Lisa can drive 81 miles in the same amount of time it takes her to ride her bike 18 miles. if she drives at a speed that is 28 miles per hour faster than she rides her bike, how fast is she riding her bike?

Answer:o/1

Step-by-step explanation:

The ratio of boy to girl who play kickball at race is 6 to 2. There are 18 girl on the team. the number of boys who play kickball at race is 12 boys.

The ratio of boy to girl who play kickball at race is 6 to 2

6 boys: 2 girls

Multiply the number of girls by the ratio:

18 girls x (6 boys / 2 girls) = 18 x 3 = 54

Subtract the number of girls from the total to get the number of boys:

54 - 18 = 36

Therefore, there are 12 boys who play kickball at race.

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Answer: 18.5227272727

Step-by-step explanation:

1630/44 = 37.0454545455

Therefore 37.0454545455 to 2 decimal places = 37.05

1630/44 divided by 2 » (1630/44) ÷ 2 » 37.0454545455 ÷ 2

= 18.5227272727

Answer:

3704.54545455

Step-by-step explanation: simplified

Answer:

True- She needs $3 more. She will not have enough money to buy everything. The cost is $28.

False- She has $3 left over.

Step-by-step explanation:

2 pounds of burgers for $3 each is $6

1 bag o bun equals $2

5 bags of chips for $4 each is $20

$20 + $6 +$2 = $28

She only had $25 to spent, so she doesn't have enough money and needs to 3 more dollars.

To compare the unit rates, we need to find the cost per ounce for each bottle of water.

For the 16-ounce bottle, the unit rate is:

$2.40 / 16 ounces = $0.15 per ounce

For the 28-ounce bottle, the unit rate is:

$2.80 / 28 ounces = $0.10 per ounce

From the unit rate we can see that the 28 ounce bottle of water is a better deal because it cost $0.10 per ounce while the 16 ounce bottle cost $0.15 per ounce.

It's important to know that as the amount of water increases the price decreases making the 28 ounce bottle cheaper than the 16 ounce bottle.

Answer: k= 9

x= 7/4

Step-by-step explanation:

https://www.symbolab.com/solver/order-of-operations-calculator/36x%20-%2063%20%3D%20k%5Cleft(4x%20-%207%5Cright)

a. There would be y = 13\(e^\frac{-t}{100}\) salt is in the tank after t minutes.

b. There would be 7.8 kg salt is in the tank after 30 minutes

(a) Let y be the amount of salt (in kg) in the tank after t minutes. We can write a differential equation for y as:

dy/dt = (salt in) - (salt out)

The rate of salt in is given by the concentration of salt in the incoming water (which is 0) times the flow rate of incoming water, which is 0 L/min. The rate of salt out is given by the concentration of salt in the tank, which is y/6000 kg/L, times the flow rate of outgoing water, which is 60 L/min. So we have:

dy/dt = 0 - (y/6000) * 60

Simplifying and solving this first-order linear differential equation, we get:

y = 13\(e^\frac{-t}{100}\)

(b) To find the amount of salt in the tank after 30 minutes, we simply plug in t = 30 into the equation we found in part (a):

y =13 \(e^\frac{-30}{100}\) ≈ 7.8 kg (rounded to one decimal place)

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The schedule is as follows:

T1 -> T2 -> T1 -> T3 -> T1 -> T2 -> T1.

To construct a schedule using the Earliest Deadline First (EDF) scheduling algorithm, we need to consider the execution time, period, and deadline of each task and assign them priorities based on their deadlines. The task with the earliest deadline will be scheduled first. Let's create a schedule for the given task set:

Task T1: Execution time (e) = 2 ns, Period (P) = 5 ns, Deadline (D) = 5 ns

Task T2: Execution time (e) = 4 ns, Period (P) = 7 ns, Deadline (D) = 7 ns

Task T3: Execution time (e) = 7 ns, Period (P) = 7 ns, Deadline (D) = 7 ns

We have a period of 22 ns, and we need to schedule these tasks within that period. Let's start with the task with the earliest deadline:

At time 0 ns: Execute T1 (2 ns)

At time 2 ns: Execute T2 (4 ns)

At time 6 ns: Execute T1 (2 ns)

At time 8 ns: Execute T3 (7 ns)

At time 15 ns: Execute T1 (2 ns)

At time 17 ns: Execute T2 (4 ns)

At time 21 ns: Execute T1 (2 ns)

This completes the execution of all tasks within the given period of 22 ns. The schedule is as follows:

T1 -> T2 -> T1 -> T3 -> T1 -> T2 -> T1

In this schedule, we have followed the EDF algorithm by selecting tasks based on their deadlines. The task with the earliest deadline is always scheduled first to meet the timing requirements of the system.

