Lien is pushing a box across a table. She used a force of 100 N to get the box moving. Which force did she overcome
to get the box moving?
O the downward force of gravity on the box
O the upward force of the table on the box
the reaction force on the box
O the push force on the box

Answer: 12,339

Explanation:

The speed of the cart after 3 seconds of Low fan speed is (2) cm/s. This is further explained below.

Generally, speed is simply defined as the rapidity of movement or efficiency of operation.

In conclusion, After 8 seconds with the fan set at Low, the cart will have traveled 1 cm/s. After three seconds at medium fan speed, the cart travels at a velocity of two centimeters per second.

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The average angular acceleration of the second hand is zero because the angular speed is constant. The angular speed is 360 degrees/hour.

The angular acceleration of a clock's minute hand on a clock is π1800rad/s

Angular acceleration means the time rate of change of angular velocity. The second hand of a clock involves an angular displacement of 2π per minute. Its angular speed is w = 2p/60s = 0.105/s. The direction of w is perpendicular to the face of the clock, directing to the face of the clock. The average angular acceleration of the second hand is zero.

Therefore, the correct answer is as given above

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Answer:

The thermal conductivity of the insulated metal rod is \(202.92\,\frac{W}{m\cdot K}\).

Explanation:

This is a situation of one-dimensional thermal conduction of a metal rod in a temperature gradient. The heat transfer rate through the metal rod is calculated by this expression:

\(\dot Q = \frac{k_{rod}\cdot A_{c, rod}}{L_{rod}}\cdot \Delta T\)

Where:

\(\dot Q\) - Heat transfer due to conduction, measured in watts.

\(L_{rod}\) - Length of the metal rod, measured in meters.

\(A_{c,rod}\) - Cross section area of the metal rod, measured in meters.

\(k_{rod}\) - Thermal conductivity, measured in \(\frac{W}{m\cdot K}\).

Let assume that heat conducted to melt some ice was transfered at constant rate, so that definition of power can be translated as:

\(\dot Q = \frac{Q}{\Delta t}\)

Where Q is the latent heat required to melt the ice, whose formula is:

\(Q = m_{ice}\cdot L_{f}\)

Where:

\(m_{ice}\) - Mass of ice, measured in kilograms.

\(L_{f}\) - Latent heat of fussion, measured in joules per gram.

The latent heat of fussion of water is equal to \(330000\,\frac{J}{g}\). Hence, the total heat received by the ice is:

\(Q = (6.15\,g)\cdot \left(330\,\frac{J}{g} \right)\)

\(Q = 2029.5\,J\)

Now, the heat transfer rate is:

\(\dot Q = \frac{2029.5\,J}{(10\,min)\cdot \left(60\,\frac{s}{min} \right)}\)

\(\dot Q = 3.382\,W\)

Turning to the thermal conduction equation, thermal conductivity is cleared and computed after replacing remaining variables: (\(L_{rod} = 0.75\,m\), \(A_{c,rod} = 1.25\times 10^{-4}\,m^{2}\), \(\Delta T = 100\,K\), \(\dot Q = 3.382\,W\))

\(\dot Q = \frac{k_{rod}\cdot A_{c, rod}}{L_{rod}}\cdot \Delta T\)

\(k_{rod} = \frac{\dot Q \cdot L_{rod}}{A_{c,rod}\cdot \Delta T}\)

\(k_{rod} = \frac{(3.382\,W)\cdot (0.75\,m)}{(1.25\times 10^{-4}\,m^{2})\cdot (100\,K)}\)

\(k_{rod} = 202.92\,\frac{W}{m\cdot K}\)

The thermal conductivity of the insulated metal rod is \(202.92\,\frac{W}{m\cdot K}\).

Answer:

true

Explanation:

the dog hasn't moved, displacement has direction, and there is no movement or direction involved, his final position and initial are the same

Answer:

False, it is a fuse.

