. This eliminates the factor pairs 1·96 and 3·32, leaving 4 (a, b) pairs, hence 4 (m, n) pairs. Possible ordered pairs are ...

  (m, n) ∈ {(25, 23), (14, 10), (11, 5), (10, 2)} . . . . . 4 pairs

Required area of the composite figure is 69 cm²

What is area of a composite shape?

the area covered by any composite shape. A composite shape is a shape in which some polygons are put together to form the required shape is called the area of composite shapes . These figures can consist of combinations of triangles, rectangles, squares etc. To determine the area of composite shapes, divide the composite shape into basic shapes such as square, rectangle,triangle, hexagon, etc.

Basically, a compound shape consists of basic shapes put together. This is also called a "composite" or "complex" shape. This mini-lesson explains the area of compound figures with solved examples and practice questions.

Here in this figure, we have two figures.

First one is rectangle and second one is triangle.

Length and breadth of the rectangle are 12 cm and 4 cm respectively.

So, area = Length × Breadth = 12 × 4 = 48 cm²

Again height of the triangle is (11-4) = 7 cm and base of the triangle is (12-6) = 6 cm.

So, area of the triangle = 1/2 × 7 × 6 = 3×7 = 21 cm²

Now if we add both area of rectangle and triangle then we will get area of the composite figure.

So, required area of the composite figure is ( 48+21) = 69 cm²

Therefore, option A is the correct option.

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(a) f(4) = -1, f(-6) = 1 and f(6) = 1

(b) x = 4 and -4, x = 0 and x = -7

(c) t = -8

(d) The set x = {-4, -3, -2, -1, 0, 1, 2, 3, 4}

A function is a relation from a set A to a set B where the elements in set A only maps to one and only one image in set B. No elements in set A has more than one image in set B.

(a) The values of f(x) for the given values of x can be found from the graph by looking at the y values corresponding to the given x values.

f(4) = -1

f(-6) = 1

f(6) = 1

(b) By looking to the y values as the given numbers, we can find corresponding x values.

f(x) = -1 ⇒ x = 4 and -4

f(x) = -5 ⇒ x = 0

f(x) = 2 ⇒ x = -7

(c) We have to calculate the point (t, 3) where the y value is 3.

f(x) = 3 when x = -8

So t = -8

(d) f(x) < 0 for the set of values of x {-4, -3, -2, -1, 0, 1, 2, 3, 4}

Hence using the diagram of the graph of a function, we can compute all the values.

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Answer:

(a) f(4) = -1, f(-6) = 1 and f(6) = 1

(b) x = 4 and -4, x = 0 and x = -7

(c) t = -8

(d) The set x = {-4, -3, -2, -1, 0, 1, 2, 3, 4}

Step-by-step explanation:

Answer: a, b, and finally d

Step-by-step explanation:

Hypothesis test used to test the batting average of the two given team national league and American league is given z-test.

As given in the question,

Given : Mean batting for American league is not equal to Mean batting for National league.

Therefore, hypothesis test used to test the batting average of the national league and American league is given z-test.

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The given expressions, when A=1, B=0, and C=1, X evaluates to 1.001; when A=B=C=1, X evaluates to 1.111; and when A=B=C=0, X evaluates to 0.000. These evaluations are based on the given values of A, B, and C, and the notation ¯¯¯¯¯¯BC represents the complement of BC.

To evaluate the expression X = A.¯¯¯¯¯¯BC, we substitute the given values of A, B, and C into the expression.

(a) For A = 1, B = 0, and C = 1:

X = 1.¯¯¯¯¯¯01

To find the complement of BC, we replace B = 0 and C = 1 with their complements:

X = 1.¯¯¯¯¯¯01 = 1.¯¯¯¯¯¯00 = 1.001

(b) For A = B = C = 1:

X = 1.¯¯¯¯¯¯11

Similarly, we find the complement of BC by replacing B = 1 and C = 1 with their complements:

X = 1.¯¯¯¯¯¯11 = 1.¯¯¯¯¯¯00 = 1.111

(c) For A = B = C = 0:

X = 0.¯¯¯¯¯¯00

Again, we find the complement of BC by replacing B = 0 and C = 0 with their complements:

X = 0.¯¯¯¯¯¯00 = 0.¯¯¯¯¯¯11 = 0.000

In conclusion, when A = 1, B = 0, and C = 1, X evaluates to 1.001. When A = B = C = 1, X evaluates to 1.111. And when A = B = C = 0, X evaluates to 0.000. The evaluation of X is based on substituting the given values into the expression A.¯¯¯¯¯¯BC and finding the complement of BC in each case.

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The bug crawls a distance of approximately 1.28 meters during the hour.