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To find the volume between the planes 4x + 3y + z = 8 and 5x + 5y + z = 8, and above the region defined by x + y ≤ 2, x ≥ 0, and y ≥ 0, we can set up a triple integral over the specified region.

The volume can be calculated as follows:  ∭V dV

Where V represents the volume and dV represents the differential volume element. To define the limits of integration, we need to determine the boundaries of the region in the xy-plane and the range of z values.

In the xy-plane, the boundaries are determined by the inequalities x + y ≤ 2, x ≥ 0, and y ≥ 0. These inequalities define a triangle in the first quadrant with vertices at (0, 0), (2, 0), and (0, 2). Therefore, the limits of integration for x and y are:

0 ≤ x ≤ 2

0 ≤ y ≤ 2 - x

For the z values, we need to consider the intersection of the two planes 4x + 3y + z = 8 and 5x + 5y + z = 8. By solving these equations simultaneously, we find that z = 0. Therefore, the limits of integration for z are:

0 ≤ z ≤ 8 - 4x - 3y

Putting it all together, the triple integral for the volume is:

\(\int\ \int\ \int V dV = \int\limits^2_0 \int\limits^{2-x}_0 \int\limits^{8-4x-3y}_0dz dy dx\)

This represents the volume between the planes 4x + 3y + z = 8 and 5x + 5y + z = 8, and above the region defined by x + y ≤ 2, x ≥ 0, and y ≥ 0

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The quadratic equation that represents the solution is F: p(x) = x² - 49.

The term "quadratic" refers to functions where the highest degree of the variable (in this example, x) is 2. A quadratic function's graph is a parabola, which, depending on the sign of the leading coefficient a, can either have a "U" shape or an inverted "U" shape.

Algebra, geometry, physics, engineering, and many other branches of mathematics and science all depend on quadratic functions. They are used to simulate a wide range of phenomena, including population dynamics, projectile motion, and optimisation issues.

Given that the solution of the quadratic function are x = -7 and x = 7 thus we have:

p(x) = (x + 7)(x - 7)

Solving the parentheses we have:

p(x) = x² - 7x + 7x - 49

Cancelling the same terms with opposite sign we have:

p(x) = x² - 49

Hence, the quadratic equation that represents the solution is F: p(x) = x² - 49.

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Answer:

  parallel

Step-by-step explanation:

You want to know the parallel/perpendicular status of the lines described by the equations ...

Parallel lines have the same slope. The slope is the coefficient of x when the equation is written in the form ...

  y = mx +b

as is the second equation.

The first equation can be put in that form by solving for y.

  2x -5y = 25 . . . . . . given equation

  2x -25 = 5y . . . . . . add 5y -25

  2/5x -5 = y . . . . . . divide by 5

The coefficient of x (slope) is 2/5, same as the second equation.

The lines are parallel.

__

Additional comment

Your graphing calculator can help you figure this out, too. The graphed lines are parallel.

Answer:

12 carrots

Step-by-step explanation:

If there is 3 times as much cabbages as there is carrots, and there is 36 cabbages then you would do 36/3 because of the 3 times as much.  The answer would be 12 carrots.

36/3=12

Answer:

16

Step-by-step explanation:

2*8=16

16/1=16

Answer:

about $521.05

Step-by-step explanation:

61.3% of 850 is 521.05

I) f is continuous at x=2

II) f is differentiable at x=2

These both f (function ) are true

The given limit can be recognized as the definition of the derivative of f at x=2. Specifically, it states that the derivative of f at x=2 is equal to 5.

Using this information, we can make the following conclusions:

I) We cannot say for sure whether f is continuous at x=2 based on the given limit alone. While a function being differentiable at a point implies that it is also continuous at that point, the converse is not necessarily true. Therefore, we would need additional information to determine whether f is continuous at x=2.

II) The given limit implies that f is differentiable at x=2, since the limit exists and is finite. Specifically, we can say that the derivative of f at x=2 exists and is equal to 5.

III) The given limit also implies that the derivative of f is continuous at x=2. This is because the limit defines a continuous function at x=2, and it is well-known that if a function is differentiable at a point, then it is also continuous at that point.

Therefore, the correct answers are II and III.

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Angles Formulas at the center of a circle can be expressed as:

Central angle, θ = (Arc length × 360º)/(2πr) degrees

Sum of Interior angles=180°(n-2)

The angles formulas are used to find the measures of the angles. An angle is formed by two intersecting rays, called the arms of the angle, sharing a common endpoint.

The corner point of the angle is known as the vertex of the angle. The angle is defined as the measure of the turn between the two lines.

There are various types of formulas for finding an angle; some of them are the central angle formula, double-angle formula, etc...

We use the central angle formula to determine the angle of a segment made in a circle.

We use the sum of the interior angles formula to determine the missing angle in a polygon.