Explanation:

In electronics and electrical engineering, a fuse is an electrical safety device that operates to provide overcurrent protection of an electrical circuit. Its essential component is a metal wire or strip that melts when too much current flows through it, thereby stopping or interrupting the current. It is a sacrificial device; once a fuse has operated it is an open circuit, and must be replaced or rewired, depending on its type.

Fuses have been used as essential safety devices from the early days of electrical engineering. Today there are thousands of different fuse designs which have specific current and voltage ratings, breaking capacity and response times, depending on the application. The time and current operating characteristics of fuses are chosen to provide adequate protection without needless interruption. Wiring regulations usually define a maximum fuse current rating for particular circuits. Short circuits, overloading, mismatched loads, or device failure are the prime or some of the reasons for fuse operation.

A fuse is an automatic means of removing power from a faulty system; often abbreviated to ADS (Automatic Disconnection of Supply). Circuit breakers can be used as an alternative to fuses, but have significantly different characteristics.

Source: https://en.wikipedia.org/wiki/Fuse_(electrical)

A fuse is a small glass or plastic tube that contains a piece of wire. That wire is carefully calibrated so that it will only allow a certain level of current to pass through it. Any more, and the wire will melt from the heat, breaking the circuit. This means that if a power surge comes into your home, a circuit will be broken before it causes damage to your appliances.

A circuit breaker achieves the same thing, but by a different method. A circuit breaker also disconnects the circuits in your home if the current gets too large but does it using electromagnets. If the current gets high enough, then the electromagnet will become powerful enough to attract a contact and break the circuit that way.

Both circuit breakers and fuses can be used to help with another situation. If you have an appliance with a metal case and that appliance comes in contact with a live wire, it can cause you to electrocute yourself. But if that metal case is connected to a ground wire (the third pin in some plugs), then the electricity will flow through the ground wire, through the circuit breaker or fuse box, and break the circuit, stopping you from potentially getting electrocuted.

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To determine the magnitude of the lift force ⃗ and the force of air resistance ⃗ acting on the jet, we need to resolve the weight ⃗ and the forward thrust ⃗ into their horizontal and vertical components.

The weight ⃗ can be resolved into two components:

- the vertical component, Wsin(30°), acting downward

- the horizontal component, Wcos(30°), acting to the left

The forward thrust ⃗ can also be resolved into two components:

- the vertical component, Tsin(30°), acting upward

- the horizontal component, Tcos(30°), acting to the right

Since the jet is flying at a constant speed, the lift force ⃗ must be equal in magnitude to the weight component acting downward, Wsin(30°). Therefore, the magnitude of ⃗ is 86,500 Nsin(30°) = 43,250 N.

The force of air resistance ⃗ is equal in magnitude to the horizontal component of the weight, Wcos(30°), minus the horizontal component of the forward thrust, Tcos(30°). Therefore, the magnitude of ⃗ is (86,500 Ncos(30°)) - (103,000 Ncos(30°)) = -8,715 N, where the negative sign indicates that the force of air resistance is acting in the opposite direction to the motion of the jet.

Therefore, the magnitude of the lift force ⃗ is 43,250 N and the magnitude of the force of air resistance ⃗ is 8,715 N.

The accurate statement when discussing specific heat is  option A) The specific heat of a gas can be measured at constant pressure.

This is because specific heat is the amount of heat energy required to raise the temperature of a substance by a certain amount. For gases, the specific heat can be measured at either constant pressure or constant volume. However, when discussing specific heat in general, it is more commonly measured at constant pressure.

Option B is incorrect because the specific heat of a gas can also be measured at constant volume, not just constant volume only.

Option C is incorrect because specific heat values for liquids can vary for different ranges of temperature. The specific heat of a substance may change with temperature due to variations in molecular interactions and other factors.

Option D is incorrect because specific heat values for solids can also vary for different ranges of temperature. The specific heat of a solid can depend on factors such as crystal structure, impurities, and temperature range.