To estimate the distance using the left-hand Riemann sum, we first divide the time interval [0,1] into subintervals of width Δt=0.2. Then, we evaluate the velocity function at the left endpoint of each subinterval and multiply it by the width of the subinterval. Adding up these products gives us an estimate of the total distance traveled. Using this method, we get an underestimate of 0.8 meters.

To estimate the distance using the right-hand Riemann sum, we evaluate the velocity function at the right endpoint of each subinterval and multiply it by the width of the subinterval. Adding up these products gives us an estimate of the total distance traveled. Using this method, we get an overestimate of 1.6 meters.

To get a new estimate, we average the left-hand and right-hand Riemann sums. So, the new estimate of the total distance traveled by the bug is (0.8+1.6)/2 = 1.2 meters.

Therefore, the bug crawls a distance of approximately 1.28 meters during the hour, with an underestimate of 0.8 meters and an overestimate of 1.6 meters. By taking the average of the two Riemann sums, we get a more accurate estimate of 1.2 meters.

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Answer:

what type of math is it?

Step-by-step explanation:

Answer:

y=x-2

Step-by-step explanation:

the equation for slope intercept is y=mx+b, where m is the slope and b is the y intercept. The y intercept is -2, (where the line comes in contact with the x axis) and the slope is determined from the equation y2-y1/x2-x1 (rise over run) With this, we can see the slope is 1. hope this helps

Answer:

12

Step-by-step explanation:

1 - 1/4 = 3/4 (remaining animals which are cats and ferrets)

1 - 8/9 = 1/9 (means 1/9 of the remaining animals are ferrets)

1/9 x 3/4 = 1/12 (means 1/12 of the animals are ferrets)

1/12 x 144 = 12 ferrets

The 8-bit two's complement representation for 87 is 01010111, and for -49 is 11001111. To find the 8-bit two's complements for the numbers 87 and -49, we need to represent the numbers in binary form and apply the two's complement operation.

Let's start with 87. To represent 87 in binary, we perform the following steps:

Divide 87 by 2 continuously until we reach zero:

87 ÷ 2 = 43, remainder 1

43 ÷ 2 = 21, remainder 1

21 ÷ 2 = 10, remainder 1

10 ÷ 2 = 5, remainder 0

5 ÷ 2 = 2, remainder 1

2 ÷ 2 = 1, remainder 0

1 ÷ 2 = 0, remainder 1

Read the remainders in reverse order to obtain the binary representation of 87:

87 in binary = 1010111

To find the two's complement of -49, we perform the following steps:

Represent the absolute value of -49 in binary form:

Absolute value of -49 = 49 = 110001

Take the one's complement of the binary representation by flipping all the bits:

One's complement of 110001 = 001110

Add 1 to the one's complement to obtain the two's complement:

Two's complement of -49 = 001111

Therefore, the 8-bit two's complement representation for 87 is 01010111, and for -49 is 11001111.

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Answer:

If a researcher cannot gain access to a target population, snowball sampling procedures can assist in locating subjects. In regard to sampling procedures, if a researcher wants to be able to generalize results to the total population of interest, then a purposeful sampling technique is the best approach.

Answer:

Non-probability sampling

Step-by-step explanation:

Non-probability sampling is a method of selecting units from a population using a subjective  method.

a. The probability that the system will operate as shown is approximately 0.6141.

b. Probability ≈ 0.6141The probability remains the same as in the previous case, which is approximately 0.6141.

c. The probability that the system will operate with each component having a backup with a probability of 0.85 and a switch that is 90% reliable is approximately 0.6485.

a. To find the probability that the system will operate as shown, we multiply the probabilities of each component. Since the system is shown to have three components with a probability of 0.85 each, we can calculate:

Probability = 0.85 × 0.85 × 0.85

Probability ≈ 0.6141

The probability that the system will operate as shown is approximately 0.6141.

b. In this case, each system component has a backup with a probability of 0.85 and a switch that is 100% reliable. Since the backup has a probability of 0.85, and the switch is 100% reliable (probability = 1), we can calculate the probability as:

Probability = 0.85 × 0.85 × 0.85

Probability ≈ 0.6141The probability remains the same as in the previous case, which is approximately 0.6141.

c. In this scenario, each system component has a backup with a probability of 0.85, but the switch is 90% reliable (probability = 0.90). We can calculate the probability as:

Probability = 0.85 × 0.90 × 0.85

Probability ≈ 0.6485

The probability that the system will operate with each component having a backup with a probability of 0.85 and a switch that is 90% reliable is approximately 0.6485.

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41) s(-1/6)=0

=> 36*(-1/6)^3 + 36*(-1/6)^2 - 31*(-1/6) - 6 = 0

=> -12 + 72 + 31 - 6 = 0

=> 85 = 0

So, s(x) = 36x^3 + 36x^2 - 31x - 6

Factors completely as:

(3x+1)(12x^2 - 5x - 6)

45) p(x) = x^3 - 5x^2 + 4x - 20

=> p(5) = 125 - 75 + 20 - 20 = 0

Using the rational zeros theorem, the possible zeros are ±1, ±5/2, ±4.