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The Probability that you selected one good and one bad card is =  3/6

According to our question-

Hence,The probability that you selected one good and one bad card is =  3/6

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Qualitative and quantitative data are both valuable in understanding and analyzing the causes and effects of geographic change within urban areas. Here's how each type of data can be used:

Qualitative Data:

Qualitative data provides insights into the subjective experiences, perceptions, and behaviors of individuals and communities. It involves non-numerical information that is collected through methods such as interviews, observations, and case studies. In the context of geographic change within urban areas, qualitative data can help reveal the underlying social, cultural, and political factors influencing the processes and outcomes of urbanization. It can shed light on the lived experiences of residents, their attitudes towards change, and the social dynamics at play.

Quantitative Data:

Quantitative data, on the other hand, involves numerical measurements and statistical analysis. It provides objective and measurable information about various aspects of urban areas, such as population, infrastructure, economic indicators, and environmental factors. Quantitative data can be collected through surveys, censuses, sensors, and other statistical sources.

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The word in the problem that indicates that a negative sign should be used is "descend"

We know that he stops for water breaks four times, and between each water break, he descends 15 meters.

The written equation is:

4*(-15)m = -60m

Why the negative sign is used?

The negative sign is used because the hiker is descending, so its height is decreasing. The word in the problem that indicates that a negative sign should be used is "descend"

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Hey there! :)

Answer:

C. BC = 39 units.

Step-by-step explanation:

Use the Pythagorean theorem to solve for BC. Let BC = c, AB = a, and AC = b.

c² = a² + b²

c² = 15² + 36²

Square and simplify:

c² = 225 + 1296

c² = 1521

c = √1521

c = 39 units.

Therefore:

BC = 39 units.

Answer:

C. 39

Step-by-step explanation:

Use Pythagorean Theorem to find the missing length

15² + 36² = C²      Simplify

225 + 1296 = C²   Add

1521 = C²              Take the square root of both sides

39 = C

As per the given distance, he surrounded around 20 miles

Here we have given that Pete drives from his house to the store and then to the fair.

While we have given the distance covered by the Pete driver as,

=> 6, 5, 4, 3, 2

Then the total travelling distance is calculated by sum up all the details,

Then  we get,

=> 6 + 5 + 4 + 3 + 2

=> 20 units.

Here we have also given that 1 unit is equal to 1 miles.

Therefore, the resulting distance is 20 miles.

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Answer:

One possible answer would be they sold 80 student tickets and 30 adult tickets

Step-by-step explanation:

set up two inequalities, one to show number of tickets that can be sold, and the other is how much money they need to make

5x+10y G than or =  700

x+y L than or = 110

The first inequality shows that each student (x) ticket sells for $5, and each adult (y) ticket sells for $10, and the amound has to be greater or equal to 700.

The second inequality shows that both student and adult tickets sold have to be less than or equal to 110.

First find either x or y, in this case finding y was easier

y is g than or = to 30

This means that they sold at least 30 adult tickets= $300

With y, plug into the inequality x+y L than or = to 110 to find x

x is less than or = to 80

This means that they sold at most 80 student tickets = $400

Hope this helps!

Which of these values for x make the value of the expression (x-5)(x+7) the greatest? ​

This is a quadratic equation (vertical parabola) open upward

the vertex is a minimum

the greatest value of this expression is for the greater value of x in absolute value

we have

that -9 is the greater value in absolute value

therefore

the answer is -9

Answer:

1360

Step-by-step explanation:

8160 / 12 ( the number of months) = 680  

680 x 2 = 1360

Answer:

1360

Step-by-step explanation:

Answer:

the length of building is 675.4 m

Step-by-step explanation:

the ratio of pole and his shadow

2.8/1.9

1.47

then, let the building lengh be x

x/49.5=1.47

x=675.4 m

The task is to find the convolution of the marginal distributions of two independent random variables x and y with identical geometric distributions.

To find the convolution of the marginal distributions of x and y, we need to calculate the probability distribution function of the sum of x and y. Since x and y have identical geometric distributions, we know that the probability of x=k and y=m is given by p(x=k, y=m) = (1-p)^k * p * (1-p)^m * p = p^2 * (1-p)^(k+m), where p is the probability of success in each trial of the geometric distribution.

To find the probability distribution function of the sum Z=x+y, we need to compute the probability of each possible value of Z. That is, P(Z=k) = Σ P(X=i, Y=k-i) for all i from 0 to k. Plugging in the probability distribution function of x and y, we get P(Z=k) = Σ p^2 * (1-p)^(i+k-i) = p^2 * (1-p)^k * Σ 1. The summation is over all i from 0 to k, and is equal to k+1. Therefore, we have P(Z=k) = (k+1) * p^2 * (1-p)^k. This is the probability distribution function of the sum of two independent random variables x and y with identical geometric distributions, and is the convolution of the marginal distributions of x and y.

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First, let's define some terms.