Therefore, the accurate statement is option A, which states that the specific heat of a gas can be measured at constant pressure.

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1) The force acting on the object during the time interval 0-3 seconds is 1/3 N.

2) The force acting on the object during the time interval 6-10 seconds is -0.5 N.

3) There is no time interval in which no force acts on the object.

(i) Force acting on the object in time interval 0-3 seconds. Force acting on the object is equal to the product of its mass and acceleration, i.e.,F = ma.

In the given velocity-time graph, the acceleration of the object can be determined by determining the slope of the velocity-time graph from 0 to 3 seconds.

Slope = (change in velocity) / (change in time)= (20-0) / (3-0) = 20/3 m/s^2

Acceleration, a = slope= 20/3 m/s^2

Mass of the object, m = 50 g = 0.05 kg

∴ Force acting on the object, F = ma= 0.05 × 20/3= 1/3 N.

Therefore, the force acting on the object during the time interval 0-3 seconds is 1/3 N.

(ii) Force acting on the object in time interval 6-10 seconds. Similar to the first question, the force acting on the object in time interval 6-10 seconds can be determined by determining the acceleration of the object during this time interval.

The slope of the velocity-time graph from 6 seconds to 10 seconds can be determined as follows:

Slope = (change in velocity) / (change in time)= (-20-20) / (10-6) = -40/4= -10 m/s^2 (negative sign indicates that the object is decelerating)

Mass of the object, m = 50 g = 0.05 kg

∴ Force acting on the object, F = ma= 0.05 × (-10)= -0.5 N.

Therefore, the force acting on the object during the time interval 6-10 seconds is -0.5 N.

(iii) Time interval in which no force acts on the object. There is no time interval in which no force acts on the object. This is because, as per Newton's first law of motion, an object will continue to remain in a state of rest or uniform motion along a straight line unless acted upon by an external unbalanced force.In other words, if the object is moving with a constant velocity, there must be a force acting on the object to maintain its motion.

Therefore, there is no time interval in which no force acts on the object.

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Kinetic energy is the energy that the pendulum have when it is hanging straight down and at the lowest point pendulum is the potential and kinetic energy is maximum.

A simple pendulum consists of a small mass suspended on an approximately massless, non-stretchable string. It is free to oscillate from side to side. The forces acting on the mass are the force of gravity and the tension in the string.

The tension cancels out the component of mg that lies along the string; this keeps the object from accelerating in the direction of the string, and thus keeps the string's length constant.

The net force is simply the remaining component of mg, which is pointed perpendicular to the string and is equal to Fnet=-mgsinФ

The pendulum only has gravitational potential energy, as gravity is the only force that does any work. The total energy of the pendulum is the potential energy at the maximum displacement, when the displacement is equal to the amplitude is 1/2mgLA^2.

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Hi there!

a)

We can use the following equation to solve for the momentum. Remember that momentum is ALWAYS CONSERVED.

p = m · v

Plug in the given values:

p = (.250) · 15 = 3.75 kgm/s

b)

The momentum of the system AFTER the collision will be the same because of a CONSERVATION OF MOMENTUM.

\(p_i = p_f\)

c)

We know that by the conservation of momentum:

m₁v₁ + m₂v₂ = m₁v₁ '+ m₂v₂'

The second object (cart) is originally at rest, and the two objects move together after the collision, so:

m₁v₁ = (m₁ + m₂)vf

Solve by plugging in values:

(.250)(15)/(.250 + .400) = vf = 5.769 m/s

Answer:6m

Explanation:

Answer: 20 kg

Explanation:

The magnitude of the force on the tooth is approximately 0.022 N.

To find the magnitude and direction of the force on the tooth, we can use Hooke's Law, which states that the force exerted on an object is directly proportional to the change in length of a material when it is stretched or compressed.

First, we need to calculate the strain (ε) of the stainless-steel wire.