Testing these, -4 is also a zero.

So the roots are -4, 5, -5/2.

46) q(-5/2) = 2(-5/2)^3 - 3(-5/2)^2 - 10(-5/2) + 25

=> -25 - 45 + 50 + 25 = 5

So q(-5/2) = 0

Other roots: Factoring as (2x + 5)(x^2 - x - 5)

=> -5, -1, -2.

56) f(x) = x^6 - 6x^4 + 17x^2 + k

For (x+1) to be a factor, the remainder should be 0 when f(x) is divided by (x+1).

f(-1) = -1 - 6 + 17 + k

=> k = 10

So when k = 10, (x+1) is a factor.

Again, remainder should be 0 when f(x) is divided by (x+a) for (x+a) to be a factor.

f(-a) = -a^6 + 6a^4 - 17a^2 + 10

Set this equal to 0 and solve for a. You'll get a = -3 or 2.

So when k = 10, f(x) also has (x-3) as a factor.

Depending on the size and thickness of the box, a certain amount of metal is required to cast a cubical metal box.

Depending on the size and thickness of the box, a certain amount of metal is required to cast a cubical metal box. In general, more metal is required for larger, thicker boxes. One must first calculate the box's volume in order to determine how much metal is required. The box's length, width, and height can be multiplied together to get this. The thickness of the metal must next be determined. The total amount of metal required can be estimated by multiplying the volume of the box by the thickness of the metal once the volume and thickness of the metal have been established. For instance, consider a box with dimensions of 6 inches long, 6 inches wide, and 6 inches high and a metal thickness.

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Answer:

the answer of your question is 0

Step-by-step explanation:

the answer is 0

Answer:

2125 miles

Step-by-step explanation:

Okay so to work this out we first need to find out how far the plane flies in one minute. To do this we do:

175 = 7

divide both sides by 7 to get 1 minute

25 = 1

The plane travels 25 miles in one minute.

Now to get 85 minutes we just do 25 x 85

25 x 85 = 2125

The plane travels 2125 miles in 85 minutes.

Hope this helps you :)

Answer:

First, we have to find the miles the jet flies in 1 minute. So we divide 175/7.

Multiply the quotient by 85. The answer will be the product, or miles a jet flies in 85 minutes.

Hope this helps!

Step-by-step explanation:

The components of a number are the numbers that divide evenly into it. To find the factors of 13, divide 13 by each number from 1 to 13 and check whether or not the result is an integer. 13 is made up of two factors: 1 and 13.

Division is one of the four fundamental arithmetic operations that allows integers to be connected to produce new numbers. Addition, subtraction, and multiplication are the other operations. Division is the process of dividing a given amount into equal pieces in mathematics. For example, a group of 20 people can be divided into four groups of five people each, or five groups of four people each, and so on. Splitting anything involves dividing it into two or more equal halves, such as an area, class, category, group, or division. To divide something simply is to cut it in half and give it to a group.

Here,

A number's components are the numbers that split equally into it. To determine the factors of 13, divide 13 by each number from 1 to 13 and see if the result is an integer or not. 13 has two factors: 1 and 13.

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Answer:

x = 20

Step-by-step explanation:

Some restrictions that local officials are placing, or planning to place in some towns are:

The term is seen as  the method that is used to observes a town and they are known to be the rules that is said to govern land use as well as the set up of the environment,  transport networks and others.

Note that the aim of town planning regulations is to aid and make sure that orderly growth and settlement of communities in the urban centers.

Hence, Some restrictions that local officials are placing, or planning to place in some towns are:

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You can fine the area of the figure by width times height

The lengths of the diagonals are approximately 10.6 cm and 31.8 cm.

To solve this problem, we can use the formula for the area of a rhombus, which is A = (d₁ x d₂)/2, where A is the area, and d₁ and d₂ are the lengths of the diagonals.

We are given that the area of the rhombus is 168 square centimeters, so we can substitute this value into the formula:

=> 168 = (d₁ x d₂)/2.

We are also given that one diagonal is three times as long as the other, so we can express the length of one diagonal in terms of the other: d₁ = 3d₂.

Substituting this expression for d₁ into the formula for the area, we get:

168 = (3d₂xd₂)/2 336 = 3d₂²2 d₂² = 112 d₂ = √(112) = 10.6 (to the nearest tenth of a centimeter)

Using the expression for d₁ in terms of d₂, we can find the length of the other diagonal:

d₁ = 3d₂ = 3(10.6) = 31.8 (to the nearest tenth of a centimeter)

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