- Vectors are quantities that have both magnitude and direction. In this case, we're working with vectors in R2, which means they have two components (x and y).
- A linear combination is a way of combining vectors using multiplication and addition. For example, if we have two vectors v1 = [1, 2] and v2 = [3, 4], then a linear combination of these vectors could be 2v1 + 3v2 = 2[1, 2] + 3[3, 4] = [8, 14].
- Coefficients are the numbers we multiply the vectors by in a linear combination.

Now, let's move on to your question.

You have four vectors in R2, but they do not form a basis. This means that they are linearly dependent, which implies that at least one of the vectors can be expressed as a linear combination of the others.

You are given one vector v = [-20, 4, 13, 68], and you are asked to find two different ways to express it as a linear combination of the other vectors v1, v2, v3.

To do this, we can use a method called Gaussian elimination. We can write the vectors as rows in a matrix, and then use row operations to simplify the matrix and find the coefficients we need.

Here's the matrix we get:

| v1 | v2 | v3 | v |
|----|----|----|---|
|    |    |    |   |
|    |    |    |   |
|    |    |    |   |
|    |    |    |   |

We can start by subtracting multiples of v1 from the other vectors to get zeros in the first column:

| v1 | v2 | v3 | v |
|----|----|----|---|
| 1  | 0  | -2 |  1|
| 0  | 1  |  3 | -4|
| 0  | 0  |  0 |  0|
| 0  | 0  |  0 |  0|

Now we can see that v3 is a linear combination of v1 and v2:

v3 = -2v1 + 3v2

We can use this to express v in terms of v1, v2, and v3:

v = -v1 - 4v2 + 68/13 v3

This is one way to express v as a linear combination of v1, v2, v3.

To find another way, we can swap the positions of v2 and v3 in the matrix and repeat the process.

| v1 | v3 | v2 | v |
|----|----|----|---|
| 1  | -2 | 0  |  1|
| 0  |  0 | 1  |  3|
| 0  |  0 | 0  |  0|
| 0  |  0 | 0  |  0|

Now we can see that v2 is a linear combination of v1 and v3:

v2 = 2v1 - 3v3

We can use this to express v in terms of v1, v2, and v3:

v = -v1 + 68/13 v2 + 4/13 v3

This is another way to express v as a linear combination of v1, v2, v3.

Finally, you are asked to express v as a linear combination of v1, v2, v3 when the coefficient of v1 is 0 and the coefficient of v3 is 1.

To do this, we can set up the following system of equations:

- a v1 + b v2 + c v3 = v
- a = 0
- c = 1

Substituting a = 0 and c = 1, we get:

b v2 + v3 = v

We already know that v3 = -2v1 + 3v2, so we can substitute that in:

b v2 - 2v1 + 3v2 = [-20, 4, 13, 68]

Simplifying, we get:

-2v1 + (b+3)v2 = [-20, 4, 13-68b, 68]

Now we can use Gaussian elimination to solve for b:

| v1 | v2 | v3 | v |
|----|----|----|---|
| -2 | b+3|  0 | -20|
|  0 |  0 |  1 |  3|
|  0 |  0 |  0 |  0|
|  0 |  0 |  0 |  0|

From the first row, we can see that b = -1.

Substituting that back into our equation, we get:

v = 2v1 - v2 + 68/13 v3

This is the desired expression of v as a linear combination of v1, v2, v3 with the coefficient of v1 being 0.

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The power series ∑n=0[infinity]n!x2n converges for all real values of x. This can be shown using the ratio test, where the limit as n approaches infinity of |(n+1)!x^(2n+2)/(n!x^(2n))| is equal to the limit as n approaches infinity of |(n+1)x^2|, which equals infinity for x≠0.

However, the ratio test is inconclusive for x=0, so we need to use a different test to determine convergence at x=0. The Cauchy-Hadamard theorem states that the radius of convergence of a power series is given by R=1/lim sup (|an|^(1/n)), where an is the nth term of the series.

Applying this to our power series, we get R=1/lim sup (n!^(1/n) x^2), which simplifies to R=0 for all values of x. Therefore, the power series converges only at x=0 and diverges for all other real values of x.

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Answer:

Step-by-step explanation:

Number of people using more than one sport facility:

Since 16 is counted for all three, total number of those using more than one facility is therefore:

Number of people using exactly one facility is:

Probability of the person using exactly one facility is:

Answer:

329.6 $

Step-by-step explanation:

320 + 9.60 = 329.6

Hopefully this helps you :)

pls mark brainlest ;)

Answer:

Step-by-step explanation:

If you are look for the cost  of the item after the tax is

$320+$9.60=$329.60

If you are look for the percentage of the tax

320=100%

9.60=

9.60×100÷320=3

Answer is 3%

If you are looking for the percentage increase then  the answer is 3%