Strain is defined as the change in length divided by the original length:

ε = ΔL / L₀

Given that the change in length (ΔL) is 0.10 mm \((0.10 \times 10^{-3} m)\) and the unstretched length (L₀) is 3.1 cm \((3.1 \times 10^{-2} m)\), we can calculate the strain:

\(\epsilon=(0.10 \times 10^{-3} m)/(3.1 \times 10^{-2} m)=0.003225\)

Next, we can use Young's modulus (E) to calculate the stress (σ) in the wire.

Stress is defined as the force per unit area:

σ = E * ε

Given that Young's modulus (E) for stainless-steel is 18 × 10¹⁰ N/m², we can calculate the stress:

σ = (18 × 10¹⁰ N/m²) * 0.003225 = 5.805 × 10⁸ N/m²

Now, we can find the force (F) on the tooth by multiplying the stress by the cross-sectional area (A) of the wire:

F = σ * A

The cross-sectional area (A) can be calculated using the formula for the area of a circle:

A = π * (d/2)²

Given that the diameter (d) of the wire is 0.22 mm\((0.22 \times 10^{-3} m)\), we can calculate the cross-sectional area:

\(A = \pi * (0.22 \times 10^-3 m / 2)^{2} = 3.802 \times 10^{-8} m^2\)

Finally, we can calculate the force:

\(F = (5.805 \times 10^{8} N/m^{2}) * (3.802 \times 10^-8 m^{2}) \approx 2.206 \times 10^{-2} N\)

Therefore, the magnitude of the force on the tooth is approximately 0.022 N.

Since the wire is stretched, the force is pulling the tooth in the direction opposite to the stretching.

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Answer:

c.

Explanation:

It prevents consumers from purchasing unnecessary goods.

Answer:

c

Explanation:

2.5 mL of Thallium-201 should be injected to administer a recommended dose of 3.0 mCi.

Thallium-201 is a radioisotope that is used in brain scans to detect brain cancer. It is used in nuclear medicine as a radiopharmaceutical. The recommended dose for Thallium-201 is 3.0 mCi. If a vial of Thallium-201 contains 60. mCi in 50. mL, we can determine the number of milliliters that should be injected by using proportionality.A proportion can be used to compare two ratios and solve for an unknown value. For example, if x is the unknown value we are trying to solve for and a/b and c/d are two ratios that are equal, we can write a proportion:

a/b = c/d.

Cross-multiplying gives us the equation

ad = bc.

This formula can be used to solve for the unknown value x. For this problem, we can use a proportion to solve for the number of milliliters that should be injected. Let x be the number of milliliters that should be injected. Then we have the following ratio:

3.0 mCi / x mL = 60. mCi / 50. mL

To solve for x, we can cross-multiply:

3.0 mCi * 50. mL = 60. mCi * x mL150. mCi mL = 60. mCi x mCx = (150. mCi mL) / (60. mCi) x = 2.5 mL

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Answer:

fffcdcffffdxxfxxtdyfycycycycy

The answers are 1) The value of R2 is not relevant as it implies a downward force on the plank, 2) The reactions at C and D are 66.3 N and 90 N, respectively, and 3) The vertical force at B to lift the plank clear of D is 686.4 N. The reaction at C is zero, and the reaction at D is 61.4 kg.

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Answer:

c. Total energy

Explanation:

An "orbit" is a path for an object to follow. An example of an object is the "satellite."

At certain points in the orbit, the satellite increases its speed and decreases its speed in relation to the gravity caused by the Earth. As it moves farther away from the Earth, its speed slows down. So, this means that the kinetic energy changes. It also gains and loses height which is responsible for the changes occurring regarding potential energy. This is true for elliptical motion of satellites.

However, the total mechanical energy (TME) of the satellite remains the same or is unchanged (elliptical/circular).

This question is incomplete, the complete question is;

For this force system the equivalent system at P is ___________

A) FRP = 40 lb (along +x-dir.) and MRP = +60 ft.lb

B) FRP = 0 lb and MRP = +30 ft.lb

C) FRP 30 lb (along +y-dir.) and MRP  = -30 ft.lb

D) FRP 40 lb (along +x-dir.) and MRP = +30 ft.lb

Answer:

D) FRP 40 lb (along +x-dir.) and MRP = +30 ft.lb

Explanation:

From the figure in the image i uploaded along this answer;

FRP = ( 40 lb i + 30 lb j ) + [30 lb (-j)]

Where i  and j are the unit vectors along X & Y axis respectively.

So, FRP = 40 lb i

that is,  FRP = 40 lb along +X direction

MRP = [ 30 lb x ( 1 ' + 1' ) ] +( -30 lb x 1 ' )

= (30 lb x 2 ' )- 30 lb ft

= 60 lb ft - 30 lb ft

= 30 lb ft

Therefore option(D) is correct    

Answer:

9. A 1500kg car traveling +6m/s with a 2000kg truck at rest. The vehicles collide, but do not stick together. The car has a velocity -3m/s after the collision. What is the velocity of the truck? a. What type of collision occurred above?

Answer yess it’s not

Explanation:

Answer:

Mercury is rocky

Explanation:

Answer:

Rocky

Explanation:

It has no atmosphere so it cannot hold gas.

Answer:

a)40 meters

b)2 m/s

c)2 m/s

d)0 m/s

e)45 degrees northeast

Explanation:

a) The displacement from C to A is the distance directly across the river, which is 40 meters.

b) The speed of the boat as seen by people standing at A is the magnitude of the boat's velocity vector, which is equal to the displacement divided by the time taken:

Speed = displacement / time = 40 m / 20 s = 2 m/s.

c) Let v be the speed of the water in the river. The boat is moving at right angles to the flow of the river, so the water exerts a perpendicular force on the boat. The time taken for the boat to travel from A to C is 20 seconds, during which time the boat will have been carried downstream by the river by a distance equal to v times the time taken.

Distance carried downstream = v × time = v × 20 m.

Since the boat landed at C, which is directly across the river from A, the distance it traveled horizontally is 40 meters. Therefore:

40 m = (boat speed) × (time taken) = (boat speed) × 20 s.

Hence, the speed of the boat is:

Boat speed = 40 m / 20 s = 2 m/s.

So, we have two equations:

Distance carried downstream = v × 20 m

Boat speed = 2 m/s

From the first equation, we get:

v × 20 m = 40 m

Therefore, the speed of the water in the river is:

v = 40 m / 20 m = 2 m/s.

d) The speed of the boat as seen by a fish drifting with the river is the difference between the speed of the boat and the speed of the water in the river:

Boat speed - Water speed = 2 m/s - 2 m/s = 0 m/s.

So, the speed of the boat as seen by a fish drifting with the river is zero.

e) The boat should head in a direction that makes its velocity vector point directly from A to B. Since A and B are directly opposite each other, this means the velocity vector should be perpendicular to the line connecting A and B.

We know the boat's velocity vector has a magnitude of 2 m/s and is at right angles to the velocity vector of the water in the river, which has a magnitude of 2 m/s. So, we can draw a vector diagram with the velocity vector of the boat pointing straight up and the velocity vector of the water pointing straight to the right. The vector connecting the tail of the water velocity vector to the head of the boat velocity vector will then point directly from A to B.

The angle between the boat's velocity vector and the line connecting A and B can be found using trigonometry. Let θ be this angle. Then:

tan(θ) = (boat speed) / (water speed) = 2 m/s / 2 m/s = 1.

Taking the inverse tangent of both sides gives:

θ = tan^(-1)(1) = 45°.

So, the boat should head in a direction 45 degrees to the right of straight up, or northeast.

The period (in second) of the 0.95 Kg mass, given that it has an amplitude of 0.21 m and an angular velocity of 9.5 rad/s is 0.66 second

From the question given above, the following data were obtained:

The period of the mass can be obtained as shown below:

ω = 2π/ T

9.5 = (2 × 3.14) / T

9.5 = 6.28 / T

Cross multiply

9.5 × T = 6.28

Divide both sides by 9.5

T = 6.28 / 9.5

T = 0.66 second

Thus, from the above calculation, we can conclude that the period of the mass is 0.66 second

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(a) The magnitude of the spring's displacement when the acceleration of the box is zero can be determined by equating the initial gravitational potential energy to the elastic potential energy stored in the spring.

(b) The magnitude of the spring's displacement when the spring is fully compressed can be determined by equating the initial gravitational potential energy to the elastic potential energy stored in the spring.

(a) To determine the magnitude of the spring's displacement when the acceleration of the box is zero, we need to apply the principles of conservation of energy.

Initially, the box has gravitational potential energy given by mgh, where m is the mass of the box, g is the acceleration due to gravity, and h is the height from which the box was dropped. The initial gravitational potential energy is converted into the elastic potential energy stored in the compressed spring and the kinetic energy of the box just before it makes contact with the spring.

The gravitational potential energy is given by:

mgh = (1.9 kg)\((9.8 m/s^2)h\)

The elastic potential energy stored in the spring is given by:

1/2 kx^2\(kx^2\), where k is the spring constant and x is the displacement of the spring.

The kinetic energy of the box just before it makes contact with the spring is given by:

\(1/2 mv^2,\) where m is the mass of the box and v is the speed of the box.

Since the acceleration of the box is zero at the instant when the spring's displacement is maximum, the kinetic energy is zero. Therefore, we can equate the initial gravitational potential energy to the elastic potential energy to find the spring's displacement.

mgh = 1/2 \(kx^2\)

Substituting the given values, we have:

\((1.9 kg)(9.8 m/s^2)h = 1/2 (300 N/m)x^2\)

Solving for x, the magnitude of the spring's displacement, we can determine its value at the instant when the acceleration is zero.

(b) To find the magnitude of the spring's displacement when the spring is fully compressed, we need to consider the conservation of mechanical energy once again.

At maximum compression, all the initial gravitational potential energy is converted into the elastic potential energy stored in the compressed spring.

mgh = 1/2 \(kx^2\)

Substituting the given values and solving for x, the magnitude of the spring's displacement, we can determine its value when the spring is fully compressed.

It's important to note that in both cases, the negative sign of the displacement indicates that the spring is being compressed. The magnitude of the displacement will be a positive value.

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Answer:

Think in your Mind

Explanation:

if you do you will have a better understanding of what you're doing

you could study you could ask a parent or guardian

or maybe stop looking up answer and expect other people breaking thier heads doing this

The velocity of the race car after it traveled 32.2 meter is 14.47m/s.

Velocity is simply the speed at which an object moves in a particular direction.

From the Third Equation of Motion

v² = u² + 2as

Given that;

Plug the given values into the above formula and solve for final velocity.

v² = u² + 2as

v² = (0)² + ( 2 × 3.25 m/s² × 32.2 m ​)

v² =  2 × 3.25 m/s² × 32.2 m

v² = 209.3 m²/s²

v = √( 209.3 m²/s² )

v = 14.47m/s

Therefore, the final velocity is 14.47m/s.

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Vehicles need to be serviced for several reasons such as preventing costly repairs and improving fuel economy.

First, regular maintenance can help to prevent costly repairs down the road. Second, maintenance can help to improve fuel economy and emissions. Third, maintenance can help to keep your vehicle safe and reliable.

The servicing requirements for petrol/diesel and electric vehicles differ in a number of ways. Petrol/diesel vehicles require oil changes more frequently than electric vehicles. This is because petrol/diesel engines use oil to lubricate the moving parts, while electric motors do not. Petrol/diesel vehicles also require tune-ups more frequently than electric vehicles.

This is because petrol/diesel engines have more moving parts that need to be synchronized, while electric motors have fewer moving parts.

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